Answer:
6858.5712 m/s
Explanation:
Given that:
Radius, r
R = 3.20 * 10^3.
Normal force = 0.5 * normal weight
Normal force = Fn ; Normal weight = Fg
Fn = 0.5Fg
Recall:
mv² / R = Fn + Fg
Fn = 0.5Fg
mv² / R = 0.5Fg + Fg
mv² /R = 1.5Fg
mv² = 1.5Fg * R
F = mg
mv² = 1.5* mg * R
v² = 1.5gR
v = sqrt(1.5gR)
V = sqrt(1.5 * 9.8 * 3.2 * 10^3)
V = sqrt(47.04^3)
V = 6858.5712 m/s
A roller coaster car is going over the top of a 15-m-radius circular rise. The passenger in the roller coaster has a true weight of 600 N (therefore a mass of 61.2 kg). At the top of the hill, the passengers "feel light," with an apparent weight of only 360 N. How fast is the coaster moving
Answer:
v = 7.67 m/s
Explanation:
The equation for apparent weight in the situation of weightlessness is given as:
Apparent Weight = m(g - a)
where,
Apparent Weight = 360 N
m = mass passenger = 61.2 kg
a = acceleration of roller coaster
g = acceleration due to gravity = 9.8 m/s²
Therefore,
360 N = (61.2 kg)(9.8 m/s² - a)
9.8 m/s² - a = 360 N/61.2 kg
a = 9.8 m/s² - 5.88 m/s²
a = 3.92 m/s²
Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:
a = v²/r
where,
a = centripetal acceleration = 3.92 m/s²
v = speed of roller coaster = ?
r = radius of circular rise = 15 m
Therefore,
3.92 m/s² = v²/15 m
v² = (3.92 m.s²)(15 m)
v = √(58.8 m²/s²)
v = 7.67 m/s
(Ch 20 Vocab and Review)
Name 2 wave interactions that can occur when a wave encounters a barrier. (Ch 20 Vocab and Review)
Answer:
Reflection and diffraction
Explanation:
Reflection involves a change in direction of waves when they bounce off a barrier; refraction of waves involves a change in the direction of waves as they pass from one medium to another; and diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path.Diffraction refers to various phenomena that occur when a wave encounters an obstacle or opening. It is defined as the bending of waves around the corners of an obstacle or through an aperture into the region of geometrical shadow of the obstacle/aperture.
Why is it better to use the metric system, rather than the English system, in scientific measurement?
A. The English system uses one unit for each category of measurement.
B. The metric system uses one unit for each category of measurement.
C. The English system uses consistent fractions that are multiples of 10.
D. The metric system utilizes a variety of number conversions.
A. The English system uses one unit for each category of measurement.
Answer:
A
Explanation:
What are the units of momentum?O kg m/sON/sO kg m/s^2O impulses
kg m/s
Explanation
Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it movin, it is the product of the mass of a particle and its velocity
\(\begin{gathered} \rho=mv \\ where\text{ } \\ \rho\text{ is the momemtum } \\ m\text{ is the mass } \\ v\text{ is the velocity} \end{gathered}\)on the SI systems the untis would be
\(\begin{gathered} mass\text{ \lparen kg\rparen} \\ velocity(\frac{m}{s}) \end{gathered}\)so, replacing
\(\begin{gathered} \rho= mv \\ \rho=kg*\frac{m}{s} \\ kg*\frac{m}{s} \end{gathered}\)therefore, the answer is
kg m/s
I hope this helps you
Describe Fleming’s left hand rule with the aid of a drawing
The left hand rule or Fleming's rule is a law used in electromagnetism that determines the movement of a conductor that is immersed in a magnetic field or the direction in which the force is generated within it.
In a conductor that is inside a magnetic field perpendicular to it and through which a current is circulated, a force is created whose direction will depend on how both magnitudes interact. This force that appears as a result is called the Lorentz force. To obtain the direction of the force, take the index finger of the left hand pointing to the direction of the magnetic field that interacts with the conductor and point the middle finger in the direction of the current flowing through the conductor, forming an angle of 90 degrees. In this way, the thumb determines the direction of the force that driver will experience.
Conventions:
* The direction of the mechanical force points the same as the finger.
*The direction of the magnetic field is from north to south.
*The current flows in the conventional direction, that is, from positive to negative.
the mass of the velociraptor and cage together is 175 kg. What is the gravitational potential energy added when when the velociraptor and cage is lifted from the ground to a height of 9 m?
The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.
What is Potential Energy?
Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.
The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:
GPE = mgh
Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.
Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:
GPE = mgh
GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)
GPE = 15,998.95 J (joules)
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PLEASE HELP !!!!!!! Fastttt !!!!!!!!! You are using a flashlight to find your phone in the dark but the light isn’t bright enough. You turn up the brightness of the light so that you can better see. What part of the light wave are you changing? Why?
Answer:
The part of the wave is the Amplitude.
Reason: The amplitude of light waves is responsible for our perception of brightness, with larger amplitudes appearing brighter than lower amplitudes.
Explanation:
The amplitude of light waves is responsible for our perception of brightness, with larger amplitudes appearing brighter than lower amplitudes.
Thus, when you turn up the brightness of the light so that you can better see, you are increasing the amplitude of the light wave, which in turn increases the intensity of the light, seen from the increased brightness of the flash light.
what is the work done on the box from x = 0m to 16m
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
How much work will be done by electric energy source with a P.d of 4KV that delivers a current of 1 A for 1 minute?
Answer:
Given that battery V = 12.0 V
Resistance R = 2.0 ohms
a ) current in the battery is I = V /R
= 12.0 V / 2.0
= 6.0 A
b ) charge transported in the circuit is q = i * t
= 6.0 A * 10 s
= 60 C
c ) Work done on the charge by the electric field is 0 ( there is no internal resistance )
d ) work done through the resistor is w = P * t
= ( V)^2 / R * t
= ( 12.0 V )^2 / 2 *10s
= 720J
e ) Total work done is equal to work done through the resistor
W_total = 720 J
f ) there is no internal resistance hence E = 0
Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.
Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.
The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.
These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.
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Both carts start from rest, their change in momentum will be equal to their final momentum. according to newton's second law, the same force applied to the two carts results in for the plastic cart compared to the lead cart, which means the plastic cart will travel the distance of 1 m in time interval compared to the lead cart. therefore, from the momentum principle the plastic cart will have final momentum, compared to the lead cart.
The impulses and changes in momentum are identical because equal forces are applied over equal periods of time.
The momenta of the two carts are identical since they both begin at rest and experience equal changes in momentum. We are aware that force is the same as mass multiplied by acceleration. Due to the initial resting state of both carts, u = 0 m/s, and the plastic cart moves 1 m. Newton's second law states that when the same force is applied to the two carts, the plastic cart will have more final momentum than the lead cart because of the momentum principle. Newton's third law states that every object feels the same force for the same length of time, which results in the same impulse and consequent change in momentum.
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Due to equivalent forces being delivered over equal times, the impulses and changes in momentum are identical.
What occurs to the cart's acceleration when the force being applied to it is doubled?The acceleration is determined by dividing the net force by the mass. An object's acceleration doubles if the net force exerted on it also doubles. Increased mass will result in a halving of acceleration.
What is the second law of Newton?Second Law of Motion: Force In accordance with his second law, a force is defined as the change in momentum (mass times velocity) per change in time. The definition of momentum is the product of the mass m and the velocity V of an object.
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A car starts from rest with constant acceleration achieves a velocity 15m/s when it travels a distance of 200m. Determine its acceleration and the time required.
3.7996 seconds are needed to accelerate it.
How does acceleration work?acceleration is the rate of change in both speed and direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is always shifting, motion on a circle accelerates even while the speed is constant.
So we have u= 0m/s, v=15m/s, s= 200m
So,2as= v^2-u^2
A= V^2 - U^2/2s
= 225/400
=0.5625 m/s^2
V=u + a*(t^2)
15=0+0.5625(t^2)
15-0.5625= t^2
=14.4375=t^2
root14.4375= root(t)
Time= 3.7996 seconds
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50 POINTS WILL MARK BRAINLIEST!!!!
Choose a scientist from the timeline on the previous page. Conduct research using outside sources. Be sure to choose reliable resources such as government, scientific, and educational websites. Document all research in your own words. Be sure to properly site all resources used in your assignment.
Research and respond to the following: The person is Neil Bohr
Were there experiences in his life that led to his interest in science and the study of the atom?
Defend his work on the atom and its contribution to the modern atomic model.
Point out which contributions are present in the modern atomic model and which were eventually disproven and thus are not part of the modern model.
Neil Bohr works on atomic model and contributes semi-classical model of an atom.
What is Bohr's model of an atom?Neil Bohr put forth the Bohr model of the atom in 1915. It was created by the modification of Rutherford's atomic model.
By explaining that electrons move in fixed orbitals (shells) and not anywhere in between, Bohr theory amended the atomic structure model. He also showed that each orbit (shell) has a fixed energy. Bohr refined Rutherford's model of the atom's nucleus to include electrons and their varying energy levels.
In Bohr's theory, there is a tiny, positively charged nucleus that is surrounded by negatively charged electrons that orbit the nucleus. According to Bohr, an electron that is farther from the nucleus has more energy than one that is closer to it.
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A sole owner (without employees) of a contracting firm was performing maintenance and repair
work for a cork processing company.
He was working on the motor for a Nu Vac 480-volt, 14.9-kilowatt pneumatic roof-mounted
conveyor system. He found the motor to be running roughly. As he was examining it, the motor
tripped the electric starter.
He went to the electrical room on the third floor of the building to open the Square D 60-ampere,
standard-duty disconnect switch rated at 600 volts. An explosion and electrical fault occurred,
involving not only the switch but also a portion of the surrounding electric equipment.
The ensuing electric arc burned the contractor. He was hospitalized with first- and second-degree
burns to his right hand and arm and his face.
The company processed cork, including grinding, sifting, and blending cork. Because of
inadequate housekeeping, combustible cork dust was present throughout the electrical room. The
open-type electric equipment was unsuitable for use in Class II, Division 1 or 2 locations.
What procedures and policies could have been put in place to prevent this injury?
The situation shown in the scenario reveals a number of safety flaws that may have been avoided with the use of appropriate protocols and guidelines.
What is switch?A switch is a tool used in electrical engineering and electronics to open or close an electrical circuit to permit or restrict the flow of current. From basic mechanical switches to complex electronic switches that are employed in contemporary electronic devices, switches come in a variety of sorts and designs.
These are some suggestions for practices and regulations that may have been implemented to stop the injury:
Identification and evaluation of hazards: The cork processing business had to have carried out a hazard analysis to find any potential dangers in the electrical room, such as the existence of combustible cork dust. The risk of electrical arcs and fires brought on by the buildup of dust and other debris ought to have been considered throughout the assessment.
Cleaning and housekeeping: To prevent the buildup of combustible dust and other material in the electrical room, the company should have instituted a regular cleaning and housekeeping program.
Equipment selection: It is inappropriate and unsafe to employ open-type electrical equipment in a Class II, Division 1 or 2 area. Equipment suited for usage in hazardous environments and rated for the particular circumstances present in the electrical room should have been chosen and installed by the company.
Frequent inspection and maintenance of electrical equipment can assist find possible safety concerns before they become life-threatening. Before attempting to start it up, the contractor had to have checked the electrical components and the motor.
Lockout/tagout procedures: To prevent unexpected equipment activation during maintenance or repair operations, the business should have put in place a lockout/tagout policy.
All staff working in the electrical room should have received training on the risks connected with electrical equipment and the best practices for working safely in a dangerous environment. Training also includes supervision. The business was responsible for providing the necessary oversight to guarantee that the protocols were being followed.
Personal protective equipment: To guard against burns from electrical arcs and explosions, the contractor should have been given the proper personal protective equipment, such as gloves, eye protection, and clothes.
The company may have decreased the risk of injury and produced a safer working environment for the contractor and other employees by putting these processes and policies into place.
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A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 149 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 83.5 cm, what was the speed of the bullet at impact with the block
you know,dinner is taking,like,forever to cook,and i'm sterving
Answer:
OK?
Explanation:
Answer:
It happens and they might not even cook what you feel like eating.
10. What is GIVEN in the following problem? *
1 point
If Maria was driving her car at 20 km/h, then increased her speed to 35 km/h, what is her change in velocity?
Given
Want
Formula
Work
v1 = 20 km/h, v2 = 35 km/h
Change in velocity, \(\Delta v\), is the initial velocity subtracted from the final velocity. \(\Delta v = v_{2} - v_{1} = 35 - 20 = 15kmh^{-1}\)
The change in the velocity of Maria's car is equal to 15 Km/h.
What is the velocity?Velocity can be defined as a vector measurement of the rate of motion and direction of an object. The velocity of an object can be defined as the rate of change in the position of the body with respect to time.
Velocity can be defined as a vector parameter as it exhibits both magnitude and direction. A mathematical formula to calculate the velocity of the object can be represented as:
v = d / t
Where v is the velocity of the object, d is the distance, and t is the time taken by the object.
Although the S.I. unit for the measurement of the velocity is m/s and can also expressed in the terms of miles per hour (mph), and kilometers per hour(kph).
Given, the initial velocity of Maria's car, v₁ = 20 m/s
The final velocity of Maria's car, v₂ = 35 m/s
The change in the velocity of Maria's car, Δv = v₂ - v
Δv = = 35 - 20
Δv = 15 km/h
Therefore, the change in velocity is 15 Km/h.
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Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
To make a given sound seem twice as loud, how should a musician change the intensity of the sound?
A. Double the intensity
B. Halve the intensity
C. Quadruple the intensity
D. Quarter the intensity
E. Increase the intensity by factor
Answer:
C. Quadruple the intensity
Explanation:
The intensity of the sound is proportional to square of amplitude of the sound.
I ∝ A²
\(\frac{I_1}{A_1^2} = \frac{I_2}{A_2^2}\\\\I_2 = \frac{I_1A_2^2}{A_1^2}\)
When the given sound is twice loud as the initial value, then the new amplitude is twice the former.
A₂ = 2A₁
\(I_2 = \frac{I_1A_2^2}{A_1^2} \\\\I_2 = \frac{I_1(2A_1)^2}{A_1^2} \\\\I_2 = \frac{4I_1A_1^2}{A_1^2}\\\\ I_2 = 4I_1\)
Thus, to make a given sound seem twice as loud, the musician should Quadruple the intensity
Abus has velocity 20m/s towards east and another bus has velocity 15m/s
in west direction. If they start to move from a point simultaneously, what
distances do they cover in 2 minute? What will be their separation?
Answer:
Distances covered by each bus 1800 [m] & 2400 [m]
The separation = 4200 [m]
Explanation:
To solve this problem, a kinematics study should be carried out, where the movements of both buses in opposite directions are analyzed and, at the end, logically add the possible values obtained.
The time in seconds 2 [min] = 120 [s]
For the bus moving towards west:
x = - 15* 120 = - 1800 [m]
For the bus moving towards east:
x = 20* 120 = 2400 [m]
The separation is easily calculated as the arithmetic sum of both displacements, the negative sign of the bus moving westward, represents only a movement opposite the other bus.
Separation = 1800 + 2400 = 4200 [m]
When tectonic plates converge, they are most likely to form....
Answer:
Explanation : if two tectonic plates collide, they form a convergent plate boundary. Usually, one of the converging plates will move beneath the other, a process known as subduction. Deep trenches are features often formed where tectonic plates are being subducted and earthquakes are common.
Answer:
a trench
Explanation:
What are some things that the outer planets have in common?
Answer:
there round that's one thing
Answer:
large size, number of moons, lack solid surfaces and none are capable of supporting life.
Explanation:
You see a boat sitting at the end of a dock. Ten minutes later you see the same boat in a cove to the right of the dock. You did not see the boat move.
However, you know that the boat moved because its
relative to the dock changed.
The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .
Everything is always in motion, but the way we perceive it depends on our frame of reference.
In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.
It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.
In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.
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Someone help ASAP please (right answers only)
Cuban tree frogs are skilled jumpers. They can launch themselves at 4.5 meters per second at an angle of 25° above horizontal. Assuming the frog is jumping on level ground, how far will the frog travel in a single jump, what is the frog’s hang time in the air during a single jump, and what is the maximum height above the ground that the frog will achieve?
The maximum height reached by the frog is 0.185 m.
What is the maximum height reached by frog?
The maximum height reached by the frog is calculated by applying the following kinematic equation.
H = u² sin²θ / 2g
where;
u is the initial velocity 4.5 m/sθ is the angle of projectiong is acceleration due to gravityH = (4.5² x (sin 25)²) / (2 x 9.8)
H = 0.185 m
Thus, the maximum height reached by the frog depends on the initial velocity and angle of the frog's projection.
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A 3.0kg weight W is initially at rest on incline AB, which is raised 40° above the horizontal. The effective coefficient is
mu = 0.3 . Through frictionless pulley and strings of negligible mass, a small mass P, 400g, is at rest on a 200g weighting pan.
Draw a free body diagram representing the situation, and use it to determine the acceleration of the system. Use the value of acceleration calculated to determine the relative weight of P in pounds.
(a) The acceleration of the system is determined as 1.58 m/s².
(b) The relative weight of P is pounds is determined as 0.14 lb.
Acceleration of the system
The acceleration of the system is calculated as follows;
W - T = m₂a --- (1)
T = m₁a ----(2)
μmgsinθ - m₁a = m₂a
(0.3 x 3 x 9.8 x sin40) - (0.4 + 0.2)a = 3a
5.67 - 0.6a = 3a
5.67 = 3.6a
a = 5.67/3.6
a = 1.58 m/s²
Relative Weight of PW = ma
W = 0.4 x 1.58
W = 0.632 N = 0.14 lb
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QUESTION 3 (Start on a new page.)
A small disc, C, is thrown vertically upwards at a speed of 15 m-s¹ from the edge of
the roof of a building of height 30 m. AFTER 0,5 s, a small ball B is shot vertically
upwards from the foot of the building at a speed of 40 m-s in order to hit disc C.
Ignore the effects of air resistance.
3.1
3.2
3.3
15 m-s¹
30 m
Explain the term projectile.
Calculate the:
40 m-s¹
B
3.2.1
Time taken by disc C to reach its maximum height
3.2.2
Maximum height above the ground reached by disc C
Calculate the time from the moment that disc C was thrown upwards until
the time ball B hits the disc..
(2)
(3)
(4)
(6)
A projectile is an object thrown into the air and subject only to gravity and, if applicable, air resistance. The time taken by disc C to reach its maximum height is approximately 1.53 seconds, and its maximum height above the ground is around 11.48 meters. The time from when disc C was thrown upwards until ball B hits the disc is roughly 1.29 seconds.
3.1 Explanation of the term projectile:
A projectile refers to an object that is launched or thrown into the air and is subject only to the forces of gravity and air resistance (if applicable). The motion of a projectile can be analyzed independently of its mass, shape, or any other physical property. The key characteristic of a projectile is that it follows a curved path known as a trajectory.
When a projectile is launched, it moves along a parabolic trajectory due to the combination of its initial velocity and the force of gravity acting vertically downward. The horizontal motion of a projectile remains constant and unaffected by gravity, while the vertical motion is influenced by the acceleration due to gravity.
The path of a projectile can be described mathematically by considering its initial velocity, angle of projection, and the acceleration due to gravity. Projectile motion finds applications in various fields, such as sports, engineering, and physics, where objects are launched or thrown.
3.2.1 Time taken by disc C to reach its maximum height:
To determine the time taken by disc C to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:
vf = vi + at
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
t = time
Since the disc is thrown vertically upwards, its initial velocity is 15 m/s. We want to find the time it takes for the disc to reach its maximum height, so we'll use the equation and solve for time (t):
0 = 15 + (-9.8)t
Rearranging the equation, we get:
9.8t = 15
t = 15 / 9.8
Calculating this, we find:
t ≈ 1.53 seconds
Therefore, it takes approximately 1.53 seconds for disc C to reach its maximum height.
3.2.2 Maximum height above the ground reached by disc C:
To determine the maximum height reached by disc C, we can use another kinematic equation for vertical motion:
vf² = vi² + 2ad
Where:
vf = final velocity (which is zero at the maximum height)
vi = initial velocity
a = acceleration (in this case, acceleration due to gravity, -9.8 m/s²)
d = displacement (maximum height)
Since we know the initial velocity (vi) and acceleration (a), we can solve for the displacement (d), which represents the maximum height:
0² = 15² + 2(-9.8)d
Rearranging the equation, we get:
0 = 225 - 19.6d
19.6d = 225
d = 225 / 19.6
Calculating this, we find:
d ≈ 11.48 meters
Therefore, the disc C reaches a maximum height of approximately 11.48 meters above the ground.
Calculating the time from the moment that disc C was thrown upwards until the time ball B hits the disc:
To find the time it takes for ball B to hit disc C, we need to calculate the time it takes for both objects to reach the same height.
Since disc C was thrown upwards from the edge of the roof and ball B was shot vertically upwards from the foot of the building, we need to consider the additional height of the building (30 meters).
The time it takes for disc C to reach the ground is the same as the time it takes for ball B to reach a height of 30 meters above the ground.
Using the kinematic equation for vertical motion, we can calculate the time for ball B:
d = vit + 0.5at²
Where:
d = displacement (30 meters)
vi = initial velocity (40 m/s)
a = acceleration (acceleration due to gravity, -9.8 m/s²)
t = time
30 = 40t + 0.5(-9.8)t²
Rearranging the equation, we get:
4.9t² + 40t - 30 = 0
Solving this quadratic equation, we find:
t ≈ 1.29 seconds or t ≈ -5.82 seconds
Since time cannot be negative in this context, we discard the negative solution.
Therefore, it takes approximately 1.29 seconds from the moment that disc C was thrown upwards until ball B hits the disc.
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If a person steps on a scale in an elevator that is accelerating at a rate -1.100 m/s^2 (negative means downward while positive means upwards) and sees a scale reading of 598.900 Newtons what would the scale read if the elevator were not moving?
answer with correct units
Answer:
Explanation:
When the elevator is accelerating downwards, the apparent weight of the person is reduced, and when the elevator is accelerating upwards, the apparent weight is increased.
First, we need to determine the actual weight of the person. We can do this by using the formula:
Weight = mass x gravity
where mass is the mass of the person and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.
Weight = (598.900 N) / (9.81 m/s^2) = 61.048 kg
Now, when the elevator is not moving, the person is only experiencing the force due to gravity, which is:
Weight = mass x gravity = (61.048 kg) x (9.81 m/s^2) = 598.78 N
Therefore, the scale would read approximately 598.78 Newtons when the elevator is not moving.
Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is 1.65 ✕ 105 Pa and the pipe radius is 2.50 cm. At the higher point located at y = 2.50 m, the pressure is 1.22 ✕ 105 Pa and the pipe radius is 1.60 cm. Find the speed of flow in the lower section.
(b) Find the speed of flow in the upper section.
m/s
(c) Find the volume flow rate through the pipe.
m3/s
The negative outcome indicates a flaw in the information provided or how the issue was put up because the flow rate cannot be fictional or negative.
Calculation-It can be expressed as:
P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2
the terms involving h cancel out in the equation, and we can solve for v1:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
v1 = √(P2 - P1))/ρ)
Substituting the given values for P1, P2, and ρ into the equation,
\(v1 = \sqrt(1.22 x 10^5 - 1.65 x 10^5))/1000) = \sqrt(-0.43)\)
B) The same formula (v2) may be used to get the flow rate in the top part.
v2 = sqrt((2(P1 - P2))/ρ)
\(v2 = \sqrt{2} (1.65 x 10^5 - 1.22 x 10^5))/1000) =\sqrt(0.86) ≈ 0.93 m/s\)
C) The following formula may be used to get the volume flow rate (Q) via the pipe:
Q = Av
A1 = πr1\(1^{2}\); at point 2, the cross-sectional area A2 = πr\(2^2\).
we get:
Q = A1v1 = πr1^2v1
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Describe the difference between distance and displacement.
Distance:
It is the measure of length that is the actual path traveled by a particle.
Distance depends upon the path traveled by the particle from the initial to the final point.
The distance measured for a particle is always positive.
Displacement:
It is the measure of the shortest distance between initial and final points.
Displacement is not dependent on the path but depends only on the shortest distance between initial and final points.
The displacement of a particle can either be positive, negative, or zero.
Calculate the speed of an object that travels 75m in 15s.