The magnitude of electric charge on each plate of the capacitor can be found using the formula Q = CV, where Q is the charge on the plate, C is the capacitance of the capacitor, and V is the applied voltage.
The capacitance of a parallel plate capacitor can be calculated using the formula C = εA/d, where ε is the permittivity of the medium between the plates, A is the area of each plate, and d is the distance between the plates.
In this case, the plates are square with a side length of L - 10 cm, so the area of each plate is (L - 10 cm)². The distance between the plates is given as d - 2 mm, or 0.2 cm. The permittivity of free space is 8.85 x 10^-12 F/m.
Therefore, the capacitance of the capacitor can be calculated as:
C = εA/d = (8.85 x 10-¹²F/m)(L - 10 cm)²/(0.2 cm) = 3.51 x 10-¹¹(L - 10 cm)² F
Using the given voltage of 8 V, the charge on each plate can be calculated as:
Q = CV = (3.51 x 10-¹¹(L - 10 cm)² F)(8 V) = 2.808 x 10-¹(L - 10 cm)² C
Therefore, the magnitude of electric charge on each plate of the capacitor is 2.808 x 10(L - 10 cm)² C.
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A 25.0 kg door is 0.925 m wide. A customer
pushes it perpendicular to its face with a 19.2
N force, and creates an angular acceleration
of 1.84 rad/s2. At what distance from the axis
was the force applied?
[?] m
Hint: Remember, the moment of inertia for a panel
rotating about its end is I = mr².
The distance from the axis of the force applied is 2.05 m.
What is the distance from the axis of the force applied?The distance from the axis of the force applied is calculated as follows;
The formula for torque;
τ = Fr
where;
F is the applied forcer is the distance from the axis of the force appliedAnother formula for torque is given as;
τ = Iα
where;
I is the moment of inertia of the doorα is the angular acceleration;τ = (mr²)α
τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)
τ = 39.36 Nm
The distance is calculated as;
r = τ/F
r = ( 39.36 Nm ) / (19.2 N)
r = 2.05 m
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The electric field 0.385 m from a very long uniform line of charge is 810 N/C
How much charge is contained in a section of the line of length 2.50 cm?
The charge contained in a section of the line of length 2.50 cm is 8.87 × 10⁻¹⁰ C.
The formula for electric field intensity of a line charge is given by:E= λ/2πε₀rwhere,λ is the linear charge density of the line.ε₀ is the permittivity of free space.r is the perpendicular distance of the point from the line charge.
Electric field intensity, E = 810 N/CandDistance, r = 0.385 mUsing the above formula, we can find the value of linear charge density of the line.λ = 2πε₀Erλ = 2 × π × 8.85 × 10⁻¹² × 810 × 0.385λ = 3.55 × 10⁻⁸ C/mLength of the section of the line, L = 2.5 cm = 0.025 mWe need to find the charge present in a section of the line of length 2.50 cm.Since the linear charge density of the line is 3.55 × 10⁻⁸ C/m,Charge in a section of the line of length 0.025 m = λLq = λLq = 3.55 × 10⁻⁸ × 0.025q = 8.87 × 10⁻¹⁰ C
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A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
Answer:
Explanation:
is this marked??
(a). The car's average velocity between t = 1.0s to t = 1.5s will be - \(1\;m/s\)
(b). The car's acceleration at t = 1.5s will be - \(0.4\;m/s^{2}\)
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
The car's average velocity (in m/s) in the interval between -t = 1.0 s to t = 1.5 s.
The car's acceleration at t = 1.5 s.Determining whether car's speed increasing or decreasing with time.What is Acceleration?The rate of change of velocity with respect to time is called Acceleration. Mathematically -
\($a=\frac{dv}{dt}\)
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
\($v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s\)
PART - B
Velocity at t = 1.5 s will be -
\($v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s\)
The car's acceleration at t = 1.5s will be -
\($a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}\)
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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What is the frequency of a wave that passes a given point 412 times in 4.0
seconds?
O A. 0.0097 s
OB. 103 Hz
O C. 408 S
O D. 1650 Hz
SUBMIT
Answer: A.0,0097s
Mas a unidade aí deveria ser Hertz (Hz)
Explanation:
Answer:
103 hz
Explanation:
Native Americans boiled water by adding very hot stones to a leak-tight water vessel.What minimum number of 1.0 kg stones at 490 ∘C must be added to a vessel holding 7.0 kg of 20∘C water to bring the water to a boil? Use 800 J/(kg⋅K) for the specific heat of the stones and 4190 J/(kg⋅K) for the specific heat of water.
We need at least 8 stones at 490 ∘C to bring 7.0 kg of 20∘C water to a boil using the Native American method.
To calculate the minimum number of 1.0 kg stones at 490 ∘C needed to bring 7.0 kg of 20∘C water to a boil, we need to use the following formula:
Q = \(m * c * ΔT\)
where Q is the heat required to raise the temperature of the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.
We can assume that the stones will transfer all their heat to the water, so we can use the same formula for them:
Q =\(m * c * ΔT\)
where m is the mass of the stones, c is the specific heat of the stones, and ΔT is the change in temperature.
To bring the water to a boil, we need to raise its temperature from 20∘C to 100∘C, which is a change of 80∘C. So:
Qwater = \(7.0 kg * 4190 J/(kg⋅K) * 80∘C\)
Qwater = 2,955,200 J
To calculate the amount of heat the stones will provide, we need to use the same formula:
Qstones = \(m * c * ΔT\)
We don't know the mass of the stones yet, so let's assume we need n stones, each with a mass of 1.0 kg:
Qstones = \(n * 1.0 kg * 800 J/(kg⋅K) * (490 - 100)∘C\)
Qstones = 392,000 n J
To bring the water to a boil, we need the total heat provided by the stones to be equal to the heat required by the water:
Qstones = Qwater
392,000 n J = 2,955,200 J
n = 7.55
So we need at least 8 stones at 490 ∘C to bring 7.0 kg of 20∘C water to a boil using the Native American method.
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The heliocentric model Group of answer choices was supported by Johannes Kepler's observation that planets follow an elliptical orbit. was developed by Ptolemy and supported by his mathematical equations. states that the Earth is the center of the Universe, and the Moon and planets revolve around it. was widely accepted during the Middle Ages (about 476-1400 C.E.).
The heliocentric model states that the Sun is the center of the solar system, with the planets and other celestial objects orbiting around it. This model was developed by Nicolaus Copernicus in the 16th century and was supported by Johannes Kepler's observation that planets follow an elliptical orbit.
The geocentric model, on the other hand, states that the Earth is the center of the Universe, and the Moon and planets revolve around it. This model was widely accepted during the Middle Ages and was developed by Ptolemy. He was an astronomer from Alexandria, Egypt, and his model was supported by his mathematical equations.
In summary, the heliocentric model is the correct model of the solar system, with the Sun at the center. It was developed by Copernicus and supported by Kepler's observations, while the geocentric model, developed by Ptolemy, placed the Earth at the center and was widely accepted during the Middle Ages.
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a solid uniform sphere of mass 1.85 kg and diameter 45.0 cm spins about an axle through its center. starting with an angular velocity of 2.40 rev/s, it stops after turning through 18.2 rev with uniform acceleration. the net torque acting on this sphere as it is slowing down is closest to
The net torque acting on this sphere as it is slowing down is closest to -0.0299 N m.
The moment of inertia of a solid uniform sphere about an axis through its center is (2/5)MR², where M is the mass of the sphere and R is its radius. In this case, the sphere has a mass of 1.85 kg and a diameter of 45.0 cm, so its radius is 0.225 m. Therefore, its moment of inertia is:
I = (2/5)(1.85 kg)(0.225 m)² = 0.02356 kg m²
The initial angular velocity of the sphere is 2.40 rev/s, which is equivalent to:
ω_i = 2π(2.40 rev/s) = 15.08 rad/s
The final angular velocity of the sphere is 0 rad/s since it comes to a stop. The angular displacement of the sphere during this time is:
θ = 18.2 revs x 2π = 114.34 rad
The final angular velocity is related to the initial angular velocity, angular displacement, and acceleration by the equation:
ω_f² = ω_i² + 2αθ
where α is the angular acceleration. Solving for α, we get:
α = (ω_f² - ω_i²) / 2θ = (-15.08²) / (2 x 114.34) = -1.27 rad/s²
The torque acting on the sphere is related to its moment of inertia and angular acceleration by the equation:
τ = Iα
Substituting the values we've calculated, we get:
τ = 0.02356 kg m² x (-1.27 rad/s²) = -0.0299 N m
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Answer: Late answer but, .0372 N m.
Explanation: (Copying explanation from the other answer, with correct math:) The moment of inertia of a solid uniform sphere about an axis through its center is (2/5)MR², where M is the mass of the sphere and R is its radius. In this case, the sphere has a mass of 1.85 kg and a diameter of 45.0 cm, so its radius is 0.225 m. Therefore, its moment of inertia is:
I = (2/5)(1.85 kg)(0.225 m)² = 0.03746 kg m²
The initial angular velocity of the sphere is 2.40 rev/s, which is equivalent to:
ω_i = 2π(2.40 rev/s) = 15.08 rad/s
The final angular velocity of the sphere is 0 rad/s since it comes to a stop. The angular displacement of the sphere during this time is:
θ = 18.2 revs x 2π = 114.34 rad
The final angular velocity is related to the initial angular velocity, angular displacement, and acceleration by the equation:
ω_f² = ω_i² + 2αθ
where α is the angular acceleration. Solving for α, we get:
α = (ω_f² - ω_i²) / 2θ = (15.08²) / (2 x 114.34) = 0.99443 rad/s²
The torque acting on the sphere is related to its moment of inertia and angular acceleration by the equation:
τ = Iα
Substituting the values we've calculated, we get:
τ = 0.03746 kg m² x (0.99443 rad/s²) = 0.0372 N m
A passenger jet in the air increases its speed. Does the downward force of air on the top of the wings increase or decrease? Does the net lifting force of the air on the wings increase or decrease? Explain your answer
The downward force of air on top of the wings decreases. The net lifting force of the air on the wings increase. A passenger jet in the air increases its speed.
For which part of the body is Doppler ultrasound most likely to be used in
imaging?
O A. The circulatory system
B. The large and small intestines
C. A broken leg
D. A tumor
Answer: The answer is A! The Circulatory system.
Explanation:
Answer:
A
Explanation:because its right and i just did it hope this helps please mark me
Can someone one help me please !!!
Answer:
Current in the circuit(I) = 0.5 ampere
Explanation:
Given:
Number of resistors = 2 (10 ohm each)
Series of resistors
EMF = 10 volt
Find:
Current in the circuit(I)
Computation:
Total resistance in series = R1 + R2
Total resistance in series = 10 + 10
Total resistance in series = 20 ohm
Current in the circuit(I) = EMF / Total resistance in series
Current in the circuit(I) = 10 / 20
Current in the circuit(I) = 0.5 ampere
5. A ball rolls off a 1.5 m tall horizontal table and lands on the floor 0.70 m away.
A. How much time is the ball in the air?
B. How does that time compare with the time it takes for a dropped ball to fall that same distance.
C. What is the ball's velocity while it was on the table top?
D. What is the horizontal component of its velocity just prior to impact?
E. What is the vertical component of its velocity just prior to impact?
F. What is the magnitude of its velocity just prior to impact?
G. What is the direction of its velocity just prior to impact?
Take the starting position of the ball 1.5 m above the floor to be the origin. Then at time t, the ball's horizontal and vertical positions from the origin are
x = v₀ t
y = -1/2 gt²
where v₀ is the initial speed with which it rolls off the edge and g = 9.8 m/s².
A. The floor is 1.5 m below the origin, so we solve for t when y = -1.5 m :
-1.5 m = -1/2 gt²
⇒ t² = (3.0 m)/g
⇒ t = √((3.0 m)/g) ≈ 0.55 s
B. It would take the same amount of time.
C. The ball travels a horizontal distance of 0.70 m before reaching the floor, so we solve for v₀ with t = 0.55 s :
0.70 m = v₀ (0.55 s)
⇒ v₀ = (0.70 m) / (0.55 s) ≈ 1.3 m/s
D. At time t, the ball has horizontal and vertical velocity components
v[x] = 1.3 m/s
v[y] = -gt
so the horizontal component of the ball's final velocity vector is the same as the initial one, 1.3 m/s.
E. The vertical component of velocity would be
v[y] = -g (0.55 s) ≈ -5.4 m/s
F. The magnitude of the final velocity would be
√((1.3 m/s)² + (-5.4 m/s)²) ≈ 5.6 m/s
G. The final velocity vector makes an angle θ with the horizontal such that
tan(θ) = (-5.4 m/s) / (1.3 m/s)
⇒ θ = arctan(-5.4/1.3) ≈ -77°
i.e. approximately 77° below the horizontal.
a series circuit has one 10 ohm resistor and 15 ohms of inductive reactance in a single inductor. what is the apparent power (total volt-amps) of this circuit.
The result is ,(a) Z = sqrt((10^2) + (15^2)) = 18.03 ohms.
(b) the apparent power would be S = (120 V) x (1 A) = 120 VA.
To find the apparent power (total volt-amps) of a series circuit with a 10 ohm resistor and 15 ohms of inductive reactance in a single inductor, we first need to calculate the impedance of the circuit.
Impedance is the total opposition to current flow in an AC circuit and is a combination of resistance and reactance. In this case, we can use the formula Z = sqrt(R^2 + XL^2), where R is the resistance and XL is the inductive reactance.
To find the apparent power (S) of the circuit, we use the formula S = Vrms x Irms, where Vrms is the root mean square voltage and Irms is the root mean square current. Since we are not given any values for voltage or current, we cannot find the exact value of apparent power.
However, we can make some assumptions based on typical values for household circuits. For example, if the voltage is 120 volts (typical in the US) and the current is 1 amp,
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A small insect travels a distance of 24 cm in a time of 4.0 minutes. Calculate the average speed of the insect in m s −1
Explanation:
(24 cm / 4.0 min) × (1 min / 60 s) × (1 m / 100 cm) = 0.001 m/s
What is the concentration of a solution made by diluting 15 ml of 6. 0 m hcl to a final volume of 750 ml?.
The concentration of a solution made by diluting 15 ml of 6. 0 m hcl is 0.12 M
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
Given,
C₁ = 6. 0 m hcl
V₁ = 15 ml = 0.015 l
C₂ = ?
V₂ = 750 m = 0.75 L
C₁V₁ = C₂V₂
C₂ = C₁V₁ / V₂
= 6 × 0.015 / 0.75
= 0.12 M
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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2.50 x 105 kg/m•s2 corresponds to which pressures?
2.50 x 105 kg/m•s2 is a measurement of force per unit area, known as pressure.
To determine the corresponding pressure, we need to divide the force by the area it is acting upon. Without knowing the specific area, we cannot calculate the pressure. Therefore, we need additional information to provide an accurate answer. However, it is important to note that the unit for pressure in the International System of Units (SI) is the pascal (Pa), which is defined as 1 Newton per square meter (N/m2). Therefore, any measurement of force per unit area can be converted to pascals for easier comparison and understanding.
The given value, 2.50 x 10^5 kg/m•s^2, represents pressure since it has units similar to Pascal (Pa), which is the standard unit for pressure. Pressure is defined as the force applied per unit area (P = F/A), and its unit can be expressed as kg/(m•s^2) or N/m^2, which is equivalent to Pascal. In this case, the pressure corresponds to 2.50 x 10^5 Pa. It is important to note that pressure can also be measured in other units, such as atmospheres (atm) or millimeters of mercury (mmHg), but the given value is in Pascals.
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2. What angular acceleration is necessary to increase the angular speed of a
fan blade from 8.5 rad/s to 15.4 rad/s in 5.2 s?
The angular acceleration necessary to increase the angular speed of the fan blade from 8.5 rad/s to 15.4 rad/s in 5.2 s, is 1.3 rad/s²
How do i determine the angular acceleration?The know that acceleration is defined by the following formula:
a = (v – u) / t
a is the acceleration v is the final velocity u is the initial velocity t is the timeWith the above formula, we can determine the angular acceleration needed. Details below:
Initial angular speed (u) = 8.5 rad/sFinal angular speed (v) = 15.4 rad/sTime (t) = 5.2 s Angular acceleration (a) =?a = (v – u) / t
a = (15.4 – 8.5) / 5.2
a = 6.9 / 5.2
a = 1.3 rad/s²
Thus, we can conclude that the angular acceleration needed is 1.3 rad/s²
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Which one illustrates it?
A) III
B) II
C) I
D) IV
Circuit diagram number II
I) R=(4*8)/(4+8)=8/3 Ω
II) R=4+((4*4)/(4+4))= 6 Ω
III) R= 4/3 Ω
IV) the same as I: 8/3 Ω
You drop a 5 kg ball from a height of 2 m. Just
before it reaches the ground, how much kinetic
energy does it have?
Answer:
Kinetic energy = 98 N
Explanation:
Given:
Mass = 5 kg
Height = 2 m
Find:
Kinetic energy
Computation:
K(e) = P(e)
So,
P(e) = mgh
So,
K(e) = (5)(9.8)(2)
Kinetic energy = 98 N
Can someone please help me
Answer:
I don't know the answer but I needed the answer to that on a quiz and I downloaded sorcatic and it brings u to an app or website with the answer I hope this helps if you can't find the app than just tell me
what issue did the Great Compromise address
The issue did the Great Compromise address is congressional representation. During the 1787 Constitutional Convention, there was a contentious debate about congressional representation: States with bigger populations desired representation based on population, while smaller states demanded equal representation.
What are the problem did the Great Compromise address?During the 1787 Constitutional Convention, there was a contentious debate about congressional representation: States with bigger populations desired representation based on population, while smaller states demanded equal representation.
Due to the inclusion of both proportional and equal representation, the Great Compromise provided a solution to the representation issue. Large states received proportionate representation in the House, while tiny states received equal representation in the Senate.
The Connecticut Compromise, often referred to as the Great Compromise of 1787 or the Sherman Compromise, was a decision made at the 1787 Constitutional Convention that, in part, determined the legislative system and the level of representation each state would get under the new federal government.
Therefore, the correct answer is option A. congressional representation.
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two objects have a 1d head-on collision. object one has a mass m and velocity 2v to the right while object two has mass 4m and velocity v to the left. the final velocity of object two is v/5 to the right. let the right be the positive direction. determine the final velocity of object one and identify the type of collision.
The final velocity of object one is 2v/5 to the right, and the collision is an elastic collision.
What are the final velocities of the objects in the head-on collision with different masses?In a head-on collision between two objects, object one has a mass of "m" and an initial velocity of "2v" to the right, while object two has a mass of "4m" and an initial velocity of "v" to the left. We are given that the final velocity of object two is "v/5" to the right.
To determine the final velocity of object one, we can apply the law of conservation of momentum.
In a collision, the total momentum before the collision is equal to the total momentum after the collision, provided no external forces are acting on the system. The momentum is given by the product of mass and velocity.
Initially, the total momentum is given by (2m)(2v) - (4m)(v) since object one is moving to the right and object two is moving to the left. This simplifies to 4mv - 4mv = 0.
After the collision, the total momentum is given by (2m)(v1) + (4m)(v2/5), where v1 and v2 are the final velocities of object one and object two, respectively.
Applying the law of conservation of momentum, we have:
0 = (2m)(v1) + (4m)(v2/5)
0 = 2mv1 + (4m)(v/5)
0 = 2mv1 + 4mv/5
0 = 10mv1 + 4mv
0 = 14mv1 + 4mv
To solve for v1, we isolate it on one side of the equation:
-4mv = 14mv1
v1 = -4mv / 14m
v1 = 2v/5
Therefore, the final velocity of object one is 2v/5 to the right. The collision between the two objects is an elastic collision since both momentum and kinetic energy are conserved.
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PHYSICS HELP!!! 100POINTS !!! PLUS BRAINIEST IF CORRECT!!!
Three masses are arranged in the (x, y) plane
as shown.
What is the magnitude of the resulting
force on the 2 kg mass at the origin? The
value of the universal gravitational constant
is 6.6726 × 10−11 N · m2
/kg2
.
Answer in units of N.
The magnitude of the force of gravity that is acting on the objects is 1.33 × 10^−10 N.
What is the force that acts on the bodies?We know that the gravitational force is an attractive force that acts on all the objects that do exist in the universe. Thus, once body lies within the gravitational field of the earth this force of gravity can be said to act on the object. We have in the question two objects that are positioned on the cartesian coordinates as shown. The distance between the objects is 2 m.
Using the formula;
F = Gm1m2/r^2
F = gravitational force
G = gravitational constant
m1 and m2 = masses of the objects
r = distance of separation
Then we have;
F = 6.6726 × 10^−11 * 4 * 2/(2)^2
F = 1.33 × 10^−10 N
Thus the attractive force has a magnitude of 1.33 × 10^−10 N.
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the wavelength of a laser light is 372.6 nm in air. what is the wavelength of the laser light in a transparent medium that has an index of refraction of 2.08 in units of nm?
The wavelength of the laser light in a transparent medium is 234.70 nm.
What is the Refractive index?Wavelength can affect the refractive index. White light is refracted as a result and separated into its component hues.Dispersion is the term for this. Prisms, rainbows, and chromatic aberration in lenses are all examples of this effect.A complex-valued refractive index can be used to explain how light moves through absorbing materials.After then, the imaginary part takes care of attenuation, and the real part takes care of refraction.Across the visible spectrum, the refractive index varies with wavelength for the majority of materials by several percent.However, the refractive indices of materials are frequently reported using a single value for n, which is normally determined at 633 nm.From X-rays to radio waves, the refractive index principle is applicable to the entire electromagnetic spectrum.We know that the refraction index, n, is defined as the ratio of the wavelength in the vacuum to the wavelength in the medium.
n = λ / λₓ
Given that
n = refraction index = 2.08
λ = wavelength of the laser light in air = 372.6 nm.
λₓ = wavelength of the laser light in a transparent medium
We know that
refraction index = wavelength of the laser light in air /λₓ
2.34 = 549.2 nm/λₓ
λₓ=234.70 nm
Therefore, the wavelength of the laser light in a transparent medium is 234.70 nm.
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A mass of 0.5kg of water at 10°c is converted into ice at 0°c the specific latent heat of water is 4.2jkg/°c and the specific latent heat of fusion of ice 334jkg the amount of heat refracted from water is
So, the amount of heat refracted from water as it freezes into ice is 146 J.
What is specific latent heat?Specific latent heat is the amount of heat required to change the phase of a unit mass of a substance at a constant temperature. It is a specific quantity, meaning that it is defined for a particular substance and a particular phase change. The term "latent" refers to the fact that the heat is absorbed or released during the phase change, but does not result in a change in temperature of the substance. For example, the specific latent heat of fusion of ice is the amount of heat required to change 1 kilogram of solid ice at 0°C into 1 kilogram of liquid water at 0°C, without changing the temperature of the water. The SI unit for specific latent heat is joules per kilogram (J/kg).
Here,
To calculate the amount of heat refracted from water as it freezes into ice, we need to consider two stages:
Cooling the water from 10°C to 0°C:
The amount of heat lost by the water is given by:
Q1 = m * c * ΔT
where m = 0.5 kg is the mass of water, c = 4.2 J/(kg·°C) is the specific heat capacity of water, and ΔT = (0 - 10)°C = -10°C is the change in temperature.
Thus, Q1 = 0.5 kg * 4.2 J/(kg·°C) * (-10)°C = -21 J (Note that the negative sign indicates heat loss).
Freezing the water at 0°C into ice:
The amount of heat lost by the water is given by:
Q2 = m * Lf
where m = 0.5 kg is the mass of water, and Lf = 334 J/kg is the specific latent heat of fusion of ice.
Thus, Q2 = 0.5 kg * 334 J/kg = 167 J
Therefore, the total amount of heat refracted from water is:
Q_total = Q1 + Q2 = -21 J + 167 J = 146 J
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gauss’s law is useful for calculating electric fields that are , true
This claim is accurate because, assuming the electric field on the normal distribution surface is uniform, the field may be calculated by dividing Q enclosed/e0 by area.
What is the explanation of the electric field?The value per unit particles that is applied to describe the electromagnetic field analytically is just the force per tonne of production applied on a test charge that is located rest at a certain place. An electric field can be created by an electric charge or a magnetic field with varying amplitudes.
Can a person sense an electric field?While it has long been recognized that cells in animals and even humans can perceive and respond to electromagnetic fields, the precise mechanism by which cells do so has remained somewhat obscure and the focus of current study.
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3. Use the simulation to predict where you think the magnet’s magnetic field was
strongest. Explain your answer.
Magnetic field is stronger at the poles whereas weaker at the center.
The magnetic field on the bar magnet is strongest at the poles because the field lines are most concentrated at the poles while on the other hand, the magnetic field is weaker in the central part of magnet.
Magnetic field has equal amount of strength at both the poles so in my opinion as well as scientific point of view, magnet field is stronger at the poles and weaker at the center of magnet.
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can someone please help i will name brainliest
Answer:
dang it its so long :(
Explanation:
During a 980. miles cruise, a ship travelled 590 miles in 7 hours first. Then the ship changed its speed for the rest of the trip. If 13 hours were spent on the whole cruise, what was the speed for the rest of the trip? mph
Explanation:
The average speed of a modern cruise ship is roughly 20 knots (23 miles per hour), with maximum speeds reaching about 30 knots (34.5 miles per hour).
HELP ME PLEASE!!!!!!!
Jessica did an investigation about the states of matter. As part of the investigation, Jessica wanted to change a liquid into a solid. What must she do to bring about this change in state?
place the liquid in a different container
A
B
stir the liquid as quickly and thoroughly as possible
C
remove energy from the liquid so that its particles slow down
D
increase the energy of the liquid so that its particles move faster
Answer:
D : Increase the energy of the liquid so that its particles move faster
Explanation:
Sorry the other guy was wrong can i have brailiest please.