A particle (charge = 40 μC) moves directly toward a second particle (charge = 80 μC) which is held in a fixed position. At an instant when the distance between the two particles is 2.0 m, the kinetic energy of the moving particle is 16 J. Determine the distance separating the two particles when the moving particle is momentarily stopped.
Answers
Answer:
The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
Explanation:
Given that,
First charge = 40 μC
Second charge = 80 μC
Distance between the two particles = 2.0 m
Kinetic energy = 16 J
We need to calculate the distance separating the two particles when the moving particle is momentarily stopped
Using conservation of energy
\(K.E+\dfrac{kq_{1}q_{2}}{d}=\dfrac{kq_{1}q_{2}}{x}+K.E\)
Put the value into the formula
\(16+\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{2}=\dfrac{9\times10^{9}\times40\times10^{-6}\times80\times10^{-6}}{x}+0\)
\(16+14.4=\dfrac{28.8}{x}\)
\(30.4x=28.8\)
\(x=\dfrac{28.8}{30.4}\)
\(x=0.947\ m\)
Hence, The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m
The distance separating the two particles when the moving particle is momentarily stopped is 0.947 m.
The given parameters;
charge of the first particle, q₁ = 40 μCcharge of the second particle, q₂ = 80 μCinitial distance between the particles, x₁ = 2 minitial kinetic energy, K.E₁ = 16 JThe kinetic energy is zero at the instant the moving particle is momentarily stopped.
The distance separating the two particles when the moving particle is momentarily stopped is calculated as follows;
\(K.E_1 \ + W_1 = K.E_2 + W_2\\\\K.E_1 + \frac{kq_1q_2}{x_1} = K.E_2 + \frac{kq_1q_2}{x_2} \\\\16 \ + \ \frac{(9\times 10^9)\times (40\times 10^{-6})\times (80\times 10^{-6})}{2} = 0 \ + \ \frac{(9\times 10^9)\times (40\times 10^{-6})\times (80\times 10^{-6})}{x_2} \\\\30.4= \frac{28.8}{x_2} \\\\x_2 = \frac{28.8}{30.4} \\\\x_2 = 0.947 \ m\)
Thus, the distance separating the two particles when the moving particle is momentarily stopped is 0.947 m.
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Related Questions
The voltage across the primary winding is 6000 v. if the primary winding has 50 coils and the secondary winding has 20 coils, what is the secondary voltage? 120 v 2400 v 15,000 v 120,000 v
Answers
if the primary winding has 50 coils and the secondary winding has 20 coils then the secondary voltage will be equal to 2400V
What is voltage?Voltage is defined as the potential difference which apply a force on the charge to flow in the circuit.
This is a question on transformer. A transformer is a device used to step up or step down current and voltage. It consists of the primary windings and secondary windings. Each windings possesses both coil and amount of voltage across each coil.
The transformer formula is
\(\dfrac{V_S}{V_P}=\dfrac{N_S}{N_P}\)
Where;
Vs is the voltage across the secondary coil
Vp is the voltage across the primary coil
Ns is the number of turn in the primary coil
Np is the number of turns in the primary coil.
According to the question,
Vs is unknown
Vp is 6000V
Ns is 20turns
Np is 50turns
Substituting the values in the formula given
\(\dfrac{V_S}{6000}=\dfrac{20}{50}\)
Vs = 2400V
Therefore the secondary voltage is 2400V
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Answer:
2400
Explanation:
edge 2022
Match the phrase with word please help!
Phrases:
1.) The amount of work done when jerry carries a box from his house to the moving truck . He exerts a force of 35 N while carrying the box 4 meters
2.) The power resulting from 420 Nm of work being completed in 3 seconds
3.) The amount of work done when Fido carries his toy from the backyard to his crate. He exerts a force of 1.2 N over a distance of 15 m
4.) The power resulting from 120 Nm of work being completed in 20 seconds
A.) 140 joules
B.) 140 Newton-meters
C.) 6 joules
D.) 6 Newton-meters
Answers
Answer:
1-B, 2-A, 3-D, 4-C
Explanation:
1. The force exerted is, F = 35 N
Distance the box is moved, d = 4 m
So the amount of work done is, W = F x d
= 35 x 4
= 140 Newton-meters
2. Work done, W = 420 Nm
Time, T = 3 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{420}{3}$\)
= 140 joules
3. The force exerted is, F = 1.2 N
Distance the box is moved, d = 5 m
So the amount of work done is, W = F x d
= 1.2 x 5
= 6 Newton-meters
4. Work done, W = 120 Nm
Time, T = 20 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{120}{20}$\)
= 6 joules
You and your friend pull on opposite ends of a rope. You each pull with a force of 35 N. What is the
tension in the rope ?
Answers
Answer:
pulling force exerted by each person on the rope is
65
N
, and consequently by NIII, the rope exerts an equal but opposite tension force of
65
N
on each person.
Explanation:
Which object is most efficient?
a. A heat engine that produces 30 J of work for 60 J of input energy.
b. A heat engine that produces 15 J of work for 30 J of input energy.
c. A heat engine that produces 20 J of work for 60 J of input energy.
d. A heat engine that produces 40 J of work for 50 J of input energy.
Answers
Answer:
It is b
Explanation:
Four cube-shaped blocks are floating in equilibrium in a tank of water. Blocks a, b, and c have the same size. Block d is larger than the others. The masses of the blocks are unknown
Answers
Part (a) Sort the buoyant force magnitudes acting on blocks A, B, C, and D from largest to smallest. Sort the block masses in part (b) starting with the largest.
What do physics magnitudes mean?Magnitude in physics is simply described as "distance or quantity." It shows the size or direction that an object moves in either an absolute or relative sense. It is a way of expressing something's size or scope.
What is an illustration of magnitude?Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In just this case, the car is happening faster than the motorcycle by a wider margin.
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why do many people consider isaac newton one of the greatest scientists who ever lived?
Answers
Answer:
In 1687, Newton published one of the most important scientific books in history, the Philosophiae Naturalis Principia Mathematica, commonly known as the Principa. It was in this work that he first laid out his three laws of motion.
like a great curving mirror, infinitely blue and beautiful, always the same
Answers
The phrase "like a great curving mirror, infinitely blue and beautiful, always the same" is a poetic description of the sky.
This description compares the sky to a large, curving mirror, highlighting its vastness and ability to reflect light.
The sky's blue color is emphasized as being infinite and beautiful, while "always the same" suggests that it remains constant and unchanging despite the passage of time or changes in weather.
Summary: The given phrase is a poetic way of describing the sky's vastness, beauty, and constancy.
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What is the speed of a jet plane that flies 7200 km in 9 hours (in km/hr)?
Answers
Communication satellites are often put in a geo-synchronous orbit, meaning they have an orbital period of 24 hours and stay over the same spot above the equator at all times. Given that the Earth has a mass of 5.97 x 1024 kg and a radius of 6.37 x 106 meters, determine the following: a. What is the orbital height of the satellite relative to the surface of the Earth
Answers
Answer:
h = 35857 km
Explanation:
A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.
We are given;
Radius of earth(R) = 6.37 x 10^(6) m
Mass of earth (Me) = 5.97 x 10^(24) kg
Gravitational constant = 6.67 × 10^(-11) m³/kg.s²
The earth has a rotational period of 24 hours per day. This gives in seconds
T = 24 × 60 × 60
T = 86400 s
Let's make the height of the orbit from Earth's surface to be h
Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit
Now, equating the centripetal force with the gravitational force gives us;
mω²(R + h) = G•Me•m/(R + h)²
m will cancel out. Also ω can be written as 2π/T
Thus,we now have;
(R + h) = ∛(G•Me•T²/(4π²))
Plugging in the relevant values, we have;
(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))
(R + h) = 42227 Km
Since R = 6.37 x 10^(6)m = 6370 km
Thus;. h = 42227 - 6370 = 35857 km
Question 2: What is the velocity ratio of this pulley?
Load
distance=12 m
Effort
distance= 4 m
Answers
Answer:
1/3
Explanation:
Velocity ratio = distance moved by effort / distance moved by load
The potential difference across a piece of wire is 2.1 v the current in the wire is 0.30 a calculate the resistance of the wire in ohms
Answers
Answer:
7ΩExplanation:
Given:
V = 2.1 v
I = 0.30 A
R = Unknown
Solution:
R = V / I
= 2.1V / 0.30A
= 7Ω
Answer:
7Ω is the resistance of the wire in ohms
The resistance of the wire will be 7 ohms. Resistance is the antagonism strength shown in the discharge of the electric current.
What is resistance ?Resistance is the opposition force offered in the flow of the electric current. It is denoted by R.It s unit is ohms.
The given data in the problem is;
V is the potential difference = 2.1 v
I is the current = 0.30 A
R is the resistance =?
According to Ohm's law resistance is the ratio of the voltage to the current.
\(\rm R = \frac{V}{I} \\\\ \rm R = \frac{2.1}{0.30} \\\\ \rm R = 7 \ ohm\)
Hence the resistance of the wire will be 7 ohms.
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Two forces P and Q acting at a point at an angle have their resultant
(2n + 1)√P2 + Q2 and when at an angle (90° - ),the resultant is(2n - 1)√P2 + Q2.
Show that tan = (n - 1)/( n + 1).
Answers
Answer:
Answer is given in this paper.
Thank You
Please mark me Brainlest.
two parallel current carrying wires exerted equal but opposite forces on each other. the current in the second wire is doubled. how do their forces relate now?
Answers
When the current in the second wire is doubled, the forces exerted by the two parallel current-carrying wires on each other will also double, maintaining an equal but opposite relationship.
The force between two parallel current-carrying wires is given by Ampere's law. According to Ampere's law, the force is directly proportional to the product of the currents and inversely proportional to the square of the distance between the wires.
Initially, when the currents in the two wires are equal, the forces they exert on each other are also equal but opposite in direction, ensuring equilibrium. Let's call this force F1.
When the current in the second wire is doubled, the product of the currents in the two wires becomes twice the original value. Since the force is directly proportional to the product of the currents, the force between the wires will also double. Let's call this force F2.
Therefore, after doubling the current in the second wire, the forces exerted by the wires on each other will be equal but opposite in direction, and the magnitude of the forces will be twice the original value.
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the cabin pressure of a passenger jet cruising at high altitude (30,000 ft) is about 1 atm. and the pressure outside is about 0.3 atm. what is the outward force on a window measuring 1 foot by 1 foot.
Answers
The outward force on a window measuring 1 foot by 1 foot is 0.3atm-foot^2.
The force applied perpendicularly to an object's surface is divided by the surface area over which it is applied.
The pressure exerted on the surface by a force of magnitude "F" Newton when applied perpendicularly to surface area "A" is equal to the ratio of F to A. The pascal is the pressure unit used in SI (Pa).A force of one newton applied across a surface area of the one-meter square is referred to as a pascal.Since the pressure is a function of the area that the force is acting on, it can rise and fall without affecting the force. If the force applied remains constant, the pressure will rise as the surface gets smaller and vice versa.we know that,
Pressure = Force / Area
P = 1 - 0.7
P = 0.3 atm
F = 0.3 atm-foot^2
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Two small plastic balls hang from threads of negligible mass. Each ball has a mass of 0.14 g and a charge of magnitude q. The balls are attracted to each other. When in equilibrium, the balls are separated by a distance of 2.05 cm and the threads attached to the balls make an angle of 20 degrees with the vertical.(a) Find the magnitude of the electric force acting on each ball.(b) Find the tension in each of the threads.(c) Find the magnitude of the charge on the balls.
Answers
Answer:
a. 4.99 × 10⁻⁴ N b. 1.46 × 10⁻³ N c. 4.83 nC
Explanation:
(a) Find the magnitude of the electric force acting on each ball.
The tension in the string, T is resolved into horizontal and vertical components Tsin20° and Tcos20° respectively, since the string makes an angle of 20° with the vertical.
Let F = electric force and W = mg be the weight of the ball where m = mass of ball = 0.14 g = 0.14 × 10⁻³ kg and g = acceleration due to gravity = 9.8 m/s²
The electric force acts in the opposite direction to the horizontal component of the tension in each string. Since the masses are in equilibrium,
Tsin20° = F (1)
Also, the weight of the ball acts downwards, opposite to the direction of the vertical component of the tension in the string. Since the masses are in equilibrium,
Tcos20° = W = mg
Tcos20° = mg (2)
Dividing (1) by (2), we have
Tsin20°/Tcos20° = F/mg
tan20° = F/mg
F = mgtan20°
So, F = 0.14 × 10⁻³ kg × 9.8 m/s²× tan20°
F = 0.4994 × 10⁻³ N
F = 4.994 × 10⁻⁴ N
F ≅ 4.99 × 10⁻⁴ N
(b) Find the tension in each of the threads.
Since Tsin20° = F
T = F/sin20°
= 4.99 × 10⁻⁴ N/sin20°
= 4.99 × 10⁻⁴ N/0.3420
= 14.59 × 10⁻⁴ N
= 1.459 × 10⁻³ N
≅ 1.46 × 10⁻³ N
(c) Find the magnitude of the charge on the balls.
From Coulomb's law, the electric force between the masses of charge q and separated by a distance r = 2.05 cm = 2.05 × 10⁻² m
F = kq²/r² where k = 9.0 × 10⁹ Nm²/C²
q² = Fr²/k
q = √(Fr²/k)
q = [√(F/k)]r
Thus,
q = [√(F/k)]r
q = [√( 4.99 × 10⁻⁴ N/9.0 × 10⁹ Nm²/C²)]2.05 × 10⁻² m
q = [√(0.5544 × 10⁻¹³ C²/m²)]2.05 × 10⁻² m
q = [√(5.544 × 10⁻¹⁴ C²/m²)]2.05 × 10⁻² m
q = [2.355 × 10⁻⁷ C/m]2.05 × 10⁻² m
q = 4.83 × 10⁻⁹ C
q = 4.83 nC
1. Find the Work and the Power done to increase the velocity of a 9 kg ball from 14
m/s to 30 m/s in 4 s.
Answers
Answer:
65
Explanation:
because everyday my birthday
9) An object with a height of 18 cm is placed in front of a converging lens. The image has a
height of –9.0 cm.
a) What is the magnification of the lens?
b) If the focal length of the lens is 6.0 cm, how far in front of the lens is the object?
c) Where does the image appear?
Answers
Answer:
Explanation:
a) Magnification = image height / object height = -9 / 18 = -0.5
b) Magnification = - image distance / object distance = -0.5
so image distance = 0.5 object distance
1/focal length = 1/image distance + 1/object distance
1/6 = 1/(0.5 object distance) + 1/object distance
object distance = 18.0 cm
c) Image appears behind the lens.
Answer:
Explanation:
mag = ht i/ht o = -9/18 = -1/2
mag = -1/2 = -di/do
do = 2di
put in eqn
1/f = 1/di + 1/do
1/6 = 1/di + 1/2di
2di = 18
do = 18cm
image is behind lens
You may have already used the Blackbody Spectrum simulation to see how the temperature of a substance affects how light is emitted. Many of the light sources you’re familiar with are incandescent light sources. They glow because they have a nonzero temperature. The hotter the source, the more radiant energy it gives off. Now, let’s explore a few different incandescent energy sources and investigate their lighting efficiency. In this simulation, the curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature.
To begin, launch the Blackbody Spectrum simulation.
Answers
The Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light.
First, discuss the relationship between temperature, radiant energy, and lighting efficiency.
Incandescent light sources emit light due to their nonzero temperature. As the temperature of the source increases, the amount of radiant energy it gives off also increases. The Blackbody Spectrum simulation helps us visualize how the temperature of a substance affects the way light is emitted.
In the simulation, a curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature. As the temperature rises, the curve's peak shifts towards shorter wavelengths, and the area under the curve increases. This shift indicates that the emitted light becomes more energetic and intense.
However, not all of this emitted energy is in the visible spectrum; a significant portion can be in the form of infrared radiation (heat). Incandescent light sources are not very energy-efficient, as a large portion of their energy output is wasted as heat rather than visible light. The lighting efficiency of an incandescent source is determined by the percentage of radiant energy that falls within the visible spectrum.
To summarize, the Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light. As the temperature increases, the emitted radiant energy also increases. However, a considerable amount of energy is lost as heat, making incandescent sources less energy-efficient compared to other lighting technologies.
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A circular loop of wire is placed in a uniform magnetic field directed out of the page. Suddenly the magnetic field disappear . What is the direction of the induced current in the loop?
Answers
Hi there!
Counterclockwise.
If a loop of wire is placed in a magnetic field directed out of the page that disappears, that means that the magnetic flux out of the page through the loop has decreased.
The loop will try to oppose this change in the magnetic flux, so an induced current that produces an additional magnetic field out of the page will occur to make up for the decrease in the magnetic flux.
Using the magnetic right-hand rule, the current in the loop would need to be traveling in the counterclockwise direction in order for the produced magnetic field to be directed out of the page inside the loop.
What is the speed of a wave that has a wavelength of 0.579 m, an amplitude of 0.733 m, and frequency of 4.00 Hz?0.145 m/s6.91 m/s2.93 m/s2.32 m/s
Answers
v(speed) = wavelenght x frequency
v = 0.579 m x 4 hz = 2.32 m/s
The expansion of the universe after its origin takes place by a phenomenon called.
Answers
The expansion of the universe after its origin takes place by a phenomenon called Big bang
What is Big bang theory ?As the universe widened, it cooled and matter began to form. Neutrons, protons, electrons, anti-electron, photons, and neutrinos were all present in the universe one second after the Big Bang. The Big Bang nucleosynthesis, which took place during the first three minutes of the universe, produced the light elements.
The big bang theory is the most commonly accepted explanation. Learn about the initial explosion and how the universe expanded from the size of an atom to include everything that exists today.
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the science building is 5.25 m tall a. How many decimeters is it? b. How many millimeter is it? *show work*
Answers
Answer:
5.25m to 52.5 Decimeters (10x)
5.25m to 5250 Millimeters (1000x)
And that would mean it would be 5250 millimeters. For the show your work thing, all you really had to do to solve this is move the decimal point depending on what type of measurement you were changing it into. So try and kinda write something like that down where you move the decimal point. Hope this helps
NASA's Langley Research Center has been experimenting with the use of air bags to soften the landings of crew exploration vehicles (CEV) on land. What stopping time will be required in order to safely stop a 7250 kg CEV moving at 7.65 m/s with an average force of 426000 N (an average force of 6 G's)
Answers
The stopping time will be 0.13 second required in order to safely stop a CEV .
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
The average force acting on CEV is = 426000 N.
Mass of the CEV is = 7250 kg.
Initial speed of the CEV is = 7.65 m/s
Hence, deceleration of the CEV is = ( 426000 N ÷ 7250 kg) = 58.75 m/s²
Hence, required stopping time = 7.65 m/s ÷ 58.75 m/s² = 0.13 second.
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How far will a car travel in half an hour at
30 mph?
Answers
Answer:
The car will travel the distance of 15 miles
S= D/T
therefore
D=ST
D = Distance
S = Speed (30 mph)
T = Time (0.5 Hours)
D = 30 * 0.5 = 15
Can you think of a way to explain Hubble's Law other than the
standard Big Bang idea, which includes the concept of a Universe
with no center and no edge?
Answers
An alternative way to explain Hubble's Law without relying on the standard Big Bang idea of a universe with no center and no edge is through the concept of a "tired light" hypothesis.
According to this hypothesis, the redshift observed in distant galaxies is not due to their motion away from us in an expanding universe, but rather the result of photons gradually losing energy as they travel through space.
In the tired light scenario, the wavelength of light is thought to stretch over time due to interactions with matter or other unknown processes. As a result, the light from distant galaxies appears redshifted, mimicking the effect of cosmic expansion. This explanation implies that the universe may have a finite size and a center, challenging the notion of an infinite and uniformly expanding universe.
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According to the principle that the emission lines of a substance must be at exact same positions of its absorption spectrum, what substance accounts for the dark lines in the absorption spectrum
Answers
Answer:
The dark lines in absorption spectrum of light is due capacity of atoms to absorb light of a specific energy. The absorption of light by atoms occurs when the atom transitions from a lower energy or ground state to an excited high energy state, and it appears in the emission spectrum of the element as dark lines located in the same position as the bright lines
Explanation:
A runner runs around a track consisting of two parallel lines 96 m long connected at the ends by two semicircles with a radius of 49 m. He completes one lap in 2.0 minutes. What is his average speed?
Answers
The total distance covered in one lap consists of two straight segments and two semicircles. The runner's average speed is approximately 403.92 meters per minute.
To calculate the runner's average speed, we need to determine the total distance covered in one lap and divide it by the time taken.
1. Calculate the distance covered in the straight segments:
Distance_straight = 2 * 96 m
2. Calculate the distance covered in the semicircles:
Circumference_semicircle = 2 * π * radius
Distance_semicircle = 2 * Circumference_semicircle
Distance_semicircle = 2 * π * 49 m
3. Calculate the total distance covered in one lap:
Total_distance = Distance_straight + Distance_semicircle
4. Divide the total distance by the time taken to get the average speed:
Average_speed = Total_distance / Time
Now, let's calculate the values:
Distance_straight = 2 * 96 m = 192 m
Circumference_semicircle = 2 * π * 49 m ≈ 307.92 m
Distance_semicircle = 2 * 307.92 m = 615.84 m
Total_distance = Distance_straight + Distance_semicircle
Total_distance = 192 m + 615.84 m = 807.84 m
Time = 2.0 minutes
Average_speed = Total_distance / Time
Average_speed = 807.84 m / 2.0 min ≈ 403.92 m/min
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Choose a tap or water source at your business or home and
determine the flow rate in litres per minute. Describe the details
of the experiment you conducted to determine this flow rate.
Answers
To determine flow rate, I conducted an experiment by measuring the volume of water collected in a container over a specific period of time.
To determine the flow rate of water from a tap or water source, I followed a simple experiment using a container and a stopwatch. First, I selected a suitable container with known volume markings, such as a measuring jug. Then, I placed the container under the tap and ensured it was positioned securely to collect all the water without any spillage.
Next, I turned on the tap to its maximum flow and started the stopwatch simultaneously. I allowed the water to flow into the container for a specific duration, such as one minute, to ensure accurate measurements. During this time, I made sure to avoid any disruptions or obstructions to the water flow.
Once the predetermined time elapsed, I stopped the stopwatch and carefully measured the volume of water collected in the container. It is essential to ensure accurate measurements by aligning the container with the appropriate volume markings and checking from eye level.
By dividing the measured volume of water by the duration of time in minutes, I calculated the flow rate in liters per minute. For instance, if 1 liter of water was collected in one minute, the flow rate would be 1 liter/minute.
To improve the accuracy of the flow rate measurement, it is advisable to repeat the experiment multiple times and calculate the average flow rate. Additionally, it is important to note that the flow rate can vary depending on factors such as water pressure, pipe diameter, and any obstructions in the plumbing system. Regular maintenance and inspection of the tap or water source can help ensure optimal flow rates.
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How much brighter is a sun-like star than the reflected light from a planet orbiting around it?.
Answers
It is about a billion times brighter.
What is the brightness of a star called?A star's apparent magnitude, or how bright it seems to be from Earth, and absolute magnitude, or how brilliant it looks at a standard distance of 32.6 light-years, or 10 parsecs, are words used by astronomers to describe stellar brightness. How bright are planets compared to stars?Although planets and stars light up the night sky, planets usually appear much brighter than most stars. Astronomers use astronomical scales to measure the relative brightness of celestial bodies, and many planets fall within the range easily visible to the eye.To learn more about planets from the given link
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ability of the muscles to function effectively and efficiently without undue fatigue
Answers
Physical fitness can be defined as the “ability to carry out daily tasks with vigor and alertness, without undue fatigue, and with ample energy to enjoy leisure-time pursuits and to meet unforeseen emergencies” (Park 1989).