A copper wire is 1.0 meters long and it's diameter is 1.0 millimeters if the wire hangs vertically how much weight must be added to its free end in order to stretch it 3.0 millimeters?

Answers

Answer 1

Answer:

The weight required to stretch a wire can be calculated using the formula:

W = (π/4) x d^2 x L x S

where:

d = diameter of the wire

L = length of the wire

S = stress applied to the wire

π = pi (3.14)

In this case, the wire has a diameter of 1.0 millimeters and a length of 1.0 meters. We want to stretch it by 3.0 millimeters, which means the stress applied to the wire is:

S = ΔL / L = 3.0 / 1000 = 0.003

Now we can plug in the values and calculate the weight required:

W = (π/4) x (1.0)^2 x 1.0 x 0.003

W = 0.0002355 kg or 0.2355 grams

Therefore, we need to add 0.2355 grams of weight to the free end of the wire to stretch it by 3.0 millimeters.


Related Questions

The speed of x-rays is 300 000. m/s. In scientific notation, and with the correct number of significant figures, this speed is… *

Answers

Answer:

3.0 x 10 and the exponent on ten is 5.

Explanation:

You are moving the decimal point over to the left 5 times, making the exponent a positive 5 and then you would put a decimal after 3. Making it 3.0 x 10, and the exponent 5.

The speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

The given parameters;

speed of the x-ray, v = 300,000 m/s

The standard form of the given number represents the scientific notation of the number.

To represent a number in standard form, multiply the number in terms of power or exponent of 10. The value of the exponent represents the number of available zeros present.

In scientific notation the speed of the x-ray can be expressed as follows;

300,000 m/s = 3.0 x 10⁶ m/s

Thus, the speed of x-rays in scientific notation is 3.0 x 10⁶ m/s.

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Which of the following is a definition of motion?

Answers

Answer:

sorry I don't get it so pls can u repeat the question .

Movement of any object from one position to another position with respect to the observer is called as Motion. Motion Along a Straight Line: When an object moves along a straight line, the motion of the object is called rectilinear motion. For example; motion of a car on highway.

QUESTION:

Which of the following is a definition of motion?

ANSWER:

In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.

Two very large parallel metal plates, separated by 0.20 m, have a potential difference of 12V. An electron is released from rest at a location a distance d from the negative plate.
(a) Describe the motion of the electron after its release in as much detail as possible.
(b) At what distance from the positive plate, will the electron have a speed of 1 x 10^6 m/s?

Answers

Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.

(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.

(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?

For part (a):

The magnitude of an electric field can be given as  \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.

So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)

An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.

For part (b):

We know that...

- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).

- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).

- \(\vec F_e=q\vec E\)

- \(\vec F =m\vec a\)

\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)

\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)

Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)

\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)

\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)

The distance from the positive plate we'll call, "D."

\(D=0.20+\Delta \vec x\)

\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)

the diagrams below show different objects of equal masses that are acted on by one or more forces. in the diagrams below, each force vector labeled f has the same magnitude.
Which of the four objects shown has a net zero force acting on it?
a. (i)
b. (ii)
c. (iii)
d. (iv)

Answers

The figure (i) (attached below) will have net zero force acting on it.

In the given figure forces of equal magnitudes are acting on it but in opposite directions. So, the cancel out to zero .

The push or pull on an object with mass causes it to change its velocity is called force.Force is defined as an external cause that changes or tends to change the state of the body once applied. If the body is in motion, it comes to rest, and if at rest, then it will come to motion. It can also cause a change in the direction, shape, size, etc., of the body. A force is an external agent that may change the condition of rest or motion of a body. It has a magnitude as well as a direction. The direction of the force is the place where force is applied, and the application of force is the location where force is applied.The vector product of mass (m) and acceleration (a) expresses the quantity of force. The equation or the formula for force may mathematically be stated in the form of :

                                                         F=ma

Where, m= mass,

            a= rate of acceleration

The force applied on an object is measured in terms of Newton and dyne. Force is measured in dyne in the centimetre gram second system of unit (CGS unit). It is represented in Newton (N) in the standard international system of units (SI unit).

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the diagrams below show different objects of equal masses that are acted on by one or more forces. in

cheese is made of cheese

Answers

Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.

What is a dairy product?

Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.

Hence, cheese is made up of casein proteins that are present in the milk.

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As SCUBA divers go deeper underwater, the pressure from the weight of all the water above them increases tremendously which compresses the gases in their blood. What happens to the volume of gas in their blood as the diver rises quickly to the surface?

Answers

Answer:

The volume of gas in an early diving bell full of air at sea level is halved at 10 m according to Boyle’s law

Explanation:

;at 20 m pressure is 300 kPa absolute and the gas is compressed into one third the volume.

HOPE THIS HELPS         i did this before

A rightward force of 4.0 N is exerted upon an object for a distance of 3.0 meters.
What is the work done on the object?

Answers

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

\(W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J\)

So, the work done on the object is 12 J.

Three particles having charges of equal magnitude q are fixed at the conrners of an equilateral triangle as shown. two of the charges are negative: the other is positive. which of the following vectors best represents the direction of the resultant electric field at point p, the center of the triangle?

Answers

Vector B of the following vectors best represents the direction of the resultant electric field at point p, the center of the triangle.

What is vector?

A  quantity or phenomenon that has two independent properties i.e magnitude and direction is named as vector.

At the middle, where it is zero, one can see that the three charges each produce cancelling fields thanks to symmetry.In addition to the triangle's center, the second panel of the picture shows three additional sites in the middle of each triangle leg where E=0, however they are more challenging to calculate analytically.

Adding the electric field vectors resulting from each of the two lower point charges will yield the electric field at point P.

E = E1+ E2.

According to the bottom panel of the picture, a point charge's electric field has the formula E = kr2qr.

E =k ea2q uphill and to the right at 60, and E2 =kea2q upward and to the left at 60.

Therefore, E= E1 + E2 = kea2q[(cos60i+sin60j) + (cos60i+sin60j)] = kea2q[2(sin60j)

= 1.73kea2qj. i.e vector B

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A tennis ball is kicked horizontally off the edge of a 25 m high building and lands a distance of 27 m from the edge of the building. What was the final horizontal velocity of the tennis ball, in m/s? Ignore air resistance.

Answers

Given:

Height = 25 m

Distance from the edge to where it lands = 27 m.

Let's find the final horizontal velocity of the tennis ball.

To find the final horizontal velocity of a projectile motion, apply the formula:

\(v_{fx}=v_ix\)

The initial horizontal velocity and the final horizontal velocity are the same since there is no force acting on the object.

Now, to find the horizontal velocity, let's first make a free sketch of this situation:

Let's find the time of flight:

\(t=\sqrt{\frac{2h}{g}}\)

Where:

h = 25 m

g is acceleration due to gravity = 9.8 m/s²

Thus, we have:

\(\begin{gathered} t=\sqrt{\frac{2*25}{9.8}} \\ \\ t=2.26\text{ s} \end{gathered}\)

The time of flight if the projectile is 2.26 seconds.

Now, to find the final horizontal velocity, we have:

\(\begin{gathered} V=\frac{x}{t} \\ \end{gathered}\)

Where:

x is the horizontal distance = 27 m

Thus, we have:

\(\begin{gathered} V=\frac{27}{2.26} \\ \\ V=11.96\text{ m/s} \end{gathered}\)

Therefore, the final horizontal velocity is 11.96 m/s.

ANSWER:

11.96 m/s

A tennis ball is kicked horizontally off the edge of a 25 m high building and lands a distance of 27

Explain an example of how energy is transferred from one form to another

Answers

Answer:

Explanation:

Energy can can be transferred from one form to another in many ways,

Forms of energy that exist are Chemical Energy, Nuclear Energy

Electrical Energy Heat Energy and others.

one example is conversation of chemical energy by stove to heat energy.

Chemical energy which a form of energy that allow substance to experience chemical reaction, when a gasoline which posses chemical energy is put into stove then it convert this chemical energy to heat energy through burning which helps our food to cook as a result of heat energy gotten

Examine the image and assess the relationship of the atoms shown by

Examine the image and assess the relationship of the atoms shown by

Answers

The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).

During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.

What is a change in chemistry?

A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.

Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.

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What is the net force net
on an airplane window of area 1800 cm2
if the pressure inside the cabin is 0.95 atm
and the pressure outside is 0.76 atm
?

Answers

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Oceans and other bodies of water are found on which layer of earth

Answers

Answer:

They are found in the Hydrosphere

Explanation:

holped it helped!!

Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:

Answers

The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.

To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).

Saturn's density can be computed using the following formula:

density equals mass divided by volume

Saturn's mass and volume may be computed given its mass and radius.

The volume of Saturn can be determined using the sphere volume formula:

volume =\((4/3) \pi (r^3)\)

where r is Saturn's radius.

Filling in the blanks:

volume = \((4/3) \pi (5.6 \times 107) m^3\)

8.27 x 1023 \(m^3\)volume

Saturn's mass is given as \(5.68 \times 10^{26} kg.\)

We can now compute Saturn's density:

density equals mass divided by volume

density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)

This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.

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Suppose you throw a ball straight upward; it rises, then returns to your hand
(a) Calling the point where it leaves your hand the origin and upward positive, make a plausible sketch of its position (vertical height) x(t) versus time t from the instant after it leaves your hand till the instant before it reaches it again.
(b) From your x(t) plot, make a sketch of the ball’s velocity v(t) versus time.
(c) From your velocity plot, sketch a plot of the ball’s acceleration versus time.
(d) Does your plot suggest that the ball’s acceleration is zero at the top of its flight?

Answers

Answer:

Please find the attached file for the solution

Explanation:

Given that you throw a ball straight upward; it rises, then returns to your hand

(a) Calling the point where it leaves your hand the origin and upward positive, make a plausible sketch of its position (vertical height) x(t) versus time t from the instant after it leaves your hand till the instant before it reaches it again.

(b) From your x(t) plot, make a sketch of the ball’s velocity v(t) versus time.

(c) From your velocity plot, sketch a plot of the ball’s acceleration versus time.

(d) Does your plot suggest that the ball’s acceleration is zero at the top of its flight

Please find the attached file for the solution and graph

Suppose you throw a ball straight upward; it rises, then returns to your hand (a) Calling the point where

how to type a capital letter in my computer​

Answers

Answer:

Hold down the shift key if your on windows, mac or chromebooks.

Explanation:

Computer Technician

Answer:

Press the "caps lock" button and then press which letter u want to be in cap

. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

Answers

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Will we ever be able to know if there are other universes like our own? what do you think,
some say it is impossible to see beyond our own universe. but hey, we used to think that the earth was flat and look at us now, planing to go to mars.
however, it is impossible to know what kind of advancements lie ahead for science.

Answers

Answer:

I think it's possible to know if more universes exist like how we found out that more galaxies exist.

What types of appliances in your home draw the most power?A: Appliances the heat things up.B: Appliances the create light.C: Appliances like your television and radio.D: Appliances like your vacuum.

Answers

A. Appliances that heat things up.

The heating and cooling appliances draw the most power among all the appliances. On average, around 40% of the power is used by heating and cooling appliances.

The appliances like television and radio consume the least amount of power.

Thus the correct answer is option A.

An 80.8 kg man is standing on a frictionless ice surface when he throws a 2.3 kg book at 11.8 m/s. With what velocity does the man
move across the ice?
VM= ? m/s in the opposite direction as the book

Answers

The amount of velocity does the man who standing on a frictionless ice surface move across the ice(V)= 1 m/s in the opposite direction as the book.

What is Velocity?

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

How can we calculate the values of the velocity does the man move across the ice?

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Here we are given that,

Apply the law of linear momentum

Before the throw:

M₁=Man initial mass= 80kg,

U₁=Man's initial velocity = 0,

M₂=Book  initial mass = 4kg,

U₂=Book's initial velocity = 0.

After the throw:

M₁=Man final mass = 80kg,

V₁=Man's final velocity = V.

M₂=Book final mass = 4kg,

V₂=Book final velocity = 20.

Now we put the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80x0) + (4x0) = (80V) + (4x20)

Or, 0=80V + 80

Or, 80V = -80

Or, V = -80/80

Or, V= -1m/s.

From the above calculation we can conclude that,

The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book

[Note: The (-)Ve sign shows that the opposite direction]

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A football player has a mass of 100 kg and can accelerate at 4 m/s². How much
force does this football player apply?

Answers

Answer: F=400 N

Explanation:

F=ma ==> F=force, m=mass, a=acceleration

F=100*4

F=400 N

At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.
Calculate the pressure of the gas when it is heated to 900 K.

At a temperature of 300 K, the pressure of the gas in a deodorant can is 3 atm.Calculate the pressure

Answers

The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

What is the pressure of the gas when it is heated to 900 Kelvin?

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

Initial pressure P₁ = 3 atmInitial temperature T₁ = 300 KFinal pressure P₂ = ?Initial temperature T₂ = 900 K

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).

Answers

The radii of the first five Fresnel zones is 3.6 mm.

Distance from the light source to the wave surface, d₁ = 1 m

Distance from the wave surface to the observation point, d₂ = 1 m.

Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm

The expression for the radius of the Fresnel zones is given by,

rₙ = √[nλd₁d₂/(d₁ + d₂)]

Therefore, the radii of the first five Fresnel zones is,

r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]

r₅ = √(25 x 10⁻⁶/2)

r₅ = 3.6 x 10⁻³m

r₅ = 3.6 mm

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Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with the ground what is the horizontal component of Barney’s velocity

Answers

Answer:

Explanation:

The horizontal velocity is 1.61.

Barney walks at a velocity of 1.7 meters/second on an inclined plane which has an angle of 18.5 with

FILL IN THE BLANK. A ________ is a well-tested and widely accepted view that best explains certain scientific observations.

Answers

A scientific theory is a well-tested and widely accepted view that best explains certain scientific observations.

A scientific theory is a comprehensive and coherent explanation of a set of phenomena based on empirical evidence. It is not just a guess or speculation, but rather a well-supported and well-tested explanation that has been subjected to rigorous testing and scrutiny by the scientific community. Scientific theories are supported by a large body of evidence, and they can be used to make predictions and guide further research.

Scientific theories are an important part of the scientific method, which is a systematic approach to gaining knowledge and understanding about the natural world. Theories play a critical role in helping scientists make sense of their observations and in developing new ideas and hypotheses.

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1.55 J of work was done on the object that moved 5 meters. How much force was applied to the
object?

Answers

Answer:

Work=force x displacement

Force =work/ displacement

F=1.55/5

F=0.31N

Explanation:

statics and strength of materials

statics and strength of materials

Answers

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

What is the force P?

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ is the area of segment ABA₂ is the area of segment BC

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Two train whistles have identical frequencies of 1.85 102 Hz. When one train is at rest in the station and the other is moving nearby, a commuter standing on the station platform hears beats with a frequency of 8.00 beats/s when the whistles operate together. What are the two possible speeds that the moving train can have

Answers

Answer:

Explanation:

frequency of whistle = 1.85 x 10² = 185 Hz

frequency of beat heard = 8 beat /s . No of beat produced is equal to difference of frequencies of two sound source . Here difference is created due to Doppler effect . One of the train is moving so it will have apparent frequency which is different one from its original frequency .

When the moving train is approaching the observer , its frequency will be higher . As beat is heard at the rate of 8 beats / s , apparent frequency of approaching train will be 185 + 8 = 193 Hz .

Applying Doppler's formula of apparent frequency ,

193 = 185 x V / ( V - v ) , where V is velocity of sound and v is velocity of train .

193 V - 193 v = 185 V

193 v = 8 V

v = 8 x V / 193

= 8 x 343 / 193

= 14.21 m /s

Second possibility is that apparent velocity is less ie 185 - 8 = 177 Hz

In that case moving train will be moving away from observer . If its velocity be v

177 = 185 x V / ( V + v )

177 V + 177 v = 185 V

v = 8 x 343 / 177

= 15.50 m /s .

Purpose: Determine the kinetic energy of a constant velocity car when it is switched on.

A. Design an experimental procedure to find the kinetic energy of a constant velocity car. Make a list of the equipment you would use.

B. Describe the overall procedure you would follow. Provide enough detail so another student could replicate the experiment, including any steps necessary to reduce experimental uncertainty.

C. Clearly list what data you need to collect.

D. List what equations you need to use with the data you collected to find the kinetic energy of the car.

E. Describe the energy conversion that occurs while the constant velocity car is running. What other types of energy does the car have, aside from kinetic energy?

F. If you were to actually complete this lab, what are some potential sources of error that could cause your answer to be incorrect?

Answers

Answer:

The kinetic energy is proportional to the square of the speed, so doubling the speed increases the kinetic energy by a factor of 4.

In 2001, the moose population in a park was measured to be 4,850. By 2009, the population was measured again and was found to be 5,890. Assume the population continues to change linearly.
(a) Find a formula for the moose population, P, since 2001. (Let t represent the number of years since 2001.)

b) What does your model predict the moose population to be in 2017?
moose

Answers

Answer:

Explanation:

Letting 2001 equate to t=0 for our starting point

We started at (0, 4840) and 8 years later we are at (8, 6200)

4840 + 8t = 6200    The population went from 4840 to 6200 over 8 years.

Subtract 4840 from both sides

8t = 6200 - 4840

8t = 1360

divide both sides by 8 to isolate t

t = 1360/8

t = 170

The population rises by 170 moose per year

P(t) = 170t + 4840

b)  In 2020... t = 2020 - 2001 = 19 years

   P(t) = 170t + 4840

   P(t) = 170(19) + 4840

   P(t) = 8070

By our linear model there should be approximately 8070 moose by 2020.

******************************************

You could also take the two initial points (0, 4840), (8, 6200)

and find the slope m to set up the equation in

slope intercept form  y = mt + b

where m is the slope and the point (0,b) = (0, 4840) is y-intercept.

m = (rise/run) = (6200-4840)/(8-0) = 170

y(t) = mt + b = 170t + 4840

There is another, probably easier, way to find the "245" for this

problem.  We have two points (0, 4240) and (8, 6200)

We can use that to find the slope of our equation to set up the

equation in slope intercept form of  y = mx + b... or, in this case

y = mt + b   since y is a function of t

m = slope of the line, and the point (0,b) is the y-intercept = (0, 4240)

m = (change in y)/(change in t)  = (6200-4240)/(8-0) = 1960/8 = 245

We can then set up our equation y = mt + b

using 245 for m, and 4240 for b

y = 245t + 4240

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