A rower travels upstream at 6 km/h and back to the starting place at 10 km/h. The total journey takes 48 minutes. How far upstream did the rower go?.

The value of n in the given function is negative even integer.

The given parameters:

\(f(x) = a(x + k)^{\frac{1}{n } } + c\)

When n is positive, the function is written as;

\(f(x) = a(x + k)^{\frac{1}{n } } + c\)

When n is negative, the function is written as;

\(f(x) = a(x + k)^{\frac{1}{-n} } + c\\\\f(x) = \frac{a}{(x + k)^n} + c\)

When n is odd integer, the function will have three possible curves.

When n is even integer, the function will have two curves: one real solution and one imaginary solution.

When n is positive even integer, the real solution will curve upwards.

When n is negative even integer, the real solution will curve downwards.

The plot in the given graph curves downwards which indicates negative even integer value of n.

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Answer: N is a positive even integer

Explanation: The answer above is wrong I did the quiz once alr.

The pressure water exerts on the fish tank is 5000 N/m², or 5000 Pascal (Pa).

To calculate the pressure water exerts on a fish tank, we can use the formula:

Pressure = Force / Area

Given:

Force on the bottom of the tank (F) = 2000 N

Area of the bottom of the tank (A) = 0.4 m²

Substituting the values into the formula:

Pressure = 2000 N / 0.4 m²

Pressure = 5000 N/m²

Pressure is defined as the force applied per unit area. In this case, the force exerted by the water on the bottom of the tank is 2000 N, and the area of the bottom of the tank is 0.4 m². By dividing the force by the area, we find that the pressure exerted by the water is 5000 Pa.

This means that each square meter of the bottom of the tank experiences a force of 5000 N, or equivalently, the water exerts a pressure of 5000 Pa on the tank. The pressure exerted by the water is perpendicular to the surface, pressing down on the bottom of the tank.

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Answer:

C

Explanation:

The chemical equation represents one of the reactions that form acid rain. the two options that list the bonds that form in the reaction are the bond between N and O and between H and O in HNO₂, the bond between N and O, and the bond between H and O in the HNO₃

Therefore the correct options are option B and option C.

The chemical compound is a combination of two or more either similar or dissimilar chemical elements

For example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom.

These chemical compounds are formed because of different types of bonds between the constituents' elements, the chemical bonds are mainly ionic bonds, covalent bonds, and hydrogen bonds.

As given in the problem statement the given chemical equation represents one of the reactions that form acid rain. the two options that list the bonds that form in the reaction are the bond between N and O and between H and O in HNO₂, the bond between N and O, and the bond between H and O in the HNO₃.

Thus, the correct options are option B and option C.

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When the brake is applied to the car and comes to rest after some time is an example of an object that is slowing down.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

1. When the brake is applied to the body and comes to rest after some time is an example of an object that is slowing down.

2. When a person accelerates the car and the velocity is increasing is an example of speeding up.

3. An object moves in a circular motion moving at a constant speed but changing direction,

4. Acceleration is the rate of change of velocity. If the change in the velocity is constant the acceleration is zero is an example of moving at a constant velocity with zero acceleration.

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Answer:

an elevator stopping on the third floor

Explanation:

The example that best represent balanced force as regards this question is an elevator stopped on the third floor.

Examples of balanced forces are;

Therefore option A is correct, because balanced force exist as the elevator stopped.

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Answer:

3136 Joules

Explanation:

Applying,

P.E = mgh.............. Equation 1

Where P.E = potential energy, m = mass of the cinder block, h = height of the platform, g = acceleration due to gravity.

From the question,

Given: m = 16 kg, h = 20 m

Constant: g = 9.8 m/s²

Substitute these values into equation 1

P.E = 16(20)(9.8)

P.E = 3136 Joules

Hence the potential energy of the cinder block is 3136 Joules

Answer:

v1 = −2.201946 m/s ( to the left)

v2 = 0.7780534 m/s ( to the right)

Explanation:

Given the following :

Mass of first glider (m1) = 0.149kg

Initial Speed of first glider (u1) = 0.710 m/s

Mass of second glider (m2) = 0.308kg

Initial Speed of second glider (u2) = 2.27m/s

For elastic collision:

m1u1 + mu2u2 = m1v1 + m2v2

Where V1 and v2 = final velocities if the body after collision.

Taking right as positive ; left as negative

u1 = 0.710m/s ; u2 = - 2.27m/s

u1 - u2 = - (v1 - v2)

0.710 - - 2.27 = - v1 + v2

v2 - v1 = 2.98 - - - - (1)

From:

m1u1 + mu2u2 = m1v1 + m2v2

(0.149 * 0.710) + ( 0.308 * - 2.27) = (0.149 * v1) + (0.308 * v2)

0.10579 + (-0.69916) = 0.149 v1 + 0.308v2

−0.59337 = 0.149 v1 + 0.308v2

Dividing both sides by 0.149

v1 + 2.067v2 = −0.59337 - - - - - (2)

From (1)

v2 = 2.98 + v1

v1 + 2.067(2.98 + v1) = −0.59337

v1 + 6.16 + 2.067v1 = −0.59337

3.067v1 = −0.59337 - 6.16

3.067v1 = −6.75337

v1 = −6.75337 / 3.067

v1 = −2.201946 m/s ( to the left)

From v2 = 2.98 + v1

v2 = 2.98 + (-2.201946)

v2 = 0.7780534 m/s ( to the right)

Answer:

The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds.

Hope this helps :)

Ingrid uses a technique called "skate-skiing" where she holds one ski  in a V-shape in the opposite direction while pushing the other.

A technique is a way to accomplish a task or solve a problem. This may involve a specific step-by-step process or a more general approach, drawing on your individual knowledge and skills.

Techniques include physical acts, mental processes, or both.  Examples of techniques include using a hammer to hammer nails, using certain equations to solve math problems, and using certain types of meditation to relax.

The goal of any technique is to make the task easier, faster, or more accurate. This allows skiers to move over the snow without actually skiing in the traditional way. This technique is often used in areas of deep, soft snow that are not suitable for traditional skiing.

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The mass of E is 28/3, and the center of mass is located at (35/36, 0, 7/4).

We can use the triple integral to find the mass and center of mass of the solid E:

The limits of integration for x are from 0 to 5z.

The limits of integration for y are from −1 to 1.

The limits of integration for z are from 0 to 1 − y²

The density function is given by ρ(x, y, z) = 7.

Thus, the mass of E is given by:

M = ∭E ρ(x, y, z) dV

= ∭E 7 dV

= ∫₀⁵z ∫₁⁻¹ ∫₀¹−y² 7 dz dy dx

= 28/3

The x-coordinate of the center of mass is given by:

x-bar = (1/M) ∭E xρ(x, y, z) dV

= (1/M) ∭E x(7) dV

= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² x(7) dz dy dx

= 35/36

Similarly, the y-coordinate of the center of mass is given by:

y-bar = (1/M) ∭E yρ(x, y, z) dV

= (1/M) ∭E y(7) dV

= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² y(7) dz dy dx

= 0

And, the z-coordinate of the center of mass is given by:

z-bar = (1/M) ∭E zρ(x, y, z) dV

= (1/M) ∭E z(7) dV

= (1/M) ∫0^5z ∫−1^1 ∫0^1−y^2 z(7) dz dy dx

= 7/4

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The statement illustrates how engineering has influenced society in that People want the cameras in their cell phones to be able to capture high-resolution images. Option C is corect.

A digital camera that creates pictures that can be saved on a computer and seen on a screen.

People want their mobile phone cameras to be able to take high-resolution pictures, which shows how engineering has affected society.

Statement B illustrates how engineering has influenced society.

Hence option C is correct.

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Answer:

A fly is sitting at the midpoint of a wooden chord of a circular wheel. The wheel has a radius of 10cm and the chord has a length of12cm a How far from the hub (center) is the fly? b The wheel is spun. What is the path of the fly?

Explanation:

The distance is 63π cm with a displacement of 14 cm.

Hence, the correct option is C.

Each time the fly buzzes around Kit Yan's head, it travels the circumference of his head. The circumference of a circle is given by the formula:

Circumference = π × Diameter

Given the diameter of Kit Yan's head is 14 cm:

Circumference = π × 14 cm = 14π cm

The fly buzzes four and a half times around his head, so the total distance it travels is:

Total Distance = 4.5 × Circumference = 4.5 × 14π cm = 63π cm

Now, let's consider the displacement. Displacement is the straight-line distance between the initial and final positions.

Since the fly ends up on the opposite side from where it started, the displacement is equal to the diameter of Kit Yan's head, which is 14 cm.

Therefore, The distance is 63π cm with a displacement of 14 cm.

Hence, the correct option is C.

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Answer:

Protium (Hydrogen) has no neutron

Deuterium has one neutron

Tritium has two neutrons

Answer:

Our kinetic energy becomes 4 times bigger

Answer:

C. Do not write anything next to it.

Explanation:

If an equation is already balanced there is no need to provide information of that.

Answer:

D

Explanation:

Water has a high surface tension because the water molecules on the surface are pulled together by strong hydrogen bonds. That means a drop of water will "want" to have the smallest possible surface area.

Component depreciation is an accounting method where the cost of a single asset is allocated to its various components or parts and each component is depreciated separately based on its own useful life.

This approach recognizes that different components of an asset may have different useful lives and may require separate depreciation treatment.

Component depreciation must be used when an asset is composed of distinct components or parts that have different useful lives and can be separately identified. It is commonly applied to assets such as buildings, vehicles, machinery, or equipment that have significant and identifiable components with different useful lives.

By applying component depreciation, the carrying amount of each component is separately depreciated over its respective useful life, which provides a more accurate representation of the asset's value and depreciation expense over time.

The use of component depreciation enhances the accuracy and transparency of financial reporting by reflecting the different economic benefits and consumption patterns of the various components within an asset.

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Answer:

The average speed of a particle for a given ‘Interval of time’ is defined as the ratio of total distance travelled to the total time taken.

Explanation:

To find the average speed we take the total

distance traveled divided by the time interval.

If a box is pushed with a force of 75 n while it moves 6.5 m if this is done in 15 s, the power used is 32.5 W

P = W / t

W = F d cos θ

P = Power

W = Work

t = Time

F = Force

d = Distance

θ = Angle between force and displacement vector

F = 75 N

d = 6.5 m

t = 15 s

θ = 0°

P = F d cos θ / t

P = 75 * 6.5 * cos 0 / 15

P = 487.5 / 15

P = 32.5 W

Therefore, the power used is 32.5 W

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Answer:

#A

Acceleration=a

\(\\ \tt\hookrightarrow a=\dfrac{v-u}{t}=\dfrac{8}{4}=2m/s^2\)

#B

\(\\ \tt\hookrightarrow a=\dfrac{0-8}{4}=\dfrac{-8}{4}=-2m/s^2\)

Answer(s):

Solution for Practice-A:

We know that:

Solution:

Hence, the acceleration is 2 m/s for practice A.

Solution for Practice B:

We know that:

Solution:

Hence, the acceleration is -2 m/s for practice B.

Hoped this helped!

ANSWER

EXPLANATION

Parameteters given:

Initial velocity = 190 m/s

To find the maximum height, we apply the formula for the maximum height of a projectile:

where u = initial velocity

θ = angle with the horizontal

g = acceleration due to gravity = 9.8 m/s²

From the question, the projectile is fired vertically upward. This means that the projectile will make a 90° angle with the horizontal.

Therefore, we have that the maximum height of the projectile is:

Answer:

Height is equal to 1841.8367m

Explanation:

KE = GPE

Write out the formula

1/2(m)(v^2) = mgh

Fill it with the information you have

1/2(190^2) = (9.8)(h)

Solve

1/2(36100) = 9.8h

18050 = 9.8h

1841.83673 = h

Write the complete answer out

Maximum height is equal to 1841.8367m (meters)

Answer:

Approximately \(0.3\; {\rm m}\). (Assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

In this question, the ball initially possesses gravitational potential energy \(\rm GPE}\) and kinetic energy \({\rm KE}\). That energy was converted into the elastic potential energy \({\rm EPE}\) of the compressed spring.

Let \(m\) denote the mass of the ball. When the height of the ball changes by \(\Delta h\), the change in the \({\rm GPE}\) of the ball would be \({\rm GPE} = m\, g\, \Delta h\).

Let \(v\) denote the initial speed of the ball. The initial kinetic energy of the ball would be \({\rm KE} = (1/2)\, m\, v^{2}\).

Assume that the height of the cliff far exceeds the height of the spring. Thus, the change in the height of the ball would be approximately the same as the height of the cliff: \(\Delta h \approx 5\; {\rm m}\). The \({\rm GPE}\) of the ball would be:

\(\begin{aligned}{\rm GPE} &= m\, g\, \Delta h \\ &\approx (10)\, (9.81)\, (5)\; {\rm J} \\ &= 490.5\; {\rm J} \end{aligned}\).

With a speed of \(v = 2\; {\rm m\cdot s^{-1}}\), the initial \({\rm KE}\) of the ball would be:

\(\begin{aligned}{\rm KE} &= \frac{1}{2}\, m\, v^{2} \\ &= \frac{1}{2}\, (10)\, (2)^{2}\; {\rm J} \\ &= 20\; {\rm J}\end{aligned}\).

Let \(k\) denote the spring constant of the spring. With a displacement of \(x\), the \({\rm EPE}\) in the spring would be \({\rm EPE} = (1/2)\, k\, x^{2}\).

All that \({\rm GPE} + {\rm KE} \approx (490.5 + 20)\; {\rm J} = 510.5\; {\rm J}\) of energy would have been converted into the \({\rm EPE}\) of the spring.

It is given that \(k = 10000\; {\rm N\cdot m^{-1}}\). In other words, when \(x\) is in meters:

\((1/2)\, (10000)\, x^{2} = {\rm EPE} \approx 510.5\).

Solve for the displacement of the spring, \(x\):

\(\begin{aligned} x &\approx \sqrt{\frac{510.5}{(1/2)\, (10000)}} \approx 0.3\; {\rm m}\end{aligned}\).

Answer:

Applied force

Normal force

Frictional force

Tension force

Wind force

Answer: Reaction force. An object at rest on a surface experiences reaction force .

Tension. An object that is being stretched experiences a tension force.

Friction. Two objects sliding past each other experience friction forces. ...

Air resistance. An object moving through the air experiences air resistance .

Gravitational Force.

Explanation:

The dark area (shade) behind an object that obstructs the path of light is called a shadow

We can only see the outline of the object in a shadow. All details about the object cannot be seen. It is always dark in colour despite the colour of light or the colour of the object.

The true statement about the equation of respiration is:

The mass of the reactants is the same as the mass of the products; option C.

Respiration is the process by which living organisms break down large molecules such as glucose into smaller molecules such a carbon dioxide and water to release energy in the form of ATP.

Respiration are of two types in living organisms:

The equation of aerobic respiration is given below:

In the given equation above, glucose reacts i the presence of oxygen is broken down into carbon dioxide and water and energy is released.

According to the law of conservation of mass, the mass of reactants is equal to the mass of the products.

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Note that the complete question is given below:

Respiration describes the process that living cells use to release energy by combining sugar and oxygen. The primary chemical changes that happen during respiration are shown in the equation below.

C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O + energy

Which statement correctly compares the reactants and products of the equation?

Which statement correctly compares the reactants and products of the equation?

A.

The mass of the reactants is less than the mass of the products.

B.

The mass of the reactants is greater than the mass of the products.

C.

The mass of the reactants is the same as the mass of the products.

D.

The number of reactant molecules is greater than the number of products.

Answer:

The force experienced by the electron is given by:

F = Eq

where E is the electric field strength and q is the charge of the electron.

The charge of the electron is -1.6 × 10^-19 C.

Substituting the values, we get:

3.0 × 10^-6 N = E(-1.6 × 10^-19 C)

Solving for E, we get:

E = (3.0 × 10^-6 N) / (-1.6 × 10^-19 C)

E = -1.875 × 10^13 N/C

The magnitude of the electric field strength between the deflection plates is 1.875 × 10^13 N/C.

Answer:

B. Atoms are altered in both processes

Explanation:

Answer: B. Atoms are altered in both processes

Explanation:

The Luminosity Distance of the particular star is 1.082 × 10¹⁷ meters.

Given that, the apparent brightness of a particular star is 1.3 x 10⁻¹⁰ watt/m².

A parallax measurement shows the star's distance to 150.

We have to calculate the Luminosity Distance Formula.

Now, the Luminosity Distance Formula is given by:

DL = √(L / 4πF)

Where

DL = Luminosity Distance

L = Luminosity

F = Flux Density.

Let's calculate L using the following formula:

L = 4πd²lwhere,d = Distance to the star, and

l = Luminosity of the star.

Substituting the given values, we get:

L = 4π(150²) × 1.3 × 10⁻¹⁰ = 2.411 × 10²⁹ W

Now, let's substitute the calculated values of L and F in the Luminosity Distance Formula, we get:

DL = √(L / 4πF) = √(2.411 × 10²⁹ / (4π × 1.3 × 10⁻¹⁰))= 1.082 × 10¹⁷ meters.

Thus, the Luminosity Distance of the particular star is 1.082 × 10¹⁷ meters.

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Captain C-Bo takes his passengers on a deep-sea fishing trip where he expects them to catch red snappers at a rate of two fish per hour. Deep-sea fishing is done in areas of the ocean that are over 30 meters deep, where there are several types of fish, including red snapper.

The red snapper is a common catch in deep-sea fishing trips as it's a popular and delicious fish. It's found in deep waters from 30 feet to 200 feet in depth, typically near the bottom, and can weigh up to 40 pounds. Red snapper is a popular catch in deep-sea fishing, and because of its popularity, the fishing industry has developed specific rules and regulations to protect it and ensure it's sustainably fished.

In deep-sea fishing, the passengers use a fishing rod and bait to catch fish. The captain knows that each passenger will catch red snapper at a rate of two fish per hour. Thus, if there are 10 passengers on the boat, they would catch 20 fish per hour. If the trip lasts for four hours, each passenger will have caught eight fish. If the trip lasts for eight hours, each passenger will have caught 16 fish.

Thus, it's essential to understand the duration of the fishing trip to determine the catch. In conclusion, on a deep-sea fishing trip, passengers can expect to catch red snapper. If there are 10 passengers, they will catch 20 fish per hour, with each passenger catching two fish. The duration of the trip will determine the overall catch.

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