A plane flying horizontally at an altitude of 1 mi and a speed of 510 mi/h passes directly over a radar station. find the rate at which the distance from the plane to the station is increasing when it is 2 mi away from the station.
Answers
The rate at which the distance from the plane to the station is increasing is 255(sqrt(3)) mi/h when the plane is 2 mi away from the station.
To solve this problem, we will use the Pythagorean theorem and related rates.
Let x be the horizontal distance from the radar station to the plane, y be the altitude of the plane, and z be the distance between the plane and the radar station. We are given that y = 1 mi and the speed of the plane is 510 mi/h. We want to find the rate at which z is increasing when z = 2 mi.
The Pythagorean theorem states that x^2 + y^2 = z^2. Differentiating both sides with respect to time t, we get:
2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)
Since the plane is flying horizontally and maintains a constant altitude, dy/dt = 0. We're given that dx/dt = 510 mi/h. Now, we need to find x when z = 2 mi. Using the Pythagorean theorem, we have:
x^2 + 1^2 = 2^2
x^2 = 3
x = sqrt(3)
Now, we can plug in the values for x, dx/dt, y, and z into the differentiated equation:
2(sqrt(3))(510) + 2(1)(0) = 2(2)(dz/dt)
Solving for dz/dt:
1020(sqrt(3)) = 4(dz/dt)
dz/dt = 255(sqrt(3)) mi/h
Thus, the rate at which the distance from the plane to the station is increasing is 255(sqrt(3)) mi/h when the plane is 2 mi away from the station.
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Related Questions
Please can you solve it?How to find the complete displacement of a body in this case:
Answers
calculating the area under the graph by dividing it
into a triangles and rectangles
A2 = 0.5 × h × b
= 0.5 × 10 × 5 = 25
A1 = 0.5 × 10 × 15 = 75
A4 = 0.5 × 15 × 10 = 75
A4 = h × b = 10 × 35 = 350
total displacement = 25 + 75 + 75 + 350 = 525
For the given circuit, ignoring ro but include substrate effect.
a. Identify the configuration
b. Find the small signal gain
C. For what value of Rs would the gain becomes maximum and what will be the value of maximum gain?
d. Find Rout.
Answers
The configuration of the given circuit is unspecified, making it impossible to identify its specific configuration or calculate small signal gain, maximum gain, or output resistance without additional information. configuration identification, small signal gain calculation, determining maximum gain, and finding the output resistance (Rout).
(a) The configuration of the given circuit is not specified in the question. To determine the configuration, more information or a diagram of the circuit is needed.
(b) Without knowing the configuration of the circuit, it is not possible to calculate the small signal gain. The small signal gain depends on the specific circuit configuration and the values of the components used.
(c) Similarly, without knowledge of the circuit configuration, it is not possible to determine the value of Rs at which the gain becomes maximum, nor the value of the maximum gain. These values would depend on the specific circuit design and the parameters of the components used.
(d) The output resistance (Rout) of the circuit cannot be determined without knowing the specific circuit configuration and the values of the components. The output resistance depends on the arrangement and characteristics of the components in the circuit.
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a cathode ray tube (crt) uses a stream of particles to create a spot on a screen. students are asked to design an experiment to show that the particles in the stream are charged and to determine the sign of the charge. which of the following procedures will best accomplish the objective of the experiment?
A. Bringing a neutral conducting rod near the stream to see if the stream Is deflected if so, observing the direction of the deflection B. Bringing a neutral conducting rod near the stream to see if the spot on the screen changes size if so, observing whether the size of the spot increases or decreases C. Bringing a wire with known current near the stream to see if the stream is deflected if so, observing the direction of the deflection D. Bringing a wire with known current near the stream to see if the spot on the screen changes size, if so observing the whether the size of the spot increases or decreases
Answers
To determine if the particles in the stream of a cathode ray tube (CRT) are charged and the sign of the charge, the best procedure would be bringing a wire with known current near the stream to see if the stream is deflected, if so, observing the direction of the deflection. The correct option is C.
This method allows you to see if the particles are charged by observing their reaction to the magnetic field created by the current-carrying wire. If the stream is deflected, it indicates that the particles are indeed charged.
Furthermore, the direction of the deflection can help determine the sign of the charge, as positively charged particles will deflect in one direction while negatively charged particles will deflect in the opposite direction due to the interaction between the magnetic field and the charged particles.
The procedure that would best accomplish the objective of the experiment, which is to demonstrate the presence and determine the sign of the charge on the particles in the stream of a cathode ray tube (CRT), is option C: bringing a wire with known current near the stream to observe its deflection.
In this scenario, the stream of particles in the CRT is presumed to be negatively charged electrons. When a wire with a known current is brought near the stream, the magnetic field generated by the current in the wire will interact with the charged particles in the stream.
According to the right-hand rule, the magnetic field will exert a force on the moving electrons perpendicular to both the direction of the current and the velocity of the electrons. This force will cause the stream of particles to deflect.
By observing the direction of the deflection, one can determine the sign of the charge on the particles. If the stream is deflected in one direction, it indicates that the particles in the stream are negatively charged. If the deflection is in the opposite direction, it suggests that the particles have a positive charge.
This allows students to conclude that the particles in the stream are indeed charged and determine the sign of that charge.
The other options (A, B, and D) do not directly address the objective of determining the sign of the charge on the particles. Option A focuses on deflection due to proximity to a neutral conducting rod, which does not provide information about the charge of the particles.
Option B considers changes in the size of the spot on the screen, which does not necessarily indicate the presence of charge. Option D explores changes in the spot size due to the current in a wire, but again, this does not directly address the sign of the charge on the particles in the stream.
The correct option is C. Bringing a wire with known current near the stream to see if the stream is deflected if so, observing the direction of the deflection.
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Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
Answers
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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Which wind blows 30 latitude in both hemisphere almost to the equator
Answers
Hope it help
Which best explains how Selena can correct her error? She can change the magnets so like poles are facing each other. She can change the arrows so they show current traveling in opposite directions on the sides of the loop. She can change the arrows so they show the magnetic field reversing direction between the magnets. She can change the magnetic poles so they are both on one side of the loop.
Answers
Complete question is;
Selena drew a diagram to show how current moves in a loop of wire that is placed between two magnets. At top left a piece of magnet labeled N and at top right a piece labeled S. Between these a square coil of wire with green arrows at its ends away from the magnets pointing away from the magnets. Red arrows point from N to S. Which best explains how Selena can correct her error?
A) She can change the magnets so like poles are facing each other.
B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.
C) She can change the arrows so they show the magnetic field reversing direction between the magnets.
D) She can change the magnetic poles so they are both on one side of the loop.
Answer:
B) She can change the arrows so they show current traveling in opposite directions on the sides of the loop.
Explanation:
Since the direction of the arrows point north and south whereas the magnets are east and west, it means the arrows are not pointing in the correct direction. To correct it she will have to make sure the arrows are pointing in opposite directions of the magnet via the sides of the loop.
Answer:
The answer is B
Explanation: Good luck on the test!
what is the probable source of the day-to-day variations in jupiter's belts and zones?
Answers
The probable source of the day-to-day variations in Jupiter's belts and zones is differential rotation and the underlying zonal flow.
Differential rotation is the phenomenon where different parts of a rotating object rotate at different speeds. In Jupiter's case, the equator rotates faster than the poles. This differential rotation causes the belts and zones to form.
The underlying zonal flow is a large-scale circulation pattern in Jupiter's atmosphere. This flow is caused by the planet's strong gravity and the heat generated by its core. The zonal flow helps to transport heat from the equator to the poles and also helps to maintain the belts and zones.
The day-to-day variations in Jupiter's belts and are caused by a combination of differential rotation and the underlying zonal flow. These variations can be caused by changes in the planet's temperature, pressure, and composition. They can also be caused by interactions with the planet's moons and other objects in the solar system.
The day-to-day variations in Jupiter's belts and zones are a fascinating phenomenon that scientists are still trying to understand. These variations provide us with clues about the planet's interior and atmosphere, and they help us to better understand the dynamics of giant planets.
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What is the mass of a skateboard that is accelerating at 7 m/s when it is pushed with 49N?
Pls
Answers
Answer:
m = 7 kg
Explanation:
F = m × a
49 = m × 7
7m = 49
m = 49/7
m = 7 kg
Calculate the reading on voltmeter v²
Answers
The reading of the voltmeter can be determined by finding the potential difference across the 2Ω resistance by using the value of current in the circuit. V=IR, here V is the potential difference across a resistance R through which a current I is flowing.
the question is in the screenshot
Answers
Answer:
Neglecting gravity, air resistance, etc
a)10m/s.
b)The stone is 5m above ground level after 0.50s.
Acceleration due to gravity on the surface of the moon=
Velocity/Time
distance/time/1.4
1.6/1.4^2
Approx 0.82m/s^2
A photon has a frequency of 223 mhz. What is the energy of this photon?.
Answers
The energy of a photon with a frequency of 223 MHz is 0.930 eV.
To determine the energy of a photon, we can use the equation:
\(E=hf\)
Where E is energy, h is Planck's constant, and f is frequency.
Substituting the given values into the equation:
E =\((6.626 * 10^{-34} J s)(223 * 10^6 Hz)\)
= 1.48 x 10^-26 J
Converting the energy to electron volts (eV) by using the conversion factor 1 eV =\(1.602 * 10^{-19} J:1.48 * 10^{-26} J * (1 eV / 1.602 * 10^{-19} J)\)
= 0.930 eV
Therefore, the energy of a photon with a frequency of 223 MHz is 0.930 eV.
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Select all the correct answers.
Which situations describe an elastic collision?
A. Two glass marbles bounce off each other.
B. Rodrick flops onto his sofa and sinks into the cushion.
C. A tossed water balloon flattens when it lands on the grass.
D. A bowling ball knocks over five pins.
Answers
Answer:
A and d
Explanation:
Answer:
answer in picture
Explanation:
A carrier wave is an electromagnetic wave that can be modulated, as in frequency, amplitude, or phase, to transmit speech, music, images, or other signals. True/False
Answers
True, a carrier wave is an electromagnetic wave that can be modulated in frequency, amplitude, or phase to transmit speech, music, images, or other signals.
Electromagnetic waves are invisible forms of energy that travel though the universe. However, you can "see" some of the results of this energy. The light that our eyes can see is actually part of the electromagnetic spectrum.
This modulation allows the carrier wave to carry information and transmit it over long distances.
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a positively charged insulated rod is brought near two neutral conducting spheres, a and b, which are touching each other and held in place and insulated from the rest of the environment. once the rod is close to (but not touching) sphere a, the spheres are separated from each other. sphere a is then suspended from a string, and the rod is brought near it again while sphere b is moved far away. sphere a is attracted to the rod. the investigation is repeated with a negatively charged rod, and the observed results are the same. which of the following best explains why the results are the same for a positively charged rod and a negatively charged rod?
Answers
The best explanation for why the results are the same for a positively charged rod and a negatively charged rod is that the charge on the spheres is redistributed to create opposite charges on the spheres.
The charge on the spheres is redistributed to create opposite charges on the spheres, which is why the results are the same for a positively charged rod and a negatively charged rod. This redistribution happens as a result of induction. As a result of the charge redistribution, the spheres develop an attraction to the rod. When a negatively charged rod is brought close to the spheres, the charge on the spheres is redistributed, causing one of the spheres to have a net positive charge and the other to have a net negative charge.
The sphere with the opposite charge (in this case, the one with a net positive charge) is attracted to the negatively charged rod, while the sphere with the same charge (in this case, the one with a net negative charge) is repelled. This redistribution results in the spheres separating from one other.When a positively charged rod is brought near the spheres, the same charge redistribution occurs, resulting in the same attraction between the oppositely charged sphere and the rod. Sphere B is far away, hence it does not undergo any charge redistribution as a result of the presence of the charged rod.
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A school classroom has six identical lamps. Each of the lamps is connected in parallel across a 220V mains supply. State the voltage across one of the lamps
Answers
The voltage across one of the lamps will be 220V. This is because when components are connected in parallel, the voltage across each component is the same as the voltage across the source.
What is voltage?Voltage is a measure of the potential difference in electrical energy between two points. It is measured in volts and is the electrical force that causes current to flow in an electrical circuit. Voltage is the energy per unit charge that causes a current to flow through a conductor. It can be compared to the pressure of water in a pipe, where the greater the pressure, the more water that can be pushed through the pipe. Voltage is the primary factor in determining the amount of electrical current that can be produced in an electrical circuit. Voltage is also related to the amount of power that can be produced in an electrical circuit. Voltage can be generated by a variety of sources, such as batteries, generators, and rectifiers.
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A train stops at two stations A and B. It accelerates from rest from station A to a speed of 144 km h^-1 in 3 minutes and maintains this speed for 10 minutes. It then decelerates for 2 minutes and comes to rest at station B. Find the total distance between A and B.
Show work please, really need the help.
Answers
Answer:
The total distance between A and B is 30 km
Explanation:
The given information are;
The time duration of the acceleration of the train from station A = 3 minutes = 0.05 hours
The speed attained by the train after the acceleration = 144 km/h
The time duration the train maintains the speed = 10 minutes = 0.1\(\bar 6\) hours
The time duration in which the train decelerates to station B = 2 minutes = 0.0\(\bar 3\) hours
The equation of motion required are;
The initial acceleration, a = (144 - 0)/0.05 = 2,880 km/h²
The distance covered, s = u·t + 1/2·a·t²
Where;
u The initial velocity = 0
∴ s₁ = 0 × 0.05 + 1/2 × 2880 × 0.05² = 3.6 km
s₁ = 3.6 km
The distance, s₂ the train covers at the constant speed 144 km/h for 10 minutes (1/6 hours) is given as follows;
s₂ = Velocity Time = 144 × 1/6 = 24 km
s₂ = 24 km
The deceleration, a₂ that brings the train to a stop in 2 minutes (1/30 hours) is given as follows;
a₂ = (0 - 144)/(1/30) = -4320 km/h²
The distance covered, s₃ by the train as it decelerates to rest from the initial constant speed is given as follows;
s₃ = u·t + 1/2·a·t²
Where;
u = The initial velocity =144 km/h
We have;
s₃ = 144×1/30 - 1/2 × 4320 × (1/30)² = 2.4
s₃ = 2.4 km
The total distance between A and B, s = s₁ + s₂ + s₃ = 3.6 + 24 + 2.4 = 30 km
The total distance between A and B = 30 km.
If you were making an electric device and needed a piece that would easily transmit an electric charge and also not react with other materials, what material would you choose?
Answers
Answer:
This question is incomplete
Explanation:
This question is incomplete because of the absence of options. However, one material that is good candidate for conducting electricity without reacting with other materials is metallic vanadium dioxide. This is because of the inability of this electrical conductor to conduct heat (an unusual property for all other electrical conductors) and thus makes it difficult for it to react with other materials (since an increase in temperature increases possibility of a reaction).
The impulse formula allows us to relate the concepts of mass and velocity (an objects momentum) to that of:
1: The motion of an object
2: An objects position in space
3: force acting on an object over time
4: the direction an object travels
Answers
Answer:
3: force acting on an object over time
Explanation:
The impulse formula is: change in momentum = force x time
Δp = f x t
A ray trace with a candle as the object at the center of curvature in front of a concave mirror with a light ray parallel to the principal axis and reflects through the focal point. The second ray goes through the focal point, reflects off the mirror parallel to the principal axis. Where the two rays intersect we find the image formed that is inverted and the same size of the object. The image is at the center of curvature. Which describe the image formed by an object on the center of curvature? Check all that apply. Real virtual inverted upright smaller larger.
Answers
When an object is placed on the center of curvature of a concave mirror, the image formed has certain characteristics. It is a real image, meaning it can be projected onto a screen. So, the correct options are: 1 and 3
The image is inverted, meaning it appears upside down compared to the object. However, the image is not larger or smaller than the object; it is the same size. Additionally, the image is not upright. This arrangement occurs because the light rays from the object when reflected by the mirror, converge at a point on the center of curvature. As a result, an inverted, real image of the same size as the object is formed. Therefore options 1 and 3 are correct.
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--The complete Question is, A ray trace with a candle as the object at the center of curvature in front of a concave mirror with a light ray parallel to the principal axis and reflects through the focal point. The second ray goes through the focal point, reflects off the mirror parallel to the principal axis. Where the two rays intersect we find the image formed that is inverted and the same size of the object. The image is at the center of curvature. Which describe the image formed by an object on the center of curvature? Check all that apply.
1. Real
2. virtual
3. inverted
4. upright
5. smaller
6. larger.--
Answer:
1 and 3 see picture
Explanation:
12) Driving home from school one day, you spot a ball rolling out into the street (FIGURE 5-27). You brake for 1.20 s, slowing your 950-kg car from 16.0 m>s to 9.50 m>s. What was the average forceexerted on your car during braking and How far did you travel while braking?
Answers
We are given the following information
Mass of car = 950 kg
Initial speed of car = 16.0 m/s
Final speed of car = 9.50 m/s
Time = 1.20 s
The average force exerted on the car during braking can be found using Newton's 2nd law of motion
\(F=m\cdot a\)Where m is the mass of the car and a is the acceleration of the car.
The acceleration of the car is given by
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ a=\frac{9.50-16.0}{1.20} \\ a=-5.4167\; \; \frac{m}{s^2} \end{gathered}\)The negative sign indicates deacceleration since the car is stopping.
So, the force is
\(\begin{gathered} F=m\cdot a \\ F=950\cdot5.4167 \\ F=5145.865\; \; N \end{gathered}\)Therefore, an average force of 5145.865 N was exerted on your car during braking.
The distance traveled by the car while braking can be found as
\(s=v_i\cdot t+\frac{1}{2}\cdot a\cdot t^2\)Let us substitute the given values
\(\begin{gathered} s=16.0\cdot1.20+\frac{1}{2}\cdot(-5.4167)\cdot(1.20)^2 \\ s=19.20-3.90 \\ s=15.3\; m \end{gathered}\)Therefore, the car traveled a distance of 15.3 m while braking.
A mass is dropped from a height h above the ground, and freely falls under the influence of gravity. Which graphs here correctly describes the displacement and velocity of the object during the time the object is falling? Consider the "up" direction to be positive.
Which graph is it?
Answers
Answer:
B
Explanation:
The only force acting on the block is gravity, so the block has a constant, negative acceleration. This means the velocity of the block is decreasing at a constant rate, so the answer is B, D, or E. Velocity is the rate of change of displacement, and answer choice B is the only one that has a displacement graph that matches that idea.
Answer: Graph B here correctly describes the displacement and velocity of the object during the time the object is falling. Option B is correct.
It is given that the mass of an object is dropped from height 'h' above the ground and "up" direction is taken to be positive.
It is required to find the graph which describes the displacement and velocity of the object during the time the object is falling.
Which graphs here correctly describes the displacement and velocity of the object during the time the object is falling?If any body falls freely towards the ground, then its acceleration is decreasing constantly with respect to time. That means velocity of an object will also be decreased as shown in graph B. Also we know that velocity is the rate of change of displacement.
As it is given in question that up direction is positive then it is also considered that downward be negative means decreasing.
Therefore, both the quantities are decreasing. So graph B correctly describes the displacement and velocity of the object during the time the object is falling.
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Which of the following are true statements about the graph below? (choose 2)
The wavelength of the wave is decreasing as time goes on.
The frequency is decreasing as time goes on.
Something is damping the wave.
The amplitude of the wave is decreasing as time goes on.
Answers
Answer:
The amplitude of the wave is decreasing with time.
Something is damping the wave (the amplitude is decreasing with time)
Explanation:
The amplitde is measdured in the +/- y direction. Certainly you can observe that it is changing.
A damped wave is one whose vertical disdtance keeps going down until it is almost a straight line. Smething is causing that. The phenomenon is called damping.
So the answer is the last two. (c and d)
The frequency is measured on the x axis. If the distance between waves changes, then the frequency changes. Wavelength is also measured on the x axis. If the distance occupied by 2 consecutive waves changes , then the wave length changes.
A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is the object's change in momentum?
Answers
Answer:
60 kg m/s
Explanation:
Let \(a\;\; m/s^2\) be the acceleration of the object.
As the acceleration of the object is constant, so
\(a=\frac {v-u}{t}\cdots(i)\)
Given that applied force, F=6.00 N,
From Newton's second law, we have
\(F= m\times a\),
\(\Rightarrow F=\frac {m(v-u)}{t}\) [from equation (i)]
\(\Rightarrow Ft=m(v-u)\)
\(\Rightarrow Ft=mv-mu\)
\(\Rightarrow mv-mu=6\times 10\) [given that time, t=10 s and F=6 N]
\(\Rightarrow mv-mu=60 kg \;m/s\)
Here mv is the final momentum of the object and mu is the initial momentum of the object.
So, the change in the momentum of the object is mv-mu.
Hence, the change in the momentum of the object is 60 kg m/s.
The change in momentum of object is 60 kg-m/s.
Given data:
The magnitude of force is, F = 6.00 N.
The mass of object is, m = 3.00 kg.
The speed of object is, v = 15.0 m/s.
The time interval is, t = 10.0 s.
The change in momentum is mathematically equal to the difference between the final momentum and initial momentum of object. And it is obtained from the impulse-momentum concept as,
\(F=\dfrac{\Delta p}{t}\\\\\Delta p = F \times t\)
Solving as,
\(\Delta p = 6.00 \times 10\\\\\Delta p =60.0 \;\rm kg.m/s\)
Thus, we can say that the change in momentum of object is 60 kg-m/s.
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A proper cool-down
O increases the heart-rate
O makes muscles cold
O helps prevent fainting or dizziness
none are correct
Answers
Answer:
Option D (none are correct) is the appropriate solution.
Explanation:
After yet another workout, a cool or calming down allows the breathing as well as pulse rate to recover more quickly. It will also assist to eliminate the lactic acid build-up during the exercise, eventually increasing the muscle soreness with delayed onset. Wind yourself off for 5 to 10 minutes by taking public transportation a stationary bicycle.Some other three scenarios do not correspond to something like the situation described. So, this same correct decision is the one above.
Types of media that can influence one's social development include all of the following except
A. movies
B. Internet
C. books
D. traditions
Please select the best answer from the choices provided
Answers
Answer:
the answer is D
Explanation:
A) Millions of years of rain and wind
B) Millions of years of high pressure and temperatures
C) Processing in a factory
D) Millions of years of erosion
Answers
Answer:
B. Millions of years of high pressure and temperature.
Millions of years of high pressure and temperature the ancient forests turn into fossil fuels.Explanation:
Fossil fuels were formed from the dead remains of living organisms millions of years ago. They were formed under high pressure and high temperature.
Coal : about 300 million years ago the earth had this forest in low lying wetland areas. Due to natural processes like flooding, these forest god buried under the soil. As more soil deposited over them, they were compressed. Under high pressure and high temperature, dead plants got slowly converted into coal. Petroleum : Petroleum was formed from organisms living in the sea. As these organisms died, their bodies settled at the bottom of the sea and got covered with layers of soil and clay. Over millions of years, absence of air, high pressure and high temperature transformed the dead organisms into Petroleum.Coal, Petroleum and natural gas are fossil fuels.
in a fluorescent tube of diameter 3 cm, 6 times 1018 electrons and 1.5 times 1018 positive ions (with a charge of e) flow through a cross-sectional area each second. what is the current in the tube?
Answers
The current in the tube would be \(3.825 \times 10^{-5} A\).
The given diameter of the fluorescent tube is 3 cm. We need to find the current in the tube.
The total charge flowing through the cross-sectional area of the tube each second is:
charge = total charge/time
charge = \((6 \times 10^{18} - 1.5 \times 10^{18}) \times 1.6 \times 10^{-19} = 7.2 \times 10^{-1} C\)
Time = 1 s
Here, we have taken the charge of an electron as negative and the charge of a positive ion as positive.
Substitute the given values in the formula:
\(I = Q/t\)
\(I = (7.2 \times 10^{-1})/1\)
I = 0.72 A
Therefore, the current in the tube is 0.72 A.
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Look at the velocity versus time graph below. What is the magnitude of the
displacement of the object after it travels for seven seconds?
Velocity (m/s)
Time (s)
OA. 28 m
B. 26 m
OC. 30 m
OD. 24 m
Answers
The magnitude of the displacement of the object after it travelled for seven seconds is 28 m (Option A).
What is displacement?The displacement of an object is the change in the position of the object.
Velocity = displacement / time
How to determine the displacement from the velocity - time graph;
From the question given above, the following data were obtained:
Time = 7 s
Velocity = 4 m/s
Displacement =?
Velocity = displacement / time
4 = displacement / 7
Cross multiply
Displacement = 4 × 7
Displacement = 28 m
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11) Stored energy is called ________ energy.
12) When you move your hand or foot, your body has converted potential energy into ________ energy.
13) When coasting while roller skating, you eventually stop due to ________.
14) A ball has 100 J of potential energy when it is on a shelf. The kinetic energy of the ball the instant it hits the floor is ________J.
Answers
electrofeiod force of 2x10-2 is extertwd on a charge of 4 columbs at point p in magniute of the electro field intesty at p
Answers
The magnitude of the electric field intensity at point P is 5x10^(-3) N/C.
To determine the magnitude of the electric field intensity at point P, we need to use the formula:
Electric field intensity (E) = Electric force (F) / Charge (q)
Given that the electric force exerted on the charge is 2x10^(-2) N (Newtons), and the charge is 4 C (Coulombs), we can substitute these values into the formula:
E = (2x10^(-2) N) / (4 C)
Simplifying the equation gives us:
E = 5x10^(-3) N/C
The electric field intensity represents the force experienced by a unit positive charge at a given point in an electric field. In this case, the magnitude of the electric field intensity is 5x10^(-3) N/C, indicating that a positive charge placed at point P would experience a force of 5x10^(-3) Newtons per Coulomb in the direction of the electric field.
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