A rectangle is graphed on the coordinate grid.
Which represents the equation of a side that is perpendicular to side s?
y = negative x + 9
y = negative x + 5
y = x + 9
y = x + 3

On a coordinate plane, side p has points (1, 4) and (3, 6), side q has points (3, 6) and (6, 3), side r has points (4, 1) and (6, 3), and side s has points (4, 1) and (1, 4).

Answer:

Proper: 15/4

Improper: 3 3/4

Step-by-step explanation:

Well to solve the following question,

5/12 + (5/12 + 3/4)

We solve the part in the parenthesis first,

5/12 + 3/4 = 14/4

Simplified -> 7/2

5/12 + 7/2

= 45/12

Simplified -> 15/4

Thus,

the answer is 15/4 or 3 3/4.

Hope this helps :)

Answer:

Step-by-step explanation:

\(\frac{5}{12}+\left(\frac{5}{12}+\frac{3}{4}\right)\\\\=\frac{5}{12}+\frac{5}{12}+\frac{3}{4}\\\\\mathrm{Add\:similar\:elements:}\:\frac{5}{12}+\frac{5}{12}=2\times \frac{5}{12}\\=2\times \frac{5}{12}+\frac{3}{4}\\\\=\frac{5\times \:2}{12}\\\\=\frac{10}{12}\\\\=\frac{10}{12}\\\\=\frac{5}{6}+\frac{3}{4}\\L.C.M =12\\\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}\\\\\frac{5}{6}=\frac{5\cdot \:2}{6\times \:2}=\frac{10}{12}\\\\\frac{3}{4}=\frac{3\times \:3}{4\times \:3}=\frac{9}{12}\\\)

\(\\=\frac{10}{12}+\frac{9}{12}\\\mathrm{Since\:the\:denominators\:are\:equal\\\:combine\:the\:fractions}:\\\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\=\frac{10+9}{12}\\\\=\frac{19}{12}\)

By percentage , 79.17%  is the starting range for the grades on the test.

What does percentage ?

When a piece of a whole is stated as a percentage, it is not a fraction but rather a number between 0 and 100. Nothing is zero percent, everything is 100 percent, half of something is 50 percent, and nothing is zero percent. Divide the share of the whole by the whole and multiply the result by 100 to get the percentage.

And the average grade of the 50 students is A.

We know that after it increased by 20%, the average of the grades is 95.

Then we just need to solve the percentage equation:

95 = A*(1 + 20%/100%) = A*(1.2)

95/1.2 = A = 79.17

We conclude that the starting average grade is 79.17%.

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If you use pre-tax dollars, then it lowers your taxable income now and most likely when you retire, your income will be lower, so you'll pay a lower tax rate  then.

Answer: D

Answer:

\(3 \div 7 = x \\ \)

The correct answer is option (e): None of these answers is correct.

The statement "the mode is the most frequently occurring data value" is true. However, none of the options provided accurately describes the relationship between the mode and the mean.

The mode and the mean are different measures of central tendency and can have different values. There is no general rule or guarantee that the mode will always be larger or smaller than the mean. The relationship between the mode and the mean depends on the specific dataset and its distribution. Therefore, none of the provided options correctly describes the relationship between the mode and the mean.

Answer:   75%

                   Hope this helps answer your question!

Answer:

75%

Step-by-step explanation:

3 of 12 bows are red, meaning that 9 bows are not red.  (12-3 = 9)

9 non-red bows/12 bows total = 3/4 = 0.75 = 75%

Answer:3.76 kg.

Step-by-step explanation:

The equation of a vertical line is of the form:

A vertical line has an infinite slope. The slope-intercept form of a line equation is:

where "m" is the slope and "b" is the y-intercept. The equation of a vertical line has an undefined slope because the denominator of the slope, i. e, the change in the "x" variable is zero. Therefore, it cannot be written as a slope-intercept form.

fn is an integrable function on [a, b]. further, assume that the sequence (fn) converges uniformly to f on [a, b]. f is integrable on integral [a, b].

Let ε > 0. Since (fn) converges uniformly to f on [a, b], there exists an N such that |fn(x) - f(x)| < ε for all x ∈ [a, b] and all n ≥ N.

Since fn is integrable on [a, b], it follows that

∫a b|fn(x)|dx < ∞ for all n ≥ N.

We have

∫a b|f(x)|dx ≤ ∫a b|fn(x)|dx + ∫a b|fn(x) - f(x)|dx

Since |fn(x) - f(x)| < ε, it follows that

∫a b|f(x)|dx ≤ ∫a b|fn(x)|dx + ε(b - a)

Since the right hand side is finite, it follows that ∫a b|f(x)|dx is finite. Hence, f is integrable on integral [a, b].

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Based on the distance that Jill is above sea level, and the distance of the whale, the difference in elevation is 1.35 km.

Jill's elevation relative to sea level is:

= +5/4 km

The whale's elevation relative to sea level is:

= - 0.1 km

The difference is therefore:

= 5/4 - (-0.1)

= 1.25 + 0.1

= 1.35 km

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x-7 is not a factor of \(x^{4}-3x^{3}+x^{2} +2x+1435\).

In long division method, we divide  \(x^{4}-3x^{3}+x^{2} +2x+1435\) by x-7

x-7 )  \(x^{4}-3x^{3}+x^{2} +2x+1435\)  (  \(x^{3}-10x^{2} +71x-495\)

        \(x^{4}+7x^{3}\)

  -----------------------------

              \(-10x^{3}+x^{2} +2x+1435\)

             \(-10x^{3}-70x^{2}\)

          --------------------------

                        \(71x^{2} +2x+1435\)

                        \(71x^{2} +497x\)

                   ----------------------------

                                  \(-495x+1435\)

                                  \(-495x-3465\)

                               ----------------------------

                                                 \(4900\)

As 4900 is a remainder, x-7 is not a factor.

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You invested $12,000 in the company when you originally started it. Additionally, you borrowed $12,000 for a five-year (long-term) loan and paid back $2,018 of it.

Businesses, a noun in plural. a group of people who are connected or who have joined together. a guest or guests: We're having people over for dinner. a collection of individuals together for social purposes. association, camaraderie, and fellowship She is a lot of joy to be around.

The Old French word "compagnie," which was first used in the Salic code and meaning "one who eats bread with you," is where the English word "company" originates. To describe a "society, friendship, closeness, or body of troops," it was first used in 1150.

You invested $12,000 in the company when you originally started it. Additionally, you borrowed $12,000 for a five-year (long-term) loan and paid back $2,018 of it.

Total Amount to be when start the company is $12000 + $12000

= $24000

Out of which company owns land and a building worth $8,878 and equipment worth $4,230 and have retained $1,291 in earnings to be reinvested in the company, and you decided to put $1,000 of it aside for a long-term investment.

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Answer:

sold 120 chocolate bars

sold 140 peanut butter bars

Step-by-step explanation:

x = peanut butter bars

y = chocolate bars

x + y = 260, total lbs

0.25x + 0.30y = 71, money

solve double variable equation

multiply -4 on both sides for 2nd equation

-x + -1.2y = -284

add both equations together

-0.2y = -24

y = 120

x = 260 - 120

x = 140

sold 120 chocolate bars

sold 140 peanut butter bars

Answer:

120 to 30 cars to SUVs, 120 to 150 cars to vehicles, 30 to 150 SUVs to vehicles, 4 to 1 cars to SUVs

Answer:

For these types of problems, You must look at the coefficients and variables separately and find the GCF for each. Then, combine the two

First, take 12 and 9

Factors of both

9- 1, 3, 9

12- 1, 2, 3, 4, 6, 12

So the gcf of 12 and 9 is 3

Now do the variables a and a^2

a^2 is just a twice

The GCF is a

Now combine a and 3

Answer: GCF is 3a

Answer:

GCF is 3a

Step-by-step explanation:

I just know LOLLL

Answer:

A

Step-by-step explanation:

48x^2-8x-18x=3

8x(6x-1)-3(6x-1)

(8x-3)(6x-1)

8x-3

Answer:

Step-by-step explanation:

48x2 - 26x + 3

48x2 - 18x - 8x + 3

6x( 8x - 3) - 1(8x - 3)

(8x - 3) and (6x - 1) are the factors

Option A is the correct answer

Heuristic is 0 for every city Heuristic is 1 for every city Selecting an inadmissible heuristic has a -50% penalty.

To find the shortest path to a destination city from a start city using roads (e.g., traveling from Arad to Bucharest) using A* search, the following heuristics are admissible:

Manhattan distance ("go first east/west and then north/south") between a city and start city.

Euclidean distance ("as the crow flies") between a city and destination city.

Euclidean distance ("as the crow flies") between a city and start city.

Manhattan distance ("go first east/west and then north/south") between a city and destination city.

The following heuristics are inadmissible:

Twice the Euclidean distance ("as the crow flies") between a city and destination city.

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The missing number in the expression (5 x 7) + (n x 4) = 5 x (7+ 4) is 5.

The GCF of two or more than two numbers is the highest number that divides the given two numbers completely.

We also know that distributive property states a(b + c) = ab + ac.

Given, An expression (5 × 7) + (n × 4) = 5 × (7 + 4).

Now, If we expand the RHS we have,

5×(7 + 4).

= (5 × 7) + (5 × 4).

Now, Writing the obtained RHS with LHS we have,

(5 × 7) + (n × 4) =  (5 × 7) + (5 × 4).

So, The missing number is 5.

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Answer:

y=x/14+1

Step-by-step explanation:

3(2x-4y) +14-2y=5x

6x-12y+14-2y=5x

6x-14y+14=5x

x+14=14y

x/14+1=y

And dude I feel ur pain no one is responding to my questions :(

Answer: A. 871.97 feet

Here given:

Using Sine Rule:

\(\sf sin(x) = \dfrac{opposite}{hypotenuse}\)

\(\rightarrow \sf sin(33) = \dfrac{height}{1601}\)

\(\rightarrow \sf height = 1601sin(33)\)

\(\rightarrow \sf height = 871.97 \ feet\)

Let's check

Now

Apply Pythagorean theorem

On solving we will get

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Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

J (1, 4 ) → J' (- 1, 4 )

K (1, 0 ) → K' (- 1, 0 )

L (4, 3 ) → L' (- 4, 3 )

Plot the points J', K', L' and connect them in order to obtain image

Answer:

x<-1 or x>11

Step-by-step explanation:

Set the equation x-5>6 and solve. You would then get x>11

For the second part, you want to flip the > sign into < and turn the 6 into -6. Solve the equation to get x-5<-6 which is then x<-1

Answer:

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \(\pi\), and a confidence level of \(1-\alpha\), we have the following confidence interval of proportions.

\(\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}\)

In which

z is the z-score that has a p-value of \(1 - \frac{\alpha}{2}\).

427 had paid for coaching courses and the remaining 2733 had not.

This means that \(n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351\)

95% confidence level

So \(\alpha = 0.05\), z is the value of Z that has a p-value of \(1 - \frac{0.05}{2} = 0.975\), so \(Z = 1.96\).

The lower limit of this interval is:

\(\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232\)

The upper limit of this interval is:

\(\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147\)

The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).

Answer:

42 units

Step-by-step explanation:

Area of a trapezoid is always 1/2(b1+b2)*h

so here base 1 is 4 units, and base 2 is 10 units. When we add these we get 14, divided by 2 which is 7, and multiplied by height of 6, which is 42