a. In the building there are 133 steps from the ground floor to the sixth floor.
Each step is 16.2 cm tall. It takes 6 minutes and 16 seconds for a person with a mass of m = 89.2 kg to walk all the way up. How much work did the person do?


b. What was the average power performed by the person during the walk?


c. How many food Calories did the person burn during the walk? (1 Cal = 4.1868 kJ. Do not enter unit for this part.)

Answers

Answer 1

Answer:

(a) \(W\approx18834.7 \ J\)

(b) \(P \approx 50.1 \ W\)

(c) \(\text{Food Calories} \approx 4.5 \ cal}\)

Explanation:

Part (a): To calculate the work done by the person, we can use the formula:

\(\rightarrow W= F d\)

The force can be calculated using the person's mass and the acceleration due to gravity:

\(\rightarrow F=mg\)

Given:

Number of steps, N = 133

Height of each step, h = 16.2 cm = 0.162 m

Time taken to walk, t = 6 minutes and 16 seconds = 376 seconds

Mass of the person, m = 89.2 kg

First, let's calculate the vertical distance traveled:

\(d=Nh\\\\\\\\\Longrightarrow d=(133)(0.162)\\\\\\\\\therefore d=21.546 \ m\)

Now, we can calculate the work done:

\(W= F d\\\\\\\\\Longrightarrow W=mgd\\\\\\\\\Longrightarrow W=(89.2)(9.8)(21.546)\\\\\\\\\therefore \boxed{\boxed{W\approx18834.7 \ J}}\)

Therefore, the person did approximately 18,515.7 joules of work.

Part (b): The average power performed by the person can be calculated using the formula:

\(\rightarrow P=\dfrac{W}{t}\)

Calculating the average power by plugging in the appropriate values into the above formula:

\(P=\dfrac{W}{t}\\\\\\\\\Longrightarrow P= \dfrac{18834.7}{376} \\\\\\\\\therefore \boxed{\boxed{P \approx 50.1 \ W}}\)

Therefore, the average power performed by the person during the walk was approximately 50.1 watts.

Part (c): To calculate the food Calories burned during the walk, we need to convert the work done from joules to kilojoules (kJ) and then to food Calories:

\(\rightarrow W \ \text{(in} \ kJ)=\dfrac{W \ \text{(in} \ J)}{1000}\\\\\\\\\Longrightarrow W \ \text{(in} \ kJ)=\dfrac{18834.7}{1000}\\\\\\\\\therefore W=18.8347 \ kJ\)

\(\rightarrow\text{Food Calories} = \dfrac{ W \ \text{(in} \ kJ)}{4.1868} \\\\\\\\\Longrightarrow \text{Food Calories} = \dfrac{ 18.8347}{4.1868}\\\\\\\\\therefore \boxed{\boxed{ \text{Food Calories} \approx 4.5 \ cal}}\)

Therefore, the person burned approximately 4.5 food Calories during the walk.


Related Questions

What component of fitness should you work on every time you exercise?

Answers

Answer:

1.body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardio respiratory endurance.

Explanation:

Answer:

The component of fitness you should work on every time you exercise are your muscular strength, muscular endurance, physique (body composition), your flexibility, and endurance.

Explanation:

it is important to focus on these types of exercise in order to have a well balanced routine/fitness and to stay in fit.

hope this helps !:)

A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the potential energy (U) of the toy when the spring is compressed 4.4 cm from its equilibrium position? *I found the KE, but need help on PE*

Answers

Answer:

0.14 J

Explanation:

The maximum velocity is the amplitude times the angular frequency.

vmax = Aω

ω = vmax / A

ω = (3.2 m/s) / (0.06 m)

ω = 53.3 rad/s

For a spring-mass system:

ω = √(k / m)

ω² = k / m

k = ω²m

k = (53.3 rad/s)² (0.050 kg)

k = 142 N/m

The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

What is the kinetic energy of a 10kg object moving at 2.0m/s? *

Answers

Answer:

20J

Explanation:

\(KE = \frac{1}{2} mv^{2} = \frac{1}{2} (10)(2)^{2} =20J\)

What is the average force of gravitation between Venus and the sun?

Answers

The average force of gravitation between Venus and the Sun is3.24 x 10²² N.

What is average gravitational force?

The force of gravitation between two objects can be calculated using the equation;

F = G (m1m2) /d²

where;

F is the force of gravitation, G is the gravitational constantm1 and m2 are the masses of the two objects, and d is the distance between them.

To find the average force of gravitation between Venus and the Sun, we need to know their masses and the average distance between them.

Venus has a mass of approximately  4.87 x 10²⁴ kg, and the average distance between Jupiter and the Sun is about 108 million kilometers.

Plugging these values into the equation, we get:

F = 6.67 x 10⁻¹¹ (4.87 x 10²⁴) x (1.989 x 10³⁰ kg) / (108 x 10⁶)²

F = 3.24 x 10²² N.

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Which statement describes the way in which energy moves between a
system of reacting substances and the surroundings?
OA. The potential energy of the system and its surroundings
increases.
B. The thermal energy of the system and its surroundings increases.
C. Molecular collisions create energy that is then released into the
surroundings.
D. Molecular collisions transfer thermal energy between the system
and its surroundings.

Answers

The correct statement is Molecular collisions transfer thermal energy between the system and its surroundings. Thus, option D is correct.

The energy moves between a system of reacting substances and the surroundings by the collision of molecules. The transfer of heat or thermal energy between the system and its surroundings by the process of Conduction. Conduction is the process of transmitting the heat to the neighboring atoms or collisions by the process of collisions.

The conduction takes place more steadily in solids and liquids where the molecules are closer together. When the molecules are collided with the nearby molecules, the potential energy is converted into kinetic energy and hence the heat energy is transferred between the system and its surroundings.

Hence, Molecular collisions transfer thermal energy between the system and its surroundings. Thus, the correct option is D.

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Which of the following is not true about minerals?

A
They always include oxygen and silicon.

B
They are naturally occurring materials.

C
They each have unique properties.

D
They have a crystalline structure.

Answers

A the always include oxygen and silicon

It is not true about minerals, that they always include oxygen and silicon. Option (A) is correct.

Minerals are inorganic, naturally occurring substances with a crystalline structure and a particular chemical makeup. They are solid substances that are created over a long period of time by geological processes in the crust of the Earth.

Even while silicon and oxygen are frequently occurring components in many minerals, not all minerals necessarily contain these elements. Minerals are inorganic, naturally occurring substances with a crystalline structure and a particular chemical makeup. They can be made of a wide range of substances, including silicon and oxygen, among others.

Hence, It is not true about minerals, that they always include oxygen and silicon. Option (A) is correct.

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For science class your teacher gives you and your partner a ball she ask you to figure out a way to Balance forces that you apply to the ball how do you partner show this?

Answers

Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.

What is Balanced Force?

The forces are balanced if the pullers are exerting equal force but going in the opposite direction on either side of the rope.

Forces that are balanced can cancel one another out. The thing stays in place whenever there is a balanced force.

To lift, turn, move, open, close, push, pull, and many other things requires forces. You apply force to a ball when you throw it in order for it to travel through the air. An object can be under the influence of multiple forces at once.

Therefore, Two forces are said to be balanced when their strengths are equal but their directions of action are opposing.

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What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?

Answers

To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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To determine the acceleration of an object moving in a straight line, you must calculate the change in its speed during each unit of?
a. velocity
b. time
c. motion
d. declaration
*giving brainliest!*

Answers

B is the Right Answer. TIME

why fan videos be streamed from the cloud to a computer with no lost quality

Answers

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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A war-wolf or trebuchet is a device used during the Middle Ages to throw rocks at castles and now sometimes used to fling large vegetables and pianos as a sport. A simple trebuchet is shown in the figure below. Model it as a stiff rod of negligible mass, d = 2.60 m long, joining particles of mass m1 = 0.115 kg and m2 = 68.5 kg at its ends. It can turn on a frictionless, horizontal axle perpendicular to the rod and 13.0 cm from the large-mass particle. The operator releases the trebuchet from rest in a horizontal orientation.
Find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally.

A war-wolf or trebuchet is a device used during the Middle Ages to throw rocks at castles and now sometimes

Answers

The maximum speed that the small-mass object attains when it leaves the trebuchet horizontally is approximately 28.3 m/s.

To find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally, we can apply the principle of conservation of mechanical energy.

Initially, the trebuchet is at rest, so its total mechanical energy is zero. As the small-mass object leaves the trebuchet horizontally, it gains kinetic energy. At this point, all of the potential energy of the system is converted into kinetic energy.

The potential energy of the system can be calculated as the sum of the gravitational potential energies of the two masses:

PE = m1 * g * h1 + m2 * g * h2

Since the trebuchet is released from rest in a horizontal orientation, the initial height h1 is zero. The height h2 can be calculated as the perpendicular distance between the pivot point and the center of mass of the larger mass m2:

h2 = 13.0 cm = 0.13 m

Therefore, the potential energy simplifies to:

PE = m2 * g * h2

The kinetic energy of the small-mass object can be calculated as:

KE = (1/2) * m1 * v^2

where v is the maximum speed of the small-mass object.

Since the total mechanical energy is conserved, we have:

PE = KE

m2 * g * h2 = (1/2) * m1 * v^2

Plugging in the given values, such as g = 9.8 m/s^2, m1 = 0.115 kg, m2 = 68.5 kg, and h2 = 0.13 m, we can solve for v:

(68.5 kg * 9.8 m/s^2 * 0.13 m) = (1/2) * 0.115 kg * v^2

Solving for v, we find:

\(v^2 = (68.5 kg * 9.8 m/s^2 * 0.13 m) / (0.115 kg)\)

\(v^2 = 800\)

v ≈ 28.3 m/s

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SHOW WORK.
What is the acceleration of the object
whose motion is described by the graph
above?
-0.0 m/s^2
-9.0 m/s^2
-4.5 m/s^2
-4.0 m/s^2

SHOW WORK.What is the acceleration of the objectwhose motion is described by the graphabove?-0.0 m/s^2-9.0

Answers

Acceleration is the rate of change of velocity, so if velocity is linear, the acceleration is the slope of its graph.

Here, the line passes through the points (0, 1) and (0.5, 3), so its slope is

(3 m/s - 1 m/s) / (0.5 s - 0 s) = (2 m/s) / (0.5 s) = 4 m/s²

part 1 of 2
A runner is jogging in a straight line at a
steady u, 2.2 km/hr. When the runner is
L 4 km from the finish line, a bird begins
flying straight from the runner to the finish
line at v= 6.6 km/hr (3 times as fast as the
runner). When the bird reaches the finish
line, it turns around and flies directly back to
the runner.
24
finish
line
L
What cumulative distance does the bird
travel? Even though the bird is a dodo, as-
sume that it occupies only one point in space
(a "zero" length bird), travels in a straight
line, and that it can turn without loss of
speed.
Answer in units of km.
Answer in units of km

Answers

After the given information and solving it the cumulative distance the bird travel is 6 km.

Equation :

The given parameters of the motion are;

The velocity of the runner,

vr  = 2.2 km/hr

The distance from the finish line and the bird begins to fly from the runner to the finish line,

L = 4 km

The direction and speed of the runner = 6.6 km/hr in a straight line to the finish line and back to the runner

The speed of the bird = 4 × The speed of the runner

Given,

The length of the bird = 0

The bird turns without loss of speed

The time it takes the bird to reach the finish line,

t₁ = 4 km / (6.6 km/hr) = 0.606 hr

The distance the runner runs in time t₁,

d = 2.2 km/hr × 0.606 hr

d = 1.3332 km

The distance runner and  bird combined travel before they meet,

X, is given as follows;

X = L - d

X = 4 km - 1.3332 km

X = 2.667 km

We get; X = (vr + vb) x t

Which gives;

2.667 = ( 2.2 + 6.6) × t

t = 2.667/( 2.2 + 6.6 )

t =  2.667/(8.8)

t = 0.303

The time it take for the bird and the runner to meet,

t = 0.303 hour

The distance the bird travels before reaching the runner,

d₂ = vb x t

So,

d₂ = 6.6 km/hr × 0.303 hr = 2 km

The cumulative distance the bird travels dt = L + d2

dt = 4 km + 2km

dt = 6 km

The cumulative distance the bird travels by the time it reaches the runner dt = 6 km

Alternatively, we have;

db = d₁ + d₃

dr = d₂

d₁ + d₃ + d₂ = 2·L

So, dr + db = 2·L

dr = The distance runner runs before meeting with the bird

db = The distance bird travels before meeting with the runner

db = 4dr

So,

dr +  db = 3 × 4 = 12

dr + 4· dr = 4 · dr = 12

dr = 12 /4 = 3

db =3 × dr

db = 3 × 2

db = 6 km

The distance bird travels before meeting with the runner,

db = 6 km

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How does the use of vectors
allow you to compare,
translate, and determine the
motion of a object?

Answers

Answer:

Explanation:

A vector is any substance that has both magnitude and direction. lndeed a vector quantity has both magnitude and direction. Example of a vector quantity is velocity. Determining the velocity of an object allows one to determine how fast and in what direction the object moves. Velocity also affords the opportunity to compare the motion of more than one vectors.

An ideal simple machine is one that...
Select one:
a. conserves force.
b. conserves distance.
c. conserves work.
d. conserves velocity.

Answers

An ideal simple machine is one that conserves forces because every input force is useful or not lost to friction and it is considered as a perfect or ideal system.

What is an ideal machine?

An ideal machine is a type of machine whose efficiency is 100 percent. This type of machine does not loss heat to friction or does no work against frictional forces.

When energy is not lost to friction, we say that such system is perfect or ideal. Or simply put, such system conserves forces.

In Ideal machine, mechanical advantage is one.

Mechanical advantage = output force / input force

In ideal simple machine, output force = input force

Therefore, ideal simple machine is one that conserves forces because every input force is useful or not lost to friction and it is considered as a perfect or ideal system.

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Consider a spinning plate is dropped onto a stationary plate (which is itself at rest on a frictionless surface). Both plates have a radius of 30cm and a mass of 1kg. The spinning plate is initially spinning at a rate of 0.7 revolutions per second. Hint: This is like a totally-inelastic collision.

Required:
a. After a sufficiently long time, what is the angular velocity of the initially-spinning plate? What about the initially-stationary plate?
b. Assume that the period of velocity matching happens over a course of 2 seconds. Further, assume that the torque exerted by each plate on the other is constant over time. In that case, what is the magnitude of the acceleration that each plate feels during those two seconds? Hint: Use the rotational impulse-momentum theorem.

Answers

Answer:

The final angular velocity is  \(w_f = 2.1994 rad/sec\)

The angular acceleration is  \(\alpha = 1.099 \ rad/sec^2\)

Explanation:

From the question we are told that

    The radius of each  plate is  \(r = 30 \ cm = \frac{30}{100} = 0.3 \ m\)

    The mass of each  plate is  \(m_p = 1 \ kg\)

    The angular speed of the spinning plate is \(w = 0.7 \ rev \ per \ sec = 0.7 * 2 \pi = 4.3988 \ rad/sec\)

  From the law of conservation of momentum

         \(L_i = L_f\)

Where \(L_i\) is the initial angular momentum of the system (The spinning and stationary plate ) which is mathematically represented as

          \(L_i = I_1 w + 0\)

here \(I_1\) is the moment of inertia of the spinning plate which mathematically represented as

              \(I_1 = \frac{m_pr^2}{2}\)

      and the zero signify that the stationary plate do not have an angular momentum as it is at rest at the initial state

         \(L_f\) is the final angular momentum of the system (The spinning and stationary plate) , which is mathematically represented as

              \(L_f = (I_1 + I_2 ) w_f\)

Where  

           \(I_2\) is the moment of inertia of the second plate (This was stationary before but now it spinning due to the first pate )   and is equal to  \(I_1\)

and  \(w_f\) is the final angular speed

So we have  

             \(I_1 w = (I_1 + I_2)w_f\)

             \(\frac{m_p r^2}{2} * w = 2 * \frac{m_p r^2}{2} * w_f\)

             \(w = 2 * w_f\)

substituting values

             \(4.3988 = 2 * w_f\)

            \(w_f = \frac{4.3988 }{2}\)

            \(w_f = 2.1994 rad/sec\)

The the rotational impulse-momentum theorem can be mathematially represented as

        \(\tau * \Delta t = 0.09891\)

Where \(\tau\) is the torque  and  \(\Delta t\) is the change in time  

So at  \(\Delta t = 2 \ sec\)

        \(\tau = \frac{0.09891}{2}\)

        \(\tau = 0.0995 \ Nm\)

now the angular acceleation is mathematically represented as

         \(\alpha = 2 * \frac{\tau}{m_p * r^2 }\)

substittuting values

           \(\alpha = 2 * \frac{0.0995}{1 * 0.3^2}\)

           \(\alpha = 1.099 \ rad/sec^2\)

       

     

A cows mass is 401 kg and a trucks mass is 832 kg. What is the difference between their weights . Answer please!!!

Answers

Answer:

403 kg is the diffrence

The index of refraction of n-propyl alcohol is 1.39. Find the angle of refraction of light in that medium if light comes from air with an angle of incidence of 55 degrees.

Answers

Answer:

36.11 degrees

Explanation:

index of refraction n = sin i/sinr

i is the angle of incidence

r is the angle of refraction

Substitute into the expression

1.39 = sin55/sin(r)

1.39 = 0.8191/sin(r)

sin(r) = 0.8191/1.39

sin(r) = 0.5893

r = arcsin(0.5893)

r = 36.11

hence the angle of refraction of light is 36.11 degrees

According to Newton's 3rd Law of Motion, Doug, a baseball
player hits a ball with his bat with a force of 1,000N. The ball
exerts a reaction force equally against the bat of

A.less than 1,000N
B.more than 1,00N
C.1,000N
D.double 1,000N

Answers

B,
the reaction according to Newton’s third law must be an equal and opposite reaction. The force will be greater in order to bounce off of Doug’s bat

NEED HELP What color is the container for R-134a refrigerant? A. Light blue B. Yellow C. Dark green D.White and yellow​

Answers

Answer:

It is A. Light blue

_____________

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╭━┻╮╲┗━━━━╮╭╮┈

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┈┈╰━┳┓┏┳┓┏╯┈┈┈

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A simple pendulum is constructed by attaching a 1.0 kg mass to a length L of fishing line. At the equilibrium point the pendulum bob has a kinetic energy of 2.0 joules and an angular velocity about the pivot point of 0.66 radians/sec. What is the period of the pendulum?​

Answers

The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds

How do i determine the period of the pendulum?

First, we shall list out the given parameters from the question. This is shown below:

Mass (m) = 1.0 KgKinetic energy (KE) = 2.0 joules Angular velocity (ω) = 0.66 radians/secPeriod of pendulum (T) =?

The period and angular velocity are related according to the following formula:

ω = 2π/ T

Inputting the given parameters, we can obtain the period of the pendulum as follow:

0.66 = (2 × 3.14) / T

0.66 = 6.28 / T

Cross multiply

0.66 × T = 6.28

Divide both sides by 0.66

T = 6.28 / 0.66

T = 9.52 seconds

Thus, we can conclude that the period of the pendulum is 9.52 seconds

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Kiting during a storm. The legend that Benjamin Franklin flew a kite as a storm approached is only a legend — he was neither stupid nor suicidal. Suppose a kite string of radius 2.02 mm extends directly upward by 0.823 km and is coated with a 0.506 mm layer of water having resistivity 159 Ω·m. If the potential difference between the two ends of the string is 186 MV, what is the current through the water layer? The danger is not this current but the chance that the string draws a lightning strike, which can have a current as large as 500 000 A (way beyond just being lethal).

Answers

Answer:

The current is   \(I  =  1.1434*10^{-5}}\  A\)

Explanation:

From the question we are told that

   The radius of the kite string is  \(R =  2.02 mm =  0.00202 \ m\)

   The  distance it extended upward is   \(D =  0.823 km = 823 \  m\)

   The thickness of the water layer is \(d = 0.506 mm  =  0.000506 \  m\)

   The resistivity is  \(\rho =  159\ \Omega  \cdot m\)

   The potential  difference is  \(V  =   186 MV =  186 *10^{6} \  V\)

Generally the cross sectional area of the water layer is mathematically represented as

      \(A =  \pi r^2\)

Here  r is mathematically represented as

      \(r =  [(R + d ) - R]\)

=>   \(r =  [(0.00202 +  0.000506 ) - 0.00202]\)

=>  \(r =  0.000506\)

=>     \(A = 3.142 *  [0.000506]^2 \)  

=>     \(A = 8.0447*10^{-7}\ m^2 \)  

Generally the resistance of the water is mathematically represented as

    \(R =  \frac{\rho  * D }{A}\)

=>   \(R =  \frac{159  *823 }{8.0447*10^{-7}}\)

=>   \(R = 1.62662 * 10^{11} \  \Omega  \)

Generally the current is mathematically represented as

      \(I  =  \frac{V}{R}\)

=>    \(I  =  \frac{186 *10^{6} }{1.62662 * 10^{11}}\)

=>    \(I  =  1.1434*10^{-5}}\  A\)

what is the value of 3 in
24.635​

Answers

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

What is Place Value?The value of each digit in a number is known as place value.For example the 2 in 125 represent 2 tens or 20, however the 2 in 2103 represent 2 thousands or 2000.Frequently, they will only include the letters like Millions, Hundred Thousands, Ten Thousands, Thousands, Hundreds, Tens, Ones, tenths, hundredths, and so on to denote each place.

How to solve this question?

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

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a double-decker london bus (figure 1) might be in danger of rolling over in a highway accident, but at the low speeds of its urban environment, it's plenty stable. the track width is 2.05 m. with no passengers, the height of the center of gravity is 1.45 m, rising to 1.73 m when the bus is loaded to capacity. What are the critical angles for both the unloaded and loaded bus?

Answers

When the bus is fully loaded, the center of gravity rises to 1.73 m, and the critical angles are 35.3 degrees for the unloaded bus and 30.6 degrees for the loaded bus, respectively.

Center of gravity: What is it?

Theoretically, the body's total weight is concentrated at a location called the center of gravity.

What distinguishes the center of mass from the center of gravity?

The main distinction between the centers of mass and gravity is that the center of gravity refers to the location where the total weight of the body is balanced, whereas the center of mass refers to the location where the body's complete mass is directed.

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In a DC generator, the generated emf is directly proportional to the

Answers

In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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(ASAP) would it be 125 m/s2 to calculate for her speeding up?

(ASAP) would it be 125 m/s2 to calculate for her speeding up?

Answers

Answer:

\(0\:\mathrm{ m/s^2}\)

Explanation:

Recall the formula for acceleration:

\(\displaystyle\\a=\frac{v_f-v_i}{\Delta t}\), where \(v_f\) is final velocity, \(v_i\) is initial velocity, and \(\Delta t\) is elapsed time (change in velocity over this amount of time).

Let's look at our time vs velocity graph. At t=0 seconds, V=25 m/s. So her initial velocity is 25 m/s.

We want to find the acceleration during the first 5 seconds of motion. Well, looking at our graph, at t=5 seconds, isn't our velocity still 25 m/s? Therefore, final velocity is 25 m/s (for this period of 5 seconds).

We are only looking from t=0 seconds to t=5 seconds which is a total period of 5 seconds. Therefore, elapsed time is 5 seconds.

Substituting values in our formula, we have:

\(\displaystyle a=\frac{25-25}{5}=\frac{0}{5}=\boxed{0\:\mathrm{m/s^2}}\)

Alternative:

Without even worrying about plugging in numbers, let's think about what acceleration actually is! Acceleration is the change in velocity over a certain period of time. If we are not changing our velocity at all, we aren't accelerating! In the graph, we can see that we have a straight line from t=0 seconds to t=5 seconds, the interval we are worried about. This indicates that our velocity is staying the same! At t=0 seconds, we have a velocity of 25 m/s and that velocity stays the same until t=5 seconds. Even though we are moving, we haven't changed velocity, which means our average acceleration is zero!

Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.

Answers

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

What is the  magnitude of the initial acceleration?

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Suppose a small plane can fly at 280 km/h [N] relative to the surrounding air. Suppose also that there is a 60 km/h [S] headwind. How fast does the plane's shadow move across the ground?

a. 300 km/hr

b. 220 km/hr

c. 240 km/hr

d. 210 km/hr

Answers

Answer:

b

Explanation:

On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the gravitational and electric forces on a small dust particle of mass 2.2 ✕ 10−15 g that carries a single electron charge. Fg FE = What is the acceleration (both magnitude and direction) of the dust particle? (Enter the magnitude in m/s2.) magnitude m/s2 direction ---Select---

Answers

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

\(\frac{F_E}{F_G}=\frac{qE}{mg}\)              (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

\(\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764\)

Then, the gravitational force is 0.764 times the electric force on the particle

b)

The acceleration of the particle is obtained by using the second Newton law:

\(F_E-F_G=ma\\\\a=\frac{qE-mg}{m}\)

you replace the values of all variables:

\(a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}\)

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?

Answers

mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

What is the energy of an electron that has undergone a 100 kV potential difference?

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

What is the relationship between kinetic energy and the de Broglie wavelength?

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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