A dog owner wants to test how exercise affects how his dog sleeps. On day 1, he exercises his dog for 2 hours and then records the amount of sleep the dog experiences that evening. The next day he exercises the dog for 4 hours and records the amount of sleep experienced by the dog and finally he records the amount of sleep with 6 hours of exercise. He was careful to give his dog the same amount of food on the days he did the experiment.

The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

To find the answer, we have to know more about the basic forces acting on a body.

                                 \(N=mg\\F_t=ma\\F_t=F-f\)

where, N is the normal reaction, mg is the weight of the box, \(F_t\) is the net force, f is the kinetic friction.

                      \(f=kN=kmg=0.267*1.75*9.8= 4.58N\)

                        \(F_t= 8.35-4.58=3.77N\)

Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.

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The net force acting on the box is 3.77 N.

We need to learn more about the fundamental forces affecting a body in order to locate the solution.

                             \(N=mg\\F_n=F-f\)

where N stands for the normal reaction, mg for the box's weight, is the net force, and f for kinetic friction.

                            \(f=kN=kmg=4.58N\)

                                     \(F_n=3.77N\)

Thus, it is clear that the box with a mass of 1.75 kg will experience a net force of 3.77 N when it is pushed across a surface with a coefficient of friction of 0.264.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

The statement is not correct.

Explanation:

To know if the statement is correct, we shall determine the velocity of the car after 3 s. This is illustrated below.

Data obtained from the question include:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) = 3 s

Final velocity (v) =?

v = u + gt

v = 0 + (9.8 × 3)

v = 0 + 29.4

v = 29.4 m/s

Thus, the velocity of the car after 3 s is 29.4 m/s.

Hence, the statement made by the friend is not correct as the car has a falling velocity of 29.4 m/s after 3 s.

To measure the surface area of the outline of the map of Africa, follow these steps: obtain a clear map, define the scale, digitize the outline using software, break it into sections, measure each section using tools or rulers, calculate the area using geographic data and formulas, and sum up the areas for the total surface area.

To measure the surface area of the outline of the map of Africa, you would need to follow a systematic approach involving several steps. Here's an outline of the process:

1. Obtain a high-quality map of Africa: Start by acquiring a map of Africa with clear and accurate boundaries. You can find printable maps or use digital mapping tools or Geographic Information System (GIS) software to access detailed maps.

2. Define the scale: Determine the scale of the map, which represents the ratio of a distance on the map to the corresponding distance on the Earth's surface. This information is typically provided on the map itself. Knowing the scale will help ensure accurate measurements.

3. Digitize the outline: Using digital mapping software or tools, carefully trace the outline of Africa on the map. This process is called digitization and involves converting the map's physical features into digital data points. Ensure that you capture all the intricate details of the outline.

4. Break it into smaller sections: Since Africa's outline is complex, you can divide it into smaller sections for easier measurement. This can be done by drawing imaginary lines or using software tools to split the outline into manageable parts.

5. Measure the sections: Once you have the individual sections, use measurement tools available in the software or tools like a digital ruler to measure the length of each section. Multiply the measured length by the scale factor to obtain the corresponding real-world distance.

6. Calculate the surface area: To calculate the surface area of each section, you would need additional data like the latitude and longitude coordinates of each point along the outline. Using geographic coordinate data, you can apply mathematical algorithms like the Shoelace formula or use GIS software with built-in area calculation functions to determine the area of each section.

7. Sum up the areas: Finally, sum up the areas of all the sections to obtain the total surface area of the outline of Africa.

It's important to note that the accuracy of the measurement will depend on the precision of the map, the quality of the digitization process, and the accuracy of the geographic coordinate data used in area calculations.

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Answer:

\(\huge\boxed{\sf 10 \ m/s \ west}\)

Explanation:

Displacement = d = 120 m

Time = t = 12 s

Velocity = v = ?

v = d/t

Put the given data in the above formula.

v = 120/12

Since, the dog is running west so velocity will also be in the west direction.

\(\rule[225]{225}{2}\)

Answer:

A. the time of fire is 15 seconds, and the angle of fire is approximately 23.794° above the horizontal

B. The angle of fire is increased to approximately 35.4126° above the horizontal

Explanation:

A. The height of the bridge, h = 70 m

The speed with of the shell, v₀ = 100 m/s

The location of the speedboat = 3000 m

The direction of the speedboat = 26 m/s

The acceleration of the speedboat, a = 11 m/s²

Let t represent the time of firing the shells, and let x represent the distance of the speedboat from the bridge, and let θ, represent the angle to fire with, we have;

For the speedboat, t = x/(100 × cos(θ))

We note that the time the shell can travel the 3,000 m = 30 seconds

Therefore an adequate time to fire is, t = 15 seconds

The distance the speedboat covers in 15 seconds is given as follows;

s = u·t + 1/2·a·t²

s = 26 × 15 + 1/2 × 11 × 15² = 1627.5 m

At the point the speedboat had traveled 1,627.5 m, the distance of the speedboat, x is then 3000 - 1,627.5 = 1,372.5 m from the bridge, the angle of fire is given from the following formula;

t = x/(100 × cos(θ))

15 = 1,372.5/(100 × cos(θ))

cos(θ) = 1,372.5/(15 × 100) = 0.915

θ = cos⁻¹(0.915) ≈ 23.794°

The angle of fire, θ ≈ 23.794° above the horizontal in the direction of the speedboat

B. Given that a 10 m/s wind is blowing towards East, we have;

The horizontal velocity towards East = 10 + v₀ × cos(θ)

The angle of firing is therefore, given as follows;

15 = 1,3725.5/(10 + 100 × cos(θ))

(10 + 100 × cos(θ)) = 1,3725.5/15

100 × cos(θ) = 1,372.5/15 - 10

cos(θ) = (1,372.5/15 - 10)/100 = 0.815

θ = cos⁻¹(0.815) ≈ 35.4126°

Therefore, the angle of fire, θ, will be increased to approximately 35.4126° above the horizontal in the remote controlled speedboat direction.

Answer:

When farm animals eat the grass on land until there is almost no ground cover, it is called overgrazing

Answer:

Its called over grazing

Explanation:

Answer:

no we can send rovers into space to explore i am reading the martian but this is my opinion it depends on what nasa decides

Explanation:

Answer:

Fp = 45 N

VMR = 2

VMI = 2

Efficiency = 100%

Explanation:

English Translation

In a 6m bar that is used as a lever, the fulcrum is placed 2m away from the right end, as shown in the figure. At that same end it is required to support a load of 90N. Neglecting lever weight, determined Fp, VMI, VMR and system efficiency

Solution

With the diagram not massively needed to solve this question.

Although, the load of 90 N is placed at the right end of the bar, the fulcrum is placed 2 m from that right end and the balancing force or effort is placed at the extreme most left end of the 6 m bar.

Taking moment about the fulcrum,

The sum of clockwise moments must balance the sum of anti-clockwise moments.

(Load) × (Distance of load from the fulcrum) = (Balancing force) × (Distance of balancing force from fulcrum)

Load = L = 90 N

Distance of load from the fulcrum = 2 m

Balancing force or Effort = Fp = ?

Distance of balancing force from fulcrum = 6 - 2 = 4 m

90 × 2 = Fp × 4

Fp = (180/4) = 45 N

The mechanical advantages are them given as

VMR = (Load)/(Effort) = (90/45) = 2

VMI = (Distance of Effort from the fulcrum)/(Distance of Load from fulcrum) = (4/2) = 2

Efficiency is then given as the VMR divided by VMI in percentage terms

Efficiency = 100% × (VMR/VMI)

Efficiency = 100% × (2/2) = 100%

Hope this Helps!!!

The following will decrease its frequency of oscillation The period is reduced to one-half of what it was.

Mass also affects the oscillation period. For example, a stiff spring with constant mass will oscillate for a short period, while increasing mass will oscillate for a long period. Using stiffer springs increases the frequency of the vibrating system.

Adding mass to a system lowers its resonant frequency. More mass means more inertia so you get more periods and this is also affected by the spring constant. The greater the spring constant the greater the force of the spring and thus the shorter the time.

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Answer:

Q. 1 - your mass will vary from planet to planet meaning it can either decrease or increase depending on the gravitational pull of the planet

Q. 2 - jupiter since it has the highest gravitational pull

Q. 3 - moon since its gravitational pull is the least but since the moon isn't a planet it would be mercury

Q. 4 - uranus has the closest gravitational pull than of earth

Q. 5 - here's my version you can write your own if u want to

Ever since I moved to saturn I've always felt bit more heavier than before it felt like my weight had significantly increased I felt a few more kgs heavier I couldn't do much since I could only stay there for a day

That's about it

At 30 degrees Celsius, a saturated solution of KClO3 will contain approximately 24 grams.

Solution: Plagiarism is the act of taking someone else's work or ideas and passing them off as your own. It is an unethical practice and is considered an academic offense. To avoid plagiarism, it is important to properly cite any sources that are used, including quotes, facts, images, and any other type of borrowed material. Additionally, it is important to give credit to the original authors of any ideas or works that are used. It is also recommended to paraphrase or re-word any material that is borrowed, so that it is not presented in the same exact form as the original. By following these steps, you can ensure that your work is completely plagiarism-free.

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According to the Newton's law of universal gravitation 2.4, the force between any more than two or three types of heavier mass which really involves with mass falling to the ground is proved by the distance, the mass's rotational speed and the rotating direction. It happens the changes in space and time, and also in the diameter of it's own mass.

Answer:

15 m

Explanation:

We'll begin by calculating the speed of the wave. This can be obtained as follow:

Time = 5 s

Distance = 15 m

Speed =?

Speed = distance / time

Speed = 15 / 5

Speed = 3 m/s

Finally, we shall determine the distance between the crests of the wave. This can be obtained as follow:

Speed (v) = 3 m/s

Frequency (f) = 0.2 Hz

Distance between the crest (λ) =?

v = λf

3 = λ × 0.2

Divide both side by 0.2

λ = 3 / 0.2

λ = 15 m

Therefore, the distance between the crests of the wave is 15 m

Answer:

4.96×10¯¹⁰ N

Explanation:

The following data were obtained from the question:

Mass 1 (M1) = 300 Kg

Mass 2 (M2) = 300 Kg

Separating distance (r) = 110 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Gravitational force (F) =?

The gravitational force between the two goal posts can be obtained as follow:

F = GM1M2 / r²

F = 6.67×10¯¹¹ × 300 × 300 / 110²

F = 6.003×10¯⁶ / 12100

F = 4.96×10¯¹⁰ N

Therefore the gravitational force between the two goal posts is 4.96×10¯¹⁰ N

The molar specific heat of the mixture at constant volume, when one mole of a monoatomic gas is mixed with three moles of a diatomic gas, is 2.25r. The correct option is b.

The molar specific heat at constant volume (Cv) is a measure of the amount of heat required to raise the temperature of one mole of a substance by one degree Celsius while keeping the volume constant.

For a monoatomic gas, the molar specific heat at constant volume is given by Cv = (3/2)R, where R is the molar gas constant.

For a diatomic gas, the molar specific heat at constant volume is given by Cv = (5/2)R.

When one mole of a monoatomic gas is mixed with three moles of a diatomic gas, the total moles of gas in the mixture is four. The molar specific heat of the mixture at constant volume can be calculated by taking the weighted average of the molar specific heats of the individual gases, based on their respective mole ratios.

In this case, the mixture consists of one mole of the monoatomic gas and three moles of the diatomic gas, giving a mole ratio of 1:3. Using the weighted average formula, the molar specific heat of the mixture is calculated as:

Cv_mixture = (1/4) × (Cv_monoatomic) + (3/4) × (Cv_diatomic)

= (1/4) × (3/2)R + (3/4) × (5/2)R

= (3/8)R + (15/8)R

= (18/8)R

= 2.25R

Therefore, the molar specific heat of the mixture at constant volume is 2.25R. The correct option is b.

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We can solve this problem by applying conservation of momentum and conservation of kinetic energy.

(a) Before the collision, the momentum is given by:

p = mv = (2.00 g)(8.60 m/s) = 17.2 g m/s

After the collision, the total momentum is still conserved and can be expressed as:

p = mv₁ + mv₂

where v₁ and v₂ are the velocities of the two particles after the collision. Since the collision is perfectly elastic, we know that the kinetic energy is also conserved:

(1/2)mv₁² + (1/2)mv₂² = (1/2)mv²

where v is the velocity of the 2.00-g particle before the collision.

Solving these equations simultaneously, we can find the velocities of the two particles after the collision:

v₁ = (m₁ - m₂)/(m₁ + m₂) * v + 2m₂/(m₁ + m₂) * 8.60 m/s = 2.00 m/s (in the positive direction)

v₂ = 2m₁/(m₁ + m₂) * v - (m₁ - m₂)/(m₁ + m₂) * 8.60 m/s = 6.60 m/s (in the positive direction)

Therefore, the velocity of the 2.00-g particle after the collision is 2.00 m/s in the positive direction, and the velocity of the 1.00-g particle after the collision is 6.60 m/s in the positive direction.

(b) Using the same approach as in part (a), we can find the velocities of the two particles after the collision:

v₁ = (m₁ - m₂)/(m₁ + m₂) * v + 2m₂/(m₁ - m₂) * 8.60 m/s = 0.344 m/s (in the positive direction)

v₂ = 2m₁/(m₁ + m₂) * v - (m₁ - m₂)/(m₁ + m₂) * 8.60 m/s = 1.716 m/s (in the positive direction)

Therefore, the velocity of the 2.00-g particle after the collision is 0.344 m/s in the positive direction, and the velocity of the 10.0-g particle after the collision is 1.716 m/s in the positive direction.

(c) The kinetic energy of the incident 2.00-g particle is given by:

KE = (1/2)mv² = (1/2)(2.00 g)(8.60 m/s)² = 73.96 mJ

In part (a), the kinetic energy is conserved, so the final kinetic energy of the 2.00-g particle is also 73.96 mJ.

In part (b), the kinetic energy is not conserved since the 10.0-g particle has more mass and therefore more momentum. The final kinetic energy of the 2.00-g particle can be found using:

KE = (1/2)mv₁² = (1/2)(2.00 g)(0.344 m/s)² = 0.118 mJ

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Answer:

I'd say it's B

Sorry if I get you wrong-

1. Connect the DC motor with a potentiometer to the Arduino board, along with a temperature sensor and an IR sensor with an LED.

2. Write the necessary code to integrate all the sensors and control the motor based on the inputs.

To connect a DC motor with a potentiometer to an Arduino board, you will need to use a motor driver module that can handle the power requirements of the motor. The motor driver module allows you to control the speed and direction of the motor using the Arduino. Connect the motor to the appropriate terminals on the motor driver module and the potentiometer to an analog input pin on the Arduino. The potentiometer will act as a voltage divider, allowing you to vary the input voltage to control the motor speed.

Next, connect a temperature sensor that can measure temperatures in the range of -10 to +45 degrees Celsius. Depending on the type of temperature sensor you are using, you may need to follow specific wiring instructions provided by the manufacturer. Connect the temperature sensor to the appropriate digital or analog input pin on the Arduino board.

Lastly, connect an IR sensor with an LED to detect motor overspeed. The IR sensor can be used to measure the rotational speed of the motor by detecting interruptions in the infrared beam caused by the rotating motor shaft. If the motor speed exceeds the threshold of 25,000 rpm, the IR sensor will trigger an output to activate the LED as a signal.

To make all the sensors work together, you will need to write code using the Arduino programming language. Use appropriate libraries and functions to read the sensor values and implement the desired logic for motor control and overspeed detection. You can define temperature thresholds and motor speed limits in the code and take appropriate actions based on the sensor readings.

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Answer:

22

Explanation:

Answer:

The net force of engine on total mass of train is 35000 N

The net acceleration is 1.944 m/s²

I

Answer:

25N

Explanation:

The force the head of the nail is doing on the hammer is 25N. This is based on the newton's third of law of motion.

It states that "action and reaction are equal but opposite in direction".

A body exerting a force of 25N on another will get a reaction force of an equal but negative magnitude of force in the opposite direction.

Answer:

The cells in the spores start differentiate into different cells once it is on the ground

At the time of the summer solstice, the noontime altitude of the sun is at its highest point, around 90°.

Altitude is the height above sea level. It is typically measured in either metres or feet. In aviation, altitude can also refer to the vertical distance between an aircraft and a certain reference point on the ground. Altitude can be used to determine the air pressure, temperature, and density of the air. Altitude can also be used to calculate the distance a plane can travel without refueling. Altitude can play an important role in the weather of an area, as air pressure and temperature tend to decrease with altitude. Altitude can also affect the type of vegetation found in an area. In mountain regions, the altitude can have a dramatic effect on the climate, creating distinct areas of vegetation and wildlife. Altitude can also affect the types of crops that can be grown in an area, depending on the air pressure, temperature, and precipitation.

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Answer:

Earth's larger mass results in a larger acceleration due to gravity as compared to the moon. In other words, you weigh more on Earth; you would weigh less on the moon. For instance, if you take a 10 kg bowling ball to the moon, it would still have a mass of 10 kg.

Explanation:

Hope this helps ^_^

~ KisamesAbs

Answer:

Math & Science

Explanation:

You said so

Answer:

i hope u get it right

Explanation:

The correct option for the question "What is the stepper motor?" would be (a) DC motor.

A stepper motor is a type of DC motor that rotates in small, precise steps in response to electrical pulses from a control unit.

Therefore, the correct option for the question "What is the stepper motor?" would be (a) DC motor.

The rotation angle of the stepper motor is proportional to the number of input pulses provided to the motor.

This makes stepper motors useful in situations where precise motion control is required, such as in robotics, CNC machines, and 3D printers.

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Answer:

344.8 m/s

Explanation:

Looking for speed of sound  = meters / sec

       2 meters / .0058 seconds = 344.8 m/s

The velocity of the sound wave is 344.8 meter/second.

A sound is a vibration that travels as a mechanical wave across a medium. It can spread through a solid, a liquid, or a gas as the medium. Solids carry sound the quickest, liquids somewhat more slowly, and gases the least slowly.

According to physics, sound is described as a vibration that travels through a material like a gas, liquid, or solid as an audible wave of pressure.

Given parameters:

The microphones are held 2.0 m apart.

it took the sound 0.0058 seconds to travel from one microphone to the other.

Hence,  the velocity of the sound wave is = distance travelled/time taken

= 2.0 meter / 0.0058 second

= 344.8276 meter/second.

Hence, the velocity of the sound wave is 344.8 meter/second ( after rounding  answer to one decimal place.).

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