A cook uses a pair of twelve-inch-long tongs to remove a piece of chicken from the grill. The chef is applying 3 pounds of squeezing force to the tongs. If more than 1 pound of force is applied to the fish, it will break.

The AMA of the system (rounded to the nearest hundredth) is

.
Using the static equilibrium calculations, the tongs must be held
inches (rounded to the nearest whole number) away from the fulcrum to avoid damaging the fish.

Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

Based on the fact that Megan arranged the machines according to their functions, this is Process layout. Thus, option A is correct.

This is the way of arranging a shop or factory where the machines and equipment are arranged according to their function.Megan arranged her machines according to how they function so that she can be able to move from one station to another. This is therefore a process layout.

In the process layout, similar processes are grouped together, and machines are arranged according to the production process. This type of layout is ideal for factories that produce a variety of products with different production requirements, as it allows for flexibility in production.

In a heavy machine tools factory, various machines with different production requirements are used, and a process layout would allow for efficient use of resources and flow of materials.

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The discharge rate of the supply of water to the roof top is;

V' = 9.8641 L/s

The conditions given to us are;

- Water goes in atmosphere and so; p₂ = p_atm

- Velocity at point 1 is very small and so; V₁ ≈ 0

- Reference level is point 1

- Difference between pressures p₁ and p₂ is gauge pressure;

p_gauge = p₁ - p_atm

- There is no turbine and pump

From the conditions above, we can say that the Velocity V₂ can be gotten from the expression;

(p₁ - p_atm)/(ρg) + 0 + 0 + 0 = (V₂²/2g) + h + 0 + h_L

Making V₂ the subject gives us;

V₂ = √[(2p₁_gauge)/ρ - 2g(h + h_L)]

We are given;

p₁_gauge(air pressure in the tank)  = 300 KPa = 300000 Pa

ρ(density of water) = 1000 kg/m³

h (height above the water tank level) = 8 m

h_L(head loss) = 2 m

Thus;

V₂ = √[(2 * 300000/1000) - 2(9.8)(8 + 2)]

V₂ = 20.095 m/s

The discharge rate of the supply of water to the roof top is given by the formula;

V' = A₂ * V₂

Where A₂ is cross sectional area of pipe = πr² = π * (2.5/200)² = 4.90874 * 10⁻⁴ m²

Thus;

V' = 20.95 * 4.90874 * 10⁻⁴

V' = 9.8641 L/s

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Answer:

The law of parallelogram of forces states that if two vectors acting on a particle at the same time be represented in magnitude and direction by the two adjacent sides of a parallelogram drawn from a point their resultant vector is represented in magnitude and direction by the diagonal of the parallelogram drawn from .

A statement that assigns all elements in the array atomic Weights the value 1.003,independent of the size of the array is atomicWeights(:) = 1.0032.

An array is a grouping of identically typed components that are stored in adjacent memory locations and can each be individually referred to using an index to a special identifier. There is no need to declare five distinct variables when declaring an array of five int values (each with its own identifier). are by default not set. This indicates that none of the components in the array have any specific values assigned to them; rather, their contents are unknown at the time the array is declared.

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Answer:

t₁ = 378.668 K

Explanation:

From the given information:

The heat dissipated (q) from the electrical device = \(10^4 W/m^2\)

The contact resistance between device and aluminium;

(R_{const} ) = 0.5× 10⁻⁴ m² K/W

Conductivity of aluminum (k)  = 238 \ W/mK

The thickness of aluminum plate (L) = 0.004 m

Convection coefficient (h) = 100 \ W/m^2 K

Surrounding temperature (t_2) = 278 \ k

According to Fourier's law of heat conduction.

\(q = \dfrac { t_1- t_2 }{R_{const} + \dfrac{L}{k} + \dfrac{1}{h} }\)

\(10^4 = \dfrac{t_1 - 278}{0.5 \times 10^{-4} + \dfrac{0.004}{238} + \dfrac{1}{100} }\)

\(10^4 *( 0.5 \times 10^{-4} + \dfrac{0.004}{238} + \dfrac{1}{100}) = t_1 - 278\)

\(100.668 = t_1 -278\)

t₁ = 378.668 K

The equation of yx3 with the given transformations vertical compression by a factor of 17 is,  y = x³ ⇒ y =-1/7(x+8)³

Four distinct ways to modify the position and/or shape of a point, line, or geometric figure are collectively referred to as transformations. The Pre-Image of the object is its initial shape, and the Image, after transformation, is the final shape and location of the object.

Isometry is the name for a transformation that maintains congruence. Alternatively put, a transformation in which the side lengths and angle measurements of the Image and Pre-Image are equal. The isometries of translation, reflection, and rotation. In contrast to reflections and rotations, a translation maintains orientation while also maintaining congruence, which is why it is referred to as a "direct isometry".

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Answer:

final temperature = 26.5°

Explanation:

Initial volume of water is 1 x 1 x 1 = 1 \(m^{3}\)

Initial temperature of water = 20° C

Density of water = 1000 kg/\(m^{3}\)

volume of copper block = 0.46 x 0.46 x 0.46 = 0.097 \(m^{3}\)

Initial temperature of copper block = 100° C

Density of copper = 8960 kg/\(m^{3}\)

Final volume of water = 1 - 0.097 = 0.903 \(m^{3}\)

Assumptions:

mass of water remaining in the tank will be density x volume = 1000 x 0.903 = 903 kg

specific heat capacity of water c = 4186 J/K-kg

heat content of water left Hw = mcT = 903 x 4186 x 20 = 75.59 Mega-joules

mass of copper will be density x volume = 8960 x 0.097 = 869.12 kg

specific heat capacity of copper is 385 J/K-kg

heat content of copper Hc = mcT = 869.12 x 385 x 100 = 33.46 Mega-joules

total heat in the system = 75.59 + 33.46 = 109.05 Mega-joules

this heat will be distributed in the entire system

heat energy of water within the system = mcT

where T is the final temperature

= 903 x 4186 x T = 3779958T

for copper, heat will be

mcT = 869.12 x 385 = 334611.2T

these component heats will sum up to the final heat of the system, i.e

3779958T + 334611.2T = 109.05 x \(10^{6}\)

4114569.2T = 109.05 x \(10^{6}\)

final temperature T = (109.05 x \(10^{6}\))/4114569.2 = 26.5°

Synchronous sequential circuits are sequential circuits in which all flip-flops are clocked at the same time.

That is, all flip-flops are controlled by the same clock signal. The circuit’s input signal(s) are also synchronous to the clock signal, thus ensuring proper functioning of the circuit.

A synchronous sequential logic circuit can be designed using D flip-flops. The design process includes the following steps:

Step 1: Determine the number of states The circuit given can count from 0 to 5, which requires 3 flip-flops.

Step 2: State tableThe state table for the given circuit is shown below:Present State (Q2 Q1 Q0)Next State (Q2 Q1 Q0)+1D20 (0 0 0) 1 (0 0 1) 0 (0 0 0)D21 (0 0 1) 2 (0 1 0) 1 (0 0 1)D22 (0 1 0) 3 (0 1 1) 2 (0 1 0)D23 (0 1 1) 4 (1 0 0) 3 (0 1 1)D24 (1 0 0) 5 (1 0 1) 4 (1 0 0)D25 (1 0 1) 0 (0 0 0) 5 (1 0 1)

Step 3: Simplify the next-state expressionsSimplifying the next-state expressions involves minimizing the Boolean functions that define the next state of each flip-flop. Karnaugh maps or Boolean algebra can be used to obtain the minimized expressions. The next-state expressions are shown below:D20 = Q2’Q1’Q0 + Q2’Q1Q0’D21 = Q2’Q1Q0 + Q2Q1’Q0’D22 = Q2Q1’Q0 + Q2Q1Q0’D23 = Q2Q1Q0’ + Q2’Q1’Q0D24 = Q2’Q1’Q0’ + Q2’Q1Q0D25 = Q2’Q1’Q0 + Q2Q1’Q0’

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The term that is not designed to absorb collision energy is dimples.

What is an energy-absorbing mechanism?

Energy-absorbing mechanism is a safety mechanism that absorbs the kinetic energy that is generated during an impact.

The shock-absorbing material, which is intended to be compressed in a controlled manner under the impact, is the most basic component of this system.

What is the purpose of the design of a crush zone?

Crush zones are engineered areas of a vehicle that are designed to absorb and dissipate energy during a collision.

They are often constructed from a variety of materials, including high-strength steel, aluminum, magnesium, and other composites.

O Slots, crush zones, and reinforcements are all safety features that are designed to absorb collision energy and lessen the impact of a collision on the vehicle and its occupants.

These energy-absorbing mechanisms allow the vehicle to deform or collapse in a controlled manner, slowing down the rate of deceleration and reducing the amount of force transferred to the vehicle's occupants.

Dimples, on the other hand, are not an energy-absorbing mechanism.

Dimples are tiny indentations or bumps on the surface of a material that is often used to reduce aerodynamic drag. They are not designed to absorb collision energy.

Therefore, the answer is dimples.

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Answer:

In  case whereby you  work for rev and check your work email on your mobile phone and You have decided to resign your job and take a position with a different company. Regarding rdm on your mobile phone, you should B. Take your phone to IT Services, and they will wipe it clean.

What is expected to do when leaving the company?

It is expected from you to return anything that belong to the company before leaving the company, but in the case whereby there is still a rdm on your mobile phone, then you can work to the IT services so they can wipe it away.

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Missing options:

A. Turn your phone to IT Services

B. Take your phone to IT Services, and they will wipe it clean

C. Download RDM to your personal computer

D. Call IT Services for support, and they will assist

E. Nothing. IT Services will automatically remove all data

The capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

A DC series circuit can be defined as a type of circuit in which all of its resistive components are connected end to end, so as to form a single path for the flow of current.

This ultimately implies that, the same amount of current flows through a direct current (DC) series circuit.

Mathematically, the capacitive reactance of a DC series circuit is given by this formula:

\(X_C = \frac{1}{2\pi fC}\)

Where:

From the above formula, we can deduce that the capacitive reactance of a DC series circuit is inversely proportional to both frequency and capacitance. Thus, the capacitive reactance of a DC series circuit increases when its capacitance decreases and vice-versa.

In conclusion, a capacitor would influence a simple DC series circuit by blocking the flow of direct current (DC) through it.

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Answer:

No, the offspring of two black horses cannot have chestnut hair. Since the black hair allele is recessive, both parents have to be hz recessive and do not carry the dominant chestnut hair allele. The only allele the parents can pass back to their offspring is the black allele.

Explanation:

Edg. 2022

Answer: The offspring of two black horses cannot have chestnut hair. Since the black hair allele is recessive, both parents have to be his recessive and do not carry the dominant chestnut hair allele. The only allele the parents can pass back to their offspring is the black allele.

Explanation:

To increase the security of devices in the accounting department, you should implement VLANs (Virtual Local Area Networks) and configure ACLs (Access Control Lists).

VLANs: Create a dedicated VLAN for the accounting department. By segregating the accounting computers into their own VLAN, you can ensure that broadcast traffic sent by an accounting computer will only be received by other accounting computers within the same VLAN. This enhances security by limiting the exposure of sensitive accounting data to other devices on the network.

ACLs: Implement ACLs on the switch to control traffic sent to accounting computers. ACLs allow you to define rules that permit or deny traffic based on various criteria such as source/destination IP addresses, protocols, and ports. By configuring ACLs specifically for the accounting VLAN, you can restrict access to accounting resources and prevent unauthorized communication with accounting computers from other parts of the network.

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The correct answer is To calculate the discrete settling velocity of a grit particle, we can use the following formula:

\(V_s = (2/9) * (ρ_p - ρ_f) * g * r^2 / η\)

V_s = discrete settling velocity

ρ_p = density of particle

ρ_f = density of fluid

g = acceleration due to gravity

r = radius of particle

η = dynamic viscosity of fluid Given that the radius of the grit particle is 0.05mm and its specific gravity is 2.65, we can calculate its density as:

ρ_p = specific gravity * ρ_water

\(= 2.65 * 1000 kg/m^3= 2650 kg/m^3\)

At a water temperature of 20°C, the dynamic viscosity of water is\(1.004 × 10^-6 m^2/s,\)which we are given.

The density of water at 20°C is approximately \(1000 kg/m^3,\) and the acceleration due to gravity is\(9.81 m/s^2.\)

Substituting these values into the formula, we get:

\(V_s = (2/9) * (2650 - 1000) * 9.81 * (0.05 × 10^-3)^2 / (1.004 × 10^-6)= 0.086 m/s\)(rounded to three decimal places)

Therefore, the discrete settling velocity of the grit particle is approximately 0.086 m/s.

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Draw a line AB, 50 mm long, inclined at 30° to the H.P and at 60° to the V.P.Project the ends A and B of the given line perpendicular to xy in the H.P and project them down to xy in the V.P.

The problem of drawing the projection of a line AB 50mm long, inclined at 30° to the H.P. and making an angle of 60° with the V.P. can be solved by following the steps below:Step 1: Draw the given line AB, 50mm long, inclined at 30° to the H.P. and making an angle of 60° with the V.P. (Figure 1).Step 2: Project the ends A and B of the given line perpendicular to xy in the H.P. and project them down to xy in the V.P by making 60° with xy. (Figure 2).Step 3: Draw a line through the points A1 and B1 in the V.P. to intersect the xy line in the H.P. This intersection point gives the true length of the line AB (Figure 3).Step 4: Draw a line through the points A and B in the H.P. to intersect the xy line in the V.P. This intersection point gives the distance between the projections of A and B. Join these two points to obtain the projection of the line (Figure 4).Step 5: Complete the projections of the line by drawing perpendiculars from A and B to the xy line in the V.P. This will show the actual height of the line above xy in the V.P. (Figure 4).

The projections of a line can be easily obtained by following the steps above. The key is to first draw the line in the correct position with respect to the H.P. and V.P., then project its ends to xy in the H.P. and V.P., and finally, use these projections to obtain the true length and distance between the projections of the line.

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Both technicians are partially correct.

Technician A is partially correct, as diodes in the alternator rectify the alternating current (AC) produced by the alternator into direct current (DC), which is used to charge the battery and power the electrical systems in the vehicle. However, diodes do not regulate the voltage output of the alternator; that is the job of the voltage regulator.

Technician B is also partially correct. The field current in the alternator can be computer controlled in some modern vehicles, but not in all. Older vehicles typically use a mechanical voltage regulator to control the alternator's field current. However, newer vehicles may use electronic controls to adjust the field current, which can help improve fuel efficiency and reduce emissions.

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9514 1404 393

Answer:

  11 bit

Explanation:

The number of resolution units required is ...

  (1000 °C -0 °C)/(0.5 °C) = 2000

log2(2000) = 10.97, so an unsigned word length of 11 bits is the minimum required.

The pace at which a material heat up by conduction via a certain unit area is known as thermal conductivity. In general, the rate of heat transfer increases with increasing thermal conductivity and vice versa.

The property of a substance that directly relates to its capacity to transport heat is known as thermal conductivity (). Conduction is the process of transferring energy within a substance without the material itself moving.

Therefore, A crucial factor is thermal conductivity, since it determines temperature gradients both during material growth and inside of devices.

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For modifying ImprovedFibonacci on pages 9-10 as in- structed one should access the below java code.

Below is the modified version of the ImprovedFibonacci class as SubsetOutputFib in the Fibonacci.java file:

class SubsetOutputFib {

   public static void main(String[] args) {

       if (args.length != 2) {

           System.out.println("Please provide two integer arguments.");

           return;

       }

       int begin, end;

       try {

           begin = Integer.parseInt(args[0]);

           end = Integer.parseInt(args[1]);

       } catch (NumberFormatException e) {

           System.out.println("Both arguments should be positive integers.");

           return;

       }

       if (begin <= 0 || end <= 0) {

           System.out.println("Both arguments should be positive integers.");

           return;

       }

       int lo = 1;

       int hi = 1;

       String mark;

       System.out.println("1: " + lo);

       for (int i = 2; i <= end; i++) {

           mark = (hi % 2 == 0) ? " *" : "";

           if (i >= begin) {

               System.out.println(i + ": " + hi + mark);

           }

           hi = hi + lo;

           lo = hi - lo;

       }

   }

}

Thus, this can be the modified version of the given code.

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The field in Niger Delta, developed by NPDC has an estimated potential of 80,000,000 (80MM) barrels of oil. The development  is estimated to take about 4 years. The production is assumed to start at the end of the third year, and facilities will be constructed to handle 20,000 barrels of oil per day.

The economic limit is determined to be 600 barrels of oil per day. Determine a forecast of the annual production rate and cumulative production over the entire life of this field. Annual production rate: Annual production rate = 20,000 barrels of oil per day × 365 days Annual production rate = 7,300,000 barrels of oil per year.

At the end of the sixth year, the facility limit is expected to be reached, and the production will continue at a constant rate of 20,000 barrels of oil per day until the 12th year. Cumulative production: Production from year 0 to year 6 = 7,300,000 barrels of oil per year × 6 years.

Production from year 0 to year 6 = 43,800,000 barrels of oil Cumulative production from year 7 to year 12:Annual production rate = 20,000 barrels of oil per day × 365 days Annual production rate = 7,300,000 barrels of oil per year Cumulative production from year 7 to year 12 = 7,300,000 barrels of oil per year × 6 years Cumulative production from year 7 to year 12 = 43,800,000 barrels of oil.

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Answer:

the output of the IF amplifier consist of 675 kHz

Explanation:

Given the data in the question;

AM signal carrier frequency \(_{RF\)  = 460 kHz

Local oscillator frequency\(_{lo\) = 1135 kHz

Now, The output of the IF amplifier consists of difference of local oscillator frequency & AM carrier signal frequency;

FREQUECY\(_{IF\) = FREQUECY\(_{lo\) - FREQUECY\(_{RF\)

so we substitute in our given values

FREQUECY\(_{IF\) = 1135 kHz - 460 kHz

FREQUECY\(_{IF\) = 675 kHz

Therefore, the output of the IF amplifier consist of 675 kHz

For external force convection calculation, the characteristic length for a circular cylinder or a sphere in a flow process over the surface is taken to be the diameter. This is because the diameter is the characteristic length used to characterize the Nusselt number for a cylinder or a sphere.

The Nusselt number (Nu) is a dimensionless parameter used to define the ratio of convective heat transfer to conductive heat transfer across (normal to) a boundary surface. The characteristic length (L) for the Nusselt number of a particular geometry is used to define the length scale, and it is an essential factor for calculating the Nusselt number.

For a cylinder or a sphere in external forced convection, the diameter (D) is used as the characteristic length (L) for Nu calculation because of its symmetry. In this case, the Nusselt number is calculated as

Nu = 0.3 + (0.62 x Ra x 0.5 x Pr x (1/3)) / (1 + (0.4 / Pr)x (2/3)) x 0.25

Where Ra is the Rayleigh number, which is the ratio of the buoyancy force to the viscous force, and Pr is the Prandtl number, which is the ratio of momentum diffusivity to thermal diffusivity.

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Answer: The Republican

Explanation:

The power factor of the circuit with R = 8 Ω and two capacitors with reactance -j2 Ω each is 0.788, indicating a lagging power factor.

To determine the power factor for the given circuit, we need to first calculate the impedance of the circuit.

The circuit has three impedance, R = 8 Ω, and two capacitors with reactance -j2 Ω.

To find the total impedance Z of the circuit, we need to add the impedance of the components in series.

The reactance of capacitors adds in series as if they were resistances in parallel, so we can calculate it using the formula:

1/Zc = 1/jwC = -j/(wC)

where w is the angular frequency (in radians/second) and

C is the capacitance (in farads).

Let's assume that the frequency of the AC source is 50 Hz, which corresponds to an angular frequency of w = 2*π*50 = 314.16 rad/s.

The impedance of the circuit can be calculated as follows:

Z = R + Zc1 + Zc2

Z = 8 - J/(wC) - J/(wC)

Z = 8 - J(1/(314.162*10⁻⁶) + 1/(314.162*10⁻⁶))

Z = 8 - J(3183.1 + 3183.1)

Z = 8 - J*6366.2

The magnitude of the impedance is |Z| = 6366.5 Ω, and the phase angle of the impedance is θ = -39.26 degrees.

The power factor of the circuit is given by the cosine of the phase angle, so:

PF = cos(θ)

PF = cos(-39.26)

PF = 0.788

Since the power factor is positive, we know that it is a lagging power factor.

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