a series of elementary reactions by which reactants are converted to products is called the reaction__

The minimum number of grams of propane for the given question is calculated as 55.39 g.

Propane is a three-carbon alkane with molecular formula of C₃H₈. It is a gas at a standard temperature and pressure but is compressible to a transportable liquid.

Given, mass of ice = mass of water = 4.10 kg = 4100 g

and temperature of ice = -16 °C ; Temperature of water = 75.5 °C

Heat required to change  ice to water under the specified conditions is:-

As we know, q = q(-16 C to 0°C) + q(fusion) + q (0 C to 75.5 °C)

So q  = m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)

 = 4100[2.03(0-(-16)) + 334 + 4.18(75.5-0)]

q = 2796 kJ

As the enthalpy change for combustion of propane is -2220 kJ/mol

Therefore, now the number of moles of propane corresponding to required energy of 2796 kJ ;

= 1 mole * 2796 kJ/2220 kJ

= 1.259 moles of propane

As we know molar mass of propane = 44 g/mol

So, mass of propane required = 1.259 moles * 44 g/mol

Hence we get, mass of propane required  = 55.39 g

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The combination of the equations would give us;

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

We have the equations to be combined as;

CH(g) + 2O2(g) → CO2(g) + 2H2O(g)

CO(g) + H2O(g) → CO2(g) + H2(g)

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

This gives us;

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

This equation represents the complete combustion of methane, a process commonly used in energy production and heating systems. It illustrates how methane and oxygen react to form carbon dioxide and water vapor as the primary products.

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To neutralize 23.5 mL of a 0.145 M barium hydroxide solution, 23.9 mL of a 0.284 M hydrochloric acid solution is needed.

What does barium hydroxide serve?

Barium hydroxide is used to titrate weak acids, especially organic acids, in analytical chemistry. In contrast to the alkali hydroxides, barium carbonate creates clear, carbonate-free aqueous solutions because it is insoluble in water.

Acidity of barium hydroxide

When heated to 800 °C, barium hydroxide turns into barium oxide. Barium carbonate is produced when carbon dioxide reacts with it. Its strong base causes its extremely alkaline aqueous solution to go through neutralization reactions with acids.

Briefing:

The equation is given as:

Ba(OH)₂    +  2HCl     ------>   BaCl₂    +   2H₂O

from the equation it is clear that :

1mole of Ba(OH)₂  = 1 mole of HCl  

number of moles of Ba(OH)₂ = volume × Molarity

                          =  0.0235 × 0.145

                         = 0.0034 mol

Therefore, number of moles of HCl = 2× 0.0034 mol = 0.0068 mol

volue of HCl = moles / Molarity

                      = 0.0068 / 0.284

                       = 0.0239 L = 23.9 mL

Thus, The volume of a 0.284 M hydrochloric acid solution is required to neutralize 23.5 mL of a 0.145 M barium hydroxide solution is 23.9 mL.

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Answer:

Give a brief question

Not an awful question

The molecular formula of the unknown compound is C2H2O2.

To determine the molecular formula of the unknown compound, we need to calculate the empirical formula first and then find the multiple of its subscripts to obtain the molecular formula.

Given:

Percentage of carbon = 40.0%

Percentage of hydrogen = 6.7%

Percentage of oxygen = 53.3%

Molecular mass = 60.0 g/mol

Step 1: Convert the percentages to grams.

Assuming we have 100 grams of the compound:

Mass of carbon = 40.0 g

Mass of hydrogen = 6.7 g

Mass of oxygen = 53.3 g

Step 2: Convert the masses to moles using the molar masses of the elements.

Molar mass of carbon = 12.01 g/mol

Molar mass of hydrogen = 1.008 g/mol

Molar mass of oxygen = 16.00 g/mol

Number of moles of carbon = Mass of carbon / Molar mass of carbon

= 40.0 g / 12.01 g/mol

= 3.332 mol

Number of moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen

= 6.7 g / 1.008 g/mol

= 6.648 mol

Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen

= 53.3 g / 16.00 g/mol

= 3.331 mol

Step 3: Determine the empirical formula by dividing the moles by the smallest value.

Dividing the moles of carbon, hydrogen, and oxygen by 3.331 gives approximately 1 for each element.

So, the empirical formula of the compound is CHO.

Step 4: Determine the multiple of the subscripts to obtain the molecular formula.

To find the multiple, we divide the molecular mass by the empirical formula mass.

Molecular mass = 60.0 g/mol

Empirical formula mass = (12.01 g/mol) + (1.008 g/mol) + (16.00 g/mol) = 29.018 g/mol

Multiple = Molecular mass / Empirical formula mass

= 60.0 g/mol / 29.018 g/mol

= 2.07

Rounding to the nearest whole number, we get 2.

Therefore, the molecular formula of the unknown compound is C2H2O2.

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Answer:

The larger the highest energy level, the larger the atomic radius.

Explanation:

The ultrasonic cleaner solution becomes visibly cloudy when needing to be changed; it becomes highly contaminated with use. It should be discarded at least once a day.

Ultrasonic cleaner solutions are used to remove dirt and grime from various objects through the use of sound waves. When the ultrasonic cleaner solution is used, it becomes contaminated and needs to be changed regularly. The solution can become visibly cloudy and the contaminants can be seen in the solution.

When this happens, it is important to change the solution to ensure that it continues to work effectively.To maintain the cleaning efficiency, it is recommended that the solution be changed at least once a day. This is to ensure that the contaminants do not build up and reduce the effectiveness of the ultrasonic cleaner.

The solution should be discarded according to the manufacturer's instructions or as indicated by changes in the solution's color, clarity, or cleanliness. It is important to dispose of the used solution according to local regulations.

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Answer:

It is the length of these chains, and the patterns in which they are arrayed, that make polymers strong, lightweight, and flexible.

Explanation:

Synthetic polymers are made up of long chains of atoms, arranged in repeating units, often much longer than those found in nature. It is the length of these chains, and the patterns in which they are arrayed, that make polymers strong, lightweight, and flexible. In other words, it's what makes them so plastic.

When balancing a chemical equation, there are several things you should do in order to ensure that the equation is balanced correctly. One of the most important things to do is to balance the equation with coefficients one element at a time. This means that you should start by identifying the different elements present in the equation and then balancing them one at a time.

For example, if you have an equation that contains carbon, hydrogen, and oxygen, you should first balance the carbon atoms on both sides of the equation, then balance the hydrogen atoms, and finally balance the oxygen atoms. By doing this, you will ensure that the equation is balanced correctly and that the number of atoms of each element is the same on both sides of the equation.
Another thing to do when balancing a chemical equation is to use the smallest possible whole number coefficients. This will help to simplify the equation and make it easier to read and understand. Additionally, you should always double check your work to ensure that the equation is balanced correctly and that all the coefficients are correct.
Overall, balancing a chemical equation requires attention to detail, patience, and a good understanding of chemistry principles. By following the steps outlined above, you can ensure that you are able to balance any chemical equation with ease and accuracy.

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Given the data from the question, the starting equation is

C₂H₃Br + O₂ --> CO₂ + H₂O + HBr

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

Considering the equation given from the qustion

2C₂H₃Br + 5O₂ --> 4CO₂ + 2H₂O + 2HBr

We can see that the above equation is already balanced.

Thus, the starting equation will be the skeletal equation which is unbalanced.

Therefore, we can conclude that the starting equation is:

C₂H₃Br + O₂ --> CO₂ + H₂O + HBr

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Answer:

D

Explanation:

took the test

Answer:

i am not sure but

Explanation:

b and c should be correct

Answer:b and D

Explanation:

The specific heat capacity at constant volume of nitrogen gas (N2) is 20.8 J/(kg·K).

The specific heat capacity at constant volume of a substance is a measure of how much heat energy is required to raise the temperature of a given mass of the substance by one degree Kelvin when the volume is held constant.

For nitrogen gas (N2), the molar mass is 28.0 g/mol. To compute the specific heat capacity at constant volume, we need to convert the molar mass to kilograms. Since there are 1000 grams in a kilogram, the molar mass of N2 is 0.028 kg/mol.

The specific heat capacity at constant volume (Cv) can be calculated using the following formula:

Cv = (5/2)R

where R is the ideal gas constant, equal to 8.314 J/(mol·K). Substituting the values into the formula, we get:

Cv = (5/2) × 8.314 J/(mol·K)

Cv = 20.785 J/(mol·K)

To express the specific heat capacity in joules per kilogram per kelvin, we divide the Cv value by the molar mass in kilograms:

Cv = 20.785 J/(mol·K) / 0.028 kg/mol

Cv ≈ 743.036 J/(kg·K)

Therefore, the specific heat capacity at constant volume of nitrogen gas (N2) is approximately 743.036 J/(kg·K).

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Oxidation of a 24-carbon fatty acid would require ELEVEN (11) rounds of beta-oxidation and TWELVE (12) rounds of the Krebs cycle. It is part of cellular respiration.

Cellular respiration is a group of chemical reactions by which aerobic cells can produce ATP by using energy from foods.

Cellular respiration has three parts: glycolysis, the Krebs cycle (also called the acid citric cycle) and oxidative phosphorylation.

During the Krebs cycle, hydrogen atoms or electrons pass through a series of hydrogen/electron carriers.

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The name of N₂Cl₄ is Dinitrogen Tetrachloride. the type of bond between is covalent bond. The steps use to name the compound is nomenclature.

The given compound N₂Cl₄  name is Dinitrogen Tetra chloride. In this compound , Nitrogen and Chlorine are non metals . nonmetals are electronegative elements that means they want to gain electron.  according to octet rule , atom need to have 8 electrons in outermost shell and it occurs by sharing of electron or by transferring of electron.

In case of nitrogen and chlorine both are electronegative and wants to gain electron so that they will complete their octet. The atom will complete their octet by sharing of electron. Hence form covalent bond.

Two nitrogen atoms are central atom and two chlorine atom connected to each nitrogen atom forming covalent bond.

two nitrogen = Dinitrogen ( Di for two)

four chlorine = tetrachloride ( tetra for 4 )

N₂Cl₄ = Dinitrogen tetrachloride

Thus, The name of N₂Cl₄ is Dinitrogen Tetrachloride. the type of bond between is covalent bond. The steps use to name the compound is nomenclature.

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Le Châtelier's Principle states that we can move the equilibrium's position to the right by either adding an excessive amount of a reactant or by deleting one of products. If utilize significant amount more of one reactant.

A component that is involved at the outset of a chem reaction is known as a reactant. Products are the component(s) to the east of the arrow. A product is the substance that is also present after a chemical process has finished.

A compound that is a reactant is that which is present at the outset of a chemical reaction and changes as the reaction develops. They can also be refereed to as reagents or beginning materials.

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The C atoms in ethene use sp2 hybrid orbitals, which is in accordance with orbital hybridization theory.

Energy is ultimately the basis of everything in the chemical world. Orbitals combine because doing so results in a molecule that is less energetic and therefore more stable than it would be if the orbitals did not combine.

In order to create the second bond (Pi bond) in the C-C double bonds, one unhybridized p orbital must remain.

The two carbon atoms overlap one sp2 hybrid orbital to create a single sigma bond. The C-C double bond is finished when one of each C atom's p orbitals crosses over to create a pi bond.

When the H s orbitals overlap with the remaining sp2 hybrid orbitals from each C, the H atoms are joined to the C atoms by sigma bonds.

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71.27 grams of cadmium (II) phosphate are needed to prepare 250 mL of 0.75 M cadmium (II) phosphate solution.

To determine how many grams of cadmium (II) phosphate are needed to prepare 250 mL of 0.75 M solution, we can use the following steps:

Calculate the number of moles of cadmium (II) phosphate required:

Molarity = moles / volume

Rearranging the equation:

moles = Molarity x volume

moles = 0.75 M x 0.25 L = 0.1875 moles

Calculate the molar mass of cadmium (II) phosphate:

Cd3(PO4)2 has a molar mass of 380.15 g/mol

Calculate the mass of cadmium (II) phosphate required:

mass = moles x molar mass

mass = 0.1875 moles x 380.15 g/mol = 71.27 g

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If this reaction was performed with 2-methylbut-2-ene instead of 1-octene, the major product would be a 2-methylbutanoic acid. If 2-methylbut-2-ene was reacted with aqueous sulfuric acid, the major product would be 2-methylbutane-2-sulfonic acid.

Without the knowledge of the given reaction, it's difficult to provide a proper explanation about the major product. However, based on the given reactants, 1-octene and aqueous sulfuric acid, it can be assumed that the reaction is hydration of 1-octene using aqueous sulfuric acid as a catalyst.

If 2-methylbut-2-ene was used instead of 1-octene, the reaction will still follow the same mechanism. The alkene will undergo hydration to form an alcohol. The major product formed would be 2-methylbutanal.The reaction mechanism for the hydration of 2-methylbut-2-ene using aqueous sulfuric acid as a catalyst is as follows:

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Vm will be close the Eion which has the highest conductance at the point in the AP.

Vm, the membrane potential of a neuron, will be closest to the equilibrium potential (Eion) of the ion with the highest conductance at that point in the action potential.

Conductance is a measure of how easily ions can move across the membrane, and the ion with the highest conductance at a given point in the action potential will have the greatest influence on the membrane potential.

At rest, the membrane potential is close to the equilibrium potential of potassium (EK) because the resting conductance of potassium is high. During depolarization, the conductance of sodium (ENa) increases, and the membrane potential approaches the equilibrium potential of sodium.

During repolarization and hyperpolarization, the conductance of potassium increases again, and the membrane potential returns to EK.

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When a cell produces a constant voltage of 1.50 V and 0.230 mL of Br2(l) has been consumed, the electrical work done can be calculated using Faraday's law. First, convert the volume of Br2(l) to moles using its molar volume (24.45 L/mol).

Then, determine the moles of electrons (n) involved in the redox reaction, knowing that 1 mole of Br2 consumes 2 moles of electrons.

Next, calculate the total charge (Q) by multiplying n by Faraday's constant (F = 96,485 C/mol). Finally, determine the electrical work (W) using the formula W = Q * V, where V is the voltage (1.50 V).

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The electrical wοrk dοne when 0.230 mL οf Br2(l) has been cοnsumed is apprοximately 3.11 jοules.

Wοrk is defined as the transfer οf energy that οccurs when a fοrce is applied tο an οbject, causing it tο mοve in the directiοn οf the fοrce. Mathematically, wοrk is calculated as the prοduct οf the fοrce applied tο an οbject and the displacement οf the οbject in the directiοn οf the fοrce. Wοrk is a scalar quantity which is measured in jοules (J).

Tο calculate the electrical wοrk dοne, we need tο knοw the number οf mοles οf electrοns transferred in the reactiοn.

Since 0.230 mL οf Br2(l) has been cοnsumed, we can determine the mοles οf Br2 by using its mοlar vοlume at standard temperature and pressure (STP), which is 22.4 L/mοl.

Tο cοnvert the vοlume:

0.230 mL = 0.230/1000 L = 0.00023 L

Next, calculate the mοles οf Br2:

mοles = vοlume(V) (in L) / mοlar vοlume (mV)

mοles = 0.00023 L / 22.4 L/mοl ≈ 1.03 x 10⁻⁵ mοl

Since each mοle οf Br2 transfers 2 mοles οf electrοns in a redοx reactiοn, the number οf mοles οf electrοns transferred is:

mοles οf electrοns = 2 x (1.03 x 10⁻⁵mοl) = 2.06 x 10⁻⁵ mοl

Nοw, we can calculate the electrical wοrk dοne using the equatiοn:

wοrk = vοltage x mοles οf electrοns x Faraday's cοnstant

Faraday's cοnstant (F) is equal tο 96,485 C/mοl (cοulοmbs per mοle).

wοrk = 1.50 V x (2.06 x 10⁻⁵ mοl) x (96,485 C/mοl)

wοrk ≈ 3.11 J (jοules)

Therefοre, the electrical wοrk dοne when 0.230 mL οf Br2(l) has been cοnsumed is apprοximately 3.11 jοules.

Electrical wοrk refers tο the wοrk dοne by οr against an electric field. It represents the transfer οf electrical energy in an electrical circuit οr system. The fοrmula fοr electrical wοrk is:

Wοrk = Vοltage x Charge

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True Statements

False Statements

__________________________________________________________

Which equation should you use?

B. P₁V₁=P₂V₂

What is the new pressure?  

✔ 5000  kPa

__________________________________________________________

The problem gives initial volume (2.00 L), final volume (20.0 mL), and initial pressure (50.0 kPa). Then it asks to find the final pressure. Answer B has all these variables, with P₁=initial pressure, P₂=final pressure, V₁=initial volume, and V₂=final volume. Plug the given values into the equation and then solve for the unknown value, which is P₂, final pressure.

When plugging in the values, use consistent units. 2L=2000 mL, I chose to make the consistent unit in mL. You'll get the same answer if you choose to use L as the consistent unit.

\(2000*50=20*P2\)

\(100000=20*P2\)

Divide both sides by 20

\(100000/20=(20*P2)/20\)

\(5000=P2\)

Here's a photo of Edge just incase.

Propane produces more energy as compared to ethanol during burning.

Energy produce by ethanol is 10.45 kilojoules per gram whereas  propane release 46 kilojoules per gram of energy when burn so by comparing these two chemicals we can conclude that propane produces more energy as compared to ethanol during burning.

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The enthalpy of freezing for a substance with an enthalpy of condensation of -1.46 kJ/g and an enthalpy of sublimation of 4.60 kJ/g, the enthalpy of freezing for the substance is 6.06 kJ/g.

1. Recall the relationships between the enthalpy terms: enthalpy of sublimation = enthalpy of condensation + enthalpy of freezing.

2. Rearrange the equation to solve for the enthalpy of freezing: enthalpy of freezing = enthalpy of sublimation - enthalpy of condensation.

3. Plug in the given values: enthalpy of freezing = 4.60 kJ/g - (-1.46 kJ/g).

4. Calculate the enthalpy of freezing: enthalpy of freezing = 4.60 kJ/g + 1.46 kJ/g = 6.06 kJ/g.

So, the enthalpy of freezing for the substance is 6.06 kJ/g.

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Answer:

2 NaOH + H2SO4 -> Na2SO4 + 2 H2O

If you react H2SO4 with NaOH, then NaHSO4 is formed.

H2SO4+NaOH - NaHSO4+H2O

The combination that will produce a precipitate is AgNO3 (aq) and Ca(C2H3O2)2 (aq). Option B is the correct answer.

When these two solutions are mixed, a double displacement reaction occurs, producing insoluble AgC2H3O2 (silver acetate) and soluble Ca(NO3)2 (calcium nitrate).

The silver acetate will precipitate out of the solution, indicating that a chemical reaction has occurred. The other answer choices do not involve reactions that produce insoluble products and therefore will not produce a precipitate.

This question highlights the importance of understanding double displacement reactions and the solubility rules of different compounds when predicting chemical reactions.

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Explanation:

Mass of xenon tetrafluoride = 4.658 g

To determine the number of grams of xenon in 4.658 grams of the compound xenon tetrafluoride:

The chemical formula for xenon tetrafluoride is XeF_4XeF

4

Molar mass of XeF_4XeF

4

= 207.28 g/mol

Molar mass of xenon = 131.29 g/mol

First of all, we would calculate the number of moles of XeF_4XeF

4

.

\begin{gathered}Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{4.658}{207.28}\end{gathered}

Cancer is a group of diseases involving abnormal cell growth with the potential to invade or spread to other parts of the body.[2][8] These contrast with benign tumors, which do not spread.[8] Possible signs and symptoms include a lump, abnormal bleeding, prolonged cough, unexplained weight loss, and a change in bowel movements.[1] While these symptoms may indicate cancer, they can also have other causes.[1] Over 100 types of cancers affect humans.[8]

Tobacco use is the cause of about 22% of cancer deaths.[2] Another 10% are due to obesity, poor diet, lack of physical activity or excessive drinking of alcohol.[2][9][10] Other factors include certain infections, exposure to ionizing radiation, and environmental pollutants.[3] In the developing world, 15% of cancers are due to infections such as Helicobacter pylori, hepatitis B, hepatitis C, human papillomavirus infection, Epstein–Barr virus and human immunodeficiency virus (HIV).[2] These factors act, at least partly, by changing the genes of a cell.[11] Typically, many genetic changes are required before cancer develops.[11] Approximately 5–10% of cancers are due to inherited genetic defects.[12] Cancer can be detected by certain signs and symptoms or screening tests.[2] It is then typically further investigated by medical imaging and confirmed by biopsy.[13]

Answer:

Graph is attached below.

Explanation:

Go to insert, then chart, then select line, then go to sheets and edit it to fit what you need it to say.

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a great day!

−xXheyoXx

The 2(4)4 is the significant figure used to calculate that density of the sample.

Significant figure is the number of important of single digits that use as the coefficient of an expression in scientific notation. Density is a measurement of how tight the material when packed with other material. To calculate the bone density we use formula :

bone density = mass : volume

As per data given, the bone density will be

bone density = 34.261 : 3.8

The 2(4)4 will be the significant that represent the calculate density of the sample.

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