A hydraulic lift is used to lift a car. The small piston has an area of 5 cm2 and the large piston has an area of 50 cm2. If a driver applies a force of 30 N to the small piston, what is the weight of the car the large piston can support

The true statement about the electric potential for the equipotential surface is  \(V_A = V_B = V_C\)

A surface with an equipotential potential is one where all points on the surface have the same electric potential. .

That is an equipotential surface is that surface at every point of which, the electric potential is the same.

The formula for the potential across every point on the surface is given as;

V = F/Q x R

V = ER

where;

Since the surface is equipotential with uniform electric across the surface, the electric potential at any point across the surface will be the same.

So \(V_A = V_B = V_C\)

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Answer:

≈39.2354 [m]

Explanation:

1) coordinates of the rock 1;

2) coordinates of the rock 2; note, ↑ means, the rock moves up, ↓ means the rock moves down;

3) the required distance.

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A uniform spherical shell of mass M = 12.0 kg and radius R = 0.370 m can rotate about a vertical axis on frictionless bearings (see the figure).

Why is the human eye spherical?

Anxiety in the Eye The inward force of interfacial tension in the eye's outer shell is also isotropic. The spherical structure of the eye is determined by the balance of these inward and external forces.

Is the eye spherical?

The globe (eyeball) is more pear-shaped, with a "bulge" on the front that houses the cornea, iris, and natural lens. The curvature of the corneal surface also is not perfectly spherical; it is a "spheroid," approximately the structure of a rugby ball.

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A spherical specimen of the mineral chalcopyrite measures 3.9 cm in diameter and has a mass of 129.67 g, its specific gravity is 4.17g/cm³

The ratio of a substance's density to that of a reference substance is its specific gravity, also known as relative density.

Water, which has a density of 1.0 kg/litre at 4 °C (39.2 °F), serves as the standard of comparison for solids and liquids (62.4 pounds per cubic foot).

Dry air, which is frequently used as a comparison point for gases, has a density of 1.29 grams per litre (1.29 ounces per cubic foot) under what are known as "standard conditions" (a temperature of 0 °C and a pressure of 1 standard atmosphere).

As an illustration, the specific gravity of liquid mercury is 13.6 due to its density of 13.6 kg per litre. The density of the gas carbon dioxide, which is 1.976 grams per liter under ideal conditions, translates into a specific gravity of 1.53 (= 1.976/1.29).

The formula for specific gravity is given by

specific gravity = density of the object / density of the water

Here given that a spherical specimen of the mineral chalcopyrite measures 3.9 cm in diameter and has a mass of 129.67 g

Then its volume is

Volume of sphere = \({\frac {4}{3}}\pi r^{3}\)

Substituting the values we get

V =  \({\frac {4}{3}}\pi (\frac{3.9}{2} )^{3}\)

   = 31.06 cm³

Density = Mass/Volume

Density of mineral chalcopyrite = 129.67g / 31.06 cm³

= 4.17 g/cm³

Now, we can finally calculate specific gravity

specific gravity = 4.17 g/cm³ / 1g/cm³                  (Density of water is 1m/1V)

= 4.17g/cm³

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Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

Answer: Negative punishment includes taking away a certain reinforcing item after the undesired behavior happens in order to decrease future responses. Positive punishment involves adding an aversive consequence after an undesired behavior is emitted to decrease future responses.

HOPE THIS HELPS

SUKHMANJOT

Answer:

here`s your answer

Winds often slow down during an eclipse as the atmosphere temporarily settles. Heating causes the atmosphere to mix and bubble, just like a pot of water on the stove. As it warms, the water level in the pot rises because warm objects, including water, expand. In the case of the atmosphere, it also expands when heated.

Explanation:

Hi there!

(A)

A grinding wheel is the same as a disk, having moment of inertia of:

\(I = \frac{1}{2}MR^2\)

Plug in the given mass and radius (REMEMBER TO CONVERT) to find the moment of inertia:

\(I = \frac{1}{2}(0.380)(0.085)^2 = 0.00137 kgm^2\)

(B)

We can use the rotational equivalent of Newton's Second Law to calculate the needed torque:

Στ = Iα = τ₁ - τ₂

Begin by solving for the angular acceleration. Convert rpm to rad/sec:

\(\frac{1750r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 183.26 rad/sec\)

Now, we can use the following equation:

ωf = wi + αt (wi = 0 rad/sec, from rest)

183.26/5 = α = 36.65 rad/sec²

τ = Iα = 0.0503 Nm

Since there is a counter-acting torque on the system, we must begin by finding that acceleration:

\(\frac{1500r}{min} * \frac{1 min}{60 s} * \frac{2\pi rad}{1 r} = 157.08 rad/sec\)

ωf = wi + αt

-157.08/55 = α = -2.856 rad/sec²

τ₂ = Iα = 0.0039 Nm

Now, calculate the appropriate torque using the above equation:

\(\Sigma\tau = \tau_1 - \tau_2\)

\(\Sigma\tau + \tau_2 = \tau_1\)

\(0.0503 + 0.0039 = \large\boxed{0.054 Nm}\)

Answer:

I = Δq / t

Explanation:

The quantity of electricity i.e charge is related to current and time according to the equation equation:

Q = It

Δq = It

Where:

Q => is the quantity of electricity i.e charge

I => is the current.

t => is the time.

Thus, we can rearrange the above expression to make 'I' the subject. This is illustrated below:

Δq = It

Divide both side by t

I = Δq / t

Answer:

630cm/s

Explanation:

In simple harmonic motion, the tangential velocity is expressed mathematically as v = ὦr

ὦ is the angular velocity = 2πf

r is the radius of the disk

f is the frequency

Given the radius of disk = 10cm

frequency = 10Hz

v = 2πfr

v = 2π×10×10

v = 200π

v = 628.32 cm/s

The tangential velocity = 630cm/s ( to 2 significant figures)

The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion.

Explanation:

The increase in the kinetic energy was found to be 300000 J

define kinetic energy ?

The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort while slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that contains a derivative with respect to time in the Lagrangian of a system.

kinetic energy was mentioned as ⇒1/2(m)v^2

kinetic energy =1/2(m)v^2

=1/2x2000x(10)^2

=100000 J

=1/2(m)v^2

=1/2x2000x(20)^2

=400000 J

therefore the increase in the kinetic energy was 400000-100000=300000 J

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Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω

Answer:

the trajectory for the missile \(\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}\)

the downrange of the missile R =  39570.6973 ft

Explanation:

Suppose the initial velocity v(0) = <1000, 1400, 368 > ft/sec

The single force which is acting over the missle is the gravitational force.

a (t) = <0, 0, -32>  ft/sec²

We are to  determine the trajectory and the downrange for the missle

Consider the motion  of a given object r(t) to be:

\(r(t) = v_it + \dfrac{1}{2}at^2\)

\(r(t) = \langle1000,1400,368 \rangle t + \dfrac{1}{2} \langle 0,0, -32\rangle t^2\)

\(r(t) = \langle1000t,1400t,368t \rangle + \langle 0,0, -16 t^2 \rangle\)

\(r(t) = \langle1000t,1400t, 368t -16t^2 \rangle\)

Thus, the trajectory for the missile \(\mathbf{r(t) = \langle1000t,1400t, 368t -16t^2 \rangle}\)

To determine the downrange of the missile,

\(v(0) = \langle 1000,1400,368 \rangle\)

where;

the horizontal vel. of the missle \(v_h= \sqrt{1000^2+1400^2}\)

= 1720.4651 ft/s

the vertical vel. of the missile is \(v_v = 368 \ ft/s\)

The time required to reach the ground \(t =\dfrac{2 \times v_v}{g}\)

\(t =\dfrac{2 \times 368}{32}\)

t = 23 sec

Finally, the downrange of the missile \(R = v_h \times t\)

R = 1720.4651  × 23

R = 39570.6973 ft

The trajectory of the missile as a function of time is obtained as

\(r(t)= <100t, 1400t, 368t-16t^2>\).

Given that the initial velocity is;

\(v(0) = <1000, 1400, 368>\,ft/sec\)

The acceleration of the missile is provided by the gravitational force.

\(a = g = <0, 0, -32>\,ft/sec^2\)

The trajectory of the object at time 't' is given by;

\(r(t)=v(0)\,t+\frac{1}{2} at^2= <100, 1400, 368>t\,+\frac{1}{2} <0, 0, -32>t^2\)

\(\implies r(t)= <100t, 1400t, 368t-16t^2>\)

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Answer:

You take the derivative of the velocity equation!

Explanation:

The acceleration basically refers to how the velocity changes over time. To find that, you need to take the derivative of the velocity equation. Comment if you would like me to show you what that looks like. Once you find the derivative you can plug your time value into the equation and get the acceleration at that time!

Answer:

find the rate of change of the velocity equation

Answer:

Explanation:

C

you haven't attached the diagram, but i assume that this diagram is what you were talking about

Answer:

near Y

Explanation:

the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.

The charge will most likely leave the electric field near Y letter. Hence option C is correct.

Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C

The charge on the electron is negative, and the force is directed in the opposite direction as the electric field. When an electron is projected perpendicular to a uniform electric field, it experiences an electric force in the opposite direction of the field.

the trajectory of the charged particle in the electric filed is parabolic and in magnetic field it is circular. when this electron moves perpendicular to the electric field, electron experience force in opposite direction to the electric field and due to parabolic nature, it will leave at Y.

Hence option C is correct.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

In this case, we have to use the potential energy definition

Where U = 1,780 Joules, h = 15 meters, g = 10 m/s2. Let's replace these values and solve for m

THERE ARE COMMONLY THREE SYSTEMS OF UNIT. THEY ARE:-

• CGS System- (Centimeter-Gram-Second system) A metric system of measurement that uses the centimeter, gram and second for length, mass and time.

• FPS System- (Foot–Pound–Second system).

The system of units in which length is measured in foot , mass in pound and time in second is called FPS system. It is also known as British system of units.

• MKS System- (Meter-Kilogram-Second system) A metric system of measurement that uses the meter, kilogram, gram and second for length, mass and time. The units of force and energy are the "newton" and "joule."

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Average speed is the ratio of the total distance to total time. The average velocity is the rate at which position changes. That is average velocity is the ratio of total displacement to the total time.

The speed is a scalar quantity and the velocity is a vector quantity.

The distance is the total length of the path of the object, whereas the displacement is the straight or the minimum distance between the initial and the final position of the object.

Therefore when an object completes its motion, the distance traveled by the object can be larger than the displacement.

Thus, an object can have a high average speed but a small average velocity.

Answer:

If two bumper cars collide with a certain force, then they will move away from each other in opposite directions with the same force. This demonstrates Newton's third law, which states that for every action, there is an equal and opposite reaction.

Explanation:

Acceleration of of flywheel is 0.624 m/s^2

Acceleration is the rate of change of an object's velocity with respect to time. Acceleration is a vector quantity. The direction of an object's acceleration is given by the direction of the net force acting on that object

Solution:

Tangential acceleration is given by,

\(a_{tan}\) = dv/dt

here, dt = time interval = 2.00 s

dv = change in linear speed of that point = Vf - Vi = (wf - wi)*r

r = radius of flywheel = 0.400 m

wf - wi = change in angular speed

from first rotational kinematics law,

wf - wi = α*dt

where,α= angular acceleration = 0.600 rad/s^2

then,

\(a_{tan}\) = α*r*dt/dt = α*r

\(a_{tan}\) = 0.600*0.400

\(a_{tan}\) = 0.240 m/s^2

Radial acceleration is given by,

\(a_{rad}\) = wf^2*r

here, again from first rotational kinematics law,

wf = wi +α*dt

wi = initial angular speed = 0 (As, starts from rest.)

then,

\(a_{rad}\) = (wi +α*dt)^2*r

\(a_{rad}\) = (0 + 0.600*2.00)^2*0.400

\(a_{rad}\) = 0.576 m/s^2

As, radial and tangential acceleration are always perpendicular to each other then resultant acceleration will be:

a = sqrt(arad2 + atan2)

a = sqrt(0.576^2 + 0.24^2)

a = 0.624 m/s^2

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When using a dial test indicator (DTI), it is essential to ensure that the gauge is positioned at a right angle to the contact surface for accurate readings.

However, in certain situations, it may be challenging to achieve a perfect right angle alignment. In such cases, adjustments can be made to compensate for the misalignment and obtain accurate measurements.To adjust the DTI reading when the gauge is not positioned at a right angle to the contact surface, the following steps can be taken:Determine the misalignment angle: Measure the angle at which the DTI is misaligned from the right angle position. This can be done using a protractor or by estimating the deviation visually.Calculate the correction factor: Based on the misalignment angle, calculate the correction factor using trigonometric functions such as sine or cosine. The correction factor accounts for the difference between the actual displacement and the displacement measured by the DTI.Apply the correction factor: Multiply the correction factor by the DTI reading to adjust the measurement. This compensates for the misalignment and provides a more accurate reading.It's important to note that adjusting the DTI reading can introduce some degree of error, especially if the misalignment is significant. Therefore, it is always preferable to position the gauge at a right angle to the contact surface whenever possible to obtain the most precise measurements.

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Answer:

It isn't moving

Explanation: