a steel bottle contains argon gas at standard temperature and pressure. what is the final temperature if the pressure is changed to 2.76 atm?

Answers

Answer 1

When the pressure is changed to 2.76 atm, is approximately 754.19 Kelvin. When the pressure inside the steel bottle is changed to 2.76 atm while containing argon gas at standard temperature and pressure (STP), the final temperature of the gas will increase.

According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin. Since the volume remains constant in this case, we can rearrange the equation as P₁/T₁ = P₂/T₂, where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature. Given that the initial conditions are at STP, the initial temperature is 273.15 K. If we substitute the values into the equation, we get 1 atm / 273.15 K = 2.76 atm / T₂. Solving for T₂, we find T₂ = (273.15 K) * (2.76 atm / 1 atm) ≈ 754.19 K.Therefore, the final temperature of the argon gas in the steel bottle, when the pressure is changed to 2.76 atm, is approximately 754.19 Kelvin.

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Related Questions

From the balanced equation, the mole ratio of Al to Al2O3 is 4:2. Therefore, for 5 mole of Al, mole of Al2O3 produced = (2/4) x 5 = 2.5 moles. Hence, 2.5 moles of Al2O3 can be formed.

Answers

The balanced chemical equation is given as:4 Al + 3 _{2} → 2 Al_{2}O_{3} .when all 5.0 moles of Al aluminum are used up, 2.5 moles of Al_{2}O_{3} will be formed.

The balanced chemical equation is given as:4 Al + 3 _{2} → 2 Al_{2}O_{3} .One mole of aluminum (Al) reacts with three moles of oxygen (O2) to form two moles of aluminum oxide (Al_{2}O_{3}). Therefore, the mole ratio of Al to Al_{2}O_{3} is 4:2 or 2:1. This means that for every 4 moles of aluminum that react, 2 moles of Al2O3 will be produced. If 5 moles of aluminum is used up in the reaction, the number of moles of Al_{2}O_{3} formed can be calculated as follows:
Number of moles of Al_{2}O_{3} = (\frac{Number of moles of Al}{ Mole ratio of Al2O3 to Al})*Mole ratio of Al_{2}O_{3} to Al
Number of moles of Al_{2}O_{3} = (\frac{5.0}{ 4}) * 2 = 2.5
Therefore, when all 5.0 moles of Al are used up, 2.5 moles of Al_{2}O_{3} will be formed.

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complete question:

5.0 mol Al reacts with 6.0 mol O2 to form Al2O3.

4 Al + 3 O2 → 2 Al2O3

How many moles of Al2O3 form when all 5.0 moles of Al are used up?

A 5.00 g piece of metal is heated to 100.0oC, then placed in a beaker containing 20.0 g of water at 10.0oC. The temperature of the water rises to 15.0oC. Calculate the specific heat of the metal. What is the metal?

Answers

The metal is 6 a 5.00 g piece of metal is heated to 100. Then places in a beaker containing 20.

What is the mass of 7.00 mol of hydrogen peroxide (h2o2)? 0.206 g 0.389 g 126 g 238 g

Answers

The mass of the hydrogen peroxide is 238 g.

Hydrogen peroxide at room temperature stays in liquid form. It has a bitter taste and is colorless. It is an important regent used in pharmaceutical and other industries. It also has medical use. It can be used as an antiseptic.

The number of miles in the hydrogen peroxide is n.

n = 7 mol

The molar mass of hydrogen peroxide is,

The molar mass of hydrogen peroxide = Molar mass of hydrogen + Molar mass of oxygen

= 2 × 1 + 2× 16

= 34 g/mole

The molar mass of hydrogen peroxide is 34 g/mole.

The mass of the hydrogen peroxide is,

\(Number \: of \: moles = \frac{ Mass }{ Molar \: mass}\)

\(n = \frac{m}{M} \)

m = n × M

m = 7 × 34

m = 238 g.

Therefore, the mass of the hydrogen peroxide is 238 g.

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A chemist weighed out 2.9 g of nickel. Calculate the number of moles of nickel she weighed out. Be sure your answer has the correct number of significant digits.

Answers

Answer:moles = 2.9 g Ni × 1 mol Ni 58.69 g Ni = 0.0663 mol Ni

You were asked to notice that the rim of the porcelain evaporating dish is unglazed, and observe what water will do to the unglazed side of the piece of terra cotta plant pot on your tray. This is why we preheated the evaporating dish prior to measuring the evaporating dishes initial mass. Brian suggests to Matt that if the evaporating dish was not preheated, the mass of the anhydrate will be heavier resulting in a greater value for the anhydrate, and a smaller value for "z" in this formula, CuxCly • zH2O. Do you agree or disagree? Justify your answer

Answers

Yes, I am agree with the evaporating dish is not preheated, then the mass of the anhydrate will be heavier, resulting in a greater value for the anhydrate and a smaller value for "z" in this formula:

CuxCly • zH2O

An anhydrate is a chemical compound that does not contain any water molecules. An anhydrate is formed when the water molecules present in a hydrate are removed through heating or another process. When we heat a hydrated compound, it results in the loss of water molecules from the compound, leading to the formation of an anhydrate.The anhydrate's mass is measured by calculating the difference in weight of the evaporating dish containing the hydrated sample and the weight of the empty evaporating dish. When we use an unpreheated evaporating dish, it results in the loss of weight as the water molecules are released from the hydrated compound. The water molecules released from the sample will condense on the cooler surface of the evaporating dish, which will lead to a higher weight than the actual weight of the anhydrate. Therefore, if the evaporating dish is not preheated, then the mass of the anhydrate will be heavier, resulting in a greater value for the anhydrate and a smaller value for "z" in this formula, CuxCly • zH2O.

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Please answer this question ASAP

Salts of metals can be prepared by reacting a metal with an acid to produce the
salt and the gas hydrogen. Describe the test to show that the gas is hydrogen.
(2 marks)

Answers

Answer:

put a test tube over the opening, remove it and quickly put a lit splint near the mout or in the tube. if you hear a squeaky pop it is hydrogen.

Explanation:

hydrogen ignites in air.

NO2 + H20-------> HNO2+ HNO3​

Answers

Answer:

6NO2+3H2O-------->3HNO2+3HNO3

A geologist is studying the shore along a river. She finds a pile of rocks at the base of a riverbank. These broken rock pieces are the result of. A little farther along the river, the geologist finds some smaller pebbles in a very shallow, slow-moving section of the river. These rocks were moved to this location through the process of. The process of the rocks actually being placed here is called.

Answers

The scientist who studies the earth constituent like solids, gas and liquid is called a geologist. Weathering and erosion are the correct blanks.

What are weathering and erosion?

The process of the deterioration of any solid particles like minerals, soils and rocks is called weathering. It occurs due to biochemical substances, atmospheric gases and water pressure.

The process of the transportation of the rocks and mineral particles away from their original position is called erosion it is due to forceful air and water.

The rocks moved from their original place to some another due to weathering and this process of their transportation is called erosion.

Therefore, weathering and erosion are the correct blanks.

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Answer:

A

Explanation:

I just finished it

at the exact instant that a carbonated beverage is opened, it isSelect the correct answer below:A. unsaturated with carbon dioxideB. saturated with carbon dioxideC. supersaturated with carbon dioxideD.saturated with oxygen

Answers

At the exact instant that a carbonated beverage is opened, it is saturated with carbon dioxide. The carbon dioxide is dissolved in the liquid under high pressure, which maintains its solubility in the liquid.

When the bottle or can is opened, the pressure is released, and the carbon dioxide begins to come out of solution, forming bubbles. As the carbon dioxide leaves the liquid, the beverage becomes less saturated with the gas.

Carbonated beverages, such as soda, are made by dissolving carbon dioxide gas (CO2) under high pressure into a liquid, such as water. The pressure forces more gas to dissolve in the liquid than would normally be possible under normal atmospheric conditions. The dissolved carbon dioxide forms carbonic acid (H2CO3), which gives the drink a slightly acidic taste.

When the container of the carbonated beverage is opened, the pressure is released, and the carbon dioxide comes out of solution. The carbon dioxide gas forms bubbles that rise to the surface of the liquid and escape into the air. This process is called degassing, and it causes the drink to lose its fizziness and become flat.

The degree of carbonation in a beverage depends on several factors, such as the amount of carbon dioxide added, the temperature of the liquid, and the pressure at which it is stored. For example, colder liquids can hold more dissolved gas than warmer liquids, and higher pressures can force more gas into the liquid. Different types of carbonated beverages can also have different levels of carbonation, with some having more or less carbon dioxide than others.

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the molar volume of copper (63.5 g•mol–1 ) at 25oc is 7.09 cm3 • mol–1 . what is the density of copper at 25oc in g• cm3?

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The density of copper having a molar volume of 7.09 cm³/mol at 25℃ is 8.96 g·cm⁻³.

The density of copper is the ratio of its mass to volume. That is, we need to calculate the mass of 1 cm³ of copper, which is equal to the density of copper. We can use the molar mass of copper to find out the mass of 1 mole of copper.

Molar mass of copper (Cu) = 63.5 g·mol⁻¹

We know that 1 mole of copper has a volume of 7.09 cm³. We can use this information to find the mass of 1 cm³ of copper.

Mass of 1 cm³ of copper = Mass of 1 mole of copper ÷ Volume of 1 mole of copper = 63.5 g ÷ 7.09 cm³ = 8.96 g/cm³

Therefore, the density of copper at 25℃ is 8.96 g·cm⁻³.

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the chemical substance and apparatus needed to investigate the nature of pH of a sample of onion solution

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Sun BATCH 1:6:30am & 7:30amBATCH2.

To investigate the nature of pH in a sample of onion solution, the appropriate chemical substance (onion) and the necessary apparatus (pH meter or pH indicator strips, beaker or test tube, stirring rod, distilled water, and pH calibration solutions for pH meter), is required.

Investigating the Nature of pH in Onion Solutions: Unraveling the Essence of Acidity and Alkalinity

Chemical Substance:

Onion: Obtain fresh onions and prepare a sample of the onion solution by blending or crushing a small piece of onion in water.

Apparatus:

pH Meter or pH Indicator Strips: A pH meter or pH indicator strips are used to measure the acidity or alkalinity of the onion solution. Beaker or Test Tube: Use a clean and transparent beaker or test tube to hold the onion solution for pH testing.Stirring Rod: A stirring rod helps mix the onion solution thoroughly, ensuring an even distribution of onion particles in the water.Distilled Water: Use distilled water to dilute the onion solution if needed or to rinse the pH meter or pH indicator strips between measurements.pH Calibration Solutions: If you are using a pH meter, you will need pH calibration solutions of known pH values to calibrate the meter before testing the onion solution.

Thus, the right chemical (onion) and the right equipment (pH metre or pH indicator strips, beaker or test tube, stirring rod, distilled water and pH calibration solutions for pH metre) are needed to explore the nature of pH in a sample of onion solution.

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t/f do not use oil-based products (vaseline, body lotions) because they destroy latex

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True. Do not use oil-based products such as Vaseline and body lotions because they destroy latex. Latex is a natural rubber, and when it comes into contact with oil-based products, it reacts chemically.

This reaction causes latex to degrade and lose its elasticity, making it prone to breakage. Therefore, it is important to avoid oil-based products when using latex products, such as condoms, gloves, and other medical supplies. Instead, use water-based products that are safe to use with latex. Water-based products are gentle on the skin and do not react chemically with latex, making them ideal for use with latex products.

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Which of the following molecules has a trigonal planar shape?

Which of the following molecules has a trigonal planar shape?

Answers

Answer:

Structure of boron trifluoride, an example of a molecule with trigonal planar geometry.

Examples: SO3

Coordination number: 3

Point group: D3h

Bond angle(s): 120°

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2 moles of NO, was placed in an empty I dm' bottle and allowed to reach equilibrium according to the equation:
At equilibrium, 1.2 moles of N,O, dissociated. Calculate the value of the equilibrium constant for the reaction at that
temperature.

Answers

The balanced equation for the dissociation of nitrogen monoxide (NO) is:

2NO(g) ⇌ N2(g) + O2(g)

According to the problem statement, 2 moles of NO were placed in a 1 dm^3 bottle and allowed to reach equilibrium, and at equilibrium, 1.2 moles of NO had dissociated. This means that the initial concentration of NO was:

[NO]initial = 2 mol / 1 dm^3 = 2 M

And the concentration of NO at equilibrium is:

[NO]equilibrium = (2 - 1.2) mol / 1 dm^3 = 0.8 M

Since the stoichiometry of the balanced equation is 2:1:1 for NO, N2, and O2, respectively, the equilibrium concentrations of N2 and O2 will also be 0.6 M.

The equilibrium constant (Kc) can be calculated using the equilibrium concentrations of the reactants and products, raised to the power of their stoichiometric coefficients. Therefore:

Kc = ([N2][O2]) / ([NO]^2)

Substituting the equilibrium concentrations into the equation, we get:

Kc = (0.6 M x 0.6 M) / (0.8 M x 0.8 M)
Kc = 0.5625

Therefore, the value of the equilibrium constant for the reaction at that temperature is 0.5625. Note that the units of Kc depend on the stoichiometry of the balanced equation. Since the stoichiometric coefficients are all 1, the units of Kc in this case are M^-1

H2 produced by the above reaction? Calculate the mass of NaCl required producing
35.5g of H2?

Answers

To produce 35.5g of H2, approximately 2055.49g of NaCl is required.

To calculate the mass of NaCl required to produce 35.5g of H2, we need to determine the stoichiometry of the reaction and use the molar mass of NaCl.

The balanced equation for the reaction is:

2NaCl + 2H2O -> 2NaOH + H2

From the balanced equation, we can see that for every 2 moles of NaCl, 1 mole of H2 is produced. We can use the molar mass of H2 (2.016g/mol) to convert the given mass of H2 into moles:

moles of H2 = mass of H2 / molar mass of H2

moles of H2 = 35.5g / 2.016g/mol

moles of H2 = 17.6 mol

Since the stoichiometry of the reaction is 2 moles of NaCl to 1 mole of H2, we can set up the following ratio:

moles of NaCl / moles of H2 = 2 / 1

Rearranging the equation to solve for moles of NaCl:

moles of NaCl = (moles of H2 * 2) / 1

moles of NaCl = (17.6 mol * 2) / 1

moles of NaCl = 35.2 mol

Now, we can calculate the mass of NaCl required using the molar mass of NaCl (58.44g/mol):

mass of NaCl = moles of NaCl * molar mass of NaCl

mass of NaCl = 35.2 mol * 58.44g/mol

mass of NaCl = 2055.49g

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2. A 250.0 g gold statue at 21.0°C is placed in a tank containing 1105. g of water at an initial temperature
of 80°C. If no heat enters or leaves the system, find the final equilibrium temperature.

Answers

Answer:

The final equilibrium temperature of the system is 37.9°C.

Explanation:

To find the final equilibrium temperature, we need to use the principle of heat conservation, which states that the total heat lost by the hot water is equal to the total heat gained by the cold gold statue. We can express this principle mathematically as follows:

Q_lost = Q_gained

where Q_lost is the heat lost by the water, and Q_gained is the heat gained by the gold statue.

To calculate the heat lost by the water, we can use the formula:

Q_lost = m_w * c_w * (T_i - T_f)

where m_w is the mass of the water, c_w is the specific heat capacity of water, T_i is the initial temperature of the water, and T_f is the final equilibrium temperature.

To calculate the heat gained by the gold statue, we can use the formula:

Q_gained = m_g * c_g * (T_f - T_i)

where m_g is the mass of the gold statue, c_g is the specific heat capacity of gold, T_i is the initial temperature of the gold statue, and T_f is the final equilibrium temperature.

Equating Q_lost and Q_gained, we have:

m_w * c_w * (T_i - T_f) = m_g * c_g * (T_f - T_i)

Substituting the given values, we get:

1105. g * 4.184 J/g°C * (80°C - T_f) = 250.0 g * 0.129 J/g°C * (T_f - 21.0°C)

Simplifying and solving for T_f, we get:

T_f = 37.9°C

Therefore, the final equilibrium temperature is 37.9°C.

100 g of calcium carbonate was heated until it decomposed to give calcium oxide and carbon dioxide. 56 g of calcium oxide was left. Work out the mass of carbon dioxide given off.

Answers

Answer:

44g of carbon dioxide was produced

Explanation:

100 g of calcium carbonate was heated until it decomposed to give calcium oxide and carbon dioxide. 56

If 100 g of calcium carbonate was heated until it decomposed to give calcium oxide and carbon dioxide and 56 g of calcium oxide was left. The mass of carbon dioxide, given off, is 44 g.

How to find the mass of carbon dioxide?

According to the rule of conservation of matter, which stipulates that during a chemical reaction, matter cannot be generated or destroyed but can only be changed from one form to another,

We recognized that a reactant's total mass is equal to its total mass of products, that is,

The total mass of reactant  is equal to the total mass of products

According to the above information, we can get the mass of CO₂ carbon dioxide, given off as follows:

CaCO₃ → CaO + CO₂

Mass of CaCO₃ is 100 g

Mass of CaO is 56 g

Mass of CO₂ =?

So, total mass of reactant = Total mass of products

Mass of CaCO₃ is equal to mass of CaO + mass of CO₂

100 = 56 + mass of CO₂

Mass of carbon dioxide = 100 – 56

Mass of carbon dioxide = 44 g

Thus, the mass of carbon dioxide, CO₂ given off, is 44 g.

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Ethyl acetate is synthesized in a nonreacting solvent (not water) according to the following reaction CH_3CO_2H + C_2H_3OH rightarrow CH_3CO_2C_2H_3 + H_2O K = 2.2 Acetic acid Ethanol Ethyl aceute For the following mixtures (a-d), will the concentration of H_2O increase, decrease, of remain the same as equilibrium is established? [CH_3CO_2C_2H_5] = 0.22 M, [H_2O] = 0.10 M, [CH_3CO_2H] = 0.010 M, [C_2H_5OH] = 0.010 M increase decrease remain the same [CH_2CO_2C_2H_5) = 0.22 M, [H_2O] = 0.0020 M, [CH_3CO_2H] = 0.0020 M [C_2H_3OH] = 0.10 M increase decrease remain the same CH_2CO_2C_2H_5] =0.88 M, [H_2O] = 0.12 M [CH_3CO_2H] =0.044 M, [C_2H_5 OH] = 6.0 M increase decrease remain the same CH_2CO_2C_2H_5] =4.4 M, [H_2O] = 4.4 M [CH_3CO_2H] =0.88 M, [C_2H_5 OH] = 10.0 M increase decrease remain the same What must the concentration of water be for a mixture with [CH_3CO_2C_2H_5] = 3.0 M, [CH_3CO_2H] = 0.10 M, and [C_2H_5OH] = 6.0 M to be at equilibrium

Answers

At equilibrium, the concentrations of the reactants and products remain constant over time, although the individual molecules are continuously interconverting. The concentration of water must be 0.227 M for the mixture to be at equilibrium.

To determine whether the concentration of water (H₂O) will increase, decrease, or remain the same as equilibrium is established, we need to compare the given concentrations of reactants and products with their stoichiometric coefficients in the balanced equation.

The balanced equation for the reaction is:

CH₃CO₂H + C₂H₅OH -> CH₃CO₂C₂H₅ + H₂O

Let's analyze each mixture (a-d) and determine the change in the concentration of water:

(a) [CH₃CO₂C₂H₅] = 0.22 M, [H₂O] = 0.10 M, [CH₃CO₂H] = 0.010 M, [C₂H₅OH] = 0.010 M

In this mixture, the concentration of water remains the same because the given concentrations are in equilibrium.

(b) [CH₃CO₂C₂H₅] = 0.22 M, [H₂O] = 0.0020 M, [CH₃CO₂H] = 0.0020 M, [C₂H₅OH] = 0.10 M

The concentration of water decreases because its initial concentration is higher than the equilibrium concentration.

(c) [CH₃CO₂C₂H₅] = 0.88 M, [H₂O] = 0.12 M, [CH₃CO₂H] = 0.044 M, [C₂H₅OH] = 6.0 M

The concentration of water increases because its initial concentration is lower than the equilibrium concentration.

(d) [CH₃CO₂C₂H₅] = 4.4 M, [H₂O] = 4.4 M, [CH₃CO₂H] = 0.88 M, [C₂H₅OH] = 10.0 M

The concentration of water remains the same because the given concentrations are in equilibrium.

To determine the concentration of water for a mixture to be at equilibrium with [CH₃CO₂C₂H₅] = 3.0 M, [CH₃CO₂H] = 0.10 M, and [C₂H₅OH] = 6.0 M, we need to set up an expression using the equilibrium constant (K) and the concentrations of the other species:

K = [CH₃CO₂C₂H₅] / ([CH₃CO₂H] * [C₂H₅OH] * [H₂O])

We can rearrange the equation to solve for [H₂O]:

[H₂O] = [CH₃CO₂C₂H₅] / (K * [CH₃CO₂H] * [C₂H₅OH])

Substituting the given concentrations:

[H₂O] = 3.0 M / (2.2 * 0.10 M * 6.0 M)

Simplifying the expression:

[H₂O] = 0.227 M

Therefore, the concentration of water must be 0.227 M for the mixture to be at equilibrium.

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nuclear energy is created through the process of splitting apart atoms and releasing large amounts of heat energy that can be converted to electrical energy.this process is known as?

Answers

Nuclear fission is a process by which the nucleus of an atom is split into two or more smaller nuclei, known as fission products. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

how does dalton's theory explain the process of chemical change.

Answers

Dalton's theory, also known as the atomic theory of matter, provides a fundamental understanding of chemical change. According to this theory, atoms are indivisible and indestructible particles that combine in fixed ratios to form compounds. In the process of chemical change, known as a chemical reaction, atoms are rearranged, but they are neither created nor destroyed.

In more detail, Dalton's theory explains that when a chemical reaction occurs, the bonds between atoms are broken and new bonds are formed, resulting in the creation of different substances. These reactions occur due to the rearrangement of atoms and the redistribution of their electrons.

For example, in the reaction between hydrogen and oxygen to form water, Dalton's theory explains that the hydrogen and oxygen atoms combine in a fixed ratio of two hydrogen atoms for every one oxygen atom. The reaction involves breaking the bonds between hydrogen and oxygen molecules and forming new bonds between hydrogen and oxygen atoms to create water molecules.

Overall, Dalton's theory provides a framework for understanding how chemical changes occur through the rearrangement of atoms and the formation of new substances with different properties.

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helpppppppppppppppppppppppppp

helpppppppppppppppppppppppppp

Answers

Conductor = Radiator , Frying pan , Ceramic baking dish
Insulator = Winter coat , Oven mitt and ice chest

help! What is the atomic mass of Carbon dioxide

Answers

Answer:

44

Explanation:

(16 × 2) + (12 × 1)

so basically 32 plus 12 which equals 44

What is the limiting reactant for the following reaction given we have 3.4 moles of ca(no3)2 and 2.4 moles of li3po4?

Answers

Calcium nitrate \(Ca(NO_{3})_{2}\) )is the limiting reactant for the reaction.

This is fewer than the 2.4 moles of lithium phosphate \(Li_{3} PO_{4}\) that are readily available. This indicates a deficiency in calcium nitrate\(Ca(NO_{3})_{2}\). 2.4 moles of lithium phosphate must be added in order to complete the reaction.

As a result, calcium nitrate \(Ca(NO_{3})_{2}\) is the limiting reagent and lithium phosphate\(Li_{3} PO_{4}\) is in excess. The availability of Calcium Nitrate \(Ca(NO_{3})_{2}\) is lesser than the 2.4 moles of lithium phosphate \(Li_{3} PO_{4}\) that are accessible. This indicates that present amount of calcium nitrate \(Ca(NO_{3})_{2}\) is inadequate to completely react with 2.4 moles of lithium phosphate\(Li_{3} PO_{4}\). Thus, calcium nitrate \(Ca(NO_{3})_{2}\) is the limiting reagent and lithium phosphate \(Li_{3} PO_{4}\) is in excess.

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if two surface water types with the same density but different salinities and temperatures mix, the resulting water will be .

Answers

If two surface water types with the same density but different salinities and temperatures mix, the resulting water will be denser than both the surface water types.

Areas under warm and high salinity surface water with an appreciable depth, the temperature and salinity decreases with depth and internal vertical mixing processes occur despite stability of the water column. Eventually, this phenomenon is caused by the ability of the sea water to lose or gain heat by conduction and loss or gain of salt takes place by diffusion. This causes the density of the moving water to change directions.

Salt water mixes over limited depths and forms homogenous layers.

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What mass of fluorine is needed to completely react with 3.6 grams of water?

Answers

= 18.02 g/mol) im sure its that

Wave interference occurs only when a wave is reflected.
TRUE or false

Answers

Answer:

False

Explanation:

It occurs when two waves meet while traveling along the same medium.

4. Which of the following units are not paired correctly?
a) Liter (L) - Mass
b) Newton (N) - Force
c) Pascal (P) - Pressure
d) Joule (J) - Work

Answers

Answer:

a

Explanation:

i hope i am right

choose the ground state electron configuration for ti2+.

Answers

The ground state electron configuration for Ti²⁺ is [Ar] 3d². Here’s how it can be derived: The element with atomic number 22 is Titanium (Ti).

Its full electronic configuration is 1s²2s²2p⁶3s²3p⁶4s²3d². When this atom loses two electrons to form Ti²⁺, it loses two from the 4s sub-shell, and its new configuration is [Ar]3d².

The electron configuration of an atom is the distribution of electrons among its orbitals. It represents the state of an atom's electrons in their ground state or unexcited state. It's important to remember that when an atom becomes an ion, its electron configuration changes.

The process of ionization entails removing or adding electrons from the outermost or valence shell of an atom. The valence shell is the outermost shell in an atom's electron cloud.

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The oxidation of inorganic molecules such as hydrogen sulfide into carbohydrates is called:
a. photosynthesis.
b. chemosynthesis.
c. photoautotrophy.
d. evolution.

Answers

it is called chemosynthesis

The oxidation of inorganic molecules such as hydrogen sulfide into carbohydrates is called chemosynthesis.

option B is the correct answer.

What is oxidation?

Oxidation is a process in which a chemical substance changes because of the addition of oxygen. Carbon dioxide is a necessary result of the oxidation of carbon compounds.

Chemosynthesis is the biological conversion of one or more carbon-containing molecules and nutrients into organic matter using the oxidation of inorganic compounds or ferrous ions as a source of energy, rather than sunlight, as in photosynthesis.

So the oxidation of inorganic molecules such as hydrogen sulfide into carbohydrates is called chemosynthesis.

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Consider the following generic reaction for which k = 2. 54: 3 z q ⇄ 2 x what is the value of k for the following reaction: 4 x ⇄ 6 z 2 q.

Answers

The equilibrium constant of the second reaction is 0.155.

What is equilibrium constant?

The equilibrium constant is a numerical value that shows the extent to which reactants are converted into products at a given temperature.

Now, we have the reaction; 3Z + Q ⇄ 2 X  and  4 X ⇄ 6 Z + 2 Q.

In the first reaction;

K =[ X]^2/[Z]^3 Q

In the second reaction;

[Z]^6 [Q]^2/[X]^4

Let [ X]^2 = A

[Z]^3 Q = B

Then the second reaction can be;

K = (B)^2/(A)^2 = (B/A)^2

The equilibrium constant of the second reaction therefore is; (1/2.54)^2

K = 0.155

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