A small rocket burns a mass 0.55kg of fuel per second, ejecting it as a gas with a velocity relative to the rocket of magnitude 1616 m/s .
A.) What is the thrust of the rocket? (Answer: 889 N)
B.) What is the rockets change in velocity after it has burned 355kg , of fuel if its total initial mass is 1830kg ?
C.) What is the rockets velocity after 171 s, if it had an initial velocity of 1028 m/s ?

Yes, it is possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero.

This is due to the fact that electric and magnetic forces are perpendicular to one another, meaning that they can be in opposition and cancel each other out.

To explain in more detail, electric fields exert a force on a charged particle that is proportional to its charge and the magnitude of the electric field. This force, Fe, is given by Fe = qE.

Meanwhile, magnetic fields exert a force on a moving charged particle that is proportional to its charge, the magnitude of the magnetic field, and its velocity. This force, Fm, is given by Fm = qv × B.

Since these forces are perpendicular to each other if the electric force is equal in magnitude to the magnetic force but opposite in direction, they can cancel each other out. This will result in a net force of zero on the particle.

Therefore, it is true that it is possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero.

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The difference in the emission of interstellar hydrogen atoms between radio waves at a wavelength of 21cm and visible light is due to the physical conditions of the hydrogen clouds.

Hydrogen atoms emit radio waves at a wavelength of 21cm when their electrons change their spin state from parallel to anti-parallel. This transition corresponds to a change in energy that is characteristic of hydrogen atoms in interstellar space, where the density of particles is low and the temperature is cold.

However, some hydrogen clouds can emit visible light when the conditions are right for the excitation of the hydrogen atoms. This can happen, for example, when the density of particles is high enough for collisions to excite the electrons of the hydrogen atoms to higher energy levels, and then they release that energy as visible light when they return to their ground state.

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The correct answer is D. persist and continue to destroy ozone for decades.

Chlorofluorocarbons (CFCs) are a class of human-made chemicals that were widely used in refrigeration, air conditioning, and aerosol spray products. When CFCs are released into the atmosphere, they can rise to the stratosphere, where they are broken down by ultraviolet radiation from the sun. This process releases chlorine atoms, which can then react with and destroy ozone molecules, leading to the formation of the so-called "ozone hole."

Although production of CFCs has been curtailed through international agreements such as the Montreal Protocol, the threat to the upper atmospheric ozone layer persists because CFCs have a long atmospheric lifetime. Once released, they can persist in the atmosphere for decades, continuing to destroy ozone molecules and contributing to the thinning of the ozone layer. It is estimated that the ozone hole over Antarctica will not recover to pre-1980 levels until the middle of this century.

Therefore, continued efforts to reduce CFC emissions and replace them with safer alternatives are important to protect the ozone layer and prevent harmful effects on human health and the environment.

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Answer:

10 m/s²

Explanation:

Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.

∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².

Answer:

10 m/s^2 I hope it helps u a lot

42 Joules energy is gained by the block. This can be solved by using the concept work done formula.

The product of a force and the distance it is applied across is what is referred to as the work done. An item moves across space when a force is applied to it, which is referred to as doing work. By applying a force across a distance, such as when you lift a burden, you are performing labor.

A force delivered over a distance to an item causes work to be done. Thus, an object's total energy will be impacted when a force is applied to it across a distance.

Given that,

a force of 6.0 Newtons is applied to a block at rest on a horizontal friction less surface over a 7.0 meter span.

The parameters given are:

Distance covered = 7.0 m

The force = 6.0 N

The formula for work done is the product of force and distance. That is,

Work done = force × distance

Where work done is the same as energy.

So, Energy = force × distance

or, Energy = 6.0 N × 7.0 m

or, Energy = 42 Joules.

Therefore, the energy gained by the block is 42 Joules.

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Answer:

Jethro Wood is the one who designed the one-piece wrought iron plow.

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

Anomalous expansion of water is a property of water in which water expands instead of contracting.

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Answer/Explanation:

Part 1: 13 chromosomes.

Reproductive cell, male or female, whose nucleus contains only one chromosome of each pair (they are said to be haploid n = 13) and which unites with the gamete of the opposite sex (fertilization) to give birth to an egg (zygote 2n = 26 ) diploid resulting from the association of the two gametes with each his half of the genetic capital.

2. The process of creating a new flower is called reproduction.

Human reproduction is the process by which a man and a woman engender a new individual. It is a method of sexual reproduction.

Sexual reproduction requires:

The distance the car would travel along the barrier before coming to a stop 14.6 m.

The distance travelled by the car before stopping is determined by applying the following kinematic equation.

v² = u² - 2as

where;

when the car stops, v = 0

0 = u² - 2as

2as = u²

s = u²/2a

Given;

u = 110 km/h = 30.56 m/s

a = 32 m/s²

s = (30.56²) / (2 x 32)

s = 14.6 m

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The oscillation frequency of the H2 molecule is approximately 1.27 × 10¹³ Hz.

To calculate the oscillation frequency (f) of the H2 molecule, we can use the formula for the frequency of a harmonic oscillator:

f = (1 / 2π) * √(k₁ / m_eff)

Given, k₁ = 530 N/m, and m_eff = m/2, where m is the mass of a hydrogen atom.

First, let's find the mass of a hydrogen atom:

1.008 μ = 1.008 * 1.661 × 10⁻²⁷ kg
m ≈ 1.675 × 10⁻²⁷ kg

Now, we can calculate the effective mass (m_eff):

m_eff = m / 2
m_eff ≈ (1.675 × 10⁻²⁷ kg) / 2
m_eff ≈ 0.8375 × 10⁻²⁷ kg

Finally, let's find the oscillation frequency (f):

f = (1 / 2π) * √(530 N/m / 0.8375 × 10⁻²⁷ kg)
f ≈ (1 / 2π) * √(6.33 × 10²⁶ s²)
f ≈ (1 / 6.28) * √(6.33 × 10²⁶ s²)
f ≈ 0.159 * √(6.33 × 10²⁶ s²)
f ≈ 1.27 × 10¹³ Hz

So, the oscillation frequency of the H2 molecule is approximately 1.27 × 10¹³ Hz.

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The oscillation frequency f of an H₂ molecule, when displaced from equilibrium by a small amount and acted on by a restoring force Fₓ= -k₁x with k₁=530 N/m, is calculated using the formula meff f²=k₁/m, where meff is the effective mass of the system. For H₂, meff = m/2, where m is the mass of a hydrogen atom (1.008 μ or 1.008 x 10⁻²⁷ kg). Substituting these values, we get f = 1.16 x 10¹⁵ Hz.

In a simple harmonic motion, the restoring force is directly proportional to the displacement from equilibrium. For an H₂ molecule, the restoring force is Fₓ= -k₁x, where k₁=530 N/m. The oscillation frequency f is related to the restoring force and the effective mass of the system, given by meff f²=k₁/m. For H₂, the effective mass is meff = m/2, where m is the mass of a hydrogen atom (1.008 μ or 1.008 x 10⁻²⁷ kg). Substituting these values, we get f = 1.16 x 10¹⁵ Hz. This means that the two hydrogen atoms in an H₂ molecule oscillate back and forth 1.16 x 10¹⁵ times per second when displaced from their equilibrium position by a small amount.

The oscillation frequency f can be calculated using the formula: f = (1/2π) √(k₁/m_eff)

where k₁ is the spring constant of the H₂ molecule, m_eff is the effective mass of the system, and π is a mathematical constant approximately equal to 3.14.We are given the value of k₁ as 530 N/m and the mass of a hydrogen atom as 1.008 μ, so we can calculate the effective mass as: m_eff = 2m = 2(1.008 μ) = 2.016 μ

Substituting these values into the formula, we get: f = (1/2π) √(530 N/m / 2.016 μ)

= 1.23 × 10¹⁴ Hz

Therefore, the oscillation frequency of the H₂ molecule is approximately 1.23 × 10¹⁴ Hz.

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Answer:

They vary quite a lot, yet there are some similarities

Explanation:

With Mercury, you have a hot and barren expanse of rock

With Venus, you also have a fairly hot and barren expanse of rock, with a molten core

With Earth, you have a warm/cool variant with water and a full atmosphere

With Mars, you have a colder and barren expanse of valleys and rock, with a rather paste-like ground

With Jupiter, we have our first gas giant, covered in clouds with a thick atmosphere

With Saturn, it is yet another gas giant, with rings of gas and rock and a dense core of metals, such as iron and nickel

With Uranus, it is also rather gas-full with a fair amount of water and methane, which results in its bluish color (an ice giant)

And finally with Neptune, it is the other ice giant, consisting of water, methane, and ammonia

So there are some similarities (gases, water, land formations, etc.) and some differences (rings, temperature, structure, etc.). Our planets are very unique to one another and continue to engage and surprise us.

Newton’s ideas described the universe as a series of concentric spheres. This statement is false. Sir Isaac Newton (1642-1727) was an English physicist, mathematician, astronomer, theologian, and author, whose work has had a great impact on science, and is famous for his laws of motion and universal gravitation.

Newton was a proponent of the heliocentric view of the solar system, which had been introduced by Copernicus and supported by Galileo. According to this view, the sun, rather than the Earth, was at the center of the universe, and the planets, including the Earth, orbited around it in elliptical paths. Newton's work also helped to explain the tides, which are caused by the gravitational pull of the moon on Earth's oceans. He proposed that the moon's gravity was responsible for the tides because it was closer to Earth than the sun. In summary, Newton's ideas did not describe the universe as a series of concentric spheres, but rather as a heliocentric system in which the planets orbited the sun in elliptical paths.

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Answer:

I believe D

Explanation:

Of course the manufacturer would most likely be biased to the product the have created, but the other sources would have no reason to. Hope this helps!

The Question does not contain any option, the question is incomplete.

I think the Question may be :

Television is an integral part of our daily entertainment. for which of these processes has the television not used any form of energy?

A. manufacturing

B. packaging

C. storage

D.none of the above


The operation of televisions requires the use of energy throughout its entire lifecycle, from the manufacturing process, packaging, storage, transportation, and its use by consumers. The correct option is D.

During the manufacturing process, the television components need to be assembled and tested, which requires the use of energy to power the machinery and tools used in the process.

Packaging and storage also require energy to produce and maintain suitable conditions for the television until it is sold to consumers.

Transportation of televisions from the manufacturing facility to retailers or directly to consumers requires the use of energy for shipping and logistics. Finally, the use of televisions by consumers requires energy to power the device and produce the images and sounds on the screen.

Therefore, The correct answer is D i.e none of the above

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Responder:

3,37 m / s, + ve x - dirección

Explicación:

Utilizando la ley de conservación de la cantidad de movimiento expresada por la fórmula;

m1u1 + m2u2 = (m1 + m2) v

m1 y m2 son las masas de los objetos

u1 y u2 son sus velocidades iniciales

v es su velocidad común

Dado

m1 = 0,519 kg

u1 = 4,80 m / s

m2 = 0,220 kg

u2 = 0 m / s (cuerpo en reposo)

Necesario

Velocidad común v

Sustituir en la fórmula los valores dados;

0,519 (4,8) + 0,22 (0) = (0,519 + 0,220) v

2,4912 + 0 = 0,739 v

2,4912 = 0,739v

Dividir ambos lados por 0,739

2,4912 / 0,739 = 0,739 / 0,739

v = 3,37 m / s

Por lo tanto, la rapidez de ambas bolas después de la colisión es de 3.37 m.s hacia la dirección x positiva, ya que m1> m2 y la velocidad común es positiva.

Answer:

Frictional force will be 150N

Answer:

\(0.741\ \text{m/s}^2\)

Explanation:

v = Velocidad final = \(40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}\)

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2\)

La aceleración del camión en el primer intervalo de tiempo es \(0.741\ \text{m/s}^2\).

Answer:

Conduction

Explanation:

The transfer of energy through matter by direct contact of particles is called. Conduction.

Answered by the ONE & ONLY #QUEEN herself aka #DRIPPQUEENMO!!!

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The semi-major axis an of the ellipse and the period of revolutions T of a planet around the sun are related by the formula T2 = k a3.

An elliptical helps speed up the process of losing body fat since it burns more calories per minute than some other cardio equipment, such as the stationary cycle. This is particularly true if you emphasize interval training.

The best machine for you will depend on your specific requirements. Keep using the elliptical if you have a neuromuscular ailment or are prone to injuries. if you really want to increase your calorie burn while strengthening your legs.

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Answer:

density = 5000 [kg/m^3]

Explanation:

Density is defined as the relationship between mass and volume.

Now we have:

m = 100 [gr] = 0.1[kg]

V = volume = 20[cm^3]

\(20[cm^{3}]*1[\frac{m^{3} }{100^{3} cm^{3} } ] = 2*10^{-5}[m^{3} ]\)

density = 0.1 / (2 x 10^-5)

density = 5000 [kg/m^3]

Answer:5

Explanation:

The order of transportation modes by propulsive efficiency, from the lowest first, would be:

1. Helicopter
2. Small motorcycle
3. Medium size U.S. car - one passenger
4. Peak-hour city bus

This is because helicopters and small motorcycles typically have less efficient motors and require more fuel to operate compared to cars and buses. Additionally, peak-hour city buses tend to have larger and more efficient motors to transport a larger number of passengers at once.

Keep in mind that factors such as load, fuel efficiency, and operating conditions can influence the actual propulsive efficiency of each transportation mode.

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For a voltage of 208 Volts is connected to the circuit and electric power of 13.25 kW, the current drawn by the circuit is 63.7 A.

Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions are constant.

Mathematically, ohms law is written as;

V = IR

where;

The relationship between the electrical power, voltage and current is given as;

P = IV

where;

I = P/V

when a voltage of 208 Volts is connected to the circuit, the current drawn by the circuit is calculated as;

I = (13250)/(208)

I = 63.7 A

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The main advantage why the moment magnitude scale is the most dependable approach to calculating the relative length of huge earthquakes

It is that its underlying calculation technique avoids the trouble of significance saturation because it's far based on measurements of an earthquake's overall power earthquake.

Mainly, for very big earthquakes, moment importance offers the most dependable estimate of earthquake length. the moment is a bodily quantity proportional to the slip at the fault expanded by using the place of the fault floor that slips; it is related to the full strength launched in the earthquake.

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Answer:

Glycolysis

Pyruvate

Krebs Cycle

Electron Transport Chain

Explanation:

The concept map on ATP production shows the process of cellular respiration in living organisms.

Cellular respiration begins with glucose which is broken down in the process of glycolysis that occur in cytoplasm and gives 2 ATP. Glycolysis gives pyruvate as end product that enter in the process of Krebs Cycle or citric acid cycle as a aerobic process, that occur in mitochondria and produces 2 ATP. This energy is then used in Electron Transport Chain to pump high energy electrons and H+ that produces 36 ATP.

a) On a wet basis, the molar composition of the gas is approximately 0.813 mol propane, 0.055 mol n-butane, and 0.132 mol water. The ratio of mol H₂O to mol dry gas is 0.162 mol H₂O/mol dry gas.

b) The required air feed rate is approximately 65.9 kmol/h. If the combustion were only 65% complete, the required air feed rate would increase to approximately 101.4 kmol/h.

a) To calculate the molar composition on a wet basis, we convert the weight percentages to mole fractions using the molar masses of propane, n-butane, and water. The molar composition is determined by dividing the weight percentage by the respective molar mass and normalizing the values to sum up to 1. The ratio of mol H₂O to mol dry gas is determined by dividing the mol water by the sum of mols of propane and n-butane.

b) To calculate the required air feed rate, we use the stoichiometry of the combustion reaction between butane and air. The balanced equation shows that 1 mol of butane reacts with 13.5 mol of air. Considering the 25% excess air requirement, we multiply the stoichiometric air requirement by 1.25. If the combustion is only 65% complete, the remaining butane requires additional air to achieve complete combustion. Therefore, the required air feed rate increases to account for the unreacted butane.

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Answer:

I'd say true, it does exercise and work most major muscle groups .

Explanation:

Practicing soccer skills helps in working most of the muscle groups in the body. Therefore, the given statement is true.

Soccer is also known in many countries as football. It is one of the world's most popular sports. It is a sport which combines the speed, strength, and skill of an individual player. Two teams, each with about 11 players, play on a rectangular field and attempt to score maximum goals by kicking or heading a ball into the opposing team's goal.

This sports requires speed, strength, and skill of the players. Hence, helps in practicing and exercise of different muscles in the body.

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The distance between the two stars in their rest frame is approximately 15.63 light-years.

Length contraction is the phenomenon that a moving object's length is measured to be shorter than its proper length, which is the length as measured in the object's own rest frame.

To answer this question, we can use the concept of length contraction in special relativity.

The formula for length contraction is:
\(L = L_0 * \sqrt{(1 - v^2 / c^2)\)
where L is the contracted length (7.86 light-years in this case), L₀ is the proper length (the distance between the stars in their rest frame), v is the velocity of the spaceship (90.1% of the speed of light), and c is the speed of light.

First, we need to find the factor by which the length contracts:
\(\sqrt{(1 - v^2 / c^2)} = \sqrt{(1 - (0.901c)^2 / c^2)} = \sqrt{(1 - 0.811801)\)

Now we can solve for L₀:
L₀ = L / \(\sqrt{(1 - 0.811801)\) = 7.86 light-years /  \(\sqrt{(1 - 0.811801)\)

L₀ ≈ 15.63 light-years
This is the required distance.

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When the accumulated count exceeds the preset count in a counter system, the correct response is that the D. counter done bit becomes true.

In this situation, the accumulated value represents the total count that has been recorded, while the preset count serves as a threshold or target value. Once the accumulated count surpasses this threshold, the counter's done bit is set to true, signaling that the desired count has been reached. This done bit is typically used to trigger other actions within a control system or to provide feedback to the operator.

It is important to note that the accumulated value is not reset to zero (A) and the preset value is not set to zero (B) when the accumulated count exceeds the preset count. These values remain unchanged unless the system is manually reset or a specific reset command is given. Furthermore, the reset state itself does not change (C) solely due to the accumulated count surpassing the preset count.

In summary, when the accumulated count exceeds the preset count, the counter done bit becomes true, providing an indication that the desired counting threshold has been reached. This signal can then be used to initiate further actions within the system or provide feedback to the operator. Therefore the correct option is D

The Question was Incomplete, Find the full content below :

When the accumulated count exceeds the preset count,the:

A)accumulated value is set to zero.

B)preset is set to zero.

C)reset changes state.

D)counter done bit is true.

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