A county is in the shape of a rectangle that is 50 miles by 60 miles and has a population of 50,000. What is the average number of people living in each square mile of the county? Round your answer to the nearest whole number. a. 227 b. 17 c. 20 d. 14

The percent of the field goals did Samuel make will be 77.5%.

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100. The percentage therefore refers to a component per hundred. Per 100 is what the word percent means. It is represented by %.

Samuel made 31 out of 40 field goals during football practice. The percent of the field goals did Samuel make will be:

= 31 / 40 × 100

= 77.5%

The percentage is 77.5%.

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Answer:

56

Step-by-step explanation:

48 ounces would feed 6 people and if 16 oz is for two people than 8 oz is for one person. So, 48 plus 8 is 56.

The solution for the variable w in the equation s = a + lw is w = (s - a)/l.

Given the equation in the question:

s = a + lw

w = ?

To solve the equation s = a + lw for the variable w, we have to isolate w on one side of the equation.

s = a + lw

Subtract a from both sides:

s - a = a + lw - a

s - a = a - a + lw

s - a = lw

Reorder the equation:

lw = s - a

Divide both sides by the coefficient of w:

lw/l = ( s - a )/l

Simplifying, we get:

w = ( s - a )/l

Therefore, the variable w equals ( s - a )/l.

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Answer: Multiply the numerators together.

Multiply the denominators. Check to see if the product can be simplified.

Step-by-step explanation:

Answer:

-6-(-1)

Step-by-step explanation:

The patient can consume approximately 2 cans of 12 oz Coca Cola without exceeding the advised sugar limit.

To determine the number of 12 oz cans of Coca Cola the patient can consume, we need to convert the sugar limit provided by the doctor into grams and then calculate the amount of sugar in a 12 oz can of Coca Cola.

Provided:

Sugar limit: 8.5 × 10^(-2) kg

Coca Cola sugar content: 110 g/L

Volume of a 12 oz can: 12 oz (which is approximately 355 mL)

First, let's convert the sugar limit from kilograms to grams:

Sugar limit = 8.5 × 10^(-2) kg = 8.5 × 10^(-2) kg × 1000 g/kg = 85 g

Next, we need to calculate the amount of sugar in a 12 oz can of Coca Cola:

Volume of a 12 oz can = 355 mL = 355/1000 L = 0.355 L

Amount of sugar in a 12 oz can of Coca Cola = 110 g/L × 0.355 L = 39.05 g

Now, we can determine the number of cans the patient can consume by dividing the sugar limit by the amount of sugar in a can:

Number of cans = Sugar limit / Amount of sugar in a can

Number of cans = 85 g / 39.05 g ≈ 2.18

Since the number of cans cannot be fractional, the patient should limit their consumption to 2 cans of Coca Cola.

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sin (60° - 20)°

sin (40°)

Note that:

sin(A - B) = sinAcosB - cosAsinB

The given trigonometric expression is:

sin 60° cos 20° - cos 60° sin 20°

Applying the addition rule of trigonometry written above:

sin 60° cos 20° - cos 60° sin 20° = sin(60° - 20°)

This can also be written as sin (40°)

The likelihood that there are 1 man and 2 girls are selected is approximately 0.4357. We can use the following formula for the chance of an occurrence to determine the probability that one male and two female candidates are chosen:

P(event) equals (number of possible outcomes for the event) / (total number of possible outcomes) Out of a total of 25 pupils, the programme is choosing 1 male and 2 female participants. 

Using the combination formula, we can first determine the overall number of events that are possible: nCr equals n and (r! * (n-r)!) where r is the number of students being chosen, and n is the overall number of students (25). (3). Therefore, there are a total of the following outcomes: 25C3 = 25! / (3! * (25-3)!) = 25! / (3! * 22!) = 2300

Next, we need to determine how many different methods there are to choose 1 guy and 2 females. Utilizing the product law of chance, we can accomplish this: The number of methods is equal to the sum of the ways to select one man and two females. 

There are 11 methods to choose one guy out of 11, and there are 91 ways to choose two females out of 14. The overall number of options for choosing one man and two females is thus: 11 * 91 = 1001

Finally, we can enter these numbers into the likelihood of the occurrence formula as follows: P(1 man, 2 women) = 1001/2300 = 0.4357

Consequently, the likelihood that there are 1 man and 2 girls are selected is approximately 0.4357.

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Answer:

19 and 43

Step-by-step explanation:

small=n

larger=2n+5

52=2n+5+n

57=3n

19=n

Smaller=19

(19*2)+5=43

Larger=43

Answer:

After about 9 minutes.

Step-by-step explanation:

We can write an exponential function to model the decay of Herodium-100.

We are given that it decreases by half every minute.

The standard exponential function is given by:

\(f(m)=A(r)^m\)

Where A is the initial amount, r is the rate, and m is the rate (in this case, in minutes).

Mathman initially has 2000 mL of Herodium-100. Therefore, A = 2000.

And since it decreases by half every minute, r = 1/2. Thus:

\(\displaystyle f(m)=2000\Big(\frac{1}{2}\Big)^m\)

Mathman needs to rest when the Herodium-100 levels drop to 4 mL. Therefore, we can substitute 4 for f(m) and solve for m:

\(\displaystyle 4=2000\Big(\frac{1}{2}\Big)^m\)

Solve for m. Divide both sides by 2000:

\(\displaystyle \frac{4}{2000}=\frac{1}{500}=\Big(\frac{1}{2}\Big)^m\)

We can take the natural log of both sides:

\(\displaystyle \ln\Big(\frac{1}{500}\Big)=\ln\Big(\frac{1}{2}^m\Big)\)

By logarithm properties:

\(\displaystyle \ln\Big(\frac{1}{500}\Big)=m\ln\Big(\frac{1}{2}\Big)\)

Therefore:

\(\displaystyle m=\frac{\ln(1/500)}{\ln(1/2)}\approx 8.9657\approx 9\text{ minutes}\)

Mathman will have to rest and replenish after 9 minutes.

The differences disappear on later tests due to the improved mathematics education and curriculum in the United States.

The initial lag in performance of U.S. middle school students compared to their Japanese counterparts in international algebra tests can be attributed to various factors, including differences in teaching methods, curriculum, and cultural emphasis on mathematics. However, over time, the differences tend to disappear as U.S. students progress through their education and benefit from improved mathematics education and curriculum.

In recent years, the United States has made efforts to enhance its mathematics education system, implementing reforms and adopting new teaching strategies to improve student outcomes. These changes aim to provide students with a deeper understanding of mathematical concepts and problem-solving skills. As a result, U.S. students have shown improvements in their performance on later tests, narrowing the gap with their Japanese peers.

While U.S. middle school students may initially lag behind their Japanese counterparts in international algebra tests, the differences tend to disappear on later tests due to the ongoing efforts to enhance mathematics education in the United States. Continuous improvements in curriculum, teaching methods, and student support contribute to closing the gap and ensuring that U.S. students can compete globally in mathematics proficiency.

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Answer:

C and d

Step-by-step explanation:

Answer:

Here is your 2 answers.

Step-by-step explanation:

First question: -2+3y=9

step 1 simplify first so now it's 3y-2

step 2 add both sides by 2 now its 3y=11

step 3 divide both sides by 3 so on the left both sides should cross out leaving only y=11/3 so this is your first answer

Second question:

I attach the link this question acquires a graph to plot I believe so here is the answer for the second one hope I help please mark brainliest if I did! <3

Answer:

Whatever makes the statement true.

Step-by-step explanation:

Example:

19=3x+1

Subtract 1 from both sides.

19-1=3x+1-1

18=3x

Divide both sides by 3.

18/3=(3x)/3

When x is alone on one side, the answer is on the other. In this case…

6=x

If you plug in 6 for x, you get 19.

3(x)+1=19

3(6)+1=19

3(6)=18

18+1=19

Answer: 3, 5, and 7

Step-by-step explanation:

Vertical angles, corresponding angles, and alt. ext. angles

There are 4096 functions from a set with 4 elements to a set with 8 elements.

To find the number of functions from one set to another, we use the formula:

Number of functions = (Number of elements in the codomain)Number of elements in the domain

In this case, the domain is the set with 4 elements and the codomain is the set with 8 elements. Plugging in these values into the formula, we get:

Number of functions = 84

Number of functions = 4096

Therefore, there are 4096 functions from a set with 4 elements to a set with 8 elements.

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Potential type of statistical error would be Type I statistical error.

What is statistical error?

The term "error" (also known as "statistical error") refers to the discrepancy between a value obtained through a data gathering procedure and the population's "actual" value. The data are less representative of the population the higher the inaccuracy. Both sampling error and non-sampling error can have an impact on data.

Given that:

two sided test of hypothesis is giving 0.05 level of significance.

and statistic resulting from the analysis was 1.23.

According to statistic result,

the results are not statistically significant because the p-value > 0.05.

So, Here we can say that it follows the Type I statistical error.

Hence, potential type of statistical error would be Type I statistical error.

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Answer:

452.38934 yd^3

Step-by-step explanation:

The scale of increase in the drawing to inches in the actual room is 18

A room is 15 feet long and 12 feet wide. A scale drawing of the room is 10 inches by 8 inches

1 feet = 12 inches

Initially the room's length = 15 feet = 15 x 12 = 180 inches

On scale drawing the length = 10 inches

Let the  scale of inc in the drawing to inches in the actual room be k

10 x k = 180

k = 180 / 10 = 18

Initially the room's width = 12 feet = 12 x 12 =144 inches

On scale drawing the width = 8inches

8 x k = 144

k = 18

Therefore,  the  scale of inc in the drawing to inches in the actual room is 18

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The probability that the next puck Dave grabs will be green is 1/6 or approximately 0.167.

To determine the probability of Dave grabbing a green puck on the next grab, we need to calculate the probability based on the given data.

Given:

Number of red pucks = 4

Number of orange pucks = 3

Number of yellow pucks = 1

Number of pink pucks = 2

Number of green pucks = 2

Total number of pucks = 4 + 3 + 1 + 2 + 2 = 12 pucks

The probability of grabbing a green puck can be calculated as:

Probability = Number of green pucks / Total number of pucks

Probability = 2 green pucks / 12 pucks

Probability = 1/6

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The visitor should run 1.2 miles to minimize the time it takes to reach the island.

Consider the following figure.

Let us assume that x (CD) represents the distance covered when visitor runs at a rate of 5 mph

So, the time taken by visitor would be:

t₁ = x/5

Let the distance covered 10 - x when visitor swims at a rate of 3 mph

From figure consider right triangle ABC.

Using Pythagoras theorem,

BC² = 7² + (10 - x)²

BC = \(\sqrt{49 + (10-x)^2}\)

Now the times taken by visitor when he swims at a rate of 3 mph,

t₂ =  \(\frac{ \sqrt{49 + (10-x)^2}}{3}\)

so, the total time would be:

t = t₁ + t₂  

\(t=\frac{x}{6}+\frac{ \sqrt{49 + (10-x)^2}}{3}\)

Differentiating with respect to x we get,

\(\frac{dt}{dx}=\frac{1}{6} -\frac{(10-x)}{ \sqrt{49 + (10-x)^2}}\)

consider dt/dx = 0

\(\frac{1}{6} -\frac{(10-x)}{ \sqrt{49 + (10-x)^2}}=0\)

If we solve above equation for x we get, x = 11.2 and x = 8.8

The distance the visitor should run to minimize the time would be:

10 - 8.8 = 1.2 miles

Therefore, the required distance is 1.2 miles

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Answer:

and i

Step-by-step explanation:

oop.

Answer:

c

Step-by-step explanation:

Answer:

its C bro i dont copy her/he

dont be suspiciousful

Step-by-step explanation:

ita right mark me as brainlest

Multiplication and division of regular numbers are the same as fractions and we will learn them with the multiplication and division of rational numbers worksheet.

To do the multiplication, first find the greatest common divisor of the numerator and the denominator. The factors are then grouped together so that the score equals one. Then multiply by the remaining factors. To divide, first rewrite the division as multiplication by the inverse of the denominator.

Cuemath's interactive math worksheets contain visual simulations to help your child visualize the concepts being taught, "see things as they really are, and reinforce learning from them". The Rational Numbers Multiplication and Division Worksheet follows a step-by-step learning process that helps students better understand concepts, identify errors, and eventually develop strategies for solving future problems.

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Answer:

Budget= $1,100

Step-by-step explanation:

Giving the following information:

They spent $737 on equipment and 33% of the total budget on costumes.

If they spent all their budget on equipment and costumes, then the percentage spent on equipment was 67% (100 - 33).

Then, to calculate the total budget, we need to use the following formula:

Budget= 737 / 0.67

Budget= $1,100

Answer:

\(f^{-1}\) (x) = \(\sqrt{x-5}\), \(-\sqrt{x-5}\)

Step-by-step explanation:

hope this helps! :D

have a miraculous day!! <3

Answer:

\(f^{-1}\) (x) = \(\sqrt{x-5}\) , - \(\sqrt{x-5}\)

Step-by-step explanation:

Hope this helps!!

The inequality that models the situation if Jasmine and Sammy both worked the same number of hours (h) is 50 + 7h > 20 + 10h.

The hours worked to make this true is 10 hours.

Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.

Let the number of hours be h.

Jasmine earns $10 an hour. She also received $20 in tips. This will be 20 + 10h.

Sammy earned $7 per hour but receives a bonus of $50. This will be 50 + 7h

This will be illustrated as:

50 + 7h > 20 + 10h.

10h - 7h > 50 - 30

3h > 30.

Divide

h > 30/3

h > 10

The hours will be 10 hours.

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Answer:

it would be “>”, 100% guaranteed.

Answer:

answer is >

Step-by-step explanation:

hope this is helpful

The solution to the given IVP is.\($i(t)-\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{R}{L}}$\)

Initial value problems describe a type of problem in calculus. Initial value problems in calculus concern differential equations with a known initial condition that specifies the value of the function at some point. The purpose of these problems is to find the function that describes the system, which can be done by integrating the differential equation.

Consider the initial value problem,

L \(\frac{d i}{d t}+R i=E \text {. }\)

The initial condition is. \($i(0)=i_0$\)

Rewrite the DE as,

\(\begin{gathered}L \frac{d i}{d t}+R i=E \\\frac{d i}{d t}+\frac{R}{L} i=\frac{E}{L}\end{gathered}$$\)

This is a linear DE.

Compare the DE  \(\frac{d i}{d t}+\frac{R}{L} i=\frac{E}{L}$\) with the general DE \(\frac{d i}{d t}+P(t) i=Q(t)$\). Then \($P(t)=\frac{R}{L}$\) and \($Q(t)=\frac{E}{L}$\).

Find the integrating factor (IF).

                                     \($$\begin{aligned}I F & =e^{\int P(t) \vec{t}} \\& =e^{\int\left(\frac{\pi}{\mathrm{I}}\right) \mathrm{A}} \\& =e^{\frac{\pi}{l^2}}\end{aligned}$$\)

Thus, the integrating factor is \($I F=e^{\frac{R^2}{2^2}}$\).

Now multiply both sides of the DE with the IF.

                                   \($$\begin{array}{r}e^{\frac{R}{\bar{L}^t}}\left(\frac{d i}{d t}+\frac{R}{L} i\right)=\frac{E}{L} e^{\frac{R}{L^t}} \\\frac{d i}{d t} e^{\frac{\pi}{L^t}}+\frac{R}{L} e^{\frac{R}{\bar{L}^t}} i=\frac{E}{L} e^{\frac{\pi}{\bar{L}^t}} \\{\left[i e^{\frac{R}{L^2}}\right]=\frac{E}{L} e^{\frac{R^L}{L^t}}}\end{array}$$\)

Integrate on both sides.

        \($$\begin{aligned}& \int\left[i e^{\frac{R}{L}}\right] d t=\int \frac{E}{L} e^{\frac{R}{L^t}} d t \\& i e^{\frac{R}{L^{\mathrm{r}}}}=\frac{E}{L} \int e^{\frac{\pi}{L^t}} d t \\& i e^{\frac{R}{\perp} r}=\frac{E}{L}\left[\frac{e^{\frac{R}{2}}}{\frac{R}{L}}\right]+C \\& i e^{\frac{R}{\Gamma}+}=\frac{E}{R} e^{\frac{R^2}{I^{+}}}+C \\& i(t)=\frac{\frac{E}{R} e^{\frac{R}{L^2}}+C}{e^{\frac{R}{D^2}}} \\& t(t)=\frac{E}{R}+C e^{-\frac{R}{L^t}} \\&\end{aligned}$$\)

Thus, the general solution to the \(\mathrm{DE}\) is \($i(t)=\frac{E}{R}+C e^{-\frac{R}{t^*}}$\).

Use the initial condition. \($i(0)=i_0$\)

Substitute \($t=0$\) and \($i(0)=i_0$\) in \($i(t)=\frac{E}{R}+C e^{-\frac{R}{I^t}}$\).

\($$\begin{aligned}& i(0)=\frac{E}{R}+C e^{-\frac{R}{I}(0)} \\& i_0=\frac{E}{R}+C e^0 \\& i_0=\frac{E}{R}+C \quad \text { use } e^0=1 \\& C=i_0-\frac{E}{R}\end{aligned}$$\)

Substitute  \($C=i_0-\frac{E}{R}$\) in \($i(t)=\frac{E}{R}+C e^{-\frac{R}{L^1}}$\).

\($$\begin{aligned}& i(t)=\frac{E}{R}+C e^{-\frac{R}{I}} \\& i(t)=\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{\pi}{t^t}}\end{aligned}$$\)

Therefore, the solution to the given IVP is. \($i(t)-\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{R}{L}}$\).

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The standard deviation lies in the range of 0 to 1. The numerical value of standard deviation can never be negative.

The standard deviation is a measure of amount of variation or dispersion of a set of values. When we compare two unequal observations, the result is always greater than zero i.e., always positive.

Standard deviation is the square root of the variance of the observations and the root always gives values either positive or zero, it can never be negative.

Therefore, the numerical value of the standard deviation can be positive. The value of standard deviation is always greater or equal to zero.

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