A proton in an accelerator attains a speed of 0.845 . what is the magnitude of the momentum of the proton?

An Atwood's machine is an apparatus that consists of two weights suspended over a pulley. It is a simple device used to study the acceleration and tension of a system and has several real-world applications. In general, it is used to measure the effect of gravity on the motion of objects. Some common examples of its use include studying the speed of falling objects and the motion of planets around the sun. It is also used to measure the gravitational pull of the earth and other planets. Atwood's machine is commonly used in physics classes to study the principles of mechanical forces and the laws of motion. It is a simple yet effective way to teach the concept of acceleration and force. It is used to calculate the acceleration of the weights, the force applied to the system, and the tension in the string.

There are several reasons that could account for the percent error calculated above. One reason is that the experiment may have been affected by friction. Friction can cause the weights to move more slowly, which would lead to a lower acceleration. Another reason could be that the weights were not exactly the same mass. This would cause the system to be imbalanced, which would affect the acceleration and tension in the string. Lastly, human error could have also contributed to the percent error. This could include errors in measurement or incorrect calculations.

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The fractional uncertainty in each distance measurement is calculated by dividing the radius of the circle (i, i0, or t) by the measured distance while the percent uncertainties are larger than fractional uncertainties.

When the distances were measured very accurately, the fractional uncertainty is small and the percent differences are large as the measurements are not necessarily close to the true values.

Given the radii of circles = i, i0, t

It is said that there was an estimate of error in the provided experimental values for each of the horizontal ranges.

For example, if the radius of circle i is 10 cm and the distance measurement is 40 cm, then the fractional uncertainty would be (10/40) = 0.25

The percent differences between the initial and final values of the kinetic energy, between the initial and final values of the x-component of the total momentum, and between the final y-components of the two balls are much larger than the fractional uncertainties in the horizontal ranges. Since, the fractional uncertainties are related to the precision of the measurements they are larger while the percent differences are related to the accuracy of the measurements.

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The moment of inertia of the system  for the three situations are 0.026667 kg m2,0.04 kg m2,0.013333 kg .

Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods

a) The moment of inertia of the system about an axis

through the center of the square,

perpendicular to its plane (an axis through point O) is equal to

4 x 0.200 kg x (0.400 m)2/12

= 0.026667 kg m2.

b) The moment of inertia of the system about an axis

bisecting two opposite sides of the square (an axis along the line AB) is equal to

4 x 0.200 kg x (0.400 m)2/8

= 0.04 kg m2.

c) The moment of inertia of the system about an axis

that passes through the centers of the upper left and lower right spheres and

through point O is equal to

2 x 0.200 kg x (0.400 m)2/12

= 0.013333 kg m2.

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Answer:

The angular speed will be 85.13 rad/sec

Explanation:

Answer:

Explanation:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled.

Answer:

Yes

Explanation:

Astrology is a pseudoscience that claims to divine information about human affairs and terrestrial events by studying the movements and relative positions of celestial objects.

Answer:

Astrology has not demonstrated its effectiveness in controlled studies and has no scientific validity, and is thus regarded as pseudoscience.

Explanation:

Answer:

11m/s^2

Explanation:

Acceleration can be calculated by diving speed by time. Since we know speed and time, acceleration can be calculated.

55/5 = 11m/s^2

Answer:

Explanation:

A capacitor is an electronic component that stores and releases electrical energy. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied across the plates, charge accumulates on them, creating an electric field between the plates.

The capacitance of a capacitor is a measure of its ability to store charge. It is typically represented by the symbol 'C' and is measured in farads (F). In your case, you mentioned a 55-μF (microfarad) capacitor, indicating its capacitance value.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The rate at which the capacitor charges and discharges depends on the capacitance and the resistance in the circuit

Since there is no figure provided in the text, I am unable to reference it for the specific details of the voltage waveform. However, I can explain the general behavior of a capacitor when a voltage waveform is applied.

When a voltage waveform is applied across a capacitor, the capacitor charges and discharges in response to the changes in voltage. The behavior of the capacitor is determined by its capacitance, which is given as 55 μF in this case.

As the voltage waveform varies, the capacitor stores and releases electrical charge. During the rising portion of the waveform, the capacitor charges and accumulates energy. During the falling portion, the capacitor discharges and releases the stored energy.

The exact behavior and characteristics of the voltage waveform and the charging/discharging process depend on the specific shape and frequency of the waveform. Without the specific details of the voltage waveform provided in the figure, it is challenging to provide a more detailed analysis.

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Answer:

when it is not moving/at the bottom

Explanation:

because if It had alot of kinetic energy it would be the most

Answer:

It is a low pressure system.

Explanation:

The wind is blown into these low pressure areas due to it being thin. The air then rises causing condensation.

The geographic north pole is not shown by a magnetic compass. The earth's magnetic poles, which are distinct from the planet's geographic poles, are shown by a magnetic compass.

A magnet will always point northward or southward. A magnet's north pole will always point in the direction of the Earth's geographic north (which is also its magnetic south pole).

Since opposite poles pull together, the earth's magnetic north pole is actually located on the Southern Hemisphere, making it operate like a physical magnet.

The direction of magnetic field lines is set up so that they come out of the north pole of the magnet and go in through the south pole.

Therefore, the magnetic pole that is closest to the geographic north pole of the earth is the south magnetic pole. The law of attraction applies to magnets.

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Answer:

a.

Explanation:

cuz whenever the ball was traveling up the staircase it was building up energy to use (potential energy) unlike b.

Answer:

the Answer is A dhdhjdddjfhfhxhhddhhsshhss

Explanation:

because it travels

Answer:

Reflected

Explanation:

During the process of reflection whatever that is sent forth e.g light comes back (reflects)

Answer:

transmitted

Explanation:

took quiz

To determine the force that needs to be applied to the smaller piston, we can use Pascal's law, which states that the pressure in a fluid is transmitted equally in all directions.

Given:

Force on the larger piston (F1) = 13,000 N

Diameter of the larger piston (D1) = 25 cm

Diameter of the smaller piston (D2) = 5.0 cm

The ratio of the areas of the pistons is equal to the ratio of the forces applied. The formula to calculate the force on the smaller piston (F2) is:

F2 = (A2 / A1) * F1

where A1 is the area of the larger piston and A2 is the area of the smaller piston.

To calculate the area of a piston, we use the formula:

Area = π * (radius)²

First, let's calculate the areas of the pistons:

A1 = π * (D1/2)²

A2 = π * (D2/2)²

Now, we can substitute the values and calculate F2:

F2 = (A2 / A1) * F1

Finally, we can find the correct answer from the given options by calculating F2.

Let's go through the calculations:

A1 = π * (25 cm / 2)² = 4.91 cm²

A2 = π * (5.0 cm / 2)² = 0.79 cm²

F2 = (0.79 cm² / 4.91 cm²) * 13,000 N

F2 ≈ 209.58 N

The closest option to this value is 260 N. Therefore, the force that needs to be applied to the 5.0 cm diameter piston to lift the 13,000 N vehicle is approximately 260 N.

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Answer:

Resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

Explanation:

When the two resistors are in series, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B.

Given that V₁ + V₂ = 6.0 V and V₁ = 4.0 V,

V₂ = 6.0 V - V₁ = 6.0 V - 4.0 V = 2.0 V

Also, let the current in series be I.

So, V₁ = IR₁ and V₂ = IR₂

I = V₁/R₁ and I = V₂/R₂

equating both expressions, we have

V₁/R₁ = V₂/R₂

4.0 V/R₁ = 2.0 V/R₂

dividing through by 2.0 V, we have

2/R₁ = 1/R₂

taking the reciprocal, we have

R₂ = R₁/2

R₁ = 2R₂

From the parallel connection, let V₁ = voltage in resistor A and R₁ = resistance of resistor A and V₂ = voltage in resistor B and R₂ = resistance of resistor B. Since it is parallel, V₁ = V₂ = V = 6.0 V

Also, V₂ = I₂R₂ where I₂ = current in resistor B = 2.0 A and R₂ = resistance of resistor B

So, R₂ = V₂/I₂

= 6.0 V/2.0 A

= 3.0 Ω

R₁ = 2R₂

= 2(3.0 Ω)

= 6.0 Ω

So, resistance of resistor A = 6.0 Ω and resistance of resistor B = 3.0 Ω

The resistance of A is 6Ω while for B is 3Ω.

Potential difference is the amount of work done in moving a unit charge from one point to another.

When the two resistors are connected in parallel across the 6.0 V battery, the current in B is found to be 2.0 A, hence:

2 * Rb = 6 V

Rb = 3Ω

For the series connection:

I * 3 = (6 - 4)

I = 2/3 A

Hence:

(2/3) * Ra = 4

Ra = 6Ω

The resistance of A is 6Ω while for B is 3Ω.

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Answer:

a = 1.49m/s²

Explanation:

Find the diagram attached  

According to Newton's second law of motion

\sum Fx = ma

Fm - Ff = ma

Fm is the moving force

Ff is the frictional force

Fm = Wsin theta

Ff = μR = μWcos theta

Wsin theta - μWcos theta = ma

W is the weight = 50.1 * 9.8 = 490.98N

theta is the angle of inclination = 27.2°

μ is the coefficient of friction = 0.343

m is the mass = 50.1kg

a is the acceleration  

Substitute into the formula as shown;

Wsin theta - μWcos theta = ma

490.98sin27.2° - 0.343(490.98)cos 27.2° = 50.1a

224.423 - 149.78 = 50.1a

74.64 = 50.1a

a = 74.64/50.1

a = 1.49m/s²

Hence the acceleration of the block is a = 1.49m/s²

Answer:

A good hand soap effectively kills germs without causing irritation or drying out your skin. For a cleanse that's both gentle on your skin and tough on germs, we looked for soaps made with moisturizing ingredients like olive oil, aloe vera, and glycerin.

Explanation:

Answer:

100°C

Explanation:

The heat gained by the ice equals the heat lost by the steam, so the total heat transfer equals 0.

Heat lost by the steam as it cools to 100°C:

q = mCΔT

q = (3 kg) (2.00 kJ/kg/K) (100°C − 120°C)

q = -120 kJ

Total heat so far is negative.

Heat lost by the steam as it condenses:

q = -mL

q = -(3 kg) (2256 kJ/kg)

q = -6768 kJ

Heat absorbed by the ice as it warms to 0°C:

q = mCΔT

q = (6 kg) (2.11 kJ/kg/K) (0°C − (-40°C))

q = 506.4 kJ

Heat absorbed by the ice as it melts:

q = mL

q = (6 kg) (335 kJ/kg)

q = 2010 kJ

Heat absorbed by the water as it warms to 100°C:

q = mCΔT

q = (6 kg) (4.18 kJ/kg/K) (100°C − 0°C)

q = 2508 kJ

The total heat absorbed by the ice by heating it to 100°C is 5024.4 kJ.

If the steam is fully condensed, it loses a total of -6888 kJ.

Therefore, the steam does not fully condense.  The equilibrium temperature is therefore 100°C

The tension be to produce the correct frequency is 306N

The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.

f= 1/2L\(\sqrt\) μT

so

fα\(\sqrt\) T

∴ f 1/f 2 = \(\sqrt\)T 1/T 2

In our example, f 1 = 460 Hz, and T 1 =?

​and for f = 510 Hz, T 2 = 255.

∴

510/460  = \(\sqrt\)T 1/255.

∴T 1 =( 510/510 )=306N.

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Answer:

silver and copper

Explanation:

Answer:

The new force becomes 3 times of the initial force.

Explanation:

Let q₁ and q₂ are two charged particles. The force between them is given by :

\(F=\dfrac{kq_1q_2}{r^2}\ ......(1)\)

If \(q_1'=\dfrac{q_1}{4}\)

and

\(q_2'=3q_2\)

Also, r' = r/2

New force,

\(F'=\dfrac{kq_1'q_2'}{r'^2}\)

Putting all the above values,

\(F'=\dfrac{k\dfrac{q_1}{4}3q_2}{(r/2)^2}\\\\F'=3\times \dfrac{kq_1q_2}{r^2}\\\\F'=3F\)

So, the new force becomes 3 times of the initial force.

Answer:

 v₂ =\(( \frac{r_1}{r_2})^2 \ v_1\)

Explanation:

This phenomenon is explained by the continuity equation in fluids

           v₁A₁ = v₂A₂

where the subscript 1 is for the input narrow part and the subscript 2 for the wide part

         v₂ = \(\frac{A_1}{A_2} v_1\)

consider the cross section at each point

           A₁ = π r₁²

           A₂ = π r₂²

we substitute

          v₂ =\(( \frac{r_1}{r_2})^2 \ v_1\)

therefore the exit velocity is less than the entrance velocity of the fluid.

We can also analyze the situation using Bernoulli's equation

         P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y²

       if we assume a horizontal system y₁ = y₂

         P₁-P₂ = ρ g (v₂² - v₁²)

Answer:

the distance is 0.6 km

Explanation:

The computation of the distance is shown below:

As we know that

Distance = Speed × time

where

Speed = 72 km/h

And, the time is 30 seconds

So, the distance is

= 72 × 30

= 0.6 km

Hence, the distance is 0.6 km

Answer:

answer is 2 option because more force is applied

Definition: When an object moves in a circular path with uniform speed, the motion is called uniform circular motion.

ac=rv2=ω2r

It depends on the context and details of the situation involving the rods AD and BE. The relationship between the forces applied to the two rods could be different depending on various factors such as the materials, dimensions, and boundary conditions of the rods.

However, in general, the relationship between the forces can be determined by applying the principle of equilibrium, which states that the sum of forces acting on an object must be zero for it to be in a state of static equilibrium. If the two rods are connected by a point, then the forces applied to them must be equal and opposite so that their net sum is zero. In that case, the equation that would show the relationship between the force applied to rod AD and the force applied to rod BE is:

Fad = -Fbe

where Fad is the force applied to rod AD and Fbe is the force applied to rod BE. This equation ensures the principle of equilibrium is satisfied.

However, if the two rods are not connected at a point, then the relationship between the forces would depend on the details of the system and the forces being applied.

Answer:

Angle of diffraction for second order maxima is θ = 18.941°

Explanation:

From the question it is given that

wavelength of incident light = λ = 541 nm = 541 x \(10^-^9 m\)

order of maxima = n =2

diffraction grating has 600 lines per mm

⇒ distance between two slit is \(\frac{1mm}{600}\) = 1.66 x \(10^-^6\) m

using the relation of Braggs diffraction formula i.e.,

2dsinθ = nλ ..................................(1)

where, d = distance between two lines of grating

θ is the angle of diffraction

n= order of maxima

λ is the intensity of incident photon

on substituting the respected values in relation (1) we get,

2 x 1.66 x \(10^-^6\)m sinθ = 2 x 541 x \(10^-^9 m\)

⇒ sinθ = 0.3246

⇒ θ = \(sin^-^1(0.3246)\) = 18.941 °