А geostationary satellite moves in an orbit of radius 6300km. Calculate the speed with which it moves in the orbit [π=22÷7]​

The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)

The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.

To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).

The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).

In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).

Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.

If co > co_critical, the system is considered overdamped (Option E).

If co = co_critical, the system is considered critically damped (Option D).

If co < co_critical, the system is considered underdamped (Option C).

Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.

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What What What What...... error

Answer:

Mass Kinetic Energy and Jules

Explanation:

The train in question is  big and heavy and a car is decently heavy but say a train moving at 55 mph can plow through a car and a car driving at 55mph driving at a train will be stopped dead in its tracks. This is because newtons laws of motion specifically an object in motion will stay in motion unless its opposed. The train also has a payload behind it meaning it hurts with force while a car doesn't have to much mass behind it. The train takes loner to stop for as it's acceleration as well as it's deceleration are very slow because its huge and takes a lot of force to stop it while a car is very centralized and compact when it comes to weight and its brakes are usually effective at stopping at 55 mph in about 2 to 6 seconds while a train might stay moving for a good 35 seconds. The force behind the train is immense for as even if the wheels don't spin at all the train will still move since the force behind it is great and a cars tires have a lot of grip and not a lot mass which plays into the force the car has so it can stop simply.

Answer:

the index of refraction of the coating is 1.33  

Explanation:

Given the data in the question;

refraction index of  interior portion of the rod η\(_{interior\) = 1.55

angle of incidence θ\(_i\) = 59.5°

From Snell's law, we know that;

η\(_{interior\) × sinθ\(_i\)  = η\(_{coating\) × sinθ\(_r\)

where η\(_{interior\)  is the index of refraction of the rod ( material 1 )

θ\(_i\)  is the angle of incidence

η\(_{coating\) is the index of refraction in outer coating ( material 2 )

θ\(_r\) is the angle of refraction

so we substitute our values into the equation;

η\(_{interior\) × sinθ\(_i\)  = η\(_{coating\) × sinθ\(_r\)

1.55 × sin( 59.5° )  = η\(_{coating\) × sin( 90° )

1.55 × 0.861629  = η\(_{coating\) × 1

1.3355 = η\(_{coating\) × 1

η\(_{coating\) = 1.33   { 2 decimal places }

Therefore, the index of refraction of the coating is 1.33  

Answer:

6.75m/s

Explanation:

using the second equation of motion, the time is calculated.

and with the formula a= (v - u)/t

where a is acceleration but in this case it's deceleration (and should be negated as you solve it ) .

v is final velocity

u is initial velocity

t is time taken

Answer: a

Explanation: :)

Answer: five

Each player may accrue up to five personal fouls a game prior to disqualification. A common foul occurs away from the ball and does no affect attempted shots. Free-throws: Penalty shots are awarded as follows: a) one free throw for a shooter whose goal is successful and is fouled while shooting.

Explanation:

Answer:

5

Explanation:

The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:

\($$F=k\frac{q_1q_2}{r^2}$$\)

where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:

\($$E=\frac{kq}{r^2}$$\)  where k is the Coulomb constant.

So, let's calculate the electric field due to each charge separately and then add them up:

For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)

For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:

\($$E_2=\frac{kq_2}{r^2}\)

\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)

The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.

To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)

Substituting the values of E1 and E2:

\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)

net comes out to be -1.5×10⁴ N/C.

Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.

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The size and aperture of the telescopes determine its ability to gather light

and reveal details.

A) Observatory X can detect dimmer stars and Observatory Y reveals more

details.

Reasons:

The benefits of using several small telescopes included the production

high resolution images of bright objects such as binary stars that reveal

more details similar to a telescope with a very large aperture, with a

process known as interferometry, through which a star's diameter can be

determined.

The benefit of a large telescope is its ability to gather light from a source,

thereby making possible to detect a dim light source, such as dimmer

stars.

Therefore;

The single large telescope in observatory X can detect dimmer stars while

the interferometer consisting of five 10-meter telescopes, spread out over a

region 100 meters across can see more detail in its images.

The correct option is; A) Observatory X can detect dimmer stars and

Observatory Y reveals more details.

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Question options:

A) Observatory X can detect dimmer stars and Observatory Y reveals more

details.

B) Observatory Y can detect dimmer stars and Observatory X reveals more

details.

C) Observatory X both detect dimmer stars and reveals more details

D) Observatory Y both detect dimmer stars and reveals more details

When the crest of one wave passes through the trough of another wave, destructive interference takes place.

The crest and trough of a wave, respectively, are its highest and lowest surface portions. The wave height is the vertical distance between the peak and trough. The wavelength is the horizontal separation between two consecutive crests or troughs.

When the crest of one wave passes through the trough of another wave, interference takes place.

This interference can be constructive, where the amplitudes of the waves add up, resulting in a larger wave, or destructive, where the amplitudes of the waves cancel out, resulting in a smaller wave or no wave at all.

The type of interference that occurs depends on the relative amplitudes, wavelengths, and phases of the two waves.

Therefore, destructive interference takes place when the crest of one wave passes through the trough of another wave.

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No matter the detector, the pattern on the screen is still non-interference.

In the double-double slit experiment, photons are momentum entangled and can share information about each other's which-slit paths if one of them is found near any double slit. If a single slit of a double-slit is blocked, it is possible to determine the which-slit path from the simultaneous photon detection.

In quantum physics, the double-slit experiment serves as a prominent illustration of the observer effect. The measured outcomes of this experiment can alter if quantum phenomena are observed, according to physicists.

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Answer:

The horizontal range is maximum when θ is equal to 45°

Explanation:

Projectile Motion

It's known as the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and \(g=9.8\ m/s^2\) the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\(\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}\)

Since the sine of an angle is bounded between -1 and 1, the maximum range will occur when the sine is 1:

\(\sin(2\theta)=1\)

The only angle between 0° and 360° whose sine is 1 is 90°, thus:

\(2\theta=90^\circ\)

Solving:

\(\theta=45^\circ\)

The horizontal range is maximum when θ is equal to 45°

The horizontal range is maximum for the value of angle equivalent to \(45^{\circ}\).

Given data:

The player kicks the ball with an angle \(\theta\) with the horizontal.

The given problem is based on the concept and fundamentals of projectile motion. In a projectile motion, the horizontal range is the horizontal distance covered by an object during its trajectory.

The mathematical expression for the horizontal range is given as,

\(R = \dfrac{u^{2}sin2 \theta}{g}\)

Here,

R is the horizontal range.

u is the initial speed.

And g is the gravitational acceleration.

Clearly, if we need maximum horizontal range, then we need to have the maximum value of sine. So if,

\(\theta =45^{\circ}\)

\(sin2 \theta=sin90\) = 1

So the maximum range is,

\(R = \dfrac{u^{2}sin(2 \times 45^{\circ})}{g}\\\\R = \dfrac{u^{2} \times sin 90^{\circ}}{g}\\\\R = \dfrac{u^{2}}{g}\)

Thus, we can conclude that the horizontal range is maximum for the value of angle equivalent to \(45^{\circ}\).

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The forces, act upon the block which  is at rest on an inclined plane, are:

Two surfaces that come into contact and glide against one another produce frictional force.

When  the block is on an inclined plane, its weight is acting downwards for force of gravity, the surface on the plane acts an upward force named normal force. But to become it rest, a resistive frictional force acts on it. Hence, the  forces, acts upon the block, are:

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Answer:

The three agents of sediment transport, which result in deposition as energy decreases, are ice, wind, and water.

Answer:

100.390407

Explanation:

To find acceleration, you would use the formula a=f/m (acceleration equals force divided by mass) and then once you enter those numbers in the formula, a=180/1.793. Then you divide 180 divided by 1.793 which gets you an answer of 100.390407.

Answer:

Yellow dwarfs are small, main sequence stars. The Sun is a yellow dwarf. A red dwarf is a small, cool, very faint, main sequence star whose surface temperature is under about 4,000 K. Red dwarfs are the most common type of star. Proxima Centauri is a red dwarf.

Explanation:

Answer:

Red dwarfs are low-mass main-sequence stars. Yellow dwarfs are main-sequence (dwarf) stars with masses comparable to that of the Sun.

Explanation:

Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

Answer:

get some

get some ⛽⛽⛽⛽⛽

pour the ⛽ on the module,

get that on itttttt and booooooommmm

Explanation:

Answer:

Cu + Br2 = CuBr2

Explanation:

Written above is the balanced version of the equation. It is a synthesis reaction.

The best explanation for why the results are the same for a positively charged rod and a negatively charged rod is that the charge on the spheres is redistributed to create opposite charges on the spheres.

The charge on the spheres is redistributed to create opposite charges on the spheres, which is why the results are the same for a positively charged rod and a negatively charged rod. This redistribution happens as a result of induction. As a result of the charge redistribution, the spheres develop an attraction to the rod. When a negatively charged rod is brought close to the spheres, the charge on the spheres is redistributed, causing one of the spheres to have a net positive charge and the other to have a net negative charge.

The sphere with the opposite charge (in this case, the one with a net positive charge) is attracted to the negatively charged rod, while the sphere with the same charge (in this case, the one with a net negative charge) is repelled. This redistribution results in the spheres separating from one other.When a positively charged rod is brought near the spheres, the same charge redistribution occurs, resulting in the same attraction between the oppositely charged sphere and the rod. Sphere B is far away, hence it does not undergo any charge redistribution as a result of the presence of the charged rod.

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300 meters = 0.186411 miles, 65 minutes = 1.08333 hours, 35 yards = 32.004 meters

1. To convert 300 meters to miles, you can use the conversion factor 1 mile = 1609.344 meters. So, 300 meters = 300/1609.344 miles = 0.186411 miles.
2. To convert 65 minutes to hours, you can use the conversion factor 1 hour = 60 minutes. So, 65 minutes = 65/60 hours = 1.08333 hours.
3. To convert 35 yards to meters, you can use the conversion factor 1 yard = 0.9144 meters. So, 35 yards = 35*0.9144 meters = 32.004 meters.
In summary:
300 meters = 0.186411 miles
65 minutes = 1.08333 hours
35 yards = 32.004 meters

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Answer:

The surface closest to the balloon becomes positively charged, while the far side of the can becomes negatively charged. This results in an attractive force that draws the can to the balloon.

Explanation:

Answer:

The balloon is negatively charged.

Explanation:

hope it helps

Answer:

11.a) Car B  is faster than Car A. This is because Car B covers more distance in less time, whereas Car A covers less distance in more time. Now, as we know that distance is directly proportional and time is inversely proportional to speed. In Car B, a larger distance and less time and a smaller distance and more time in Car A, indicates that the speed of Car B is more than the speed of Car A.

b) Car B accelerates faster than Car A. We know that, the acceleration is directly proportional to the change in linear velocity and inversely proportional to time taken. Here, The overall journey of Car B is short, whereas for Car A, it's longer. Also, as previously mentioned that the final speeds of Car B is more than Car A [remembering that both Cars start from the origin(rest)]. Hence, the change of velocity in Car B is more than Car A. Hence so.

Careful measurements of the shifting spectral lines in an ordinary star orbiting a black hole can provide valuable information about the presence and properties of the black hole.

By observing the shifting of spectral lines, scientists can infer the presence of a massive object exerting gravitational influence on the star. This gravitational effect, known as gravitational redshift or blueshift, causes the wavelengths of light emitted by the star to shift towards longer or shorter wavelengths, respectively. The careful measurements of these spectral line shifts can provide insights into various aspects of the black hole, such as its mass, spin, and orbital characteristics. The degree of spectral line shift can be used to estimate the gravitational force exerted by the black hole, which in turn helps determine its mass.

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the transverse Wave which is Answer:2

Answer:

1

Explanation:

amplitude is the maximum distance from the rest of the particles. amplitude is thus measured from the rest position to the peak of a crest or of a trough.

as seen below, graph 1 has an amplitude of 1 while both graph 2 and 3 has an amplitude of 2.

Answer:

B seismic wave

The velocity of the blood is 0.1925 m/s.

When blood flows back and forward, and creates a different frequency on the diagnostic ultrasound echo, the blood flow creates a doppler effect on the device. The formula

f₂ = f₁ × ((v ± vb) ÷ (v ± vb'))

The velocity of the blood is the same but in a different direction.

f₂ = f₁ × ((v ± vb) ÷ (v ± vb'))

2,000,500 = 2,000,000 × ((1,540 + vb) ÷ (1,540 - vb))

2,000,500 ÷ 2,000,000 = ((1,540 + vb) ÷ (1,540 - vb))

1.00025 = ((1,540 + vb) ÷ (1,540 - vb))

1.00025 (1,540 - vb) =  1,540 + vb

1,540.385 - 1.00025vb = 1,540 + vb

1,540.385 - 1,540 = vb + 1.00025vb

0.385 = 2.00025vb

vb = 0.385 ÷ 2.00025

vb = 0.1925 m/s

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By using seatbelts, all passengers and driver may prevent or limit the injuries that could occur from the effects of inertia.

Inertia is a tendency to do nothing or to remain unchanged.

Inertia means an object will continue its current motion until some force causes its speed or direction to change.

While travelling in a vehicle, the inertias experienced by the passengers and drivers are inertia of motion and inertia of rest.

To avoid these, seatbelts are designed.

A seat belt is defined as a vehicle safety device designed to secure the driver or a passenger of a vehicle against the inertias.

Hence,

By using seatbelts, all passengers and driver may prevent or limit the injuries that could occur from the effects of inertia.

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Answer:

Displacement is the change in position of an object. To find displacement, we can subtract the initial position from the final position. In this case, the initial position is 0 m/s, since you start at rest, and the final position is 6.0 m/s south. So, the displacement is 6.0 m/s south.