A driver of an automobile travelling at a constant speed of 20m/s suddenly applies a brake and the automobile comes to rest in 2 seconds after skidding for a certain distance. What is the length of the skid distance? A. 400m B. 20m C. 40m D. 10m.​

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

the ray of light should approach normal

Explanation:

When light passes through two means of different refractive index, it fulfills the equation

              n₁ sin  θ₁ = n₂ sin θ₂

where index 1 and 2 refer to each medium

In this problem, they tell us that light passes to a medium with a higher index, which is why

               n₁ <n₂

let's look for the angle in the second half

            sinθ₂ = n₁ /n₂  sin θ₁

            θ₂ = sin⁻¹ (n₁ /n₂  sin θ₁)

let's examine the angle argument the quantity n₁ /n₂ <1   therefore the argument decreases, therefore the sine and the angle decreases

Consequently the ray of light should approach normal

19.56m is the common height from which the rocks were released.

Formula used for calculating the height(s) is

s = ut + 1/2gt²

where

s = Common height from which the rocks were released

u = Initial velocity

g = acceleration

t = time period taken

For Wes

Initial velocity(u) = 0

So, s = 1/2gt² .... (1)

For Lindsay

Initial velocity = 27m/s

Time (t) = t - 1.35

So, s = 27(t - 1.35) + 1/2g(t - 1.35)² ..... (2)

From equation (1) and (2)

1/2gt² = 27(t-1.35) + 1/2g(t - 1.35)²

On solving we get

t = 1.998 seconds

Now By putting the calculated value of (t) in equation (1)

s = 1/2 × 9.8 × (1.998)²

s = 19.56 m

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Answer:

Tension

Explanation:

Answer:

Sporulation

the formations of spores from vegetative cells during unfavorable environmental conditions

Fragmentation

The asexual reproduction, where the body of the organism breaks into smaller pieces

Fragmentation: The breaking up of the body of organisms into two or more pieces or fragments on maturing, each of which subsequently can grow into a completely new organism is called fragmentation.

Definition of sporulation

: the formation of spores

sporulation refers to the formation of spores from vegetative cells during unfavorable environmental conditions. As such, it may be described as an adaptive response that allows the organism to survive given adverse conditions (radiation, extreme heat or cold, lack of nutrition etc).

Answer: Charge on the ball is 3.6 ×10^-4 C.

In this question we have given the Electric field of the region we need to find the Charge on the ball .

What is Electric Field?

--An electric field  is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

We used the concept of string ball--  i.e

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Answer:

W = 3F

Explanation:

Work is defined as the inner product between force and displacement. The inner product picks out the force components which point in the same direction as the displacement. The vertical components do not matter in the horizontal displacement. I am assuming you're dealing with 1-dimensional motion? Then the work would be:

\(W=Fd\)

The displacement is 3 meters. Therefore, the work is:

\(W=3F\)

You haven't gave the force being applied to the object, so I cannot give an explicit answer. Just multiply the force by 3 to get the work.

Water enters the hull at a rate of 29400 cm^3/s.

The distance an object travels in a unit of time is its speed. Speed is a scalar quantity since it has simply magnitude and no direction. SI unit of speed is meter per second.

Given that area of the hole of puncture = 20 cm^2

Depth of the hole: d = 1.5 m.

Then, the speed of the water enter the hull =

acceleration due to gravity × depth

= 9.8 × 1.5 m/s

= 14.7 m/s

= 1470 cm/s.

Hence, the rate of water enter the hull is = the speed of the water × area of the hole

=   1470 cm/s × 20 cm^2

= 29400 cm^3/s.

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The work-energy theorem explains the idea that the net work - the total work done by all the forces combined - done on an object is equal to the change in the kinetic energy of the object. After the net force is removed (no more work is being done) the object's total energy is altered as a result of the work that was done.

This idea is expressed in the following equation:

is the total work done

is the change in kinetic energy

is the final kinetic energy

is the initial kinetic energy

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Answer:

280N

Explanation:

As the statement put in parenthesis state-You need to add up all the forces acting on the object to find the net force, so over here-

250+30=280N

(a) The final velocity of the two vehicles if the collision was inelastic is 1.1 m/s.

(b)  For the elastic collision, the final velocity of the car is 9.81 m/s backwards and the final velocity of the truck is 2.19 m/s forward.

(c) The time taken to exert the given force is 0.00625 m (s).

The given parameters;

(a) The final velocity of the two vehicles if the collision was inelastic is calculated as follows;

\(m_1 u_1 + m_2u_2 = v(m_1+ m_2)\\\\12m + 10m(0) = v(m + 10m)\\\\12m = v(11m)\\\\v = \frac{12m}{11m} \\\\v = 1.1 \ m/s\)

(b) The final velocity of the two vehicles if the collision was elastic is calculated as follows;

\(m_1 u_1 + m_2u_2 = m_1v_1 + m_2v_2\\\\\12m \ + \ 10m(0) = mv_1 + 10mv_2\\\\12m = m(v_1 + 10v_2)\\\\12 = v_1 + 10 v_2\ \ - --(1)\)

Apply one-directional velocity equation:

\(u_1 +v_1 = u_2 + v_2\\\\12 + v_1 = 0 + v_2\\\\12+ v_1 = v_2 \ \ --- (2)\)

Substitute the value of \(v_2\) into equation (1);

\(12 = v_1 + 10(12 + v_1)\\\\12= v_1 + 120 + 10v_1\\\\12- 120 = 11v_1\\\\-108 = 11v_1\\\\v_1 = \frac{-108}{11} \\\\v_1 = -9.81 \ m/s\\\\\)

Solve for \(v_2\);

\(v_2 = 12 + v_1\\\\v_2 = 12 - 9.81\\\\v_2 = 2.19 \ m/s\)

Thus, for the elastic collision, the final velocity of the car is 9.81 m/s backwards and the final velocity of the truck is 2.19 m/s forward.

(c)

The change in the momentum of the truck is calculated as;

\(\Delta P = m_2(v_2 - u_2)\\\\\Delta P = 10m(2.19)\\\\\Delta P = 21.9m\)

The time taken to exert the given force is calculated as follows;

\(Ft = \Delta P\\\\t = \frac{\Delta P}{F} \\\\t = \frac{21.9 \ m}{3500} \\\\t = 0.00625 \ m (seconds)\)

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A is provided with the proper procedure by moles x molar mass. This same mass metric grams of one mole of an ingredient is its molar mass.

The proportion of substance in a thing is measured by its mass. That thing will be the same mass no matter where it is in the enormous universe. Contrarily, weight is a measurement that indicates how much gravitational potential energy is being applied to an object.

A pure element's atomic mass in number of atoms (amu) or grams for every mole (g/mol) is proportional to the mass about one mole of its elements in grams. Despite the fact that mass can be stated as either amu or g/mol, g/mol.

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a) The initial speed of the car = 0 m/s

b) The final speed of the car = 160 km/h =44.4 m/s

c) Average speed = 80 km/h = 22.22 m/s

a) Since the car starts from rest, the initial speed of the car, u = 0 m/s

It accelerates uniformly to a line 1.0 km away

Therefore, the distance, S = 1.0 km = 1 x 1000 m

Distance, S = 1000 m

It crosses the line at 160 km/h

Final speed, v = 160 km/h

v = 160 x 1000/3600 m/s

b) The final speed, v = 44.4 m/s

c) The average speed is calculated below

Average speed = (Initial speed + Final speed)/2

Average speed = (0+160)/2

Average speed = 160/2 = 80 km/h

Average speed = 80 x 1000/3600

Average speed = 22.22 m/s

Second method

Average speed = Total distance/Total time

Average speed = 1 km/45s = 1000m / 45s

Average speed = 22.22 m/s

Answer:

2.39 Ω

Explanation:

Given that

Number of winnings on the coil, = 250 turns

Radius if the copper wire, r(c) = 1.3/2 = 0.65 mm

Radius of single cylinder layer, R = 12 cm

Length of the cylinderical coil, L = 250 * 2π * 12 = 188.4 m

Resistivity of copper, ρ = 1.69*10^-8 Ωm

Area is πr(c)², which is

A = 3.142 * (0.65*10^-3)²

A = 3.142 * 4.225*10^-7

A = 1.33*10^-6 m²

The formula for resistance is given as

R = ρ.L/A, if we substitute, we have

R = (1.69*10^-8 * 188.4) / 1.33*10^-6

R = 3.18*10^-6 / 1.33*10^-6

R = 2.39 Ω.

Therefore, the resistance is 2.39 Ω

Answer:

Earth have a liquid water supply and Mars does not because of the difference in their magnetic fields. Therefore the option B is correct.

Explanation:

The atmosphere of Earth is shielded from solar winds and radiation by a potent magnetic field, which keeps the atmosphere from being torn away. This enables water to remain liquid on the surface of the planet.

Mars, in contrast, has a weaker magnetic field, which results in a thinner atmosphere that is unable to support liquid water. Mars is hence more colder and drier than Earth.

One of the main reasons that Mars has no life as we know it is because it lacks a magnetic field, whereas the magnetic field of Earth is crucial in fostering the conditions necessary for life to flourish.

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Answer:

It bends.

Explanation:

Water is denser than water. This causes light that is passing from air to water to appear to bend towards the normal line near the water's surface.

Answer:

Yes, of course

Explanation:

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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Answer:

b. parallel

Explanation:

The radius of curvature of the bowl is 42 cm. It should be noted that this is a negative value, indicating that the mirror is concave (curved inward) rather than convex (curved outward).

The situation described can be modeled using the thin lens equation, which relates the object distance, image distance, and focal length of a lens or curved mirror. In this case, we can assume that the bowl acts as a concave mirror, with its reflecting surface forming a portion of a sphere.

We can also assume that the mirror is thin, meaning that the distance between the reflecting surface and the center of curvature is much greater than the radius of curvature.

Let us denote the radius of curvature of the mirror as R. When the child looks into the bowl, an erect image of himself is formed at a distance of 21 cm from the bowl. Using the thin lens equation, we can write:

\(1/f = 1/d_o + 1/d_i\)

where f is the focal length of the mirror, \(d_o\) is the object distance (i.e., the distance between the child and the mirror), and \(d_i\)is the image distance (i.e., the distance between the mirror and the image).

In this case, the object distance is negative (since the child is looking into the bowl from the same side as the object), and the image distance is positive (since the image is erect). Substituting the given values, we obtain:

\(1/f = -1/21 + 1/d_i\)

Next, when the child turns the bowl over, another erect image of himself is formed at a distance of 7 cm from the bowl. Using the same equation, we can write:

\(1/f = -1/d_o + 1/d_i'\)

where d_i' is the image distance for this case. In this case, the object distance is positive (since the child is looking at the bowl from the opposite side of the object), and the image distance is also positive (since the image is erect). Substituting the given values, we obtain:

\(1/f = 1/7 + 1/d_i'\)

Now we have two equations for f in terms of \(d_i\) and \(d_i\)', respectively. We can solve for \(d_i\)and \(d_i\)' by setting these two equations equal to each other and simplifying:

\(-1/21 + 1/d_i = 1/7 + 1/d_i'\\d_i' = 1/(1/7 - 1/21 + 1/d_i) = 28 cm\)

Now that we know both image distances, we can solve for the radius of curvature R using the mirror formula, which relates the focal length to the radius of curvature:

1/f = 2/R

Substituting the values of f and \(d_i\), we obtain:

\(1/R = 2/f = -1/21 + 1/d_i\)

Solving for R, we obtain:

R = -42 cm

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Answer:

1 x 10^-9 kilometers

Hope this helps

Have a good day :)

Explanation:

Answer:

Therefore, the voltage required is 20 volts

Explanation:

To find the voltage that will send a current of 5 amperes through a bell circuit with a resistance of 4 ohms, we can plug in the values into the equation and solve for V: V=IR

V=(5A)(4Ω)

V=20V

The true weight of the goods being marked up by 8.3% by the shopkeeper.

A bending moment is the reaction that occurs in a structural element as a result of an external force or moment that causes the element to bend, as defined by solid mechanics. The beam is the most prevalent or most basic structural component that experiences bending moments.

Calculated the bending moment about the balance:

P₁(33.6 + 1.35) = P₂ ( 33.6 - 1.35)

P₂ = 1.083 P₁

Hence, percentage change = (P₂-P₁)/P₁ × 100% = 8.3 %

So, the true weight of the goods being marked up by 8.3% by the shopkeeper.

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Expression for the electric potential a distance z away from the center of rod on the line that bisects the rod is \(V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx\).

The electric potential at a distance z from a point charge Q is given by:

V = k * Q / r

here

k is Coulomb constant and

r is distance from the point charge to the point.

For a thin rod of length L and charge Q, we can model it as a line of charge with linear charge density λ = Q/L. The electric potential at a distance z away from the center of the rod on the line that bisects the rod can be found by breaking the rod into infinitesimal charge elements and integrating the electric potential due to each element over the length of the rod.

Let's consider a small element of length dx located at a distance x from the center of the rod:-

\(dQ = \lambda * dx = Q/L * dx\)

The displacement element to pt.:-

\(r = \sqrt{(x^2 + z^2)}\)

The electric potential due to this element is:

\(dV = k * dQ / r = k * Q/L * dx / \sqrt{(x^2 + z^2)}\)

Integrating this expression over the length of the rod, we get the total electric potential at a distance z away from the center of the rod on the line that bisects the rod:

\(V = \int\limits^(^-^L^/^2^)_L_/_2 {k * Q/L * dx / √\sqrt{(x^2 + z^2)}} \, dx\)

To evaluate this integral,

\(u = x^2 + z^2, du/dx = 2x dx\),

This can be further simplified:-

\(u = z^2 * tan^2\theta + L^2/4 * sec^2\theta\)

\(V = k * Q / L * \int\limits {cos\theta / z \sqrt{(1 + L^2/4z^2 * tan^2\theta)} d\theta} \, dx\)

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Answer:

Explanation:

average acceleration= (15-0)/5

                                   =15/5

                                   3ms-2

Answer:

silverware and tupperware?

The block's centripetal acceleration may be calculated since ac=v2rac=v2r when the radius and tangential speed of the block are known.

The phrase "force" seems to have a precise definition in physics. It is quite acceptable to refer to a force of this level as a push or a pull. An item does not "have in it" or "contain" a force. One thing is subject to a force from another.

Basically, force is a push or pull that affects an item or energy as a characteristic of physical motion or movement. When two things interact, it happens. Furthermore, a body is said to be in motion when it is moving.

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