A silver atom at rest has a mass of about 1. 8×10−25kg. What is the rest energy of a silver atom?

Answers

Answer 1

The rest energy of a silver atom can be calculated using Einstein's famous equation, E=\(mc^{2}\), where E is the energy, m is the mass and c is the speed of light.

Rest energy of a silver atom (E) = mass of silver atom (m) x speed of light \((c)^{2}\)

= 1.8 x \(10^{-25}\) kg x (3 x \(10^{8}\) \(m/s)^{2}\)

= 1.62 x \(10^{8}\) J

This means that even when the silver atom is at rest, it has an enormous amount of energy stored in its mass due to its mass-energy equivalence.

This concept is important in understanding nuclear reactions, where a small amount of mass is converted into energy through the process of nuclear fission or fusion.

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Related Questions

the equation of a wave to a wave to y=0·0055m The equation of a wave is y=0·005 Sin [x (0.5x - 200t) where x and y are in metres and it is in seconds. what is the velocity of the wave?​

Answers

the velocity of the wave is 400m/s

The formula for the velocity of the wave is, V = w/k

where ,  w is the coefficient of t and k is the coefficient of x

now putting values we get, v = 200/0.5 = 400

Hence the velocity of the wave is 400 m/s

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An object in motion will remain in motion and an object at rest will remain at rest until a greater force interrupts it. Explain this concept.

Answers

Answer:

A object, lets say a cup. This cup will never, ever move unless something or someone disturbs it. If something touches or hits this cup the cup will move. But, until the cup gets touched, nothing will EVER make it move.

Explanation:

I hope this helps!!

a metal block increases in tempreture from 15 digree to 60 digree when supplied with 13500 j of heat energy​

Answers

By finding the specific heat, we can expect that the material of the block is copper or silver (or a mix).

Of which type of metal is the block made?

We know that we give 13,500 joules of energy to the metal block (which we assume has a mass of 1kg) and the temperature increases from 15°C to 60°C.

Then the increase is:

60°C - 15°C = 45°C

Then this metal has a specific heat of:

H = 13,500j/(45°C*1 kg) = 300 J/°C*kg

So it could be copper, which has a specific heat of 380J/°C*kg or Silver, which has a specific heat of 240 J/°C*kg (or a mix of these two).

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A cylinder fitted with a piston has a volume of 0.2 m? and contains 1 kg of steam at 300 kPa.
Heat is transferred to the steam until the temperature is 400 C, while the pressure remains
constant. Determine the heat transfer and the work for this process.

Answers

The heat transfer and work for this process are 554.1 kJ and 47,000 J, respectively. The gas law equation (PV = nRT) is used to calculate the final volume.

Step 1: Identify known values and convert them into SI units. Volume = 0.2 m³Pressure = 300 kPa, Temperature = 400 °C, Mass = 1 kg

Step 2: Find the final volume of the system since the pressure is constant. The gas law equation (PV = nRT) is used to calculate the final volume. V₁ = nRT / PInitial volume, V₂ = 0.2 m³, pressure P = 300 kPa = 300,000 Pa, R = 0.287 kJ/kg K (gas constant), and n = m/M, where m = 1 kg and M = 18.01528 kg/kmol (molar mass of steam)

Hence, V₁ = (1 kg × 0.287 kJ/kg K × 673 K) / (300,000 Pa × 18.01528 kg/kmol)

= 0.0435 m³

Step 3: Find the work done during the process.

The work done, W = PΔV, where ΔV is the change in volume.ΔV = V₁ - V₂

= 0.0435 m³ - 0.2 m³

= -0.1565 m³

Hence, W = -300,000 Pa × -0.1565 m³

= 47,000 J (work done by the gas)

Step 4: Determine the heat transfer during the process.

Q = mCΔT, where C is the specific heat capacity of steam at constant pressure. C = 1.847 kJ/kg KΔT

= T₂ - T₁

= 400 °C - 100 °C

= 300 K

Hence, Q = 1 kg × 1.847 kJ/kg K × 300 K

= 554.1 kJ (heat absorbed by the gas)

Therefore, the heat transfer and work for this process are 554.1 kJ and 47,000 J, respectively.

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What is the main force driving the creation of a star?
A.electromagnetic

B.the Big Bang

C.friction

D.gravity

Answers

Answer:

D.gravity

Explanation:

A hunter is standing on flat ground between two vertical cliffs that are directly opposite one another. He is closer to one cliff than to the other. He fires a gun and, after a while, hears three echoes. The second echo arrives 2.1 s after the first, and the third echo arrives 0.5 s after the second. Assuming that the speed of sound is 343 m/s and that there are no reflections of sound from the ground, find the distance between the cliffs. 445.9 Incorrect: Your answer is incorrect. m

Answers

Answer:

531.65 m

Explanation:

Let d₁ be the distance between the hunter and the closer cliff and d₂ be the distance between the hunter and the farther cliff. The speed of sound v = 343 m/s.

t₁ is the time taken for the sound to reach the neared cliff and return back to the hunter as echo. Hence:

t₁ = 2d₁/343

t₂ is the time taken for the sound to reach the farther cliff and return back to the hunter as echo. Hence:

t₂ = 2d₂/343

t₂ - t₁ = 2.1

2d₂/343 - 2d₁/343 = 2.1

d₂ - d₁ = 360.15        (2)

t₃ is the time taken by the third echo as a result of the second echo reaching the nearer cliff. Hence:

t₃ = 2d₁/343

0.5 = 2d₁/343

d₁ = 85.75 m

d₂ - d₁ = 360.15

d₂ - 85.75 = 360.15

d₂ = 445.9 m

The distance between the two cliffs = d₁ + d₂ = 445.9 + 85.75 = 531.65 m

A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1).

Answers

The reading on the scale is equal to the weight of the student which is 646.8 N.

The given parameters;

mass of the student, m = 66 kg

The reading on the scale is determined by applying Newton's second law of motion as follows;

\(R = ma+ mg\\\\R = m(a + g)\\\\R = m(0 + g)\\\\R = mg\)

The student is at rest and not accelerating, a =0

\(R = 66 \times 9.8\\\\R = 646.8 \ N\)

Thus, the reading on the scale is equal to the weight of the student which is 646.8 N.

The complete question is below:

A 66 kg student stands on a very light, rigid board that rests on a bathroom scale at each end as shown in (Figure 1). what is the reading on the scale?

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Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?

Answers

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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A student's pencil rolls off a desk and lands 0.47 m away from the edge of the
desk. The height of the average school desk is 0.90 m.
What was the initial velocity of the pencil in the x-axis?

Answers

Answer: 56

Explanation: i took the quiz

a light wave travels from air into a medium of refractive index 1.54. If the wavelength of the light in air is 5.4 * 10^-7. calculate its wavelength in the medium​

Answers

3.51 × 10^-7m

Explanation:

Refractive index = wavelength of the light in air ÷ wavelength in the medium

wavelength in the medium = wavelength of the light in air ÷ refractive index

= 5.4 * 10^-7 ÷ 1.54

= 3.51 × 10^-7m

A car travels 120 km in the first 2 hours and 100 km in the next 2 hours.

What is the car’s average speed?

240 km/h

440 km/h

55 km/h

128 km/h

Answers

Option C, 55km/h

Working:

The car travels 120km in hours meaning that the speed is 60km per hour.
Then it travels 100km in 2 hours meaning that the speed is 50 km per hour.

The average speed of the speed is (60+50)/2 is 55km/h

Pls mark me brainliest

Complete the missing information for each of the following.
Calculate the energy, height, and velocity at each of the following
points for the 1.5 kg weighted basketball.

(at the top) PE=29.4J KE= h=
(at the halfway point) PE= KE= v= h=
(on the floor) PE= KE= v=

Answers

Answer:

3.141592653 im  king of NYC

Explanation:

how did life evolve from nonliving matter?

Answers

the expansion from the big bang theory

The moving of soil by water

Answers

Erosion is the moving of soil by water, which represent a geological process able to shape the features of different rock layers.

What is the geological erosion?

The geological erosion is the process by which natural forces such as winds and also water may shape a given layer of rock, which occurs at a geological scale because it is a slow phenomenon.

Therefore, with this data, we can see that the erosion process is a slow phenomenon that shape the geographic features of layers of rocks on the Earth surface.

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Which of these stars has the shortest life expectancy?
a. an isolated 1Msun star
b. a 1Msun star in a closed binary system with a 0.8Msun star
c. a 1Msun star in a closed binary system with a 2Msun star

Answers

A 1Msun star in a closed binary system with a 2Msun star.

Systems in which the two stars are close to each other are called close binary star system.

The most massive stars have the shortest lifespans. The reason is that they have most fuel, they burn it so enormously that their lifetimes are very short. As a 1Msun star in a closed binary system with a 2Msun star becomes the massive star so it has the shortest life expectancy.

a. No, an isolated 1Msun star has not the shortest life expectancy.

b. No, a 1Msun star in a closed binary system with a 0.8Msun star has not the shortest life expectancy.

c. Yes, A 1Msun star in a closed binary system with a 2Msun star has the shortest life expectancy.

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A spring has an unstretched length of 0.2 m. A 0.2 kg mass hanging from the spring stretches it to an equilibrium length of 0.3 m. Suppose the mass is pulled down to where the spring’s length is 0.5 m. When it is released, it begins
to oscillate. What is the amplitude of the oscillation?

Answers

I think it is c
But there could be some other people that think differently

Maria throws two stones from the top edge of a building with a speed of 20 m/s. She throws one straight down and the other straight up. The first one hits the street in a time t1. How much later is it before the second stone hits

Answers

Maria throws two stones from the top edge of a building at a speed of 20 m/s, The time is mathematically given as

t=4.5 sec.

How much later is it before the second stone hits?

Generally, the equation for speed  is mathematically given as

V = u+at

Therefore

0 = 22-9.8xt.

t = 22 /9.8 sec

t = 2.24489.

The same time will be taken from max^m height to point O

The extra time is taken

t=4.49 sec.

t=4.5 sec.

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for what size objects mmust we use a wave model to correctly descfibe th interactions of light with the objects

Answers

1580nm

Object size should be comparable to wavelength of light

so it is comparable of 400nm to 700nm

\(n=\frac{10^-^3}{632.8*10^-^9}\)    

1580 nm

What is wavelength?

It is measured in the direction of the wave.The distance from one crest to another, or from one trough to another, of a wave is defined as its wavelength (which may be an electromagnetic wave, a sound wave, or any other wave).  Because wavelength is a distance/length, it is measured in length units such as metres, centimetres, milimetres, nanometres, and so on.

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10-kg box is sliding across an ice rink at 10 m/s . A skater exerts a constant force of 10 N against it. How long will it take for the box to come to a complete stop?

Answers

Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

difference between longitudnal and transverse waves??

Answers

The difference between longitudinal and transverse waves is with respect to their mediums.

Transverse waves and longitudinal waves are two different forms of waves that differ in the direction that the medium is moving. When the medium's vibration is parallel to the wave direction, a transverse wave is produced. At a right angle to the wave's direction of travel, amplitude is recorded. When the medium being employed vibrates parallel to direction of wave, longitudinal waves are produced.

Amplitude is measured at a zero-degree angle to the wave's travel direction. Transverse waves include crests and troughs, whereas longitudinal waves have compressions and rarefactions. While longitudinal waves can move through fluids like liquids and gases, transverse waves need a relatively rigid medium to do so.

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Which of Galileo's theories drew fire from the Catholic Church and led to his
house arrest?

Answers

Answer:

imma have to come back to you on that one

Answer:

The Sun is at the center of the solar system and the planets move around it.

Explanation:pluto/edmentum

14 What is the weight of each of
the following masses on Eth?
a) 2 kg
b) 3.5kg
c) 5.25 kg
Newton’s

14 What is the weight of each ofthe following masses on Eth?a) 2 kgb) 3.5kgc) 5.25 kgNewtons

Answers

Explanation:

On earth,

g=10 m/s^2

When M=2 kg,

weight on earth=2×10

=20N

When M=3.5 kg,

weight on Earth=3.5×10

=35N

When M=5kg,

weight on Earth=5.25×10

=52.5N

What is a closed system?

A. A system in which no work is done
B. A system that can exchange matter with its surroundings
C. A system that cannot exchange matter with its surroundings
D. A system in which no heat flows​

Answers

Answer:

C

Explanation:

A closed system does not allow transfer of matter in or out of the system

what is her acceleration (give components)? enter the radial and tangential components of the acceleration using two significant figures separated by a comma

Answers

Acceleration is defined as the rate of the change of velocity, and it has both the magnitude and the direction.

The direction of acceleration can be expressed in terms of its radial and tangential components, which are perpendicular to each other. The radial component of acceleration is directed towards the center of rotation, while the tangential component is directed tangentially to the circular path of motion. To calculate the components of acceleration, one would need to know the object's velocity and its rate of change with respect to time, as well as the radius and direction of the circular path.

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In this graph (mass vs volume), what does the slope represent? I will mark brainliest​

In this graph (mass vs volume), what does the slope represent? I will mark brainliest

Answers

Answer:

Slope y2-y1/x2-x1

m=mass/volume

slope represents density(g/ml)

Explanation:

PLS MARK BRAINLIEST

Slope = Mass/ Volume = Density. The given slope represents Density.

Thus, Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density.

Grams per cubic centimeter are a typical unit of measurement for density.  For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated.

The volume of a body is equal to the mass multiplied by the density (M = Vd), while the volume is equal to the mass divided by the density (V = M/d). Density provides a straightforward way to determine a body's mass from its volume, or vice versa.

Thus, Slope = Mass/ Volume = Density. The given slope represents Density.

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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.

Answers

No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.

This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.

i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.

ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.

The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.

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Consider a spring that does not obey Hooke's law very faithfully. One end of the spring is fixed. To keep the spring stretched or compressed an amount x, a force along the x-axis with x-component Fx=kx−bx2+cx3 must be applied to the free end. Here k=100N/m, b=700N/m2, and c=12000N/m3. Note that x>0 when the spring is stretched and x<0 when it is compressed.

Answers

Answer:

The work done will be 0.115 J.

Explanation:

Given that,

\(k=100\ N/m\)

\(b=700\ N/m^2\)

\(c=12000\ N/m^3\)

A force along the x-axis with x-component,

\(F(x)=kx-bx^2+cx^3\)

Suppose, How much work must be done to stretch this spring by 0.050 m from its unstretched length?

We need to calculate the work done

Using formula of work done

\(W(x)=\int{F(x)dx}\)

Put the value into the formula

\(W(x)=\int{(kx-bx^2+cx^3)dx}\)

\(W(x)=\dfrac{kx^2}{2}-\dfrac{bx^3}{3}+\dfrac{cx^4}{4}\)

Put the value of k,b,c and x

\(W(0.050)=\dfrac{100\times(0.050)^2}{2}-\dfrac{700\times(0.050)^3}{3}+\dfrac{12000\times(0.050)^4}{4}\)

\(W(0.050)=0.115\ J\)

Hence, The work done will be 0.115 J.

The value of spring displacement is greater than zero. Therefore, spring is stretched.

Force in spring :

  It is given as,  \(F=kx\)

Where k is constant and x is amount of displacement.

The force function is given that,

       \(F(x)=kx-bx^{2}+cx^{3}\)

Here given that,  \(k=100N/m, b=700N/m^{2} , c=12000N/m^{3} .\)

Substitute all values in above equation,

           \(F(x)=100x-700x^{2} +12000x^{3}\)

To check, the spring is stretched or it is compressed.

Substitute f(x) = 0

          We get x is greater than zero.

Thus, The value of spring displacement is greater than zero. Therefore, spring is stretched.

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What is the expected ratio of free-hanging earlobes to attached earlobes in the offspring

Answers

The expected ratio of free-hanging earlobes to attached earlobes in the offspring is 1:2.

How to illustrate the ratio?

The diagram depicts a Punnett square used to predict the earlobe shape of two parents' offspring. The capital A represents free-hanging earlobes, while the lowercase a represents attached earlobes.

The Punnett square is a square diagram used to predict genotypes of a specific cross or breeding experiment. It is named after Reginald C. Punnett, who invented it in 1905. Biologists use the diagram to calculate the likelihood of an offspring having a specific genotype.

In this case, the genotype rato based on the attached diagram is 1:2.

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What is the expected ratio of free-hanging earlobes to attached earlobes in the offspring

how long does it take to do 278J of work with 17 W of power

Answers

Answer:

t= 278/17 =16.35s

Explanation:

p=w/t

t=w/p

∴t=278/17

Answer:

t=16.4

Explanation:

power = energy/time

p=e/t

17=278/t

t=278/17

t=16.352941

t=16.35

t=16.4

Two hours after the start of a 100-kilometer bicycle race, a cyclist passes the 70-kilometer mark while riding at a velocity of 37 kilometers per hour.
(A) Find the cyclist's average velocity during the first two hours of the race

Answers

The average velocity of the cyclist during the first two hours of the race is 37 km/h.

A cyclist passes the 70-kilometer mark while riding at a velocity of 37 kilometers per hour.The total distance covered in the race = 100 km.

Let's find the time taken by the cyclist to reach the 70 km mark. To calculate the time taken to cover the 70 km distance, use the formula:

v = d/t

Where:

v = velocity (km/h)d = distance (km)t = time (h)

Substitute the given values in the above formula:

37 = 70/tt = 70/37h

On substituting this value in the formula for total time, the time taken by the cyclist to cover the remaining 30 km can be found as:

total time = 2 + 70/37 + 30/37 total time = 2.81 h

Let's calculate the cyclist's average velocity during the first two hours of the race by using the formula for average velocity:

Average velocity = Total distance / Total time The distance covered during the first two hours = 2 × 37 = 74 km Average velocity = (74 km) / (2 h) = 37 km/h

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