A ratio that compares the width and length of a garden is what type of model?

Answer:

In picture one because string telephones are best heard when there is more tension on the string

Explanation:

The angular acceleration of the larger camshaft is 995.72 rad/s².

The given parameters;

The angular acceleration of the 3.75 cm camshaft is calculated as follows;

$$\begin{gathered} {\omega }_f={\omega }_i+\alpha t \\ {\omega }_f=0+\alpha t \\ {\omega }_f=\alpha t \\ (1250\frac{rev}{min}\times \frac{2\pi rad}{rev}\times \frac{1min}{60s})=0.032\alpha \\ 130.92=0.032\alpha \\ \alpha =\frac{130.92}{0.032}=4091.25rad/s^2 \end{gathered}$$

The angular momentum of the camshaft is calculated as follows;

$$\begin{gathered} I_1{\alpha }_1=I_2{\alpha }_2 \\ \frac{1}{2}m{r}_1^2{\alpha }_1=\frac{1}{2}m{R}^2{\alpha }_2 \\ {r}_1^2{\alpha }_1=R^2{\alpha }_2 \\ {\alpha }_2=\frac{r_1^2{\alpha }_1}{R^2} \\ {\alpha }_2=\frac{(0.037{)}^2\times (4091.25)}{(0.075{)}^2} \\ {\alpha }_2=995.72rad/s^2 \end{gathered}$$

Thus, the angular acceleration of the larger camshaft is 995.72 rad/s².

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Answer:

Endothermic, because the reactants are lower in energy (C)

Explanation:

From the graph, you can see the energy of the products is higher than the energy of the reactants. If you recall that  when the enthalpy change  Eproducts is gretater than  Ereactants, the reaction is said to be endothermic.

At the center of buoyancy, the buoyant force operates in an upward, vertical direction.

Here are a few real-world instances of the buoyant force. Iceberg drifting on the sea, a boat traveling down a river An individual wearing a life jacket floating in the water, a ship sailing the seas, a helium balloon soaring into the sky, etc. The density has a direct relationship with the buoyant force.

The fluid's pressure on the object is what creates the buoyant force. The net upward force results from the fact that the pressure on the bottom of an item is always greater than the force on the top since pressure rises as depth increases. Whether an object sinks or floats, the buoyant force always exists.

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Answer: the long day in neptune would be .18383562 years!

Explanation:also for every day is 16 hours

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

6.54 × 10⁻⁵ Pa-s

Explanation:

Since the shear force, F = μAu/y where μ = viscosity of fluid between plates, A = area of plates, u = velocity of fluid = 0.6 m/s and y = separation of plates = 0.02 mm = 2 × 10⁻⁵ m

Since F = μAu/y

F/A = μu/y where F/A = force per unit area

Since we are given force per unit area, F/A = 1.962 N per unit area = 1.962 N/m²

So,  μ = F/A ÷ u/y

substituting the values of the variables into the equation, we have

μ = F/A ÷ u/y

μ = 1.962 N/m² ÷ 0.6 m/s/2 × 10⁻⁵ m

μ = 1.962 N/m² ÷ 0.3 × 10⁵ /s

μ = 6.54 × 10⁻⁵ Ns/m²

μ = 6.54 × 10⁻⁵ Pa-s

The acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

The formula for acceleration due to gravity is:

g = GM/r² Where, g = acceleration due to gravity G = universal gravitational constant M = mass of the planet r = radius of the planet

In this case, since the mass of the hypothetical planet is the same as that of Earth, we can use the mass of Earth instead of M.

Therefore, g is proportional to 1/r².

So, using the ratio of radii given (1.8), we can write:

r = 1.8 x r Earth, where r Earth is the radius of Earth.

Substituting this value of r in the formula for acceleration due to gravity, we get:

g = GM/(1.8 x r Earth)² = GM/(3.24 x rEarth²) = (1/3.24)GM/rEarth²

We know that the acceleration due to gravity on Earth (g Earth) is 9.8 m/s².

Therefore, we can calculate the acceleration due to gravity on the hypothetical planet (gh) as follows:

gh = (1/3.24) x g Earth = 3.02 m/s²

Thus, the acceleration due to gravity near the surface of the hypothetical planet is 3.02 m/s².

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The models provide important tools for understanding the strong force interactions within a proton.

The strong force interactions between quarks and gluons within a proton are described by Quantum Chromodynamics (QCD), which is a fundamental theory of the strong nuclear force in particle physics. QCD is a non-Abelian gauge theory, meaning that the interactions between the quarks and gluons are highly nonlinear and non-perturbative.

One of the most promising theoretical models for describing the strong force interactions within a proton is lattice QCD, which is a numerical approach that uses a discrete grid to represent the space-time continuum. Lattice QCD allows for the calculation of QCD observables from first principles, without resorting to perturbative expansions. This method can handle non-perturbative effects such as confinement and chiral symmetry breaking by allowing for the simulation of the strong interactions on a discrete space-time grid

Another promising model is effective field theory, which provides a way to describe the low-energy behavior of QCD by constructing an effective Lagrangian that contains only the degrees of freedom relevant to a particular energy scale. This allows for the calculation of QCD observables in a systematic expansion in powers of a small parameter, such as the ratio of the quark mass to the QCD energy scale.

Chiral perturbation theory is another effective field theory that focuses on the dynamics of light quarks, which are the building blocks of pions, the lightest hadrons. Chiral perturbation theory provides a systematic expansion for the interactions between pions and nucleons, and can be used to calculate the properties of these particles at low energies.

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Answer:

The skier will be moving at 13.31 m/s.

Explanation:

To calculate the velocity of the skier we need to find the acceleration, as follows:

$\mathrm{\Sigma }F=ma$

$F_r-F_f=ma$

Where:

$F_r$: is the force due to the rope = 365 N

$F_f$: is the combined average frictional force = 190 N

m: is the mass = 75.0 kg

$a=\frac{365N-190N}{75.0kg}=2.33m/s^2$

Now, we can calculate the velocity of the skier by using the following kinematic equation:

$v_f^2=v_0^2+2ad$

Where:

$v_f$: is the final velocity =?

$v_0$: is the initial velocity = 0 (the skier is initially at rest)

d: is the distance = 38.0 m

$v_f=\sqrt{2\ast 2.33m/s^2\ast 38.0m}=13.31m/s$

Therefore, the skier will be moving at 13.31 m/s.

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Total mass lost by the comet is 30.24 x 10¹⁰ kg.

Rate at which mass is lost, R = 35 x 10⁴ kg/s

Time period, T = 100 days = 8.64 x 10⁶s

Therefore,

Total mass lost by the comet, m = R x T

m = 30.24 x 10¹⁰ kg

So,

The fraction of loss = (30.24 x 10¹⁰)/(5 x 10¹⁵) = 60.48 x 10⁻⁵

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A defining characteristic of a city is often referred to as a "landmark." A landmark is a distinctive feature or building that stands out and is used to identify or represent a location. Landmarks can be man-made, such as structures, monuments, or historical locations, or they can be natural, like mountains, rivers, or lakes.

Landmarks are significant tourist destinations for both locals and visitors because they frequently have historical, cultural, or architectural value. They can serve as a symbol of a city's identity, history, and personality and end up being recognised as the place's iconic symbols. Landmarks might be notable buildings, statues, cathedrals, museums, or bridges that have come to symbolise the city in which they are located.

Therefore, option (OB) "landmark" is the term used to describe a distinguishing feature in a city.

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The charge q(t) on the capacitor would be, $q(t)=0.25c(1-e^{-t/0.04s})$

And the current I(t) in the circuit will be,$I(t)=0.25mA(1-e^{-t/0.04s})$

To find the charge q(t) on the capacitor at any time t, we can use the equation for the charge on a capacitor in an RC circuit:

$q(t)=Q_{max}(1-e^{-t/RC})$

where Qmax is the maximum charge on the capacitor, R is the resistance, C is the capacitance, and t is time.

To find Qmax, we can use the equation for the maximum charge on a capacitor in an RC circuit:

Qmax = E × C

where E is the electromotive force.

So, we have:

Qmax = 100 V × 10⁻⁴F = 0.01 C

Using the given values of R and C, we have:

R*C = 400 ohms × 10⁻⁴F = 0.04 s

Substituting these values into the equation for q(t), we get:

$q(t)=Q_0.01(1-e^{-t/0.04C})$

To find the current I(t), we can use Ohm's law and the equation for the charge on a capacitor:

I(t) = (1/R) × d(q(t))/dt

where d(q(t))/dt is the derivative of q(t) with respect to time.

Taking the derivative of q(t), we get:

$dq(t)/dt=0.01C(1-e^{-t/0.04C})$

Substituting this into the equation for I(t), we get:

$I(t)=(1/400ohm)(0.01/0.04s)(1-e^{-t/0.04C})$I

Simplifying, we get:

$I(t)=0.25mA(1-e^{-t/0.04C})$

Therefore, the charge q(t) on the capacitor is:

$q(t)=0.25c(1-e^{-t/0.04s})$

And the current I(t) in the circuit is:

$I(t)=0.25mA(1-e^{-t/0.04s})$

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The correct examples of cause-and-effect relationship are both the systems speed up for the duration of the force exerted on them. Both systems stop moving for the duration of the force exerted on them. Thus, the correct options are C, D, E, and G.

Cause-and-effect relationship describes a relationship which is present between actions or events in which at least one of the action or event is a direct result of the other action or events.

The correct examples of cause-and-effect relationship are both the systems speed up for the duration of the force exerted on them. Both systems stop moving for the duration of the force exerted on them. A spring can exert a force on the dynamic cart. The force of the spring continues to act upon the cart until it stops moving.

Therefore, the correct options are C, D, E, and G.

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Answer:

The object is using kinetic energy if it is in motion

Explanation:

Hope this helps and may God bless you<3

Answer:

The answer is 5×10‐⁵

Step-by-step Explanation:

$\alpha =\frac{l2-l1}{l1(\beta 2-\beta 1)}$

let ß be ø

$\alpha =\frac{40.05-40}{40(45-20)}$

$\alpha =\frac{0.05}{40\times 25}$

$\alpha =\frac{0.05}{1000}$

$\alpha =\frac{0.05}{1000}$$\alpha =5.0\times {10}^{-5}$

Answer:

left

Explanation:

N pole should be in the same direction of the field, so N will point left.

The compass in a uniform magnetic field  always points to the north pole of the magnet. Here, the north pole is at the left and thus, compass needle points to the left.

Magnetic field is produced by the field lines from a strong magnet. The magnetic  field lines are created from  moving electric field. A magnet have two poles namely a south pole and north pole.

Like two the electric charges, where two like charges repel each other and unlike charges attracts, two like poles of a magnet repels and unlike poles attracts each other.

Therefore, at the two poles the magnetic field lines towards the opposite poles will be more stronger . The north pole of a magnet is always pointing to the geographic north and the south pole is attracted towards the north pole. Therefore, compass needle will points towards the geographic north that is left direction here.

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$Question$

explain why it is dangerous to jump out of a moving bus​

Answer:

Hi, there! ♚♛♕♔ッ✨♚

a moving bus is dangerous since the jumping guy, who is moving at the bus's high speed, will appear to stay in motion due to inertia even after falling to the ground, and will be injured due to the ground's resistance.

hope this helps! ♚♛♕♔ッ✨♚

$-xXxanimexXx-$

Answer:

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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According to the information we can infer that the decrease in speed is offset by the increase in radius.

To calculate the speed the ice cube we have to consider that the gravitational force on the ice cube is balanced by the normal force provided by the cone. So, the speed of the ice cube must be such that the centripetal force equals the gravitational force.

In this case, to find the speed of the ice cube let M be the mass of the ice cube and r be the radius of the circular path. The gravitational force on the ice cube is given by Fg = Mg, where:

g = acceleration due to gravity.

The centripetal force is given by Fc = Mv^2/r, where:

v = speed of the ice cube

Setting Fg = Fc, we get:

Solving for v, we get:

v = sqrt(gr)

No piece of data is unnecessary for the solution.

According to the information, when R is made two times larger, the required speed will decrease. For example:

From part (a), v is proportional to the square root of R. Therefore, if R is doubled, v will be multiplied by the square root of 2, which is approximately 1.414.

To know if the time required for each revolution will increase, decrease or stay constant we have to consider that shen R is made two times larger, the time required for each revolution will increase. To see this, note that the period T of the circular motion is given by:

T = 2πr/v

According to the information, the answers to parts (c) and (d) are not contradictory because the decrease in speed is offset by the increase in radius, resulting in a longer period of revolution. The net effect is that the ice cube will travel the same distance in each revolution, so the total time required for one complete revolution will remain constant.

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Answer:

90.3N

Explanation:

⊥mg = (0.170 m)(1.20 kg) 9.81 m/s

τ ball = r⊥Wball = (0.340 m)(1.42 N) = − 0.483 N ⋅m

F − 2.001− 0.483 N ⋅m = 0

F = 2.484 N ⋅m

0.0275 m = 90.3 N

The net torque acting on the forearm and hand is 90.3N

Torque is a measure of the pressure that can motivate an object to rotate about an axis. simply as pressure is what causes an object to accelerate in linear kinematics, torque is what reasons an item to collect angular acceleration. Torque is a vector amount.

⇒mg = (0.170 m)(1.20 kg) 9.81 m/s

⇒torque = r⊥weight of the ball

⇒ (0.340 m)(1.42 N) = − 0.483 N ⋅m

⇒F = − 2.001− 0.483 N ⋅m = 0

⇒F = 2.484 N ⋅m

⇒0.0275 m = 90.3 N

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Answer:

V₁ = 57.9 L.

Explanation:

The initial volume can be found by calculating the work done on the system:

$W=-P(V_2-V_1)$

Where:

P: is the pressure = 0.557 atm

V₂: is the final volume = 55.1 L

V₁: is the initial volume =?

Now, the work can be calculated as follows:

$\mathrm{\Delta }E=Q+W$

Where:

ΔE: is the internal energy of the system = -104.7 J

Q: is the heat absorbed = 51.0 J  

$W=\mathrm{\Delta }E-Q=-104.7J-51.0J=-155.7J$

Hence, the initial volume is:

$V_1=V_2-\frac{W}{P}=55.1L-\frac{-155.7J\ast \frac{1atm\ast L}{101.34J}}{0.557atm}=57.9L$                  

Therefore, the initial volume of the system is 57.9 L.

I hope it helps you!

The rank of the forces in order of increasing magnitude is Fg < FB < FA.

option D is the correct answer.

The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.

That is, the two forces acting on a person when he is moving in an elevator are:

When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.

When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.

Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.

The box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.

FA = FB + Fg

Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.

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Answer:

support lights as a wave

Explanation:

In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.

Answer:

v =  57.2 m/s

Explanation:

The average velocity of the train can be defined as the total distance covered by the train divided by the time taken by the train to cover that distance. Therefore, we will use the following formula to find the average velocity of the train:

v = s/t

where,

s = distance covered = 460 km = (460 km)(1000 m/1 km) = 4.6 x 10⁵ m

t = time taken to cover the distance = 2 h 14 min

Now, we convert it into minutes:

t = (2 h)(60 min/1 h) + 14 min

t = 120 min + 14 min = (134 min)(60 s/1 min)

t = 8040 s

Therefore, the value of velocity will be:

v = (4.6 x 10⁵ m)/8040 s

v =  57.2 m/s

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

$k=\frac{1}{2}m{v}^2$

m is the mass

v is the velocity

From the question we have

$$\begin{gathered} k=\frac{1}{2}\times 8\times 4^2 \\ =4\times 16 \end{gathered}$$

We have the final answer as

Hope this helps you

the answer to your question is 200 J