A gallon of iced tea containing 128 fl oz of iced tea contains 3.79 liters of the liquid.
Volume ConversionThe problem here has to do with converting from fl oz to liters.
Recall that:
1 fl oz = 29.6 mL
Thus:
128 fl oz = 29.6 x 128
= 3,788.8 mL
Also recall:
1 mL = 0.001 L
Thus:
3,788.8 L = 3,788.8 x 0.001
= 3.7888 L
In other words, a gallon of iced tea containing 128 fl oz of tea contains 3.79 liters of tea.
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state which separation method you would use to carry out the following separations:
(i) Ethanol from a mixture of ethanol and water
(ii) Red dye from a mixture of red and blue dye
(iii) Calcium carbonate (insoluble in water) from mixture of CaCO3 and water
2. What would charge would you expect a magnesium atom to form?
O 2+
017
2
Answer:
-2
Explanation:
Magnesium usually has a negative charge.
Answer:
+2
Explanation:
Magnesium has the following electron configuration: 1s^2 2s^2 2p^6 3s^2 or [Ne] 3s2.
You can see that Magnesium contains two electrons in its outermost orbit. It loses these 2 electrons during the chemical reaction and transitions to the closest stable noble gas form. It also generates the Mg2+ ion as it loses two electrons. It has an ionic charge of 2+ as a result.
I hope you now fully comprehend why magnesium has a 2+ charge.
ws oxidation number and balancing equation
Oxidation number is a number assigned to an atom in a chemical compound that represents the number of electrons lost or gained by the atom.
What is balancing equation?A balancing equation or balanced is a chemical expression wherein the tally of atoms for each constituent element mirrors harmoniously on either side of the equation. This harmonious alignment extends to both mass and charge, embodying equilibrium throughout.
The art of balancing equations holds great significance as it upholds the revered principles of the conservation of mass and the conservation of charge.
The conservation of mass, a fundamental decree, dictates that the essence of matter remains unaltered, impervious to creation or annihilation in the course of a chemical transformation.
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Complete question:
What is oxidation number and balancing equation?
The elements fluorine (F), chlorine (Cl), and iodine (I) are all part of the same _________on the periodic table.
Explanation:
The elements Fluorine (F),Chlorine (Cl) and Iodine (I) are all part of the same Group ( i.e, Group 17 ) on the periodic table.
Answer:
Group
Explanation:
If a snail crawls 55 inches per day, how many centimeters will he crawl in 23 days?
Group of answer choices
5.0X102 cm
1.06 cm
3.2X103 cm
6.1 cm
2.0X10-3 cm
If a snail crawls 55 inches per day ,the snail will crawl approximately \(3.2 * 10^3 centimeters.\)
To convert inches to centimeters, we need to use the conversion factor: 1 inch = 2.54 centimeters.
First, let's calculate the distance the snail crawls in inches in 23 days. We can multiply the daily distance by the number of days:
Distance in inches = 55 inches/day × 23 days = 1265 inches.
Now, to convert the distance from inches to centimeters, we multiply the distance in inches by the conversion factor:
Distance in centimeters = 1265 inches × 2.54 cm/inch = 3215.1 cm.
Rounding to the appropriate number of significant figures, the snail will crawl approximately 3215 cm or \(3.2 * 10^3 centimeters.\) in 23 days.
Therefore, the answer is Option 3:\(3.2 * 10^3 centimeters.\)
This means that in 23 days, the snail will crawl approximately\(3.2 * 10^3 centimeters.\)
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Transition metals often form ions with a charge of _____-
a) +1
b) -1)
O c) +2
d) -2
e) They can form ions with all of the above charges.
Na + - FeCl, - _NaCl + Fe
NO LINKS!!!!
Answer:
2Na + FeCl2 → 2NaCl + Fe (sodium)
Explanation:
What is the area civilization began?
Answer: Mesopotamia
Civilizations first appeared in Mesopotamia (what is now Iraq) and later in Egypt. Civilizations thrived in the Indus Valley by about 2500 B.C.E., in China by about 1500 B.C.E., and in Central America (what is now Mexico) by about 1200 B.C.E. Civilizations ultimately developed on every continent except Antarctica.
Hope this helps!
What does water vapor do to the density of the air
Answer:
The amount of water vapor in air influence density. Water vapor is relatively light compared to diatomic Oxygen and diatomic Nitrogen - the dominant components in air. When vapor content increases in moist air the amount of Oxygen and Nitrogen are decreased per unit volume and the density of the mix decreases since the mass is decreasing.
Explanation:
Correctly write the chemical formula for as many ions and compounds as you can:
1. Copper (11) ion
2. Bromide ion
3. Magnesium ion
4. Phosphide ion
5. Copper (11) Bromide
6. Sulfur Dichloride
7. Barium Fluoride
8. Magnesium Phosphate
9. Lithium Permanganate
10. Strontium Sulfite
11. Nitrogen Monoxide
12. Diselenium Tetraoxide
13. Aluminum Sulfide
14. Tin (IV) lodide
15. Beryllium Oxide
16. Potassium Hydroxide
The chemical formulas for the ions and compounds you listed:
Copper (II) ion: Cu²⁺
Bromide ion: Br⁻
Magnesium ion: Mg²⁺
Phosphide ion: P³⁻
Copper (I) Bromide: CuBr
Sulfur Dichloride: SCl₂
Barium Fluoride: BaF₂
Magnesium Phosphate: Mg₃(PO₄)₂
Lithium Permanganate: LiMnO₄
Strontium Sulfite: SrSO₃
Nitrogen Monoxide: NO
Diselenium Tetraoxide: Se₂O₄
Aluminum Sulfide: Al₂S₃
Tin (IV) Iodide: SnI₄
Beryllium Oxide: BeO
Potassium Hydroxide: KOH
Copper (II) ion: Cu²⁺
Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.
Bromide ion: Br⁻
The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.
Magnesium ion: Mg²⁺
The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.
Phosphide ion: P³⁻
The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.
Copper (I) Bromide: CuBr
Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.
Sulfur Dichloride: SCl₂
Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.
Barium Fluoride: BaF₂
Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.
Magnesium Phosphate: Mg₃(PO₄)₂
Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.
Lithium Permanganate: LiMnO₄
Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.
Strontium Sulfite: SrSO₃
Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.
Nitrogen Monoxide: NO
Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.
Diselenium Tetraoxide: Se₂O₄
Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.
Aluminum Sulfide: Al₂S₃
Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "
2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.
Tin (IV) Iodide: SnI₄
Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.
Beryllium Oxide: BeO
Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.
Potassium Hydroxide: KOH
Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.
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Balance the following reaction by typing in the correct coefficients in front of each reactant and product.
H3PO4(s) -
-->
H₂(g) +
P(s) +
O₂(g)
1. The number density of conduction electrons in pure silicon at room temperature is about 11016m3. By doping with phosphorous, you desire to increase this number by a factor of 1 million(106). At room temperature, assume that the thermal energy is sufficient that all of the extraelectrons from the P doping enter the conduction band. What fraction of silicon atoms must youreplace with phosphorous atoms
This question is incomplete, the complete question is;
The number density of conduction electrons in pure silicon at room temperature is about 10¹⁶ m⁻³. By doping with phosphorous, you desire to increase this number by a factor of 1 million (10⁶). At room temperature, assume that the thermal energy is sufficient that all of the extra electrons from the P doping enter the conduction band. What fraction of silicon atoms must you replace with phosphorous atoms
Answer:
the fraction of silicon atoms we must replace with phosphorous atoms is 4( 10⁶ - 1 )
Explanation:
Given that;
the number density no = 10¹⁶ m⁻³
Required no = (10¹⁶ × 10⁶) = 10²² m⁻³
Each silicon atom has 4 valence electron,
Hence; Silicon density = 10¹⁶/4
now, if x = No of silicon atoms to be replaced with phosphorous, then;
(10¹⁶/4 - x)4 + 5x = 10²²
10¹⁶ - 4x + 5x = 10²²
10¹⁶ + x = 10²²
x = 10²² - 10¹⁶
Fraction of silicon atoms will be;
⇒ 10²² - 10¹⁶ / 10¹⁶/4
⇒ 4( 10²² - 10¹⁶ / 10¹⁶ )
⇒ 4( 10²²/10¹⁶ - 10¹⁶/10¹⁶ )
⇒ 4( 10⁶ - 1 )
Therefore, the fraction of silicon atoms we must replace with phosphorous atoms is 4( 10⁶ - 1 )
How many chlorine atoms are there in 2 molecules of ICl?
Answer: 38 chlorine atoms are in 3 molecules of HCI
Explanation:
Which group of pair with a group 5 non-metal, such as nitrogen, in a 1:1 ratio based on trends in valence electrons?
A. Group 1A or 1
B. Group 2A or 2
C. Group 3A or 13
D. Group 6A or 16
Based on valence electron trends, the correct answer is C. Group 3A or 13.
Based on trends in valence electrons, the group of pairs with a group 5 non-metal, such as nitrogen (N), in a 1:1 ratio is Group 3A or 13. Group 5 non-metals have 5 valence electrons, and they tend to form compounds by either gaining 3 electrons to achieve a stable octet or by sharing 3 electrons in covalent bonds.
Group 1A or 1 elements, such as hydrogen (H) and lithium (Li), have only 1 valence electron. They would need to gain 4 additional electrons to achieve a stable octet, which is energetically unfavorable.
Group 2A or 2 elements, such as beryllium (Be) and magnesium (Mg), have 2 valence electrons. They would need to gain 3 additional electrons to achieve a stable octet, which is also energetically unfavorable.
Group 6A or 16 elements, such as oxygen (O) and sulfur (S), have 6 valence electrons. They would need to gain only 1 additional electron to achieve a stable octet, making them more likely to form a 2:1 ratio with a group 5 non-metal.
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80 POINTS
Someone pls help me out
2) The heat capacity of aluminum is 219.44 J/mol.°C.
3) a) the experimental ΔHs of ice is -0.154 kJ/mol.
b) too high
How to calculate heat capacity?Calculate the heat released by the aluminum:
q = mcΔT
where q = heat released, m = mass of aluminum, c = specific heat capacity of water and ΔT = change in temperature.
q = (24.7 g) (0.903 J/g°C) (100.0°C - 23.4°C)
q = 18643.26 J
Next, calculate the heat absorbed by the calorimeter:
q = mcΔT
q = (99.5 g + 24.7 g) (15.8 J/°C) (23.4°C - 19.5°C)
q = 4009.92 J
The heat released by the aluminum is equal to the heat absorbed by the calorimeter and water:
18643.26 J = 4009.92 J + q3
where q3 = heat absorbed by the water.
q3 = 14633.34 J
Calculate the molar heat capacity of aluminum:
Cp,m = q3 / (nΔT)
where Cp,m = molar heat capacity, n = number of moles of aluminum, and ΔT = change in temperature.
n = m / M
where m = mass of aluminum and M = molar mass of aluminum (26.98 g/mol).
n = 24.7 g / 26.98 g/mol
n = 0.916 mol
Cp,m = 14633.34 J / (0.916 mol * 76.6°C)
Cp,m = 219.44 J/mol.°C
Therefore, the heat capacity of aluminum is 219.44 J/mol.°C.
3) (a) To calculate the experimental ΔHs of ice, we first need to calculate the heat gained by the water and the heat lost by the ice during the process.
Heat gained by water = mass of water × specific heat capacity of water × change in temperature
= 100.0 g × 4.184 J/g·°C × (-20.1°C)
= -8,423.84 J
Heat lost by ice = mass of ice × heat of fusion of ice
= 25.6 g × 6.01 kJ/mol
= 154.496 J
Since the process is assumed to be adiabatic (no heat exchange with the surroundings), the heat gained by the water must be equal to the heat lost by the ice.
Thus, -8,423.84 J = 154.496 J = -8,269.344 J
The negative sign indicates that the process is exothermic. Therefore, the experimental ΔHs of ice is:
ΔHs = -154.496 J/mol = -0.154 kJ/mol
(b) If the student forgets to include the calorimeter term in the calculation, the calculated ΔHs of ice will be too high. This is because the heat absorbed by the calorimeter during the process is not accounted for, leading to an overestimation of the heat gained by the water and underestimation of the heat lost by the ice.
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HELP PLEASEUse the molar volume of a gas at SATP to determine the
following values at SATP:
(a) the amount of nitrogen in 44.8 L of pure gas
(b) the volume (in litres) of 4.8 mol of propane gas, C3H,(g)
(c) the mass of carbon dioxide in 34.6 L of carbon dioxide
gas, CO₂(g)
(d) the volume (in mL) of 1250 g of methane, CH₂(g)
(e) the amount of oxygen in 36.5 L of 02 gas
The most common example is the molar volume of a gas at standard temperature and pressure (STP), which is equal to 22.4 L for 1 mole of any ideal gas at 273.15 K and 1 atm of pressure.
What are the applications of the Ideal Gas Law- Molar Volume?Stoichiometry refers to the quantitative relationship between reactants and products. Calculating the quantities of reactants needed to make a given quantity of products, or the quantities of products resulting from a given quantity of reactants, is required in stoichiometric problems. Gas laws must be taken into account for the calculation if one or more reactants or products in a chemical reaction are gases. The findings of ideal gas law applications are often accurate to within 5%. We go over a few key ideas that are crucial for solving Stoichiometry Problems involving Gases in the sections below.
Stoichiometry and gas laws both rely on the mole notion as their foundation. A mole is an exact measurement of a substance. Based on the quantity of identities, a mole is a unit (i.e. atoms, molecules, ions, or particles). The number of identities in a mole of anything is equal to the number of atoms in exactly 12 grams of carbon-12, the most common isotope of carbon.
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A researcher studying the nutritional value of a new candy places a 6.00 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.42 ∘C. If the heat capacity of the calorimeter is 30.70 kJ⋅K−1, how many nutritional Calories are there per gram of the candy?
We obtain the nutritional calories as 2967 cal/g.
What is the nutritional Calories are there per gram of the candy?Now we know that heat is evolved when we combust a compound or a substance inside the bomb calorimeter. Given that we have the following information about the system;
Temperature rise = 2.42 ∘C
Heat capacity = 30.70 kJ⋅K−1
The we have the energy as obtained from;
H = 30.70 kJ⋅K−1 * 2.42 ∘C = 74.29 kJ or 17.8 * 10^3 cal
Now we are required in this question as we have it to obtain the heat capacity per gram as; 17.8 * 10^3 cal/6g = 2967 cal/g
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According to the ideal gas law, what
will be the volume of 0.25 mol of
nitrogen at 0.82 atm pressure and
57°C temperature?
Explanation:
Ideal Gas Law
PV = n R T
V = n R T / P n = moles R = gas constant = .082057 L atm / ( K mol)
T is in Kelvin
V = .25 moles * .082057 * (273.15 + 57) K / .82 atm = 8.3 moles
( two Sig Dig)
10. What is the molality of a solution
containing 288 g of calcium chloride
dissolved in 2.04 kg of water?
The choice of solution has a concentration of 1.144 mol/kg molality.
What exactly are molality and molarity?Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.
Is one molarity the same as one molality?Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.
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Scientific method practice hypothesis construction & experimental design
Is it true or false that the Temperature is a direct measurement of the energy stored in a substance?
c) Discuss precision and Accuracy as they relate to types of errors.
what is the answer
Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.
Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.
Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.
Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.
Errors in measurements can be classified into two types: random errors and systematic errors.
Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.
Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.
In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.
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What is an extensive property that can be calculated?
Answer: The property which depends on the quantity of the substance is called an extensive property. The free energy change for a reaction (Δ G) depends on the quantity of the substance and is therefore an extensive property. It shows the additive nature. The extensive property Δ G is easily calculated from the formula, ΔG = -nFE cell.
Explanation:
What kind of change forms a new substance?
A physical change
Answer:
Chemical change
Explanation: Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
Hello How do you do?
What is logic bomb and time bomb?
Answer:
A logic bomb and a time bomb are both types of malicious software or code that are designed to cause harm to a computer system or network. Here's a brief explanation of each:
Logic Bomb:
A logic bomb is a piece of code or software that is intentionally inserted into a system to execute a malicious action when specific conditions are met. It remains dormant until triggered by a predefined event or circumstance, such as a specific date, time, or user action. Once triggered, the logic bomb may perform various harmful actions, such as deleting files, corrupting data, or disrupting system functionality. The purpose of a logic bomb is often to cause damage or to gain unauthorized access to a system.
Time Bomb:
A time bomb is similar to a logic bomb, but it is specifically designed to activate or execute its malicious payload at a certain date or time. It is usually programmed to remain undetected until the predetermined time arrives. The time bomb can be set to trigger after a specific time period or on a particular date, at which point it may carry out destructive actions. Time bombs can be used by attackers to target specific events or to coordinate an attack to occur simultaneously across multiple systems.
Both logic bombs and time bombs are considered forms of malicious code or malware and are used with malicious intent to disrupt, damage, or compromise computer systems or networks. They can be extremely harmful, and it is important to have strong security measures, such as antivirus software and regular system updates, to protect against such threats.
Explanation:
PLEASE ANSWER QUICKLY!!!!
2KI (aq) + Cl₂(g) → 2KCl(aq) + 1₂(g)
What volume of 12 gas forms when
21 L Cl2 react at STP?
[?] L 12
The volume of 12 gas forms when 21 L Cl2 react at STP is 21 L.
To determine the volume of 12 gas (I assume you mean I2 gas) formed when 21 L of Cl2 reacts at STP (standard temperature and pressure), we need to use the ideal gas law equation.
The ideal gas law equation is given by:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
At STP, the pressure is 1 atm, and the temperature is 273.15 K.
From the balanced equation, we can see that the molar ratio between Cl2 and I2 is 1:1. So, if 21 L of Cl2 reacts, it will produce an equal volume of I2 gas.
Given that the volume of Cl2 is 21 L, we can assume the volume of I2 gas formed will also be 21 L.
Therefore, the volume of I2 gas formed is 21 L.
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How many grams of Aluminum Sulfate do you have if you have 2.837x10^26 atoms of Sulfur?
Apparently, the right answer is 5.373x10^4, but I do not know how to get there, please help.
The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .
The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:
Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol
(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol
Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S
Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)
Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)
Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.
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ACHIEVE (Sapling) CHEMISTRY ASSESSMENT:
Question(please help):
Convert 5.90km/s to units of meters per hour. Show the unit analysis by dragging conversion factors into the uni-factor slots.
Based on the electron configuration of the two
atoms, predict the ratio of metal cationic (+) atom
to nonmetal anionic (-) atom in the compound.
Hydrogen 1s
Fluorine 1s22s22p5
A. 2:3
B. 1:2
C. 1:1
D. 3:2
Answer:
1 per 2 berarti a.2:3 berarti bagi bagi 1 22. 22 sama dengan 5
for each 20 grams of glucose made by the plant, calculate the mass of water used
Answer: 6
Explanation:
You would need 6