A measure of how much the volume of matter decreases under pressure is called compressibility or compressed.
In thermodynamics and fluid mechanics, compressibility (also called compressibility or compressed, if the temperature is held constant, isothermal compressibility) is a measure of the instantaneous relative volume change of a liquid or solid in response to pressure (or average pressure) changes. In its simplest form, compressibility can be expressed as
\(\beta = -\frac{1}{V} \frac{delta V}{delta p}\)
where V is volume and p is pressure. Choose to define compressibility as the negative value of the fraction, so compressibility is positive where (usually) an increase in pressure causes a decrease in volume. The inverse of compressibility at a fixed temperature is called isothermal compressibility modulus.
The compressibility of a fluid is basically a measure of the change in density that a given pressure change will cause in the fluid. Gases, on the other hand, are highly compressible, while most liquids are not.
Compressibility effects can have a major impact on fluid flow. The flow of compressible fluids, commonly known as gas dynamics, is the study of such flows where density and temperature vary significantly.
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The act, process or state of the change in place or position oa a body with respect to time and relative to the observer is said to be :-
1. Rest
2. Stationary
3. Motion
4. None of the above
Answer:
motion
Explanation:
rest and stationary us a situation where an object is constant-not moving
A car, initially at rest, travels from 0 m/s to 18.4 m/s in 27.8 s. What is the car's acceleration?
Take into account that the acceleration of the car can be calculated by using the following expression:
\(a=\frac{v-v_o}{t}\)where,
vo: initial speed = 0m/s
v: final speed = 18.4m/s
t: time = 27.8s
Replace the previous values of the parameters into the formula for a and simplify:
\(a=\frac{18.4\frac{m}{s}-0\frac{m}{s}}{27.8s}\approx0.66\frac{m}{s^2}\)Hence, the acceleration of the car is approximately 0.66m/s^2
why does the pattern shrink with increase energy LEED?
The pattern shrinks with increasing energy in LEED because the electrons are more energetic at higher energies. This means that the electrons can be more deeply penetrating, meaning that they scatter from deeper layers in the material. This results in a decrease in the diffraction spot intensity,
which is why the pattern appears to be shrinking.In LEED (low-energy electron diffraction), electrons are scattered off of a solid surface. This scattering produces a diffraction pattern that can be used to obtain information about the crystal structure of the material.
The energy of the electrons used in LEED is typically quite low, on the order of a few electron volts. As the energy of the electrons is increased, the pattern begins to shrink. This is due to the fact that the electrons become more energetic and can scatter from deeper layers in the material. This results in a decrease in the intensity of the diffraction spots, which is why the pattern appears to shrink. The main answer, therefore, is that the pattern shrinks with increasing energy in LEED because the electrons are more energetic at higher energies.
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A baseball bat strikes a baseball with a force of 35 N. The bat is in contact with the ball for 0. 12 s.
What impulse did the bat exert on the baseball to change the ball's momentum?
Answer:
4.2 N. S
Explanation:
Impulse =Force X Time
35 X 0.12
4.2 N
If we have a velocity of 20 m/s and our acceleration is -5 m/s, then after 2 seconds our velocity will be....
a) 15 m/s
b) 40 m
c) 10 m/s
d) -10 m/s
Answer:
v = 10 m/s
Explanation:
We have,
Our initial velocity is 20 m/s
Our acceleration, \(a=-5\ m/s^2\)
It is required to find the velocity after 2 seconds. It is a concept based on equation of kinematics. Using first equation:
\(v=u+at\)
Plugging all the known values
\(v=20+(-5)(2)\\\\v=10\ m/s\)
So, our final velocity is 10 m/s.
10. Bites of some animals can cause
sprain
tetanus
rables
Answer:
an infection, including bacterial and rabies infections.
broken animal teeth embedded in your wound.
foreign objects embedded in your wound.
possible nerve and blood vessel damage.
If a cannonball were launched with a speed of 35m/s at a 50° angle from the height of 0m, what would be the cannonball's range?
The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.
The launching of a cannonball is a case of projectile motion.
The formula for the range(R) of a projectile is
R = 2 u² sin(θ) cos(θ)/g
Here,
u = initial speed with which the projectile is launched = 35 m/s
θ = Angle at which projectile is launched = 50°
R = 2 (35)² sin(50) cos(50)/ 9.8
R = 2 x 1225 x 0.76 x 0.64/9.8
R = 119.1 m
Thus, The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.
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Given are the major and minor principal stresses at any point within a rock mass σ1 = 50 MPa and σ3 = 20 MPa
Determine graphically the magnitude of the stress components acting on a plane that is inclined at an angle of 25 to the major principal plane
The magnitude of the stress components acting on a plane inclined at an ANGLE of 25° to the major principal plane can be determined graphically using Mohr's circle construction.
1. a horizontal line representing the major principal stress (σ1 = 50 MPa) on a graph paper or a suitable software.2. From the center of the circle, mark a point on the major stress line, representing the major principal stress (50 MPa).
3. Draw a circle with the major stress point as the center and a radius equal to the difference between the major and minor principal stresses [(σ1 - σ3)/2 = (50 - 20)/2 = 15 MPa].4. The circle intersects the horizontal axis at two points. These points represent the maximum and minimum stress components acting on planes perpendicular to the major principal plane.
5. Draw a line at an angle of 25° from the major stress point towards the circumference of the circle.6. The intersection point of this line with the circle represents the stress components acting on the plane inclined at 25° to the major principal plane.
7. Measure the coordinates of this intersection point to determine the magnitudes of the stress components on the inclined plane.
By following these steps, you can construct Mohr's circle and determine graphically the magnitude of the stress components acting on a plane inclined at an angle of 25° to the major principal plane.
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Based on your understanding of galaxy evolution, what patterns would you expect to see among the redshifts of absorption lines from elements other than hydrogen? would they have redshifts similar to those of galaxies along the line of sight to the quasar, or would they be evenly distributed throughout intergalactic space?
Drag the items on the left to the appropriate blanks on the right to complete the sentences. (not all terms will be used.) Elements ___than hydrogen (and helium) are made by ___ and therefore should be located within galaxies. so if we see absorption lines from these elements in quasar spectra, they should have the ___redshifts as hydrogen lines from intervening galaxies. absorption lines may ___ at redshifts of protogalactic clouds that are composed of hydrogen and helium only.
- interstellar gas
- heavier
- stars
- same
- be present
- not be present
- different
- lighter
Elements heavier than hydrogen (and helium) are made by stars and therefore should be located within galaxies.
So if we see absorption lines from these elements in quasar spectra, they should have the same redshifts as hydrogen lines from intervening galaxies. Absorption lines may not be present at redshifts of protogalactic clouds that are composed of hydrogen and helium only. This means that the redshifts of these elements should be similar to the redshifts of the galaxies they are associated with. However, it is possible that absorption lines may be present at redshifts of protogalactic clouds that are composed of hydrogen and helium only. In these cases, the redshifts of heavier elements would be different than the redshifts of the protogalactic clouds and therefore not be present in the spectrum.
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Define measurement and write its importance.
Answer:
Measurement is the way humans define certain amounts of matter, and is expressed in various types of units respective to the type of matter or object being defined.
Explanation:
Measurement is extremely important because it helps one another understand how much of something is needed to accomplish something. If no method existed to define the specific amount needed, we would simply mess delicate operations up and machines, even simple recipes, would fail.
A farsighted man uses contact lenses with a refractive power of 1.80 diopters. Wearing the contacts, he is able to read books held no closer than 0.290 m from his eyes. He would like a prescription for eyeglasses to serve the same purpose. What is the correct prescription for the eyeglasses if the distance from the eyeglasses to his eyes is 0.030 m?
The answer is 2.11 diopters, how do you get this answer?
The correct prescription for the eyeglasses is 2.11 diopters.
How to determine the correct prescription for the eyeglassesTo get the correct prescription for the eyeglasses, we need to first calculate the refractive power needed.
We can use the formula:
Refractive power = 1 / focal length (in meters)
We know that with the contact lenses, the man can read books held no closer than 0.290 m from his eyes.
This means the focal length of the lenses is:
Focal length = 0.290 m
So, the refractive power of the contact lenses is:
Refractive power = 1 / 0.290 m = 3.45 diopters
Now, we need to adjust the refractive power for the new distance between the eyeglasses and his eyes (0.030 m).
We can use the formula:
Adjusted refractive power = original refractive power + (original refractive power x distance change)
Distance change = (new distance - old distance) / old distance
Distance change = (0.030 m - 0.290 m) / 0.290 m = -0.8966
So, the adjusted refractive power for the eyeglasses is:
Adjusted refractive power = 3.45 diopters + (3.45 diopters x -0.8966) = 2.11 diopters
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a 500 n force is applied to a 25 m/s2 object . The mass of the object is ____
Answer:
20kg
Explanation:
ΣF = ma
500N = 25m
m = 20kg
Read solar basics and use the information to answer the question. what factors affect the amount of solar energy that reaches the earth’s surface?
Explanation: The amount of solar energy available varies by location on earth, the time of the day at that location, the season and weather conditions. Rain, fog, and clouds will lower the amount of solar power available to gather and there are fewer hours of sun available in different seasons (winter for North America). To gather solar power, you also need a large area. This can be lessened by conditions such as snow, so that even on a sunny day, covered panels will collect less energy.
Answer:
.
Explanation:
The quantity of solar energy accessible varies by location on the planet, time of day, season, and weather conditions. Rain, fog, and clouds reduce the quantity of solar power available for collection, and various seasons have less hours of sunlight accessible (winter for North America). A big region is also required to collect solar electricity. Conditions such as snow can reduce this, such that even on a sunny day, covered panels will absorb less energy.
1 A Copper bar is 120m long at 0°c What is the increase in length when it is heated at 40°c The Linear expansion for Copper is 1.7x10^-5/℃
The increase in length of the copper with original length of 120 m is 8.16×10⁻² m.
What is increase in length?A change in length ΔL is produced when a force is applied to a wire or rod parallel to its length L0, either stretching it (a tension) or compressing it.
To calculate the increase in length of the copper, we use the formula below
Formula:
ΔL = αLΔT..................... Equation 1Where:
ΔL = Increase in length α = Linear expansion of copperΔT = Change in TemperatureL = Original LengthFrom the question,
Given:
α = 1.7×10⁻⁵/°CL = 120 mΔT = 40-0 = 40 °CSubstitute these values into equation 1
ΔL = 1.7×10⁻⁵×120×40ΔL = 8.16×10⁻² mLearn more about change in length here: https://brainly.com/question/27934934
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A car of mass 500 kg travelling at 36 km/hr brought to
rest over a distance of 40m find the average retraldation and
average braking force
Answer:
Explanation:
mass, m = 500 kg
initial velocity, u = 36 km/h = 10 m/s
final velocity, v = 0
distance, s = 40 m
\(v^{2} = u^{2} + 2as\)
\(0^{2} = 10 ^{2} +\) 2 × a × 40
0 = 100 + 80 a
- 80a = 100 - 0
-80a = 100
a = -100 / 80
a = -1.25 m/\(s^{2}\)
force, f = ?
mass = 500 kg
acceleration = -1.25 m/s^2
f = ma
= 500 × -1.25
= -625 N
Hope this helps
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2kg of water of 40°C is mixed with 1kg of water at 80°C. Calculate the temperature of the mixure
So, the equilibrium temperature after the first object mixed with second object is approximately 53.3°C.
IntroductionHi! I will help you to solve Black's Principle. Black's Principle state that the heat absorbed by one object is always similar to the heat released by another. So, these objects will transfer heat into each other until they reach an equilibrium temperature. Usually, Black's principle used to find the equilibrium temperature after the interaction of two objects with the same masses but different types, with the same type but different masses, or different types and masses. The type of objects will affect the heat absorbed or released because each type has its specific heat characteristics (c).
Formula UsedSo, mathematically Black's Principle can be expressed in the following equation:
\( \sf{\bold{Q_1 = Q_2}}\)
\( \boxed{\sf{\bold{m_1 \cdot c_1 \cdot (T_1-T') = m_2 \cdot c_2 \cdot (T'-T_2)}}}\)
With the following condition:
\(\sf{m_1}\) = mass of the first object\(\sf{m_2}\) = mass of the second object\(\sf{c_1}\) = specific heat of the first object\(\sf{c_2}\) = specific heat of the second object\(\sf{T'}\) = change in temperature value\(\sf{T_1}\) = temperature of the first object\(\sf{T_2}\) = temperature of the second objectThe first object has higher temperature than the second object.Problem SolvingWe know that:\(\sf{m_1}\) = mass of the first object = 1 kg.\(\sf{m_2}\) = mass of the second object = 2 kg.\(\sf{c_1 = c_2 = c}\) = specific heat of water >> the value can ignored because its will devided by each other.\(\sf{T_1}\) = temperature of the first object = \(\sf{80^\circ}\) C.\(\sf{T_2}\) = temperature of the second object = \(\sf{80^\circ}\) CWhat was asked ?\(\sf{T'}\) = change in temperature value = ...°CStep by step :\( \sf{m_1 \cdot c_1 \cdot (T_1-T')= m_2 \cdot c_2 \cdot (T'-T_2)}\)
\( \sf{1 \cdot \cancel c \cdot (80-T')= 2 \cdot \cancel c \cdot (T'-40)}\)
\( \sf{80 - T'= 2T' - 80}\)
\( \sf{-3T'= -160}\)
\( \sf{T'= \frac{-160}{-3}}\)
\( \sf{\bold{T' \approx 53.3^\circ C}}\)
ConclusionSo, the equilibrium temperature after the first object mixed with second object is approximately 53.3°C.
1. why is it often necessary to add air to your car tires during the winter? 1 2. why do you think it might be a bad idea to throw an aerosol car into a fire? 1
The temperature drops as soon as winter arrives. Air inside car tires shrinks as the temperature drops.
The lower air pressure in the tires can result in poor fuel efficiency, which can be inconvenient and expensive. For example, the rolling resistance of under-inflated tires would be higher, necessitating more energy to move the vehicle, which would result in higher fuel consumption.In addition, under-inflated tires could result in reduced handling and less traction on slick roads. As a result, keeping the tires correctly inflated is crucial to a safe and pleasant winter driving experience.It is a bad idea to throw an aerosol can into a fire because of the following reasons:When an aerosol can heats up, the pressure within the can increases. The pressure within the can would continue to rise until it explodes. Because of the expansion of gases, this explosion can cause damage to property, burns, or other injuries. When heated, the cans can cause chemical reactions that release toxic and flammable gases. This combustion, in turn, can generate toxic chemicals that may damage the atmosphere and potentially be dangerous to breathe.Therefore, it is best to avoid throwing an aerosol can into a fire.for more such question on necessitating
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what needs to happen to the index of refraction to produce a rainbow
To produce a rainbow, the index of refraction needs to vary with wavelength, which causes the different colors of light to refract at slightly different angles.
This occurs when light enters a water droplet and is bent, or refracted, as it slows down due to the higher index of refraction of water compared to air. The different colors of light then reflect off the inner surface of the droplet and are refracted again as they exit the droplet, creating a spectrum of colors. This process is called dispersion and is what creates the beautiful colors of a rainbow.
To produce a rainbow, the index of refraction needs to vary with the wavelength of light. This phenomenon, called dispersion, causes different colors (wavelengths) of light to bend at slightly different angles when passing through a medium like water droplets in the atmosphere. The variation in the index of refraction leads to the separation of colors and the formation of a rainbow.
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A car drives 75 miles off a cliff. What is the cars horizontal speed just before it hits the ground question
assume obj1 and obj2 are object references. which of the following best describes when the expression obj1 == obj2 is true?
The reference equality is tested using the == operator. True. If obj1 and obj2 refer to same object, then obj1 == obj2 is true. True. A String object cannot be changed.
What is a string, exactly?In programming, a string is a form of data that is used to data type rather than integers. Letters, numbers, symbols, and even spaces can all be found in a string, which is a collection of characters. In order for it to recognized as a string, it needs to be encapsulated in quotation marks.
Is string a datatype or an object?A string is frequently implemented as just an array data structure of bits (or words) that records a sequence of elements, usually characters, using some text encoding. Typically, a string is considered to be a data type.
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A toy airplane is flying at an average velocity of 3. 4 m/s by a 660 W engine which applies its force in the direction of the flight. What is the magnitude of the force delivered by the airplane's engine
Only normal acceleration occurs in a uniform circular motion, and it moves in the direction of the center. Tangential acceleration is equal to zero.
What does circular motion's uniform look like?A particular kind of motion in which an object moves in a circle at a fixed speed is known as uniform circular motion. Any point on a propeller, for instance, that is rotating at a consistent speed is doing uniform circular motion.
What are the features of a circular motion that is constant?Two properties let us recognize a particle moving uniformly in circles: It travels in a circle with a radius of r and moves at a constant speed v. The particle's acceleration is then radially pointed toward the center of the circular path and has a magnitude of v2/r.
The weight of the toy is: m = 1 k g
The circle's diameter is r = 1.5 meters.
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PLEASE HELP!
A truck pushes a 2030 kg-car with a force 700 N for 5.0 s. The cars starts from rest.
How far will it go?
Answer:
x = 4.32 [m]
Explanation:
We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 700 [N]
m = mass = 2030 [kg]
a = acceleration [m/s²]
Now replacing:
\(F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]\)
Then we can determine the final speed using the principle of conservation of momentum and amount of movement.
\((m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})\)
where:
m₁ = mass of the car = 2030 [kg]
v₁ = velocity at the initial moment = 0 (the car starts from rest)
Imp₁₋₂ = The impulse or momentum (force by the time)
v₂ = final velocity after the impulse [m/s]
\((2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]\)
Now using the following equation of kinematics, we can determine the distance traveled.
\(v_{2}^{2} =v_{1}^{2}+2*a*x\)
where:
v₂ = final velocity = 1.72 [m/s]
v₁ = initial velocity = 0
a = acceleration = 0.344 [m/s²]
x = distance [m]
\(1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]\)
A ray diagram is shown.
Answer:
Angle of Refraction ?
Explanation:
My decided answer on this question
1. Re-arrange the Ohm’s Law equation to solve the following:I = Type your answers here.R = Type your answers here.2. Power is equal to voltage multiplied by current. Add the missing information in each of the following power equations.P = V Type your answers here.P = R Type your answers here.P = V2 Type your answers here.
2)
\(\begin{gathered} P=VI \\ P=RI^2 \\ P=\frac{V^2}{R} \end{gathered}\)Explanation
Step 1
Ohm's law states that the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.
\(I=\frac{V}{R}\)so
a)
\(I=\frac{V}{R}\)b)
\(\begin{gathered} I=\frac{V}{R} \\ \text{Multiply both sides by R} \\ I\cdot R=R\cdot\frac{V}{R} \\ IR=V \\ \text{divide both sides by I} \\ \frac{RI}{I}=\frac{V}{I} \\ R=\frac{V}{I} \end{gathered}\)Step 2
2
let
Power is equal to voltage multiplied by current.
so
\(P=VI\rightarrow(1)\)also, replacing
\(\begin{gathered} P=VI \\ P=(IR)I \\ P=RI^2\rightarrow(2) \\ \end{gathered}\)also
\(\begin{gathered} V^2=I^2R^2 \\ \text{hece} \\ I^2=\frac{V^2}{R^2} \\ \\ \text{therefore, } \\ P=RI^2\rightarrow(2) \\ P=\frac{V^2}{R^2}\cdot R \\ P=\frac{V^2}{R} \end{gathered}\)I hope this helps you
Which method of popcorn popping transfers heat into the kernels without any direct
contact (nothing hot touched the kernels)? Explain.
Answer:
It is cause by radiation that's the answer
Explanation: the heat project sun rays towards the popcorn which causes it to pop
For cardiovascular exercise, it is important to exercise in your:
1. Resting Heart Rate
2. Target Heart Rate
3. Maximum Heart Rate
4. All of the Above
Answer:
4 target heart rate. is the answer
Explanation:
hope its right
specialty stores compete on the basis of low prices, high turnover, and high volume. True or False
Specialty stores compete on the basis of low prices, high turnover, and high volume, this statement if false.
Specialty stores typically compete based on factors other than low prices, high turnover, and high volume. Specialty stores differentiate themselves by offering unique, high-quality, or niche products to target specific customer segments. They often focus on providing a curated selection of merchandise, personalized customer service, and expertise in their specific product category.
While competitive pricing and turnover can still be important, the primary emphasis is on providing specialized products and a unique shopping experience rather than competing solely on low prices, high turnover, and high volume.
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A brick, milk, and ice cubes are all examples of matter.
true because
brick: solid
milk: liquid
ice cube: solid
An uncharged object becomes charged without direct contact.
What method of charging is occurring?
Answer:
chargeing by induction
Explanation:
this is the answer have a great day
WF4-358 is a white dwarf in the globular cluster NGC 6397. This star's spectrum is highlighted with the red box. Notice that wavelength is tracked on the X axis and intensity is tracked on the Y axis. For this activity, we will be paying attention to the wavelengths that have the highest intensity. As you progress throughout the steps of this activity, you will be filling in this table:
Wavelength Suspected Element Frequency Energy
1.
2.
3.
Step 1: Study the Spectrum
Familiarize yourself with the spectral signature of this star, which shows which wavelengths are absorbed at which intensities. After studying the spectrum, notice which wavelengths ranges have the highest intensity (in other words, notice where the black line under WF4-358 reaches a high point and note which wavelengths ranges that point is associated with). Write down three wavelengths that have the highest intensity in WF4-358. Not that because of the scale of this particular graph, you likely won't be able to tell an exact wavelength. Instead, make the best guess that you can with the information you have. Fill in the first column (Wavelengths) of the table with your answer.
Step 2: Determine Elements
After documenting three wavelengths, refer to the diagram below to investigate which elements may be associated with those wavelengths.
For each of the three peaks in the spectrum you noted, make a guess about which element that peak represents. You will take the wavelength you noted in Step 1, and finding that wavelength on the diagram. For example, if you thought that a wavelength of 475 nm was a peak, you would find that wavelength on the chart and note that Argon might be the element represented by that peak. Repeat for all three peaks. Fill the second column (Suspected Element) of the table with your answers.
Step 3: Find Frequencies
Do some online research to find the frequencies of the three wavelengths you identified. Fill in the third column (Frequency) of the table with your answers.
Step 4: Calculate Energy
Use Planck's Equation to calculate the energy of a photon of light at each of the wavelengths you identified. Planck's Equation goes as follows:
E = hv
In this equation:
E = energy, and is unknown. This is what we are solving for.
h = Planck's constant (6.626 x 10^-34 joule-seconds)
v = frequency
Fill in the last column (Energy) of the table with your answers.
Step 5: Reflection Questions)
Would you expect the spectrum of a blackbody radiator to have peaks and valleys like the spectrum of WF4-358? Why or why not? Define blackbody radiators in your answer.
Pick one element from the chart you made. How might you expect its wavelength to change if it goes from traveling through Earth's atmosphere to traveling through water in the ocean?
Submit the following in one word processing document:
The table you completed in Steps 1-4
The answers to the reflection questions from Step 5
The highest points of intensity for WF4-358 include 390nm, 402nm, and 420nm (all estimated by x-axis locations in 10 nm increments).
What is wavelength?Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire. In physics, the wavelength is the spatial period of a periodic wave—the distance over which the wave's shape repeats.
These are the closest approximate wavelengths along the x-axis that correspond to the highest intensities along the y-axis for WF4-358.
The highest points of intensity for WF4-358 include 390nm, 402nm, and 420nm (all estimated by x-axis locations in 10 nm increments).
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