A proton with mass 1.7e-27 kg is moving with a speed of 2.8e8 m/s. a) What is the total energy of this proton? b) What is the kinetic energy of this proton?
Answers
The kinetic energy of the proton is 6.834 × 10^-11 J. Therefore, the total energy of the proton is 6.834 × 10^-11 J and the kinetic energy of the proton is also 6.834 × 10^-11 J.
Given, Mass of proton, m = 1.7 × 10^-27 kg Speed of proton, v = 2.8 × 10^8 m/s . We know that the energy of a body is given by the formula E = (1/2)mv² .
Here, the total energy of proton (E) can be given as E = (1/2) × m × v²Let's substitute the given values. E = (1/2) × m × v²E = (1/2) × 1.7 × 10^-27 kg × (2.8 × 10^8 m/s)²E = 6.834 × 10^-11 J .
The total energy of proton is 6.834 × 10^-11 J Now, let's find the kinetic energy of the proton. Kinetic energy of the proton is given by the formula KE = (1/2)mv².
Let's substitute the given values and get the answer.KE = (1/2) × m × v²KE = (1/2) × 1.7 × 10^-27 kg × (2.8 × 10^8 m/s)²KE = 6.834 × 10^-11 J . The kinetic energy of the proton is 6.834 × 10^-11 J. Therefore, the total energy of the proton is 6.834 × 10^-11 J and the kinetic energy of the proton is also 6.834 × 10^-11 J.
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Related Questions
9.) Why would a pendulum swing faster or slower on different planets?
Answers
p3. a double-convex lens is to be made of glass with an index of refraction of 1.5. one surface is to have twice the radius of curvature of the other and the focal length is to be 60 mm. what is the (a) smaller and (b) larger radius?
Answers
The magnitude of smaller and larger radius is 45mm and 90mm respectively.
Using lens makers formula:
1/f = (n-1) (1/ \(r_{1}\) - 1/ \(r_{2}\))
where n is the index of refraction, \(r_{1}\) and f is the focal length and the curvature's radius of the first surface the light touches, and \(r_{2}\) is the second's radius of curvature. The radius of one surface is two times that of the other, such that one is concave to the incoming light and the other is convex.
Plugging in the values we get:
1/f = (n-1) (1/ \(r_{1}\) + 1/ \(2r_{1}\)) = 3(n-1) / 2\(r_{1\)
(a) For magnitude of smaller radius:
3(n-1)f / 2 = 3(1.5-1)(60) / 2 = 45mm
(b) For larger radius:
\(r_{2} = 2r_{1}\) = 90mm
Therefore, the magnitude of smaller and larger radius is 45mm and 90mm respectively.
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A 0.10-kilogram piece of modeling clay is tossed at a motionless 0.10-kilogram block of wood and sticks. The block slides across a frictionless table at 15 m/s.
a. At what speed was the clay tossed?
b. The clay is replaced with a “bouncy” ball tossed with the same speed. The bouncy ball rebounds from
the wooden block at a speed of 10 m/s. What effect does this have on the wooden block? Why?
Answers
The clay was tossed at a speed of 15 m/s. The system's overall momentum is still preserved, but its total kinetic energy is not.
What does conservation of momentum?In an isolated system, when two objects contact, the total momentum before and after the collision is equal, according to the law of conservation of momentum. This is because the momentum that is lost by one object and acquired by another is equivalent.
a. we can use the conservation of momentum equation:
m1v1 + m2v2 = (m1 + m2)v
m1 and v1 are the mass and starting velocity of the clay, m2 and v2 are the mass and initial velocity of the wooden block (which is immobile), respectively.
Substitute in the given values,
(0.10 kg) v1 + (0.10 kg) (0 m/s) = (0.10 kg + 0.10 kg) (15 m/s)
Solving for v1,
v1 = 15 m/s
b. The wooden block experiences force in the opposite direction of the motion as the bouncy ball bounces off of it. The block finally slows down and stops as a result of this. The wooden block is affected by the bouncing ball in such a way that it receives some of the ball's kinetic energy and moves in the opposite direction of the ball. The wooden block slows down and comes to a stop, while the ball continues to move because it bounces back and retains some of its kinetic energy.
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Freud was an influential and controversial psychologist who believed that psychology should study the unconscious mind. Describe
the two books Freud published in the early 1900s. (Site 2)
Answers
Answer:
The Interpretation of Dreams": Freud noticed that dreams played an important role in his analysis of neurotic and "hysterical" patients. When he asked his patients to talk about whatever came into their minds, they often referred to their dreams, which would set off other associations and often illuminate other important connections in their past experience. It took Freud about two years to write the book, finishing it in September 1897.
A velocity vs. time graph for an object is shown. A graph titled Velocity versus Time shows time in seconds on the x axis, numbered 0 to 5, velocity in meters per second on the y axis, numbered 0 to 5. A line starts at the origin and ends at (5, 5). Which best describes the acceleration of the object? constant and positive constant and negative changing and positive changing and negative
Answers
Answer:
Constant and positive constant
Explanation:
The object move with the same velocity at the same interval
Justify that animals and plants can survive without surface tension
Answers
Answer:
oxygen and carbon dioxide
Explanation:
are soluble in water animal and plants can utilize these dissolved gases for resporation and photosynthesis and hence can survived in water
A spring stores 12 J when it is stretched by 16 cm. Calculate the spring constant.
Answers
\(\\ \rm\rightarrowtail W=Fx\)
\(\\ \rm\rightarrowtail 12=1.6F\)
\(\\ \rm\rightarrowtail F=7.5N\)
Now
\(\\ \rm\rightarrowtail F=-Kx\)
\(\\ \rm\rightarrowtail 7.5=-1.6k\)
\(\\ \rm\rightarrowtail k=-4.68N/m\)
How do you calculate the average power, current, potential difference of an AC generator
Answers
How much work must be done on a particle with a mass of m to accelerate it from rest to a speed of 0.085 c?
Answers
work done must be done on a particle with a mass of m to accelerate it from rest to a speed of 0.085 c is 0.68m/s2
Work-done is described as the product of the magnitude of the displacement (d) and the component of the force acting in the displacement direction.
The Work-done W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea. The work is W = fd cos if the force is applied at an angle of to the displacement.
The product of an object's displacement and the component of the applied force that is directed in the direction of the object's displacement is known as the Work-done by a force.
There are several instances of Work-done in our daily lives. For instance, a parent wheeling a grocery cart while his horse pulls a plow through a field.
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A student investigates the motion of a ball. They throw the ball downwards with a velocity of 1.5ms-1. If the ball accelerates at 9.8ms-2 and hits the ground 2.61s later, what was the final velocity of the ball?
Answers
The final velocity of the ball, given that it was thrown downwards with a velocity of 1.5 m/s is 27.078 m/s
How do I determine the final velocity?First, we shall list out the various parameters given from the question. This is given below:
Initial velocity (u) = 1.5 m/sAcceleration (a) = 9.8 m/s²Time (t) = 2.61 secondsFinal velocity (v) =?The final velocity of the ball can be obtained by using the following equation of motion:
v = u + at
Inputting the values, we have:
v = 1.5 + (9.8 × 2.61)
Clear bracket
v = 1.5 + 25.578
v = 27.078 m/s
Thus, from above calculation, it is evident that the final velocity of the ball is 27.078 m/s
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Ya'll I been thinking...
is cereal really just a type of soup?
Answers
Answer:
Your a genius!
Explanation:
To measure the depth of the ocean, a ship sends a short pulse of sound downwards, which is reflected from the ocean floor and arrives back at the ship 2 seconds after it was sent. If the bulk modulus of the sea water is 0.21 x 1010 N/m2 and the density of sea water is 1024 kg/m3, what is the speed of sound in the sea water and what is the depth of the ocean at that location.
Answers
How fast sound travels through water at sea level and how deep the ocean is 1.432 x 10³m.
Given
Bulk modulus ( B ) = 0.21 x 10¹⁰ N/ m²
density of sea le ) = 1024 kg / m³
Speed of sound In sea water ( v ) = √B/е
V =√0. 21 x 10¹⁰/1024
V = 1-.432 x 10³ m/s
The Speed of sound has to travel at the bottom of sea and get reflected back to ship itself the distance travel by Sound is 2x
So
(t = 2 see )
2x = vt
2x = 1 . 432 x 10³ x 2
x = 1.432 x 10³m
By observing the velocity of this compressed area as it passes through the medium, we can determine the speed of sound. The sound wave travels at a speed of approximately 343 meters per second, or 767 miles per hour, in dry air at 20 degrees Celsius.
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the science club wants to create a habitat area for monarch butterflies on a vacant hillside across from the athletic field. the students are planning to use a large slingshot to launch seed bombs packed with milkweed seeds horizontally over the fence into an approved site within a range of 10-20 m away. on the field, the students use a radar gun to measure the initial velocity of the seed packets at 12 m/s. if the students stand on a platform so that the slingshot is 2.9 m off the ground, will the seed bombs reach the approved site?(1 point)
Answers
Based on the information provided, let's calculate if the seed bombs will reach the approved site. The initial velocity of the seed packets is 12 m/s and the range of the approved site is between 10-20 m away.
To determine the time it takes for the seed bombs to reach the approved site, we can use the formula:
Time = Distance / Velocity
Let's calculate the time it takes for the seed bombs to reach the approved site when launched at the maximum range of 20 m:
Time = 20 m / 12 m/s = 1.67 seconds
Now, let's calculate the maximum height reached by the seed bombs when launched at a 2.9 m height:
Maximum height = (Initial velocity^2) / (2 * Acceleration due to gravity)
Acceleration due to gravity is approximately 9.8 m/s^2.
Maximum height = (12 m/s)^2 / (2 * 9.8 m/s^2) = 7.35 m
Since the seed bombs reach a maximum height of 7.35 m and the approved site is 2.9 m off the ground, the seed bombs will reach a total height of 10.25 m. Therefore, the seed bombs will clear the fence and reach the approved site, which is within a range of 10-20 m away.
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A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?
Answers
Answer:
\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)
Given:
Initial velocity (u) = 25 m/s
Final velocity (v) = 0 m/s (Rest)
Time taken (t) = 5 seconds
To Find:
Distance travelled by car (s)
Explanation:
From equation of motion of object moving with uniform acceleration in straight line we have:
\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)
By substituting value of v, u & t in the equation we get:
\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)
\( \therefore\)
Distance travelled by car (s) = 62.5 m
The distance car travel during that time is 62.5 meter.
What is acceleration?
Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Initial velocity (u) = 25 m/s
As the car becomes rest, final velocity (v) = 0 m/s (Rest)
Time taken (t) = 5 seconds.
The deceleration of the car: a = (initial speed - final speed)/time interval
= ( 25 m/s - 0 m/s)/5 second
= 5 m/s²
The distance car travel during that time = ut - at²/2
= 25 × 5.0 meter - (5×5²/2) meter
= 62.5 meter.
Hence, the distance car travel during that time is 62.5 meter.
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What is the minimum runway length that will serve? hint: you can solve this problem using ratios without having any additional information. express your answer in miles.
Answers
There are many factors that determine if an aircraft can operate from a given airport. Of course the availability of certain services, such as fuel, access to air stairs and maintenance are all necessary. But before considering anything else, one must determine if the plane can physically land at an airport, and equally as important, take off.
What is the minimum runway length that will serve?
Looking at aerial views of runways can lead some to the assumption that they are all uniform, big and appropriate for any plane to land. This couldn’t be further from the truth.
A given aircraft type has its own individual set of requirements in regards to these dimensions. The classic 150’ wide runway that can handle a wide-body plane for a large group charter flight isn’t a guarantee at every airport. Knowing the width of available runways is important for a variety of reasons including runway illusion and crosswind condition.
Runways also have different approach categories based on width, and have universal threshold markings that indicate the actual width.
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you need to process an arraylist and remove several elements in the list. which loop is most appropriate?
Answers
The for-each loop is the best choice for processing an array list and removing multiple elements from the list. This loop is designed specifically to iterate over collections such as an ArrayList.
The for-each loop makes it easier to remove elements that meet certain criteria by providing a convenient way to access each element in the list.
It is important to note, however, that the for-each loop is only intended for reading list elements and not for modifying them. It is recommended to use an iterator to remove elements from an ArrayList while iterating over it. An iterator allows you to remove elements from a collection while iterating over it.
Overall, the for-each loop is a simple and efficient way to process an array list, while the iterator provides a more flexible approach for modifying the list as needed.
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Ferryboat Docking Bumper Shock M₂ Absorber M 1979M2. A ferryboat of mass Mi= 2.0 x 105 kilograms moves toward a docking bum per of mass My thatis attached to a shock absorber. Shown below is a speed v vs. time t graph of the ferryboatfrom the time it cuts off its engines to the time it first com esto rest after colliding with the bumper. At the instant it hits the bumper, t= 0 andv= 3 meters per second. 3 m/s 2 m/s a. After colliding inelastically with the bumper, the ferryboat and bumper move together with an initial speed of 2 meters per second
Answers
Mass of the bumper =M2=1*10^5 kg
It is given that collision is inelastic and after Collision Both Boat and Bumber moves with 2m/see then, velocity from conservation of momentum.
M_{1}*v_{1} = (M_{1} + M_{2}) * v_{2}
(m_{1}*v_{1})/v - m_{1} =m 2
M_{2} =2*10^5*3/2-2*10^5 = 1*10^5 kg
According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.
Conservation of momentum states that the center of mass's mass times velocity remain constant. Conserving Angular Momentum: The system's overall angular momentum is constant. Newton's Third Law: Since all internal forces occur in pairs, there can be no net force generated within the system.
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batteries and generators create the electricity which flows in wires. group of answer choices true false
Answers
The given statement "batteries and generators create the electricity which flows in wires" is true because electricity is created by batteries and generators.
Batteries and generators are both sources of electromotive force (emf) which create a potential difference in a circuit, causing the flow of electric charges (current) through wires.
A battery is a device that converts stored chemical energy into electrical energy, while a generator is a device that converts mechanical energy into electrical energy.
In both cases, the source of the energy ultimately comes from the movement of electrons, either through a chemical reaction in the battery or through a rotating magnetic field in the generator.
Once the emf is created, the electric charges are able to flow through the wires due to the presence of a conductive material. Therefore, batteries and generators are essential components of electrical circuits that allow for the transfer of energy from one location to another.
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for a camera equipped with a 55-mm-focal-length lens, what is the object distance if the image height equals the object height? how far is the object from the image on the film?
Answers
In a a camera equipped with a 55-mm-focal-length lens, what is the object distance if the image height equals the object height.The object is effectively located at an infinite distance from the camera lens.
To determine the object distance in this scenario, where the image height equals the object height, we can use the lens formula:
1/f = 1/d_o + 1/d_i
Where:
f is the focal length of the lens,
d_o is the object distance,
and d_i is the image distance.
Given that the focal length (f) is 55 mm, and the image height (h_i) equals the object height (h_o), we can assume that the image distance (d_i) is equal to the focal length (f) due to the nature of the scenario.
Substituting the known values into the lens formula, we have:
1/55 = 1/d_o + 1/55
Simplifying the equation, we get:
1/d_o = 1/55 - 1/55
1/d_o = 0
Since the equation results in 0, it implies that the object distance (d_o) is at infinity in this scenario. The object is effectively located at an infinite distance from the camera lens.
As for the distance between the object and the image on the film, it is not possible to determine it precisely without additional information, such as the specific type of camera and the positioning of the film plane relative to the lens. However, in typical camera setups, the image on the film is formed when the object is located at the focal point of the lens or at a significant distance from the lens, resulting in a sharp image on the film plane.
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Use two ideal op amps and resistors to implement the summing function:v0 = v1 + 2v2 - 3v3 - 5v4
Answers
In this configuration, the two ideal op-amps and resistors work together to implement the specified summing function.
To implement the summing function v0 = v1 + 2v2 - 3v3 - 5v4 using two ideal op-amps and resistors, you can use a combination of a non-inverting summer and an inverting summer.
1. Connect the non-inverting inputs of both op-amps to the ground.
2. Connect the inverting inputs of both op-amps to a summing junction using resistors.
3. For the non-inverting summer (Op Amp 1), connect v1 and v2 to the summing junction using resistors R1 and R2 with the same resistance value. This will produce v1 + v2 at the output of Op-Amp 1.
4. For the inverting summer (Op Amp 2), connect v3 and v4 to the summing junction using resistors R3 and R4 with resistance values in the ratio of 3:5, respectively. This will produce -3v3 - 5v4 at the output of Op-Amp 2.
5. Finally, connect the outputs of both op-amps (Op Amp 1 and Op Amp 2) to another summing junction using equal-value resistors. This will result in the desired summing function v0 = v1 + 2v2 - 3v3 - 5v4 at the output.
In this configuration, the two ideal op-amps and resistors work together to implement the specified summing function.
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help plz anyone ?????
Answers
Answer:
Most likely, it will be harder to get strong magnets to change phase because they have more density.
Is kilometer less than, greater than, or equal to dekameter
Answers
Answer:
Less than
Explanation:
Because a dekameter has a higher vantage point than kilometer as a kilometer has a lower vantage point
Answer: a dekameter is actually 10 yrds while 1 kilometer is actually 4 to 5 miles
Explanation:
will give correct answer brainliest
5 kg m/s
8kg m/s
80 kg m/s
200 kg m/s
Answers
Answer: Here this will help you..
Explanation:
1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second
5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second
10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second
20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second
30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second
40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second
50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second
75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second
100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second
During a collision with another car, the occupants of a minivan initially travelling at 4.0 m/s come to a complete stop in 0.5 s. What was the acceleration of the occupants of the minivan?
a) 8.0 m/s2
b) –8.0 m/s2
c) 2.0 m/s2
d) –2.0 m/s2
Answers
Answer: b) - 8.0 \(m/s^{2}\)
Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:
a = \(\frac{v}{t}\)
and its SI unit is \(m/s^{2}\)
For the minivan to stop, it takes a period of 0.5s:
a = \(\frac{4.0}{0.5}\)
a = 8.0 \(m/s^{2}\)
As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).
the allowed shapes for orbits under the force of gravity are
Answers
A race car starts at rest and accelerates north at 12.27 m/s2 for 3.19 seconds. What
is the car's final velocity?
Answers
Using that formula;
Vf = 0 + 12.27(3.19)
Vf = 39.14 m/s
Note: you started from rest, so your initial velocity is 0.
1. What net force is required to accelerate a car at a rate of 2 m/s2 if the car has a mass of 3,000 kg?
F=______
m=______
a= ______
Answers
Answer:
Net force required to accelerate the car is 6000 N
Explanation:
Force is calculated by the equation, F = Mass × Acceleration
This is based on Newton's Second Law of Motion which states that the force acting on an object is its mass times the acceleration of the object.
Here, mass = 3000 kg and acceleration = 2 m/s²
⇒ Force = Mass × Acceleration
= 3000 × 2 = 6000 N
⇒ F = 6000 N
⇒ M = 3000 kg
⇒ a = 2 m/s²
Run some of your own experiments to see if you can detect a difference in refracted angles at other incident angles. Why did I choose 80 degrees
Answers
The reason why you chose 80 degrees could not be inferred from the given information since the question only asks for the steps to run an experiment to detect a difference in refracted angles at other incident angles. Therefore, I will provide the steps to run this experiment below:
Step-by-step explanation: The steps to run an experiment to detect a difference in refracted angles at other incident angles are as follows: Materials Needed: Water Shallow dish Protractor Ruler Pencil or pen Instructions: Pour water into the shallow dish until it is half full. Place the protractor flat against the side of the dish. Place a pencil or pen in the water at a 40-degree angle so that it intersects the protractor at the zero-degree line. The angle between the water's surface and the pencil or pen is called the incident angle. Record the angle of refraction, which is the angle between the water's surface and the pencil or pen inside the water. Repeat this process at different angles such as 30, 50, and 60 degrees to see if you can detect a difference in refracted angles at other incident angles.
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Choose forces from the box to complete these sentences.
Answers
Answer:Upthrust, Weight
Explanation:
The upward force is called Upthrust.
The downward force is called weight.
Whenever a body is submerged fully or partially in the liquid, it experiences an upward force that is equal to the weight of water replaced.
What are the effects of gravity on earth?
Answers
Answer:
Without it, we could not survive on Earth. Earth orbits the sun due to the gravity of the sun, which maintains us at a convenient distance from it to enjoy the sun's warmth and light. It keeps the air we need to breathe and our atmosphere in place. Our planet is held together by gravity.