A pole having a length of 2. 750 m is balanced vertically on its tip. It starts to fall and its lower end does not slip.

A. If the mass of the pole is 9. 50 kg , what will be the change in gravitational potential energy for the falling pole? Assume the mass of the pole is uniformly distributed.

B. What is the rotational inertia of the pole about an axis through its lower end and perpendicular to the pole?

C. Suppose the pole is not vertical when it is released; instead suppose the pole makes an angle of 29 degrees with the vertical when it is released. What will be the speed of the upper end of the pole just before it hits the ground in such a case?

Answers

Answer 1

A. To determine the change in gravitational potential energy for the falling pole, we can use the formula:

ΔPE = mgh

Where ΔPE is the change in gravitational potential energy, m is the mass of the pole, g is the acceleration due to gravity, & h is the height through which the pole falls.

Since the pole is initially balanced vertically on its tip, the initial height, h, is zero. When the pole falls, it rotates about its lower end & moves through a distance equal to its length, L, which is 2.750 m. Therefore, the final height, h', is L.

Substituting the given values, we have:

ΔPE = (9.50 kg)(9.81 m/s2)(2.750 m) = 252.0 J

Therefore, the change in gravitational potential energy for the falling pole is 252.0 J.

B. The rotational inertia of the pole about an axis through its lower end and perpendicular to the pole is given by:

I = (1/3) mL²

Where I is the rotational inertia, m is the mass of the pole, & L is the length of the pole.

Substituting the given values, we have:

I = (1/3)(9.50 kg)(2.750 m)² = 62.0 kg m²

Therefore, the rotational inertia of the pole about an axis through its lower end and perpendicular to the pole is 62.0 kg m².

C. To determine the speed of the upper end of the pole just before it hits the ground, we can use the conservation of energy principle, which states that the initial total energy of a system is equal to the final total energy of the system. Initially, the pole has gravitational potential energy, and when it falls, this energy is converted into kinetic energy.

The total energy of the system is:

E = PE + KE

Where E is the total energy, PE is the gravitational potential energy, and KE is the kinetic energy.

Since the pole starts from rest, its initial kinetic energy is zero. Therefore, the total energy of the system at the start is equal to the gravitational potential energy of the pole.

Using the formula for gravitational potential energy from part A, we have:

PE = (9.50 kg)(9.81 m/s²)(2.750 m)(cos 29°) = 218.6 J

At the end of the fall, all the gravitational potential energy is converted into kinetic energy. Therefore, the total energy of the system is:

E = KE

Using the formula for kinetic energy, we have:

KE = (1/2)Iω²

Where KE is the kinetic energy, I is the rotational inertia of the pole about an axis through its lower end and perpendicular to the pole, and ω is the angular velocity of the pole just before it hits the ground.

We can relate the linear velocity of the upper end of the pole, v, to its angular velocity using the formula:

v = ωL/2

Where L is the length of the pole.

Substituting the given values, we have:

218.6 J = (1/2)(62.0 kg m²)ω²

ω = √(2(218.6 J)/(62.0 kg m²)) = 3.49 rad/s

v = (3.49 rad/s)(2.750 m)/2 = 4.79 m/s

Therefore, the speed of the upper end of the pole just before it hits the ground is 4.79 m/s.

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Related Questions

Identify Variables - help

Identify Variables - help

Answers

In science, variables are factors or conditions that change or affect the outcome of a study. They can be classified into three types: independent variables, dependent variables, and controlled variables. Dependent variables are those that researchers measure to assess the impact of independent variables.

In science, variables are factors or conditions that change or affect the outcome of a study. They can be classified into three types: independent variables, dependent variables, and controlled variables. Identifying variables is critical in any research, as they enable scientists to control the study's conditions, determine cause-and-effect relationships, and achieve accurate results.
Independent variables are those that researchers manipulate to investigate their effect on the dependent variable. They are also called explanatory or predictor variables.

For instance, in a study investigating the effect of different levels of fertilizer on plant growth, the independent variable is the level of fertilizer.
Dependent variables are those that researchers measure to assess the impact of independent variables.

They are also called response variables. In the plant growth study, the dependent variable is the growth rate or size of the plants.
Controlled variables are those that researchers hold constant throughout the study to reduce the impact of extraneous factors on the outcome.

They are also called confounding or intervening variables. In the plant growth study, controlled variables include the type of plant, the amount of water, the light exposure, and the temperature.
In conclusion, identifying variables is crucial in scientific research to achieve accurate results, establish cause-and-effect relationships, and control the study's conditions. Independent, dependent, and controlled variables are the three types of variables used in scientific studies.

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State the forces acting on an object that is stationary/moving. Explain how acceleration changes when the same object is kicked with a great force and a small force. Describe the difference in the movement if the initial object now weighs 50 lbs and is acted on by a small force and a large force.​

Answers

Answer:

it all is force I the barly kick you then it won't do that much date but If the full force kick you then it might hurt.

Explanation:

i hope this helps

For a data set of chest sizes (distance around chest in inches) and weights (pounds) of six anesthetized bears that were measured, the linear correlation coefficient is r 0.144. Use the table valable below to find the critical values of r. Based on a comparison of the linear correlation coefficient r and the critical values, what do you conclude about a linear correlation?
Click the icon to view the table of critical values of r
The critical values are
(Type integers or decimals. Do not round. Use a comma to separate answers as needed.).
Since the correlation coefficient ris
there
sufficient evidence to support the claim of a linear correlation

Answers

In order to determine whether a correlation coefficient is statistically significant or not, we use the critical values of r, which can be obtained from a table of critical values of r

The critical values are ±0.811. Since the correlation coefficient r = 0.144 is less than the critical values of r which are ±0.811, there is insufficient evidence to support the claim of a linear correlation.

Hence, the correct option is

Since the correlation coefficient r is less than the critical values of r, there is insufficient evidence to support the claim of a linear correlation.

What is a linear correlation?

Linear correlation is the measure of the degree of correlation or association between two variables in a data set. If there is a strong correlation between the two variables, it indicates that there is a strong relationship between the two. If there is a weak correlation between the two variables, it indicates that there is a weak relationship between the two.

In order to determine whether a correlation coefficient is statistically significant or not, we use the critical values of r, which can be obtained from a table of critical values of r. If the correlation coefficient is greater than the critical value, it indicates that there is sufficient evidence to support the claim of a linear correlation. If the correlation coefficient is less than the critical value, it indicates that there is insufficient evidence to support the claim of a linear correlation.

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A man runs 650 m east and then turns and runs 850 m west. This takes him 240 seconds.

What is the man’s average VELOCITY for the race?

Answers

Answer:

v = 6.25 m/s

Explanation:

Given that,

A man runs 650 m east and then turns and runs 850 m west. This takes him 240 seconds.

Let east is positive and west is negative

Average velocity = total displacement/total time taken

Total displacement = final psoition - initial position

D = -850 - 650 = -1500 m

So,

\(v=\dfrac{-1500\ m}{240\ s}\\\\v=-6.25\ m/s\)

So, 6.25 m/s is the average velocity of the man.

Explain how the design of a racing car makes it less likely to turn over.​

Answers

The principles which allow aircraft to fly are also applicable in car racing. The only difference being the wing or airfoil shape is mounted upside down producing downforce instead of lift. The Bernoulli Effect means that: if a fluid (gas or liquid) flows around an object at different speeds, the slower moving fluid will exert more pressure than the faster moving fluid on the object. The object will then be forced toward the faster moving fluid. The wing of an airplane is shaped so that the air moving over the top of the wing moves faster than the air beneath it. Since the air pressure under the wing is greater than that above the wing, lift is produced. The shape of the Indy car exhibits the same principle. The shape of the chasis is similar to an upside down airfoil. The air moving under the car moves faster than that above it, creating downforce or negative lift on the car. Airfoils or wings are also used in the front and rear of the car in an effort to generate more downforce. Downforce is necessary in maintaining high speeds through the corners and forces the car to the track. Light planes can take off at slower speeds than a ground effects race car can generate on the track. An Indy ground effect race car can reach speeds in excess of 230 mph using downforce. In addition the shape of the underbody (an inverted wing) creates an area of low pressure between the bottom of the car and the racing surface. This sucks the car to road which results in higher cornering speeds.

The total aerodynamic package of the race car is emphasized now more than ever before. Teams that plan on staying competitive use track testing and wind tunnels to develop the most efficient aerodynamic design. The focus of their efforts is on the aerodynamic forces of negative lift or downforce and drag. The relationship between drag and downforce is especially important. Aerodynamic improvements in wings are directed at generating downforce on the race car with a minimum of drag. Downforce is necessary for maintaining speed through the corners. Unwanted drag which accompanies downforce will slow the car. The efficient design of a chassis is based on a downforce/drag compromise. In addition the specific race circuit will place a different demand on the aerodynamic setup of the car.

A road course with low speed corners, requires a car setup with a high downforce package. A high downforce package is necessary to maintain speeds in the corners and to reduce wear on the brakes. This setup includes large front and rear wings. The front wings have additional flaps which are adjustable. The rear wing is made up of three sections that maximize downforce.

The speedway setup looks much different. The front and rear wings are almost flat and are used as stabilizers. The major downforce is found in the shape of the body and underbody. Drag reduction is more critical on the speedway than on other circuits. Since the drag force is proportional to the square of the speed, minimizing drag is a primary concern in the speedway setup. Lap speeds can average over 228 mph and top speeds can exceed 240 mph on a speedway circuit. Effective use of downforce is especially pronounced in highspeed corners. A race car traveling at 200 mph. can generate downforce that is approximately twice its own weight.

Generating the necessary downforce is concentrated in three specific areas of the car. The ongoing challenge for team engineers is to fine tune the airflow around these areas.


What is the reason eclipses do not happen every full moon and new moon

A. The moon rotates around itself slower than Earth rotates around itself

B. The moon completes a rotation around the earth faster than earth complete a rotation around the sun

C. The moon has a much smaller mess than earth or the moon

D. The moons orbit around the earth is tilted compared to the earths orbit around the sun

Answers

The answer is D, hope this helped!

If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor A) decreases B) increases. C) does not change. D) It cannot be determined from the information given.

Answers

If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.

Capacitance is the amount of charge that can be stored at a given voltage by an electrical component called a capacitor.

C=Q/V

The unit of capacitance is the Farad (F)

C = εA/d,

C is capacitance; ε is permittivity, a term for how well dielectric material stores an electric field; A is the parallel plate area; and d is the distance between the two conductive plates.

electric field between two parallel conducting plates depends on the electric potential or voltage of the two plates and the distance between the two plates. So, the electric field E=Vd E = V d where d is the distance between the two charged plates.

The force on the charge is the same no matter where the charge is located between the plates. This is because the electric field is uniform between the plates.

If the electric field between the plates of a given air-filled capacitor is weakened by removing charge from the plates, the capacitance of that capacitor does not change.

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what will be the final kinetic energy if the velocity of a body is halved keeping mass constant​

Answers

Answer:

Kinetic energy of the body

\(K.E = \frac{1}{2}mv {}^{2}\)

So, K.E∝ v²

If speed of the body is halved, its kinetic energy is reduced by a factor of 4.

Calculate the KE in joules of a 1500 kg car moving at 29 m/s?

Answers

Answer:

x J = (1500 kg)(29 m/s)(y m/s)

Explanation:

x J = (1500 kg)(29 m/s)(y m/s)

To know that a 1500 kg car is moving at 29 m/s is not enough.

The value of x depends on y. You’re missing a number of meters and a quantity of ‘per seconds’ somewhere in your problem statement and you need to find them in order to solve the problem

a piece of wood is has a density of 0.600 g/cm3. when dipped in water, what fraction of the wood is submerged inside water? (give answer to 3 significant figures)

Answers

To determine the fraction of the wood submerged in water, we need to compare the density of the wood to the density of water.

The density of water is 1.000 g/cm3 at standard temperature and pressure.

If the wood has a density of 0.600 g/cm3, it is less dense than water, which means it will float on water.

To determine the fraction of the wood submerged in water, we can use the following formula:

fraction submerged = (volume submerged) / (total volume)

Since the wood floats on water, the volume of water displaced by the wood is equal to the volume of the submerged portion of the wood.

The total volume of the wood is equal to its mass divided by its density:

total volume = mass / density

We don't have the mass of the wood, but we can use any arbitrary value to determine the fraction submerged.

Let's assume the wood has a mass of 100 g.

total volume = mass / density = 100 g / 0.600 g/cm3 = 166.67 cm3

Now, let's assume that when the wood is submerged in water, it displaces 80 cm3 of water.

fraction submerged = (volume submerged) / (total volume) = 80 cm3 / 166.67 cm3 = 0.48

Therefore, approximately 48% of the wood is submerged in water.

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Please help 25 points Add the following numbers and round your answer to the correct number of significant figures:

90.0 + 80 =

Show both the unrounded and rounded answer.

Answers

Explanation:

Wouldn't this just be 90+80 meaning the answer would be 170?

90.0 + 80 = 170.0 however the number 80 could be just 1 significant figure, in which case the final answer is 200 to 1 significant figure.

At the end of 3N force acts on the object during time interval of 1.5seconds with force acting towards right. A constant force of 4N to left is applied for 3seconds. What is the velocity at the end of the 3seconds ?

Answers

Answer:

v_f = -7.5 m / s

Explanation:

Let's analyze this exercise a little, two forces that act on a body for different time intervals are indicated, each force creates an impulse and since this is a vector quantity we must add in the form of vectors. The net momentum is

we assume that the direction to the right is positive

             I = I₁ + I₂

             I = F₁ Δt₁ - F₂ Δt₂

             I = 3  1.5 - 4  3

             I = -7.5   N s

now let's use the relationship between momentum and momentum, suppose the object starts from rest (vo = 0)

             I = Δp

             I = m (v_f - v₀)

             

             v_f = I / m

             

              v_f = -7.5 / m

to finish the calculation we must assume a mass m = 1 kg

              v_f = -7.5 m / s

the negative sign in the body is moving to the left

What is the dewpoint in radiation fog at a temperature of 10 °C
(50 °F)?

Answers

Assuming 100% relative humidity, the dewpoint temperature in radiation fog at a temperature of 10 °C (50 °F) is approximately 10 °C.

To find the dewpoint in radiation fog at a temperature of 10 °C (50 °F), we need to consider the saturation point of air, which is the temperature at which the air becomes saturated and condensation occurs.

The dewpoint temperature is the temperature at which the air must be cooled for it to reach saturation and for condensation to occur. When the dewpoint temperature is reached, fog or dew will form.

The relationship between temperature, relative humidity, and dewpoint temperature is complex and depends on various factors such as air pressure and moisture content. However, we can estimate the dewpoint using empirical formulas or tables.

One commonly used approximation is the Magnus formula:

Td = (T × Arctan[0.151977 × (RH + 8.313659)^0.5]) + Arctan(T + RH) - Arctan(RH - 1.676331) + 0.00391838 × (RH^(3/2)) × Arctan(0.023101 × RH) - 4.686035

Where:

Td = Dewpoint temperature in degrees Celsius

T = Temperature in degrees Celsius

RH = Relative humidity (expressed as a decimal)

Assuming a relative humidity of 100%, which represents saturated air, we can estimate the dewpoint temperature at a temperature of 10 °C (50 °F).

Substituting the values:

T = 10 °C

For simplicity, we assume RH = 1 (100% relative humidity).

Td = (10 × Arctan[0.151977 × (1 + 8.313659)^0.5]) + Arctan(10 + 1) - Arctan(1 - 1.676331) + 0.00391838 × (1^(3/2)) × Arctan(0.023101 × 1) - 4.686035

Simplifying the equation, we find that the estimated dewpoint temperature (Td) is approximately equal to 10 °C.

Therefore, assuming 100% relative humidity, the dewpoint temperature in radiation fog at a temperature of 10 °C (50 °F) is approximately 10 °C.

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The area on an entrance ramp where you increase speed to that of expressway traffic is the ______? * 1 point deceleration lane median lane entrance lane acceleration lane

Answers

The area on an entrance ramp where you increase speed to that of expressway traffic is the acceleration lane.

So the correct option is (D) that is acceleration lane.

A section or lane of adjustment for speed that has extra flooring on the borders of the lanes of traffic to let vehicles to accelerate until they merge with the flow of traffic.

Drivers must reach the posted speed limit before entering the acceleration lane, signal, locate a gap in traffic, and then merge.

Drivers can accelerate or decelerate in an area not being used by high-speed through traffic by using acceleration/deceleration lanes, also known as speed-change lanes or auxiliary lanes. The abrupt change in pace can result in stop-and-go traffic, crashes, and other problems on freeways and some major streets. These issues can be reduced by including acceleration/deceleration lanes in the roadway design.

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A group of particles is traveling in a magnetic field of unknown magnitude and direction. You observe that a proton moving at 1.50 km/s in the +x-direction experiences a force of 2.06×10−16 N in the +y-direction, and an electron moving at 4.20 km/s in the −z-direction experiences a force of 8.60×10−16 N in the +y-direction.
Part A
What is the magnitude of the magnetic field?
Part B
What is the direction of the magnetic field? (in the xz-plane)
Part C
What is the magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s ?
Part D
What is the direction of this the magnetic force? (in the xz-plane)

Answers

part a: The magnitude of the magnetic field is 1.17 × 10−5 T. part b:  Therefore, the direction of the magnetic field is in the xz-plane.(explanation below). part c: The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is 9.02 × 10−14 N. part d: Therefore, the direction of the magnetic force in the xz-plane is in the +z direction. are the answers

Part A:

The magnetic field is given by the formula:

F= qvBsinθ

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.

The force on proton moving in the +x direction,

Fp = 2.06×10−16 N and the

velocity,  vp = 1.50 km/s = 1.5 × 10^3 m/s

Putting the values in the formula:

Fp= qvpBsinθp

2.06×10−16 = (1.60 × 10−19)(1.50 × 10^3)Bsinθp

where q is the charge of proton which is 1.6 × 10−19 C

The angle θp between the velocity and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

Sin 90° = 1

Substituting the values, we get

B = 1.17 × 10−5 T

The magnitude of the magnetic field is 1.17 × 10−5 T

Part B:

The direction of the magnetic field can be obtained from the force on the electron moving in the -z direction and the force is given by

Fe = 8.60×10−16 N

and the velocity,

ve = 4.20 km/s = 4.2 × 10^3 m/s

Putting the values in the formula:

Fe= qveBsinθe8.60×10−16 = (1.60 × 10−19)(4.2 × 10^3)Bsinθe

where q is the charge of electron which is 1.6 × 10−19 C

The angle θe between the velocity and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

Sin 90° = 1

Substituting the values, we get

B = 1.68 × 10−5 T

Since the force is in the +y direction and the velocity is in the -z direction, the magnetic field should be in the +x direction.

Therefore, the direction of the magnetic field is in the xz-plane.

Part C:

The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is given by the formula:

F= qvBsinθ

where F is the magnetic force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field and θ is the angle between the velocity of the particle and the magnetic field.

The velocity of the electron, ve = 3.50 km/s = 3.5 × 10^3 m/s

The angle between the velocity of the particle and the magnetic field is 90° since the force is perpendicular to the velocity and the magnetic field.

θ = 90° = π/2

Substituting the values in the formula:

F= qveBsinθF = (1.60 × 10−19)(3.5 × 10^3)(1.68 × 10−5) × 1F = 9.02 × 10−14 N

The magnitude of the magnetic force on an electron moving in the −y-direction at 3.50 km/s is 9.02 × 10−14 N.

Part D:

The direction of the magnetic force can be obtained from the right-hand rule. The direction of the magnetic force is perpendicular to both the magnetic field and the velocity of the particle.The velocity of the electron is in the -y direction and the magnetic field is in the +x direction. Using the right-hand rule, the direction of the magnetic force is in the +z direction.

Therefore, the direction of the magnetic force in the xz-plane is in the +z direction.

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Se lanza desde el piso una piedra con velocidad vertical de +42 m/s. El punto de referencia se encuentra en el piso. Calcular: a). Escribir la ecuación de posición y la ecuación de la velocidad. b). Calcular en que instante su velocidad es nula. c). Calcular la máxima altura que llego. (Considerar la aceleración de la gravedad: a=9.81m/s2).

Answers

Answer:

a)  y = 42 t - 4,905 t² ,      v = 42 - 9.81 t,  b)   t = 4.281 s , c)   y = 89.9 m

Explanation:

This problem is an example of vertical launch

a) the expression for the position is

         y = v₀ t - ½ g t²

we substitute

          y = 42 t - 4,905 t²

the expression for speed is

        v = v₀ - gt

        v = 42 - 9.81 t

b) the speed is null when v = 0

         v₀ = gt

          t = v₀ / g

          t = 42 / 9.81

          t = 4.281 s

c) for the maximum height we can use the expression

        v² = v₀² - 2gy

    at maximum height v = 0

         y = v₀² / 2g

     let's calculate

        y = 42 2/2 9.81

        y = 89.9 m

A 2455 kg car was pushed by 77 kg student with a force of 720 N. What force does the car apply on the student?
a.0 N
b.-797 N
c.- 720 N
d.-3175 N

Answers

Answer:

C

Explanation:

Given that a 2455 kg car was pushed by 77 kg student with a force of 720 N.

According to Newton's third law of motion which state that in every action, there will be equal and opposite reaction.

The action on the car = 720 N

The reaction from the car = - 720 N

Therefore, the force the car will apply on the student will be -720N.

The correct answer is C

1. when all other factors are constant, the ______ determines the length of a projectile's trajectory.

Answers

When all other factors are constant, the initial velocity determines the length of a projectile's trajectory.

A projectile is an object that is thrown or projected into the air and follows a path determined by the forces of gravity and air resistance. The length of a projectile's trajectory is determined by the time it takes for the projectile to reach its maximum height and the time it takes for the projectile to return to the ground. Initial velocity is the velocity at which a projectile is launched, and it determines the initial speed and direction of the projectile.

The greater the initial velocity, the farther the projectile will travel before hitting the ground, this is because the projectile spends less time in the air, so it has less time to slow down due to air resistance. In contrast, a projectile with a lower initial velocity will travel a shorter distance because it spends more time in the air and slows down more due to air resistance. Therefore, the initial velocity is a crucial factor that determines the length of a projectile's trajectory.

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Which change increases the electric forcWhich change increases the electric force between objects?e between objects?

Answers

The electric force increases because the amount of charge has a direct relationship to the force. ... Electrons are added to two negatively charged objects. Hope it helps

Answer:

b

Explanation:

A 20 N force is necessary to stretch a spring 0.5 m. What is the spring constant of this spring?

Answers

Answer: The spring constant of a given spring is \(40 N/m\).

Explanation:

Given,

Force (F) = 20N

The displacement of the spring\(= x = 0.5 m\)

To find: Spring constant (k) = ?

As we know that,

Hook's law states that,

\(F = k\) · \(x\)

Therefore, \(k = \frac{F}{x}\)

\(k = \frac{20}{0.5}\)

\(k = \frac{(20)(10)}{5}\)

\(k = 40 N/m\)

Hence, The spring constant of a given spring is \(40 N/m\).

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1. Which among the sports you stated above are you familiar with?​

Answers

I am familiar with Russian Mountaineering

what does light means​

Answers

Answer:

Light is a source of illumination, whether a natural one (like the sun) or an artificial one (like your lamp). Like light itself, the word can take a lot of different forms — it can be a noun, an adjective, or a verb, and it can mean "bright" or "not heavy".

Explanation:

Answer:

the natural agent that stimulates sight and makes things visible

The decomposition of H2O2 is a first-order reaction given by the formula: Rate = k [H2O2]1. How would the reaction rate be affected if the H2O2 concentration were double its original value?

Answers

Answer: The decomposition of H₂O₂ is a first-order reaction. Then, the reaction rate will be 2 times the original rate, if we double its concentration value.

Explanation: To find the answer, we need to know about the decomposition of H₂O₂.

What is the rate of reaction, if we double the concentration of H₂O₂?We have the equation of decomposition of H₂O₂ as,

                              2H₂O₂→ 2 H₂O+ O₂

We have given that, the equation of reaction rate of the first order reaction as,

                              Rate = k [H₂O₂]1

As we know that the equation of reaction rate is,

              Rate = rate constant × concentration of [H₂O₂]

Thus, by comparing both the equations, we get,

         rate constant=k and the concentration of [H₂O₂] = 1[H₂O₂].

Given that the concentration is doubled. Then the expression for rate will be,

                              Rate = 2k [H₂O₂].

Thus, we can conclude that the rate of reaction will be 2 times the initial rate if we double the concentration.

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If we double the concentration value, the reaction rate will be twice as fast as before.

In order to determine the solution, we must understand how H2O2 breaks down.

If we double the concentration of H2O2, what will happen to the reaction rate?The formula for the breakdown of H2O2 is,

                        2H₂O₂→ 2 H₂O+ O₂

We have provided the first order reaction's reaction rate equation as,

                      Rate = [H2O2] k

As we are aware, the reaction rate equation is

                   Rate = rate constant × [H2O2] concentration

As a result, by comparing the two equations, we obtain, rate constant is k, and the [H2O2] concentration is 1 [H2O2].The concentration has doubled as a result. Afterward, the rate expression will be,

                           Rate = [H2O2] 2k.

As a result, we can infer that doubling the concentration will cause the reaction rate to double.

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Which of the following is NOT an
example of an installment loan?
A. a student loan
B. a car loan
C. a mortgage loan
D. a lump-sum loan

Answers

The answer is D. A lump-sum loan
The answer is d on edge

Students conducted a pendulum experiment to demonstrate the conservation of
energy principle. The diagram shows the pendulum at different points of its swing.
Which number(s) on the diagram would correspond to the point(s) of the pendulum's
swing with the least kinetic energy?

Students conducted a pendulum experiment to demonstrate the conservation ofenergy principle. The diagram

Answers

Answer:

1 and 5

Explanation:

Kinetic energy is the energy that an object possesses due to its motion. Since the pendulum has 0 velocity at points 1 and 5, and it is at those points that the pendulum is furthest from its equilibrium position, we say that it has no kinetic energy and maximum potential energy.

a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP

Answers

Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

\(KE_{initial} = PE_{final}\)

Plugging in:

\(\frac{1}{2}*30*5^2 = 30*9.8*h\)

Solving for h, we get 1.27551m

what is the physical state of gold at room temperature

Answers

Answer:

solid

Explanation:

Gold is a chemical element with symbol Au and atomic number 79. Classified as a transition metal, Gold is a solid at room temperature.

the resistance of the connecting wires in a series circuit is generally ? the resistance of the load.

Answers

My sister didn’t this it’s B my mom help

a) When we blow air with our mouth narrow open, we feel the air cool. When the mouth
is made wide open, we feel the air warm. What are the thermodynamic processes involved in these processes? Explain. [2]​

Answers

As the air is compressed, the work done on the air causes its temperature to increase.

What is Thermodynamic Process?

A thermodynamic process is a physical change that occurs in a system as it exchanges heat and/or work with its surroundings. It involves a change in one or more thermodynamic variables, such as temperature, pressure, volume, or entropy. There are four main types of thermodynamic processes: isothermal, adiabatic, isobaric, and isochoric.

When we blow air with our mouth narrow open, we feel the air cool because of the adiabatic expansion of the air. Adiabatic expansion is a thermodynamic process in which the air expands rapidly without losing or gaining any heat to or from the surroundings. As the air expands, it does work against the pressure of the surrounding atmosphere, and this work causes the temperature of the air to decrease. This is known as the Joule-Thomson effect.

On the other hand, when the mouth is made wide open, we feel the air warm because of the adiabatic compression of the air. Adiabatic compression is a thermodynamic process in which the air is compressed rapidly without losing or gaining any heat to or from the surroundings.

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in 1801, the italian astronomer giusseppe piazzi discovered a large, rocky body orbiting the sun. the body was surrounded by other similar rocky bodies that traveled in the same orbit. what did piazzi most likely discover?

Answers

In 1801, Italian astronomer Giuseppe Piazzi discovered a large, rocky body orbiting the sun, which he named Ceres.

This celestial object was found to be part of a group of similar rocky bodies traveling in the same orbit, known as the asteroid belt. The asteroid belt is located between the orbits of Mars and Jupiter and is comprised of numerous irregularly shaped objects, primarily composed of rock and metal. These objects, referred to as asteroids, vary in size and can range from a few meters to several hundred kilometers in diameter.

Piazzi's discovery of Ceres marked the first time an asteroid was identified and it subsequently led to the observation of many more objects within the asteroid belt. This region in our solar system has since become a subject of significant interest and study, as it provides valuable information on the formation and evolution of the solar system. Additionally, understanding the composition and characteristics of asteroids has practical implications, as it aids in predicting and mitigating potential threats posed by near-Earth objects.

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