The radius of the copper cable is approximately 0.004 m.
The resistance of the copper cable can be calculated using Ohm's law: R = V/I, where V is the potential difference and I is the current. Thus, R = (1.6 x 10^-2 V) / (1200 A) = 1.33 x 10^-5 ohms.
The resistance of a cylindrical conductor is given by R = (ρL) / A, where ρ is the resistivity of the material, L is the length of the conductor, and A is its cross-sectional area. Solving for the area, we get A = (ρL) / R.
Assuming the cable is made of pure copper with a resistivity of 1.68 x 10^-8 ohm-meters, and using the length of the two points on the cable, which is 0.24 m, we can calculate the area of the cross-section of the cable. A = (1.68 x 10^-8 ohm-meters x 0.24 m) / (1.33 x 10^-5 ohms) = 0.0000757 m^2.
Finally, we can solve for the radius using the formula for the area of a circle, A = πr^2. The radius of the cable is approximately 0.004 m.
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When the mass of an object decreases, the force of gravity - Remains Unchanged - Decreases - increases - Becomes irregular
Answer:
Decreases
Explanation More mass=More gravitational pull
Less mass=Less gravitational pull
Hope this helps
Answer:
decreses
Explanation:
A 10,300 kg railroad car traveling at a velocity of 19 m/s strikes a second boxcar at rest. If the two cars stick together and move off with a velocity of 6 m/s, what is the mass of the second car?
The mass of the second box car from the calculation is 22317 Kg.
What is the mass of the second car?We have to note that we can be able to obtain the momentum as the product of the mass and the velocity of the object that is to be studied. In the case of the cars that we have here;
The momentum before Collison = Momentum after collision
We would then have from the question;
(10300 * 19) + (M * 0) = (10300 + M) * 6
Let the mass of the second box car be M
Then;
195700 = 61800 + 6M
M = 22317 Kg
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Now our wavelength is getting longer because the waves are stretching out. This make the _________ lower as well as the pitch we hear.
Now our wavelength is getting longer because the waves are stretching out. This makes the 1. Frequency is lower as well as the pitch we hear.
Wavelength is the gap among equal factors (adjacent crests) in the adjacent cycles of a waveform sign propagated in the area or alongside a twine. In wi-fi systems, this duration is generally laid out in meters (m), centimeters (cm), or millimeters (mm).
Equation of the wavelength, we will tell that the wavelength of a wave is inversely proportional to its frequency, i.e., because the frequency of a wave increases, its wavelength decreases.
A better-frequency sound has a better pitch, and a decreased-frequency sound has a lower pitch. In discern 10.2 sound A has a better pitch than sound B. for example, the chirp of a bird would have an excessive pitch, but the roar of a lion could have a low pitch. The human ear can discover a huge variety of frequencies.
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Disclaimer:- your question is incomplete, please see below for the complete question.
Now our wavelength is getting longer because the waves are stretching out. This makes the _________ lower as well as the pitch we hear.
1. Frequency
2. Loudness
3. Amplitude
. a proton is at rest at the plane boundary of a region containing a uniform vertical magnetic field. an alpha particle moving with velocity, v makes a head-on elastic collision with the proton. the mass of alpha particle is four times that of the proton. the charge of the alpha particle is twice that of the proton. immediately after the collision, both particles enter the region with the magnetic field. the alpha particle feels a magnetic force of 12 n while moving perpendicular to the direction of the magnetic field. find the magnetic force felt by the proton after the collision while moving perpendicular to the direction of the magnetic field?
According to Fleming's left-hand rule, the direction of the force is parallel to the directions of the magnetic field and current.
Here, the current is flowing upward while the magnetic field is to the right (opposite to the flow of electron). When a charge particle moves through the magnetic field, a force known as the magnetic force is exerted on the charge particle. The magnetic force acts perpendicular to the velocity at every time when a charged particle moves perpendicular to a uniform magnetic field, causing the particle to proceed on a circular path with a constant velocity v. As a result, although the direction of the velocity changes, its magnitude does not.
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When summer changes to fall, what seasonal changes do plants experience? (IGNORE HIGHLIGHTED ANSWER)
Answer:
C
Explanation:
There is a decrease in temperature and daylight and plants produce less food.
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List 3 objects that would sink in water & 3 object that would float in water :)
Answer:
items that would sink : spoon marbles rocks
Explanation:
items that would float : straw feather cotton
How much time in seconds did it take a tow truck using 125,000 W of power to pull a
car with 875,000 J of work?
Answer:
7 Seconds
Explanation:
P=W/t
t=W/P
t=875,000/125,000
t=7 seconds
"Calculate the frequency of infrared light with wavelength of 9.50 x 10-7m"
Answer:
The frequency of the infrared light is approximately 3.156 × 10¹⁴ Hz
Explanation:
Given that the wavelength of infrared light, λ = 9.50 × 10⁻⁷ m, we have;
The speed of light (which is constant), c = v × λ = 299,792,458 m
Where v = The frequency of the infrared light, we have;
v = c/λ = 299,792,458/(9.50 × 10⁻⁷) ≈ 3.156 × 10¹⁴ Hz
The frequency of the infrared light = v ≈ 3.156 × 10¹⁴ Hz.
Which of the following conclusion of the Nebular Condensation Theory plus collisions are supported by observations in our solar system? All observations of our solar system support this conclusion. Observations of our solar system do not support this conclusion. No Answers Chosen No Answers Chosen Possible answers :: Collisions between portions of material in the solar system cancel their up-and-down motions, leaving them revolving in a thin disk around the Sun. :: Planets that experienced large collisions would have their rotation directions changed. :: Objects in the far outer solar system (out past the jovians) orbited so slowly that they would have experienced few collisions, leaving behind small, solid bodies. Next
Observations in our solar system support the conclusion that collisions between portions of material in the solar system cancel their up-and-down motions, leaving them revolving in a thin disk around the Sun. Observations do not support the conclusion that objects in the far outer solar system orbited so slowly that they would have experienced few collisions, leaving behind small, solid bodies.
The Nebular Condensation Theory proposes that our solar system is formed from a rotating disk of gas and dust called the solar nebula. According to this theory, collisions between portions of material in the solar system canceled their up-and-down motions, resulting in a thin disk of material revolving around the Sun. Observations of our solar system, such as the flattened shape of the planetary orbits and the presence of a protoplanetary disk around young stars, support this conclusion.
Additionally, observations suggest that large collisions can change the rotation directions of planets. This is evident in the case of Uranus, which has an extreme axial tilt likely caused by a past collision. Other examples of planets with tilted axes or unusual rotation patterns also support this conclusion.
However, observations do not support the conclusion that objects in the far outer solar system orbited slowly enough to experience few collisions, resulting in small, solid bodies. Instead, the outer solar system is known to contain a significant population of icy objects, such as dwarf planets and comets, which have likely experienced numerous collisions throughout their history. These collisions have shaped their orbits, compositions, and sizes.
Overall, while some conclusions of the Nebular Condensation Theory plus collisions are supported by observations in our solar system, others do not find substantial evidence in favor.
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Which component of a galaxy consists of tiny particles that look smoky or cloudy and
can be found in the space between stars?
Cosmic Dust.
Why? When stars explode, or die, they releases dust and gas.
To solve this we must be knowing each and every concept related to galaxy. Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.
What is galaxy?Galaxies are collections of stars as well as other celestial objects that are gravitationally bound. The cosmos contains and over 100 billion galaxies, each of which has stunning formations seen in photographs captured by telescopes of the far sky.
According to Samuel, a galaxy's shape is the result of continual interactions between its many components. The majority of the mass is provided by the dark matter, which uses gravity to hold everything together. Cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.
Therefore, cosmic dust of a galaxy consists of tiny particles that look smoky or cloudy and can be found in the space between stars.
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what are similar things that convex and concave have in common ?
Answer:
they are both curved surfaces
Explanation:
Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52
The solution to the equation is; x =4 and x = 10
How do you solve an equation?In most cases, the goal is to isolate the variable (usually represented by x) on one side of the equation. To do this, you can use inverse operations (e.g., adding, subtracting, multiplying, or dividing both sides of the equation by the same value) to cancel out any other terms.
If the equation contains more than one variable, you will need to repeat the above steps to solve for the other variables.
Now we have that;
(x – 3)^2 = 49
x^2 - 6x + 9 = 49
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at t=1.0s , a firecracker explodes at x=10m in reference frame s. four seconds later, a second firecracker explodes at x=22m. reference frame s′ moves in the x-direction at a speed of 5.1 m/s .
In reference frame s', the positions of the firecrackers are:
1.The first firecracker explodes at x' = 4.9 m.
2. The second firecracker explodes at x' = -3.5 m.
Based on the given information, let's analyze the events in both reference frames:
In reference frame s:
At t = 1.0 s, a firecracker explodes at x = 10 m.
Four seconds later, at t = 5.0 s, a second firecracker explodes at x = 22 m.
In reference frame s':
Since reference frame s' moves in the x-direction at a speed of 5.1 m/s relative to s, we need to consider the effects of time dilation and length contraction.
1. Time dilation:
In reference frame s', time appears dilated compared to reference frame s. This means that the time intervals observed in s' will be longer.
2. Length contraction:
In reference frame s', lengths appear contracted along the direction of motion. This means that the distances observed in s' will be shorter.
Let's calculate the events in reference frame s':
- At t' = 1.0 s (according to frame s'), the first firecracker explodes.
- Four seconds later, at t' = 5.0 s (according to frame s'), the second firecracker explodes.
To find the positions of the events in reference frame s', we need to account for the motion of the reference frame. Given that s' moves at a speed of 5.1 m/s, we can calculate the positions as follows:
- At t' = 1.0 s:
The position x' of the first firecracker in reference frame s' is:
x' = x - v * t
x' = 10 m - 5.1 m/s * 1.0 s
x' = 10 m - 5.1 m
x' = 4.9 m
- At t' = 5.0 s:
The position x' of the second firecracker in reference frame s' is:
x' = x - v * t
x' = 22 m - 5.1 m/s * 5.0 s
x' = 22 m - 25.5 m
x' = -3.5 m
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if a wave has a velocity of 200 m/s and a wavelength of 4 m what is the frequency of the wave?
a proton follows the path shown in (figure 1). its initial speed is v0 = 2.8×106 m/s.
The proton's speed as it passes through point P is 1.66×10⁶ m/s.
The proton's speed at point P can be determined by the equation:
KE = PE + ( mv²/2 )
where,
KE= kinetic energy
PE = potential energy
m = mass of the proton
v = speed of the proton.
Given
Proton's initial speed is v₀ = 2.8×10⁶ m/s
By putting the values in the question the solution is as follows so as the Proton's speed at point P can be calculated as:
v = √(2KE/m)
= √(2 ×2.8 × 10⁶ m/s² / 1.67 × 10⁻²⁷ kg)
= 1.66 × 10⁶ m/s
Therefore, the proton's speed as it passes through point P is 1.66×10⁶ m/s.
Your question is incomplete most probably your full question was
A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 2.8×106 m/s.What is the proton's speed as it passes through point P?Express your answer to two significant figures and include the appropriate units.
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the deposits on a properly burning spark plug should be ____.
The deposits on a properly burning spark plug should be very little or none. A spark plug works as a sensor in an engine and the deposits indicate the overall health of the engine.
Deposits on a spark plug are often black, brown, or greyish in color. When the deposits are more, it may indicate that the engine is not running as efficiently as it should or that it has some problem causing the engine to misfire. If the engine is not running efficiently or is not burning fuel, it can cause the spark plug deposits to build up quickly. Therefore, it is important to keep the spark plugs clean and free from excessive deposits to ensure optimal engine performance.
The deposits on a properly burning spark plug should be very little or none. A spark plug works as a sensor in an engine and the deposits indicate the overall health of the engine.
When the spark plug is functioning properly, it burns off any fuel or oil that comes into contact with it during the combustion process. This results in very little or no deposit buildup on the spark plug. However, if the engine is not running efficiently, such as when it is misfiring or not burning fuel properly, it can cause the spark plug deposits to build up quickly.There are several types of deposits that can accumulate on a spark plug. Carbon deposits are typically black in color and are caused by incomplete combustion of fuel. Oil deposits, on the other hand, are typically brown or greyish in color and are caused by worn piston rings or valve seals, which allow oil to seep into the combustion chamber and burn with the fuel. Deposits can also indicate that the engine is running too hot, which can be caused by a malfunctioning cooling system or a lean air-fuel mixture.
A properly burning spark plug should have very little or no deposits. Excessive deposits can indicate that the engine is not running efficiently and may require maintenance or repair. It is important to keep the spark plugs clean and free from excessive deposits to ensure optimal engine performance.
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true/false. straighterline meissner's corpuscles sense deep pressure.
False. Meissner's corpuscles do not sense deep pressure.
Meissner's corpuscles, also known as tactile corpuscles, are specialized sensory receptors located in the dermal papillae of the skin, particularly in areas with high tactile sensitivity such as the fingertips, palms, and soles of the feet. They are most sensitive to light touch, fluttering sensations, and fine textures. Meissner's corpuscles are especially responsive to low-frequency vibrations.
However, when it comes to deep pressure, other sensory receptors are responsible for detecting and relaying this information to the brain. Pacinian corpuscles, located deeper in the skin and within connective tissue, are specialized receptors that sense deep pressure and high-frequency vibrations. These receptors are larger and more responsive to mechanical forces associated with deep pressure.
In summary, Meissner's corpuscles are not involved in sensing deep pressure. They are primarily associated with light touch and fine tactile discrimination, while Pacinian corpuscles are the receptors specialized for deep pressure sensations.
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Atoms are known to form charges due to their ability to gain and lose electrons in reactions. As a result, atoms
become ions that are positively or negatively charged depending on the loss or gain of electrons. Which of the
following atoms has a charge of +2 given the number of electrons?
O A. O: 10 electrons
OB. N: 10 electrons
O C. Fe: 24 electrons
OD. Cl: 18 electrons
Answer:
C. Fe: 24 electrons
Explanation:
From the analogy given, the atom with a charge of +2 is Fe having 24 electrons.
To calculate the charges on an atom;
Number of charges = Number of protons - Number of electrons.
O: 10 electrons: 8 protons = 8 - 10 = -2
N: 10 electrons; 7 protons = 7 - 10 = -3
Cl: 18 electrons; 17 protons = 17 - 18 = -1
So;
Fe: 24 electrons and 26 protons = 26 -24 = +2
Therefore, the solution is Fe
What is the magnitude of the gravitational force between an electron and a proton separated by a distance of 1.0 x 10-10 meter?
A proton and electron separated by 1.0 x 10-10 meters exert 1.0 x 10-47N of gravitational force on each other.
What exactly is gravitational, in simple terms?The gravitational force will bring together any two mass-containing objects. The gravitational force is described as attracting because it consistently tries to draw masses together and never tries to push them apart. In reality, you and every other item in the universe are pulling toward one another.
What is the origin of gravity?
All of the mass on Earth is what creates gravity. The cumulative gravitational attraction of all of its mass exerts pressure on all of the body's mass. Your weight is determined by that. Furthermore, your weight would be lower if you were on a planet with a lower mass than Earth.
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A 7.72 kg box is sliding to the right at a constant velocity of 12:14. If the box has a force 53.14 applied to the right, what is the magnitude of the force of friction?
Type your answer...
Well, you didn't tell us what the unit of the 53.14 is. But whatever it is, the force of friction is the same 53.14 of them.
The only way the box can move with constant velocity is if the forces acting on it all add up to zero. So the force of friction to the left, holding it back, must be exactly equal to the force pushng it forward to the right.
Notice that none of this depends on the mass of the box, or WHAT the constant velocity IS. None of that information matters, or makes any difference. It's only included in the question to confuse and distract us.
A squeeze bottle squeezes when pressed. It regains its shape when pressed .It regains its shape when the pressure from your hand is withdrawn. What may happen if the squeeze bottle is pressed to take the sauce out and then immediately corked tightly? Will it regain its shape? If not, Why?
Answer:
The squeeze will not regain its shape
Explanation:
The squeeze bottle will not regain its shape.
This is because the atmospheric pressure compresses the squeeze bottle. Since the pressure in the squeeze bottle is now not equal to the atmospheric pressure since it has been corked tightly, its internal pressure cannot balance out the atmospheric pressure and thus cancel its effect.
So, the squeeze bottle does not regain its shape due to this imbalance of pressure.
I NEED HEL PLEASE THANKS!
What will happen to the pitch of a sound as that sound’s source approaches an observer? Explain why this happens, based on what you have learned about wave properties.
Answer:
The pitch increases
Explanation:
When the source of the sound moves, the medium becomes more compressed in front of the source, and less compressed behind it. So to an observer being approached by the sound's source, the pitch sounds higher.
This is known as the Doppler effect.
Which of the following is not important when shopping for a credit card?
a. the costs of the card
b. the features of the card
c. what the card looks like
d. how you plan to use the card
Answer:
C
Explanation:
You don't want to buy a 1000 dollar credit card.
The features are useful, like the little sync feature to automatically pay is awesome.
The plan of use for the card is important
the card aesthetic doesn't affect the card in any way, just your personal preference
A spring has a spring constant of 330 N/m.
how far is the spring compressed if 150 N force is used ?
0.45 m far is the spring compressed if 150 N force is used in a spring has a spring constant of 330 N/m
Define spring constant
The stiffness of the spring is quantified by the spring constant, k. For various materials and springs, it varies. The spring becomes stiffer and more challenging to stretch as the spring constant increases.
It is used to assess the stability or instability of a spring and, consequently, the system it is meant to serve. Its expression is given by the formula k = - F/x, which reworks Hooke's Law. where x is the displacement caused by the spring, given in N/m, and k is the spring constant.
Force = spring constant * extension
150 = 330 * extension
Extension = 150/330
Extension = 0.45 m
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How does newton’s third law of motion relate to a catapult?
PLEASE ANSWER ASAP. WILL GIVE BRAINLIEST
Answer: the force when the catapult swings has the same force as it does when coming down
Explanation:
for every reaction there is an equal opposite reaction
I need help with this question and please show the whole work
and do it asap
If a star displays \( 0.0190 \) arcseconds of parallax, then long would it take to travel to that star if traveling at half the speed of light?
The first step is to convert the parallax angle of the star to distance. We can use the formula: parallax angle in arc seconds = (distance to star in parsecs)^-1 We can rearrange this equation to isolate distance: d = (parallax angle)^-1 Therefore, the distance to the star in parsecs is:
d = (0.0190 arcseconds)^-1 = 52.6 parsecs Next, we need to find the actual distance in meters. One parsec is equivalent to 3.09 × 10^16 meters. Therefore, the distance to the star in meters is: distance = (52.6 parsecs)(3.09 × 10^16 meters/parsec) = 1.63 × 10^18 meters Now, we can use the formula for time: d = vt Solving for time: t = d/v We are told to travel at half the speed of light, which is v = 0.5c, where c is the speed of light.
Therefore, the time to travel to the star is: t = (1.63 × 10^18 meters)/(0.5c) Using the speed of light, c = 3.00 × 10^8 m/s, we get: t = (1.63 × 10^18 meters)/(0.5 × 3.00 × 10^8 m/s)t ≈ 10.9 years Therefore, it would take about 10.9 years to travel to the star if traveling at half the speed of light.
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Hydropower is the production of electrical energy through the use of
A. gravitational force
B. stored energy
C. water flowing upwards
D. water resistance
Answer:
gravitational force .. .. .
Explanation:
hope it helps^o^Crate is being pushed a constant velocity. What forces are being used?
A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist's acceleration?Felipe drives his car at a velocity of 28 m/s. He applies the brake, which slows the vehicle down at a rate of 6.4 m/s2 and causes it to slow to a stop. How long does it take for the car to stop? Round your answer to the nearest tenth.
Answer:
a) a = - 0.0833 m / s², b) t = 4.4 s
Explanation:
a) this is a kinematics exercise where the acceleration is along the inclined plane
v = v₀ - a t
a = v₀ - v / t
a = 3 - 8/60
a = - 0.0833 m / s²
b) in this case the final velocity is zero
v = v₀ - a t
0 = v₀ - at
t = v₀ / a
t = 28 / 6.4
t = 4.375 s
t = 4.4 s
a hot tub has 4.38x10³ kg of water in it. each water molecule has a mass of 2.98x10-²⁴. how many water molecules are in the hot tub?
The number of water molecules in the hot tub is 1.47×10²⁷ molecules
Data obtained from the questionThe following data were obtained from the question:
Mass of water = 4.38×10³ KgMass of one molecule = 2.98×10⁻²⁴ KgNumber of molecules =?How to determine the number of moleculesThe number of water molecules in the hot tub can be obtained as follow
Number of molecules = Mass of water / mass of one molcule
Number of molecules = 4.38×10³ / 2.98×10⁻²⁴
Number of molecules = 1.47×10²⁷ molecules
Thus, number of molecules in the hot tub 1.47×10²⁷ molecules
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