A man throws a ball straight up to his friend on a balcony who catches it at its highest point. The ball was thrown with an initial velocity of 17.9 m/s2. What height does the ball reach?

The x component of the force is -8.03 N.

The y component of the force is -11.47 N.

The parallel components of the force is resolved into x and y components as follows;

The x component of the force is calculated as follows;

Fx = F cosθ

where;

Fx = 14 N x cos (235)

Fx = -8.03 N

The y component of the force is calculated as follows;

Fy = F sinθ

where;

Fy = 14 N x sin (235)

Fy = -11.47 N

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Answer:

1/2

Explanation:

Given

c=distance

a= length

e= c/a

3/6

e= 1/2 or 0.5

Answer:

Explanation:

v= s/t

V =90m/5s

V = 8m/s

Answer:

No a shape is a 2d figure and cannot have a smell or anything else

Explanation:

The closest distance and angle to this question are 1540.35 kilometers and 38.4 ° S. (depending on how you rounded).

There is a common misconception that distance & displacement are simply two different terms for the same thing. But separation separates the concepts of distance and displacement. The total distance covered by an object is always larger than the movement between those two sites, even if it changes direction throughout the course of its voyage.

The smallest (straight line) length between a body's starting position and its final location—represented by an arrow pointing from starting spot to final position—is referred to as a brain's displacement when it moves through one position to another.

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The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Given:

Speed of sound, v = 344 m/s

Low frequency, fl = 30 Hz.

High frequency, fh = 25 kHz.

Let's find the audible range of sound spectrum.

The range of sound can be said to be the wavelength.

To find the wavelength, apply the formula:

Where:

• λ is the wavelength in meters (m).

• v is the speed in meters per second (m/s)

• f is the frequency (Hz.)

• To find the largest wavelength, we have:

• To find the smallest wavelength, we have:

Therefore, we have:

Smallest value: 0.014 m

Largest value: 11.47 m

ANSWER:

• Smallest value: , 0.014 m

• Largest value: , 11.47 m

The material that obeys Hooke's law is elastic material.

Hooke's Law says that the force needed to extend or compress a spring by some distance scales linearly with respect to that distance. And it is known for the formula  F = kX

F is the force, x is the deformation, and k is the spring constant.

Elastic materials are able to return to their original shape after being deformed by a force.

The amount of deformation is noted to be directly proportional to the amount of force applied.

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The expression for the initial velocity at point A is:

0 = (velocity at point A - 0) / time

Simplifying the equation, we find:

Velocity at point A = 0

The initial velocity at point A is zero, indicating that the object starts from rest before sliding on the horizontal plane AB.

To write an expression for the initial velocity at point A, we need to analyze the forces acting on the object and apply the principles of motion.

Given:

Mass of the object, m

Radius of the semi circle, R

Coefficient of kinetic friction, μ\(_k\) = 0.5

Force applied at point C, F = 3mg

The object is initially at rest.

Let's break down the motion into two parts: the motion on the horizontal plane AB and the motion along the semi circle BCD.

1. Motion on the horizontal plane AB:

The only force acting on the object on the horizontal plane is the force of kinetic friction. The frictional force can be calculated using:

Frictional force, f = μ\(_k\)* Normal force

The normal force is equal to the weight of the object, which is mg.

Normal force, N = mg

Frictional force, f = μ\(_k\) * mg

The frictional force acts in the opposite direction to the motion, so its magnitude is negative. Thus, the net force on the object on the horizontal plane is:

Net force = -f = -μ\(_k\)* mg

Using Newton's second law, we can relate the net force to the acceleration:

Net force = mass * acceleration

-μ\(_k\) * mg = m * acceleration

The acceleration can be expressed as the rate of change of velocity:

Acceleration = (final velocity - initial velocity) / time

Since the object is initially at rest, the initial velocity is zero.

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Answer:

deductive reasoning usually follows steps .

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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Answer:

the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

Explanation:

A)

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

\(\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}\)

However; the net electric field i.e the sum of the electric filed produced is represented as:

\(\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}\)

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

\(\mathbf{F = q* E'}\)

\(\mathbf{F = \frac{q*v}{2d}}\) -----    equation (1)

Also ; we know that

\(\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}\)

\(\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}\)

\(\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}\)    -----   equation (2)

Replacing equation 3 into equation (2); we have:

\(\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}\)

\(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

Therefore,  the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

B)

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

\(\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }\)

The net workdone to raise the plate from separation d to 2d is:

\(\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

\(\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }\)

D) The energy stored in the plate after the  the top plate was raised is as follows:  

\(\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }\)

E) Yes,  work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

\(\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

\(\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.

The answer is B) I. The electric field will have the greatest magnitude at point I because it is the closest point to the charged conductors. The closer to the conductors, the greater the electric field magnitude.

Electric field is an invisible force field that surrounds any object that has an electric charge. It is measured in terms of volts per meter (V/m) and is responsible for the attraction or repulsion of two objects with different electric charges. The force of the electric field is determined by the amount of charge on the objects and the distance between them. Any changes in the electric field will cause a corresponding change in the force felt by the objects. Electric fields can be created by moving charges, such as those found in electric currents, or by static charges, such as those found on a charged object. Electric fields are essential for the transmission of electrical signals and are used in many applications, from telecommunications to medical imaging.

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Answer:

beacause it's contracts

Explanation:

when using a large bottomed glass the hot water cools that's why is good to use thin bottomed glass

Answer:

An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor

The magnetic field in the cyclotron, is 0.292 T.

Angular velocity, ω = 2.8 x 10⁷rev/s

Charge of a proton, q = 1.6 x 10⁻¹⁹C

Mass of a proton, m = 1.67 x 10⁻²⁷kg

A cyclotron is a device that strongly accelerates the charge on charged particles or ions. The cyclotron amplifies the energy of the charged particles through the application of both magnetic and electric fields.

The expression for the angular velocity of the cyclotron is given by,

ω = qB/m

Therefore, the magnetic field in the cyclotron,

B = ωm/q

B = 2.8 x 10⁷x 1.67 x 10⁻²⁷/1.6 x 10⁻¹⁹

B = 0.292 T

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1.The Sun is located at one of the foci of the planets' elliptical orbits.

2.The path of the planets around the Sun is elliptical in shape. are the correct statement.

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Answer: 6.7 CENTIMETERS

Explanation: 15 EAST AND 8.3 WAST

NET DISPLACEMENT 15-8.3= 6.7

Answer:

Explanation:

A) 131 dB = 10*log(I / 1e-12W/m²)

where I is the intensity at 2.6 m away.

13.1 = log(I / 1e-12W/m²

1.25e13= I / 1e-12W/m²

I = 1.25 x10^1W/m²

power = intensity * area

P = I * A = 12.5W/m² * 4π(2.6m)² =1061 W ◄

B) 86 dB = 10*log(I / 1e-12W/m²)

8.6 = log(I / 1e-12W/m²)

3.98e8 = I / 1e-12W/m²

I = 3.98e-4 W/m²

area A = P / I = 1061W / 3.98e-4W/m² = 2.66e6 m²

A = 4πr²

2.66e6 m² = 4πr²

r = 14.5m ◄

Answer:

The sensation of a frequency is commonly referred to as the pitch of a sound. A high pitch sound corresponds to a high frequency sound wave and a low pitch sound corresponds to a low frequency sound wave.

Explanation:

Hope this helps : )

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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Answer:

The speed of the ball at this distance is 9.15 m/s

Explanation:

Given;

initial speed of the baseball, U = 5.0 m/s.

distance traveled along the path way, h = 3 m

final speed of the baseball at this distance, V = ?

The baseball is falling under the influence of gravity.

Acceleration due to gravity, g is positive, since the baseball is falling towards its direction.

g = 9.8 m/s²

Apply the third kinematic equation;

V² = U² + 2gh

V² = 5² + 2 x 9.8 x 3

V² = 25 + 58.8

V² = 83.8

V = √83.8

V = 9.15 m/s

Therefore, the speed of the ball at this distance is 9.15 m/s

Answer:

eating instrument must be: HARDNESS,  INERT, NOT TOXIC

eating tools: digested by the body

Explanation:

An eating instrument must be able to contain food, so it must have a good HARDNESS, besides it must be poorly absorbent of heat and the most important must be INERT, not react with food or be NOT TOXIC to humans.

Additionally, for a spoon to be edible, it must be able to be digested by the body, in general they are made with a starch base, so that the non-digestible parts of it have not been toxic to the body and can be eliminated from it.

There are numerous features of a spoon but these properties must an edible spoon

have

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An insulating vessel contains 80 g of a block of ice at -12 °C. If 450 g of water at 60 °C is added to the ice in the vessel, Energy required for complete melting = \(80 g X (3.33 X 10^3 J/kg)\).

To determine whether the ice will soften absolutely and calculate the final temperature of the system, we need to do not forget the strength transferred among the ice and water at some stage in the procedure.

(i) To decide if the ice will melt completely, we need to examine the energy won by using the ice to the electricity required for complete melting.

Energy received by way of the ice = mass of ice × particular heat capacity of ice × alternate in temperature

Energy won by using the ice = eighty g × 2100 J/(kg·°C) × (final temperature - (-12°C))

Energy required for complete melting = mass of ice × latent warmth of fusion of ice

Energy required for whole melting = 80 g × (3.33 × 10^3 J/kg)

If the strength received via the ice is extra than or same to the electricity required for entire melting, the ice will soften completely.

(ii) To calculate the very last temperature of the gadget, we want to keep in mind the power transferred between the ice and water.

Energy won by the water = mass of water × unique heat ability of water × trade in temperature

Energy received by using the water = 450 g × 4200 J/(kg·°C) × (final temperature - 60°C)

Since electricity is conserved inside the machine, the power gained by means of the ice and water need to be identical:

Energy gained through the ice = Energy won by the water

Using the equations above, we will installation the following equation:

80 g × 2100 J/(kg·°C) × (very last temperature - (-12°C)) = 450 g × 4200 J/(kg·°C) × (very last temperature - 60°C)

Thus, this the final temperature of the system.

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Explanation:

density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC

Answer:

space = 66.24 [m]

Explanation:

To solve this problem we must remember that the average speed is defined as the relationship between a space traveled over a certain time.

\(Av = \frac{space}{time}\)

where:

space [m]

Av = average velocity = 3.6 [m/s]

time = 18.4 [s]

\(space = 3.6*18.4\\space = 66.24 [m]\)

Answer:

Its the sum of the potential energy and the kinetic energy

Answer:

the speed of the textbook just before it hits the floor is 2.4 m/s

Explanation:

  Given the data in the question;

mass of pulley = 1.50 kg

radius of pulley = 0.240 m

mass of text book = 2.0 kg

height from which text book was released = 0.9 m

angular speed of the pulley = 10.0 rad/s

the speed of the textbook just before it hits the floor = ?

the speed of the textbook v = angular speed of the pulley × radius of pulley

we substitute

v = 10.0 rad/s × 0.240 m

v = 2.4 m/s

Therefore, the speed of the textbook just before it hits the floor is 2.4 m/s

To calculate the energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C, we need to consider two processes:

(1) raising the temperature of the wax from 20°C to 68°C

(2) melting the wax at its melting point of 68°C.

The first process requires an energy input of Q1 = mcΔT, where m is the mass of the wax (100 g), c is the specific heat capacity of the wax (29 J/g°C), and ΔT is the change in temperature (68°C - 20°C = 48°C). Thus, Q1 = (100 g)(29 J/g°C)(48°C) = 139,200 J.

The second process requires an energy input of Q2 = mL, where L is the specific latent heat of fusion of the wax (220 J/g). Thus, Q2 = (100 g)(220 J/g) = 22,000 J.

Therefore, the total energy gained when changing the temperature of 100g of solid candle wax at 20°C to liquid at 68°C is Q = Q1 + Q2 = 139,200 J + 22,000 J = 161,200 J.

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