A shell (a large bullet) is shot with an initial speed of 20 m/s, 60 degrees above the horizontal. At the top of the trajectory, the bullet explodes into two fragments of equal mass. One fragment has a speed of zero just after the explosion and simply drops straight down. How far from the gun does the other fragment land, assuming that the ground is level and that the air drag is negligible.

Answer:

37500 N

Explanation:

F = ma

F = 7500 (5 m/s^2) = 37500 N

Answer:

6.29 meters.

Explanation:

, where v is the speed of wave and f is the frequency of wave.

We are given that ,

The speed of sound is 346 m/s.

i..e v=346 m/s

A sound wave travels at a frequency of 55 H.

i..e f=55

the wavelength would be 6.29 meters.

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The cyclist accelerates at 1.2 m / s² after 2 seconds he reaches a speed of 2.4 m / s, then the momentum at this point would be 211.2 kg-m/s, therefore the correct answer is option D.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem a cyclist and his bicycle has a combined mass of 88 kg and a combined weight of 862.4 N. The cyclist accelerates at 1.2 m/s2. After 2 seconds he reaches a speed of 2.4 m/s.

The momentum of the cyclist = 88 × 2.4

                                                 = 211.0 kgm/s

Thus, the momentum of the cyclist would be  211.0 kgm/s.

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The equation supports his conclusion is about calories

\((2720 calories - 2700 calories) * f'\)\(=0.2\)

Calories are a unit of measurement used to measure the energy value of food. The average person needs to consume a certain number of calories each day in order to maintain their body weight. Eating too many calories can lead to weight gain, while eating too few can lead to weight loss.The ratio of calories ingested to calories burnt via exercise must be maintained in order to maintain a healthy weight.

Assuming Sam's current daily calorie intake is 2700 calories, the equation that supports his conclusion is:

Weight (in pounds) = \((2720 calories - 2700 calories) * f'\)

Weight (in pounds) = \(0.2 * f'\)

Weight (in pounds) =  \(0.2\)

Therefore,The equation supports his conclusion is

\((2720 calories - 2700 calories) * f'\)\(=0.2\)

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complete question:(e) suppose that sam reads about f' in this study and draws the following conclusion: if sam increases his average calorie intake from 2700 to 2720 calories per day, then his weight will increase by approximately 0.2 pounds. fill in the blanks below so that the equation supports his conclusion.

f' (           )=(       )

Answer:

a) 1.2 m/s

b) 0.350 m

c) 1.2 m/s

d) 0.250 m

Explanation:

a)

       \(v = \lambda * f (1)\)

       \(v = \lambda * f = 6.0 m * 0.2 1/s = 1.2 m/s (3)\)

b)

       ⇒ A = Δd/2 = 0.700m/2 = 0.350 m (4)

c)

d)

Answer:

nice try but it's plasma membrane

The cell that is known to produce their own food should have a central vacuole. The correct option is A.

A vacuole is a cell organelle that is membrane-bound. Vacuoles are generally small in animal cells and help to sequester waste products.

Vacuoles in plant cells help to retain water balance. A solo vacuole can sometimes take up the maximum of the interior space of a plant cell.

Plant cells have much larger vacuoles than animal cells. When a plant cell stops growing, it usually has one very large vacuole.

That vacuole can sometimes take up more than half of the cell's volume. The vacuole can hold a lot of water or food.

The given cell is known to be round and incapable of producing its own food, so it must be having a central vacuole.

The correct option is A.

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Answer:

VR = Velocity of effort / Velocity of Load

Explanation:

The ratio of the out-lever to the in-lever (length of the resistance arm to effort arm) is known as the velocity ratio (VR). It indicates that the distance covered by effort is four times that covered by the load.

The load-to-effort ratio of a machine, or alternatively, the output-to-input ratio of a machine, is known as its mechanical advantage. Another definition of velocity ratio is the ratio of the velocity of effort to the velocity of load.

When a machine has a force ratio of 4 and a velocity ratio of 4, this indicates that the weight moved is multiplied by 4 and the distance moved by the effort is multiplied by 4 at the same time.

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The centripetal acceleration of this ball is equal to 12 \(m/s^2\)

Given the following data:

Radius = \(\frac{Diameter}{2} = \frac{1.5}{2} = 0.75 \;meters\)

To find the centripetal acceleration of this ball:

The acceleration of an object along a circular track is referred to as centripetal acceleration.

Mathematically, the centripetal acceleration of an object is given by the formula:

\(A_c = \frac{V^2}{r}\)

Where:

V is the velocity of an object.

Substituting the given parameters into the formula, we have;

\(A_c = \frac{3^2}{0.75}\\\\A_c = \frac{9}{0.75}\\\\A_c = \frac{9}{0.75}\)

Centripetal acceleration = 12 \(m/s^2\)

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Answer:

The cooler air from region of up to 30degree latitude belt on both sides of the equator ,rushes toward the equator ,to take the place of warm rising air. This makes the wind to blow from north and south direction toward equators

The displacement of the runner after four seconds is 78.4 m.

We know that in this case, we are dealing with a case of an object that has a motion under gravity. We are told that the road runner an fell straight down off a cliff. The fact that we have been told that the runner just fell down the cliff means that the initial velocity of the runner would have to be taken in this context as zero since the runner was dropped from a height as shown.

Acceleration of the runner (g) = 9.8 m/s^2

Initial velocity of the runner (u) = 0 m/s

Time take (t) = 4 seconds

We then have;

h = ut + 1/2gt^2

If we then know that the initial velocity of the person is zero, then we have;

h = 1/2gt^2

h = 0.5 * 9.8 * (4)^2

h = 78.4 m

The height is 78.4 m.

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The  molecule of hydrogen peroxide contains four atoms.

The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is:

O2 + 2H2 → 2H2O2

This equation shows that one molecule of oxygen (O2) reacts with two molecules of hydrogen (H2) to produce two molecules of hydrogen peroxide (H2O2).

We are given that one liter of oxygen (O2) combines with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2). Since one mole of any gas at standard temperature and pressure (STP) occupies 22.4 liters, we can assume that one mole of oxygen (O2) reacts with one mole of hydrogen (H2) to produce one mole of hydrogen peroxide (H2O2) at STP.

Using Avogadro's number (6.022 x 10^23), we can calculate the number of molecules of each substance in one mole:

Oxygen (O2): 1 mole = 6.022 x 10^23 molecules

Hydrogen (H2): 1 mole = 6.022 x 10^23 molecules

Hydrogen peroxide (H2O2): 1 mole = 6.022 x 10^23 molecules

From the balanced chemical equation, we know that two molecules of hydrogen peroxide (H2O2) are produced for every one molecule of oxygen (O2) that reacts. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of oxygen (O2) that react.

Since we are given that one liter of oxygen (O2) reacts with one liter of hydrogen (H2) to produce one liter of hydrogen peroxide (H2O2), we can say that the volumes of the gases are proportional to their number of molecules. Therefore, the number of molecules of hydrogen peroxide (H2O2) produced is also equal to the number of molecules of hydrogen (H2) that react.

So, we can start with one mole of hydrogen (H2) and use the balanced chemical equation to find the number of moles of hydrogen peroxide (H2O2) produced:

1 mole H2 → 2 moles H2O2

Since one molecule of hydrogen peroxide (H2O2) contains two hydrogen atoms and two oxygen atoms, we can find the total number of atoms in a molecule of hydrogen peroxide:

2 hydrogen atoms + 2 oxygen atoms = 4 atoms

Therefore, a molecule of hydrogen peroxide contains four atoms.

In summary:

The chemical equation for the reaction between oxygen and hydrogen to form hydrogen peroxide is: O2 + 2H2 → 2H2O2

Since the number of molecules of hydrogen peroxide (H2O2) produced is equal to the number of molecules of hydrogen (H2) that react, we can find the number of atoms in a molecule of hydrogen peroxide by considering the atoms in a molecule of hydrogen. Therefore, a molecule of hydrogen peroxide contains four atoms (two hydrogen atoms and two oxygen atoms).

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The speed of the spring from its initial position is 0.8 m/s.

The speed of the spring after it descended from the given position is calculated by applying the principle of conservation of energy.

K.E = U

¹/₂mv² = ¹/₂kx²

mv² = kx²

v² = kx² / m

v = √ ( kx² / m )

where;

The speed of the spring after descending the given distance is calculated as;

v = √ ( 850 x 0.049² / 3.2 )

v = 0.8 m/s

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Answer:

4 bobux

Explanation:

one bobux

two bobux

three bobux

four bobux

Answer:

equal

Explanation:

If all three corresponding sides are equal and all three corresponding angles are identical in measure, two triangles are said to be congruent. These triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other. The symbol of congruence is' ≅'.

Congruent means equal, as it is a term used to describe two or more objects or figures that have the same shape and size.

When two or more figures or things have the same size and shape, they are said to be congruent.

When we state that two things or figures are congruent, we mean that their lengths, angles, and proportions are all the same.

The idea of congruence is that there should be no distinction or contrast between the things being compared. It denotes complete equality and a perfect match.

Congruence informs us that all geometric shapes, including line segments, angles, triangles, and others, are the same and can be placed on one another without overlap or gaps.

Thus, a fundamental idea in geometry called congruence enables us to evaluate and contrast geometric forms and their characteristics.

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a) The angular velocity of the turntable after 0.200 s is 0.430 rev/s. b) the turntable has spun through 0.0088 revolutions in this time interval. c) the tangential speed of a point on the rim of the turntable at t = 0.002 s is 0.094 m/s.

The coefficient of kinetic friction between the object and the rough surface is 0.083. We can use the work-energy principle to solve this problem. According to the principle, the work done by all forces acting on an object is equal to the change in its kinetic energy.

The work done by the force of friction is given by W_friction = -f_k * d, where f_k is the force of kinetic friction and d is the distance traveled. The change in kinetic energy of the object is given by ΔK = K_f - K_i = (1/2) * m * v_\(f^2\) - (1/2) * m * v_\(i^2.\)

Since the object is moving on a horizontal surface, the work done by gravity is zero. Therefore, we have W_friction = ΔK.

Substituting the given values, we get:

-f_k * d = (1/2) * m * v_f^2 - (1/2) * m * v_\(i^2\)

-f_k * 8.0 m = (1/2) * m * (2.0 \(m/s)^2\) - (1/2) * m * (9.0\(m/s)^2\)

Simplifying and solving for f_k, we get:

f_k = (m/8.0 m) * [(1/2) * (2.0 \(m/s)^2\)- (1/2) * (9.0 \(m/s)^2\)]

f_k = 0.813 \(m/s^2\)

The coefficient of kinetic friction is given by μ_k = f_k / N, where N is the normal force. Since the object is moving horizontally, the normal force is equal to the weight of the object, which is N = m * g, where g is the acceleration due to gravity.

Substituting the value of f_k and N, we get:

μ_k = f_k / N = 0.813 \(m/s^2\) / (m * g)

The value of g is approximately 9.8 \(m/s^2\). Therefore, the coefficient of kinetic friction is:

μ_k = 0.083

Therefore, the coefficient of kinetic friction between the object and the rough surface is 0.083.

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The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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At point B, the ball is moving at a speed of around 2.05 m/s. At point C, the ball is moving at a speed of roughly 3.67 m/s.

Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.

(a) The ball has plummeted to a height at point B of h = r(1 - cos), where r is the hemisphere's radius and is the angle formed by the vertical and the line connecting A and B.

The ball loses as much potential energy as it gains in kinetic energy:

mgh = (1/2)mv² + (1/2)Iω²

Since the ball is rolling without slipping, we have v = rω. Also, for a solid sphere or ball, I = (2/5)mr^2.

By simplifying and substituting these formulas, we obtain:

mgh = (7/10)mv²

Solving for v, we get:

v = √((10/7)gh)

Substituting the given values, we get:

v = √((10/7) x 9.8 m/s² x 0.5 m x (1 - cos(30°)))

≈ 2.05 m/s

(b) The ball has dropped through a height of h = 2r at point C. Applying the same simplifications and conservation of energy equation as before, we arrive at:

mgh = (7/5)mv²

Solving for v, we get:

v = √((5/7)gh)

By simplifying and substituting these formulas, we obtain:

v = √((5/7) x 9.8 m/s² x 1.0 m)

≈ 3.67 m/s.

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Answer:

120 km/hr

Explanation:

Let D be the distance between the rocket and the camera as the rocket is moving upwards. Let d be the distance the rocket moves and L be the distance between the camera and the base of the rocket = 4 km.

Now, at any instant, D² = d² + L²

= d² + 4²

= d² + 16 since the three distances form a right-angled triangle with the distance between the rocket and the camera as the rocket is moving upwards as the hypotenuse side.

differentiating the expression to find the rate of change of D with respect to time, dD/dt ,we have

d(D²)/dt = d(d² + 16)/dt

2DdD/dt = 2d[d(d)/dt]

dD/dt = 2d[d(d)/dt] ÷ 2D

Now d(d)/dt = vertical speed of rocket = 200 km/hr

dD/dt = 200d/D  [D = √(d² + 16)]

dD/dt = 200d/[√d² + 16]

Now substituting d = 3 km, the distance the rocket has risen into the equation, we have

dD/dt = 200(3)/[√(3² + 16)]

dD/dt = 600/[√(9 + 16)]

dD/dt = 600/√25

dD/dt = 600/5

dD/dt = 120 km/hr

So,  the speed at which the distance from the camera to the rocket changing when the rocket has risen 3 km is 120 km/hr.

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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We will have the following:

a)

b)

c)

d)

e)

So, the time it takes is sqrt(10) s, that is approximately 3.2s.

f)

So, the final velocity is approximately 36.4 m/s.

So, the angle would be approximately 58.5°.

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

\((P_{1})-(P_{2})=P_{3}\)

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

\((85) - 85 = P_{3}\\P_{3}= 0\)

There is no movement of any of the balls, they remain at rest after the impact.

Answer:

75 cm/second.

Explanation:

Formula:

Walking speed = stride length / time per step

Walking speed = 90cm/time per step

                         = 90cm/1.2 seconds (a common estimate time per step)

                         = 75cm/second.

Explanation:

ur answer is in attachment.

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Explanation:

Force applied on the box = 20 N

Displacement, s = 10 m

Time taken = 5 sec

According to first condition of the question, we could find the value of work done

i.e

Work done = force × displacement

= 20 × 10

= 200 Joule

According to second condition of the question, we could find the value of power

i.e

Power = work done/Time taken

= 200/5

= 40 watt.

Hope it helpful!!!!!!!!!!!!

Answer:

(a) 1.73 m/s²

(b) 18 s

Explanation:

Part a)

To calculate the minimum constant acceleration, we will use the following equation

Where vf is the final velocity, v0 is the initial velocity, a is the acceleration and x is the distance traveled.

Now, convert 112 km/h to m/s as follows

Then, we can replace vf = 31.11 m/s, v0 = 0 m/s, x = 280 m and solve for a, so

Therefore, the acceleration is 1.73 m/s².

Part b)

To calculate the time, we will use the following equation

Replacing x = 280 m, v0 = 0 m/s, and a = 1.73 m/s² and solving for t, we get:

Then, the aircraft becomes air airborne after 18 seconds