PLS HELP !! I WILL MARK BRAINLIEST!!!
Question
.........
The number of bacteria in a Petri dish quadruples every hour. How many bacteria are in the dish after 5 hours if there were originally 10 bacteria?
Circles A, B, and C overlap. The overlap of circles B and C is labeled x.
Which statements are true about x? Select three options.
x ∈ B ⋃ C
x ∈ B ∩ C
x ∈ A ⋃ C
x ∈ A ∩ C
x ∈ A
Given:
Circles A, B, and C overlap.
The overlap of circles B and C is labeled x.
To find:
The three correct statements about x.
Solution:
It is given that the overlap of circles B and C is labeled x. It means x represent the common elements of B and C.
So, x belongs to the intersection and union of B and C.
\(x\in B\cup C\)
\(x\in B\cap C\)
Since x is the element of C, therefore it is also the element of A union C.
\(x\in A\cup C\)
The overlap of circles B and C is labeled x. It means \(x\notin A\). So,
\(x\notin A\cap C\).
Therefore, the correct options are A, B and C.
Answer:
A, B and C.
Step-by-step explanation:
edge
Juwad picked 30 bags of apples on Monday and sold them at his fruit stand for
$3.45 each. The following week he picked and sold 26 bags.
How much money did Juwad earn in the first week?
How much money did he earn in the second week? How much did Juwad earn selling bags of apples these two weeks? Each bag Juwad picked holds 15 apples. How many apples did he pick in two
weeks?
Answer:
89.70 dollars
Step-by-step explanation:
If Juwad picked 30 bags of apples and only sold 26 of them for 3.45 each, then you would have to multiply the number of bags sold by the price, and you would get your answer. So in this case:
1. (#sold)* (price)= total amount of money made
2. 26*3.45= 89.70
3. And you can check by dividing 89.70(your answer) by the price of the apples
4. 89.70/3.45= 26
What is the area of this square????
pls help
Answer:
The area is 25
Step-by-step explanation:
To find an area of a square just multiply the same number by itself like in this problem multiply 5 X 5
Given h(x) = -2x + 5, solve for a when h(x) = 3.
Answer:
Step-by-step explanation:
-2x + 5 = 3
-2x = -2
x = 1
The formula F = \frac{9}{5} C + 32$ can be used to convert temperatures between degrees Fahrenheit ($F$) and degrees Celsius ($C$). What Celsius temperature $C$ has the same value when converted to a Fahrenheit temperature $F$?
The Celsius temperature that has the same value as when converted to a Fahrenheit temperature is -40
What Celsius temperature has the same value as FFrom the question, we have the following parameters that can be used in our computation:
F = 9/5C + 32
The Celsius temperature that has the same value as F implies that
C = F
Substitute the known values in the above equation, so, we have the following representation
C = 9/5C + 32
So, we have
C - 9/5C = 32
Evaluate the like terms
-4/5C = 32
So, we have
C = -32 * 5/4
Evaluate
C = -40
Hence, the value of C is -40
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I need help with this question for my exam practice, please. pi = 3.14
Answer:
28.095 cm^2
Explanation:
To determine the area of the given shape, we have to determine the area of the complete rectangle, then subtract the areas of each of the cut-out semi-circles as seen below;
From the shape, let's determine the length and width of the rectangle;
Length(l) = 2 cm + 5 cm + 2 cm = 9 cm
Width(w) = 1 cm + 4 cm + 1 cm = 6 cm
So the area of the complete rectangle will be;
\(\begin{gathered} A_r=l\cdot w=9\cdot6=54cm^2 \\ \text{where;} \\ A_r=\text{ Area of the complete rectangle} \end{gathered}\)Let's now determine the area of the top semi-circle given that the radius is 2cm (radius = diameter/2 = 4/2 = 2cm);
\(\begin{gathered} A_{\text{tsc}}=\frac{\pi r^2}{2}=\frac{3.14(2)^2}{2}=\frac{3.14\cdot4}{2}=\frac{12.56}{2}=6.28cm^2 \\ \text{where;} \\ A_{\text{tsc}}=\text{Area of top semi-circle} \end{gathered}\)Given that the two semi-circles by the side of the rectangle have the same radius(r) which is 2.5cm (r = diameter/2 = 5/2 = 2.5cm), let's go ahead and determine their area;
\(\begin{gathered} A_{\text{ssc}}=2(\frac{\pi r^2}{2})=\pi r^2=3.14\cdot(2.5)^2=3.14\cdot6.25=19.625cm^2 \\ \text{where;} \\ A_{\text{ssc}}=\text{Area of side semi-circles} \end{gathered}\)So the area of the shape will be;
\(\begin{gathered} A=A_r-A_{\text{tsc}}-A_{\text{ssc}}=54-6.28-19.625=28.095cm^2 \\ \end{gathered}\)Therefore, the area of the shape is 28.095 cm^2
Suppose two utilites, People's Electric and Muricipal Energy, each produce 900 tons of pollution per year. The government has a goal of eliminating haf the pclution, and, in turn, provides 450 pollution permits to each utlity. A pollution permit is required to legally produce a ton of poliubon. However, the tao utities are allowed to trade permas. Suppose the cost of eliminating one ton of pollution for People's Electric is $400 and the cost of eliminating a ton of polution for Municipal Energy is $350. The total cost of each utility eliminating 450 tons of pollution is $ (Enter your response as a whole number)
The total cost of each utility eliminating 450 tons of pollution is $180,000.
To calculate the total cost for each utility to eliminate 450 tons of pollution, we need to multiply the cost per ton of pollution elimination by the number of tons each utility needs to eliminate.
For People's Electric, the cost of eliminating one ton of pollution is $400. So, to eliminate 450 tons, the total cost would be 450 tons * $400/ton = $180,000.
For Municipal Energy, the cost of eliminating one ton of pollution is $350. Again, to eliminate 450 tons, the total cost would be 450 tons * $350/ton = $157,500.
Therefore, the total cost for each utility to eliminate 450 tons of pollution is $180,000 for People's Electric and $157,500 for Municipal Energy.
The cost calculation is based on the given information that each utility is provided with 450 pollution permits by the government. These permits allow them to legally produce a ton of pollution. By setting a limit on the number of permits, the government aims to reduce pollution by half. The utilities have the option to trade permits with each other.
In this scenario, People's Electric has a higher cost of eliminating pollution per ton compared to Municipal Energy ($400 vs. $350). It means that People's Electric would find it more expensive to reduce pollution through internal measures like investing in cleaner technology or implementing environmental initiatives. On the other hand, Municipal Energy has a lower cost, indicating that they have relatively more cost-effective methods for pollution reduction.
Given these costs, it is more beneficial for People's Electric to purchase permits from Municipal Energy rather than eliminating the pollution themselves. By purchasing permits, People's Electric can meet the pollution reduction target at a lower cost. Conversely, Municipal Energy can generate additional revenue by selling their permits.
This permit trading mechanism allows for cost efficiency in achieving the government's pollution reduction goal. The total cost for each utility is determined by multiplying the cost per ton of pollution elimination with the number of tons they need to eliminate.
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Find the value of k such that the equation (k+4) x^2 + 2(k+1)x +(k-1)= 0 has equal roots
Answer:
b^2-4ac(formula for finding the roots )
Step-by-step explanation:
1)9-4k=0
k=9/4(roots are real )
2)4-4k+4=0
8-4k=0
k=2(the roots are real )
3)64-8k=0
k=8
4)36-16k+16=0
52-16k=0
k=52/16=13/8
16-4k+4=0
k=5
Step-by-step explanation:
what grade in the us takes advanced single-variable quadratic equations and complex numbers
Advanced single-variable quadratic equations and complex numbers are advanced topics studied in high school mathematics curricula in the US. The specific grade at which they are introduced and studied may vary depending on the state, district, or school.
In general, single-variable quadratic equations are usually introduced in the 9th or 10th grade in high school, but some schools may introduce them in earlier grades.
These equations are a type of polynomial equation of degree two that can be written in the form
ax² + bx + c = 0,
where a, b, and c are constants and x is a variable. The study of quadratic equations includes topics such as factoring, completing the square, and the quadratic formula.
Complex numbers are usually introduced in high school algebra 2 courses. Algebra 2 is a 10th or 11th-grade course in the US that builds on the concepts learned in algebra 1. Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit, which is defined as the square root of -1. The study of complex numbers includes topics such as complex arithmetic, the complex plane, and the quadratic formula for complex numbers.In conclusion, advanced single-variable quadratic equations and complex numbers are typically studied in high school math courses in the US. The specific grade at which they are studied may vary, but they are usually introduced in the 9th or 10th grade for quadratic equations and the 10th or 11th grade for complex numbers.Know more about the quadratic equations
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A tortilla chip is shaped like an equilateral triangle.
If an exterior angle on this tortilla chip measures(2x-80), which equation can you solve to calculate the value of x?
HINT: The interior angles of an equilateral triangle all measure 60.
Step-by-step explanation:
Two interior opposite angles of a triangle are equal to the exterior angel
\(60 + 60 = 2x - 80 \\ 120 = 2x - 80 \\ 2x = 120 + 80 \\ 2x = 200 \\ x = \frac{200}{2} \\ x = 100\)
researchers are investigating whether taking aspirin regularly reduces the risk of heart attacks. four hundred men participate in the study. the men are divided randomly into two groups: one group takes aspirin pills, and the other group takes placebo pills (a pill with no aspirin in it). the men each take one pill a day, and they do not know which group they are in. at the end of the study, researchers will count the number of men in each group who have had heart attacks. identify the explanatory and response variables in this situation.
Explanatory variable: The type of pill the men took each day.
Response variable: Whether a subject had a heart attack.
We have been given that :
Participated candidates are 400
Men are divided randomly so we find out explanatory and response variable.
The explanatory variable is the variable that is manipulated by the researcher. Explanatory Variable also known as the independent or predictor variable, it explains variations in the response variable; in an experimental study, it is manipulated by the researcher.
Response variable: Response Variable is the result of the experiment where the explanatory variable is manipulated. It is a factor whose variation is explained by the other factors. Response Variable is often referred to as the Dependent Variable or the Outcome Variable.
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A line with a slope of 1 passes through the point (-9, -4). What is its equation in
slope-intercept form?
LA
Answer:
y = x + 5
Step-by-step explanation:
The hits to a Web site occur at the rate of 10 per minute between 7:00 P.M. and 10:00 P.M. The random variable X is the number of hits to the Web site between 7:56 P.M. and 8:22 P.M. State the values of land for this poisson process.
Given that the hits to a web site occur at a rate of 10 per minute between 7:00 P.M. and 10:00 P.M., we can say that the web site experiences a Poisson process. The value of land for this Poisson process is 260.
The random variable X represents the number of hits to the web site between 7:56 P.M. and 8:22 P.M.
To find the values of λ, we need to use the formula for the Poisson distribution:
P(X = k) = (λ^k * e^-λ) / k!
where λ is the average number of hits per unit time.
Since we are interested in the hits between 7:56 P.M. and 8:22 P.M., which is a duration of 26 minutes, we need to adjust the rate of hits accordingly. Therefore, λ for this duration would be:
λ = 10 hits/min * 26 min = 260 hits
So, the values of λ for this Poisson process would be λ = 260.
To determine the values of λ (lambda) for this Poisson process, we need to first calculate the time interval between 7:56 P.M. and 8:22 P.M. and then find the expected number of hits to the website during that time.
Step 1: Calculate the time interval
The time interval between 7:56 P.M. and 8:22 P.M. is 26 minutes.
Step 2: Determine the expected number of hits
The website receives hits at a rate of 10 per minute. To find the expected number of hits during the 26-minute interval, multiply the rate by the length of the interval:
10 hits/minute * 26 minutes = 260 hits
Step 3: State the value of λ for the Poisson process
The random variable X represents the number of hits to the website during this interval. Since the expected number of hits is 260, the value of λ for this Poisson process is 260.
Your answer: The value of λ for this Poisson process is 260.
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Please help me quickly i am in class
1. A graph of two similar, but not equal, right triangles using segments of line AB as the hypotenuse of each triangle is shown below.
2. The three pair of corresponding angles and sets of proportionate sides include:
ΔACE ≅ ΔBDF, ΔAEC ≅ ΔBFD, and ΔCAE ≅ ΔDBF.
AC = BD, EC = FD, and AE = BF
3. Yes, the slope of line is the same between any two points on the line.
What are the properties of similar triangles?In Mathematics and Geometry, two triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.
Part 1.
In this exercise, we would use an online graphing tool to create two similar, but not equal, right triangles by using line segments AB as the hypotenuse of each triangle.
Part 2.
Based on the side, side, side (SSS) similarity theorem, we can logically deduce the following congruent (similar) triangles and sets of proportionate sides:
ΔACE ≅ ΔBDFΔAEC ≅ ΔBFDΔCAE ≅ ΔDBF.AC = BDEC = FDAE = BFPart 3.
In Mathematics and Geometry, the slope of any straight line can be determined by using this formula;
Slope = (y₂ - y₁)/(x₂ - x₁)
Slope AC = (0 + 1)/(-3 + 5)
Slope AC = 1/2.
Slope BD = (3.5 - 2)/(4 - 1)
Slope BD = 1/2.
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Which of these is not part of an algebraic equation?
A
an inequality sign
B
an expression
C
an equal sign
D
a variable
Answer:
A-an inequality sign
Step-by-step explanation:
inequality sign: greater then, less than, equal to.
expression: 2x + 3 no equal sign
equal sign: =
Variable: a letter in the equation such as n x 6=?
Hope this is correct.
Write V- 5in simplest radical form
Answer:
The square root of 5 is expressed as √5 in the radical form and as (5)½ or (5)0.5 in the exponent form.
Step-by-step explanation:
What is the percent decrease from 100 to 82
Percent decrease from 100 to 82 is 18% decrease.
Calculating the % decrease from 100 to 82,
\(\frac{82-100}{100}\)×100%
\(\frac{-18}{100}\)×100%
on simplifying we get,
-18%
here, negative sign indicates that there is a decrease of percentage.
Hence, we get 18% decrease from 100 to 82.
How to calculate Percent decrease?
Do the % growth and reduction calculations. By dividing the new number by the initial value, the percentage is computed.
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What’s 5 more than twice a number
Answer:
33 is the correct answer
Answer:
2x+5
Step-by-step explanation:
if the number is x
∴ 5 more than twice a number is
ll ll
V V
+5 *2
So, 2*x+5
which of the following tests is considered to be more powerful? group of answer choices neither; they are both equally statistically powerful which is more powerful depends on the sample size a one-tailed test a two-tailed test
A two-tailed test is considered to be more powerful than a one-tailed test. Therefore, Option D (a two-tailed test) is the correct answer.
The one-tailed test and the two-tailed test are two sorts of hypothesis tests. The number of tails, as the name implies, is the fundamental distinction between the two sorts of hypothesis tests. The tails are the areas under the probability distribution curve that are beyond the critical values or the cut-off points.
The one-tailed test is one of the types of hypothesis testing in which an alternative hypothesis is generated in a specific direction. In comparison to two-tailed tests, they are simpler to conduct. The one-tailed test is less likely to reject the null hypothesis since it only tests one of the tails. On the other hand, the two-tailed test tests both tails of the distribution, making it more powerful since it is more inclusive than the one-tailed test.
The two-tailed test is more effective since it tests for discrepancies on both sides of the distribution, whereas the one-tailed test only tests for discrepancies on one side of the distribution.
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= Evaluate SSR xy dA where R is the region in the first quadrant between x2 + y2 = 1 and x² + y2 = 2.
Da = rdr dθ.now, we can set up the integral:
ssr xy da = ∫∫r xy rdr dθ
integrating with respect to θ first:
∫∫r xy rdr dθ = ∫[0,π/2] ∫[1,√2] (r cosθ)(r sinθ) r dr dθ
simplifying:
∫∫r xy rdr dθ = ∫[0,π/2] ∫[1,√2] r³ cosθ sinθ dr dθ
integrating with respect to r:
∫[0,π/2] ∫[1,√2] r³ cosθ sinθ dr dθ = ∫[0,π/2] (1/4) (sin(2θ) - sinθ) dθ
evaluating the inner integral:
∫[0,π/2] (1/4) (sin(2θ) - sinθ) dθ = (1/4) [(-cos(2θ)/2) + cosθ]∣[0,π/2] = (1/4) [(-cos(π) + 1/2) - (cos(0) + 1)]
= (1/4) (-(-1/2) - 0) = (1/4)(1/2)
= 1/8.
to evaluate the double integral of ssr xy da over the region r, where r is the region in the first quadrant between x² + y² = 1 and x² + y² = 2, we need to set up the integral and determine the limits of integration.
since the region r is bounded by the curves x² + y² = 1 and x² + y² = 2, we can express the limits of integration in terms of polar coordinates.
in polar coordinates, x = r cosθ and y = r sinθ. we can rewrite the equations of the curves as r² = 1 and r² = 2.
the region r in polar coordinates can be defined by 1 ≤ r ≤ √2 and 0 ≤ θ ≤ π/2.
now, let's express the element da in terms of polar coordinates. in the cartesian coordinate system, da is given by da = dx dy. converting to polar coordinates, we have:
da = |j| dr dθ
where |j| is the jacobian determinant of the transformation from cartesian to polar coordinates, which is simply r. now, we can set up the integral:
ssr xy da = ∫∫r xy rdr dθ
integrating with respect to θ first:
∫∫r xy rdr dθ = ∫[0,π/2] ∫[1,√2] (r cosθ)(r sinθ) r dr dθ
simplifying:
∫∫r xy rdr dθ = ∫[0,π/2] ∫[1,√2] r³ cosθ sinθ dr dθ
integrating with respect to r:
∫[0,π/2] ∫[1,√2] r³ cosθ sinθ dr dθ = ∫[0,π/2] (1/4) (sin(2θ) - sinθ) dθ
evaluating the inner integral:
∫[0,π/2] (1/4) (sin(2θ) - sinθ) dθ = (1/4) [(-cos(2θ)/2) + cosθ]∣[0,π/2] = (1/4) [(-cos(π) + 1/2) - (cos(0) + 1)]
= (1/4) (-(-1/2) - 0) = (1/4)(1/2)
= 1/8
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Investigate and graph the function Y=2x³-6x²+4
Answer:
-128
Step-by-step explanation:
Given, f(x)=2x
3
−21x
2
+36x−20
∴f
′
(x)=6x
2
−42x+36
When f(x) is a maximum or a minimum, f
′
(x)=0
Hence, 6x
2
−42x+36=0
x
2
−7x+6=0
x
2
−6x−x+6=0
x(x−6)−1(x−6)=0
(x−6)(x−1)=0
x=1,6
Again f
′′
(x)=12x−42
=6(2x−7)
Now, when x=1,f
′′
(x)=−30 ....[negative]
And when x=6,f
′′
(x)=30 ....[positive]
Hence, f(x) is maximum for x=1 and minimum for x=6.
The maximum and minimum values of f(x) are
f(1)=2(1)
3
−21(1)
2
+36(1)−20
=2−21+36−20=−3
f(6)=2(6)
2
−21(6)
2
+36(6)−20
=432−756+216−20=−128
Find the total surface area of this triangular prism.
13 cm
15 cm
12 cm
20 cm
5 cm
9 cm
2 1 리
12. The Williams family ate dinner at Olive Garden. The
total bill was $76. They left a tip that was 18% of the bill.
How much did the Williams family pay, including the tip?
A. $76.00
B. $76.18
13.6f
C. $89.68
+
76
D. $62. 32
Answer:
$89.68 was their total bill (bill + tip)
Step-by-step explanation:
Turn the percentage into a decimal:
76 x 0.18 = 13.68
13.68 is the tip of their total bill. Now, add the tip and the total bill cost together.
13.68 + 76 = $89.68
A city planner is studying the need for affordable housing in the city's Urban Planning Department. He learned from the census of all 65,489 households in the city that the median family income is $45,000, with an average of 3.1 persons-per-household, and 79% live in a single household unit. Previously, the planner had surveyed a group of 300 randomly selected households in the city. The surveyed households had a median family income of $39,000, an average of 3.8 persons-per-household, and 83% lived in a single household unit.
(a) For city planner's survey, identify the population and the sample.
(b) Choose whether each number described below is a parameter or a statistic for the city planner's survey
Number Parameter Statistic
The 539,000 median family income of the group of randomly
selected households.
The average of 3.1 persons per household of all the households
in the city.
The 83% of the group of randomly selected households that live
in a single household unit.
According to the question (a) Population: 65,489 households. Sample: 300 randomly selected households. (b) Median family income (539,000): Statistic. Average persons per household (3.1): Parameter. Percentage living in a single household unit (83%): Statistic.
A researcher divides a city into three zones based on income levels and randomly selects households from each zone for a survey on spending habits. The type of sampling used in this scenario is stratified sampling.
(a) For the city planner's survey:
- Population: All 65,489 households in the city.
- Sample: The group of 300 randomly selected households surveyed by the planner.
(b) Identifying whether each number is a parameter or a statistic:
- The $39,000 median family income of the group of randomly selected households: Statistic
- The average of 3.1 persons per household of all the households in the city: Parameter
- The 83% of the group of randomly selected households that live in a single household unit: Statistic
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An Arrow-Debreu security pays $1 at expiry node (6,2). The upstate risk neutral probability is π=0.4 and the return over one time-step is R=1.05. What is the premium of this Arrow-Debreu security?
The value of the Arrow-Debreu security is calculated as the present value of its expected payoff, discounted at the risk-neutral rate. As a result, the premium of the Arrow-Debreu security can be computed using the following formula: \($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$,\)
where π=0.4, R=1.05, n=6, and t=2 (expiry node).
By substituting the values, we obtain:
\($P_{2}=\frac{1}{(1+1.05)^{6-2}}\times 0.4 = \frac{0.4}{(1.05)^4} \approx 0.3058$.\)
Therefore, the premium of the Arrow-Debreu security is approximately $0.3058.
Arrow-Debreu securities are typically utilized in financial modeling to simplify the pricing of complex securities. They are named after Kenneth Arrow and Gerard Debreu, who invented them in the 1950s. An Arrow-Debreu security pays $1 if a particular state of the world is realized and $0 otherwise.
They are generally utilized to price derivatives on numerous assets that can be broken down into a set of Arrow-Debreu securities. The value of an Arrow-Debreu security is calculated as the present value of its expected payoff, discounted at the risk-neutral rate. In other words, the expected value of the security is computed using the risk-neutral probability, which is used to discount the value back to the present value.
The formula is expressed as:
\($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$\),
where P_t is the price of the Arrow-Debreu security at time t, π is the risk-neutral probability of the security’s payoff, R is the risk-free rate, and n is the total number of time periods.However, Arrow-Debreu securities are not traded in real life. They are used to determine the prices of complex securities, such as options, futures, and swaps, which are constructed from a set of Arrow-Debreu securities.
This process is known as constructing a complete financial market, which allows for a more straightforward pricing of complex securities.
The premium of the Arrow-Debreu security is calculated by multiplying the risk-neutral probability of the security’s payoff by the present value of its expected payoff, discounted at the risk-neutral rate.
The formula is expressed as
\($P_{t}=\frac{1}{(1+R)^{n-t}}\times \pi$,\)
where P_t is the price of the Arrow-Debreu security at time t, π is the risk-neutral probability of the security’s payoff, R is the risk-free rate, and n is the total number of time periods. Arrow-Debreu securities are not traded in real life but are used to price complex securities, such as options, futures, and swaps, by constructing a complete financial market.
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Any population, P, for which we can ignore immigration, satisfies dP/dt = Birth rate - Death rate. For organisms which need a partner for reproduction but rely on a chance encounter for meeting a mate, the birth rate is proportional to the square of the population. Thus, the population of such a type of organism satisfies a differential equation of the form dP/dt = aP^2 - bP with a, b > 0. This problem investigates the solutions to such an equation. Sketch a graph of dP/dt against P. Note when dP/dt is positive and negative. dP/dt < 0 when P is in dP/dt > 0 when P is in
As a result, on a graph of dP/dt vs P, the curve would be concave down for P b/a and concave up for P > b/a. The curve would reach its maximum when P = b/a, with dP/dt equal to zero.
What is equation?In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign.
Here,
The equation dP/dt = aP² - bP represents the rate of change of the population P over time t.
When dP/dt is positive, the population is increasing. When dP/dt is negative, the population is decreasing.
To find when dP/dt is positive and negative, we need to find the critical points where dP/dt = 0.
Solving the equation dP/dt = aP² - bP = 0, we get:
aP² - bP = 0
aP(P - b/a) = 0
This equation has two solutions: P = 0 and P = b/a.
For P < b/a, dP/dt is negative (the population is decreasing). For P > b/a, dP/dt is positive (the population is increasing).
So, on a graph of dP/dt against P, the curve would be concave down for P < b/a and concave up for P > b/a. At P = b/a, the curve would have a maximum and dP/dt = 0.
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Find the Unit Rate: $2.40 for 8 oranges
Answer:
30 cents per orange
Step-by-step explanation:
$2.40 ÷ 8 = 30 cents
Answer:
30 Cents per orange
Step-by-step explanation:
so 2.40/8 to x/1
it will then be 2.40x1 and 8x.
we divide 2.40 by 8 to get x by itself.
Then x = .3 so 30 cents. <3
What is the antiderivative of 1x?
The antiderivative of 1x (or simply x) is (1/2)x² + C, where C is the constant of integration. In other words, the antiderivative of x is the function whose derivative is equal to x.
This is a basic result in calculus, and it is derived using the power rule of integration. The antiderivative of 1x (or simply x) is the function whose derivative is equal to x. This function is (1/2)x² + C, where C is the constant of integration. To find the antiderivative, one can use the power rule of integration, which states that the antiderivative of xⁿ is (1/(n+1))x⁽ⁿ⁺¹⁾ + C. In the case of x, n is equal to 1, so the antiderivative is (1/2)x² + C. The constant of integration represents the family of functions that have the same derivative, so it is added to the antiderivative to reflect this.
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Which is larger? Convert to a decimal using long division. please show your work!!
Answer:
1.255
Step-by-step explanation:
10^-1 equals 0.1
1÷8=0.125
so our greatest one is 1.255