A population of ducks lives in an area that floods many times each year. Some of the ducks are better at finding food on dry land, while other ducks are better at finding food in wet, muddy areas. Eventually, the land around the lake permanently changes from dry soil to wet, marshy mud. How will this change to the land most likely affect the duck population? The population will remain stable because the ducks will not be affected by this kind of change. The population will eventually balance out so that there are equal numbers of both types of ducks. The population will evolve so that most ducks survive no matter how they find food. The population will evolve so that most ducks are better at finding food in wet, muddy areas.

Answer:

it is safe to stand at the end of the table

Explanation:

For this exercise we use the rotational equilibrium condition

         Στ = 0

         W x₁ - w x₂ - w_table x₃ = 0

         M x₁ - m x₂ - m_table x₃ = 0

where the mass of the large rock is M = 380 kg and its distance to the pivot point x₁ = 850 cm = 0.85m

the mass of the man is 62 kg and the distance

            x₂ = 4.5 - 0.85

            x₂ = 3.65 m

the mass of the table (m_table = 22 kg) is at its geometric center

            x_{cm} = L/2 = 2.25 m

            x₃ = 2.25 -0.85

            x₃ = 1.4 m

let's look for the maximum mass of man

            m_{maximum} = \(\frac{ M x_1 -m_{table} x_3}{ x_2}\)

let's calculate

             m_{maximum} = \(\frac{ 380 \ 0.85 - 22 \ 1.4}{3.65}\)(380 0.85 - 22 1.4) / 3.65

             m_{maximum} = 80 kg

we can see that the maximum mass that the board supports without turning is greater than the mass of man

             m_{maximum}> m

consequently it is safe to stand at the end of the table

when water in a metal pot is heated over a campfire. Primarily, by means of convection energy transfer is thermal energy moved from the fire to the bottom of the pot

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can flow by different means such as conduction, convection, and radiation.

As given in the problem when water in a metal pot is heated over a campfire. The energy we receive around the campfire is mostly due to the effect of the radiation of the heat but the Primary means of energy transfer is thermal energy moved from the fire to the bottom of the pot because of the convection.

Thus, when water is heated in a metal pot over a campfire. Thermal energy is primarily transferred from the fire to the bottom of the pot through convection.

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Blood comes into the right atrium from the body, moves into the right ventricle and is pushed into the pulmonary arteries in the lungs. After picking up oxygen, the blood travels back to the heart through the pulmonary veins into the left atrium, to the left ventricle and out to the body's tissues through the aorta.

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Answer:

Hello

I think the first one is correct.

Explanation:

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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Answer:

a) d = 3.6 km

b) 0.024°

Explanation:

To see the top of a 1 m tall deer over the surface of a 6400 km radius perfect sphere, the angle subtended is

cosθ = 6 400 000 / (6 400 001)

θ = 0.0320293...°

d = Rtanθ = 6 400 000tan0.0320293

d = 3,577.708... m

5 ft = 1.524 m

tanθ = 1.524 / 3577.7

θ = 0.0244063...°

Work of art from the Amarna Period that is abstract or descriptive in nature.

That momentarily altered during the Amarna Period. The neck, arms, and hands were among the longer characteristics on the body. The traditional Egyptian painting form was briefly replaced by this strange new art form, which resulted in portraits of people that were virtually caricatures.

Religious iconoclasts are associated with the Amarna Period. Because he only worshiped the Aten, the pharaoh Amenhotep IV changed his name to Akhenaten. At Tell el-Amarna in Middle Egypt, he constructed a brand-new capital and cemetery.

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Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

Explanation:

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time

Explanation:

B) A pendulum is a mass suspended on the bottom of a string.

A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.

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Answer:

Answer:Sir haymo knows

Explanation:

he gave as homework

The acceleration of the Saturn is - (2πf)²x(t).

A motion in which the restoring force is directly proportional to the body's displacement from its mean position is known as a simple harmonic motion, or SHM. This restoring force always moves in the direction of the mean position. A particle moving in simple harmonic motion accelerates as a(t) = - ω² x (t). Here, ω denotes the particle's angular velocity.

The acceleration of the particle at any position is directly proportional to the displacement from the mean position in simple harmonic motion, which is an oscillatory motion.

Given that:

at any time, the angular position of Saturn is (2πf)t.

the displacement in SHM at that time t is given by x(t)=R cos(2πf)t.

Hence, speed  in SHM at that time t is given by

\(v(t) = \frac{dx(t)}{dt} =R \frac{d }{dt} cos(2\pi f)t = -(2\pi f) sin(2\pi f)t\)

it's acceleration is

\(a(t) = \frac{dv(t)}{dt} =-(2\pi f) R \frac{d }{dt} sin(2\pi f)t = -(2\pi f)^2 Rcos(2\pi f)t = -(2\pi f)^2 x(t)\)

hence, at any time t, the acceleration of the Saturn is - (2πf)²x(t).

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Answer:

5 cm - 53 degrees

Explanation:

\( \sqrt{ {4}^{2} + {3}^{2} } = 5cm\)

\( \tan ^{ - 1} (4 \div 3) \) = 53°

Answer:

please find your answer in the attached picture, along with explanation.

Answer:

D, the acceleration  of A is twice that of b.

Explanation: in four seconds b got to ten, in two seconds a got to 20. Going  10m/s faster in half the time is going twice the acceleration

Answer:

work

Explanation:

Answer:

\(3.6\times10^{23} N\)

Explanation:

\(F=\frac{GmM}{r^2}=4\times10^{22} N\)

\(F'=\frac{GmM}{(r/3)^2}=9\frac{GmM}{r^2}=9\times4\times10^{22}=3.6\times10^{23} N\)

if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

The gravitational force between two objects is given by Newton's law of universal gravitation:

\(\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]\)

where:

F is the gravitational force between the two objects,

G is the gravitational constant \((\( G \approx 6.67430 \times 10^{-11} \, \text{m}^3/\text{kg}\cdot\text{s}^2 \)),\)

\(\( m_1 \)\) and \(\( m_2 \)\) are the masses of the two objects, and

r is the distance between the centers of the two objects.

Let's assume the planet is \(\( m_1 \)\) and the star is \(\( m_2 \).\)

Given that the original force is \(\( 4 \times 10^{22} \, \text{N} \)\), we have:

\(\[ F_{\text{original}} = 4 \times 10^{22} \, \text{N} \]\)

Let's denote the original distance between the planet and the star as \(\( r_{\text{original}} \).\)

Now, when the planet is 3 times closer to the star, the new distance \((\( r_{\text{new}} \))\) will be \(\( \frac{1}{3} \)\) of the original distance:

\(\[ r_{\text{new}} = \frac{1}{3} \cdot r_{\text{original}} \]\)

To find the new magnitude of the force \((\( F_{\text{new}} \))\) on the star due to the planet, we use the same formula with the new distance:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{r_{\text{new}}^2} \]\)

Substitute \(\( r_{\text{new}} \)\) with \(\( \frac{1}{3} \cdot r_{\text{original}} \):\)

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\left( \frac{1}{3} \cdot r_{\text{original}} \right)^2} \]\)

Simplify the expression:

\(\[ F_{\text{new}} = \frac{G \cdot m_1 \cdot m_2}{\frac{1}{9} \cdot r_{\text{original}}^2} \]\)

Multiply both the numerator and denominator by 9 to get rid of the fraction:

\(\[ F_{\text{new}} = \frac{9 \cdot G \cdot m_1 \cdot m_2}{r_{\text{original}}^2} \]\)

Now, we can see that \(\( F_{\text{new}} \)\) is simply 9 times the original force \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times F_{\text{original}} \]\)

Substitute the value of \(\( F_{\text{original}} \):\)

\(\[ F_{\text{new}} = 9 \times 4 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 36 \times 10^{22} \, \text{N} \]\[ F_{\text{new}} = 3.6 \times 10^{23} \, \text{N} \]\)

So, if the planet were 3 times closer to the star, the magnitude of the force on the star due to the planet would be \(\( 3.6 \times 10^{23} \, \text{N} \).\)

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If the clown on the right weighs 50 kg, her height at her tallest point will be 6 m.

The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

From the conservation energy principle potential energy at the lowest and the highest points are equal.

\(\rm m_1gh_1=m_2gh_2 \\\\ 50 \ kg (h_2)=(75 \ kg )(4 \ m)\\\\\ h_2=6 \ m\)

Hence, the maximum height that the clown on the right can reach if she has a mass of 50 kg will be 6m.

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The machine makes the task easy by increasing the distance through which the force is applied, by changing the direction of the force applied or by changing the magnitude of the applied force.

Hence, 1st option (force) is the correct answer.

At the lowest point on the Ferris wheel, there are two forces acting on the child: their weight of 430 N, and an upward centripetal/normal force with magnitude n; then the net force on the child is

∑ F = ma

n - 430 N = (430 N)/g • a

where m is the child's mass and a is their centripetal acceleration. The child has a linear speed of 3.5 m/s at any point along the path of the wheel whose radius is 17 m, so the centripetal acceleration is

a = (3.5 m/s)² / (17 m) ≈ 0.72 m/s²

and so

n = 430 N + (430 N)/g (0.72 m/s²) ≈ 460 N

The information is missing here but data that may support the existence of life in an exoplanet may include the discovery of atmospheric biological gases.

An exoplanet is any planet that surrounds another star beyond the sun, and therefore they are discovered by analyzing other galaxies in the Universe.

The existence of life in these exoplanets can be indirectly supported by the presence of gases that are only produced by organisms, which are detected by suitable telescopes that analyze emission spectra.

In conclusion, the information is missing here but data that may support the existence of life in an exoplanet include biological gases.

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Pressure = (force) divided by (area)

But force and area are both derived units themselves.

-- Force = (mass) times (acceleration)

But acceleration is a derived unit itself.

Acceleration = (length) divided by (time squared)

So force = (mass) · (length / time squared)

-- Area = (length squared)

So pressure = (mass · length / time-squared) / (length-squared)

Pressure = (mass) / (length · time-squared)

That sure looks to me like it's derived from a bunch of other stuff.

A satellite with mass M travels at a constant velocity v in a circle with radius R. Then its centripetal acceleration is constant, its tangential acceleration is zero, and its angular speed is v/R.

The earth launches satellites into orbit around it. To place the satellite in the desired orbit, many rockets are launched from the satellite at the appropriate time. The satellite will continue to move in an orbit under the pull of the earth's gravity once it has been placed in the desired orbit and is moving at the appropriate speed for that orbit.This satellite has potential energy because it is in a gravitational field and has kinetic energy since it circles around the planet. A satellite's kinetic energy is equal to half its gravitational energy, as shown by, Gravitational energy has a value of GMm/r, hence kinetic energy has a value of GMm/2r and is positive.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Given:

The mass of one object is m1 = 16 kg

The initial speed of the object is

The mass of another object is m2 = 9 kg.

The speed of the object will be zero as it is at rest.

To calculate the kinetic energy lost.

Explanation:

The collision is inelastic.

According to the conservation of momentum, the speed after the collision can be calculated as

The loss in kinetic energy during a collision can be calculated as

Thus, the correct choice is E

Answer:

P = cte / V

therefore pressure and volume are inversely proportional

Explanation:

For this exercise we can join the ideal gases equation

        PV = n R T

they indicate that the amount of matter and the temperature are constant, therefore

         PV = cte

        P = cte / V

therefore pressure and volume are inversely proportional

Answer:

I will guess c for your answer!

Explanation:

I don't know really how to explain my guess.

Answer:

I believe B

Explanation:

73 - 65 = 8

8 / 5 = 1.6

We can obtain the resultant displacement by geometry as 9.4 m North East

Displacement is the distance covered in a specific direction. It is a vector quantity hence its resultant must be obtained geometrically.

Given that, we can obtain the resultant displacement by the use of the Pythagoras theorem;

R= √(5)^2 + (8)^2

R = 9.4 m North East

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Answer:

88.14 m/s

Explanation:

From the question given above, the following data were obtained:

Radius (r) = length of blade = 80 m

Revolution (rev) = 1

Time (t) = 5.7 s

Velocity (v) =?

The velocity of the blade can be obtained by using the following formula:

v = (rev × 2πr) / t

NOTE: Pi (π) = 3.14

v = (1 × 2 × 3.14 × 80) / 5.7

v = 502.4 / 5.7

v = 88.14 m/s

Therefore, the velocity of the blade is 88.14 m/s

In social psychology, a stereotype is a generalized belief about a particular category of people.

A stereotype can be described as the accepted, condensed, and essentialist opinion  with regards to certain population.

I should be nted hat his can be related to  gender identity, race  as well as ethnicity, country,  however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.

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