The period of the oscillator is approximately 0.89 seconds and its frequency is approximately 1.12 Hz
To calculate the period and frequency of a simple harmonic oscillator with a mass of 5 kg and a spring constant of 250 N/m, we can use the following equations:
Period (T) = 2π√(m/k)
Frequency (f) = 1/T
where m is the mass of the oscillator and k is the spring constant.
Substituting the given values, we get:
T = 2π√(5/250) = 2π√(0.02) ≈ 0.89 seconds
f = 1/T = 1/0.89 ≈ 1.12 Hz
Therefore, the period of the oscillator is approximately 0.89 seconds and its frequency is approximately 1.12 Hz. These values represent the time and rate at which the oscillator will complete one full cycle of its motion. The simple harmonic oscillator is a fundamental concept in physics and is used to model a wide range of physical systems, including mechanical vibrations, electronic circuits, and quantum mechanical systems.
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When coal is burned completely in a power plant, the solid carbon in the coal combines with oxygen gas from the atmosphere to form carbon dioxide. What type of change is this?
a. Nuclear
b. Physical
c. Chemical
d. Cellular
e. pH change
The type of change that occurs when coal is burned completely in a power plant, resulting in the formation of carbon dioxide, is a chemical change.
When coal is burned completely in a power plant, a chemical reaction takes place between the solid carbon in the coal and the oxygen gas from the atmosphere. This reaction is known as combustion. During combustion, the carbon in the coal combines with oxygen to form carbon dioxide (CO2). This process involves the breaking and rearranging of chemical bonds between the carbon atoms and the oxygen atoms.
A chemical change, also known as a chemical reaction, involves the transformation of one or more substances into different substances with different chemical properties. In this case, the solid carbon in the coal is being transformed into carbon dioxide gas. The formation of carbon dioxide is a chemical change because new chemical bonds are formed and the chemical composition of the coal is altered.
Therefore, the correct answer is c. Chemical.
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Can someone tell me what they think reliability means ?
Answer:
it is being accountable basically like some one can relive and trust that you'll do what you say your going to do
question 9: what is the total lifetime of the sun (up to the point when it becomes a whitedwarf and no longer supports fusion)?
The total lifetime of the Sun is estimated to be about 10 billion years.
It is currently about 4.6 billion years old, so it has roughly 5 billion years left until it exhausts the hydrogen fuel in its core and starts to evolve into a red giant. During the red giant phase, the Sun will expand to a size that may reach beyond the current orbit of Earth and will become much brighter. This phase is expected to last for about 1 billion years.
Eventually, the Sun will shed its outer layers and become a compact, hot object known as a white dwarf. This final phase is expected to last for trillions of years. So in total, the Sun's lifetime is estimated to be about 10 billion years until it exhausts its fuel and starts to evolve, and then trillions of years as a white dwarf.
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If ocean waves strike the shore every 3.0 s and the horizontal distance between adjacent crests and troughs is 1.0 m, what is the average speed of the waves
The average speed of the waves which strikes the shore is 0.333m/s.
What is average speed?The average speed of any moving object is the ratio of the total distance covered and the total time taken to cover that distance.
If ocean waves strike the shore every 3.0 s and the horizontal distance between adjacent crests and troughs is 1.0 m,
The speed is related to wavelength and frequency as
v = fλ
Wavelength is the distance between the adjacent crest or trough and the frequency is the reciprocal of Time period.
So, speed will be
v =λ/T
Substitute the values, we have
v = 1/3
v = 0.333 m/s
Thus, the speed of the wave is 0.333 m/s
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Define reference point
plz help me
Answer:
a basis or standard for evaluation, assessment, or comparison; a criterion.
Explanation:
Definition of reference point. : something that is used to judge or understand something else The professor used the study as a reference point for evaluating and discussing other theories.
Answer:
something that is used to judge or understand something else
Explanation:
The professor used the study as a reference point for evaluating and discussing other theories.
Globular clusters are important to understanding the Milky Way because Choose one: A. they reveal the size of the Milky Way and Earth's location in it. B. they are so young that they provide information about current star formation. C. they provide information about dwarf ellipticals from which the Milky Way formed. D. the stars in them are highly enhanced in metals.
The correct answer is (A) they reveal the size of the Milky Way and Earth's location in it.
Why are globular clusters important?Globular clusters are densely packed groups of old stars. They are roughly spherical in form and contain hundreds of thousands, if not millions, of stars. Studying them can help astronomers determine the age of the universe or locate the core of a galaxy.
According to Georgia State University there are around 150 identified globular clusters in the Milky Way galaxy. Most are thought to be at least 10 billion years old and contain some of the galaxy's oldest stars. The clusters most likely originated relatively early in the galaxy's evolution, before it flattened into a spiral disc.
Some globular clusters, like as Messier 13 (M13) in Hercules, are visible with the eye.
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If a ball is thrown at a wall at 3 m/s (with NO air resistance), with what velocity will it
hit the wall?
Answer:
3 m/s
Explanation:
have a good day
A droplet grows by condensation from a radius of 2 um to 20 um in 10 min at a temperature of 0°C and a pressure of 70 kPa. Estimate the ambient supersaturation, neglecting the solution and curvature terms in the growth equation. 7. 2. S= 0. 45%
Answer:
the estimated ambient supersaturation is approximately 18.7%.
Explanation:
ln(R2/R1) = (4/3) * S * L * t
Where:
R1 is the initial radius of the droplet (2 um)
R2 is the final radius of the droplet (20 um)
S is the ambient supersaturation (what we need to find)
L is the Kelvin factor, which is dependent on temperature and pressure
t is the time duration (10 min)
Since we are neglecting the solution and curvature terms, we can assume the Kelvin factor (L) to be 1.
Now let's calculate the ambient supersaturation (S) using the given data:
ln(20/2) = (4/3) * S * 1 * 10
ln(10) = (4/3) * 10S
ln(10) = 40S/3
S = (3 * ln(10)) / 40
S ≈ 0.187
To convert the supersaturation to a percentage, we multiply it by 100:
S ≈ 0.187 * 100
S ≈ 18.7%
WILL MARK BRAINLIEST FOR CORRECT ANSWER!! PLEASE HELP ME
3. An object has a mass of 3 Kg hit the wall with initial velocity 4m/s and bounce back with 3.4 m/s. What is the change of momentum of the object?
A.1.8 Kgm/s
B.22.2 Kgm/s
C.-22.2 Kgm/s
D.10.2 Kgm/s
Answer:
The change of momentum of an object can be calculated using the formula Δp = m (Δv) where Δp is the change in momentum, m is the mass of the object and Δv is the change in velocity. In this case, the initial velocity of the object is 4m/s and it bounces back with 3.4 m/s. Therefore, the change in velocity is 4 - 3.4 = 0.6 m/s. The mass of the object is 3 Kg. Thus, the change of momentum of the object is Δp = 3 Kg * 0.6 m/s = 1.8 Kg m/s.
1. 300 meters convert by 1 mile
2. 65 minutes convert by 1 hour
3. 35 yards convert by 1 meter
(show solution)
300 meters = 0.186411 miles, 65 minutes = 1.08333 hours, 35 yards = 32.004 meters
1. To convert 300 meters to miles, you can use the conversion factor 1 mile = 1609.344 meters. So, 300 meters = 300/1609.344 miles = 0.186411 miles.
2. To convert 65 minutes to hours, you can use the conversion factor 1 hour = 60 minutes. So, 65 minutes = 65/60 hours = 1.08333 hours.
3. To convert 35 yards to meters, you can use the conversion factor 1 yard = 0.9144 meters. So, 35 yards = 35*0.9144 meters = 32.004 meters.
In summary:
300 meters = 0.186411 miles
65 minutes = 1.08333 hours
35 yards = 32.004 meters
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Can you please help me figure out the work for the missing quantities?
Answer: set up proportions
Explanation:
an object has mass 0.2 kg, how much force is required to throw it vertically with velocity 5ms
0.2×51000)
Explanation:
change 5ms into cms before multiplying by 0/2 kgs
This waterbottle has a mass of .5 kg. If the net force acting on the bottle is five and to the right what is the bottles acceleration (hint: use formula a=f/m
Answer:
a = 10/s^2
Explanation:
Answer:
a=10 m/s *2 right
Explanation:
The net force (0.5 kg) divided by the mass (5 N) = 10
The force moved the object to the right.
So you Would put this in the equation a=___ m/s *2 _____
And you would get a=10m/s*2 right
HOPE YOU LEARNED SOMETHING SO WHEN WE GO BACK TO SCHOOL YOU WILL KNOW WHAT YOU ARE TALKING ABOUT ! : )
The measurement of body temperature is an example of a variable that uses what scale?A. Interval scaleB. Ordinal scaleC. Nominal ScaleD. Ratio scale
The measurement of body temperature is an example of a variable that uses option A, interval scale.
A scale with an interval has order and a meaningful difference between two values. Temperature (Fahrenheit), temperature (Celsius), pH, SAT score (200-800), and credit score are a few examples of interval variables (300-850).
One variable that uses interval scale is the measurement of body temperature.
Only ratio scales have a genuine zero, even though interval and ratio data can both be categorized, sorted, and spaced equally apart between consecutive values. As 0 is not the lowest attainable temperature, temperature in Celsius or Fahrenheit, for instance, is measured on an interval scale.
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What is the integral of the function x4 in the interval from c to d?Options shown in pictures
Where C is a constant
Now limit should be applied. We do not need to consider the constant when we apply limit as it cancels out
\(\frac{x^5}{5}\text{ from c to d is }\)\(\frac{1}{5}(d^5-c^5)\)Hence the answer is
Find the potential function and the gravitational field intensity function inside and outside of a thin ring with Radius R, in terms of r (the distance from the center of the ring to the field point.) Note: inside R >r, outside r>R. the function will be different.
The potential function and the gravitational field intensity function inside and outside of a thin ring with radius R, in terms of r (the distance from the center of the ring to the field point), are as follows:
Inside the ring (r < R): The potential function is given by V = -GM/r, and the gravitational field intensity function is E = GM/r², where G is the gravitational constant and M is the mass of the ring.
Outside the ring (r > R): The potential function is V = -GM/r + GM/R, and the gravitational field intensity function is E = GM/r², where G is the gravitational constant, M is the mass of the ring, and R is the radius of the ring.
Inside the ring (r < R), the potential function is given by V = -GM/r. This represents the gravitational potential due to the mass of the ring at a point inside the ring. The negative sign indicates that the potential decreases as the distance from the center of the ring decreases. The gravitational field intensity function is E = GM/r², representing the strength of the gravitational field at a point inside the ring. The field intensity decreases as the distance from the center of the ring increases, following an inverse square relationship.
Outside the ring (r > R), the potential function is V = -GM/r + GM/R. In addition to the potential due to the mass of the ring, there is an additional potential term GM/R, which arises from considering the ring as a point mass located at its center. The gravitational field intensity function remains the same as E = GM/r², indicating that outside the ring, the gravitational field follows an inverse square relationship with the distance from the center of the ring.
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The first law of thermodynamics states that energy can neither be created nor destroyed. If this is true then why are we always looking for new sources of energy? Use the 2nd law of thermodynamics to answer this question.
Answer:
The second law of thermodynamics states in an isolated system, the entropy (the amount of thermal energy that cannot be converted into mechanical work, also known as the amount of disorder) always increases, therefore, an isolated system always require an external input (new sources) of energy for there to be orderliness or for the available energy of the system to remain constant or increase
Explanation:
Please help! Will mark brainliest
Answer:
Runner B
Explanation:
its just displacement over change in time
a cable that weighs 8 lb/ft is used to lift 650 lb of coal up a mine shaft 300 ft deep. find the work done.
The total work done in lifting the coal and the cable is 267000 ft lb.
The work done in lifting the coal can be calculated using the equation:
W = F * d
Where W is the work done, F is the force applied, and d is the distance moved. In this case, the force applied is the weight of the coal, which is 650 lb, and the distance moved is 300 ft. So,
W = 650 lb * 300 ft
W= 195000 ft lb
However, we also need to take into account the weight of the cable. The cable weighs 8 lb/ft, so over a distance of 300 ft, it weighs 8 lb/ft * 300 ft = 2400 lb.
The work done in lifting the cable is given by:
W_cable = 2400 lb * 300 ft = 72000 ft lb
The total work done in lifting the coal and the cable is given by:
W_total = W + W_cable
=> 195000 ft lb + 72000 ft lb
=> 267000 ft lb
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What is needed in a market for a good to be considered elastic?
If the amount demand of a product changes more than proportionally as its price rises or falls, then it is said to be elastic.
How is a market made elastic?The more replacements there are for an item, more elastic the good is, according to definition of an elastic good, which is where change in price results in a large movement in demand. Price elasticity of demand is determined by dividing percentage change in quantity required by the percentage change in price.
Products like cars, appliances, and luxury items that are rarely purchased are examples of elastic commodities. In the event that the cost of these products is momentarily high, consumers may decide to put off buying.
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Can the velocity of a body reverse the direction when acceleration is constant? If you think so, give an example.
Consider a particle moving to the left with some speed v. If we take leftward to be the negative direction, then the particle's velocity is -v, and it's moving in the negative direction.
Now give the particle a positive acceleration pointing rightward. The particle will eventually slow to a stop before increasing its speed in the positive direction.
So the answer is yes, the direction in which a body is moving can be reversed with constant acceleration.
Explain how your model is different from the model in the picture
What does your model look like and the one it's being compared to?
Answer:
you should prolly put the model
Explanation:
A body starts with an initial velocity of 10m/s and moves along a straight line with a constant acceletion. When the velocity of the particle is 50m/s, the acceleration is reversed in direction. find the velocity of the particle when it reaches it's starting point.
The velocity of the particle when it reaches the starting point = 70 m/s
Explanation:For the first part of the motion
The initial velocity, u = 10 m/s
The final velocity v = 50 m/s
\(\begin{gathered} v^2=u^2+2as_1 \\ 50^2=10^2+2as_1 \\ 2500-100=2as_1 \\ 2as_1=2400..........(1) \end{gathered}\)For the second part of the motion
The initial velocity, u = 50 m/s
Final velocity, v = 0 m/s
\(\begin{gathered} v^2=u^2-2as_2 \\ 0=50^2-2as_2 \\ 2as_2=2500........(2) \\ where\text{ s}_1\text{ is the distance covered during the first part of the motion} \\ s_2\text{ is the distance covered during the second part of the motion} \\ \end{gathered}\)Add equations (1) and (2)
\(\begin{gathered} 2as_1+2as_2=2400+2500 \\ 2a(s_1+s_2)=4900........(3) \end{gathered}\)Taking the whole motion as a whole
Let the velocity of the particle when it reaches the starting point be vn
\(\begin{gathered} v_n^2=u^2+2a(s_1+s_2) \\ \\ v_n^2=0^2+4900 \\ \\ v_n^2=4900 \\ \\ v_n=\sqrt{4900} \\ \\ v_n=70\text{ m/s} \end{gathered}\)The velocity of the particle when it reaches the starting point = 70 m/s
Two vibrating tuning forks, held side by side, will create a beat frequency of what value if the individual frequencies of the two forks are 342 Hz and 345 Hz, respectively?
When two tuning forks are sounded together, they can produce a phenomenon known as a beat frequency. This is caused by the interference of sound waves produced by the two forks. When two sound waves with slightly different frequencies meet, they will produce a periodic variation in sound intensity. This variation in sound intensity is perceived as a beat frequency.
In this case, the two tuning forks have frequencies of 342 Hz and 345 Hz, respectively. The difference between these two frequencies is:
345 Hz - 342 Hz = 3 Hz
Therefore, the beat frequency will be 3 Hz. This means that the sound intensity will vary at a rate of 3 times per second.
The beat frequency can be calculated by subtracting the frequency of one tuning fork from the frequency of the other. The resulting difference is the beat frequency.
The phenomenon of beat frequency has many practical applications. For example, musicians use it to tune their instruments. They can adjust the pitch of their instruments by listening to the beats produced by two tuning forks and matching the desired frequency.
Beat frequency is also important in the field of acoustics. It is used to measure the frequency of sound waves, which can be useful in a variety of applications such as sonar and acoustic imaging.
In conclusion, the beat frequency produced by two tuning forks with frequencies of 342 Hz and 345 Hz, respectively, will be 3 Hz. This phenomenon is caused by the interference of sound waves produced by the two forks and has many practical applications in the fields of music and acoustics.
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Outside temperatures over a 24-hour period can be modeled by a sinusoidal function. Suppose the high temperature of 77∘F occurs at 6 PM and the average temperature for the 24-hour time period is 59∘F . Find the temperature at 7 AM to the nearest tenth of a degree.
At 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.
What is the approximate temperature at 7 AM?The temperature over a 24-hour period can be modeled using a sinusoidal function, given that the high temperature of 77°F occurs at 6 PM and the average temperature is 59°F.
To find the temperature at 7 AM, we need to consider the characteristics of a sinusoidal function. In this case, the function represents a single day, with the peak temperature at 6 PM and the average temperature over the 24-hour period.
Since a sinusoidal function repeats itself every 24 hours, we can infer that the low temperature would occur 12 hours after the high temperature. Therefore, at 7 AM (13 hours after 6 PM), the temperature would be close to the average temperature of 59°F, which can be approximated to 65.9°F.
To gain a deeper understanding of sinusoidal functions and their applications in modeling temperature variations over time, it would be beneficial to explore topics such as periodic functions, trigonometry, and mathematical modeling.
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A 70kg man runs at a pace of 4 m/s and a 50g meteor travels at 2 km/s. Which has the most kinetic energy?.
Answer:
the 70kg man
Explanation:
because he has more weight and is moving faster
When dropping a grape and a bowling ball from a height, the force of gravity would be identical on each object. True or False
A.
FALSE
B.
TRUE
Answer:
I think true but im not sure sorry if this didnt help/
Explanation:
Answer:
true 50%
Explanation:
An egg is dropped onto a wood floor and breaks. When a different egg (same mass) is dropped the same distance onto a foam pad on the wood floor, it does not break. Why (in terms of physics) does this happen?
A. The pad extends the time so the impulse changes.
B. An egg requires a harder surface so it won’t break.
C. The pad pulls the egg to the floor.
D. Wood is harder than the pad.
Answer:
A.
Explanation:
The pad extends the time so the impulse changes.
Answer:
A. The pad extends the time so the impulse changes
Explanation:
in term of physics it has same mass:)
What could Alex do to make the reaction happen faster than normal?
Answer:
Chris lives farther from the school than Alex lives, and Chris walked to school at a faster rate than Alex walked.
Explanation:
Block A has a mass of 10 kg and block B has a mass of
6 kg. They are connected by a rope and pulley system as
shown in the diagram on the right.
What must the coefficient of static friction be
between block A and the table for neither block to
move?
Acceleration will be zero when there is no movement. The coefficient of static friction is 0.6
What is Friction ?Friction is a force that opposes motion. It is static in a stationary object while dynamic in a moving object.
Given that Block A has a mass of 10 kg and block B has a mass of
6 kg. They are connected by a rope and pulley system as shown in the diagram in the question. Since both blocks are not moving, acceleration a = 0
The weight W on block B = mg
W = 6 × 9.8
W = 58.8 N
This weight will be equal to the tension T pulling block A. That is,
T = μN = W
Where the normal force N on block A = mg
N = 10 × 9.8
N = 98 N
Substitute N and T to find the coefficient of static friction μ
58.8 = 98μ
μ = 58.8/98
μ = 0.6
Therefore, 0.6 must be the coefficient of static friction between block A and the table for neither block to move
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