a current of 6.83 a in a solenoid of length 10.6 cm creates a 0.371 t magnetic field at the center of the solenoid. how many turns does this solenoid contain

Answer:

ok

Explanation:

Paine's Rejection of British Protection.

Upakar Thapa

What does Paine say about the argument that Britain has defended the colonies in the past? A. That the colonists should have protected Britain B. That the colonists never really needed the help OC. That Britain only did so out of self-interest D. That Britain created conflict so its protection seemed needed

The reference to "Paine" likely refers to Thomas Paine, a political activist and writer who was a key figure in the American Revolution. In his influential pamphlet "Common Sense," which was published in 1776, Paine argued for American independence from Britain.

Regarding the argument that Britain has defended the colonies in the past, Paine argues that this is not a valid reason for the colonies to remain under British rule. He asserts that Britain's protection of the colonies was motivated by its own self-interest, rather than a genuine concern for the well-being of the colonists.

Paine argues that Britain has actually done more harm than good for the colonies, pointing to the various restrictions and regulations that the British government has placed on the colonies. He also asserts that the colonies are perfectly capable of defending themselves, and that they should not rely on Britain for protection.

Overall, Paine's argument is that the colonies should seek independence from Britain in order to secure their own freedom and self-determination.

Upakar Thapa

The First Law of Thermodynamics is generally referred to as _____.

First Law of Motion

Joule's Law E = IR2

Law of Conservation of Matter and Energy

Universal Gravitation

The First Law of Thermodynamics is generally referred to as the "Law of Conservation of Matter and Energy."

Upakar Thapa

Consider a gas at STP in a container of 22.4 L. If you apply the ideal gas law, what is the approximate value of n?

a. 1

b. 8.31

c. 224

d. 0.5

At STP (Standard Temperature and Pressure), the conditions are defined as 1 atmosphere of pressure and 0°C (273.15 K) of temperature.

Using the ideal gas law, we have:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

At STP, the pressure is 1 atm, the volume is 22.4 L, and the temperature is 273.15 K.

Substituting these values into the ideal gas law, we get:

(1 atm) (22.4 L) = n (8.31 J/mol·K) (273.15 K)

Simplifying, we get:

n = (1 atm) (22.4 L) / (8.31 J/mol·K) (273.15 K)

n = 1

Therefore, the approximate value of n is a. 1.

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Orchids have six petals arranged in a 3-2-1 arrangement.

Orchids have three sepals (one dorsal and two lateral) and three petals, but usually the middle petal, the labial, is distinct from the other petals. In most orchids, the flower rotates 180° during growth, so the lip is the lowest of the petals and points upwards. There are three sepals that are the outer petals. This is what you see when you look at an unopened bud. He also has three petals, but one of his orchid petals is specialized for the lip. Orchids always have three petals. Two are "normal" and the third is a highly specialized structure called a lip.

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The density of the hot air inside the balloon is 0.913 kg/\(m^{3}\).

To solve this problem, we need to use the principle of buoyancy. The weight of the balloon and the weight it can lift are equal to the weight of the air displaced by the balloon. The density of the hot air inside the balloon will determine how much air is displaced.

First, we need to find the weight of the air displaced by the balloon:

Weight of air displaced = volume of balloon x density of air outside balloon x gravity

Weight of air displaced = 2051 \(m^{3}\) x 1.205 kg/\(m^{3}\) x 9.81 m/\(s^{2}\).

Weight of air displaced = 24,043.28 N

Next, we need to subtract the weight of the balloon (5028 N) from the weight of the air displaced to find the weight of the hot air inside the balloon:

Weight of hot air = weight of air displaced - weight of balloon

Weight of hot air = 24,043.28 N - 5028 N

Weight of hot air = 18,015.28 N

Finally, we can use the formula for density to find the density of the hot air inside the balloon:

Density = mass/volume

Density = weight of hot air/gravity x volume of balloon

Density = 18,015.28 N/(9.81 m/\(s^{2}\) x 2051 \(m^{3}\))

Density = 0.913 kg/m3

Therefore, the density of the hot air inside the balloon is 0.913 kg/\(m^{3}\).

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When polychromatic visible light shines through a diffraction grating, the central maximum will be visible as a mixture of the wavelengths present. option c

A diffraction grating is an optical element that separates white light into its component colors using an array of equally spaced, parallel slits.

A beam of light is diffracted by the grating to produce a series of spectra, the brightest of which is called the central maximum, with the other spectra organized around it. The angles and intensity of the spectra are determined by the wavelength of the light being diffracted, as well as the spacing and number of slits on the grating. Hence, option c is correct.

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Main answer:The mass of Carmelita is 27 kg Let Carmelita's mass be m, Ricado's mass is 81 kg and the total mass of canoe and occupants be M = 81 kg + m + 30 kg.

The initial moment of inertia I1 about an axis in the center of mass of the canoe and occupants isI1 = 1/12 * M * L²where L = 3.0 m is the distance between seats. After exchanging seats, the occupants and canoe have moved a distance x = 0.20 m relative to the log. Therefore, the final moment of inertia I2 isI2 = I1 + M * x²where M is the total mass of the canoe and occupants. The exchange of seats has not changed the center of mass of the canoe and occupants. Therefore, the final moment of inertia I2 must be equal toI2 = 1/12 * M * L² + m * (L/2)² + (81 kg) * (L/2)²

The first term represents the moment of inertia of the canoe and occupants about the center of mass, the second term represents the moment of inertia of Carmelita and the third term represents the moment of inertia of Ricado. Equating I1 and I2 gives1/12 * M * L² = 1/4 * m * L² + 1/4 * (81 kg) * L² + 1/12 * M * x²Substituting L = 3.0 m, M = 111 kg and x = 0.20 m gives27 m = mTherefore, the mass of Carmelita is 27 kg.

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The equivalent resistance between points A and B in the diagram is 22 Ω

We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:

1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₜ = 1/6 + 1/6 + 1/6

1/Rₜ = 3/6

1/Rₜ = 1/2

Rₜ = 2 Ω

Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:

R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁

R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2

R = 22Ω

Thus, we can conclude that the equivalent resistance is 22 Ω

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An inflated basketball is left outside on a hot day, causing the temperature of the gas to increase. Option D. The pressure of the gas increases, and the volume of the gas increases would happen to the gas inside of the basketball.

Where P stands for pressure, V is volume, N is the number of molecules in the sample, k is Boltzmann's constant, and T is absolute temperature typically expressed in kelvins.

The pressure on a system will increase by increasing the temperature, decreasing the volume, and pumping more gas.'

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To find the work done by the tension force on the elevator, we can use the formula: work = force x distance x cos(theta)
where theta is the angle between the force and the direction of motion (which is 0 degrees in this case since the tension force is acting in the same direction as the motion.

The work done by the tension force is:
work = (2.58 ✕ 10⁴ N) x (1.70 m) x cos(0) = 4.38 ✕ 10⁴ J
Therefore, the work done by the tension force on the elevator is 4.38 ✕ 10⁴ J.
(b) To find the work done by the force of gravity on the elevator, we can use the formula:
work = force x distance x cos(theta)
where theta is the angle between the force and the direction of motion (which is 180 degrees in this case since the force of gravity is acting in the opposite direction of the motion).
The force of gravity on the elevator can be calculated using the formula:
force of gravity = mass x gravitational acceleration
where gravitational acceleration is approximately 9.81 m/s².
So, the force of gravity on the elevator is:
force of gravity = (2.40 ✕ 10³ kg) x (9.81 m/s²) = 2.35 ✕ 10⁴ N
Now, we can use the work formula to find the work done by the force of gravity:
work = (2.35 ✕ 10⁴ N) x (1.70 m) x cos(180) = -7.97 ✕ 10⁴ J
Therefore, the work done by the force of gravity on the elevator is -7.97 ✕ 10⁴ J.

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D. 36 in Kr

Let's analyze all the elements in Option

By looking at all the given options we can clearly see that Krypton has the highest number of electrons as compared to the given options so It is the answer. Also with the highest mass, in the given four options.

It can be easily seen in options as the Number of electrons and mass is already written in options.

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Answer:

i cant see it just put the question

Explanation:

The S-P interval, also known as the S-wave to P-wave interval, can be found on a seismograph by measuring the time difference between the arrival of the S-wave and P-wave.

Because it moves more slowly than the P-wave (primary wave), the S-wave (secondary wave) reaches the seismograph after the P-wave. How to calculate the S-P interval:

Find the P-wave's arrival on the seismogram. Usually, this is the first noticeable upward deflection.

Find the S-wave's arrival on the seismogram. After the P-wave, this is often the second substantial upward deflection.

Calculate the difference in seconds between the S-wave and P-wave's times of arrival. The S-P interval is this temporal difference.

Thus, the S-P interval can be found by measuring the time difference between the arrival of the S-wave and P-wave on a seismograph.

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Answer:

34.55 m/s

Explanation:

Due to the lack of information on the frictional force acting on the book, we cannot determine the amount of work done by friction on the book during its displacement to the left by 3.0 m.

In order to find out the work done on a book by friction during a displacement of 3.0 m to the left, we first need to understand the concept of work and friction. Work is defined as the product of the force acting on an object and the distance through which the object is displaced in the direction of the force.

Whereas, friction is the force that opposes the motion of an object due to the contact between the surfaces of the object and its surroundings.

Now, let's assume that a book is placed on a surface and it experiences a frictional force while it is displaced to the left by 3.0 m. Here, we know that the work done by friction is given by the product of the frictional force and the displacement of the book.

However, we need to know the value of the frictional force in order to determine the work done by friction. Due to the lack of information on the frictional force acting on the book, we cannot determine the amount of work done by friction on the book during its displacement to the left by 3.0 m.

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Answer:

α=atr

the relationship between linear accelaration and linear accelaration is proportional. The greater the angular acceleration is, the larger the linear (tangential) acceleration.

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

                 \(P=\frac{F}{A}\)

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

             \(P=1atm=1.013*10^5Pascals\)

            \(F=mg=P*A=1.013*10^5*4.5=4.56*10^5N\)

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

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Maps can convey a lot of different types of information. They can tell you where you are or they can tell you something about a location. Earth scientists often use maps that have coordinates so that they can locate themselves or the features they are interested in. Different types of maps show different things well. For example, some types of maps show the tropical areas really well but do a terrible job depicting the polar regions.

Answer:

Here is your answer

Explanation:

Given:

Given:Density of sea water (d) = 1020 kgm^{3}3

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg\begin{gathered} = \frac{10200000}{1020 \times 10} \\ \\ = 1000 \: m \\ \\ = 1 \: km.\end{gathered}=1020×1010200000=1000m=1km.

Given:Density of sea water (d) = 1020 kgm^{3}3Acceleration due to gravity (g) = 10 ms^{–2}–2To find:Depth of sea.Solution:In order to find depth of sea water first we need to find pressure of sea water.Pressure of sea water (P)= 1.02 × 10^{7}7= 102,00,000 Nm^{–2}–2We know that,P = h × d × g\therefore∴ h = P/dg\begin{gathered} = \frac{10200000}{1020 \times 10} \\ \\ = 1000 \: m \\ \\ = 1 \: km.\end{gathered}=1020×1010200000=1000m=1km.Hence, depth of sea is 1 km

1). Wrap more turns of the wire around the nail.

2). Increase the electrical current through the wire. (Do this by inserting another battery in the circuit, in series with the first one.)

Answer:

98.

Explanation:

divide

The change in the kinetic energy of the cart is equal to 34875 J.

The energy which is possessed by a moving body because of its motion is known as kinetic energy. Work should be done in order to bring the change in the kinetic energy of a moving object.

The kinetic energy of a moving object can be determined from the formula mentioned below:

K.E. = ½mv²     where ‘m’ and 'v' is the mass and velocity of the object.

Given, the mass of the carriage, m = 450 Kg

The speed of the carriage, u = 18 m/s

The initial kinetic energy of the cart = (1/2) × 450 × (18)²

(K.E.)₁ = 72900 J

The final speed of the cart, v = 13 m/s

The final kinetic energy of of the cart = (1/2) × 450 × (13)²

(K.E.)₂ = 38025 J

The change in the kinetic energy of the cart = (K.E.)₂ - (K.E.)₁

Change in the kinetic energy = 72900 - 38025 = 34875 J

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The speed of the waves is dependent on the frequency and wavelength of the waves. Without knowing the frequency, we cannot accurately calculate the speed of the waves.

The speed of waves can be affected by several factors, including the density, viscosity, and elasticity of the medium through which they are traveling. In general, waves travel faster through denser and more elastic mediums, and slower through less elastic and more viscous mediums. For example, sound waves travel faster through solids than through gases because solids are denser and more elastic than gases.

Wave speed calculations have many practical applications in fields such as acoustics, optics, and telecommunications. For example, the speed of sound waves can be used to calculate the distance to an object using sonar or ultrasound technology.

The speed of light waves can be used to design optical fibers for high-speed internet and telecommunications networks. Understanding wave speed is also important in fields such as seismology.

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Answer:

Q = 1128.6 [kW] - kilowatts

Explanation:

To calculate the amount of energy required, the following expression should be used:

\(Q=m*c_{p}*(T_{f} - T_{i}) \\where:\\C_{p}=specific water heat = 4.18 [\frac{kJ}{kg*K}] \\m = mass = 15 [kg]\\T_{f}= Final temperature = 38 [C]\\T_{i}=20[C]\)

Q = 15*4.18*(38-20)

Q = 1128.6 [kW]

The statement that underscore the an advantage of the thermal properties of plastic is that plastics are easy to mold into any shape.

A plastic is a synthetic material that is made of polymers that are joined together. Many plastics are known to have a very high tensile strength and this makes them to be relevant in several applications.

The statement that underscore the an advantage of the thermal properties of plastic is that plastics are easy to mold into any shape. This explains the fact that plastic materials can be seen to occur in various shapes and sizes.

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The graph that best illustrates how the intensity of sound varies as a detector is moved further and further from a stationary source projecting sound in all directions would be an inverse square law graph. This graph would show that the intensity of sound decreases as the distance from the source increases. The intensity of sound is inversely proportional to the square of the distance from the source.

This means that if the distance from the source is doubled, the intensity of sound is decreased by a factor of four. This relationship is commonly observed in physics and engineering and is known as the inverse square law of sound propagation. This law states that the intensity of sound decreases as the distance from the source increases in a manner that is inversely proportional to the square of the distance.

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(a) The magnetic force experienced by the wire when it perpendicular is 0.01 N.

(b) The magnetic force experienced by the wire when the angle is  30⁰ is 5 x 10⁻³ N.

(c) The magnetic force experienced by the wire when it parallel is 0 N.

The magnetic force experienced by the wire is calculated by applying the following;

F = BIL x sin(θ)

where;

When the angle of inclination is perpendicular,  

F = 1 x 10⁻² x 10 x 0.1 x sin(90)

F = 0.01 N

When the angle of inclination is 30⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(30)

F = 5 x 10⁻³ N

When the wire is parallel, the angle is 0⁰,

F = BIL x sin(θ)

F = 1 x 10⁻² x 10 x 0.1 x sin(0)

F = 0 N

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To prepare 100ml of a 1.5m Kbr solution, 1.785 g of KBr is required.

Potassium bromide, also referred to as KBr, is a salt that is frequently employed as a sedative and anticonvulsant.

Kalii bromidum, tripotassium tribromide, and potassium bromide salt are some other names for potassium bromide.

The taste of the odorless potassium bromide salt, which comes in white crystals, colorless crystals, and white granular solids, is sharp, bitter, salty. The pH of aqueous KBr solutions is 7.

we can use the formula:

mass = molarity x volume x molar mass

where molar mass of KBr is 119.00 g/mol.

So,

mass = 1.5 M x 100 ml x (119.00 g/mol) / 1000 ml/L

mass = 1.785 g

Therefore, 1.785 g of KBr is required to prepare 100 ml of a 1.5 M solution.

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The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Answer:

wat

Explanation:

1.

a) Hydrogen chloride (HCl) - 1 hydrogen atom, 1 chlorine atom

b) Sulfur dioxide (SO₂) - 1 sulfur atom, 2 oxygen atoms

c) Ammonia (NH₃) - 1 nitrogen atom, 3 hydrogen atoms

d) Carbon monoxide (CO) - 1 carbon atom, 1 oxygen atom

2.

a) Hydrogen chloride (HCl) :

H

|

Cl--C--

|

H

b) Sulfur dioxide (SO₂) :

O

//

O=S

\\

O

c) Ammonia (NH₃) :

H

|

H--N--H

|

H

d) Carbon monoxide (CO) :

O

//

C=O