A gas-filled balloon having a volume of 1.00 L at 1.2 atm and 25°C is allowed to rise to the stratosphere (about 30 km above the surface of Earth), where the temperature and pressure are -23°C and 3.00 10-3 atm, respectively. Calculate the final volume of the balloon.

The total bond energy of the reactants and products must be subtracted to obtain the energy change in the reaction \(2H_2O --- > 2H_2 + O_2\) using the provided bond energy.

Reactants:

2H-O-H (2 molecules) = 2 * (2 * O-H) = 2 * (2 * 463 kJ/mol) = 1852 kJ/mol

Products:

2H-H (2 molecules) = 2 * (2 * H-H) = 2 * (2 * 436 kJ/mol) = 1744 kJ/mol

O=O = 1 * O=O = 1 * 495 kJ/mol = 495 kJ/mol

1852 kJ/mol is the total binding energy of the reactants.

The combined binding energy of the products is 1744 kJ/mol + 495 kJ/mol, which is equal to 2239 kJ/mol.

Energy change (ΔE) = Total bond energy of the products - Total bond energy of the reactants

ΔE = 2239 kJ/mol - 1852 kJ/mol = 387 kJ/mol

So, the answer is E.

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Your question is incomplete, most probably the complete question is:

Calculate the energy change of the following reaction

based on the bond energies given.

2H2O2H2 + O2

H-H: 436kJ/mol

O=0: 495kJ/mol

O-H: 463kJ/mol

Select one:

Cu(s), will spontaneously reduce Fe2+ and Ag+. Thus option A is the answer.

A redox (reduction-oxidation) reaction is a chemical reaction in which one species (the reducing agent) loses electrons, while another species (the oxidizing agent) gains electrons. The reducing agent is said to be reduced, while the oxidizing agent is said to be "oxidized." In this case, copper metal, Cu(s), is the reducing agent, and \(Fe2+\) and \(Ag+\) are the oxidizing agents.

In the redox reaction, copper metal will lose electrons and is oxidized to Cu2+. The Fe2+ and Ag+ ions will gain electrons and be reduced to Fe and Ag, respectively. This process is spontaneous because the final state of the reaction is more stable than the initial state.

The reaction can be written as:

\(Cu(s) + Fe^{2+} -- > Cu^{2+} + Fe(s)\)

\(Cu(s) + Fe^{2+} -- > Cu^{2+} + Fe(s)\)

In summary, copper metal is a stronger reducing agent than Fe2+ and Ag+ ions, which is why the reaction is spontaneous.

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There are approximately 0.38133 moles of nitrogen in the sample of epinephrine. Epinephrine is both a neurotransmitter and a hormone, but it acts mainly as a hormone. Epinephrine, also known as adrenaline, plays an important role in your body's fight-or-flight response. It's also used as a medication to treat many life-threatening conditions

To determine the number of moles of nitrogen in the sample of epinephrine, we need the molar ratio between carbon and nitrogen in the compound. Without this information, we cannot provide a direct answer. The molar ratio can be obtained from the chemical formula of epinephrine (C9H13NO3), which indicates that there is 1 nitrogen atom for every 9 carbon atoms.

Using this information, we can set up a proportion:

(Number of moles of nitrogen) / (Number of moles of carbon) = (Number of nitrogen atoms) / (Number of carbon atoms)

Since we know the number of moles of carbon is 3.432, we can solve for the number of moles of nitrogen:

(Number of moles of nitrogen) / 3.432 = 1/9

Cross-multiplying, we get:

(Number of moles of nitrogen) = (3.432 * 1) / 9

Calculating the result:

(Number of moles of nitrogen) = 0.38133 moles

Therefore, there are approximately 0.38133 moles of nitrogen in the sample of epinephrine.

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As the size of the ring contracts, the carbonyl peak in the ring shifts to higher frequencies. This is due to the decrease in ring size, which increases the ring strain and results in a more polarized carbonyl group.

Hence, the carbonyl bond becomes weaker and more polar, which shifts the peak to higher frequencies. This effect is known as ring strain and is caused by the distortion of the bond angles and bond lengths in the ring.

A carbonyl peak is a strong signal that appears in infrared spectra due to the presence of a carbonyl group in a molecule. The position and shape of the peak are influenced by various factors such as ring size, substitution, and conjugation. In general, the carbonyl peak is a good indicator of the functional group and molecular structure of a compound.

The answer to the given question is that the carbonyl peak in a ring shifts to higher frequencies as the size of the ring contracts.

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The size of a ring can influence the chemical shift and intensity of signals generated from the nucleus located in the ring. This is because the ring size determines the ring current and aromaticity of the molecule in question. The carbonyl peak is a common NMR signal observed in organic molecules.

The carbonyl carbon, C=O, is located next to an electronegative atom (O, N), which draws electron density away from the carbon atom and causes it to appear at a high frequency or up field region in the NMR spectrum. The size of the ring can influence the carbonyl peak in two ways; the first effect is the ring strain effect, which is observed when the ring size is reduced.

The ring strain effect causes an increase in the deshielding effect experienced by the carbonyl carbon, resulting in a chemical shift towards a lower frequency or downfield region in the NMR spectrum. As the ring size reduces, the carbonyl peak moves towards a lower frequency, indicating that the electronegative atoms near the carbonyl group are pulling electrons towards themselves.

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The intermediates in the given three-step mechanism are Cl (g) and CCl3 (g).

In the mechanism, Cl2 (g) is in equilibrium with 2 Cl (g), indicating that Cl (g) is an intermediate formed during the reaction. This means that Cl2 (g) breaks apart into Cl (g) molecules, which then go on to react with other species in subsequent steps.

In the second step, Cl (g) reacts with CHCl3 (g) to form HCl (g) and CCl3 (g). Here, Cl (g) is consumed as it reacts with CHCl3 (g) to produce the products.

In the third step, Cl (g) reacts with CCl3 (g) to form CCl4 (g). This step consumes Cl (g) as it reacts with CCl3 (g) to produce the final product.

Overall, the intermediates in this three-step mechanism are Cl (g) and CCl3 (g). They are formed in intermediate steps of the reaction and are consumed in subsequent steps to yield the final products.

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Answer:

C, Reactants rearrange to form new products

Explanation:

The work done on the car was a negative force, since it was the act of slowing down or removing energy from the car.

When you apply the brakes to slow down, the negative momentum of your speed is lessened. You are therefore accelerating. Therefore, the sign of the acceleration is dependent upon the sign of the velocity change. The car slows down by pushing against the road as the driver depresses the brake pedal, applying forces to both wheels in the reverse direction and bringing the vehicle to a stop. So since work is equal to force multiplied by displacement as the acceleration decreases force becomes negative and hence work done on the car is also negative.

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Answer:

Answer is C.

Explanation:

I hope it's helpful!

Explanation:

mass number....................

Answer:

I think its D

Explanation:

Answer:

D

Explanation:

It's B because homeostasis is the ability to maintain a relatively stable internal state that persists despite changes.

Hope this helps!!! If this is incorrect, I'm so sorry! Have a lovely day.

Rank the crystal lattice structures in order of decreasing efficiency of space in the structure.

1. Simple cubic

2. Body centered cubic

3. Face centered cubic

4. Hexegonal close packed

Explanation:

1) 3,4-dimethyl hex-1,5-diyne

2) 3,3-diethyl pent-4-yn-1-ene

3) 5-(1'-ethyl-2',3'-dimethyl propane) dec-1,3-diyne

Answer:

A link is a fastening unit that attaches two parts of an object together

Different types of links have different characteristics

Answer:

Linking is the process of combining all the component object files. The linker determines where the code will reside in memory and how control will transfer between the components.

Answer:

18.65004 grams H2O

Explanation:

First, we need to write down the balanced chemical equation for the decomposition reaction:

2LiOH -> H2O + Li2O

Since we have grams of LiOH and we need to know the grams of water, we need to convert to moles since we can only compare moles to moles.

The amu of LiOH is 23.947.

The given grams of LiOH is 63.. To convert to moles, we will divide 63 by 23.947..

This gives us 2.6310 moles LiOH..

To convert to moles of H2O (and later grams of H2O), we will use the mole fractions from the balanced equation...

When we look at the balanced equation we can see that 2 moles of LIOH can produce 1 mol of Water, so:

2.6310 moles \(* \frac{1 molH_{2}O}{2 mol LiOH}\) = 1.3155 moles H2O

Now we will convert from moles to grams (we must multiply by the amu)

1.3155 moles H2O = 18.65 grams H2O

According to stoichiometry of the chemical equation of decomposition of lithium hydroxide 23.6 g of water are produced from the decomposition of 63 grams of lithium hydroxide.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.It is useful in balancing chemical equations.

In the given example, as 47.9 g of lithium hydroxide produces 18 g water ,therefore 63 of lithium hydroxide will produce 63×18/47.9=23.6 g of water.

Thus, 23.6 g of water are produced from the decomposition of 63 grams of lithium hydroxide.

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A  volume of a 10.00% (w/v) solution of sugar is needed to provide 2.00 g of sugar of anxiety (low vs. high) and stress (low vs. moderate vs. high) on test.

Everyone experiences anxiety occasionally, but persistent anxiety can reduce your solution of life. Though likely best known for altering behavior, worry can have negative effects on our solution health. niety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are getting ready for a challenging situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have indicated that female students have greater levels of test anxiety than male students.

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Answer:

Compressibility means: being able to basically squish something easier. Like water, water can be reduced in volume or size under pressure When that water expands, it turns into a gas.

Explanation:

Answer:

please use shell notation

Answer:

16.67 grams  of  H₂ is generated from the electrolysis of 150 grams of H₂O

Explanation:

Electrolysis is the decomposition of a chemical element under the effect of an electric current. So, electrolysis of water is the process of decomposing the H₂O molecule into separate oxygen and hydrogen gases due to an electric current passing through the water.

The balanced equation of electrolysis of water is:

2 H₂O → O₂ + 2H₂

Being:

then the molar mass of the compounds that participate in the reaction is:

If the following amounts in moles are reacted by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction):

the amount of mass, by stoichiometry, that reacts and is produced is:

Then you can apply the following rule of three: if by stoichiometry 36 g of H₂O generate 4 g of H₂, 150 g of H₂O how much mass of H₂ will it generate?

\(massofH_{2} =\frac{150 grams of H_{2}O*4 grams ofH_{2} }{36 grams of H_{2}O}\)

mass of H₂= 16.67 grams

16.67 grams  of  H₂ is generated from the electrolysis of 150 grams of H₂O

If 263802 if 263 kJ are produced. Methane was burned in an amount of 3 kJkJ mol. Thus, approximately 5–6 g, or more than 1/4 mole, of methane was burned.

The pace at which mass is lost as a result of fuel combustion is known as the mass-burning rate. The rate of change in temperature from the fuel surface toward the flame can also be used to describe the temperature gradient at the fuel surface.

The product of the density of the unburned gas, the flame speed of the unburned gas, and the surface area of the flame front determines the mass burning rate of the unburned air-fuel-burned gas mixture inside the combustion chamber of an engine.

The product of the density of the unburned gas, the flame speed of the unburned gas, and the surface area of the flame front determines the mass burning rate of the unburned air-fuel-burned gas mixture inside the combustion chamber of an engine.

Combustion of methane, which you have kindly provided

CH4(g)+2O2(g)→CO2(g)+2H2O(g) ;ΔH=−802.3kJmol−1

As written, the enthalpy change is given per mole of reaction. That is, the exact amount of energy produced by burning 1 mol of methane to produce stoichiometric amounts of carbon dioxide and water vapour is 802.3 k J. In order to treat the energy as a product, I may write the reaction in this manner.:

CH4(g)+2O2(g)→CO2(g)+2H2O(g)+802.3 kJ.

o if 263 kJ are generated then

263kJ/ 802.3 kJ * 1⋅mol

methane were combusted. So this is something more than 1/4 a mole of methane combusted, approx. 5-6 g.

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To answer this question we have to usethe ideal gas law:

Where P is the pressure, V is the volume, n is the number of moles, R is the constant of ideal gases (0.082atmL/molK) and T is the temperature (in Kelvin degrees).

The first step is to convert the given mass of N2 to moles using its molecular mass:

And convert the pressure from mmHg to atm (1atm=760mmHg):

Finally, solve the initial equation for T and replace for the given values:

The temperature of the gas is 539.15K.

Convert this temperature to Celsius by substracting 273.15 to the temperature in Kelvins:

The temperature of the gas is 226°C.

0.150 moles of Al are necessary to form 80.2 g of AlBr3 from the reaction: 2 Al(s) + 3 Br2(l) → 2 AlBr3(s).

The molar mass of AlBr3 is 266.69 g/mol. To find the number of moles of AlBr3 that can be formed from 80.2 g, you can divide the given mass by the molar mass of AlBr3.

Then, using the balanced chemical equation, you can determine the number of moles of Al required to form that amount of AlBr3.

The balanced chemical equation is:2 Al(s) + 3 Br2(l) → 2 AlBr3(s)The molar mass of AlBr3 is 266.69 g/mol.Mass of AlBr3 = 80.2 g Number of moles of AlBr3 = Mass of AlBr3/Molar mass of AlBr3                                            = 80.2 g/266.69 g/mol                                            = 0.300 mol AlBr3According to the balanced chemical equation, 2 moles of Al will form 2 moles of AlBr3.

Therefore, the number of moles of Al required to form 0.300 moles of AlBr3 = 0.300 mol AlBr3 × 2 mol Al/2 mol AlBr3                                                                                                                                = 0.150 mol

Hence, 0.150 moles of Al are necessary to form 80.2 g of AlBr3 from the given reaction.

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Answer:

Magnesium sulfide | MgS - PubChem.

The molarity of the RbOH solution is 1.52 M.

Balanced chemical equation for the neutralization reaction between RbOH and HBr is;

RbOH + HBr → RbBr + H₂O

From the balanced equation, we can see that the stoichiometric ratio of RbOH to HBr is 1:1.

We can use the equation for molarity, which is;

Molarity (M) = moles of solute / volume of solution in liters

We can first calculate the moles of HBr that were used in the neutralization reaction;

moles of HBr = Molarity × volume of HBr solution in liters

moles of HBr = 1.385 M × 0.02435 L

moles of HBr = 0.0337 mol

Since the stoichiometric ratio of RbOH to HBr is 1:1, the moles of RbOH in the solution is also 0.0337 mol.

Now, we can calculate the molarity of the RbOH solution using the volume of the RbOH solution;

Molarity of RbOH = moles of RbOH/volume of RbOH solution in liters

Molarity of RbOH = 0.0337 mol / 0.0221 L

Molarity of RbOH = 1.52 M

Therefore, the molarity of the RbOH solution is 1.52 M.

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The term "ionic conductivity" refers to a property that quantifies a substance's propensity for ionic conduction. The movement of ions is known as ionic conduction.

What does study indicate about ion conductivity?

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Answer:

252

Explanation:

10.5 x 24=252

density= mass/volume

rearrange to find mass

mass= density x volume

When testing the unknown solution (D. 31) with ammonium carbonate, the solution will react with the ammonium carbonate to form a white precipitate.

This indicates that the unknown solution contains an alkali or alkaline earth metal, such as sodium, potassium, calcium, strontium, or barium.

To identify the element present in the unknown solution, you can use a flame test or a solution reaction test. For the flame test, a small portion of the unknown solution is placed in a flame and the emitted light will be characteristic of the element present.

For the solution reaction test, a small portion of the unknown solution is mixed with a known solution of an alkali or alkaline earth metal and the reaction is observed. If a precipitate is formed, it indicates that the element present in the unknown solution is the same as the element present in the known solution. By comparing the observations from these tests with the observations in Procedure A. 1 and A. 2, you can identify the element present in the unknown solution.

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