Answer: (a) The fundamental frequency of an organ pipe can be calculated using the formula:
f1 = v / (2L)
where f1 is the fundamental frequency, v is the speed of sound in air, and L is the length of the pipe.
Given that the musician measured two adjacent tones at 532 and 684 Hz, these correspond to the first harmonic (fundamental frequency) and the second harmonic (first overtone) respectively. The frequency of the second harmonic is twice the frequency of the fundamental frequency.
So, f1 = 532 Hz / 2 = 266 Hz
The fundamental frequency of the pipe is 266 Hz.
(b) Based on the given information, since the musician measured two adjacent tones, the frequencies of which are in the ratio of 1:2 (532 Hz and 684 Hz), this indicates that the pipe is open at both ends. In open-ended pipes, such as organ pipes, both ends are free to vibrate, allowing for the presence of odd harmonics (1st, 3rd, 5th, etc.) in addition to the even harmonics (2nd, 4th, 6th, etc.).
(c) To calculate the length of the pipe, we can use the formula:
L = v / (4f1)
where L is the length of the pipe, v is the speed of sound in air, and f1 is the fundamental frequency.
Given that the temperature is 20°C, the speed of sound in air at this temperature is approximately 343 m/s.
Plugging in the values, we get:
L = 343 m/s / (4 x 266 Hz) ≈ 0.808 m
So, the length of the pipe is approximately 0.808 meters.
What forces are considered when we examine interactions between two objects in a closed, isolated system
Given what we know, we can confirm that when dealing with a closed and isolated system, the forces to be considered in the system are internal forces.
What is a closed system?It is a system that does not interact with the environment or its surroundings.A closed system is described as to not interchange energy of any form. Therefore, all forces present are internal in nature.Therefore, we can confirm that because a closed system is one that does not interact with the environment or its surroundings, any forces to be considered will be internal in nature.
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In many cartoon shows, a character runs of a cliff, realizes his predicament and lets out a scream. He continues to scream as he falls. If the physical situation is portrayed correctly, from the vantage point of an observer at the foot of the cliff, the pitch of the scream should be Group of answer choices
Answer:
Increasing until terminal velocity is reached
Explanation:
Provided the scream is a constant pitch at the source, Doppler effect will make the pitch increase as the velocity of the source towards the listener increases.
1 question I still have about Baroque music
Answer:
yes
Explanation:
yesim guessing that yes u still have
Answer:
Baroque Music:
Baroque music is another way to refer to Western classical music composed between approximately 1600 and 1750. Some of the most famous Baroque music composers included Bach, Handel, and Vivaldi.
pa follow at pa brainlest answer na den
write down importance of acquiring the knowledge of science in light of Quran
Answer:
The Importance of Knowledge in the Quran: The Importance of Seeking Knowledge
A narration from the Holy Prophet Muhammad (peace be on him and his household) states:
طَلَبُ الْعِلْمِ فَرِيضَةٌ عَلَى كُلِّ مُسْلِمٍ وَ مُسْلِمَة
Seeking knowledge is an obligation for every Muslim man and woman 2
Many verses of the Quran also speak of gaining knowledge and learning. For example, the following verse:
وَمَا أَرْسَلْنَا قَبْلَكَ إِلَّا رِجَالًا نُّوحِي إِلَيْهِمْ ۖ فَاسْأَلُوا أَهْلَ الذِّكْرِ إِن كُنتُمْ لَا تَعْلَمُونَ ﴿7﴾
We did not send [any apostles] before you except as men to whom We revealed. Ask the People of the Reminder if you do not know. 3
what is the physics behind why electric parallel plates move from positive to negative
The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.
Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.
What are electric parallel plates?When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.
The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.
In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.
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When 560,000 is written in scientific notation, what is the power of 10? 4 5 6 7
Answer: hey!
i believe your answer is 5
have a nice day :)
Explanation:
Answer:
The answer is 5
A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?
Answer:
cos 0 = 1.
Fs = 7×8 = 56 J
Explanation:
Analyzing the Relationship between Variables
Which graph represents a nonlinear relationship?
40
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30
20
20
20
20
10
10
10
10
0
0
0
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o
The graph that represents non linear relationship is the graph in D
How does graph of non linear relationship look likeThe graph of a non-linear relationship is not a straight line, unlike a linear relationship. Instead, the graph of a non-linear relationship can take on various shapes, depending on the nature of the relationship between the variables.
For example, a quadratic relationship, which is a type of non-linear relationship, produces a graph that is a curve, typically in the shape of a "U" or an inverted "U". In a quadratic relationship, as one variable increases, the other variable changes at an accelerating rate.
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How can 2-phenylethanoic acid can be prepared from toluene?
Answer: C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)
Explanation:
2-Phenylethanoic acid, also known as phenylacetic acid, can be prepared from toluene through the following steps:
Bromination: Toluene is brominated using Br2 and FeBr3 as a catalyst to form 2-bromotoluene.
Grignard reaction: The 2-bromotoluene is reacted with magnesium (Mg) in dry ether to form phenylmagnesium bromide (C6H5MgBr).
Acidification: The phenylmagnesium bromide is then reacted with carbon dioxide (CO2) to form 2-phenylpropanoic acid (also known as phenylpropionic acid). This reaction is carried out by bubbling CO2 gas through the solution of phenylmagnesium bromide in dry ether.
Oxidation: The 2-phenylpropanoic acid is then oxidized using a strong oxidizing agent, such as potassium permanganate (KMnO4) or chromic acid (H2CrO4), to form 2-phenylethanoic acid.
The overall reaction can be represented as follows:
C6H5CH3 (toluene) + Br2 + Mg + CO2 + oxidizing agent → C6H5CH2COOH (2-phenylethanoic acid)
Note: This is a complex reaction sequence and should only be attempted by experienced chemists in a well-equipped laboratory with appropriate safety measures.
help pls!!
Fig above shows a wave traveling through a medium. Use the fig to answer the questions below.
A) What is the amplitude of the wave ? Include correct units.
B) Use the graph to determine the time of one wave. Use it to find the frequency.
C) If the speed of the wave is 25 cm/s, what is the wavelength of the wave ? Show data listing, equation , substitution leading to the answer for full credit.
(a) The amplitude of the wave is determined as 8 cm.
(b) The period of the wave motion is 20 s and the frequency of the wave is 0.05 Hz
(c) The wavelength of the wave is 500 cm.
What is the amplitude of the wave ?(a) The amplitude of the wave is the maximum displacement of the wave.
from the graph, amplitude of the wave = 8 cm
(b) The period of the wave motion is calculated as;
T = 20 s
The frequency of the wave = 1/T = 1/20 s = 0.05 Hz
(c) The wavelength of the wave is calculated by applying the following wave formula.
λ = v / f
λ = 25 cm/s / 0.05 Hz
λ = 500 cm
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Susan drops her camera in the river from a bridge that 250 feet high. How long does it take the camera to fall 250 feet
Answer:
It takes 4 seconds for the camera to fall 250 feet
Explanation:
4 seconds by using the quadratic formula
Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A) =. 30 and P(B) = .50...
According to the statement, on the assumption of requesting help from a statistical software consultant, the given case that P(A) + P(B) = 1 is not true, since A and B are not mutually exclusive events.
It is possible for the next request to be related to both SPSS and SAS, in which case it would be included in both A and B. Therefore, we cannot simply add their probabilities to get the total probability of either event.
B. P(A') represents the probability that the next request is NOT related to the SPSS package. We can find this by subtracting P(A) from 1, since the sum of the probabilities of an event and its complement is always equal to 1:
P(A') = 1 - P(A) = 1 - 0.30 = 0.70
Therefore, the probability that the next request is NOT related to SPSS is 0.70.
C. P(A ∪ B) represents the probability that the next request is related to either SPSS or SAS or both. We can find this by using the formula:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
Where P(A ∩ B) represents the probability that the next request is related to both SPSS and SAS. Since we don't have information about the probability of this intersection, we cannot calculate P(A ∪ B) exactly. However, we know that the probability of the intersection must be between 0 and the minimum of P(A) and P(B), which in this case is 0.30. Therefore, we can say:
0 ≤ P(A ∩ B) ≤ 0.30
and use this range to get a lower and upper bound for P(A ∪ B):
P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≤ 0.30 + 0.50 - 0 = 0.80
P(A ∪ B) = P(A) + P(B) - P(A ∩ B) ≥ 0.30 + 0.50 - 0.30 = 0.50
Therefore, the probability that the next request is related to either SPSS or SAS (or both) is between 0.50 and 0.80.
D. P(A' ∩ B') represents the probability that the next request is NOT related to either SPSS or SAS. We can find this using the formula:
P(A' ∩ B') = P((A ∪ B)')
Where (A ∪ B)' represents the complement of the event that the next request is related to either SPSS or SAS (or both). We can find (A ∪ B)' using the formula:
(A ∪ B)' = A' ∩ B'
Which represents the event that the next request is NOT related to either SPSS or SAS. Therefore:
P(A' ∩ B') = P((A ∪ B)') = 1 - P(A ∪ B)
From part c, we know that 0.50 ≤ P(A ∪ B) ≤ 0.80, so:
P(A' ∩ B') = 1 - P(A ∪ B) ≤ 1 - 0.50 = 0.50
P(A' ∩ B') = 1 - P(A ∪ B) ≥ 1 - 0.80 = 0.20
Therefore, the probability that the next request is NOT related to either SPSS or SAS is between 0.20 and 0.50.
Complete question:
Let A denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let B be the event that the next request is for help with SAS. Suppose that P(A) =. 30 and P(B) = .50.
a. Why is it not the case that P(A) + (B) = 1?
b. Calculate P(A ′).
c. Calculate P(A ∪B).
d. Calculate P(A′ ∩B′).
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Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the "if . . . then . . . because . . .” format and be sure to answer the lesson question: "How is potential energy converted to thermal energy in a system?”
Hypothesis, If the mass of the cylinder increases, then the temperature of the water will also increase because an increase in mass leads to greater potential energy, which is converted to thermal energy in the system.
According to the principle of conservation of energy, energy cannot be created or destroyed but can be transformed from one form to another. In this case, potential energy from the mass of the cylinder can be converted into thermal energy in the system. When the cylinder is lifted and submerged in the water, it possesses gravitational potential energy due to its elevated position.
As the cylinder is released and descends into the water, this potential energy is converted into kinetic energy, causing the water molecules to move and collide with higher energy. These collisions generate heat and increase the overall temperature of the water. By increasing the mass of the cylinder, more potential energy is stored.
As a result, there is a greater amount of energy available to be converted into thermal energy when the cylinder is released into the water. Thus, the temperature of the water is expected to increase as the mass of the cylinder increases.
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6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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Someone help me please
Answer:
A
Explanation:
u = 180
v = 0
t = 20
a = 180 /20
9
since they deceleration question itself no need toshow - sign so
A
Q)What is the force between two small charged spheres having charges of 2 × 10^–7C and 3 × 10^–7 C placed 30 cm apart in.
The force that is acting on the spheres is obtained as 0.006 N from the calculation that is done here.
What is the force between the charges?We know that the force can be obtained by the use of the Coulomb's law. From the Coulomb's law, we know that the force that acts for the charges on the charges must be an attractive force as we can see and then we can be able able to use the formula;
F = K\(q_{1}\)\(q_{2}\)/r^2
F = force on the object
K = electric constant
\(q_{1}\) and \(q_{2}\) = magnitude of the charges on the object.
Then we have;
F = 9 * 10^9 * 2 × 10^–7 * 3 × 10^–7 /(30 * 10^-2)^2
F = 54 * 10^ -5/0.09
F = 0.006 N
Thus, it is clear that we have an attractive force that would act on the species and the magnitude of the charged spheres 0.006 N as we can see from the calculation here.
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which of the following is a lever
Answer: the last one
Explanation: it pushes the lid off in a upward motion
Answer:
the last one
Explanation:
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Consider two cars, a 700kg Porsche and a 600kg Honda Civic. The Porsche is speeding along at 40 m/s (mph) and the Civic is going half the speed at 20 m/s. If the two cars brake to a stop with the same constant acceleration, lets look at whether the amount of time required to come to a stop or the distance traveled prior to stopping is influenced by their initial velocity.
1. A car traveling 5m/s slams on its brakes, creating an acceleration of -2 m/s^2. How far did the car travel after it applied its brakes?
2. The same car traveling for 10m/s applies the same acceleration of -2 m/s^2. How far did the car travel after it applied its brakes?
Answer:
Explanation:
To find the distance covered by the car after it applied brakes, we use 3rd equation of motion.
2as = Vf² - Vi²
s = (Vf² - Vi²)/2a
1.
We have:
Vi = Initial Velocity = 5 m/s
Vf = Final Velocity = 0 m/s (Since, car finally stops)
a = deceleration = - 2 m/s²
s = distance covered by the car = ?
Therefore,
s = [(0 m/s)² - (5 m/s)²]/2(- 2 m/s²)
s = 6.25 m
2.
We have:
Vi = Initial Velocity = 10 m/s
Vf = Final Velocity = 0 m/s (Since, car finally stops)
a = deceleration = - 2 m/s²
s = distance covered by the car = ?
Therefore,
s = [(0 m/s)² - (10 m/s)²]/2(- 2 m/s²)
s = 25 m
Hence, the distance traveled by the car is affected by the initial speed in accordance with a direct relationship.
the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
What is the force required to accelerate a 500 kg object at a rate of 10 m/s^2?
Answer:
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
Explanation:
The force required to accelerate an object can be calculated using the formula:
force = mass x acceleration
where "mass" is the mass of the object being accelerated, and "acceleration" is the rate at which the object's velocity is changing.
In this case, the mass of the object is 500 kg, and the acceleration is 10 m/s^2. Plugging these values into the formula gives:
force = mass x acceleration
force = 500 kg x 10 m/s^2
force = 5000 N
Therefore, the force required to accelerate a 500 kg object at a rate of 10 m/s^2 is 5000 Newtons (N).
Answer the following Critical Thinking Questions. Each answer is worth 5 points, for a total of 25 points.
A particular star is 20 pc away from the Earth, and its luminosity is 160 times the luminosity of the Sun and has a surface temperature of 4000 K. Its absolute magnitude is -0.66. The temperature of the Sun is 5800 K. Explain/show your work.
What is this star's parallax?
What is this star's spectral class?
What is the wavelength at which this star radiates the most energy?
What is this star's apparent magnitude?
What is this star's radius, in solar radii?
Question 2-5: You know from Activity 1-1 that an object will slow down if the force applied to the object (and the acceleration) are in the opposite direction to the velocity. Once you release the IOLab, no force is applied to the force sensor. What force is causing the IOLab to slow down
The force that is causing the IOLab to slow down is frictional force between the IOLab and the surface it is moving on.
As the force applied to an object increases, the acceleration of the object increases as well. This applied force is used to overcome the frictional force between the object and the surface it is moving on.
When the force applied to an object reduces, the effect of frictional force increases. This frictional force is the force that reduces the motion of an object.
Thus, we can conclude that the force that is causing the IOLab to slow down is frictional force between the IOLab and the surface it is moving on.
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Answer:I don’t if this helps The force that is causing the IOLab to slow down is frictional force between the IOLab and the surface it is moving on.As the force applied to an object increases, the acceleration of the object increases as well. This applied force is used to overcome the frictional forcebetween the object and the surface it is moving on.When the force applied to an object reduces, the effect of frictional forceincreases. This frictional force is the force that reduces the motion of an object.Thus, we can conclude that the force that is causing the IOLab to slow down is frictional force between the IOLab and the surface it is moving on.
Explanation:
When the displacement of a mass on a spring is 12 A, what percentage of the energy is kinetic energy? At what displacement, as a fraction of A, is the energy half kinetic and half potential?
Answer:
75%
\(\dfrac{A}{\sqrt{2}}\)
Explanation:
x = Displacement of spring = \(\dfrac{1}{2}A=\dfrac{A}{2}\)
k = Spring constant
Total energy of the spring is
\(E=\dfrac{1}{2}kA^2\)
Elastic potential energy is given by
\(U=\dfrac{1}{2}kx^2\\\Rightarrow U=\dfrac{1}{2}k(\dfrac{A}{2})^2\\\Rightarrow U=\dfrac{1}{2}k\dfrac{A^2}{4}\\\Rightarrow U=\dfrac{1}{4}\times \dfrac{1}{2}kA^2\\\Rightarrow U=\dfrac{1}{4}E\)
Total energy is given by
\(E=U+K\\\Rightarrow K=E-U\\\Rightarrow K=E-\dfrac{1}{4}E\\\Rightarrow K=\dfrac{3}{4}E\\\Rightarrow \dfrac{K}{E}=0.75\)
The percentage will be
\(\dfrac{K}{E}=0.75\times 100\%\\\Rightarrow \dfrac{K}{E}=75\%\)
The required percentage is 75%
According to the given condition
\(\dfrac{E}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{\dfrac{1}{2}kA^2}{2}=\dfrac{1}{2}kx^2\\\Rightarrow \dfrac{1}{2}kA^2=kx^2\\\Rightarrow x=\sqrt{\dfrac{1}{2}A^2}\\\Rightarrow x=\dfrac{A}{\sqrt{2}}\)
So, the energy is half when displacement is \(\dfrac{A}{\sqrt{2}}\)
Let x be the displacement of spring which is given to be \(\frac{1}{2} A=\frac{A}{2}\)
k= spring constant
Total energy of the spring is:
\(E=\frac{1}{2} kA^2\)
Elastic potential energy is given as:
\(U=\frac{1}{2} kx^2\)
Now on substituting the value of x in above equation:
\(U=\frac{1}{2} k\frac{A^2}{4}\)
It can also be written as:
\(U=\frac{1}{4} *\frac{1}{2} kA^2 \\\\U=\frac{1}{4} E\) (∵\(E=\frac{1}{2} kA^2\))
Total energy can be written as:
E=U+K
⇒K=E-U
⇒K=E-1/4 E
⇒K=3/4 E
⇒\(\frac{K}{E} =0.75\)
(i) Now, we need to calculate the percentage of kinetic energy:
\(\frac{K}{E} =0.75*100=75\%\)
The percentage of kinetic energy is 75%.
(ii) In second it is asked at what displacement, as a fraction of A, is the energy half kinetic and half potential?
∴\(\frac{E}{2} =\frac{1}{2} kx^2\)
On substituting the value of E in above equation we will get:
\(x=\sqrt{\frac{1}{2} A^2} \\\\x=\frac{A}{\sqrt{2} }\)
So, the energy is half when displacement is \(\frac{A}{\sqrt{2} }\) .
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2 kq kg of ice at -4 degress Celsius is heated at Water at room temperature of 25 degrees Celsius .how much heat is absorbed
Answer:
893.8 [kJ].
Explanation:
1) the total heat can be calculated as
E=Q₁+Q₂+Q₃, where Q₁ - energy to heat the ice from -4 to 0; Q₂ - energy to melt the ice; Q₃ - to heat the water at 0 °C to 25 °C;
2) Q₁=λ*m*Δt₁, ⇒ Q₁=2100*2*4=16800 [J];
3) Q₂=c₂*m; ⇒ Q₂=333500*2=667000 [J];
3) Q₃=c₃*m*Δt₂; ⇒ Q₃=4200*2*25=210000 [j];
4) finally, the required heat is
E=16800+667000+210000=893800 [J]=893.8 [kJ].
A force of 10 Newtons is the only force exerted on a block, and the acceleration of the block is measured. When the same force is the only force exerted on a second block, the acceleration is three times as large. What can you conclude about the masses of the two blocks?
When the acceleration is three times as large, the mass of the new block will be one-third the initial mass.
What is the acceleration of the block?
The acceleration of the block is the rate of change of velocity of the block with time.
The magnitude of the acceleration of each block can be obtained by applying Newton's second law of motion as follows;
F = ma
m = F/a
where;
m is the mass of each blockF is the applied force = 10 Na is the acceleration of each block.When the acceleration is three times as large, the mass of the new block is calculated as;
m = F/3a
m = 1/3 (F/a)
new mass = one-third the initial mass
Thus, we can conclude that when the acceleration is three times as large, the mass of the new block will be one-third the initial mass.
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A plot of land contains 3.6 acres. How many square meters does it contain? [1 acre = 43,560 ft?)
Answer:
It contains approximately 14,568.7 square meters
Explanation:
Area Units Conversion
There are several units to express the area of a shape:
\(cm^2,\ m^2,\ km^2,\ ft^2,\ in^2,\ acres, \ hectares\)
The process of expressing the area from one unit to the other is called a conversion.
Specifically, we are interested in converting from acres to square meters. The rule to make the conversion is:
\(1 acre = 4,046.86\ m^2\)
The plot of land has 3.6 acres, thus its area is:
\(3.6 * 4046.86 =14,568.696\ m^2\)
It contains approximately 14,568.7 square meters
A plane flies along a straight line path after taking off, and it ends up 190 km farther east and 80.0 km farther north, relative to where it
started. What is the plane's displacement?
O 141 km
O 210 km
O 270 km
O 110 km
1 2 3 4 5 6 7 8 9 10
Next ▸
The plane has a 210km displacement value.
The ideal answer is B.
How far is the plane moving?A plane flies straight after takeoff and ends up 190 km to the east and 800.0 km to the north of where it started.
We should use Pythagoras' Theorem to solve this problem.
Distance 2 is calculated as 190^2 + 80^ = 210 km.
which, when rounded, is equivalent to 210 kilometers.
190^2 + 80.0^2 = 45000
√45000
210KM
The displacement of the plane is 210 kilometers.
An object's positional change is referred to as "displacement." It possesses a magnitude and direction as a vector quantity. It is represented by an arrow that leads from the starting point to the destination. An object's position changes, for example, if it moves from position A to position B.
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The energy that a substance contains is
a. equilibrium
b. heat
c. thermal energy
d. entropy
The energy that a substance contains is known as heat. Thus, the correct option for this question is B.
What is Entropy?Entropy may be characterized as the measurement of the degree of randomness or in other words, it is the increase in the disorganization within a system. It is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.
Equilibrium is a state of balance between opposing forces or actions that is either static or dynamic. It symbolizes the circumstance of being balanced in nature.
Thermal energy is a type of energy that is significantly contained within a system that is responsible for its temperature. Heat is the flow of thermal energy.
Therefore, the energy that a substance contains is known as heat. Thus, the correct option for this question is B.
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did theoretical and experimental values agree? if they did not agree, explain why. in newton second law atwoood lab
Conclusion/Discussion In conclusion, we tested the theory of Newton's Second Law of Motion using the Atwood Machine. In order to test the proportionalities the second law suggests, I was able to plot two graphs and successfully calculate the acceleration of each of my trials.
The second law of Newton will be thoroughly investigated in this experiment. According to Newton's second law, force is defined as mass times acceleration (F=mxa). Simply said, his law outlines the connection between an object's mass, acceleration, and required force to move it.
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