A set of weights includes a 10 lb barbell and 8 pairs of weight plates. Each pairof plates weighs 20lbs. If x pairs of plates are added to the barbell, the total weight ofthe barbell and plates in points can be represented by (x) = 20x + 10.What is the range of the function for this situation?(A.2A)A {0,1,2,3,4,5,6,7,8}B {10, 30, 50, 70, 90, 110, 130, 150, 170}с {0,2,4,6,8}D {10,50, 90, 130, 170}

The initial temperature of the soda is 22 degrees Celsius, and its temperature after 20 minutes is approximately 10 degrees Celsius.

To find the initial temperature of the soda, we need to evaluate the temperature function T(x) at x = 0.

T(x) = -5 + 27e^(-0.03x)

T(0) = -5 + 27e^(-0.03(0))

T(0) = -5 + 27e^0

Since any number raised to the power of 0 is 1, we have:

T(0) = -5 + 27(1)

T(0) = -5 + 27

T(0) = 22

Therefore, the initial temperature of the soda is 22 degrees Celsius.

To find the temperature of the soda after 20 minutes, we evaluate the temperature function at x = 20.

T(x) = -5 + 27e^(-0.03x)

T(20) = -5 + 27e^(-0.03(20))

T(20) = -5 + 27e^(-0.6)

Using a calculator, we can compute e^(-0.6) ≈ 0.5488.

T(20) = -5 + 27(0.5488)

T(20) = -5 + 14.8152

T(20) ≈ 9.8152

Therefore, the temperature of the soda after 20 minutes is approximately 10 degrees Celsius (rounded to the nearest degree).

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Answer:

(1, 8 )

Step-by-step explanation:

A translation of 2 units left means subtracting 2 from the x- coordinate

A translation of 4 units up means adding 4 to the y- coordinate

Z (3, 4 ) → Z' (3 - 2, 4 + 4 ) → Z' (1, 8 )

Given

To find

Let the purchase value be P,

ATQ,

P -3 x 0.1P = Rs 43,740

P-0.3P = Rs 43,740

0.7P = Rs 43,740

P = Rs 43,740/0.7

P = Rs 62,486 (approx)

Hence, the purchase value of the machine would be Rs 62,486

Answer:    x=67

Step-by-step explanation:

All of the angles add up to 180 for a triangle

38 + 75 + x = 180               >combine like terms (the numbers)

113 + x = 180                       >subtract 113 from both sides

x=67

Answer:

Step-by-step explanation:

We know that,

\( \sf \: By \: Using \: Angle \: sum \: property \: of \: triangle\)

\( \large \sf \: → x +38° + 75° = 180°\)

\( \large \sf \: → x + 113 = 180°\)

\( \large \sf→ x = 180°- 113°\)

\( \boxed{\large \bf→ x = 67° }\)

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

Step-by-step explanation:

Let slice of pizza cost x and a 12-ounce cola cost y.

Then Sara's order cost: 2x+y=3

and Sydney's order cost: 3x+2y=4.75

From the first equation we have: y=3-2x and put this to the second equation:

3x+2(3-2x)=4.75

3x+6-4x=4.75

x=1.25

y=3-1.25*2=0.50

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

Answer:

12

Step-by-step explanation:

Given z = 3 + i, right away we can find

(a) square

z ² = (3 + i )² = 3² + 6i + i ² = 9 + 6i - 1 = 8 + 6i

(b) modulus

|z| = √(3² + 1²) = √(9 + 1) = √10

(d) polar form

First find the argument:

arg(z) = arctan(1/3)

Then

z = |z| exp(i arg(z))

z = √10 exp(i arctan(1/3))

or

z = √10 (cos(arctan(1/3)) + i sin(arctan(1/3))

(c) square root

Any complex number has 2 square roots. Using the polar form from part (d), we have

√z = √(√10) exp(i arctan(1/3) / 2)

and

√z = √(√10) exp(i (arctan(1/3) + 2π) / 2)

Then in standard rectangular form, we have

\(\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right)\right)\)

and

\(\sqrt z = \sqrt[4]{10} \left(\cos\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right) + i \sin\left(\dfrac12 \arctan\left(\dfrac13\right) + \pi\right)\right)\)

We can simplify this further. We know that z lies in the first quadrant, so

0 < arg(z) = arctan(1/3) < π/2

which means

0 < 1/2 arctan(1/3) < π/4

Then both cos(1/2 arctan(1/3)) and sin(1/2 arctan(1/3)) are positive. Using the half-angle identity, we then have

\(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}\)

\(\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}\)

and since cos(x + π) = -cos(x) and sin(x + π) = -sin(x),

\(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1+\cos\left(\arctan\left(\dfrac13\right)\right)}2}\)

\(\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{1-\cos\left(\arctan\left(\dfrac13\right)\right)}2}\)

Now, arctan(1/3) is an angle y such that tan(y) = 1/3. In a right triangle satisfying this relation, we would see that cos(y) = 3/√10 and sin(y) = 1/√10. Then

\(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1+\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10+3\sqrt{10}}{20}}\)

\(\sin\left(\dfrac12 \arctan\left(\dfrac13\right)\right) = \sqrt{\dfrac{1-\dfrac3{\sqrt{10}}}2} = \sqrt{\dfrac{10-3\sqrt{10}}{20}}\)

\(\cos\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}\)

\(\sin\left(\dfrac12 \arctan\left(\dfrac13\right)+\pi\right) = -\sqrt{\dfrac{10-3\sqrt{10}}{20}}\)

So the two square roots of z are

\(\boxed{\sqrt z = \sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}\)

and

\(\boxed{\sqrt z = -\sqrt[4]{10} \left(\sqrt{\dfrac{10+3\sqrt{10}}{20}} + i \sqrt{\dfrac{10-3\sqrt{10}}{20}}\right)}\)

Answer:

\(\displaystyle \text{a. }8+6i\\\\\text{b. }\sqrt{10}\\\\\text{c. }\\\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}+i\sqrt{\frac{\sqrt{10}-3}{2}},\\-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}-i\sqrt{\frac{\sqrt{10}-3}{2}}\\\\\\\text{d. }\\\text{Exact: }z=\sqrt{10}\left(\cos\left(\arctan\left(\frac{1}{3}\right)\right), i\sin\left(\arctan\left(\frac{1}{3}\right)\right)\right),\\\text{Approximated: }z=3.16(\cos(18.4^{\circ}),i\sin(18.4^{\circ}))\)

Step-by-step explanation:

Recall that \(i=\sqrt{-1}\)

Part A:

We are just squaring a binomial, so the FOIL method works great. Also, recall that \((a+b)^2=a^2+2ab+b^2\).

\(z^2=(3+i)^2,\\z^2=3^2+2(3i)+i^2,\\z^2=9+6i-1,\\z^2=\boxed{8+6i}\)

Part B:

The magnitude, or modulus, of some complex number \(a+bi\) is given by \(\sqrt{a^2+b^2}\).

In \(3+i\), assign values:

\(|z|=\sqrt{3^2+1^2},\\|z|=\sqrt{9+1},\\|z|=\sqrt{10}\)

Part C:

In Part A, notice that when we square a complex number in the form \(a+bi\), our answer is still a complex number in the form

We have:

\((c+di)^2=a+bi\)

Expanding, we get:

\(c^2+2cdi+(di)^2=a+bi,\\c^2+2cdi+d^2(-1)=a+bi,\\c^2-d^2+2cdi=a+bi\)

This is still in the exact same form as \(a+bi\) where:

Thus, we have the following system of equations:

\(\begin{cases}c^2-d^2=3,\\2cd=1\end{cases}\)

Divide the second equation by \(2d\) to isolate \(c\):

\(2cd=1,\\\frac{2cd}{2d}=\frac{1}{2d},\\c=\frac{1}{2d}\)

Substitute this into the first equation:

\(\left(\frac{1}{2d}\right)^2-d^2=3,\\\frac{1}{4d^2}-d^2=3,\\1-4d^4=12d^2,\\-4d^4-12d^2+1=0\)

This is a quadratic disguise, let \(u=d^2\) and solve like a normal quadratic.

Solving yields:

\(d=\pm i \sqrt{\frac{3+\sqrt{10}}{2}},\\d=\pm \sqrt{\frac{{\sqrt{10}-3}}{2}}\)

We stipulate \(d\in \mathbb{R}\) and therefore \(d=\pm i \sqrt{\frac{3+\sqrt{10}}{2}}\) is extraneous.

Thus, we have the following cases:

\(\begin{cases}c^2-\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\\c^2-\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\end{cases}\\\)

Notice that \(\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2\). However, since \(2cd=1\), two solutions will be extraneous and we will have only two roots.

Solving, we have:

\(\begin{cases}c^2-\left(\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3 \\c^2-\left(-\sqrt{\frac{\sqrt{10}-3}{2}}\right)^2=3\end{cases}\\\\c^2-\sqrt{\frac{5}{2}}+\frac{3}{2}=3,\\c=\pm \sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}\)

Given the conditions \(c\in \mathbb{R}, d\in \mathbb{R}, 2cd=1\), the solutions to this system of equations are:

\(\left(\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}, \sqrt{\frac{\sqrt{10}-3}{2}}\right),\\\left(-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}},- \frac{\sqrt{10}-3}{2}}\right)\)

Therefore, the square roots of \(z=3+i\) are:

\(\sqrt{z}=\boxed{\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}+i\sqrt{\frac{\sqrt{10}-3}{2}} },\\\sqrt{z}=\boxed{-\sqrt{\sqrt{\frac{5}{2}}+\frac{3}{2}}-i\sqrt{\frac{\sqrt{10}-3}{2}}}\)

Part D:

The polar form of some complex number \(a+bi\) is given by \(z=r(\cos \theta+\sin \theta)i\), where \(r\) is the modulus of the complex number (as we found in Part B), and \(\theta=\arctan(\frac{b}{a})\) (derive from right triangle in a complex plane).

We already found the value of the modulus/magnitude in Part B to be \(r=\sqrt{10}\).

The angular polar coordinate \(\theta\) is given by \(\theta=\arctan(\frac{b}{a})\) and thus is:

\(\theta=\arctan(\frac{1}{3}),\\\theta=18.43494882\approx 18.4^{\circ}\)

Therefore, the polar form of \(z\) is:

\(\displaystyle \text{Exact: }z=\sqrt{10}\left(\cos\left(\arctan\left(\frac{1}{3}\right)\right), i\sin\left(\arctan\left(\frac{1}{3}\right)\right)\right),\\\text{Approximated: }z=3.16(\cos(18.4^{\circ}),i\sin(18.4^{\circ}))\)

The equation for the proportion, p, of consumers who shop with coupons is: p = C/N where C is the number of consumers who use coupons and N is the total number of consumers asked.

An equation is a mathematical statement that indicates the equality of two expressions. It consists of two expressions separated by an equal sign (=). The expression on the left side of the equal sign is equivalent to the expression on the right side. Equations can have one or more variables, which are usually represented by letters such as x, y, or z. The goal in solving an equation is to determine the value(s) of the variable(s) that make the equation true. This involves manipulating the expressions on both sides of the equal sign using algebraic operations such as addition, subtraction, multiplication, and division, to isolate the variable on one side of the equation. Equations are used in many areas of mathematics and science to represent relationships between variables and to solve problems. They are also used in various fields such as engineering, physics, and economics to model real-world situations and make predictions based on mathematical analysis.

Here,

This equation represents the ratio of the number of consumers who use coupons to the total number of consumers. It is commonly used in statistics and market research to measure the prevalence of a certain behavior or preference among a population. By calculating the proportion of consumers who use coupons, businesses can make informed decisions about their pricing strategies, promotions, and advertising campaigns.

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Answer: 6

Step-by-step explanation: Hope I helped give me a good review and a thanks please

let number of green balls= x

let number of orange balls=x+4

x+x+4=38

2x=38-4

2x=34

x=17

number of green balls=17

number of orange balls=21

The equation of the line containing the paints A and B is y = -1/3x + 4

from the question, we have the following parameters that can be used in our computation:

The graph

Where, we have

(6, 2) and (0, 4)

A linear equation is represented as

y = mx + c

Where

c = y when x = 0

So, we have

y = mx + 4

Using the other points, we have

6m + 4 = 2

So, we have

6m = -2

Evaluate

m = -1/3

So, we have

y = -1/3x + 4

As an equation, we have

y = -1/3x + 4

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Answer:

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Step-by-step explanation:

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Explanation:

The key thing to focus on is the phrasing "starting at the age of 8"

Specifically, your teacher wants the starting height when Mia was 8 years old. That height being 52 inches.

The 7 inches refers to how much she had grown over the 2 years, which is part of the rate of change (and will be part of the slope).

Side note: 52 inches = 4 ft, 4 inches

Answer:

7/13

Step-by-step explanation:

Answer:

w = 6in, l = 10in

Step-by-step explanation:

Area of a rectangle is \(A=l*w\)

and \(l = 4 + w\)

We can solve for length and width by substituting these values for the equation.

\(60in^2=(4+w)*w\)

\(60in^2=4w+w^2\)

\(0 = w^2 + 4w + 60in^2\)

factor out the equation.

\(0= (w+10)(w-6)\)

therefore w = 6in (tossing out the negative solution)

which means

\(l = 4 + w\)

\(l = 6in + 4\)

l = \(10in\)

Hope this helps!
Brainliest is much appreciated!

The dollar value of total revenue at each price is $\(0\), $\(10\), $\(12\), $\(12\), $\(10\), and $\(6\). Total revenue will be the greatest at a price of $\(4\), with \(3\) units sold.

To find the dollar value of total revenue at each price, we can multiply the price by the corresponding quantity in the demand schedule:

Price: $\(6\)

Quantity: \(0\)

Total Revenue: $\(6 \times 0\) = $\(0\)

Price: $\(5\)

Quantity: \(2\)

Total Revenue: $\(5 \times 2\) = $\(10\)

Price: $\(4\)

Quantity: \(3\)

Total Revenue: $\(4 \times 3\) = $\(12\)

Price: $\(3\)

Quantity: \(4\)

Total Revenue: $\(3 \times 4\) = $\(12\)

Price: $\(2\)

Quantity: \(5\)

Total Revenue: $\(2 \times 5\) = $\(10\)

Price: $\(1\)

Quantity: \(6\)

Total Revenue: $\(1 \times 6\) = $\(6\)

To determine at which price the total revenue will be the greatest, we observe that the highest total revenue occurs at the price with the highest quantity sold. In this case, the price with the highest quantity is $\(3\), and the corresponding quantity sold is \(4\) units.

Therefore, at a price of $\(3\), the total revenue will be the greatest, with \(4\) units sold.

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Answer:

D

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

It translates 5 up and 3 left

To find the common roots between two functions, we need to find the roots (or solutions) of each function individually and then identify the shared solutions.

For the function f(x) = x^2 + x - 6, we can find the roots by setting the function equal to zero and solving for x:

x^2 + x - 6 = 0

To factorize this quadratic equation, we need to find two numbers that multiply to -6 and add up to 1 (the coefficient of x). The numbers that satisfy these conditions are 3 and -2:

(x + 3)(x - 2) = 0

Setting each factor equal to zero:

x + 3 = 0 or x - 2 = 0

Solving for x in each equation:

x = -3 or x = 2

Therefore, the function f(x) = x^2 + x - 6 has two roots: x = -3 and x = 2.

To find the common roots between this function and another function, we would need to know the second function. If you provide the second function, I can help determine if there are any shared roots.

Answer:

V = π ∫₀² (y² − 8y + 6√(2y)) dy

or

V = π ∫₀² (6x − 5x² + x³) dx

Step-by-step explanation:

y₁ = 0.5x²

y₂ = x

First, find the intersections of the curves.

0.5x² = x

x² = 2x

x² − 2x = 0

x (x − 2) = 0

x = 0 or x = 2

So the points of intersection are (0, 0) and (2, 2).

When we revolve this region about the line x = 3, we get a hollow shape that looks like an upside-down funnel, or a volcano.

One option is to use washer method to find the volume, by cutting a thin horizontal slice of thickness dy, inner radius 3−x₁ = 3−√(2y), and outer radius of 3−x₂ = 3−y.

V = ∫₀² π [(3−y)² − (3−√(2y))²] dy

V = ∫₀² π (9 − 6y + y² − 9 + 6√(2y) − 2y) dy

V = π ∫₀² (y² − 8y + 6√(2y)) dy

Another option is to use shell method to find the volume, by cutting a thin vertical slice of thickness dx, radius 3−x, and height y₂−y₁ = x−0.5x².

V = ∫₀² 2π (3 − x) (x − 0.5x²) dx

V = ∫₀² 2π (3x − 1.5x² − x² + 0.5x³) dx

V = ∫₀² 2π (3x − 2.5x² + 0.5x³) dx

V = π ∫₀² (6x − 5x² + x³) dx

The second option is arguably easier to evaluate, but either one will get you the same answer (V = 8π/3).

The volume of the solid of revolution is \(\frac{16\pi}{3}\) cubic units.

First, we determine the limits between the two curves. (\(f(x) = 4\cdot x -2\), \(g(x) = x^{2}+1\))

\(f(x) = g(x)\) (1)

\(4\cdot x - 2 = x^{2}+1\)

\(x^{2}-4\cdot x +3 = 0\)

\((x-1)\cdot (x-3) = 0\)

The lower and upper bounds are 1 and 3, respectively. It is to notice that \(f(x) > g(x)\) for \(x \in (1, 3)\). Thus, we determine the volume of the solid of revolution by shell method, that is to say:

\(V = 2\pi \int\limits^a_b {x\cdot |f(x) - g(x) |} \, dx\) (2)

If we know that \(a = 3\), \(b = 1\), \(f(x) = 4\cdot x - 2\) and \(g(x) = x^{2}+1\), then the volume of the solid of revolution is:

\(V = 2\pi \int\limits^3_1 {|4\cdot x^{2}-2\cdot x -x^{3}-x|} \, dx\)

\(V = 2\pi\int\limits^3_1 {(4\cdot x^{2}-x^{3}-3\cdot x)} \, dx\)

\(V = 8\pi \int\limits^3_1 {x^{2}} \, dx - 2\pi \int\limits^3_1 {x^{3}} \, dx -6\pi \int\limits^3_1 {x} \, dx\)

\(V = 8\pi\cdot \left(\frac{3^{3}}{3}-\frac{1^{3}}{3} \right)-2\pi \cdot \left(\frac{3^{4}}{4}-\frac{1^{4}}{4} \right) - 6\pi\cdot \left(\frac{3^{2}}{2}-\frac{1^{2}}{2} \right)\)

\(V = \frac{208\pi}{3} - 40\pi -24\pi\)

\(V = \frac{16\pi}{3}\)

The volume of the solid of revolution is \(\frac{16\pi}{3}\) cubic units.

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Answer: y=-3x-4

Step-by-step explanation:

Since we know slope, we can plug it into slope-intercept form to find the y-intercept by using the given points,

y=-3x+b

8=-3(-4)+b

8=12+b

b=-4

Now that we know the y-intercept, we can complete the slope-intercept form.

y=-3x-4

The child who is 4 feet tall can walk under the tent without bending over, as the height of the tent at that point is greater than 4 feet.

1. Given equation: y = -0.1\(8x^2\) + 1.6x, where y represents the height of the tent and x represents the distance from the center of the tent.

2. We want to find the maximum height of the tent to determine if a 4-foot tall child can walk under it without bending over.

3. To find the maximum height, we need to determine the vertex of the parabolic equation.

4. The vertex of a parabola in the form y = a\(x^2\) + bx + c is given by the formula x = -b / (2a).

5. In our equation, a = -0.18 and b = 1.6. Plugging these values into the formula, we get x = -1.6 / (2 * -0.18).

6. Simplifying the expression, we find x = 4.44.

7. Now, substitute this value back into the equation to find the maximum height: y = -0.18 * (4.4\(4)^2\) + 1.6 * 4.44.

8. Evaluating the expression, we find y ≈ 4.32.

9. The maximum height of the tent is approximately 4.32 feet.

10. Since the child's height is 4 feet, the child can comfortably walk under the tent without bending over, as the height is greater than 4 feet.

11. Therefore, the child who is 4 feet tall can walk under the tent without bending over.

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length= 15cm

width= 7cm

area of the rectangle.

area of rectangle= length × width

a= l × w

a= 15 × 7

= 105 cm^2

Answer:

105 cm²

Step-by-step explanation:

The formula to find the area of a rectangle is :

Area = length × width

Given that,

length ⇒ 15 cm

width ⇒ 7 cm

Let us solve it now.

Area =  length × width

Area = 15 × 7

Area = 105 cm²

Answer:

$2600

Step-by-step explanation:

It is given that the variables:

A = total income

t = amount of TV they sell.

It is also given that they sold 9 TVs. Plug in 9 for t in the given equation:

A = 800 + 200t

A = 800 + 200(9)

A = 800 + 1800

A = 2600

$2600 is the total amount they will receive if they sell 9 TVs.

~

Choe saki earn $258  in commission on tuesday. This problem is simple algebra problem where you have to form equation to answer the question.

From the question it is evident that Cho Saaki had a commission based job. we will simply solve it as any other equation in algebra

Given :

Cho Saaki makes $9 for 12 demonstrations. so total money she makes for 12 demonstrations is $108.

then she makes $15 for each demonstration over 12.

On Tuesday she makes 22 demonstrations. it means that she makes 10 more demonstration over 12. therefore she makes  $150  with those 10 more demonstrations.

so total money she earns in commission according to the equation is

12 × $9 + 10 × $15 = $108 + $150 = $158.

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Answer:

1. x/5

2. cubed root of 2x

3.x-10

4.(2x/3)-17

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. Lets find the inverse function for function f(x)=2*x/3-17

To do that first express x through f(x):

2*x/3= f(x)+17

2*x=(f(x)+17)*3

x=(f(x)+17)*3/2   done !!!                        (1)

Next : to get the inverse function from (1) substitute x by f'(x)   and f(x) by x.

So the required function is f'(x)=(x+17)*3/2 or f'(x)=3*(x+17)/2

This is function is No4 in our list. So f(x)=2*x/3-17 should be moved to the box No4  ( on the bottom) of the list.

2.  Lets find the inverse function for function f(x)=x-10

To do that first express x through f(x):

x= f(x)+10

x=f(x)+10   done !!!                        (2)

Next : to get the inverse function from (2) substitute x by f'(x)   and f(x) by x.

So the required function is f'(x)=x+10

This is function is No3 in our list. So f(x)=x-10 should be moved to the box No3  ( from the top) of the list.

3.Lets find the inverse function for function f(x)=sqrt 3 (2x)

To do that first express x through f(x):

2*x= f(x)^3

x=f(x)^3/2   done !!!                        (3)

Next : to get the inverse function from (3) substitute x by f'(x)   and f(x) by x.

So the required function is f'(x)=x^3/2

This is function No2 in our list. So f(x)=sqrt 3 (2x) should be moved to the box No2  ( from the top) of the list.

4.Lets find the inverse function for function f(x)=x/5

To do that first express x through f(x):

x=f(x)*5   done !!!                        (4)

Next : to get the inverse function from (4) substitute x by f'(x)   and f(x) by x.

So the required function is f'(x)=x*5 or f'(x)=5*x

This is function No1 in our list. So f(x)=x/5 should be moved to the box No1  ( on the top) of the list.