a person carries a plank of wood 2.00 m long with one hand pushing down on it at one end and the other hand holding it up at 0.400 m from the end of the plank. if the plank has a mass of 25.0 kg and its center of gravity is at the middle of the plank, how much force is their first hand pushing down with?

Answer:

Any force greater than 24.5 N

Explanation:

To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.

I hope I helped correct me if im wrong

A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.

First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.

\(|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N\)

where,

Then, we will calculate the friction force (f) using the following expression.

\(f = \mu \times N = 0.25 \times 98 N = 25 N\)

According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.

\(F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N\)

A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.

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The cycle time of the entire line is 30.00528 minutes per part.

To calculate the cycle time of the entire line, we need to consider the processing times, failures, and repairs of both the milling machine and the turning machine.

For the milling machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 750 mins

Mean time to repair (MTTR) = 200 mins

For the turning machine:

Mean processing time (t0) = 15 mins

Standard deviation of processing time (sigma0) = 3 mins

Mean time to failure (MTTF) = 110 mins

Mean time to repair (MTTR) = 38 mins

We also know that the arrival rate to the milling machine is 1.2 parts/hr, with a coefficient of variation (CV) of 1.

To calculate the cycle time, we can use the following formula:

Cycle time = Processing time + Failure time + Repair time

Processing time:

The processing time is the sum of the mean processing times of the milling machine and the turning machine:

Processing time = t0 (milling machine) + t0 (turning machine) = 15 mins + 15 mins = 30 mins

Failure time:

The failure time is the inverse of the MTTF, considering the arrival rate:

Failure time = 1 / (MTTF * Arrival rate) = 1 / (750 mins * (1.2 parts/60 mins)) = 0.00111 parts/min

Repair time:

The repair time is the inverse of the MTTR, considering the coefficient of variation (CV):

Repair time = 1 / (MTTR * CV) = 1 / (200 mins * 1.2) = 0.00417 parts/min

Cycle time:

Cycle time = Processing time + Failure time + Repair time = 30 mins + 0.00111 parts/min + 0.00417 parts/min

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Answer:

I think its tennis but im not sure

Explanation:

Answer:

my only true question is b

Answer:

The horizontal component of the force, \(F_x= 34.24 \ N\)

The  vertical component of the force, \(F_y=7.28 \ N\)

Explanation:

Given;

Force on the rope, F = 35 N

angle between the rope and the horizontal = 12 °

The horizontal component of the force is given by;

\(F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N\)

The vertical component of the force is given by;

\(F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N\)

The given statement "electric field lines near negative point charges circle clockwise." is False. Because electric field lines near negative point charges do not circle clockwise.

They actually radiate outward from the negative charge in all directions. The direction of the electric field lines is determined by the direction in which a positive test charge would move if placed in the field. Since like charges repel each other, a positive test charge would move away from the negative charge, resulting in electric field lines that extend outward from the negative charge. The field lines do not form closed loops or circles around the negative charge. Instead, they spread out radially, indicating the direction and strength of the electric field.

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Answer:

I mean they have the same amount of velocity

Hector does negative work of 1.728 kJ to stop the boat.

To calculate the work done by Hector to stop the boat, we first need to determine the initial kinetic energy of the boat and riders:

KE = (1/2)mv^2

where m is the mass of the boat and riders, and v is the velocity at which they are moving.

Substituting the given values, we get:

KE = (1/2)(2400 kg)(1.2 m/s)^2 = 1728 J

Since Hector stops the boat, he does negative work equal in magnitude to the initial kinetic energy:

W = -KE = -1728 J

To express this value in kilojoules, we divide by 1000:

W = -1.728 kJ

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According to Plumbing 101 principles governing blood flow through the vessels, the statement "Flow depends on pressure difference, but not the absolute pressure" is true.

In the context of Plumbing 101 principles, blood flow through the vessels can be understood by applying the laws of fluid dynamics. According to these principles, the statement that holds true is that flow depends on pressure difference, but not the absolute pressure.

Pressure difference refers to the variance in pressure between two points in a fluid system. In the case of blood flow, it refers to the pressure difference between the point of origin (such as the heart) and the destination point (such as organs or tissues). The pressure difference creates a driving force for blood to flow from higher pressure regions to lower pressure regions.

While the absolute pressure at the origin and destination points may affect the overall pressure difference, it does not directly impact the flow rate of blood. Flow is primarily determined by the pressure difference rather than the absolute pressure at the specific points. Other factors, such as the diameter of the vessel, viscosity of the blood, and the resistance offered by the vessel walls, also influence blood flow.

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The acceleration experienced by the crate is approximately 0.844 m/s

Weight of the crate:

Weight = mass × acceleration due to gravity

Weight = 114 kg × 10 m/s^2

Weight = 1140 N

Force of friction:

Force of Friction = coefficient of friction × normal force

Force of Friction = 0.541 × 1140 N

Force of Friction ≈ 616.74 N

Net force:

Net Force = Applied Force - Force of Friction

Net Force = 713 N - 616.74 N

Net Force ≈ 96.26 N

Acceleration:

Acceleration = Net Force / mass

Acceleration = 96.26 N / 114 kg

Acceleration ≈ 0.844 m/s

Therefore, the acceleration experienced by the crate is approximately 0.844 m/s

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Answer:

all of these

Explanation:

D. all of these is the correct answer

The final speed of cyclist is 12.27m/s

The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension

We will use the formula

\(v^2-u^2=2aS\)

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

v^2 = 2 x a x S

       = 2 x 46 x a

v^2=92a

v=\(\sqrt{92a}\)

where a is the acceleration

Now using the formula v= u+ at

and putting value of v in the equation

\(\sqrt{92a}\)=a x7.5

squaring both sides,

92a=56.25a^2

a=92/56.25=1.64 m/s^2

Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s

Hence her final speed is 12.27m/s

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between the focus & the centre of curvature of the mirror

Angle of θ of the K2x-ray beam of copper (2.542 Å) diffracted from the (110), (200), and (220) planes of BCC iron, which has a lattice parameter of 2.866 Å, can be calculated by using Bragg’s law. The angle of θ for (110), (200), and (220) planes of BCC iron can be calculated using Bragg’s law.

The angle of θ for (110) plane of BCC iron can be calculated using Bragg’s law as follows:nλ = 2dsinθFor (110) plane, n = 1, λ = 2.542 Å, d = √2/2a = √2/2 × 2.866 Å = 2.02 Å Therefore,2.542 = 2 (2.02) sinθ On solving the above equation, the value of θ comes out to be 24.3°. Therefore, the angle θ of the K2x-ray beam of copper (2.542 Å) diffracted from the (110) plane of BCC iron is 24.3°. Similarly, the angle of θ for (200) and (220) planes of BCC iron can be calculated as follows. The angle of θ for (200) plane of BCC iron can be calculated using Bragg’s law as follows: nλ = 2dsinθFor (200) plane, n = 2, λ = 2.542 Å, d = √2a = √2 × 2.866 Å = 4.06 Å.

Therefore,2.542 = 2(4.06)sinθOn solving the above equation, the value of θ comes out to be 18.4°.Therefore, the angle θ of the K2 x-ray beam of copper (2.542 Å) diffracted from the (200) plane of BCC iron is 18.4°.The angle of θ for (220) plane of BCC iron can be calculated using Bragg’s law as follows: nλ = 2dsinθFor (220) plane, n = 2, λ = 2.542 Å, d = √2/2a = √2/2 × 2.866 Å = 2.02 Å Therefore,2.542 = 2(2.02)sinθOn solving the above equation, the value of θ comes out to be 32.3°.Therefore, the angle θ of the K2x-ray beam of copper (2.542 Å) diffracted from the (220) plane of BCC iron is 32.3°.

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A movement from Y to Z results from plastic production technology advancements.

What induces motion along the PPC?

If resources are finite and constant, the move along a PPC through one point to the next shows that more of either good can only be generated by giving production up of the second good.

Is there a rise in plastic manufacture globally?

1950 2021: worldwide plastic output. In 2021, the output of plastics on a global scale was projected to reach 390.7 million metric tons, a rise of 4% annually. Since the 1950s, plastics production has exploded. The extraordinary adaptability of this class of materials is what drives their yearly production increases.

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Explanation:

The formula of kinetic energy is K.E= m\(v^{2}\)/2 , where m is the mass and v is the velocity. According to the formula, if we double the mass, the kinetic energy will also double then we can say the Kinectic energy is directly proportional to the mass.

Answer:

Sample Response: If the mass of an object increases, then its kinetic energy will increase proportionally because mass and kinetic energy have a linear relationship when graphed.

Explanation:

100% Edge 2022 :)

Answer:

29.55 kg

Explanation:

force gravity =  G m1 m2 / (r^2)    now change the mass 1 and the r

                     =   G 2m1 m2 / ( 2r)^2

                      = 2/4  G m1 m2 / (r^2)

the weight will be 2/4   or  1/2 the original

Answer:

objective 4

Explanation:

i took the unit test review and the regular unit test

Object 4 with a density of 2.3 g/cm³  would sink in honey, which has a density of 1.4 g/cm³, therefore the correct option is option D.

It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.

The mathematical formula for density is given below

ρ =m /v

where ρ is the density of the substance

m is the mass of the substance

v is the volume of the substance

As per the law of floatation, the objects those have less density than the honey do not sink in the honey which has a density of 1.4 g/cm³.

As per the given options, object 1 has a density of 0.9 g/cm³ which is less than the density of honey 1.4 g/cm³, therefore it would not sink in the honey. similarly, objects 2 and object, 3 have a density that is less than the density of the honey, therefore they would float instead of sinking in the honey.

The only object 4  has a density of 2.3 g/cm³ which is more than the density of honey, therefore it would sink on the honey.

Hence, the correct answer is object 4.

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Answer:

The length of chain she is allowed is 1.169 ft

Explanation:

The given parameters are;

The linear density of the chain = 0.83 lb/ft

The weight limit of the chain she wants = 1.4 lb

The formula for linear density = Weight/length

Therefore, in order to keep the chain below 1.4 lb, we have;

Linear density = Weight/length

Therefore;

The maximum length she wants = Weight/(Linear density)

Which gives;

The maximum length she wants = 1.4 lb/(0.83 lb/ft) =1.169 ft

Therefore;

The length of chain she is allowed = 1.169 ft.

Answer:

0.13m/s

Explanation:

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Answer:

4.2 km West of the start

Explanation:

Displacement is a vector quatitiy which means it has direction adn magnitude. It is the distance you are at the very end of the journey from the start.

We can assign one way as a positive direction and the other a negative and then add them

I will say that West is positive and East is negative:

(10.9) + (-6.7) = 4.2km

When an airplane turns, it needs to bank or tilt in order to change its direction of flight. This is necessary because of the way in which lift is generated by the wings of the airplane.

The wings of an airplane are designed to create lift by directing airflow over the curved upper surface of the wing. As the air flows over the wing, it creates an area of low pressure above the wing and an area of high pressure below the wing. The difference in pressure between the top and bottom of the wing creates an upward force that helps to lift the airplane off the ground and keep it in the air.

When an airplane banks or tilts, it changes the angle of attack of the wings with respect to the oncoming airflow.

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The amplitude of the given sinusoidal function is 3, the period is 6, and the sine function modeled by the given sketch is \(y = 3 sin\left(\frac{\pi}{3} x + \frac{\pi}{2}\right)\).

Given the sketch of a sinusoidal function, we need to find out the amplitude, period, and the sine function modeled by this sketch.

Observe the given graph. Consider the highest point of the graph and the lowest point of the graph. The highest point and the lowest point are at the distance of 3 units on the y-axis.

Hence, the amplitude of the given sinusoidal function is 3.  \(A = 3\)To find the period, we need to observe the distance between two consecutive peaks or troughs.  

We can observe that there are 4 peaks in one complete cycle and the distance between any two peaks is 6 units.

So, the distance between two peaks is called the period of the graph and it is given by:Period = \frac{2\pi}{\omega}

We know that omega = \frac{2\pi}{Period}

Given thatPeriod = 6\omega = \frac{2\pi}{6}\omega = \frac{\pi}{3}

Now, the sine function is represented as \(y = A sin(\omega x + \phi)\)

Here, \(A\) is the amplitude which is 3.

\omega is the angular frequency which is\frac{\pi}{3}.

Let's find the phase angle \(\phi.

As we know that the highest value of the sine function is achieved at x = 0, we can use this information to find the value of \(\phi\).

So, we get,\(3 = A sin(\omega * 0 + \phi)\)\(3 = 3 sin \phi\)\(sin \phi = 1\)\(\phi = \frac{\pi}{2}\)

Now, we can write the sine function modeled by the given sketch:\(y = 3 sin\left(\frac{\pi}{3} x + \frac{\pi}{2}\right)\)

Hence, The sine function represented by the provided sketch is \(y = 3 sinleft(fracpi3 x + fracpi2right), and the given sinusoidal function has an amplitude of 3, a period of 6, and a period of 6.of \).n x.

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The process by which an individual pursues important objectives by setting goals and monitoring progress is called self-regulation.

Self-regulation involves the ability to manage one's thoughts, emotions, and behaviors in order to achieve desired outcomes. It requires setting specific, measurable, attainable, relevant, and time-bound (SMART) goals and then actively monitoring and adjusting one's actions to stay on track.

Self-regulation encompasses various cognitive and behavioral processes, such as self-awareness, self-monitoring, self-control, and self-reflection. It involves being disciplined, persevering through challenges, and making adjustments when necessary.

By engaging in self-regulation, individuals can enhance their motivation, focus, and performance, leading to greater success in reaching their objectives. Self-regulation is a valuable skill that can be developed and honed through practice and self-awareness.

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The motion of the earth’s molten rock shows characteristic patterns that can be analyzed and explained scientifically. This analysis and explanation are impossible without understanding the principles of thermal energy.

Thermal energy is a type of energy that is transferred from one object to another as a result of a difference in temperature between the two objects.

The motion of the earth’s molten rock is driven by thermal energy, which is produced by the decay of radioactive isotopes in the earth’s core. The heat produced by this process causes the molten rock to rise toward the surface, where it cools and solidifies, forming a new crust.

The motion of the molten rock is also affected by convection currents, which are driven by differences in temperature between different regions of the earth’s core. As the molten rock moves, it creates characteristic patterns that can be observed and analyzed by scientists.

Understanding the principles of thermal energy is essential for understanding the motion of the earth’s molten rock, and for developing models that can accurately predict future patterns of movement.

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The first law of thermodynamics, which states that you cannot produce or destroy matter or energy, is broken by this. Critics assert that the big bang theory implies the universe didn't exist before the big bang.

According to a theoretical hypothesis known as the Big Bang theory, the cosmos first existed in a state of extreme density and heat. The evolution of the observable universe from the earliest known times through its later large-scale form is explained by a variety of cosmological models of the Big Bang. These models provide a thorough justification for a wide variety of known phenomena, including the abundance of light elements, cosmic microwave background (CMB) radiation, and large-scale structure. Cosmic inflation, or the abrupt and extremely rapid expansion of space during the Universe's early moments, provides an explanation for the flatness problem, or the appearance of uniformity over the whole cosmos. The initial conditions of the Big Bang, however, are not currently well modeled by any commonly accepted quantum gravity theory.

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Answer:

The force acting on it is lift

Answer:

Yeah exactly.

Explanation:

Look here down.

From Newtond second law of motion.

And this force is included the force of weight which changes from ma to mg

According to the Newton's second law,

where F is the force on the object, m is the mass of the obect and a is the acceleration of the object.

Substituting the known values,

Thus, the mass of the object is,

Hence, the mass of the object is 6 kg.