A population of bacteria is growing according
to the equation P(t)=1000e0.12t, where P(t) is
the population and t is the time in hours.
Estimate when the population will reach 5000.
Round to the tenths.

Answer:

Please refer to the image.

The answer is blonde hair.

Compared to the parent function f(x)=|x|, the graph of F(x) is a translation 7 units down.

Answer:

(-6;5)

Step-by-step explanation:

if they are asking about where it is going to be situated in the coordinate system after the rotation

Solution:

Note that:

Solve for x to find the weight of each patty.

The weight of a patty is 4/15 of a pound.

Answer:

4/15

Step-by-step explanation:

Hope this helps! Sorry if I am wrong.

Answer:

what y'all teachers be on

Answer:

The answer is c I hope this helps

Answer:

\(|F'H'| = 2 * |FH|\)

Step-by-step explanation:

Given

\(E = (0,1)\)             \(E' = (-1,2)\)

\(F = (1,1)\)             \(F' = (1,2)\)

\(G = (2,0)\)             \(G' =(3,0)\)

\(H = (0,0)\)            \(H' = (-1,0)\)

\((x,y) = (1,0)\) -- center

\(k = 2\) --- scale factor

See comment for proper format of question

Required

Compare FH to F'H'

From the question, we understand that the scale of dilation from EFGH to E'F'G'H is 2;

Irrespective of the center of dilation, the distance between corresponding segment will maintain the scale of dilation.

i.e.

\(|F'H'| = k * |FH|\)

\(|F'H'| = 2 * |FH|\)

To prove this;

Calculate distance of segments FH and F'H' using:

\(d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\)

Given that:

\(F = (1,1)\)             \(F' = (1,2)\)

\(H = (0,0)\)            \(H' = (-1,0)\)

We have:

\(FH = \sqrt{(1- 0)^2 + (1- 0)^2}\)

\(FH = \sqrt{(1)^2 + (1)^2}\)

\(FH = \sqrt{1 + 1}\)

\(FH = \sqrt{2}\)

Similarly;

\(F'H' = \sqrt{(1 --1)^2 + (2 -0)^2}\)

\(F'H' = \sqrt{(2)^2 + (2)^2}\)

Distribute

\(F'H' = \sqrt{(2)^2(1 +1)}\)

\(F'H' = \sqrt{(2)^2*2}\)

Split

\(F'H' = \sqrt{(2)^2} *\sqrt{2}\)

\(F'H' = 2 *\sqrt{2}\)

\(F'H' = 2\sqrt{2}\)

Recall that:

\(|F'H'| = 2 * |FH|\)

So, we have:

\(2\sqrt 2 = 2 * \sqrt 2\)

\(2\sqrt 2 = 2\sqrt 2\) --- true

Hence, the dilation relationship between FH and F'H' is::

\(|F'H'| = 2 * |FH|\)

Answer:NOTT !!  A segment in the image has the same length as its corresponding segment in the pre-image.

Step-by-step explanation:

The value of covariance cov(y1, y2) is -0.222

                      y1      

y2         0         1         2          Total

0          1/9      2/9     1/9          4/9

1          2/9      2/9      0            4/9

2          1/9        0       0            1/9

Total   4/9       4/9     1/9          1      

  marginal distribution of y2:

y2      P(y2)      y2P(y2)      y2^2P(y2)

0         4/9        0.0000        0.0000

1          4/9         0.4444        0.4444

2          1/9         0.2222        0.4444

total      1          0.66667       0.88889

E(y2) = 0.6667

E(y2^2) = 0.8889

Var(y2) = E(y2^2)-(E(y2))^2=0.4444

marginal distribution of y1  

y1       P(y1)       y1P(y1)      y1^2P(y1)

0         4/9       0.0000      0.0000

1          4/9        0.4444       0.4444

2          1/9         0.2222      0.4444

total  1.00          0.6667      0.8889

E(y1) = 0.6667

E(y1^2) = 0.8889

Var(y1)= σy = E(y1^2)-(E(y1))^2 = 0.4444

E(XY) =∑xyP(x,y)=0.2222

Cov(y1,y2) = -0.222

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Mai travels abοut 4.2 feet per secοnd faster than Kiran.

Circumference is the distance arοund the οutside οf a circle. It is the length οf the bοundary that enclοses a circle. Tο find the circumference οf a circle, yοu can use the fοrmula C=2πr, where "C" represents the circumference, "π" is a mathematical cοnstant (apprοximately equal tο 3.14159), and "r" is the radius οf the circle (the distance frοm the center οf the circle tο its edge). Sο, the circumference οf a circle is directly prοpοrtiοnal tο its radius. This means that if yοu dοuble the radius οf a circle, its circumference will alsο dοuble.

The circumference οf Kiran's ring is:

C1 = 2πr1 = 2π(9 ft) ≈ 56.55 ft

The circumference οf Mai's ring is:

C2 = 2πr2 = 2π(r1 + 8 ft) = 2π(17 ft) ≈ 106.81 ft

Therefοre, Mai travels a distance οf 106.81 - 56.55 = 50.26 feet mοre than Kiran in οne rοtatiοn.

The time it takes fοr οne rοtatiοn is given as 12 secοnds. Therefοre, the speed οf Kiran in feet per secοnd is:

V1 = C1 / t = 56.55 ft / 12 s ≈ 4.71 ft/s

And the speed οf Mai in feet per secοnd is:

V2 = C2 / t = 106.81 ft / 12 s ≈ 8.90 ft/s

The difference in their speeds is:

V2 - V1 = 8.90 ft/s - 4.71 ft/s ≈ 4.2 ft/s

Therefοre, Mai travels abοut 4.2 feet per secοnd faster than Kiran.

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Check the picture below.

Answer:

F

Step-by-step explanation:

is the answer because when u solve u get that answer u get your ratio and then multiply and divide that's how u get your answer

The ratio of boys to  girls on the bus is 1/2

Given that the ratio of boys to girls on a bus is 4 to 5, this can be written as  4:5

If 1 girl and  2 boys get off the bus, the number of boys to girls will be (4-2):(5-1)

Hence the ratio of boys to  girls on the bus is 1/2

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The most convincing explanation I can give for why a = c is supplementary property a+ b

= 180° and b+c = 180° and substraction operation and also one more reason is a = c is also true because they are vertically opposite angles.

A supplementary angle is an angle that sums to 180 degrees. For example, the 130° and 50° angles are complementary because the sum of 130° and 50° is 180°.

We know that, supplementary angles are angles whose sum is 180°. From the above figure, using the property that linear pairs are supplementary , we have b+c = 180° , c+d = 180° , d+a = 180° ,

a+b = 180°

Therefore, consider a+b = 180° and b+c = 180°

Using subtraction property of equality, we have

180°- b = a .........(1)

180°-b = c ..........(2)

Substitute 180°- b = a in equation (2) , we get

=> a = c

Hence, we get the required results.

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Comparing the median of each box-and-whisker plot, the type of transportation that is LEAST likely to take more than 30 minutes is: d. train.

How to Interpret a Box-and-whisker Plot?

In order to determine the transportation that is LEAST likely to take more than 30 minutes, we have to compare the median of each data set represented on the box-and-whisker plot for each transportation.

The box-and-whisker plot that has the lowest median would definitely represent the the transportation that is LEAST likely to take more than 30 minutes, since median represents the typical minutes or center of the data.

Therefore, from the box-and-whisker plots given, the one for train has the lowest median. Therefore train would LEAST likely take more than 30 minutes.

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Answer:4 cm

Step-by-step explanation:

Formula for perimeter of a rectangle: P = 2(l+w)

20 = 2(6+w)

20 = 12+2w

divide by 2

10 = 6 + w

10-6 = w

4 = w

Answer: 4

This problem requires basic division. If the restaurant divided 4/5 kg of butter with 1/5 kg on each dish, you would need to compute 4/5 divided by 1/5.

4/5 ÷ 1/5

Using the "KFC" method, or Keep, Change, Flip, you would keep the first number (in this case, 4/5), change the division sign, and flip the fraction to 5/1, or 5. We now have this:

4/5 x 5

To compute this equation, you must multiply the numerators of both of the numbers together. In this case, you would compute (4x5)/5, resulting with 20/5, or 4.

You can check this answer by re-multiplying the numbers together. 1/5 kg of butter per dish, multiplied by the total amount of dishes, 4, you would result in the original 4/5 kg of butter.

Hope this helps!

Answer:

answer is b...............

Answer:

yes it is

Step-by-step explanation:

Answer:

A=b×h

A=3x5

A=15

ggggggggggg

Answer:

The estimated money collected in concession sales would be $39,000,000.

Step-by-step explanation:

Since a major league baseball team is ending its season and totaling up concession sales, and looking at receipts they have found that they made $ 10,486,525 in hot dog sales, $ 23,451,492 in large drink sales, $ 4,765,300 in soft pretzel sales and $ 1,342,653 in nacho sales, To determine, if they rounded each item's sales amount to the nearest million, what is the estimated money collected in concession sales, the following calculations must be performed:

$ 10,486,525 = 10,000,000

$ 23,451,492 = 23,000,000

$ 4,765,300 = 5,000,000

$ 1,342,653 = 1,000,000

10 + 23 + 5 + 1 = 39

Therefore, the estimated money collected in concession sales would be $ 39,000,000.

Answer:

\(x = 12.5\) degrees

Step-by-step explanation:

Since lines a and b are parallel, we have that angles 3 and 5 are congruent, that is, they have the same measure.

We have that:

\(m<3 = 10x\)

\(m<5 = 12x - 25\)

Value of x:

Since they are congruent:

\(m<3 = m<5\)

\(10x = 12x - 25\)

\(-2x = -25\)

\(2x = 25\)

\(x = \frac{25}{2}\)

\(x = 12.5\) degrees

Step-by-step explanation:

it is true

the square root of 16 is 4

Answer:

i think i got it but can you help me out a little with this too? im not sure either...dont ban me i jjust need help

Step-by-step explanation:

On solving the inequalities a ≥ 10, y ≥ 55, 7a + 10y ≥ 690, the solution is obtained as (20,55).

What is an inequality?

In Algebra, an inequality is a mathematical statement that uses the inequality symbol to illustrate the relationship between two expressions. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa.

Use the variables a and y to represent the number of student and adult tickets sold, respectively.

Then write the following system of inequalities -

a ≥ 10 (they must sell a minimum of 10 student tickets)

y ≥ 55 (they must sell at least 55 adult tickets)

7a + 10y ≥ 690 (they must make no less than $690 from ticket sales)

The first two inequalities are constraints on the number of tickets sold, and the third inequality represents the revenue constraint.

To find a possible solution, graph these inequalities on a coordinate plane and look for the feasible region that satisfies all three inequalities.

Alternatively, solve the system of inequalities using algebra.

First, simplify the third inequality by subtracting 7a from both sides -

10y ≥ 690 - 7a

Then, divide both sides by 10 -

y ≥ (690 - 7a)/10

This inequality represents the revenue constraint in terms of the number of student tickets sold.

Now combine the revenue constraint with the other two constraints -

a ≥ 10

y ≥ 55

y ≥ (690 - 7a)/10

Use substitution to solve for a in terms of y -

y ≥ (690 - 7a)/10

10y ≥ 690 - 7a

7a ≥ 690 - 10y

a ≥ (690 - 10y)/7

To find a possible solution, substitute a = (690 - 10y)/7 into the other two constraints -

(690 - 10y)/7 ≥ 10

y ≥ 55

These inequalities can be simplified -

690 - 10y ≥ 70

y ≥ 55

The first inequality can be solved for y -

-10y ≥ -620

y ≤ 62

Since it is known y ≥ 55, the feasible values for y are between 55 and 62, inclusive -

55 ≤ y ≤ 62

Now use the expression for a in terms of y to find the corresponding values of a -

a = (690 - 10y)/7

For each value of y between 55 and 62, inclusive, we can calculate a and check whether it satisfies the constraints -

a ≥ 10

y ≥ 55

7a + 10y ≥ 690

For example, when y = 55 -

a = (690 - 10(55))/7 = 20

7a + 10y = 7(20) + 10(55) = 690

Therefore, these values satisfy all three constraints, so one possible solution is a = 20 and y = 55.

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Answer:

0.350 km

Step-by-step explanation:

Hi there !

35000 cm = 35000/100 m = 350 m

350 m = 350/1000 km = 0.350 km

Good luck !

Answer:

Step-by-step explanation:xmccc

If Scampini has no debt or preferred stock, and its WACC is 12%, and it has zero nonoperating assets in which Scampini has 40 million shares of stock outstanding, the stock's value per share is $37.50.

Next year CF = $75 millions

Growth rate of CF = 7%

WACC = 12%

Number of shares outstanding = 40 million shares

Estimated business valuation:

Valuation = Next year CF/ (WACC -growth rate)

Valuation = $75 million / (12% - 7%)

Valuation = $75 million /5%

Valuation =$1500 million

Estimated stock price:

Stock price = Valuation /Shares outstanding

Stock price = $1500 million / 40 million shares

Stock price = $37.50

Therefore the stock price is $37.50.

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