A dolphin swims 1.85 km/hr how far has the dolphin traveled after 0.6 hours

A 1.11km

B 3.08km

C 0.32km

D 1.85km

The acceleration of the object is 2.0 m/s². This means that for every second the object is in motion, its velocity will increase by 2.0 meters per second.

The given information is the net force (N) = 5.0 and the mass (kg) = 2.5. We need to determine the acceleration.


Acceleration is the rate at which an object's velocity changes over time.

It is directly proportional to the net force applied to the object and inversely proportional to its mass.

The formula to calculate acceleration is:

Acceleration = Net Force / Mass

Now, let's substitute the given values into the formula:

Acceleration = 5.0 N / 2.5 kg

Simplifying the equation:

Acceleration = 2.0 m/s²

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Answer: 3A, current flowing through the circuit is 3A

Explanation: we know that the voltage given in the figure is 120V

Formula applied - I=V/R

resistors are connected in SERIES

R1= 10

R2= 5

R3= 25

R1+R2+R3=40

I=120/40 =3A

Hence current flowing is 3A

Pitch refers to how high or low a sound seems to a person. It is the degree of highness or lowness of a sound, which is determined by the frequency of a sound wave.

Pitch is a sound's quality that enables us to discern between a low and a high sound. It is the degree of highness or lowness of a sound and is determined by the frequency of a sound wave. A high-pitched sound is a sound that has a high frequency. A low-pitched sound, on the other hand, is a sound that has a low frequency. Sound pitch is an important aspect of music and voice tone.Pitch can be described as the rate of vibration of sound waves, measured in Hertz (Hz), with higher frequencies indicating a higher pitch. The pitch of a sound can be altered by changing the frequency of the sound wave. Pitch and volume are two of the most important qualities of sound that are utilized in music and speech to express various emotions and convey meaning.The pitch of a sound is generally increased by increasing the frequency and decreased by decreasing the frequency. The pitch of a sound can also be affected by other factors, such as the size, shape, and material of the object producing the sound. For instance, a guitar string that is tight will create a high-pitched sound, while a loose guitar string will create a low-pitched sound. Similarly, a small bell will produce a high-pitched sound, while a large bell will produce a low-pitched sound.

Pitch is the degree of highness or lowness of a sound and is determined by the frequency of a sound wave. A high-pitched sound is a sound that has a high frequency. A low-pitched sound, on the other hand, is a sound that has a low frequency. Pitch can be described as the rate of vibration of sound waves, measured in Hertz (Hz), with higher frequencies indicating a higher pitch. The pitch of a sound can be changed by adjusting the frequency of the sound wave.

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Answer:

3000g

hope this helps<3

Answer:

I know its not A or D so its B or C and the more logical answer would be B. gravity

Explanation:

Answer:

A) Sue is lifting the bucket by a force of 49.035 newtons.

B) The bucket has an acceleration of 8.207 meters per square second on the Moon.

Explanation:

A) According to the First Newton's Law, a system is at equilibrium when it is either at rest or travelling at constant velocity. In this case, Sue must exert an external force on the bucket, whose magnitude is equal to the weight of the bucket but direction is opposed to it. By Second Newton's Law, we find that:

\(\Sigma F = F - m\cdot g = 0\) (1)

Where:

\(F\) - Lifting force, measured in newtons.

\(m\) - Mass of the bucket, measured in kilograms.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(m = 5\,kg\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the lifting force is:

\(F = m\cdot g\)

\(F = (5\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\)

\(F = 49.035\,N\)

Sue is lifting the bucket by a force of 49.035 newtons.

B) By the Second Newton's Law, we have the following model:

\(\Sigma F = F-m\cdot g = m\cdot a\) (2)

Where \(a\) is the net acceleration of the bucket, measured in meters per square second.

If we know that \(F = 49.035\,N\), \(m = 5\,kg\) and \(g = 1.6\,\frac{m}{s^{2}}\), then the net acceleration of the bucket is:

\(a = \frac{F}{m} -g\)

\(a = \frac{49.035\,N}{5\,kg}-1.6\,\frac{m}{s^{2}}\)

\(a = 8.207\,\frac{m}{s^{2}}\)

The bucket has an acceleration of 8.207 meters per square second on the Moon.

(a) The force applied by Sue in lifting the bucket at a constant velocity is 49 N.

(b) The acceleration of the bucket when lifted on the moon is 8.2 m/s².

The given parameters;

The force applied by Sue in lifting the bucket at a constant velocity is calculated as;

\(F = m(a + g)\)

\(F= mg\\\\F = 5 \times 9.8\\\\F = 49 \ N\)

The acceleration of the bucket when lifted on the moon with the calculated force is;

\(F = m(a + g)\\\\a+g = \frac{F}{m} \\\\a = \frac{F}{m} - g\\\\a = \frac{49}{5} - 1.6\\\\a = 8.2 \ m/s^2\)

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Answer:

a) 756.64 ft

b) 30 degrees

c) 29.27 degrees.

Explanation:

We can represent the situation as follows:

So, we can find the magnitude of the displacement (the green line) using the Pythagorean theorem. Then:

Then, the angle of the displacement can be approximate finding the angle θ. So, using a protractor on the figure, we get that θ is approximately 30 degrees.

Now, we can find the direction using a trigonometric function as:

Because 370 is the opposite side and 660 is the adjacent side. Therefore, the value of θ is:

So, the answers are:

a) 756.64 ft

b) 30 degrees

c) 29.27 degrees.

Answer:

They're impressions of organisms preserved in rock. Paleontologists use fossil remains to understand different aspects of extinct and living organisms.  They do this by analyzing invertebrate fossils. All of this, all this studying helps to know our past.

Explanation:

Answer:

1111111

Explanation:

Answer:

564356

Explanation:

Answer:

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

Explanation:

Given;

mass of the object, m = 2 kg

weigh of the object, W = 20 N

tension on the rope, T = 12 N

The acceleration of the object is calculated by applying Newton's second law of motion as follows;

T = F + W

T = ma + W

ma = T - W

\(a = \frac{T-W}{m} \\\\a = \frac{12 - 20}{2} \\\\a = -4 \ m/s^2\) (the negative sign indicates deceleration of the object)

The object accelerates downward at 4 m/s² since the tension on the rope is less than weight of the object.

An appropriate value for the resistance in parallel with the smoothing capacitor would be 1.59 kΩ.

To ensure good tracking of the AM envelope, the resistance in parallel with the smoothing capacitor should be low enough to discharge the capacitor quickly during the troughs of the modulated signal, but high enough to avoid discharging it too quickly during the peaks of the signal.

The time constant (τ) of the RC circuit formed by the smoothing capacitor and the parallel resistance is given by the formula:

τ = RC

where R is the resistance and C is the capacitance.

To determine an appropriate value for the resistance, we need to calculate the time constant and compare it to the period of the modulated signal.

The period of a 500 kHz signal is T = 1/f = 2 μs. The modulating signal has a bandwidth of 5 kHz, which means its period is 200 μs.

Assuming a small signal approximation, we can use the formula for the time constant to calculate an appropriate value for the resistance:

τ = 20 nF × R = T/2π = 31.8 ns

Solving for R, we get:

R = τ/C = 31.8 ns / 20 nF = 1.59 kΩ

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Complete question is:

The input signal into an envelope detector is an am signal of carrier frequency 500 khz. the envelope detector employs a smoothing capacitor of 20 nf. the modulating signal has a bandwidth of 5 khz. specify an appropriate value for the resistance in parallel with the smoothing capacitor for a good tracking of the am envelope.

Answer: set up proportions

Explanation:

Constructive force ➡️ Process where crust is formed

Destructive force ➡️ Process where crust is destroyed

Weathering ➡️ Break down of rock materials

Erosion ➡️ Movement of broken down rock material

Tectonic uplift ➡️ Upward movement of crust

Heya!!

For calculate aceleration, lets applicate second law of Newton:

                                                   \(\boxed{F=ma}\)

                                                 Δ   Being   Δ

                                             F = Force = 78,3 N

                                            m = Mass = 24,5 kg

                                             a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

\(\boxed{a=78,3\ N / 24,5\ kg}\)

⇒ Resolving

\(\boxed{a=3.19\ m/s^{2}}\)

Result:

The aceleration is 3,19 meters per second squared (m/s²)

Good Luck!!

Answer:

a

Explanation:

occurs when the crest of one wave meets the trough of another wave as they travel from two different points in the same direction and at the same frequency

The speed of sound in water made by a torpedo with a speed of 20.00m/s and explodes upon impact with a target 2000.0m away is 19.72 m / s

v = d / t

v = Velocity

d = Distance

t = Time

d = 2000 m

t = 101.4 s

v = 2000 / 101.4

v = 19.72 m / s

Velocity of an object is the object's rate of change of position with respect to time. It is mostly denoted as m / s.

Therefore, the speed of sound in water is 19.72 m / s

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An existing surface low-pressure system would probably stay stagnant or diminish due to the lack of support from upper-level dynamics if there was no divergence or convergence in the upper troposphere.

On the other hand, sea-level pressures rise in areas of convergence in the upper atmosphere. Surface high-pressure systems are often characterized by calm, largely clear weather due to the ensuing low-level divergence and sinking air.

The pressure systems traveling along the surface are enhanced or suppressed by this convergence and divergence. The air density above, for instance, will decrease when there is a region of diverging air in the upper troposphere.

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The motion of the particles in this kind of wave will be option C that is The particles will move side to side over small areas.

A wave can be described as a disturbance that travels through a medium from one location to another location.

When Marcus plucks an outstretched coil, the coli sets into wave like motion that is oscillates to and fro. The particles of the medium do not move along the wave but just vibrate sideways about a fixed position.

The particles would move side to side over very small areas. Such type of wave is known as a mechanical wave. A Sound wave is a mechanical wave.

The particles vibrate in the direction of the motion of the wave. The wave carries forward the energy.

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Answer:

C is the correct answer. :)

Explanation:

The second statement is correct : Gravity is a force that pulls objects towards Earth's centre.

Answer:

The second statement is correct : Gravity is a force that pulls objects towards Earth's center

Explanation: i am a smart

Answer:

its c

Explanation:

Answer:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Explanation:

I could be wrong but I would say B :)

Have a good day!

answer:

i believe the answer is d

explanation:

here's why;

c. is incorrect because everything has a gravitational force.

a. is also incorrect because gravity is what holds the tennis ball down and keeps it on the ground.

i don't really know how to explain why b. is wrong, but d. is the correct answer because the force of friction opposes the motion of an object, causing moving objects to lose energy and slow down.

good luck :)

i hope this helps

**please let me know if this was incorrect**

have a great day !!

The intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 is 27 dB.

The intensity level of a sound can be calculated using the following formula:
Intensity level (dB) = 10 log (I/I0), where I is the intensity of the sound and I0 is the reference intensity, which is typically 10-12 W/m2.
Using this formula, we can calculate the intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 as follows:
Intensity level (dB) = 10 log (5.0 × 10-10 / 10-12)
Intensity level (dB) = 10 log (5.0 × 102)
Intensity level (dB) = 10 × 2.7
Intensity level (dB) = 27 dB
Therefore, the intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 is 27 dB. It's important to note that the intensity level is a measure of how loud a sound is perceived by the human ear, and is typically measured on a logarithmic scale. So, a sound with an intensity level of 27 dB is considered relatively quiet, while a sound with an intensity level of 120 dB (such as a jet engine or a rock concert) is considered very loud and can cause hearing damage if exposure is prolonged.

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A) The moment of inertia (I) is 86.46 kg·m^2. B) The kinetic energy (K) when d = 6.00 m is 7777.14 J. C) The angular speed, when d = 6.00 m, is 57.30 rev/min.

A) To determine the moment of inertia (I) of the flywheel, we can use the equation:

I = (F * d^2) / (4π^2 * t^2)

where F is the constant force (41.0 N), d is the distance traveled (8.35 m), and t is the time elapsed (2.00 s).

Plugging in the given values, we have:

I = (41.0 * (8.35)^2) / (4π^2 * (2.00)^2)

I ≈ 86.46 kg·m^2

B) The kinetic energy (K) of the flywheel can be calculated using the formula:

K = (1/2) * I * ω^2

where I is the moment of inertia and ω is the angular speed.

Since the flywheel starts from rest, its initial angular speed (ω_i) is 0. When the free end of the rope travels 6.00 m, we can find the final angular speed (ω_f) using the equation:

d = ω_i * t + (1/2) * α * t^2

where d is the distance traveled (6.00 m), t is the time elapsed, and α is the angular acceleration. Since ω_i = 0, the equation simplifies to:

d = (1/2) * α * t^2

Solving for α:

α = (2 * d) / t^2

α = (2 * 6.00) / (2.00)^2

α = 3.00 rad/s^2

Now, we can calculate the final angular speed:

ω_f = ω_i + α * t

ω_f = 0 + 3.00 * 2.00

ω_f = 6.00 rad/s

Finally, we can substitute the values into the kinetic energy formula:

K = (1/2) * I * ω_f^2

K = (1/2) * 86.46 * (6.00)^2

K ≈ 7777.14 J

C) To convert the angular speed to rev/min, we can use the conversion factor:

1 rev = 2π rad

Therefore, the angular speed in rev/min is:

ω_f_rev_min = (ω_f * 60) / (2π)

ω_f_rev_min = (6.00 * 60) / (2π)

ω_f_rev_min ≈ 57.30 rev/min

A) The moment of inertia (I) of the flywheel is approximately 86.46 kg·m^2.

B) The kinetic energy (K) of the flywheel when d = 6.00 m is approximately 7777.14 J.

C) The angular speed of the flywheel, when d = 6.00 m, is approximately 57.30 rev/min.

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In fiber optic media, the signals are represented as patterns of light. Fiber optic cables are composed of thin strands of glass or plastic that act as a transmission medium for light signals.

These signals are typically in the form of modulated light pulses that carry information. The patterns of light are created by varying the intensity or the frequency of the light waves to encode the data being transmitted.

This modulation of light allows for the representation of complex digital signals such as voice, video, and data. The patterns of light travel through the fiber optic cable by repeatedly reflecting off the walls of the cable through a process known as total internal reflection.

At the receiving end, the light signals are decoded back into their original electronic form for further processing or display.

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Weather forecasts are made using barometers. An air pressure gauge, or barometer When the barometer reads "rising," the air pressure is rising; when it reads "falling," the air pressure is lowering.

Barometric pressure, to put it simply, is the measurement of air pressure in the atmosphere, more particularly, the measurement of the weight exerted by air molecules at a certain location on Earth.

barometer, a tool for calculating atmospheric pressure. A barometer may also be used to determine height since air pressure varies with elevation above or below sea level. Mercury and aneroid barometers are the two primary varieties.

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Spiral galaxies are classified based on spiral arm tightness, bulge size, and amount of gas and dust present. This allows astronomers to categorize them into subtypes such as Sa, Sb, and Sc.

The classification of spiral galaxies is based on three properties:

1. Spiral arm tightness: This refers to how tightly wound the spiral arms are around the galaxy's center. Galaxies with more tightly wound arms are classified as "Sa," while those with more loosely wound arms are classified as "Sc."

2. Bulge size: The central bulge of a spiral galaxy can vary in size. Larger bulges are typically found in early-type spiral galaxies (such as Sa), while smaller bulges are found in late-type spiral galaxies (like Sc).

3. Amount of gas and dust: The presence and distribution of gas and dust within a spiral galaxy also play a role in its classification. Early-type spiral galaxies generally have less gas and dust compared to late-type spiral galaxies.

By considering these three properties, astronomers can classify spiral galaxies into various subtypes (such as Sa, Sb, and Sc) within the broader spiral galaxy category.

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Answer:

The ramps length, height, degree, and the weight of the car.

Explanation:

Answer:

I think they need the slope of the ram(degree) .

& current gravitational acceleration

& the length of the ram and also l don't think mass of the cars are not needed becoz the acceleration of the cars are given by its,

Gravitational acceleration * sin( slope).

So then use that in v^2=u^2+2as equation.

s for length

a for acceleration

v for end velocity

u for start velocity

The force exerted on one end of the tank when it is full of gasoline with density 47 lb/ft3 is approximately 195,706,246.8 lb.

The weight of the gasoline can be calculated using the formula,

Weight = Volume x Density x Gravity

The volume of the gasoline can be calculated using the formula for the volume of a cylinder,

Volume = π x (Diameter/2)^2 x Length

The center of gravity of the gasoline is located at the midpoint of the tank, which is at a distance of half the length of the tank from either end.

Now, we can calculate the force exerted on one end of the tank using the formula,

Force = Weight x Distance from center of gravity to end of tank

Substituting the values,

Volume = π x (Diameter/2)^2 x Length

Volume = π x (8/2)^2 x 40 = 6,366.2 ft^3

Weight = Volume x Density x Gravity

Weight = 6,366.2 x 47 x 32.174 = 9,785,312.34 lb

Distance from center of gravity to end of tank = Length/2 = 20 ft

Therefore, the force exerted on one end of the tank is,

Force = Weight x Distance from center of gravity to end of tank

Force = 9,785,312.34 x 20 = 195,706,246.8 lb

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--The complete question is, A tanker truck transports gasoline in a horizontal cylindrical tank with diameter 8 ft and length 40 ft. if the tank is full of gasoline with density 47 lb/ft3, compute the force exerted on one end of the tank.--