A sample of a commercial wastewater has the initial dissolved oxygen reading of 9 mg/L. The reading after 2 days without adding any additional oxygen is 6 mg/L. The kinetic rate constant is 0.15/d. Estimate what would be the BOD concentration after 10 days

Answer:

204,375 mL.

Explanation:

327 mL - 3.2 M

x mL - 2 M

x= (2 M x 327 mL) /3.2 M

x= 204,375 mL.

What does acetic anhydride form when it reacts with water?

*Note that:- It is an exothermic reaction.

A system of linear equations to balance the following chemical reaction:

Limestone, CaCO₃, neutralizes the acid, H₃ O, in acid rain is:

2H₃O + CaCO₃ → 3H₂O + Ca + CO₂

To balance the chemical equation:

H₃O + CaCO₃ → H₂O + Ca + CO₂

We need to ensure that the number of atoms of each element is the same on both sides of the equation.

Let's assign variables to the coefficients of each compound:

H₃O: x

CaCO₃: y

H₂O: z

Ca: a

CO₂: b

Now, we can set up the system of equations based on the number of atoms for each element:

For hydrogen (H):

3x = 2z

For oxygen (O):

3x + 3y = 2z

For calcium (Ca):

y = a

For carbon (C):

y = b

For calcium (Ca):

a = 1

Solving this system of equations will give us the balanced coefficients. Let's solve it:

From the equation y = a, we have y = 1.

From the equation y = b, we have b = 1.

Substituting b = 1 into the equation 3x + 3y = 2z, we have:

3x + 3 = 2z

From the equation 3x = 2z, we have x = (2/3)z.

Substituting x = (2/3)z into the equation 3x = 2z, we have:

3(2/3)z = 2z

2z = 2z

This equation is true for any value of z, indicating that z can take any value.

Therefore, we can choose z = 3 to simplify the coefficients:

x = (2/3)z = (2/3)(3) = 2

y = 1

z = 3

a = 1

b = 1

Thus, the balanced equation is:

2H₃O + CaCO₃ → 3H₂O + Ca + CO₂

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The 20 mL of an approximately 10% aqueous solution of ethylamine, CH₃CH₂NH₂, is titrated with 0.30 M aqueous HCl. The indicator would be most suitable for the titration is Bromocresol green, color change from pH = 4. 0 to 5. 6. The correct option is B.

The equation is as follows :

CH₃CH₂NH₂  +  H⁺  ⇄ CH₃CH₂NH₃⁺

10 g of CH₃CH₂NH₂   in  the 100 ml solution.

The molar mass = 45.08 g/mol

The number of moles = 10 / 45.08

The number of moles= 0.222 mol

Molarity = 0.222 / 0.100

Molarity = 2.22 M

The number of moles   = 0.02  × 2.22

                                      = 0.0444 mol

The pKa Value = 10.75

The pKb value =  14 - pKa

                         = 14 - 10.75

                         = 3.25

pH = (1/2)pka - (1/2)pkb - (1/2)log [C]

pH = (1/2)10.75 - (1/2)3.25 - (1/2)log [2.22]

pH = 5.2

Therefore, the indicator that suitable for  titration is the Bromocresol Green , the Color change from the pH between 4.0 to 5.6. The option B is correct.

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Answer:

Closed system. :)

Explanation:

When the lid on the pot of soup is closed, it means matter can no longer escape, which in turn, makes it a closed system. I hope this helps, please let me know if you have any further questions

When you stir sugar into your tea with a spoon, the tea keeps swirling

even after you take your spoon out.This is first law of motion.

Motion is defined as a phenomenon which is described with respect to change in object's position with respect to time.It is given in terms of displacement,velocity,distance ,acceleration,speed.

Branch of physics which deals with motion of objects without any reference to it's cause is called kinematics while the branch which studies forces and their effects on motion is called as dynamics.

Motion applies to various systems like objects,bodies, matter particles ,radiation ,curvature.There are three laws of motion which are proposed by Newton.Classical mechanics is based on Newton's law of motion.Relativistic  mechanics is based on modern kinematics.

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Molarity of the solution is 0.071

aqueous solution of a compound with a molar mass of 34.02 g/mol is 21.5% by mass and has a density of 1.13 g/cm3

The equation is as follows: Molarity = (% by weight 10 d)/GMM. Density (d) and gram molecular mass (GMM) are used here.

Derive the formula : Molarity = (% by weight × 10 × d )/ GMM

(21.5% *10 *1.13 ) /34.02  = 0.071.

Molarity of the solution is 0.071

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The  letter represent the transition from solid to liquid E. E.

Transition is a process of change from one state or condition to another. It is a fundamental element of life, as it allows us to move forward, adapt, and develop. Transition can be physical, emotional, spiritual, or even intellectual. It can involve a change in environment, relationships, beliefs, roles, or responsibilities. Transition can be gradual, or it can happen suddenly. It can be difficult and require a lot of effort, or it can be relatively easy. Transition can be a positive experience, or it can be a difficult experience. Regardless of the form it takes, transition is a necessary part of life and growth.

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0.557 moles of K₂S react to produce 112.876 g of KNO₃.

Balanced chemical equation for the reaction is:

2LiNO₃ + K₂S → 2KNO₃ + Li₂S

From the equation, we can see that 2 moles of KNO₃ are produced for every 1 mole of K₂S that reacts.

Therefore, to determine the mass of KNO₃ produced, we need to first calculate the number of moles of KNO₃ produced:

0.557 moles of K₂S × (2 moles of KNO₃ / 1 mole of K₂S) = 1.114 moles of KNO₃

Next, we can use the molar mass of KNO₃ to convert moles to mass:

1.114 moles of KNO₃ × 101.1032 g/mol = 112.876 g of KNO₃

Therefore, 0.557 moles of K₂S react to produce 112.876 g of KNO₃.

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Answer: a. 1-chloro-4-methylpent-2-yne - \(C_6H_9Cl\)

              b. 5-chloro-2-methylpent-3-yne - \(C_6H_7Cl\)

              c. sec-butyl chloromethyl acetylene - \(C_{12}H_{21}ClO_2\)

              d.1-chloro-4,4-dimethylbut-2-yne - \(C_6H_9Cl\)

What is the full name of IUPAC?

The full name of IUPAC is International Union of Pure and Applied Chemistry.

The compound's name is typed out first, followed by the base name and the substituents in alphabetical order (derived from the number of carbons in the parent chain). Between numbers and letters are separated by dashes and commas, respectively. The name has no spaces.

Therefore, a. 1-chloro-4-methylpent-2-yne - \(C_6H_9Cl\)

              b. 5-chloro-2-methylpent-3-yne - \(C_6H_7Cl\)

              c. sec-butyl chloromethyl acetylene - \(C_{12}H_{21}ClO_2\)

              d.1-chloro-4,4-dimethylbut-2-yne - \(C_6H_9Cl\)

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The value of K_eq for this reaction is approximately 1.805 × 10^-5.

To find the value of the equilibrium constant (K_eq) for the given reaction, we can use the equilibrium concentrations of the species involved. The equilibrium constant expression for the reaction is:

K_eq = [CH3COO-][H3O+] / [CH3COOH]

Given the following concentrations at equilibrium:

[CH3COOH] = 2.0 × 10^-1 M

[CH3COO-] = 1.9 × 10^-3 M

[H3O+] = 1.9 × 10^-3 M

Substituting these values into the equilibrium constant expression, we get:

K_eq = (1.9 × 10^-3)(1.9 × 10^-3) / (2.0 × 10^-1)

K_eq = 3.61 × 10^-6 / 2.0 × 10^-1

K_eq = 3.61 × 10^-6 × 5.0 × 10^0

K_eq = 1.805 × 10^-5

Therefore, the value of K_eq for this reaction is approximately 1.805 × 10^-5.

None of the provided answer choices match this value exactly.

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To determine Eo for the given reaction, we can use the equation:  Eo(cell) = Eo(cathode) - Eo(anode)

The reduction potential for the cathode is the reduction potential of Ti²⁺, which is -1.63 V.

The reduction potential for the anode is the reduction potential of Fe³⁺, which is 0.77 V.

Plugging the values into the equation, we have:

Eo(cell) = (-1.63 V) - (0.77 V)

Eo(cell) = -2.40 V

Therefore, the standard cell potential (Eo) for the given reaction is -2.40 V.

This negative value indicates that the reaction is not spontaneous under standard conditions. The electrons flow from the anode (Fe³⁺) to the cathode (Ti²⁺), resulting in a negative cell potential. The reaction would require an external energy source to proceed.

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Answer:

Q

Explanation:

√10=3.16

The device that is most famously used to find the molecular weight of a compound is a mass spectrometer.

A mass spectrometer is an analytical instrument that is used to measure the mass-to-charge ratio of charged particles. It works by ionizing a sample of the compound, accelerating the ions, and then measuring their masses using a magnetic or an electric field. The resulting mass spectrum can be used to determine the molecular weight of the compound, as well as its elemental composition and isotopic distribution. Mass spectrometry is widely used in chemistry, biochemistry, and other fields to identify and quantify molecules, and it is considered one of the most accurate and precise methods for determining molecular weight.

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Answer:

Column A            \({}\)                                              Column B

1. CaS                   \({}\)                                              Calcium Sulfide

2. CaSO₄            \({}\)                                                Calcium sulfate

3. CaSO₃            \({}\)                                                 Calcium sulfite

Explanation:

1) Calcium sulfide is a compound formed between calcium, Ca, and sulfur, S, with a chemical formula of CaS. It forms cubic crystals similar to rock salt, and smells like rotten eggs

2) Calcium sulfate is a chemical compound consisting of calcium, Ca, and sulfate SO₄. It is found in nature in the hydrated form as the mineral gypsum

3)Calcium sulfite is a chemical compound formed between calcium, Ca and sulfite, SO₃ used to treat water and preserve food.

Answer:

the formula for calcium sulfite is CaSO3

the formula for calcium sulfate is CaSO4

the formula for calcium sulfide is CaS

Explanation:

The identity of the gas sample that weighs 4.84g and occupies a volume of 0.918L at 35 °C and 850torr is CHCl₃ with molar mass of 119.4g/mol (option A).

The number of moles of an ideal gas can be calculated using the ideal gas law equation as follows:

PV = nRT

Where;

According to this question, a sample of gas weighs 4.84g and occupies a volume of 0.918L at 35 °c and 850 torr. The number of moles can be calculated as follows:

1.12 × 0.918 = n × 0.0821 × 308

1.028 = 25.286n

n = 0.041moles

molar mass of gas = 4.84g ÷ 0.041moles

molar mass = 119.4g/mol

Therefore, the identity of the gas is CHCl₃.

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Answer: D. OH- (Edmentum)

Explanation: Took the test and got it right!

The mass of \(5.83 * 10^{17\) molecules of liquid propane is \(4.27 * 10^-5 g.\)

The mass of \(5.83 * 10^{17\)molecules of liquid propane (LP gas) can be calculated as follows.

The given quantity is the number of molecules. We need to calculate the mass of this given number of molecules. The molar mass of LP gas (\(C_3H_8\)) is 44.11 g/mol.

To calculate the mass of 1 molecule of LP gas (\(C_3H_8\)), we can use the molar mass of LP gas as follows:molar mass of LP gas (\(C_3H_8\)) = 44.11 g/molNumber of molecules present in 1 mol of\(C_3H_8\) = Avogadro's number = 6.022 × 10²³

Number of molecules present in 44.11 g of \(C_3H_8\) = 6.022 × 10²³So, the mass of 1 molecule of\(C_3H_8\) can be calculated as follows:

44.11 g of \(C_3H_8\) = 6.022 × 10²³ molecules1 g of\(C_3H_8\) = (6.022 × 10²³)/44.11 molecules

Mass of 1 molecule of \(C_3H_8\) = (1/6.022 × 10²³) × 44.11 g = 7.33 × \(10^{-23\)g

Now, the mass of 5.83 × 10^17 molecules of C3H8 can be calculated as follows:

mass of \(5.83 * 10^{17\) molecules = \(5.83 * 10^{17\)) × (7.33 × \(10^{-23\)) g= 4.27 ×\(10^{-5\) g

Therefore, the mass of\(5.83 * 10^{17\)molecules of liquid propane is \(4.27 * 10^-5 g.\)

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Answer:

D.) electron spin

Each sublevel is labeled by its principal energy level and sublevel. Electrons are indicated by arrows inside of the circles. An arrow pointing upwards indicates one spin direction, while a downward pointing arrow indicates the other direction

Answer:

B.

No light

C.

Explanation:

B. Maximum in A, Minimum in B

When a colored filter is placed in the path of white light, the light passes through the filter, is of the same color as that of filter.

So, when the white light passes through the red filter, the red light pass through it.

When red light pass through the green filter, the light passes through the green filter is none, so this is dark.

C.

When the nail is placed in ordinary water, it gets rusted due to the oxygen present in water.

When nail is placed in boiling water which is covered with oil, so the rust is very small quantity as boiling water also contains some oxygen.

When the nail is placed in calcium carbonate, it absorb all the moisture of air and no rusting takes place.

So, maximum rusting in test tube A and minimum rusting is in test tube C.  

Answer:

The main features of plate tectonics are:

Convection currents beneath the plates move the crustal plates in different directions. The source of heat driving the convection currents is radioactivity deep in the Earths mantle.

The important features of earth's plates are seismicity,volcanicity  and tectonic activity along plate margins.

It is a generally accepted scientific theory which takes into consideration earth's crust to be made up of tectonic plates. These plates move slowly and are moving since 3.4 billion years ago.

The model is developed on the concept of continental drift .Earth's lithosphere is split up in to seven-eight major plates and many minor plates.The position where plates meet their relative motion determines the plate boundary.

Tectonic plates are made up of lithosphere of ocean and thicker continental lithosphere.These plates are able to move because lithosphere has high mechanical strength.Lateral density variations occurring in mantle cause convection.

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It will take approximately 18197 years for the sample of C-14 to decay from an activity of 1050 to an activity of 205.

The question is asking for the number of years that will pass before a sample of C-14 decays from an activity of 1050 to an activity of 205. Given that the half-life of C-14 is 5700 years, we can use the formula for exponential decay to solve for the time required. The formula is:
N = N₀ (1/2)^(t/t₁/₂)
where:
N = final amount
N₀ = initial amount
t = time elapsed
t₁/₂ = half-life
We can rearrange the formula to solve for t:
t = t₁/₂ (ln(N₀/N)) / ln(1/2)
Using the given values, we have:
N₀ = 1050
N = 205
t₁/₂ = 5700
Substituting into the formula:
t = 5700 (ln(1050/205)) / ln(1/2)
t ≈ 18197 years (rounded to the nearest year)

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It will take approximately 18197 years for the sample of C-14 to decay from an activity of 1050 to an activity of 205.

The question is asking for the number of years that will pass before a sample of C-14 decays from an activity of 1050 to an activity of 205. Given that the half-life of C-14 is 5700 years, we can use the formula for exponential decay to solve for the time required. The formula is:

N = N₀ (1/2)^(t/t₁/₂)

where:

N = final amount

N₀ = initial amount

t = time elapsed

t₁/₂ = half-life

We can rearrange the formula to solve for t:

t = t₁/₂ (ln(N₀/N)) / ln(1/2)

Using the given values, we have:

N₀ = 1050

N = 205

t₁/₂ = 5700

Substituting into the formula:

t = 5700 (ln(1050/205)) / ln(1/2)

t ≈ 18197 years (rounded to the nearest year)

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Answer:

Im assuming a glass of water

Explanation:

there is less water that needs to be heated up

Answer:

yes I know it.

Explanation:

A:positive terminal

B:cathode

C:electrolyte

D:anode

E:negative terminal

Thank you for this question

Answer

Molarity (C) = 0.41 mol/L

Explanation

Given:

Number of moles = 3.5 moles

Volume = 8.50 L

Required: Molarity of the solution

Solution

To solve for molarity, you can use the following equation

Where C is the concentration or molarity, n is the number of moles and V is the volume of the solution.

C = 3.5 mol/8.50 L

C = 0.41 mol/L

Answer:

Explanation:

Decomposition reaction, also known as analysis or dissociation, is a type of chemical reaction in which a compound breaks down into simpler substances or elements. In this reaction, a single reactant undergoes a chemical change and produces two or more products.

The decomposition reaction can be represented by the general equation:

AB → A + B

Where AB is the reactant, and A and B are the products. The reactant AB is usually a compound, and it breaks down into its constituent elements or simpler compounds.

There are different types of decomposition reactions, including:

Thermal decomposition: It occurs when a compound is heated, resulting in its decomposition into simpler substances. For example, the thermal decomposition of calcium carbonate (CaCO3) produces calcium oxide (CaO) and carbon dioxide (CO2):

CaCO3 → CaO + CO2

Electrolytic decomposition: It takes place when an electric current is passed through an electrolyte, causing it to break down into its component ions. For instance, the electrolysis of water (H2O) leads to the decomposition into hydrogen gas (H2) and oxygen gas (O2):

2H2O → 2H2 + O2

Photochemical decomposition: It occurs when a compound undergoes decomposition due to exposure to light energy. Chlorine gas (Cl2) can decompose into chlorine atoms (Cl) under the influence of light:

Cl2 → 2Cl

These are just a few examples of decomposition reactions. They are important in various chemical processes and are used in industries, laboratory experiments, and natural phenomena. By understanding and controlling decomposition reactions, scientists can gain insights into the behavior of different compounds and develop practical applications in fields such as chemistry, materials science, and environmental science.

Answer:

Explanation:

reaction in which a compound breaks down into simpler substances or elements

Answer:

V= 8.235 ml

Explanation:

The man above me copied me from the comments

I did it >:C

The expected major kinetic product formed from addition of one mole of HBr to the diene is the 1,2-dibromide.

This is because the reaction occurs through a Markovnikov addition mechanism, where the H+ adds to the diene at the carbon with the most hydrogens, and the Br- adds to the carbon with the least hydrogens. This results in the formation of the 1,2-dibromide as the major product.

The reaction occurs in a kinetically controlled manner, meaning that the product formed is the one with the lowest activation energy and therefore forms the fastest.

In summary, the expected major kinetic product formed from the addition of one mole of HBr to the diene is the 1,2-dibromide, formed through a Markovnikov addition mechanism where the H+ adds to the carbon with the most hydrogens and the Br- adds to the carbon with the least hydrogens.

This reaction occurs in a kinetically controlled manner, where the product formed is the one with the lowest activation energy and forms the fastest.

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