A factory worker pushes a 30.0 kg crate a distance of 3.7 m along a level floor at constant velocity by pushing downward at an angle of 30∘ below the horizontal. The coefficient of kinetic friction between the crate and floor is 0.25.
Required:
a. What magnitude of force must the worker apply?
b. How much work is done on the crate by this force?
c. How much work is done on the crate by friction?
d. How much work is done on the crate by the normal force? By gravity?
e. What is the total work done on the crate?
Answers
Answer:
a) \(F = 210.803\,N\), b) \(W_{F} = 779.971\,J\), c) \(W_{f} = 235.683\,J\), d) \(W_{N} = 0\,J\); \(W_{g} = 544.289\,J\), e) \(W_{net} = 0\,J\)
Explanation:
a) The net force exerted on the crate is:
\(\Sigma F = F - m\cdot g \cdot \sin \theta - \mu_{k}\cdot m\cdot g \cdot \cos \theta = 0\)
The magnitud of the force that the work must apply to the crate is:
\(F = m\cdot g \cdot \sin \theta + \mu_{k}\cdot m\cdot g \cdot \cos \theta\)
\(F = (30\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \sin 30^{\circ} + 0.25 \cdot (30\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \cos 30^{\circ}\)
\(F = 210.803\,N\)
b) The work done on the crate due to the external force is:
\(W_{F} = (210.803\,N)\cdot (3.7\,m)\)
\(W_{F} = 779.971\,J\)
c) The work done on the crate due to the external force is:
\(W_{f} = (63.698\,N)\cdot (3.7\,m)\)
\(W_{f} = 235.683\,J\)
d) The work done on the crate due the normal force is zero, since such force is perpendicular to the motion direction.
\(W_{N} = 0\,J\)
And, the work done by gravity is:
\(W_{g} = (147.105\,N)\cdot (3.7\,m)\)
\(W_{g} = 544.289\,J\)
e) Lastly, the total work done is:
\(W_{net} = W_{F} - W_{f} - W_{g} - W_{N}\)
\(W_{net} = 779.971\,J - 235.683\,J - 0\,N - 544.289\,J\)
\(W_{net} = 0\,J\)
Related Questions
CONSISTENCY AND CONVERSION F1A 1) Starting with the definition 1 inch = 2.54cm, find the Mur OF (W) Kilometers in 1.00 mile and (b)feet in 1. 00 km [Hint: 1km: 0.621 mile and Im = 3·281 ft)
Answers
A conversion factor is a ratio that can be used to convert a quantity expressed in one unit of measurement to another unit of measurement.
What is conversion factor?
For example, the conversion factor between meters and feet is given by:
1 meter = 3.281 feet
This means that to convert a quantity expressed in meters to feet, multiply by 3.281. To convert a quantity expressed in feet to meters divide by 3.281.
To convert 1.00 mile to kilometres, the conversion factor is used 1 km = 0.621 miles.
To convert 1.00 km to feet, the conversion factor of 1 km = 3.281 ft
Calculation of the above statement:
This question asks to use the given definition (1 inch = 2.54 cm) to convert the units of measurement of miles and feet to kilometers.
(a) To convert 1.00 mile to kilometres, the conversion factor is used 1 km = 0.621 miles. So, to convert 1.00 mile to kilometers, multiply 1.00 by 0.621:
So, 1.00 mile is equivalent to 0.621 kilometers.
(b) To convert 1.00 km to feet, use the conversion factor of 1 km = 3.281 ft. So, to convert 1.00 km to feet, multiply 1.00 by 3.281:
So, 1.00 km is equivalent to 3.281 feet.
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Jenny's book has an area of 200 cm².
It exerts a pressure of 0.05 N/cm² on the desk.
What is the weight of the book?
Show your working out.
Answers
Weight of jenny's book will be 10N.
What is weight?The force exerted on an object by gravity is known as its weight. Weight is the result of multiplying the mass by the acceleration that is acting on it. The pound (lb), which is the most often used unit of weight, is equivalent to 1 kilogram meter per second squared (N), the SI unit of weight. The impact of gravity (or another acceleration) on an object is quantified by its weight. At various points on the Earth, two causes alter weight. Weight reduces as altitude rises. Latitude also affects weight.
Area=200cm²
p=0.05N/cm²
weight=thrust=Force
p=F/A
0.05×200=F
F=10N
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A submarine sends out a sonar signal (sound waves) in a direction directly downward it take 2.3 s for the sound waves to travel from the submarine to the ocean bottom and back to the submarine how high (approx) up from the ocean floor is the submarine?speed of sound in water is 1490 m/s
Answers
Explanation:
Using the formula;
2x = vt
x is the distance up from the ocean floor the submarine is
v is the speed of sound in water
t is the time
Given
t = 2.3s
v = 1490m/s
Required
how high (approx) up from the ocean floor is the submarine x
From the formula;
x = vt/2
x = 1490(2.3)/2
x = 745(2.3)
x = 1,713.5m
Hence the submarine is 1713.5m high up from the ocean floor
Can someone help me with this question
Answers
Answer:
hypothesis , hope it helps
Explanation:
Answer:
Inference
Explanation:
Inference is something you predict after testing that's a result after an hypothesis has been made. Hypothesis is an intelligent guess based on some observed phenomena which can be subjected to further testing.
A person standing on the roof of a building drops a 0.125 Kg ball on the ground. A
child on eight floor saw the ball passing with a speed of 33.1 m/s. The first floor of the building
is 12.0 m high and each successive floor is 8.00 m high. Determine the total numbers of floors
in the building. How fast was the ball falling just before it hit the ground? What was its kinetic
energy just before it hit the ground?
Answers
Answer:
V = a t velocity after time t
t = 33.1 / 9.80 = 3.38 sec (time ball had been falling)
S = 1/2 a t^2 = 55.9 m
So the ball had been falling for 7 * 8 = 56 m
The child was 7 floors from the top
Since he was on the eight floor the floors below him were
7 * 8 + 12 = 68 m total floors below child
68 + 56 = 124 m total height of building
Total floors in building = 7 + 7 + 1 = 15 floors
PE at top = KE at bottom
KE = m g h = .125 * 9.80 * 124 = 152 Joules
Lesson 1, What is Physical Science.
Write an expository essay explain the difference between scientific knowledge and other kinds of science, include ideas regarding:
1) the scientific method.
2) true science versus false science.
3) examples of what scientists study and do not study.
4) what is required for a scientist to consider an idea to be true.
Answers
Physical science explains the physical world and not supernatural events and an idea is considered true by science if it can be observed, explained and reproduced by others.
What is physical science?
Physical science is a systematic study of the of the physical world and phenomena based on observation and experiments.
The scientific method involves:
observation and questionshypothesisexperimentsresults and further experimentstheories and lawsScience explains the physical world and not supernatural events.
Science studies physical phenomena such as the stars, the planets, living things, etc.
Science do not study about angels or demons or supernatural events.
An idea is considered true by science if it can be observed, explained and reproduced by others.
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ALOT OF POINTS What is the best description of the acceleration of an object?
A: A runner travels 100 m in one minute.
B: A cars velocity changes from 25 m/s to 20 m/s in 5 seconds.
C: An airplane changes elevation from 10,000 ft to 5,000 ft.
D: A remote-controlled car speeds up from 0 m/s to 15 m/s.
Answers
Answer:
A car's velocity changes from 25 m/s to 20 m/s in 5 seconds.
Explanination
Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
Answers
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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Electric Field Direction only OO Voltage Values Grid 00V a +1 nc -1 nc Sensors Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is. greatest to the right of the charge. greatest below the charge. greatest above the charge. greatest to the left of the charge. O O O the same. Submit Request Answer
Answers
Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.
The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.
Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.
The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.
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The correct question is:
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.
Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.
2. 0,25 moles of sodium chloride is dissolved in water to form 100 cm solution. Calculate the concentration of the solution. 3. 20 g of sodium hydroxide is dissolved in 200 cm³ of water. Calculate the concentration of the solution. 4 Calculate the mass of magnesium chloride needed to prepare 100 ml of a standard solution of
Answers
The concentration of the solution will be 0.25M and the concentration of the
sodium Hydroxide is 2.5 M .
What is Stoichiometry ?
A branch of chemistry deals with the application of the laws of definite proportions and of the conservation of mass and energy to chemical activity. The quantitative relationship between constituent in a chemical substance.
We have given here,
Moles of sodium chloride = 0.25moles
Let us assume the the volume of the solution is 1 L.
Molarity = 0.25/
Molarity will be 0.25 M
The mass of sodium Hydroxide is 20g and the molar mass is 40g ,
and the Volume will be 0.2L
Molarity = 20/ 40×0.2
Molarity = 2.5 mol / L
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Light emitted by element X passes through a diffraction grating that has 1200 slits/mm/mm. The interference pattern is observed on a screen 79.0 cmcm behind the grating. First-order maxima are observed at distances of 58.2 cmcm , 65.2 cmcm , and 92.5 cmcm from the central maximum.
What are the wavelengths of light emitted by element X?
Answers
Answer:
The wavelengths are
\(\lambda_1 = 614\ nm \)
\(\lambda_2 = 687\ nm \)
\(\lambda_3 = 975\ nm \)
Explanation:
From the question we are told that
The number of slits per mm is N = 1200
The distance of the screen is \(D = 79.0 \ cm = 0.79 \ m\)
The first distance where First-order maxima is observed is \(y_1 = 58.2 cm = 0.582 \ m \)
The second distance where First-order maxima is observed is \(y_2 = 65.2 \ cm = 0.652 \ m \)
The second distance where First-order maxima is observed is \(y_2 = 92.5 \ cm = 0.925 \ m \)
Generally the distance of separation between the slits is mathematically represented as
\(d = \frac{1}{1200}= 8.33 *10^{-4} \ mm = 8.33 *10^{-7} \ m\)
Considering the first distance where First-order maxima is observed
Generally the the first distance where First-order maxima is observed is mathematically represented as
\(y_1 = \frac{\lambda_1 * D}{d}\)
=> \(\lambda_1 = \frac{0.582 * 8.33 *10^{-7} }{0.79}\)
=> \(\lambda_1 = 6.14 *10^{-7} m \)
=> \(\lambda_1 = 614\ nm \)
Considering the second distance where First-order maxima is observed
Generally the the second distance where First-order maxima is observed is mathematically represented as
\(y_2 = \frac{\lambda_2 * D}{d}\)
=> \(\lambda_2 = \frac{0.652 * 8.33 *10^{-7} }{0.79}\)
=> \(\lambda_2 = 6.87 *10^{-7} m \)
=> \(\lambda_2 = 687\ nm \)
Considering the third distance where First-order maxima is observed
Generally the the third distance where First-order maxima is observed is mathematically represented as
\(y_3 = \frac{\lambda_3 * D}{d}\)
=> \(\lambda_3 = \frac{0.925 * 8.33 *10^{-7} }{0.79}\)
=> \(\lambda_3 = 9.75 *10^{-7} m \)
=> \(\lambda_3 = 975\ nm \)
what is angular frequency
Answers
An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
Answers
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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Kaseem is taking his bicycle for a ride. His bicycle is a system, and its main purpose is to provide transportation. What is the main input into this system? What is the desired output of this system?
Answers
How has information technology impacted the economy? Choose three answers.
Answers
Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.
The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.
This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.
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--The complete question is, How has information technology impacted the economy?--
Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?
Answers
The following is not a source of outdoor air pollution : D) Household cleaning products.
What is meant by the outdoor air pollution?Presence of one or more substances in air at concentration or for a duration above the natural level is called air pollution.
Outdoor air pollution refers to pollutants that are released into the atmosphere by sources outside of buildings or structures. The sources of outdoor air pollution can be natural or human-made. Some examples of sources of outdoor air pollution are:
A) Exhaust from cars and trucks
B) Smoke from factories and power plants
C) Pollen from trees and plants
D) Solid fuel burning
E) Forest fires
Therefore, the correct option is D) Household cleaning products.
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Note: The question given on the portal is incomplete. Here is the complete question.
Question: Sierra lives in a southwestern town in a valley where air pollutants sometimes settle. The mountains that surround the town keep air pollution from blowing away. Sometimes Sierra can actually see the pollution in the air. Which choice is NOT a source of outdoor air pollution?
A) Exhaust from cars and trucks
B) Smoke from factories and power plants
C) Pollen from trees and plants
D) Household cleaning products.
3. How is using a model to study cells helpful?
Answers
Answer:
Yes, it is very helpful.
Explanation:
It's helpful since in a cell, plant or animal, there are a lot of different things. It's hard to memorize everything and know what they look like. Using a model can help you memorize everything better and even understand it better. If someone asked me where or what something was in a cell I think I would be able to recognize it better.
I hope this helps!
you push on a 35N object for 3 seconds. find work?
Answers
Answer:
This question is improper, The Formula for work is force times distance, it only provides you with force and time so you cannot calculate work without the distance, Maybe you've mistaken work for power, The formula is work divided by time, but ask your teacher to provide you with more information because this entire question is WRONG. If it didnt give you a distance there is a possibility that it's 0 which would be 35N*0m, get some clarification.
Explanation:
INCORRECT question
W=F*D
P=W/T
Please help 50 points and Brainly
Answers
Mechanical energy → Electrical energy → Thermal energy
What is mechanical energy?
Mechanical energy is the energy possessed by an object due to its motion or position. It is the sum of kinetic energy and potential energy of an object, which can be converted to other forms of energy, such as electrical energy or thermal energy.
What is electrical energy?
Electrical energy is the energy associated with the movement of electrons through a conductor or an electrical circuit. It is the result of the movement of charged particles, such as electrons, and is commonly generated by the conversion of other forms of energy, such as mechanical, chemical, or solar energy.
What is thermal energy?
Thermal energy is the energy associated with the temperature of an object or a system. It is the result of the movement of atoms and molecules in matter, which leads to the transfer of heat from hotter to cooler objects. Thermal energy is commonly measured in units of joules or calories and is proportional to the mass and temperature of an object or a system.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Two metal sphere each of radius 2.0 cm, have a center-to-center separation of 3.30 m. Sphere 1 has a chrage of +1.10 10^-8 C. Sphere 2 has charge of -3.60 10^-8C. Assume that the separation is large enough for us to assume that the charge on each sphere iss uniformly distribuuted.
A) Calculate the potential at the point halfway between the centers.
B) Calculate the potential on the surface of sphere 1.
C) Calculate the potential on the surface of sphere 2.
Answers
Answer:
A) V = -136.36 V , B) V = 4.85 10³ V , C) V = 1.62 10⁴ V
Explanation:
To calculate the potential at an external point of the spheres we use Gauss's law that the charge can be considered at the center of the sphere, therefore the potential for an external point is
V = k ∑ \(q_{i} / r_{i}\)
where \(q_{i}\) and \(r_{i}\) are the loads and the point distances.
A) We apply this equation to our case
V = k (q₁ / r₁ + q₂ / r₂)
They ask us for the potential at the midpoint of separation
r = 3.30 / 2 = 1.65 m
this distance is much greater than the radius of the spheres
let's calculate
V = 9 10⁹ (1.1 10⁻⁸ / 1.65 + (-3.6 10⁻⁸) / 1.65)
V = 9 10¹ / 1.65 (1.10 - 3.60)
V = -136.36 V
B) The potential at the surface sphere A
r₂ is the distance of sphere B above the surface of sphere A
r₂ = 3.30 -0.02 = 3.28 m
r₁ = 0.02 m
we calculate
V = 9 10⁹ (1.1 10⁻⁸ / 0.02 - 3.6 10⁻⁸ / 3.28)
V = 9 10¹ (55 - 1,098)
V = 4.85 10³ V
C) The potential on the surface of sphere B
r₂ = 0.02 m
r₁ = 3.3 -0.02 = 3.28 m
V = 9 10⁹ (1.10 10⁻⁸ / 3.28 - 3.6 10⁻⁸ / 0.02)
V = 9 10¹ (0.335 - 180)
V = 1.62 10⁴ V
A student stands on the ground with an egg in his hand. He throws the
egg vertically upwards. The egg rises to a height of 10 m. Then the egg
falls and lands on the ground.
Describe the energy changes of the egg during this sequence of events.
(6 marks)
Answers
The maximal potential energy is present at the highest point, and there is no kinetic energy due to the zero ultimate velocity at the lowest point.
What is potential energy?
The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
The potential energy is mainly depending upon the height of the object.
When the egg is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
When the egg lands on the ground at the striking point only the kinetic energy exists the potential energy is zero.
According to the law of conservation of energy, total energy is defined as the sum of kinetic energy and potential energy.
Total energy = kinetic energy+potential energy
Also, the energy can not be created nor destroyed and can be transferred from one form to another form.
Hence, at the highest point potential energy is the maximum and the kinetic energy is zero. because the final velocity is zero.
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At the highest point, the maximum potential energy is present. But kinetic energy is not present because of zero velocity at the lowest point.
What is potential energy?Potential energy is the energy posses by an object due to its position relative to other objects , which it stresses within itself.
Potential energy depends upon the height of the object. its SI unit is joule.
When egg rises to the maximum height from the ground surface, the potential energy is also maximum.
When the egg falls and lands on the ground , the potential energy will be zero. It posses only kinetic energy.
By the law of conservation of energy ,
The energy is neither be created nor be destroyed and cannot be transferred from one form to another.
Therefore, At the highest point the potential energy is maximum. But kinetic energy is zero.
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A man walks 30 m to the west, then 5 m to the east in 45 seconds.
What is his average speed?
Answers
when are two magnets attracted?
Answers
Answer:
when the negative and positive energy is connected
Explanation:
A hollow sphere made out of electrically insulating material is electrically neutral (no excess charge). A small amount of negative charge is suddenly placed at one point P on the outside of this sphere. If we check on this excess negative charge a few seconds later we will find one of the following possibilities: O a) All of the excess charge remains right around P. O b) The excess charge has distributed itself evenly over the outside surface of the sphere. ( c) The excess charge is evenly distributed over the inside and outside surface. d) Most of the charge is still at point P, but some will have spread over the sphere. e) There will be no excess charge left.
Answers
A hollow sphere made out of electrically insulating material is electrically neutral (no excess charge) then the correct option is b) The excess charge has distributed itself evenly over the outside surface of the sphere.
The metal spherical is a conductor and hollow. Charges can therefore circulate freely across its surface as a result. A metal body serves as an equipotential body on the other side. Once a charge has been established and there is no longer a voltage differential imprinted across the body, the charges must be distributed uniformly across the exterior surface for the body to continue to be an equipotential body. There must not be any charge in the volume because otherwise an electrical field and consequent voltage differential would arise.
Additionally, the interior surface's charge distribution must be zero. The enclosed charge must be zero if the Gauss Theorem is applied to a gaussian sphere with a radius between the internal and external surfaces and the knowledge that field E is zero.
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How do you find the centripetal acceleration without the radius???? I genuinely don’t know what to do.
Answers
Answer:
In order to calculate the value of force without radius, you may need the circumference whose formula is C=2πr. You can also find this force by calculating just acceleration using the formula: And this is also called Newton’s second law of motion, which can be calculated by entering acceleration and mass of the object.
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Explanation:
The work done on a 10. 0-kilogram mass to give it a speed of 5. 00 meters per second is.
Answers
Answer:
125 joules.
Explanation:
The work done on an object to give it a certain velocity can be calculated using the formula:
W = (1/2)mv²
where W is the work done, m is the mass of the object, and v is its final velocity.
Substituting the given values, we get:
W = (1/2)(10.0 kg)(5.00 m/s)²
W = (1/2)(10.0 kg)(25.0 m²/s²)
W = 125 J
Therefore, the work done on the 10.0-kilogram mass to give it a speed of 5.00 meters per second is 125 joules.
Nuclear DNA testing can be performed if we have the _____(a)_____ of the hair. If we only have the ____(b)______ of the hair, testing for mitochondrial DNA is done instead.
Answers
Answer:
have fabric saliva
Explanation:
next
Nuclear DNA testing can be performed if we have the root of the hair. If we only have the shaft of the hair, testing for mitochondrial DNA is done instead.
a) Nuclear DNA Testing with the Root of the Hair:
The root of a hair contains cells with a nucleus, which houses nuclear DNA. Nuclear DNA carries genetic information unique to an individual, inherited from both parents. When performing nuclear DNA testing, scientists extract DNA from the cells in the hair root.
b) Mitochondrial DNA Testing with the Shaft of the Hair:
The shaft of hair is the visible part that extends beyond the skin's surface. The shaft itself doesn't contain a nucleus it does contain mitochondrial DNA within its cells mitochondria. Mitochondrial DNA is inherited only from the mother and is used in cases where nuclear DNA may be degraded or unavailable.
In summary, nuclear DNA testing requires the root of the hair because it contains intact nuclear DNA, while mitochondrial DNA testing can be done using the hair shaft, focusing on mitochondrial DNA passed down from the mother.
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How can graphs help demonstrate the qualitative relationship that may exist in a set of data to readers?
Answers
Graphs can help to demonstrate the qualitative relationship between a set of data by identifying patterns among these data.
What other information can the data show?Comparison between groups.Proportional relationships.Variation and dispersion.Graphs can allow readers to identify a lot of information among a set of data. The most common information to be evaluated through the graphs is the existence of patterns between the data.
For example, a line graph can show the change in a variable over time, allowing readers to see if there is a consistent increase or decrease.
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How many times does the kinetic energy of a car increase when traveling 60 mph as opposed to traveling 15 mph?
K.E. increases
5
4
16
20
Answers
Answer:
20
Explanation:
i'm not so sure with my answer