A person has a weight of 500N on earth, based on this ..- If the person moves from the ground level to a position high up on a mountain, how will this affect the gravitational force between him and the earth?- What is accelerating towards the other, The Earth or the Person?

Answer:

photosynthesis, burning fossil fuels, and simply releasing breath from the lungs. 

Answer:  The speedometer does not give the direction of the vehicle. Thus, this device can measure only the speed of a vehicle, not its velocity.

Explanation: A speedometer is a device that helps to estimate and visualize a vehicle's instantaneous speed, which has only magnitude.

When a typical comet in the Oort cloud is only 1 km in diameter, then the mass of the Oort cloud is changes to  4.18×10⁹ kg.

The mass of each comet int he Oort cloud is,

mass = density × Volume

volume of sphere = 4/3(π×r²) where, r = radius of the sphere

From the given,

diameter = 1 km

radius = Diameter / 2 = 1/2(D)

Volume of the comet = 4/3 (π×r²) = 4/3 (π× (1/2 (10)³)²)

                                   = 4/3×(π) ×(1/8×10⁶)

Mass = density  × volume, where density = 1000 kg/m³

         = 1000  × 4/3×(π) ×(1/8×10⁶)

        = 4.18 ×10⁹ kg

When the typical comet in the Oort cloud is only 12 km in diameter the mass of Oort cloud is 4.18×10⁹ kg.

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The magnitude of the tension in the upper rope is 24.93 N.

The tension in the lower rope is calculated as follows;

T1 + T2 = W

where;

12.8 + T2 = (3.85)(9.8)

12.8  + T2 = 37.73

T2 = 37.73 - 12.8

T2 = 24.93 N

Thus, the  magnitude of the tension in the upper rope is 24.93 N.

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The ratio of the horizontal speed of our rocket to the horizontal speed of the rocket in the video after all the fluid has left the rocket is 1/6

The horizontal speed of the rocket depends on the momentum it gains from the fluid it expels. The momentum gained is equal to the mass of the fluid expelled multiplied by its speed relative to the rocket. Since the mass of the rocket is three times greater and the fluid is twice as dense, the mass of the expelled fluid will be six times greater than in the original experiment. However, the fluid leaves the rocket at the same speed, so the momentum gained will also be six times greater.

According to the law of conservation of momentum, the momentum gained by the rocket will be equal and opposite to the momentum lost by the expelled fluid. Since the momentum gained by the rocket is six times greater than in the original experiment, the momentum lost by the fluid will also be six times greater. Therefore, the speed of the fluid relative to the rocket will be one-sixth of its original speed.

The horizontal speed of the rocket will be proportional to the speed of the expelled fluid relative to the rocket. Therefore, the ratio of the horizontal speed of the new rocket to that of the rocket in the original experiment will be:

(new fluid speed / original fluid speed) = (1/6) / 1 = 1/6

Since the ratio of the horizontal speed is proportional to the speed of the expelled fluid, it is independent of the mass of the rocket. Therefore, the ratio of the horizontal speed of the new rocket to that of the rocket in the original experiment is 1/6. Answer: 1/6.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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Answer:

A and E

Explanation:

An easy (calculation free) way to think about it is balance. The question states that the system is un-moving and therefore balanced in the picture. To keep it balanced, we want to add equal weights at equal distances on opposite sides of the pivot point. A and E are both 2 holes away from the pivot point.

The actual (physics) explanation for this is using torques. The system is balanced in the picture since the center of mass of the bar is at D and the weight is at B. They are equal distances and weights from the pivot point, and cause torques of equal magnitude in opposite directions from each other, so the net torque is 0. We want to apply the same logic when adding 2 more masses. Torque = r F sinα, where r is the distance from the pivot point and F is the weight (force of gravity). Since F is down in both cases, they will cause torques in the opposite directions. To get a net torque of 0 (balanced), we want the torques to have equal magnitude in opposite directions, so as long as r (the distance from the pivot point) is equal for each mass, the system will remain balanced.

Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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Answer:

A. the motion of an object along a curved path

Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Following are the answers:

1. To calculate the pressure exerted by the water column on the surface of the mercury, we can use the formula:

Pressure = force/area

The force is the weight of the water column and the area is the cross-sectional area of the container.

The weight of the water column is given by the mass of the water times the acceleration due to gravity:

mass = density x volume

volume = area x height

So, mass = density x area x height = 1000 kg/m^3 x pi x (0.025 m)^2 x 0.25 m = 0.196 kg

Weight = mass x acceleration due to gravity =\(0.196 kg * 9.8 m/s^2\) = 1.92 N

The cross-sectional area of the container is pi x (0.025 m)^2 =\(0.196 m^2.\)

So, Pressure = force/area = \(1.92 N/0.196 m^2 = 9.79 N/m^2\) or 9.79 Pa

2. To calculate the density of the oil, we can use the formula:

density = mass/volume

Since the height of the oil column is 0.92 m and the cross-sectional area of the container is 0.196 m^2, the volume of the oil column is 0.196 m^2 x 0.92 m = 0.18012 m^3.

We do not know the mass of the oil, but we can calculate it using the pressure exerted by the oil column on the surface of the mercury:

Pressure = force/area = density x acceleration due to gravity x height

So, density = Pressure/ (acceleration due to gravity x height) = 9.79 N/m^2 / (9.8 m/s^2 x 0.92 m) = 1060 kg/m^3.

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Hi there! :)

We can begin by doing a summation of forces on the ball. In the horizontal direction, we have the force of tension:
\(F_{Net} = T\)

The tension force results in a centripetal force experienced by the ball. The equation of centripetal force is equivalent to:
\(F_C = m\omega^2 r\)

\(F_C\) = Centripetal force (N)
m = mass of ball (0.22 kg)

ω = angular speed of ball(? rad/sec, must convert rpm to rad/sec)

r = radius/length of string (1.0 m)

We must begin by converting rpm to rad/sec:

\(\frac{50 rev}{min} * \frac{2\pi rad}{1 rev}* \frac{1 min}{60 sec} = 5.236 \frac{rad}{s}\)

Now, we can set tension equal to the centripetal force and solve. \(T = F_{Net} = F_C\\\\T = m\omega^2 r\\\\T = (0.22)(5.236^2)(1) = \boxed{6.031 N}\)

1302200J

Explanation:

To bring water at 70°C to water at 0°C, we use MC∆T.

To convert water at 0°C to ice at 0°C, ML is applicable, where L is the latent heat of fusion and M equals mass. NB: Temperature is constant during fusion.

Again, to raise the temperature of ice to -11°c, we use MC∆T.

Total heat = MCw∆T + ML + MCi∆T

2 ×4200× 70 + 2×334000 + 2× 2100× 11 = 1302200J

The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.

The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.

To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².

Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².

Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m

The time taken, t = 38 ms = 0.038 s.

Now, we know that acceleration, a = (v - u) / t.

We can rearrange the above equation to find the final velocity, v. We get,v = u + at

Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s

Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.

Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

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The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.

The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.

In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.

By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.

By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.

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The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

(a) 6.67 m/s  (b) 3.33 m/s

Explanation:

if i understood your question correctly, the jogger goes 150m east before going in the opposite direction west for 50m. (see diagram)

in avg speed, we use the total distance (150m + 50m = 200m)  and total time (30s)

v = d/t =200/30 =6.67 m/s

in avg velocity, we use the total displacement  (150m - 50m = 100m) and total time (30s)

v= d/t = 100/30 = 3.33 m/s

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

Answer:

Relative density is the ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas.

Since you wanted to use some brain-mapping techniques to identify anatomical functioning, the method that would be the best choice is option A. MRI.

In PET scans, the breakdown of option B:  radioactive materials in the body and the release of gamma rays produce a functional view of the brain.

FDG, which stands for "fluorodeoxyglucose," is a simple sugar (like glucose) that is frequently employed in PET scanning. It is injected into the bloodstream and builds up inside the body, where it emits gamma rays as energy.

Note that without injecting any kind of dye or tracer, brain mapping techniques like magnetoencephalography (MEG) and functional magnetic resonance imaging (fMRI) scans can be used to detect the anatomical functioning of the brain. The diagnosis and treatment of neurodegenerative illnesses can both benefit greatly from these techniques.

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The cart is at rest, so it is in equilibrium and there is no net force acting on it. The only forces acting on the cart are its weight (magnitude w), the normal force (mag. n), and the friction force (maximum mag. f ).

In the horizontal direction, we have

n cos(120º) + f cos(30º) = 0

-1/2 n + √3/2 f = 0

n = √3 f

and in the vertical,

n sin(120º) + f sin(30º) + (-w) = 0

n sin(120º) + f sin(30º) = (50 kg) (9.80 m/s²)

√3/2 n + 1/2 f = 490 N

Substitute n = √3 f and solve for f :

√3/2 (√3 f ) + 1/2 f = 490 N

2 f = 490 N

f = 245 N

(pointed up the incline)

Answer:

Explanation:

yes object can move through a distance  and can have zero displacement  

as displacement is the shortest distance between two points eg: if a person has moved a distance of 20 m and comes back to his original place by moving back 20m in such a case  distance moved by the person is 40m but his displacement is 0 as shortest distance covered by him is 0 as he is in his original place

Yes, it is possible for a body to have traveled a distance yet have a displacement of zero.

Distance traveled by a body is the length of the path covered by it.

On the other hand displacement of a body is the shortest distance between the initial and the final point of a body.

When a body is traveling such that it ends at the point from where it started its journey, it covers a distance but the displacement of the body is zero.

So a body that has moved through a distance can have zero displacement.

The scientific definition of energy that reflates it to work is: the ability to use the stored potential of an object.

In physics, energy is the ability to perform work. It could exist in several different forms, such as potential, kinetic, thermal, electrical, chemical, radioactive, etc.

Additionally, there is heat and work, which is energy being transferred from one body to another. Energy is always assigned based on its nature once it has been transmitted.

So, scientifically  energy is the ability to use the stored potential of an object.

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Answer: look at the file

Answer:

\(F(t)=m\,\,a(t)=6\,m\,t\,\hat i+14\,m\,\hat j+6\,m\,t\,\hat k\\F(t)=\,(6\,m\,t,14\,m,6\,m\,t)\)

Explanation:

Recall that force is defined as mass times acceleration, and acceleration is the second derivative with respect to time of the position. Since the position comes in terms of time, and with separate functions for each component in the three dimensional space, we first calculate the velocity (with the first derivative, and then the acceleration as the second derivative:

\(r(t)=t^3\,\hat i+7\,t^2\,\hat j+t^3\,\hat k\\v(t)=3\,t^2\,\hat i+14\,t\,\hat j+3\,t^2\,\hat k\\a(t)=6\,t\,\hat i+14\,\hat j+6\,t\,\hat k\)

Therefore, the force will be given by the product of this acceleration times the mass "m":

\(F(t)=m\,\,a(t)=6\,m\,t\,\hat i+14\,m\,\hat j+6\,m\,t\,\hat k\)

Answer:

100j

Explanation:

Answer:

Diffraction is correct :)

Explanation:

Diffraction of sound waves is commonly observed; we notice sound diffracting around corners or through door openings, allowing us to hear others who are speaking to us from adjacent rooms.

Answer:

11948.64 Newtons

Explanation:

Jack speed as he hits the water is 14.13m/s

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s².  Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.

If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).  
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).  
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)

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