Answer:
A south and north pole (negative and positive pole)
Explanation:
Because opposites attract
The following arbitrary measurements are made and the errors sited are the aximum errors A = 15.21 +0.01, B = 10.82 +0.05, C = 11.00+ 0.03. If D= A + B + C; (a) Calculate the maximum error in D. (b) if the errors sited are standard errors, calculate the standard error in D.
Maximum error in the result of the sum of measurement is equal to the sum absolute error of the individual observed measurements
(a) The maximum error in D is 0.09
(b) The standard error in D is approximately 0.034
The procedure for arriving at the above values is as follows;
The given measurements and the sited errors are;
A = 15.21 + 0.01
B = 10.82 + 0.05
C = 11.00 + 0.03
D = A + B + C
(a) Required parameter;
To calculate the maximum error in D
The equation for the propagation of error in addition is presented as follows;
Given that we have;
x = a + b
Therefore;
x + ±Δx = (a ± Δa) + (b ± Δb) = a + b ± (Δa + Δb)
∴ Δx = Δa + Δb
From the above formula, we have;
Where;
D = A + B + C
The maximum error in D = The sum of the maximum error in A, B, C
∴ The maximum error in D = 0.01 + 0.05 + 0.03 = 0.09
(b) Required parameter:
To find the standard error in D
The standard error is the sampling distribution's standard deviation, SD
Variance = SD²
The combined variance, SD² = The sum of the squares of individual standard deviations
Given that the standard errors represents the standard deviation, we get;
The combined variance, SD² = 0.01² + 0.05² + 0.03²
The combined variance, SD = √(0.01² + 0.05² + 0.03²) = 0.059
\(Standard \ error = \dfrac{SD}{\sqrt{n} }\)
Where n = 3, for the three measurement, we get;
\(Standard \ error = \dfrac{\sqrt{0.01^2 + 0.05^2 + 0.03^2} }{\sqrt{3} } \approx 0.034\)
The standard error in D is approximately 0.034
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As the temperature of an air mass increases, its volume also increases and its density ______.
Answer:
Explanation:
density = mass/volume
So if mass and volume increase, density also increases
Physics. 40 points.
Help please :) (View attached image)
Answer:
1) 10 m/s 2) 14.1 m/s 3) 6.7 m 4) 11.25 m 5) 4.5 m/s 6) 12 joules
Explanation:
A block of wood weighing 30N and of specific gravity 0.75 is ties by a string to the bottom of a tank of water in order to have the block totally immersed.What is the tension of the string?
What is the momentum of an 8-kg bowling ball rolling at 2 m/s? Make sure to
include units.
Plz help ASAP
Answer:
The answer is 16 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 8 × 2
We have the final answer as
16 kg.m/sHope this helps you
test your hypothesis: how will you use the computer model to test your hypothesis? what steps will you follow? what data will you record? conduct your experiment and record your results.
Answer:
what is a or b because in the question it dosent give me the answer choses that i need
A bus negotiates a curve of radius 487 m. What force will be exerted on an 80 kg passenger by the outside wall of the bus when it is traveling at 60 km/h?
Answer:
Centrifugal Force = 45.65N
Explanation:
Given the following data;
Mass, m = 80kg
Radius = 487m
Velocity = 60km/h to m/s = 60*1000/3600 = 16.67m/s
To find the centrifugal force;
Centrifugal Force = mv²/r
Substituting into the equation, we have;
Centrifugal Force = 80*16.67²/487
Centrifugal Force = 80*277.89/487
Centrifugal Force = 2223.12/487
Centrifugal Force = 45.65N
Calculate the solubility (in g/L) of silver carbonate in water at 25°C if the k sp for Ag 2CO3 is 8.4 x 10-12 A.8.0 x 10-4 g/L B.5.6 x 10-2 g/L C.4.4x 10-2 g/L D.3.5 * 10-2
The solubility of silver carbonate in water at 25°C is approximately
1.28 x 10⁻⁴ g/L
How to find the solubilityTo calculate the solubility of silver carbonate (in water at 25°C, we need to use the solubility product constant (Ksp) and the balanced chemical equation for the dissociation of silver carbonate.
The balanced chemical equation for the dissociation of Ag2CO3 is
Ag₂CO₃(s) ⇌ 2Ag+(aq) + CO₃²-(aq)
Using the Ksp expression for Ag₂CO₃
Ksp = [Ag+]² [CO3²-]
substituting the equilibrium concentrations:
8.4 x 10⁻¹² = (2x)² * x
Simplifying the equation
8.4 x 10⁻¹² = 4x³
2.1 x 10⁻¹² = x³
taking the cube root of both sides
x ≈ 1.28 x 10⁻⁴ g/L
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Ben worked 3 hours at x dollars per hour. Julie worked 7 hours and earned twice as much as Ben per hour. Phil worked 12 hours and earned 5 dollars an hour less than Julie. Choose the expression that is correctly simplified and best represents their total wages.
29x – 5
29x – 60
22x – 5
41x – 60
Answer:
D) 41x - 60
Explanation:
You need to find the total wages of each person and add them together.
- Ben worked 3 hours at x dollars per hour so his total is: 3x
- Julie worked 7 hours but got 2x per hour so her total is: 7(2x) = 14x.
- Phil worked 12 hours and earned 2x-5 per hour. The 2x is how much Julie earned and Phil gets 5 dollars less than that, his total is: 12(2x - 5) = 24x - 60.
Now we add them all together: 3x + 14x + 24x - 60 = 41x - 60
A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?A.2.5 newtons in the downward directionB.2.5 newtons in the upward directionC.25 newtons in the upward directionD.25 newtons in the downward directionE.25 newtons perpendicular to the gravitational force
The normal force has a 25 N force magnitude and an upward force direction.
The force the book exerts on the table is downward-directed and equal to its weight, which is 25 N.
According to Newton's third law, every force an object A applies to an object B is balanced out by an equally strong force applied in the opposite direction to object A.
The book is object A in this instance, while the table is object B. According to Newton's third law, the table pulls on the book with a force that is both equal to and opposite to that of the force exerted by the table. As a result, the normal force's magnitude is the same as the weight of the book (25 N), while its direction is opposite.
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A racehorse gallops at a speed of 65 km / h. how long will it take to reach the finish line in a 1,500 m race?
It will take the racehorse approximately 83 seconds (or 1 minute and 23 seconds) to reach the finish line in a 1,500 m race at a speed of 65 km/h.
To find out how long it will take the racehorse to reach the finish line, we need to use the formula:
time = distance ÷ speed
where:
distance = 1,500 m
speed = 65 km/h = (65 × 1,000) m/h = 65,000 m/h
Now, we need to convert the speed from meters per hour to meters per second, since the distance is given in meters. We can do this by dividing the speed by 3,600 (the number of seconds in an hour):
speed = 65,000 m/h ÷ 3,600 s/h = 18.06 m/s (rounded to two decimal places)
Substituting the values into the formula, we get:
time = 1,500 m ÷ 18.06 m/s = 83.03 seconds (rounded to two decimal places)
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if the cord is subjected to a constant force of and the 15-kg smooth collar starts from rest at a, determine the velocity of the collar when it reaches point b. neglect the size of the pulley.
If the cord is subjected to a constant force and the 15-kg smooth collar starts from rest at A, determine the velocity of the collar when it reaches point B.
Neglect the size of the pulley. The acceleration of the 15-kg collar can be found as follows: F = ma => a = F/m ... (1)where F is the constant force applied and m is the mass of the collar.
Let v be the velocity of the collar when it reaches point B. Using the formula for the velocity-time relationship, we have v = u + at ... (2)where u is the initial velocity of the collar at A which is zero. Substituting (1) into (2), we have v = at ... (3)Substituting the value of a from (1) into (3), we get v = F/m t ... (4)where t is the time taken for the collar to travel from A to B and is given by:t = s/v ... (5)where s is the distance between A and B.
Since the cord is assumed to be inextensible, s is equal to twice the distance AB (AB = BC). Let us now compute the tension in the cord at point A. The tension in the cord is equal to the force F as shown in the figure below: Therefore, we have T = F = 35 N ... (6)Since the pulley is smooth, the tension in the cord is the same throughout its length. Thus, we have T = T' ... (7)where T' is the tension in the cord at point B.
Substituting (6) and (7) into the force equation for the collar gives us: T - mg = ma => T' - mg = ma ... (8)where g is the acceleration due to gravity. Substituting the value of a from (1) into (8), we get:T' - mg = F/m => T' = mg + F/m ... (9)Substituting (9) into (7), we get:mg + F/m = T = 35 N => mg = 35 - F/m ... (10)Substituting the values of m and F into (10), we get:mg = 35 - (5 kg)(7 m/s²)/(15 kg) = 28 - 2/3 N ... (11)Substituting the value of g from (11) into (9), we get:T' = 15(28 - 2/3) + 7 = 425 - 2/3 N ...
(12)Substituting (11) and (12) into (4), we get:v = (425 - 2/3)/(15) t ...
(13)Substituting the value of s from the figure above, we get:s = 2(0.8 m) = 1.6 m ... (14)Substituting (13) and (14) into (5), we get:t = s/v = (1.6 m)/(425 - 2/3)(15) = 0.025 s (approx)Substituting (13) and (15) into (4), we get:v = (425 - 2/3)/(15) (0.025) = 0.567 m/s (approx)Therefore, the velocity of the collar when it reaches point B is approximately 0.567 m/s.
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Before Freddy lands on the skateboard it has a certain momentum. After landing, the skateboards momentum
Answer:
remains the same
Explanation:
Momentum refers to the quantity of motion of a body. When any body of mass moves, it possess momentum. Numerically,
Momentum = mass x velocity
i.e. momentum is the product of the mass x velocity
Momentum of a body is always conserved.
In the context, the skateboard has certain momentum before Freddy lands on it. After Freddy lands, the momentum of skateboard remains the same, there is no change in the momentum.
This is because, here the momentum is conserved. After Freddy lands on the skateboard, the total mass on the skateboard increases and so the velocity decreases making the momentum same before the landing.
What is the function of the organelle depicted in the photo?
Answer:
It's a golgi body
Explanation:
It controls the transport system of the cell
What goes in and out the cel
1. A 500.0 g metal block absorbs 5.875 × 103 J of heat to raise its temperature by 50.0 K. What is the substance? Show your work.
Specific Heats of Selected Substances
Substance
C [J/(kg·K)]
Water (ice)
2,060
Iron
450
Aluminum
897
Gold
130
Copper
385
Silver
235
Ammonia (liquid)
4,700
Water (liquid)
4,180
Water (steam)
2,020
Lead
128
The name of the substance is silver based on the specific heat capacity value.
What is the specific heat capacity of the substance?The specific heat capacity of the substance is calculated by applying the following formula for heat capacity.
Q = mcΔθ
where;
m is the mass of the substancec is the specific heat capacity of the substanceΔθ is the change in temperaturec = Q / mΔθ
The specific heat capacity of the substance is calculated as;
c = (5875 J ) / ( 500 g x 50 )
c = 0.235 J/kgK
The substance that has the same specific heat capacity calculated above is silver.
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How do you write a Synthesis Essay? Like format based?
Answer:
HOW TO WRITE SYNTHESIS ESSAYS
Consider your purpose in writing.
Select and carefully read your sources, according to your purpose.
Formulate a thesis.
Decide how you will use your source material and take notes.
Develop and organizational plan, according to your thesis.
Explanation:
In which of these can plasma be
found?
lightning
neon signs
microwave ovens
all of these
Answer:
The sun and other stars consist of plasma. Plasma is also found naturally in lightning and the northern and southern lights. Human-made plasma is found in fluorescent lights, plasma TV screens, and plasma spheres
Explanation:
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If Earth's mass doubled, your weight would..
a. increase
b. decrease
c. stay the same
Answer:
a. increase
Explanation:
Doubling the mass of the Earth would double your weight, since gravitational force is directly proportional to mass, but doubling the radius (which doubles if the diameter doubles) would decrease your weight by a factor of 1/4, since gravitational force is inversely proportional to the square of the radius.
if 1cm^2 of cardboard costs 0.01¢ and i needed 10.16cm of cardboard how much would the total be
Write the following numbers in proper scientific notation. 3,120
What is the mass of a person that weighs 500 N on earth?
Answer:
M=51kg
Explanation:
Weight= Mass x Gravitational Acceleration
500N= M x 9.8 m/s^2
M= 51 kg
The distance time graph of a body is a straight line parallel to the time axis. What
information does the graph convey regarding the motion of the object?
Explanation:
The object is not moving, because the distance is a constant value regardless of the time value.
how long would it take a radio wave whose frequency is 7.25 × 105 hz to travel from mars to earth if the distance between the two planets is approximately 8.00 × 107 km? 1
It would take a radio wave whose frequency is 7.25 × 10⁵ Hz to travel from Mars to Earth approximately 266.67 seconds or 4.44 minutes.
The speed of light is 3 × 10⁸ m/s. You can use this information to calculate the time it would take a radio wave to travel from Mars to Earth if the distance between the two planets is approximately 8.00 × 10⁷ km. Given that the frequency of the radio wave is 7.25 × 10⁵ Hz, we can find its wavelength by using the formula:
c = λfwhere λ is the wavelength, c is the speed of light, and f is the frequency.
Substituting the given values: c = 3 × 10⁸ m/sf = 7.25 × 10⁵ Hz, we can find the wavelength:λ = c / f = 3 × 10⁸ / 7.25 × 10⁵ = 413.79 m
So the wavelength of the radio wave is 413.79 m. Now, we can use the formula for the speed of light to calculate the time it would take the radio wave to travel from Mars to Earth: d = vt where d is the distance, v is the speed, and t is the time.
Substituting the given values: d = 8.00 × 10⁷ km = 8.00 × 10¹⁰ m (converting km to m)v = c = 3 × 10⁸ m/st = d / v = (8.00 × 10¹⁰) / (3 × 10⁸) = 266.67 s
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What part of the Milky Way allows for determination of its rotational direction? A. Celestial body B. Galactic body C. Galactic disk D. Two long tails
Answer: C. Galactic disk
Explanation:
The part of the Milky Way which allows the determination of it rotational direction is known as the Galactic disk. This disc are shaped because they contain gases which are rich and dynamically young. It is also a part of a group of a galaxies disc is a component of disc galaxies, known as spiral galaxies and lenticular galaxies.
Answer:
Galactic disk
Explanation:
Galactic disc's are composed mostly of the galaxy's stars and a gaseous component mostly composed of cool gas and dust. The stellar population of galactic discs tend to exhibit very little random motion with most of its stars undergoing nearly circular orbits about the galactic center. This circular orbit maintains the galaxy's rotation momentum.
a gust of wind creates ripples on the ocean that have a wavelength of 4.7\;\mathrm{cm}4.7cm and propagate at a speed of 6.5\;\mathrm{cm/s}6.5cm/s. what is the frequency of these ocean waves?
A gust of wind creates ripples in the ocean, then the frequency of these ocean waves will be 1.4 Hz.
What is Frequency?The percentage of waves that transfer a fixed point in a unit of time is known as the frequency in physics. It is the frequency or vibrations that a body in periodic motion perceptions in a unit of time. When a body in periodic motion moves through a sequence of incidents or positions before returning to its initial state, it is believed to have experienced one cycle or one vibration.
As per the given data mentioned in the question,
Frequency = speed/wavelength
Speed = 6.65 cm/s
Wavelength = 4.7 cm
F = (6.5 × 10⁻²)/(4.7 × 10⁻²)
F = 1.4 Hz
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Calculate how many minutes it takes sunlight reach us from the sun. Light travels at 3 x 10^8
m/s and the sun is about 144 million km away
Sunlight will take 8 minutes to reach the Earth.
Sunlight is part of the electromagnetic radiation emitted by the Sun, especially infrared, visible and ultraviolet light.
Light is travelling with the speed of \(3 * 10^{8}\) m/s
Distance between Sun and Earth is 144 million km
1 km = 1000 m
1 million km = \(10^{6}\) km
\(10^{6}\) km = \(10^{9}\) m
144 million km = 144 * \(10^{9}\) m
According to the speed, distance and time relationship, speed is directly proportional to the ration of distance and time.
Mathematically \(Speed = \frac{Distance}{Time}\)\(3 * 10^{8} = \frac{144 * 10^{9} }{Time}\)
Time = \(\frac{144 * 10^{9} }{3* 10^{8} }\)
Time = 480 sec
Time = 8 minutes
Time taken by the sunlight to reach the Earth's surface is 8 minutes.
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What is it called when an unwanted material that contains radioactive atoms is present on another material?
Answer:
Radioactive contamination
Explanation:
radioactive contamination is when radioactive atoms are present on somethingWhen an unwanted material that contains radioactive atoms is present in another material is known as Radioactive contamination.
What are radioactive atoms?The process of radioactive decay is how an unstable atomic nucleus loses energy through radiation. A substance that has unstable nuclei is regarded as radioactive. Alpha, beta, and gamma decay are three of the most prevalent forms of decay, and they all entail the emission of one or more particles.
According to the statement, "For a given time, the number of nuclei of the elements existing at that moment is exactly proportional to the rate of radioactive decay of an atom." This may be expressed as, where N is the total number of nuclei, d N d t N.
When radioactive particles are deposited on, inside of, or around an individual or a business, nuclear radiation results. When radioactive materials are discharged into the environment, they have the potential to contaminate the air, water, surfaces, soil, plants, buildings, people, and animals.
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If the driver slammed on the brakes, what could happen to the crate?
why can we use the ages, determined for the lunar surface to determine the ages for the martian surface?
We cannot immediately apply the ages established for the lunar surface to the ages determined for the Martian surface since the ages of planetary surfaces rely on a range of elements.
Such as each planet's geological history, surface processes, and impact history. Some methodologies, however, can be used to calculate the relative ages of various planetary surfaces based on their crater density. This approach works on the premise that older surfaces have had more time to acquire impact craters than younger surfaces. The lunar surface has been thoroughly investigated, and the history of its cratering is well understood. We may determine relative age by comparing crater density on the lunar surface to those on other planetary surfaces, such as Mars.
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What is the electric field 6.44 m from the centre of the terminal of a Van de Graaff with a 9.82 m charge, noting that the field is equivalent to that of a 3.811C charge at the centre of the terminal?
The electric field at 6.44 m from the center of the terminal of a Van de Graaff generator with a 9.82 mC charge is 1530 N/C.
Electric field is a measure of the force that an electric charge experiences when it is placed in an electric field. The electric field at a point in space is proportional to the charge at that point and inversely proportional to the square of the distance from the point to the source of the field.
In this case, the electric field at 6.44 m from the center of the terminal of the Van de Graaff generator is equivalent to the field produced by a 3.811 C charge at the center of the terminal.
Using the formula for electric field, E = kQ / r^2, where E is electric field, k is Coulomb's constant (8.99 x 10^9 N m^2/C^2), Q is the source charge (3.811 C), and r is the distance from the source (6.44 m), we can calculate the electric field to be 1530 N/C.
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