A rectangular-shaped swimming pool has dimensions of 15m by 30m and is 3.5m deep. When the pool is filled with freshwater, the average force on the short side of the pool due to the water is?

Answer:

Five examples of locomotor movements are:

Hopping

Galloping

Walking

Running

Skipping

Explanation:

I hope it helps ❤❤

Answer:

0.58 L

Explanation:

For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.

(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2

Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.

(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

Consider our givens:

P_1 = 110atm

T_1 = 303K

V_1 = 2L

P_2 = 440atm

T_2 = 353K

Now we simply plug in these values to the equation to find the new volume, V_2.

(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2

(110atm * 2L) * 353K / (303K * 440atm) = V_2

77660 atm*L*K / 133320 K*atm = V_2

0.583 L = V_2

Hence, the new volume is 0.583 L.

Cheers.

Over time, these tiny fragments will pile up at the bottom of the river and form sediment. Sedimentation can cause the formation of new rocks or change the structure of existing rocks by burying them.

The water in a fast-moving river causes rocks to bump and scrape against one another. As the rocks scrape against each other, they break off tiny pieces from their surface.

Over time, these tiny fragments will pile up at the bottom of the river and form sediment. Sedimentation can cause the formation of new rocks or change the structure of existing rocks by burying them.

The rocks are going to get smaller and rounder, which is why rocks in fast-moving rivers are usually smoother than rocks in slow-moving water.

The erosion process can also form potholes or other unique shapes in rocks. Furthermore, fast-moving water can push rocks downstream, where they may settle in a new location or be washed away entirely.

The movement of rocks in a river can also change the shape and structure of the riverbed. When rocks are removed from a river, the water may begin to flow differently, which can cause erosion in other areas.

In summary, the rocks will get smaller and smoother over time due to the constant erosion and sedimentation caused by the water in the fast-moving river.

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If the fundamental frequency of the harmonic is 7 Hz, the frequency at which it is created depends on the harmonic being referred to.

Frequency of harmonics

If the fundamental frequency of a harmonic is 7 Hz, then the frequency at which the harmonic is created depends on the harmonic series being used.

The frequency of the nth harmonic in a harmonic series is equal to n times the fundamental frequency. Therefore, the first five harmonics of a harmonic series with a fundamental frequency of 7 Hz would be:

First harmonic (fundamental): 7 Hz

Second harmonic: 2 x 7 Hz = 14 Hz

Third harmonic: 3 x 7 Hz = 21 Hz

Fourth harmonic: 4 x 7 Hz = 28 Hz

Fifth harmonic: 5 x 7 Hz = 35 Hz

So, the frequency at which the harmonic with a fundamental frequency of 7 Hz is created depends on which harmonic is being referred to.

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The average speed of the plane is 750 miles/hour.

Initial distance covered by the plane, d₁ = 5000 miles

Second distance covered by the plane, d₂ = 10000 miles

Time taken by the plane to cover distance, t = 20 hours

The average speed of an object is defined as the total distance covered by the object in a given time.

So,

The total distance covered by the plane,

d = d₁ + d₂

d = 500 + 10000

d = 15000 miles

The expression for the average speed of the plane is given by,

v = (d₁ + d₂)/t = d/t

v = 15000/20

v = 750 miles/hour

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Vessel Mass Acting Downward (mg)

Bayonet Force Acting Above Vessel (Fb)

This force is called buoyancy. Buoyancy pushes objects up. Gravity exerts a downward force on an object determined by the object's mass. Therefore, if the downward force exerted by gravity on an object is less than the buoyant force the object floats.

Since the buoyant force on the body and the weight of the body are equal and opposite, the net force on the body is zero, giving the body a net force to levitate. The wind force acting on a sail moving a boat is an example of Newton's third law of motion. That is, every action has an equal and opposite reaction. But the relationship between force and motion is not as simple as the wind blowing just behind the sails propels the ship forward.

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The acceleration of the block down the incline is given by,

\(- a = \dfrac{ mgsin\theta - \mu sN }{m}\text{ if }mgsin\theta > \mu sN\\\\a = \dfrac{ mgsin\theta - \mu kN }{m}\text{ if }mgsin\theta \le \mu sN\)

where N = mgcosθ.

Let N be the normal force acting on the block, and F be the force of friction acting on the block. The force acting down the incline is mgsinθ, where g is the acceleration due to gravity. The net force acting on the block down the incline is given by Fnet = mgsinθ - F. Therefore, the acceleration of the block down the incline is given by a = Fnet/m.

If the block is not yet sliding, we have F = \(\mu sN\). Therefore, the maximum value of the force of friction is \(\mu sN\). If the force of gravity down the incline is greater than the maximum force of static friction, the block will begin to slide, and we have F  = \(\mu kN\).

Therefore, the acceleration of the block down the incline is given by:

\(- a = \dfrac{ mgsin\theta - \mu sN }{m}\text{ if }mgsin\theta > \mu sN\\\\a = \dfrac{ mgsin\theta - \mu kN }{m}\text{ if }mgsin\theta \le \mu sN\)

where N = mgcosθ.

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--The complete question is, What is the acceleration of a block of mass m sliding down a right inclined surface that makes an angle θ with respect to the horizontal, given the coefficients of static and kinetic friction?--

The required net force on any one of the masses of the square on the corners is calculated to be 74.35 × 10⁻¹¹ N.

Four identical masses located at the corners of a square are 2.5 kg each.

The side of the square is given as 1.09 m.

Gravitational constant G = 6.67 × 10⁻¹¹ Nm²/kg²

The expression for gravitational force is said to be,

F = G m₁ m₂/r²

Here, m₁ = m₂ = 2.6 kg

Putting in the values, we have,

F = G m₁ m₂/r² = (6.67 × 10⁻¹¹)(2.6)²/1.09² = (45.09× 10⁻¹¹)/1.19 = 37.9× 10⁻¹¹ N

The resultant force is given by,

Fr = G m₁ m₂/(1.54r)² =  (6.67 × 10⁻¹¹)(2.6)²/(1.54 × 1.09)² = (45.09× 10⁻¹¹)/(1.68)² = (45.09× 10⁻¹¹)/2.82 = 15.99× 10⁻¹¹ N

Therefore, F net = Fr + 1.54 F =  15.99× 10⁻¹¹ + 1.54 × 37.9× 10⁻¹¹ = 15.99 × 10⁻¹¹ + 58.36× 10⁻¹¹ = 74.35 × 10⁻¹¹ N

Thus, the net force on any one of the masses is 74.35 × 10⁻¹¹ N.

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Hello..!

To calculate its displacement, we first apply the data to the problem.

Data:

Now, we apply a conversion.

Conversion:

Then, we apply the formula that is.

Formula:

Finally we develop the problem.

Developing:

The displacement of the bike is 83100 meters.

Answer:

83,333.33 m (2 d.p.)

Explanation:

\(\boxed{\sf Speed=\dfrac{Distance}{Time}}\)

Given values:

As there are 60 minutes in one hour, convert minutes into hours by dividing by 60:

\(\implies \sf Time=\dfrac{50}{60}=\dfrac{5}{6}\;hour\)

Substitute the values into the formula and solve for distance:

\(\implies \sf 100=\dfrac{Distance}{\frac{5}{6}}\)

\(\implies \sf 100=Distance \times \dfrac{6}{5}\)

\(\implies \sf Distance=\dfrac{100 \times 5}{6}\)

\(\implies \sf Distance=\dfrac{250}{3}\;km\)

\(\implies \sf Distance=83.33333...\;km\)

At there are 1000 meters in one kilometer, convert kilometers into meters by multiplying by 1000:

\(\implies \sf Distance=83.33333...\times 1000=83333.33\;m\;(2\;d.p.)\)

The reaction of load L is 0 (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

To determine the reactions of the loads L and R, consider the equilibrium of the forces acting on the structure.

First, analyze the vertical equilibrium. The sum of the vertical forces must be zero:

ΣFy = R − 7 kN − 3 kN

ΣFy = 0

This gives:

R = 10kN

Next, analyze the horizontal equilibrium. The sum of the horizontal forces must be zero:

ΣFx = L

ΣFx = 0

This indicates that there is no horizontal force acting on the structure.

Therefore, the reaction of load L is zero (no horizontal force), and the reaction of load R is 10 kN (vertical upward force).

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ANSWER:

45.0 g

STEP-BY-STEP EXPLANATION:

After rounding to represent the given data to three significant figures, we have to write it down to one decimal place.

So we need to focus on the second decimal place i.e 8 as it is greater than 5 therefore we have to add one (1) to the first decimal place to do the rounding.

Answer: W represents an element Y represents a mixture

Explanation: I just took a quiz on this and got it right. Good Luck

Answer:

However, those astronauts would experience a second spectacle: A solar eclipse caused by the Earth – the Sun disappearing behind the dark disc of the Earth. When Earth inhabitants witness a lunar eclipse, Moon inhabitants would, simultaneously be witnessing a solar eclipse.

Answer:

ANSWER

EXPLANATION

Parameters given:

Speed of water at point 1, v1 = 5.1 m/s

Diameter of pipe at point 1, d1 = 3.5 cm = 0.035 m

Pressure, P1 = 1.9 atm

Diameter of pipe at point 2, d2 = 2.4 cm = 0.024 m

Atmospheric pressure = 1.013 * 10^5 Pa

Density of water = 1000 kg/m^3

First, we have to find the speed of the water at the smaller end of the pipe. To do this, apply the Bernoulli continuity equation:

where A1 and A2 are the cross-sectional areas of the pipes at point 1 and point2 respectively.

Substituting the given values into the equation above:

Now, we have to apply Bernoulli's equation to find the pressure at the constricted segment:

Substitute the known values into the equation and solve for P2, we have:

That is the answer.

Answer:

high blood pressure, high low-density lipoprotein (LDL) cholesterol, diabetes, smoking and secondhand smoke exposure, obesity, unhealthy diet, and physical inactivity.

Explanation:

Answer:

Pencil lead.

Explanation:

no need for an explemation you can put two and two together XD

Answer:

Hello!!! Princess Sakura here ^^

Explanation:

It's pencil lead because the it's taken from a mine and then it goes inside a wooden pencil and everybody uses them if you're not using a pen.

The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

\(v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s\)

So, their average velocity is 1.6 m/s.

Answer:

The decay constant, or "lambda" (λ), is the rate at which a radioactive isotope decays. It is usually measured in units of inverse time, such as seconds. In this case, the decay constant can be calculated as follows:

16:42

λ = (ln(2)/3.57 x 106) x (5.78 x 1017) = 0.

Explanation:

Answer: The displacement is 1 block.

Explanation:

Let's define:

The right is the positive side.

The left is the negative side.

Then if you start at position A, and you walk N blocks to the right, the new position is:

A + N

And if you start at position A, and you walk M blocks to the left, the new position is:

A - M.

In this case, we know that Kayla starts at -3 and she walks 5 blocks to the right.

Then her new position is:

-3 + 5 = 2

Now she walks 3 blocks to the left, then her new position is:

2 - 3 = -1

The displacement will be equal to the difference between the final position (-1) and the initial position (-2)

Then the displacement is:

D = -1 - (-2) = -1 +2 = 1

The displacement is 1 block.

The kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

The total energy of the system is conserved. The initial energy of the system is the electrostatic potential energy, which is given by:

U = k × (Q₁ × Q₂) / r

where:

U = potential energy in joules

k = Coulomb's constant (8.988 x 10⁹ N m²/C²)

Q₁ and Q₂ = charges in coulombs

r = distance between the charges in meters

In this case:

U = 8.988 x 10⁹ N m²/C² × (12 C × 5 Q) / (1.0 m) = 5.375 x 10⁻⁷ J

The final energy of the system is the kinetic energy of particle B. The kinetic energy is given by:

KE = 1/2 × m × v²

where:

KE = kinetic energy in joules

m = mass in kilograms

v = velocity in meters per second

Solve for the velocity of particle B using the conservation of energy equation:

KE = U

Substituting the expressions for KE and U gives:

1/2 × m × v² = 5.375 x 10⁻⁷ J

Solving for v gives:

v = √(2 × 5.375 x 10⁻⁷ J / m)

= 1.53 m/s

The kinetic energy of particle B is then:

KE = 1/2 × m × v²

= 1/2 × m × (1.53 m/s)²

= 4.32 J

Therefore, the kinetic energy of particle B at the instant when the particles are 3.0 m apart is 4.32 J.

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Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

Answer:

Temperature

Explanation:

  T is the measure of an objects particle energy ...

Answer:

24m

Explanation:

you can use the formula

s=ut+1/2at²

s=0+1/2(3)(4)²

=1/2(3)(8)

=24m

I hope this helps

Answer:

patterns i think

Explanation:

Answer:

Is patterns

Explanation:

Answer:

B. Increasing the temperature increases the reaction rate.

Explanation:

This is as with a higher temperature the particles have more kinetic energy, this is the consequece of the increase in reaction rate as the frequency of particles colliding is increased.

Answer: B

Explanation:

The acceleration of an hawk flying at 4m/s but later accelerates at 8m/s in 0.5s is 8m/s².

The acceleration of a moving body can be calculated using the following expression:

a = v - u/t

Where;

According to this question;

a = 8 - 4/0.5

a = 4/0.5

a = 8m/s²

Therefore, the acceleration of an hawk flying at 4m/s but later accelerates at 8m/s in 0.5s is 8m/s².

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