A sample of gas that contains 21.0 moles at a pressure of 78.0 atm with a temperature of 900. k has what volume? use r=0.08206l atm mol k for the gas constant.

Answers

Answer 1

The volume of the gas will be V = 0.946 L

We have to calculate the volume of the given moles of gas at specific temperature and pressure.

Using Ideal Gas equation;

PV = nRT

V = nRT /P ( R = gas constant = 0.08206 L atm mol−1K−1 )

V= 21 mol x 0.08206 L atm mol−1K−1 x 900K / 78 atm

V= 73.854 L atm / 78 atm = 0.946 L

V = 0.946 L

The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

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Related Questions

If a boat is producing a bow wave as it moves over the water, what must be true about its speed?

The boat is traveling slower than the waves it is producing.
The boat is traveling with the same speed as the waves it is producing.
The boat is traveling faster than the waves it is producing.

Answers

Answer:

A Bow wave is produced when a speed boat moves faster than the waves it produces.

Explanation: A Bow wave is a progressive disturbance that propagates through a fluid, such as water or air, as a result of a displacement of the anterior point of an object passing through the fluid that is greater than the speed of the wave travelling across the fluid, produced by the same object. If the speed of the object is slower than the waves it produces, then no Bow waves will be generated. In the above scenario, when the speed boat moves faster than the waves it generates, it produces the Bow wave in the water.

Why do you think that most of your body is made of this material?

Answers

Answer:

Almost 99% of the mass of the human body is made up of six elements: oxygen, carbon, hydrogen, nitrogen, calcium, and phosphorus. Only about 0.85% is composed of another five elements: potassium, sulfur, sodium, chlorine, and magnesium.

Which of the following is a way that trees have been negatively impacted by human use? a. Deforestation b. Pollution c. Reduction d. All of the above Please select the best answer from the choices provided A B C D.

Answers

Answer:

D

Explanation:

Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

Answer: D

Explanation:Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

3. If I run 150m in 30 seconds, what speed will I have been running at?

Answers

Answer:

speed = distance/time

Explanation:

speed = 150/30

speed =5m/s

you were running fast .....5m/s is a good speed

a machinist with normal vision has a near point at 25 cm. the machinist wears eyeglasses in order to do close work. the power of the lenses is 2.16 diopters. with these eyeglasses, what is the near point of the machinist?

Answers

The near point of the machinist with the eyeglasses  is 45.45 cm.

The near point is the closest distance at which an individual can see an object clearly without any visual aid, such as glasses or contact lenses. It varies depending on the individual's age and visual acuity.

Near point = 1 / (1 / Near point without eyeglasses + Power of lenses)

Plugging in the given values:

Near point = 1 / (1 / 25 cm + 2.16 diopters)

Near point = 1 / (0.04 diopters + 2.16 diopters)

Near point = 1 / 2.2 diopters

Near point = 0.4545 meters or 45.45 cm

This means that the machinist can see objects clearly at a distance of 45.45 cm or closer with the eyeglasses.

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A uniform magnetic field B has a strength of 5.5 T and a direction of 25.0° with respect to the +x-axis. A proton (1.602e-19)is traveling through the field at an angle of -15° with respect to the +x-axis at a velocity of 1.00 ×107 m/s. What is the magnitude of the magnetic force on the proton?

Answers

The magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.

Given values: B = 5.5 Tθ = 25°q = 1.602 × 10⁻¹⁹ VC = 1.00 × 10⁷ m/s Formula: The formula to calculate the magnetic force is given as;

F = qvBsinθ

Where ;F is the magnetic force on the particle q is the charge on the particle v is the velocity of the particle B is the magnetic field strengthθ is the angle between the velocity of the particle and the magnetic field strength Firstly, we need to determine the angle between the velocity vector and the magnetic field vector.

From the given data, The angle between velocity vector and x-axis;α = -15°The angle between magnetic field vector and x-axis;β = 25°The angle between the velocity vector and magnetic field vectorθ = 180° - β + αθ = 180° - 25° - 15°θ = 140° = 2.44346 rad Now, we can substitute all given values in the formula;

F = qvBsinθF

= (1.602 × 10⁻¹⁹ C) (1.00 × 10⁷ m/s) (5.5 T) sin (2.44346 rad)F

= 4.31 × 10⁻¹¹ N

Therefore, the magnitude of the magnetic force on the proton is 4.31 × 10⁻¹¹ N.

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What is the approximate color of the sun using BGR indicator and adjusting the sliding temperature scale to Sun? A Yellow B. Orange C. White D. Blue

Answers

The approximate color of the sun using the BGR indicator and adjusting the sliding temperature scale to Sun would be option A: Yellow.

Hi! To determine the approximate color of the sun using the BGR indicator and adjusting the sliding temperature scale to Sun, you can follow these steps:

1. Recognize that the BGR indicator refers to the Blue-Green-Red color model.
2. Know that the sliding temperature scale refers to adjusting the color based on the temperature of the sun.
3. Understand that the sun's surface temperature is approximately 5,500 degrees Celsius, which corresponds to a white-yellowish color.

Based on this information, the approximate color of the sun using the BGR indicator and adjusting the sliding temperature scale to Sun would be option A: Yellow.

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Besides its regular display, almost every font has ____ common stylistic sets. Select one: a.one b.four c.three d.two.

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Almost every font has four common stylistic sets, besides its regular display. These stylistic sets are alternate characters, ligatures, swashes, and small caps.

Alternate characters are different versions of the same letter, number, or symbol, which can give a font a unique and personalized look. Ligatures are two or more characters that are combined into one glyph to improve the font's legibility and aesthetics. Swashes are decorative elements that extend from letters, adding elegance and flair to a font. Lastly, small caps are lowercase letters that are designed to be the same height as uppercase letters, creating a more consistent and professional look. These stylistic sets can be accessed in many design software programs, allowing designers to customize their typography and create unique and visually appealing designs. Besides its regular display, almost every font has four common stylistic sets. These sets typically include regular, bold, italic, and bold italic styles. This allows for versatility in design and text formatting.

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A child pulls a wagon a distance of 30 m a long athe floor using a rope that makes 30o with the horizontal, how much work does the rope do on the boat if its tension is 200 N

Answers

W=5196.15J
As
W=F.d
W=Fdcosθ
where W is work, F is force and d is displacement
Force F= Tension T= 200N
d=30m
Putting values in formula
W=Fdcosθ
W=(200N)*(30m)* cos(30)°
W=(6000Nm)*(0.8660)
W=5196.15Nm=5196.15J

Two narrow slits are separated by a distance d. Their interference pattern is to be observed on a screen a large distance L away:
a) Calculate the spacing Y of the maxima of the screen for light of wavelength 500 nm when L = 1 m and d = 1 cm
b) Would you expect to observe the interference of light on the screen for this situation? Explain:
c) How close together should the slits be placed for the maxima to be separated by 1 mm for this wavelength and screen distance:

Answers

(a) The spacing Y of the maxima of the screen for light is  5 x 10^-7 m. (b) Yes, we would expect to observe the interference of light. (c) The slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

(a) The spacing Y of the maxima on the screen can be calculated using the formula for the interference of light from two slits:

=> Y

= L x λ / d

here L is distance from the slits to the screen,

λ is wavelength of the light,

d is distance between the slits.

Putting the values, we have:

=> Y

= 1 m x 500 nm / 1 cm

= 500 nm/cm

= 5 x 10^-7 m

(b) Yes, we would expect to observe the interference of light on the screen for this situation. This is because when light passes through two narrow slits, it creates an interference pattern on the screen that is a result of the constructive and destructive interference of the light waves. This pattern is characterized by bright and dark bands, with the bright bands representing areas of constructive interference and the dark bands representing areas of destructive interference.

(c) To calculate the distance the slits should be placed to observe the maxima separated by 1 mm, we need to rearrange the formula for Y and solve for d:

=> d

= L x λ / Y

= 1 m x 500 nm / 1 mm

= 500 x 10^-9 m

So, the slits should be placed a distance of 500 nm apart to observe the maxima separated by 1 mm.

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In a population of ground beetles, a genetic locus that codes for setae on the elytra has two variants: G is dominant and codes for setae on the elytra, and g is recessive and codes for glabrous elytra (no setae). If the frequency of beetles with glabrous elytra is 0.36, what is the frequency of the G allele, assuming the population is in Hardy-Weinberg equilibrium? Show all your calculations. (5 pts) a. 0.6 b. 0.4 C. 0.64 d. 0.16 e. none of the above

Answers

The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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Answers

Answer: b

Explanation: just did it

When a body is lifted through a height h, the work done on it appears in the form of its: (a) kinetic energy (b) potential energy (c) elastic potential energy (d) geothermal energy​

Answers

The work done on a body when it is lifted through a height h appears in the form of its potential energy. Therefore, option (b) is the correct answer.

What is Geothermal Energy?

Geothermal energy is a type of renewable energy that is derived from the heat generated deep beneath the Earth's surface. It is produced by harnessing the naturally occurring heat from the Earth's core, which can be used to generate electricity or heat buildings directly. This energy can be accessed by drilling deep wells into the Earth's crust and tapping into the hot water and steam that is naturally present in underground reservoirs.

When a body is lifted through a height h, the work done on it appears in the form of potential energy. This is because the energy is stored in the body due to its position or configuration, rather than its motion.

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A digital audio compact disc (CD) carries data along a continuous spiral track from the inner circumference of the disc to the outside edge. Each bit occupies 0.6 mm of the track. A CD player turns the disc to carry the track counterclockwise above a lens at a constant speed of 1.30 m/s. Find the required angular speed (a) at the beginning of the recording, where the spiral has a radius of 2.30 cm, and (b) at the end of the record-ing, where the spiral has a radius of 5.80 cm. (c) A full-length recording lasts for 74 min, 33 s. Find the average angular acceleration of the disc. (d) Assuming the acceleration is con-stant, find the total angular displacement of the disc as it plays. (e) Find the total length of the track.

Answers

(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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when the evaporation rate equals the condensation rate, the space above the liquid is

Answers

When the evaporation rate of a liquid is equal to its condensation rate, the space above the liquid is in a state of dynamic equilibrium.

This means that while molecules are constantly evaporating from the liquid surface and entering the space above, an equal number of molecules are condensing and returning to the liquid phase. The molecules in the space above the liquid are in constant motion, colliding with each other and the liquid surface.

This results in a stable vapor pressure, which is the pressure exerted by the gas molecules in the space above the liquid. The magnitude of the vapor pressure depends on the temperature and the properties of the liquid.

When the temperature increases, the evaporation rate increases, and the vapor pressure also increases until a new equilibrium is reached. Similarly, a decrease in temperature leads to a decrease in both the evaporation and condensation rates, resulting in a lower vapor pressure. Overall, the space above the liquid in equilibrium is characterized by a constant vapor pressure and a balance between the evaporation and condensation rates.

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A torpedo fired from a submerged submarine is propelled through the waterwith a speed of 20.00 m/s and explodes upon impact with a target 2000.0 maway. If the sound of the impact is heard 101.4 s after the torpedo was fired,what is the speed of sound in water? (Because the torpedo is held at a constantspeed by its propeller, the effect of water resistance can be neglected.)

Answers

Given,

The initial speed, u=20.00 m/s

The distance between the submerine and the target is d=2000.0m

The sound of impact is heard after T=101.4 s.

To find

The speed of sound in water.

Explanation

Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.

Let the speed be v.

Thus,

\(\begin{gathered} T=\frac{d}{u}+\frac{d}{v} \\ \Rightarrow101.4=\frac{2000}{20}+\frac{2000}{v} \\ \Rightarrow v=1428.6\text{ m/s} \\ \end{gathered}\)

Conclusion

Speed of the sound in water is 1428.6 m/s

Determine the condition of the airplane:
Pilot and copilot = 400 lb
Passengers -- aft position = 240 lb
Baggage = 20 lb
Fuel = 75 gal

Answers

The condition of the airplane, considering the weights of the pilot, copilot, passengers, baggage, and fuel, is important for ensuring safe flight operations and determining the aircraft's center of gravity.

To assess the condition of the airplane, we need to calculate the total weight and the location of its center of gravity (CG). Let's break down the given weights:

- Pilot and copilot: 400 lb

- Passengers (aft position): 240 lb

- Baggage: 20 lb

- Fuel: 75 gal

To determine the total weight, we sum up the weights of the pilot, copilot, passengers, baggage, and fuel. Assuming the average weight of fuel is approximately 6 lb/gal, the total weight would be:

400 lb + 240 lb + 20 lb + (75 gal * 6 lb/gal) ≈ 1,110 lb.

To calculate the CG location, we need to know the arm (distance) from a reference point. Without that information, it is difficult to provide a precise assessment. The CG position affects the aircraft's stability and control. It is crucial to ensure the CG is within specified limits to maintain safe flight characteristics.

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You are investigating the eruption history of a volcano. You find that the volcano has generated multiple lava flows that spread over large areas over the past 10,000 years. There is very little tephra. People in the nearby town remember the last eruption, when lava flows caused some forest fires. Based on this description, how would you classify the state of the volcano?
O Active Recently Erupting
O Active-Dormant
O Lurking
O Extinct

Answers

Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."

The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.

Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.

The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.

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What is the magnitude of the acceleration of a proton that is 0.70 cm from the center of the bead?

Answers

The acceleration of the proton by using Coulomb's law is 2.806 m/s²

The acceleration of a proton can be defined by using coulombs force and centripetal acceleration. The value of coulomb force is

Fc = k.q1.q2 / d²

where Fc is coulomb force, k is Coulomb's constant, q is charge and d is distance.

Centrifugal force will also same as coulomb force, which can be determined as

F = m.a

where F is centrifugal force, m is mass and a is acceleration.

From the question above, we know that:

q1 = q2 = e = 1.602176634×10‾¹⁹ C

k = 8.988×10⁹ N⋅m²⋅C‾²

m = 1.673 x 10‾²⁴ kg

d = 7 x 10‾³ m

By combining these equations, we get

F = Fc

m.a = k.q1.q2 / d²

a = k.e² / m.d²

Substitute the parameter

a = 8.988×10⁹ . (1.6×10‾¹⁹)² / ( 1.673 x 10‾²⁴ . ( 7 x 10‾³ )² )

a = 2.806 m/s²

Hence, the acceleration of the proton by using Coulomb's law is 2.806 m/s²

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a motorcycle traveling 100m/s drives off a horizontal ramp and lands a horizontal distance of 40m away from the edge of the ramp, what is the height of the ramp?

Answers

We will have the following:

First, we determine the time it takes for the motorcycle to traverse the 40 m:

\(40m=(100m/s)t\Rightarrow t=0.4s\)

Now, we will use the time to determine the height of the ramp:

\(\begin{gathered} d=(0m/s)(0.4s)+\frac{(9.8m/s^2)(0.4s)^2}{2}\Rightarrow d=\frac{98}{125}m \\ \\ \Rightarrow d=0.784m \end{gathered}\)

So, the ramp was located 0.784 meters in height.

All of the inner planets
a. have one or more moons.
b. Iare made of igneous rock.
c. have been geologically active.
d: two of the above

Answers

Answer:

The answer to this is D two of the above

what do we call a solar power plant that uses mirrors to focus the light of the sun on a central point

Answers

Answer:

Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity.

Explanation:

(a) Calculate the speed of a proton that is accelerated from rest through an electric potential difference of 114 V. m/s (b) Calculate the speed of an electron that is accelerated through the same potential difference.

Answers

(a) The speed of a proton accelerated through an electric potential difference of 114 V can be calculated using the equation for the change in kinetic energy of a charged particle in an electric field.

(b) Similarly, the speed of an electron accelerated through the same potential difference can be determined using the same equation, considering the opposite charge and mass of the electron.

(a) The change in kinetic energy \((ΔKE)\) of a charged particle accelerated through an electric potential difference \((ΔV)\) is given by the equation \(ΔKE = qΔV\), where q is the charge of the particle. In this case, since the proton has a positive charge, the equation becomes \(ΔKE = eΔV\), where e is the elementary charge.

The change in kinetic energy is equal to the kinetic energy gained by the proton, given by the equation \(KE = 1/2 mv^2\), where m is the mass of the proton and v is its speed. By equating the two equations and solving for v, we can determine the speed of the proton.

(b) Similarly, for the electron, we use the same equation \(ΔKE = eΔV\), but with the negative charge of the electron. By solving for v, we can determine the speed of the electron.

By substituting the given values and using the appropriate charge and mass for each particle, we can calculate the speed of the proton and the electron when accelerated through the same potential difference

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Question 11(Multiple Choice Worth 4 points)

(05.03 LC)

HELP ASAP!!! WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

What most likely happens when water vapor cools?

It changes into gas.
It changes into liquid.
Its temperature increases.
Its temperature remains constant.

Answers

Liquid or second option, water converts from vapor form to liquid form because of condensation. It attaches to small particles and forms liquid droplets. Even though I am helping you, try and use the web browser next time for a faster and more efficient respond

A bullet is at rest. It travels a distance of 0.34m in a time of 0.0095 seconds. Calculate its acceleration

Answers

3767 m/ seconds squared

An astronaut drops two pieces of paper from the door of a lunar landing module. one piece of paper is crumpled, and the other piece is folded into an airplane. why do the two pieces of paper land on the moon’s surface at the same time?

Answers

The two pieces of paper land on the moon's surface at the same time because they are both subject to the same gravitational force.

What controls motion on the moon?

The force of gravity is determined by the mass of the object and the distance between it and the center of the celestial body. On the moon, the force of gravity is weaker than it is on Earth, but it is still strong enough to cause objects to fall toward the surface.

The shape of the paper, whether crumpled or folded into an airplane, has no effect on the force of gravity acting on it. In the absence of air resistance, all objects, regardless of their mass, shape, or size, will fall at the same rate in a vacuum.

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If a car is traveling 35 m/s for 200 seconds, how far will the car travel?

Answers

Hey I’m just setting up my profile so I’ll say fast

An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?

Answers

Answer:

Explanation:

we know that

s=vt

given

v=5.4 m/s

t=12 s

s=5.4 m/s*12 s=64.8m

when a rifle fires at a distant target, where should the barrel be pointing?

Answers

When a rifle fires at a distant target, the barrel should be pointing straight towards the target.

This is because the barrel is the part of the rifle that the bullet travels through to reach the target. If the barrel is not pointing directly at the target, the bullet may not hit it.

Therefore, it is important to aim the barrel accurately when shooting a rifle at a distant target.

A rifle is a long gun designed to be fired from the shoulder, with a barrel that has spiral grooves (rifling) cut into the inside of the barrel wall that forces the bullet to rotate as it moves out of the barrel.

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How do I find the velocity and displacement? How would I graph the velocity on the velocity vs time graph?

How do I find the velocity and displacement? How would I graph the velocity on the velocity vs time graph?

Answers

Recall that the velocity is the rate of the change of position.

Mathematically,

\(v=\frac{\Delta x}{\Delta t}=\frac{x_2-x_1}{t_2-t_1}_{}\)

Notice from the position graph that it is a uniform motion.

To find the rate of change, select any two points on the line.

(1, 1) and (3, 3)

\(v=\frac{\Delta x}{\Delta t}=\frac{x_2-x_1}{t_2-t_1}_{}=\frac{3-1}{3-1}=\frac{2}{2}=1\)

This means that the velocity is 1 m/s and it is constant.

How do I find the velocity and displacement? How would I graph the velocity on the velocity vs time graph?
Other Questions
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