A guitar factory has a cost of production C(x) = 100x + 56000 , where is the number of guitars produced . If the company needs to break even after 150 units sold, at what price should they sell each guitar ? Use the variable p to represent the price Round up to the nearest dollar .

Answer:

it have the property of parallelogram ,

When \(y\ge0\) (above and on the \(x\)-axis), we have \(|y|=y\). The parabola \(x=y^2\) intersects with \(x=-|y|+12\) in this region when

\(y^2 = -y + 12 \implies y^2 + y - 12 = (y-3)(y+4) = 0 \implies y=3\)

On the other hand, when \(y<0\) (below the \(x\)-axis, we have \(|y|=-y\), and so the curves intersect when

\(y^2 = -(-y) + 12 \implies y^2 - y - 12 = (y - 4)(y+3) = 0 \implies y=-3\)

The area between the curves is then given by the definite integral,

\(\displaystyle \int_{-3}^3 (-|y| + 12) - y^2 \, dy\)

The integrand is symmetric about the \(x\)-axis, so the integral is equivalent to

\(\displaystyle 2\int_0^3 12 - y - y^2 \, dy = 2 \left(12y - \frac{y^2}2 - \frac{y^3}3\right)\bigg|_0^3 = \boxed{45}\)

Answer:

40

Step-by-step explanation:

A. 50 - 10 = b

B. Finding the equivalence is the first step

C. b = 40

D. Subtracting 10 from 50

E. Already did b = 40

F. Yes, they both work the same way.

G. you have choices to make to get the right answer.

The abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).

Given the equation x^2 = 2y.

The coordinates of the point are (4,1).We have to find the abscissa on the curve that is nearest to this point.So, let's solve this question:

To find the abscissa on the curve x2 = 2y which is nearest to the point (4,1), we need to apply the distance formula.In terms of x, the formula for the distance between a point on the curve and (4,1) can be written as:√[(x - 4)^2 + (y - 1)^2]But since x^2 = 2y, we can substitute 2x^2 for y:√[(x - 4)^2 + (2x^2 - 1)^2].

Now we need to find the value of x that will minimize this expression.

We can do this by finding the critical point of the function: f(x) = √[(x - 4)^2 + (2x^2 - 1)^2]To do this, we take the derivative of f(x) and set it equal to zero: f '(x) = (x - 4) / √[(x - 4)^2 + (2x^2 - 1)^2] + 4x(2x^2 - 1) / √[(x - 4)^2 + (2x^2 - 1)^2] = 0.

Now we can solve for x by simplifying this equation: (x - 4) + 4x(2x^2 - 1) = 0x - 4 + 8x^3 - 4x = 0x (8x^2 - 3) = 4x = √(3/8)The abscissa on the curve x^2 = 2y that is nearest to the point (4,1) is x = √(3/8).T

he main answer is that the abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).

The abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).

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Answer:

(4k^2+7)(7k+6)

Step-by-step explanation:

1. group the first two terms (28k^3-24k^2). The greatest common factor is 4k^2. If you factor that out you get 4k^2(7k-6)

2.When you group the last two terms (49k-42). you can factor out a 7.

7(7k-6).

3. There is a (7k-6) in both sections so you can combine all the terms.

4k^2(7k-6) 7(7k-6) becomes (4k^2)(7k-6)

The view factor from the 2 cm side to the 4 cm side of the infinitely long three-sided triangular enclosure is approximately 0.5.

The view factor (F) from Surface A to Surface B can be calculated using the formula:

F = A / (A + B)

where A and B are the areas of Surface A and Surface B, respectively.

The area of a triangle can be calculated using Heron's formula:

Area = sqrt(s * (s - a) * (s - b) * (s - c))

where s is the semi-perimeter of the triangle and a, b, and c are the side lengths of the triangle.

For Surface A:

a = 2 cm

b = 3 cm

c = 4 cm

s = (a + b + c) / 2 = (2 + 3 + 4) / 2 = 4.5 cm

Area_A = sqrt(4.5 * (4.5 - 2) * (4.5 - 3) * (4.5 - 4))

= √(4.5 * 2.5 * 1.5 * 0.5)

=√(5.625) ≈ 2.37 cm²

For Surface B:

a = 2 cm

b = 4 cm

c = 3 cm

s = (a + b + c) / 2 = (2 + 4 + 3) / 2 = 4.5 cm

Area_B = √(4.5 * (4.5 - 2) * (4.5 - 4) * (4.5 - 3))

= √(4.5 * 2.5 * 0.5 * 1.5)

=√(5.625) ≈ 2.37 cm²

Now we can calculate the view factor (F):

F = Area_A / (Area_A + Area_B)

= 2.37 / (2.37 + 2.37)

≈ 0.5

Therefore, the view factor from the 2 cm side to the 4 cm side of the infinitely long three-sided triangular enclosure is approximately 0.5.

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Isaac is preparing refreshments for a party, and he has decided to make a smoothie that is both fruity and refreshing. Isaac will make 1.875 gallons of smoothie.

To make this delicious drink, he will mix 3 quarts of strawberry puree with 1 pint of lemonade and 1 gallon of water.

Now, to determine how much smoothie Isaac will make, we need to convert all the measurements into the same unit. Since we are using quarts, pints, and gallons, we need to convert them all into gallons to get the total volume of the smoothie.

First, we need to convert the 3 quarts of strawberry puree into gallons. Since there are 4 quarts in a gallon, 3 quarts is 0.75 gallons. Next, we need to convert the 1 pint of lemonade into gallons. Since there are 8 pints in a gallon, 1 pint is 0.125 gallons. Finally, we need to convert the 1 gallon of water into... well, a gallon!

So, adding up all the volumes of the ingredients, we have:

0.75 gallons (strawberry puree) + 0.125 gallons (lemonade) + 1 gallon (water) = 1.875 gallons

Therefore, Isaac will make 1.875 gallons of smoothie. This should be enough for a decent-sized party, but he might want to double or triple the recipe depending on the number of guests.

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Answer:

4

Step-by-step explanation:

4/1 or 4

y over x, and simplify

Answer:

1 by 2 is o

Step-by-step explanation:

so slope is 1 by 2 of o .

The number of ways to draw 3 non-face cards, 2 kings, and 2 queens from a deck of 52 cards is 5,334,720.

1. There are 52 cards in a deck, with 12 face cards (3 face cards per suit: J, Q, K) and 40 non-face cards (10 cards per suit: Ace-10).

2. For 3 non-face cards: there are 40 non-face cards, and you choose 3, so use the combination formula: C(40,3) = 40! / (3! * (40-3)!) = 9,880.

3. For 2 kings: there are 4 kings in the deck, and you choose 2, so use the combination formula: C(4,2) = 4! / (2! * (4-2)!) = 6.

4. For 2 queens: there are 4 queens in the deck, and you choose 2, so use the combination formula: C(4,2) = 4! / (2! * (4-2)!) = 6.

5. Multiply the results: 9,880 (non-face cards) * 6 (kings) * 6 (queens) = 5,334,720 possible ways.

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Answer:

2x + y = 18

y = 4x - 12

x = 5,  y = 8

Step-by-step explanation:

x = 1st number

y = 2nd number

We can use the substitution method as we know what 'y' equals; that value will get plugged in for 'y' in the first equation as follows:

2x + 4x - 12 = 18

6x - 12 = 18

6x = 30

x = 5

y = 4(5) - 12 which is 20-12 or 8

y = 8

As per the given triangle, the value of x ≈ 7√3 and y = 14.

We may utilise the characteristics of a right triangle and trigonometric ratios to get the values of x and y in a triangle with angles of 60 degrees and 90 degrees.

The angle (90 degrees) in a right triangle that is opposite the right angle is always 90 degrees. The hypotenuse of this triangle is the side that is opposite the 90-degree angle.

Given that one of the triangle's angles is 60 degrees, the other two must add up to 180 - 60 = 120 degrees.

Using the sine ratio:

sin(60 degrees) = opposite / hypotenuse

sin(60 degrees) = x / y

Since sin(60 degrees) = √3 / 2, we have:

√3 / 2 = x / y

x = (√3 / 2) * y

\(y^2 = 7^2 + x^2\\\\y^2 = 49 + (\sqrt{3 / 2} * y)^2\\\\y^2 = 49 + 3/4 * y^2\\\\1/4 * y^2 = 49\\\\y^2 = 4 * 49\)

y = √(4 * 49)

y = 2 * 7

y = 14

x = (√3 / 2) * y

x = (√3 / 2) * 14

x = √3 * 7

x ≈ 7√3

Thus, x ≈ 7√3 and y = 14.

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The task requires analyzing a list of departments and performing several tasks related to relationship codes, activity relationship diagrams, reason codes, a worksheet, and a dimensionless block diagram.

We need to consider the number of departments. Since we have 7 departments listed, the number of relationship codes can be calculated using the formula: (n * (n-1)) / 2, where n is the number of departments.

Substituting the value of n = 7, we get:

Relationship Codes = (7 * (7-1)) / 2

= (7 * 6) / 2

= 42 / 2

= 21

Therefore, there will be 21 relationship codes in the chart.

Create an activity relationship diagram:

An activity relationship diagram visually represents the relationships between departments. Here is a basic diagram representing the given departments:

Receiving --+

           +-- Assembly & Shipping -- Offices

Fabrication--+

           +-- Painting -- Stores

Restrooms & Lockers

Populate the diagram with codes for all the relationships:

To populate the diagram with codes, we can assign a unique code to each relationship. Here's an example of assigning codes to the relationships in the diagram:

Receiving (R) --+

               +-- Assembly & Shipping (AS) -- Offices (O)

Fabrication (F)--+

               +-- Painting (P) -- Stores (S)

Restrooms & Lockers (RL)

What is the percentage of codes in each category? Does it follow the standard percentages?

To determine the percentage of codes in each category, we need to count the number of codes in each category and calculate the percentage relative to the total number of codes (21).

In this case, we have the following categories and their respective codes:

Production: R, F, AS, P (4 codes)

Administration: O, S (2 codes)

Support: RL (1 code)

Percentage of Production codes = (4 / 21) * 100 ≈ 19.05%

Percentage of Administration codes = (2 / 21) * 100 ≈ 9.52%

Percentage of Support codes = (1 / 21) * 100 ≈ 4.76%

These percentages do not necessarily follow any standard percentages. The distribution of codes among categories can vary depending on the specific organization or context.

Provide at least 3 reason codes for the chart:

Reason codes are used to provide explanations or justifications for the relationships depicted in the chart. Here are three example reason codes for the given chart:

R01: Receiving department receives raw materials and supplies from external sources.

AS01: Assembly & Shipping department assembles products and prepares them for shipment.

O01: Offices department provides administrative support and management functions for the organization.

Create a worksheet to assist in the creation of the dimensionless block diagram:

Here's an example of a worksheet that can assist in creating the dimensionless block diagram:

Relationship Code From Department To Department

R Receiving Fabrication

F Fabrication Painting

AS Assembly & Shipping Offices

P Painting Stores

RL Restrooms & Lockers -

O Offices -

S Stores -

This worksheet lists the relationship codes along with the corresponding "From" and "To" departments.

Create a dimensionless block diagram for your data B. Show the flow through the dimensionless block diagram:

A dimensionless block diagram represents the flow of activities or information between different departments. Here's an example of a dimensionless block diagram based on the given data:

Receiving --> Fabrication --> Painting --> Stores

                  |

                  v

        Assembly & Shipping --> Offices

                  |

                  v

       Restrooms & Lockers

The arrows indicate the flow of activities or information from one department to another.

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Answer:

3/10

Step-by-step explanation:

you do 3/5 times 1/2 which is 3/10

half of 3/5 is 3/10

hope this helps

correct me if this is wrong

Answer:

100 feet

Step-by-step explanation:

I did the test hope it helps a lot have a good day

The sequence of natural numbers that leaves a remainder of 3 when divided by 10 is:

3, 13, 23, 33, 43, 53, 63, 73, 83, 93, 103, 113, ...

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

she bought 11 cookies and 1 mince pie

Answer:

She bought 6 cookies and 3 mini pies.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

  work = 1,830,000 ft·lb

Step-by-step explanation:

You want the work done to lift 650 lb of coal 600 ft up a mine shaft using a cable that weighs 8 lb/ft.

For some distance x from the bottom of the mine, the weight of the cable is ...

  8(600 -x) . . . . pounds

The total weight being lifted is ...

  f(x) = 650 +8(600 -x) = 5450 -8x

The incremental work done to lift the weight ∆x feet is ...

  ∆w = force × ∆x

  ∆w = (5450 -8x)∆x

We can use a sum for different values of x to approximate the work. For example, the work to lift the weight the first 50 ft can be approximated by ...

  ∆w ≈ (5450 -8·0 lb)(50 ft) = 272,500 ft·lb

If we use the force at the end of that 50 ft interval instead, the work is approximately ...

  ∆w ≈ (5450 -8·50 lb)(50 ft) = 252,500 ft·lb

We can see that the first estimate is higher than the actual amount of work, because the force used is the maximum force over the interval. The second is lower than the actual because we used the minimum of the force over the interval. We expect the actual work to be close to the average of these values.

The attached spreadsheet shows the sums of forces in each of the 50 ft intervals. The "left sum" is the sum of forces at the beginning of each interval. The "right sum" is the sum of forces at the end of each interval. The "estimate" is the average of these sums, multiplied by the interval width of 50 ft.

The required work is approximated by 1,830,000 ft·lb.

__

Additional comment

The actual work done is the integral of the force function over the distance. Since the force function is linear, the approximation of the area under the force curve using trapezoids (as we have done) gives the exact integral. It is the same as using the midpoint value of the force in each interval.

Because the curve is linear, the area can be approximated by the average force over the whole distance, multiplied by the whole distance:

  (5450 +650)/2 × 600 = 1,830,000 . . . . ft·lb

Another way to look at this is from consideration of the separate masses. The work to raise the coal is 650·600 = 390,000 ft·lb. The work to raise the cable is 4800·300 = 1,440,000 ft·lb. Then the total work is ...

  390,000 +1,440,000 = 1,830,000 . . . ft·lb

(The work raising the cable is the work required to raise its center of mass.)

The perimeter of the rectangle is  4y + 6 (cm).

All four side lengths must be added up in order to get the perimeter, or the distance around the rectangle. Since there are two of each side length, it is simple to multiply the total of the length and the breadth by two in order to do this task effectively. The formula for perimeter is perimeter=(length Plus width)2.

The diagram shows a rectangle. All measurements are in centimetres  an expression in terms of y, for the perimeter of the rectangle.

The perimeter of the rectangle is

2(y+3)+24

=2y + 6 + 2y = 4y + 6 (cm)

{ the perimeter:

2 *  width + 2 * Length}

The perimeter of the rectangle is  4y + 6 (cm).

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Answer:

The answer is 30

Step-by-step explanation:

30 divided by 3 is 10.

Just multiply 3 and 10

Answer:

x = 30

Step-by-step explanation:

Quotient is division

Is means equals

x/3 =10

Multiply each side by 3

x/3 * 3 = 10 *3

x = 30

The two equation to set up to solve the equation |3x - 2| = 19 are

Question 2

x = 5 OR -9

Question 3

x ≥ 6 OR x ≥ -9

Without taking direction into account, absolute value describes how far away from zero a certain number is on the number line.

A number can never have a negative absolute value.

The equation is written in the form below

|3x - 2| = 19

removing the absolute value sign

3x - 2 = ± 19

the two equations are

3x - 2 = 19

3x - 2 = -19

Question 2

solving for x

3|x + 2| - 7 = 14

3|x + 2| = 14 + 7

3|x + 2| =  21

divide through by 3

|x + 2| =  7

removing the absolute value sign

x + 2 =  ±7

solving for x for positive value

x + 2 = 7

x = 5

solving for the negative sign

x + 2 = -7

x = -9

Question 3

-2|2x+3| + 14 ≥ -16

-2|2x+3| ≥ -30

dividing through by -2

|2x+3| ≥ 15

2x+3 ≥ ±15

solving for the positive sign

2x+3 ≥ 15

x ≥ 6

solving for the negative sign

2x+3 ≤ -15

x ≥ -9

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The missing length of the rectangle is w = 1 + 3 · x⁻¹ + (5 / 2) · x · y⁻¹, whose perimeter is p = 2 · [1 + 3 · x⁻¹ + (5 / 2) · x · y⁻¹ + 4 · x² · y²].

In this problem we need to determine the missing length and the perimeter of a rectangle. have the area equation of a rectangle, whose definition is introduced below:

A = w · h

Where:

And we need to determine the perimeter of the abovementioned figure:

p = 2 · (w + h)

Where p is the perimeter.

If we know that A = 4 · x² · y² + 12 · x · y² + 10 · x³ · y and h = 4 · x² · y², then the missing length and the perimeter of the rectangle are, respectively:

4 · x² · y² + 12 · x · y² + 10 · x³ · y = w · h

4 · x² · y² · (1 + 3 · x⁻¹ + (5 / 2) · x · y⁻¹) = w · h

w = 1 + 3 · x⁻¹ + (5 / 2) · x · y⁻¹

p = 2 · [1 + 3 · x⁻¹ + (5 / 2) · x · y⁻¹ + 4 · x² · y²]

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Answer:

The missing length is 37.

Step-by-step explanation:

Perimeter is basically adding up the sides.

So,

8+25+25+15+15=88

125-88= 37

Answer:

m<1=159 degree

m<2=21 degree

m<4=21 degree

Answer:

The system of equations is:

\(a+s = 250\\5a+2.50s = 837.50\)

Here a is the number of adult tickets and s is the number of student tickets

Step-by-step explanation:

We will use the given statements to make a system of equations for the given scenario.

First of all we have to decide which variables to be used.

Let a be the number of adult tickets and

Let s be the number of student tickets

So according to the statement that the department sold 250 tickets in total, the equation will be:

\(a+s = 250\)

This is equation one of the system of equations

According to the statement that cost of adult ticket is $5, total cost of adult tickets will be: \(5a\)

According to the statement that cost of student ticket is $2.50, total cost of student tickets will be:\(2.50s\)

The total earning was $837.50 so the second equation will be:

\(5a+2.50s = 837.50\)

Hence,

The system of equations is:

\(a+s = 250\\5a+2.50s = 837.50\)

Here a is the number of adult tickets and s is the number of student tickets

Answer:

1 13/50

Step-by-step explanation:

4 1/5 * 3/10

Change the mixed number to an improper fraction

4 1/5 = (5*4+1)/5 = 21/5

21/5 *3/10

63/50

Changing back to a mixed number

1 13/50

Answer:

1 13/50

Step-by-step explanation:

4⅕ × 3/10

21/5 × 3/10

63/50

1 13/50

Answerit is false

Step-by-step explanation: smart

Given statement :- 5y = 8x does not represent direct variation.

K= the coefficient is 8/5 instead of a single constant value.

In the equation 5y = 8x, we can determine whether it represents direct variation by comparing it to the general form of a direct variation equation: y = kx, where k is the constant of variation.

If we rewrite the given equation in the form y = kx, we divide both sides by 5 to isolate y:

y = (8/5)x

Comparing this to the general form, we can see that the given equation is not in the direct variation form. In a direct variation equation, the coefficient of x (the constant of variation, k) should remain constant, but in this case, the coefficient is 8/5 instead of a single constant value.

Therefore, the given equation does not represent direct variation.

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