A pulley system has an input force of 2.5 N and an output force of 10 N. What is the mechanical advantage of this system?

A Pulley System Has An Input Force Of 2.5 N And An Output Force Of 10 N. What Is The Mechanical Advantage

Answers

Answer 1

Answer:

Option B. 4

Explanation:

From the question given above, the following data were obtained:

Input force = 2.5 N

Output force = 10 N

Mechanical advantage (MA) =?

Mechanical advantage (MA) is simply defined as the ratio of the output force to the input force. Mathematically, it can be expressed as:

Mechanical advantage = Output : Input

MA = Output / Input

With the above formula, we can obtain the mechanical advantage of the pulley system as follow:

Input force = 2.5 N

Output force = 10 N

Mechanical advantage (MA) =?

MA = Output / Input

MA = 10/2.5

MA = 4

Thus, the mechanical advantage of the pulley system is 4.


Related Questions

help pls
In 1–2 sentences, describe the factors that affect the current (amperage) in an electric circuit.
A team of students builds an electrical circuit with a battery and a fan. In 1–2 sentences, describe how energy is changed from one form to another in their electric circuit.

Answers

Electric charge inside a sealed electrical system is influenced by power input signal and component resistance. The pace at which electrons travel is called current.

What elements influence a circuit's current?

The elements influence very strong a current flow is: Resistance of the cable and its cross-section. the conductor's material composition and thickness. the possible difference between the conductor's two points. the rate of electron drift and its density

What influences a circuit's amperage?

The amount or fluid velocity of electrons passing a location in the circuit inside one time is known as current. Cranking amps, or amps for short, is another name for current flow. More current is going to flow whenever the voltage is greater, and less current is going to move because when voltage is lesser.

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how do greenhouse gases affect global temperatures​

Answers

Answer:

Less heat radiates into space, and Earth is warmer

For transmissivity (T) = 2500 m2/day, storativity (S) = 1.0 x 10-3, and a pumping rate
(Q) = 500 m3/day, calculate drawdowns in a confined aquifer (isotropic, homogeneous, transient
condition) at observation wells located (i) 10 m and (ii) 50 m at t = 150

Answers

Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

[16 POINTS: 3 Physics Q’s]

9. What is the difference between contact forces and field forces?

11. As an object falls through Earth’s atmosphere, which statement correctly describes the energy change (assume no friction or drag)
A. The potential energy of an object decreases while the thermal energy increases.
B. The kinetic energy of the object increases while the elastic energy increases.
C. The potential energy of the object decreases while the kinetic energy increases.
D. The thermal energy of the object decreases while the kinetic energy increases.


12. Which of the following is true about the charge of an electron?
A. It is 1.602 x 10^-19 C, and the smallest unit of charge
B. It is -1.602 x 10^-19 and the smallest unit of charge.
C. It is -1.602 x 10^-9 , and it a multiple of the smallest unit of charge.
D. It is 1.602 x 10^-19, and it is a multiple of the smallest unit of charge.

*Thanks in advance* ❤️

Answers

Answer:

c

Explanation:

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Ou
A truck starts from rest and accelerates uniformly over a time of 5.5 seconds for a
distance of 130 m. Determine the acceleration (in m/s^2) of the truck.
Please submit your answer with 2 decimal places!

Answers

Answer:

8.6m/s²

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time  = 5.5s

Distance  = 130m

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use one of the appropriate motion equations:

       S  = Ut  + \(\frac{1}{2}\) at²

S is the distance

U is the initial velocity

t is the time taken

a  is the unknown acceleration

t is time taken

    Since U = 0m/s

      S  =  \(\frac{1}{2}\) at²

     130 =  \(\frac{1}{2}\)  x a x 5.5²  

     130  = 15.13a

         a  = 8.6m/s²

Yeah Physics!!!! I will give Brainliest to whoever can solve this question!!!
If i workout 90 minutes on earth, if I am on a rocket traveling 0.80c, according to the timer on the rocket, how long should I exercise?

Answers

Answer:

The person should exercise 150 minutes

Explanation:

Recall that the Lorentz factor must be applied to the relationship between the elapsed time (T) of the clock at rest (time measured on Earth), and the elapsed time (T') measured by the clock in the frame moving at 0.8 c. The equation becomes:

\(T'=\frac{T}{\sqrt{1-(\frac{0.8\,c}{c})^2 } } \\T'=\frac{90\,min}{\sqrt{1-0.8^2} } \\T'=150\,\,min\)

At which recording station did the S-wave arrive first? a. VNQ b. NCA c. ANE d. ANE and VNQ e. NCA and VNQ

Answers

The S-wave arrived first at one or more of the remaining recording stations: NCA, ANE, or ANE and VNQ.

Seismic waves are waves of energy that travel through the Earth's crust and interior following an earthquake. There are two main types of seismic waves: P-waves and S-waves. P-waves are faster and can travel through solid and liquid materials, while S-waves are slower and can only travel through solid materials.

The S-wave is a type of seismic wave that can only travel through solid materials. When an earthquake occurs, the S-wave is produced along with other types of waves, including P-waves. Because S-waves travel slower than P-waves, they arrive at seismic recording stations later than P-waves.

To determine which recording station detected the S-wave first, we need to look for the station that detected the S-wave before any other type of wave. In this case, we are given a list of four recording stations: VNQ, NCA, ANE, and VNQ.

Based on the properties of S-waves, we know that they can only travel through solid materials. Therefore, the S-wave can only be detected by recording stations that are located on solid ground. We can rule out the recording station that is not located on solid ground, which is VNQ.

Next, we need to consider the remaining three recording stations: NCA, ANE, and ANE and VNQ. We don't have enough information to determine which of these stations detected the S-wave first, but we know that at least two of them detected the S-wave before VNQ.

In summary, we can rule out the recording station that is not located on solid ground, VNQ, and determine that the S-wave arrived first at one or more of the remaining recording stations: NCA, ANE, or ANE and VNQ. This determination is based on the fact that S-waves can only travel through solid materials, so they can only be detected by recording stations that are located on solid ground.

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1. Write the goal of the lab or the question you tried to answer.

Answer:

Type your answer here.

Lab report density and buoyancy

Answers

The goal of the lab is to investigate the relationship between density and buoyancy. The lab aims to determine how different objects or substances behave in fluids and understand the principles of density and buoyancy through experimental observations and calculations.

The goal of the lab or the question being addressed in the lab report is to investigate and understand the concepts of density and buoyancy. Density refers to the measure of how much mass is contained within a given volume, while buoyancy refers to the upward force exerted on an object submerged in a fluid, such as water or air.

The lab report aims to explore the relationship between density, mass, and volume by conducting experiments and analyzing data. It may involve measurements of different objects or substances, determining their masses and volumes, and calculating their densities. The report may also involve experiments related to buoyancy, such as determining the buoyant force on an object and investigating factors affecting buoyancy.

By conducting the lab and analyzing the obtained results, the lab report aims to provide a deeper understanding of these fundamental concepts in physics and to demonstrate the principles of density and buoyancy through practical experimentation. The report may also include discussions of the significance and applications of density and buoyancy in various fields, such as engineering, architecture, and fluid dynamics.

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22. The airplane refuels in St. Louis and continues on to Boston. It travels at an average speed of 610 km/h. If the trip takes 2.75 hours, what is the flight distance between St. Louis and Boston? How do you do it?

Answers

The flight distance between St. Louis and Boston is 1677.5 Km

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can stain the flight distance between St. Louis and Boston. Details below.

How to determine the flight distance between St. Louis and Boston

The following data were obtained from the question:

Speed = 610 km/hTime = 2.75 hoursDistance = ?

The flight distance can be obtained as follow:

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 610 × 2.75

Distance = 1677.5 Km

Thus, flight distance between St. Louis and Boston is 1677.5 Km

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A 0.04 kg honeybee circles a field looking for a flower upon which to land. The radius of the circle she travels is 2.5 m and it takes her 1.57 s to complete the circle.

Find the following:
a) Tangential Velocity
b) Centripetal Acceleration
c) Centripetal Force.​

Answers

For the honeybee that circles a field looking for a flower upon which to land, we have:

a) The tangential velocity is 10.01 m/s.

b) The centripetal acceleration is 40.1 m/s².

c) The centripetal force is 1.60 N.

a) The tangential velocity can be calculated as follows:

\( v = \omega r = \frac{2\pi r}{T} \)  (1)

Where:

r: is the radius of the circle = 2.5 m

ω: is the angular velocity = 2π/T

T: is the period = 1.57 s

By entering the above values into equation (1), we have:

\( v = \frac{2\pi r}{T} = \frac{2\pi 2.5 m}{1.57 s} = 10.01 m/s \)  

Hence, the tangential velocity is 10.01 m/s.

b) The centripetal acceleration is related to the tangential velocity as follows:

\( a_{c} = \frac{v^{2}}{r} = \frac{(10.01 m/s)^{2}}{2.5 m} = 40.1 m/s^{2} \)

Therefore, the centripetal acceleration is 40.1 m/s².

c) The centripetal force is given by:

\( F = ma_{c} \)

Where:

m: is the honeybee's mass = 0.04 kg

\( F = ma_{c} = 0.04 kg*40.1 m/s^{2} = 1.60 N \)

Hence, the centripetal force is 1.60 N.

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Radio waves pass through us easily every day with no bad effects. Gamma Rays will kill you in large doses. What is the difference between these two forms of energy?

Answers

Answer:

gamma rays are super compact

Explanation:

as you move up the electromagnetic spectrum the wave lengths get shorter and shorter (higher and higher energy) gammas being the highest on the spectrum

Radio waves pass through us easily every day with no bad effects. Gamma Rays will kill you in large doses. the difference between these two forms of waves are in their energy.

What is wave ?

Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.

Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform.

There are two types of the wave longitudinal wave and transverse wave.

The energy of the electromagnetic photon is given by frequency times plank's constant. Hence energy is directly proportional to the requency. The frequency of the radio waves is far smaller than the gamma rays hence it has low energy. this is the difference, which leads gammas rays  injurious to heath.

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An equipotential surface that surrounds a point charge is called: _________

Answers

Answer:

the answer is the concentric sperical shells

A light spring with force constant 3.05 N/m is compressed by 7.80 cm as it is held between a 0.400-kg block on the left and a 0.800-kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push the blocks apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is 0, 0.035, and 0.397. (Let the coordinate system be positive to the right and negative to the left. Indicate the direction with the sign of your answer. Assume that the coefficient of static friction is the same as the coefficient of kinetic friction. If the block does not move, enter 0.)

Answers

Complete Question

A light spring with force constant 3.05 N/m is compressed by 7.80 cm as it is held between a 0.400-kg block on the left and a 0.800-kg block on the right, both resting on a horizontal surface. The spring exerts a force on each block, tending to push the blocks apart. The blocks are simultaneously released from rest. Find the acceleration with which each block starts to move, given that the coefficient of kinetic friction between each block and the surface is 0, 0.035, and 0.397. (Let the coordinate system be positive to the right and negative to the left. Indicate the direction with the sign of your answer. Assume that the coefficient of static friction is the same as the coefficient of kinetic friction. If the block does not move, enter 0.)

(a) u = 0 heavier block m/s2 m/s2 lighter block

(b)M = 0.035 heavier block m/s2 m/s2 lighter block

Answer:

a)  \(A_h=0.297\)

   \(A_l=-0.59475\)

b)  \(a=0\)

    \(a=-0.25175m/s^2\)

Explanation:

From the question we are told that:

Force constant \(k=3.05N/m\)

Compression Length \(l_c=7.80cm=0.07m\)

Left Mass \(M_l=0.400kg\)

Right Mass \(M_r=0.800kg\)

Coefficient of kinetic friction \(\mu=0, 0.035, and\ 0.397.\)

Therefore

Spring force is given as

 \(F_s=Kx\)

 \(F_s=3.05*0.070\)

 \(F_s=0.238N\)

Generally the equation for Acceleration is mathematically given by

 \(A=\frac{F}{m}\)

For Heavier block

 \(A_h=\frac{F_s}{m_r}\)

 \(A_h=\frac{0.238N}{0.8}\)

 \(A_h=0.297\)

For Lighter blocks

 \(A_l=\frac{F_s}{m_r}\)

 \(A_l=\frac{-0.238N}{0.4}\)

 \(A_l=-0.59475\)

b)

Generally the equation for Force is mathematically given by

\(F_s-F=ma\)

For Heavier block

\(F>Fs\)

Therefore

\(a=0\)

For Lighter blocks

\(F-F_s=ma\)

\((0.035)(0.4)(9.8)-(0.2379)=(0.4)a\)

\(a=-0.25175m/s^2\)

Mass of an empty dry density bottle is 25g, mass of bottle full of water is 53g volume of water in the bottle is 48cm^3.find density of water

Answers

Therefore, the density of water would be 28g/48mL.

The density of an object can be calculated by dividing its mass by its volume.

In this case, we have a density bottle filled with water.

The mass of the empty dry density bottle is 25g, while the mass of the bottle filled with water is 53g.

The volume of water in the bottle is given as 48 cm³.

To find the density of water, we can subtract the mass of the empty bottle from the mass of the bottle filled with water to determine the mass of the water alone.

In this case, the mass of the water would be 53g - 25g = 28g.

Next, we divide the mass of the water by its volume to calculate the density.

The density of water is given by the equation density = mass/volume.

So, the density of water would be 28g/48cm³.

To simplify the units, we can convert cm³ to mL (milliliters), as they are equivalent.

Therefore, the density of water would be 28g/48mL.

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6. When the net force that acts on a hockey puck is 12 N, the puck accelerates at a rate of 48 m/s2. Determine the mass of the puck.A) 0.25 kgB) 1.0 kgC) 5.0 kgD) 2.5 kgE) 2.0 kg

Answers

The equation F=ma, where F is the net force, m is the mass, and an is the acceleration, can be used. . Rearranging the formula to solve for mass, we get m=F/a. Substituting the given values, we get m=12 N/48 m/s^2 = 0.25 kg. Therefore, the answer is A) 0.25 kg.

To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force (F) is 12 N, and the acceleration (a) is 48 m/s². You are asked to determine the mass (m) of the hockey puck.

Using the equation F = ma, you can rearrange it to find the mass: m = F/a

Plug in the given values: m = 12 N / 48 m/s²

Calculate the mass: m = 0.25 kg

The mass of the hockey puck is 0.25 kg, which corresponds to option A.

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if a juggler throws a ball straight up at a speed of 25 m/s, how long will it take to come back down?

Answers

If a juggler throws a ball straight up at a speed of 25 m/s, it will take 5.10 second  to come back down.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Initial upward speed of the ball: v = 25 m/s.

Acceleration due to gravity: g = 9.8 m/s²

Hence, time taken by the ball = 2v/g

= ( 2 × 25)/9.8 second

= 5.10 second.

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The property of our eyes that makes us perceives a rotating coloured disc as white.

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Uh Wait what? Explain

g a box with mass is on a table and is connected with a spring with a spring constant to the wall. there is a friction between the box and the table with coefficient of friction. the spring is pulled distance from its unstretched length and the box is let go. what is the velocity

Answers

The box moves at a speed of 145.3398 m/s when it reaches the point when the spring is not expanded.

Friction is the consequence of the normal force multiplied by the coefficient of friction. The Friction Calculator's formula is given by the expression f = μN, which states that friction f is equal to the normal force N times the coefficient of friction.

Given mass is 4 kg, k is 148 N/mm and μ is 0.4.

Then, the friction force will be calculated as follows,

\(\begin{aligned}f&=\mu N\\&=\mu mg\\&=0.4\times4\times9.81\\&=\mathrm{15.696\;N}\end{aligned}\)

Now, using the energy principle, the velocity of the box is calculated as follows,

\(\begin{aligned}\text{spring potential energy}&=\text{kinetic energy at equilibrium}+\text{work done by friction}\\\frac{1}{2}kx^2&=\frac{1}{2}mv^2+fx\\\frac{1}{2}\times148\times24^2&=\frac{1}{2}\times4\times v^2+15.696\times24\\v&=\mathrm{145.3398\;m/s}\end{aligned}\)

The required answer is 145.3398 m/s.

The complete question is -

A box with a mass of 4 kg is on a table and is connected with a spring constant of 148 N/m to the wall. There is friction between the box and the table with a coefficient of friction of 0.4. The spring has pulled a distance of 24 m from its unstretched length and the box is let go. What is the velocity of the box when it reaches the point where the spring is not stretched?

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g a box with mass is on a table and is connected with a spring with a spring constant to the wall. there

This fossil snake and this living rat both have a structure in their skull called the quadrate bone. What best explains why both species have a quadrate bone?

Answers

The snake and rat both share the same ancestor population that had a quadrate bone, which was inherited from an ancestor population.

What is a homo-logous structure?

A homo-logous structure is a trait that may or not have the same function but has a common evolutionary origin.

A homo-logous structure can be used to trace the evolutionary relationships between species.

Conversely, an analogous structure has the same function but it does not reflect an evolutionary origin.

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A wet bar of soap (m=150 grams) starts at rest and slides without friction down a ramp 2.0 N meters long inclined at 7.3°. How long does it take to reach the bottom?

Answers

A wet bar of soap (m=150 grams) starts at rest and slides without friction down a ramp 2.0 N meters long inclined at 7.3°. It take 1.792 second time to reach the bottom.

What is friction?

Friction is a force that resists the relative motion of two contact points. Friction happens when two bodies come into touch with each other.

Given that,

A wet bar soap mass = 150 gm

Length (l) = 2m

angle (θ) = 7.3°

As we know, F = m × g × Sinθ

Acceleration (a) = \(\frac{F}{m}\) = g × Sinθ

a = (9.8) × Sin 7.3°

a = 1.2452 m/s²

Next,

S = ut + 1/2 at²

2 = 0 + 1/2 × (1.2452) × (t)²  [ As, u = 0 m/s]

t² = 3.212335

t = 1.792 seconds

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Choose the incorrect statement about the blackbody radiation. A. The higher the temperature of a blackbody, the shorter the peak wavelength in the spectrum. B. It produces the continuous spectrum curve with one peak. C. The lower the temperature of a blackbody, the higher the peak frequency in the spectrum. D. The peak position of the spectrum of the blackbody radiation gives the information of the temperature of the blackbody.

Answers

The incorrect statement about blackbody radiation is: The lower the temperature of a blackbody, the higher the peak frequency in the spectrum. The correct option is c).

In reality, the opposite is true: the lower the temperature of a blackbody, the lower the peak frequency in the spectrum.

Blackbody radiation refers to the electromagnetic radiation emitted by an idealized object called a blackbody. A blackbody absorbs all incident radiation and emits radiation across a continuous range of frequencies and wavelengths.

A. The statement that "the higher the temperature of a blackbody, the shorter the peak wavelength in the spectrum" is correct. According to Wien's displacement law, the peak wavelength of blackbody radiation is inversely proportional to the temperature. As the temperature increases, the peak wavelength shifts to shorter (higher frequency) values.

B. The statement that "it produces the continuous spectrum curve with one peak" is also correct. The spectrum of blackbody radiation follows a continuous curve, known as the Planck curve, which shows the distribution of energy across different wavelengths or frequencies.

D. The statement that "the peak position of the spectrum of the blackbody radiation gives the information of the temperature of the blackbody" is also correct. This is known as the Stefan-Boltzmann law, which states that the total radiant energy emitted by a blackbody is proportional to the fourth power of its absolute temperature. By analyzing the peak wavelength or frequency of the spectrum, one can determine the temperature of the blackbody.

Therefore, the incorrect statement is C, as the lower the temperature of a blackbody, the lower the peak frequency in the spectrum. Hence option c) is the answer.

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AB

005 (part 2 of 2) 10. 0 points

Denote the speeds of block at point A and A'

(the same point for different two cases) to be

v and v, respectively.

What is the ratio of the speeds ?

VA

1

UA

UM

1.

UN

UA

2. 1

U

3. A 3

Answers

Answer: Inelastic: Elastic= 1:2

Explanation:

carlos uses a rope to pull his car 30 m to a parking lot because it ran out of gas

Answers

carlos used a rope to pull his car 30m to a parking lot because it ran out of gas.

cuales son las características de un generador eléctrico? ​

Answers

Answer:

Los generadores eléctricos funcionan según el principio de inducción electromagnética. Una bobina conductora (una bobina de cobre enrollada firmemente sobre un núcleo de metal) se hace girar rápidamente entre los polos de un imán tipo herradura. La bobina conductora junto con su núcleo se conoce como armadura.

which option is an example of chemical energy being transformed into thermal energy?

A. a furnace burning coal

B. lightning striking a signal tower

C. a woman rubbing her hands together for warmth

D. a plant storing energy from the sun in its leaves.

Answers

C. A woman rubbing her hands together for warmth

Answer:

it's a.... a furnace burning coal

Compare two sound waves, a and b. the frequency of wave a is one third that of wave b. how does the period of wave a compare with the period of wave b?

Answers

If the frequency of wave 'a' is one-third of that of wave 'b', then the time period of wave a will be three times as compared to the time period of wave 'b'

The frequency of a wave is inversely proportional to its time period, and it is defined as the number of oscillations per second.

which means F ∝ 1/T

If we remove the proportionality we will need to add a constant.

which makes the relation F = k/T

Time period is defined as the total time taken by a wave to complete one oscillation.

Now as per the data we have,

let the frequency of wave b be 'F', and the time period of b be 'T'

\(F_{a}\) = F/3 and \(T_{a}\) = T/3

Arranging the data into the formula we get

\(\frac{F_{a}}{F_{b}} = \frac{T_{b}}{T_{a}}\)

Which gives us \(T_{b}\) = 3\(T_{a}\)

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Two possible units of magnetic field are named after famous western scientists, choose two units of magnetic field from the list below. Select one or more: Weber Amp Tesla Lorentz Gauss Volt

Answers

Two units of magnetic field named after famous Western scientists are Weber and Gauss.

In electromagnetism, the magnetic field is a vector field that represents the magnetic effects of electric charges in motion. The magnetic field is defined as a field in which an electric charge will experience a magnetic force. It is produced by electric charges and currents. A magnetic field is created by a magnet or a moving electric charge or other magnetic fields.

The strength of a magnetic field is determined by the number of magnetic field lines or magnetic fluxes that pass through a surface placed perpendicular to the direction of magnetic field lines. It is calculated in the unit of Tesla (T). In addition to Tesla, there are two other units of magnetic field named after famous Western scientists: Gauss and Weber. A magnetic field with a strength of one gauss is equivalent to one ten-thousandth (0.0001) of a Tesla.

Gauss is a unit of magnetic flux density and is named after the famous German mathematician Carl Friedrich Gauss. Weber is named after Wilhelm Eduard Weber, and it is a unit of magnetic flux. The Weber is equivalent to the magnetic flux that crosses one square meter of surface area at right angles to a magnetic field of one tesla.

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Accuracy of physical balance is dash​

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Answer:

the answer for this is my.

If a light signal and a radio signal were transmitted simultaneously from a nearby star, the first signal to reach the Earth would be

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The radio signal would reach Earth before the light signal if both signals were transmitted simultaneously from a nearby star. When a signal is transmitted, it travels at the speed of light through the medium it propagates in.

In the vacuum of space, both light and radio waves travel at the same speed, which is approximately 299,792,458 meters per second (or about 186,282 miles per second). Therefore, the speed of light and radio signals are identical.

If a light signal and a radio signal were transmitted simultaneously from a nearby star, they would both travel toward Earth at the same speed. However, the distance between stars and Earth is vast, so even though the signals travel at the same speed, the radio signal would reach Earth before the light signal.

This is because light travels in a straight line, while radio waves can be influenced by various factors, such as interstellar dust, gas, and other celestial objects. These factors can cause radio waves to scatter or be absorbed, slowing down their journey through space. On the other hand, light, being a higher-frequency electromagnetic wave, is less affected by such interstellar objects and can travel relatively unimpeded.

Thus, due to the potential obstacles that radio waves may encounter while traveling through space, the radio signal would arrive at Earth before the light signal if both were transmitted simultaneously from a nearby star.

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Mr. Mangan is in freefall on Planet Y. His velocity increases from rest to 30 m/s in 1.2 s. If his mass is 86 kg, what is his weight on Planet Y? What is the gravitational field strength on Planet Y?

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Explanation:

First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e

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