The approximate shelf-life of this product, when stored in a refrigerator (5 °C) is 21.3 hours.
What is shelf-life product?
Shelf life is defined as the length of time a product may be stored without becoming unsuitable for use or consumption.
Using a Q value of 3, the approximate shelf-life of this product is calculated as follows;
\(t_{90} (T_2) = \frac{t_{90}(T_1)}{Q_{10}^{(\frac{\Delta T}{10})} } \\\\t_{90} (T_2) = \frac{8}{3^{(\frac{25-5}{10})}} \\\\t_{90} (T_2) = \frac{8}{3^2} = 0.88 \ day = 21.3 \ hours\)
Thus, the approximate shelf-life of this product, when stored in a refrigerator (5 °C) is 21.3 hours.
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Brainliest if correct Question 6 of 10
According to the law of conservation of energy, which statement must be
true?
A. There is only one form of energy.
B. Energy that is transformed is neither destroyed nor created. C. The total energy in a system can only increase over time.
D. Energy can change only from nuclear to chemical.
SUBMIT
Answer:
Energy that is transformed is neither destroyed nor created.
Explanation:
Answer:
B: Energy that is transformed is neither destroyed nor created
Explanation:
The density of a solid or liquid material divided by the density of water is called
Answer:
I believe the answer is specific gravity
Explanation:Hope this helps :)
what is the displacement of a car with an acceleration of 4.00 m/s2 as it increases its speed from 10.0 m/s to 30.0 m/s ?
Answer:
100 m
Explanation:
We can use equation of motion to solve this
\( {v}^{2} = u {}^{2} + 2as \\ 30 {}^{2} = {10}^{2} + 2(4.0)s \\ s = 100m\)
You and your buddy are scuba diving and notice that air bubbles triple in volume as they rise to the surface from where you are in the ocean. Ignoring any temperature changes, how far below the surface of the water (in m) are you when these bubbles are released? The ocean has a density of 1,031 kg/m3.
ANSWER
\(h=20.06\text{ m}\)EXPLANATION
Since the temperature is constant, applying the ideal gas equation, we have that the product of volume and pressure remains constant:
\(P_1V_1=P_2V_2\)When they are submerged in water, their pressure is:
\(P_1=P_{atm}+h\rho g\)where Patm = atmospheric pressure
h = depth below the surface
ρ = density
g = acceleration due to gravity
At the surface of the water:
\(P_2=P_{atm}\)Applying the ideal gas equation, we have that:
\(P_1V_1=P_2V_2\)But we have that V2 = 3V1. Substituting that into the equation:
\(\begin{gathered} P_1V_1=P_2(3V_1) \\ \\ \Rightarrow P_1=3P_2 \\ \\ P_{atm}+h\rho g=3P_{atm} \\ \\ h\rho g=3P_{atm}-P_{atm}=2P_{atm} \\ \\ h=\frac{2P_{atm}}{\rho g} \end{gathered}\)Substitute the given values into the equation and solve for h:
\(\begin{gathered} h=\frac{2*101325}{1031*9.8} \\ \\ h=20.06\text{ m} \end{gathered}\)That is the height when the bubbles are released.
The mass and weight of box is 25 Kg and 245 N respectively when on Earth. What is the value of mass and weight of the box when it is brought to the moon?
Answer:
25 (kg) and 40.5 (N).
Explanation:
1) the value of 'g' on the Earth is ~9.81 (N/kg), the value of 'g' on the Moon is ~1.62 (N/kg).
It means, the mass is not depended on the value of 'g', but the weight is depended on it.
2) the mass on the Moon is the same, 25 kg.
the weight is 25*1.62=40.5 N
Think about times in your life when you have used your refusal, negotiation, and conflict resolution skills
How often do very active sunspot and solar flare cycles take place?
Answer:
Every 11 years The solar cycle is the cycle that the Sun's magnetic field goes through approximately every 11 years.
Explanation:
Our Sun is a Large ball of electrically-charged hot gas. This charged gas moves, generating a powerful magnetic field. The Sun's magnetic field goes through a cycle, called the solar cycle.
Every 11 years or so, the Sun's magnetic field completely flips. This means that the Sun's north and south poles switch places. Then it takes about another 11 years for the Sun’s north and south poles to flip back again.
The solar cycle affects activity on the surface of the Sun, such as sunspots which are caused by the Sun's magnetic fields. As the magnetic fields change, so does the amount of activity on the Sun's surface.
Hope this helps!
Brain-List?
Your friend, a world-class long jumper, is trapped on the roof of a burning building. His only escape route is to jump to the roof of the next building. Fortunately for him, he is in telephone contact with you, a Physics 131 student, for advice on how to proceed. He has two options. He can jump to the next building by using the long-jump technique where he jumps at 45o to the horizontal. Or, he can take his chances by staying where he is in the hopes that the fire department will rescue him. You learn from the building engineers that the next building is 10 m away horizontally and the roof is 3 m below the roof of the burning building. You also know that his best long-jump distance is 7.9 m . What do you advise him to do
Answer:
y = 7.33 m, x= 3 m, t = 1.608 s
it is still higher than the second building, which indicates that if it jumps it will be saved
Explanation:
Let's use the projectile launch ratios, let's start with the range ratio
R = v₀² sin² 2θ / g
in this case the range is R = 7.9m and the angle is 45º, let's find the initial velocity
v₀² = R g / sin² 2θ
let's calculate
v₀ = \(\sqrt{ \frac{ 7.9 \ 9.8}{ 1} }\)
v₀ = 8.80 m / s
Let's find the components of the initial velocity
v₀ₓ = v₀ cos 45 = 8.80 cos 45
\(v_{oy}\) = v₀ sin 45 = 8.80 sin 45
v₀ₓ = 6.22 m / s
v_{oy} = 6.22 m / s
To save yourself, you have to be at the same time as the other building or higher.
x = v₀ₓ t
t = x / v₀ₓ
t = 10 / 6.22
t = 1.608 s
let's see how much it has descended in this time
y =y₀ + v_{oy} t - ½ g t²
y = 10+ 6.22 1.608 - ½ 9.8 1.608²
y = 7.33 m
therefore it is still higher than the second building, which indicates that if it jumps it will be saved
Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
this is a Physical Education question
You
A baseball Is traveling with a momentum of 6.5kg m/s. If it gets stopped in 0.020s, then what is the magnitude of the force stopping it?
Given :
A baseball Is traveling with a momentum of 6.5kg m/s.
To Find :
The magnitude of the force stopping it If it gets stopped in 0.020 s.
Solution :
We know, force in terms of magnitude is given by :
\(Force = \dfrac{Momentum}{Time\ Taken}\\\\Force = \dfrac{6.5 \ kg\ m/s}{0.020\ s}\\\\Force = 325 \ kg \ m/s^2\)
Therefore, the magnitude of the force stopping it is 325 kg m/s² .
___________________ uses the heat energy from the Earth. This type of alternative energy can be installed basically anywhere in North Carolina.
A) wave energy
B) solar energy
C) nuclear energy
D) geothermal energy
Answer:
Geothermal!!
Explanation:
Geo means earth! Just like Hydro means water, and Pyro means fire :)
Answer:
The Answer is D). Geothermal energy
Explanation:
Hope this helps!!!!!
The thermal energy that causes the ice to melt is transferred from the lemonade as it cools. The loss of this thermal energy causes the temperature of the 300 g of the lemonade to fall by 19 °C. Calculate the specific heat capacity of the lemonade.
According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.
The formula for the specific heat capacity (C) = Q/ m × ΔT
Q is energy added and the value, which is 334J
m is the mass of the lemonade, which is 300g = 0.3 kg
Δ T is the change in temperature, which is 19°C =(273+19)= 292 K
So, C = 334/ 0.3 × 292
= 3.81 J/kg/k
So the specific heat capacity of the lemonade is 3.81 J/kg/k.
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1.Which among the following is measured using a Vernier Caliper?
[A] Dimensions
[B] Time
[C] Sound
[D] Temperature
Dimensions are measured using a Vernier Caliper (option A)
What is a Vernier Caliper?A device renowned for its accuracy in measuring the size of objects, the Vernier caliper functions with two jaws to hold an object steady as its scale offers readings. It can assess both external and internal measurements as well as depth with precision.
The Vernier caliper is made up of two main parts: the main scale and the vernier scale. The main scale is a graduated scale that is used to read the measurement in millimeters. The vernier scale is a smaller scale that is used to read the measurement in fractions of a millimeter.
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There are two forces on the 1.11 kg box in the overhead view of the figure but only one is shown. For F1 = 11.1 N, a = 14.0 m/s2, and θ = 31.7°, find the second force (a) in unit-vector notation and as (b) a magnitude and (c) a direction. (State the direction as a negative angle measured from the +x direction.)
Answer:
I said that setting enriches the characters. What I didn’t tell you is that it helps to form the characters. It does the same for the plot.
Explanation:
Before the 1970's, energy prices were A. relatively low B. extremely burdensome C. incredibly high D. very problematic
Answer:
C
Explanation:
correct me if I'm wrong.
Answer:
A
Explanation:
i got it right on acellus
Astone has a mass of 200 grams. When it is immersed in a measuring cylinder of water,the water rises 100 ml.What is the density of the stone
Answer:
2 g/mLExplanation:
The density of a substance can be found by using the formula
\(d = \frac{m}{v} \\ \)
m is the mass
v is the volume
From the question
m = 200g
v = 100 mL
We have
\(d = \frac{200}{100} = 2 \\ \)
We have the final answer as
2 g/mLHope this helps you
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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which of the following is an example of a physical change of matter
An example of a physical change of matter is (c) Melting ice.
Explanation: Melting ice is an example of a physical change of matter. When ice melts, it undergoes a change in state from a solid to a liquid, but its chemical composition remains the same. The water molecules in ice rearrange themselves to form liquid water, but no new substances are formed. This change can be reversed by cooling the liquid water to below its freezing point, causing it to solidify back into ice. Physical changes do not involve a change in the chemical identity of the substance, only a change in its physical properties, such as shape, size, or state.
In contrast, options a) Burning wood, b) Digesting food, and d) Rusting iron involve chemical changes. Burning wood involves a chemical reaction where wood reacts with oxygen to produce carbon dioxide, water vapor, and ash. Digesting food involves the breakdown of complex molecules into simpler ones through chemical reactions in the body. Rusting iron is a chemical reaction where iron reacts with oxygen and moisture in the air to form iron oxide.
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Note: The complete question is:
Which of the following is an example of a physical change of matter?
a) Burning wood
b) Digesting food
c) Melting ice
d) Rusting iron
A bicycle wheel with a diameter of 24 inches is rotating 3 revolutions per second. What is the linear speed in feet/sec? Use 3.14 for pi and round to the nearest tenth
ANSWER
\(18.8ft\/s\)EXPLANATION
We want to find the linear speed of the bicycle in feet per second.
First, we have to find the circumference of the bicycle wheel (in feet).
The circumference of a circle is:
\(C=\pi\cdot D\)First, convert the diameter to feet:
\(\begin{gathered} 12in=1ft \\ \Rightarrow24in=\frac{24}{12}=2ft \end{gathered}\)Hence, the circumference of the wheel is:
\(\begin{gathered} C=3.14\cdot2 \\ C=6.28ft \end{gathered}\)This implies that each revolution is an equivalent linear distance of 6.28 ft i.e 6.28 feet per revolution.
To find the linear speed, we have to find the product of the circumference and the
rotational speed. That is:
\(\begin{gathered} s=6.28\frac{ft}{rev}\cdot3\frac{rev}{\sec } \\ s=18.84ft\/s \\ s\approx18.8ft\/s \end{gathered}\)That is its linear speed.
A 7.80-g bullet moving at 540 m/s penetrates a tree trunk to a depth of 6.30 cm.
(a) Use work and energy considerations to find the average frictional force that stops the bullet. (Enter the magnitude.)
N
(b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.
s
(a) To find the average frictional force that stops the bullet, we can use the work-energy principle, which states that the work done by all forces on an object is equal to the change in its kinetic energy.
How do we know about work done ?In this case, the work done by the frictional force is equal to the change in the bullet's kinetic energy from its initial speed of 540 m/s to zero when it comes to a stop.
The initial kinetic energy of the bullet is given by (1/2)mv², where m is the mass of the bullet and v is its initial speed. Substituting the given values, we get
Ki = (1/2)(0.0078 kg)(540 m/s)²
= 1.4916 kJ
The final kinetic energy of the bullet is zero, so the work done by the frictional force is equal to -1.4916 kJ. The negative sign indicates that the work is done against the direction of motion of the bullet.
The distance over which the frictional force acts is equal to the depth to which the bullet penetrates the tree trunk, which is 6.30 cm. Therefore, the work done by the frictional force is also equal to the force times the distance, or W = Fd.
Equating the work done by the frictional force to the change in kinetic energy, we get
-Fd = Kf - Ki
where Kf is the final kinetic energy, which is zero. Solving for the frictional force F, we get
F = (Ki)/d = 1.4916 kJ / 0.063 m
= 23,651 N
Therefore, the average frictional force that stops the bullet is 23,651 N.
How do we find out the distance travelled ?(b) Assuming the frictional force is constant, we can use the equation of motion for constant acceleration to determine the time it takes for the bullet to come to a stop.
The distance traveled by the bullet before coming to a stop is equal to the depth to which it penetrates the tree trunk, which is 6.30 cm. The initial speed of the bullet is 540 m/s, and the acceleration is equal to -F/m, where F is the frictional force and m is the mass of the bullet. Substituting the given values, we get
d = (1/2)at² + vit
0.063 m = (1/2)(-23,651 N) / 0.0078 kg t² + 540 m/s t
Simplifying and solving for t, we get
t = 0.0229 s
Therefore, the time it takes for the bullet to come to a stop is 0.0229 seconds.
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A current of 2A flows for 2minutes through the wire in a motor. (1) how much charge passes through a wire this time
Answer:
240 C
Explanation:
Given:
I = 2At = 2 minutes = 120 secondsTo find:
Charge passing through the wire (Q)Solution: Formula relating Q, I and t is given as:
Q = It Plugging the values of I and t in the above equation, we find:Q = 2 * 120-> Q = 240 CThus, 240 Coulomb charge will pass through the wire.
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
Helelepppppppppppapap
Answer:
C. the box accelerates at 2 m/s²
Explanation:
Given
Force (F) = 10 N
mass(m) = 5 kg
acceleration (a) = ?
we know
F = M * a
10 = 5 * a
a = 10 / 5
a = 2 m/s²
Hope it will help :
What role does a resistor play in an electrical circuit? A. it removes excess electrons from the outer surface of a conducting wire. B. it transforms light energy and thermal energy into electrical energy. C. it transforms the electrical energy of the electrons into other forms of energy. D. it stores electrical energy until it can be released by closing a switch
Answer:
It transforms the electrical energy of the electrons into other forms of energy.
Explanation:
Just took the quiz
You have to lift a 15 kg object. What is your output force?
Using a lever, you push down 20 N to lift a 10 kg object.
A) Find the output force.
B) What is the input force?
C) How much does the ramp multiply your force?
You push with 10 N up a ramp to move a 40 N object to the top
of a table. By how much does the ramp multiply your force?
Answer:
Explanation:
A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:
Output force = Weight of object = m * g
where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:
Output force = 15 kg * 9.81 m/s^2 = 147.15 N
Therefore, the output force required to lift a 15 kg object would be 147.15 N.
B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.
C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:
Mechanical advantage = Output force / Input force = 40 N / 10 N = 4
So, the ramp multiplies your force by a factor of 4.
Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.
steps btw if possible
asap pls I will give u everyting
Answer:
(4) 50 ohms (5) 11.76 ohms
Explanation:
In the parallel combination, the equivalent resistance is given by :
\(\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+....\)
4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :
\(\dfrac{1}{R}=\dfrac{1}{150}+\dfrac{1}{150}+\dfrac{1}{150}\\\\R=50\ \Omega\)
5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,
\(\dfrac{1}{R}=\dfrac{1}{20}+\dfrac{1}{40}+\dfrac{1}{100}\\\\=11.76\ \Omega\)
Hence, this is the required solution.
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
a. The magnitude of the electric force that one particle exerts on the other is 1.72 millinewtons (mN). and b. the force is repulsive
To calculate the magnitude of the electric force between two charged particles, we can use Coulomb's Law, which states that the magnitude of the electric force (F) between two charged objects is given by:
F = k * (|q1| * |q2|) / r^2
where k is the electrostatic constant (k = 8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.
Given:
q1 = 8.01 nC (nanocoulombs)
q2 = 4.22 nC (nanocoulombs)
r = 1.72 m
Converting the charges to coulombs:
q1 = 8.01 x 10^-9 C
q2 = 4.22 x 10^-9 C
Plugging the values into Coulomb's Law:
F = (8.99 x 10^9 N·m^2/C^2) * ((8.01 x 10^-9 C) * (4.22 x 10^-9 C)) / (1.72 m)^2
Calculating the magnitude of the force:
F ≈ 1.72 x 10^-3 N
Therefore, the magnitude of the electric force that one particle exerts on the other is approximately 1.72 millinewtons (mN).
To determine if the force is attractive or repulsive, we need to consider the signs of the charges. If the charges have opposite signs (one positive and one negative), the force is attractive. If the charges have the same sign (both positive or both negative), the force is repulsive.
In this case, both charges are positive, so the force between them is repulsive. The particles will experience a repelling force due to their like charges, causing them to push away from each other.
The question was incomplete. find the full content below:
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
(a) What is the magnitude (in N) of the electric force that one particle exerts on the other?
(b) Is the force attractive or repulsive?
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In a certain process a gas ends in its original thermodynamic state. Of the following, which is possible as the net result of the process?
A. It is adiabatic and the gas does 50 J of work.
B. The gas does no work but absorbs so J of energy as heat.
C. The gas does no work but rejects 50 J of energy as heat.
D. The gas rejects 50 J of energy as heat and does 501 of work.
E. The gas absorbs 50 of energy as heat and does 50」ot work.
Answer:
E. The gas absorbs 50 of energy as heat and does 50」ot work
Explanation:
This is following the law of thermodynamics that energy is neither created nor destroyed
A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this time?
Answer:
s = 307.34 m
Explanation:
In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:
s = Vi t + (0.5)at²
where,
s = distance covered by the dragster = ?
Vi = Initial Velocity = 0 m/s
t = time interval = 3.97 s
a = acceleration = 39 m/s²
Therefore,
s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²
s = 307.34 m