a control volume is a system that group of answer choices allows a transfer of matter across its boundary. always has a constant volume always contains the same matter. does not interact in any way with its surroundings.

Answer:

c.

the ocean carbon cycle

Explanation:

Ocean Exploration

Edge 2020

Answer:

C. The ocean carbon cycle

Explanation:

This was the answer on edge

Answer:

1. A hiking

2. C

3. B

4. D

5. E

Answer:

b. between 2 s and 4 s

Explanation:

2-4 was both 3m/s

Since the magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s, the emf induced in the coil is -5.65 V

The induced emf in the coil is given by ε = -NΔΦ/Δt where

Since ε = -NΔΦ/Δt

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

Substituting the values of the variables into the equation, we have

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)

ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)

ε = -2(96 Wb)/34 s

ε = -192 Wb/34 s

ε = -5.65 Wb/s

ε = -5.65 V

So, the emf induced in the coil is -5.65 V

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The electrical action generated by a non-electrical source, measured in volts. The emf induced in the coil is -564.7 V.

The electrical action generated by a non-electrical source, measured in volts, is referred to as emf or electromotive force. Devices, such as batteries or generators, generate an emf by converting various sources of energy into electrical energy.

The emf induced in a coil is given by

\(\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}\)

where

ΔΦ is the change in magnetic flux, Δt is the change in time, and N is the number of loops.

Given that the initial magnetic flux is -58 Wb while the final magnetic flux is 38 Wb. Also, the change in time is 0.34 seconds and the number of loops is 2. Therefore, the emf induced can be written as,

\(\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}\)

\(\varepsilon = \dfrac{-(2) \times [38-(-58)]}{0.34}\\\\\varepsilon = -564.7\rm\ V\)

Hence, the emf induced in the coil is -564.7 V.

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The acceleration of the object will be 13.33 m/s^2.

According to Newton's second law of motion,

The magnitude of Force is equal to the product of the mass of the body and the acceleration it is given ( or achieves ).

The units of force, mass and acceleration are Newton, kg and m/s^2 respectively.

In numerical terms,

Force = mass × acceleration

i.e. F = m × a

Given,

mass of the body = 15 kg

Force applied to the body = 200 N.

Putting these values in the equation,

200 = 15 × a

=> a = 200/15

=> a = 13.33 m/s^2.

Therefore, the acceleration of the given body will be 13.33 m/s^2.

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Answer:

negative at first.

Explanation:

It's important to disconnect the negative side at first, otherwise you can cause an electrical short if positive is removed first.

The difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Given data;

The speed of sound in wood,u= 3300 m/s

The speed of sound in air,v=330 m/sec

long plank of wood, L=33 m

The time period in the air was found as;

T₁ = 33 m / 330 m/sec

T₁= 0.1 sec

The time period in wood ;

T₂= 33 m / 3300 m/sec

T₂=0.01 sec

T = T₁ - T₂

T=0.1-0.01

T=0.09 sec

Hence, the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.

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Answer:

it's A

Explanation:

Answer:

Violet (Shortest Wave Length)

Explanation:

Violet waves have the highest frequencies. The highest frequencies have the shortest wave length.

a)  The acceleration of the object down the incline is given by: a = g(sinθ - μk cosθ)

b) The acceleration of the object down the incline is 4.53 m/s^2 when θ = 31° and μk = 0.25.

(a) The force of gravity acting on the object can be broken down into two components: the force perpendicular to the incline, which does not affect the object's motion down the incline, and the force parallel to the incline, which does affect the object's motion down the incline. The force parallel to the incline is equal to mg sinθ, where m is the mass of the object and g is the acceleration due to gravity.

The force of friction acting on the object is μk times the normal force, which is equal to mg cosθ. Therefore, the force of friction is μk mg cosθ.

The net force acting on the object down the incline is the force parallel to the incline minus the force of friction, which is:

Fnet = mg sinθ - μk mg cosθ

Using Newton's second law, Fnet = ma, where a is the acceleration of the object, we can solve for the acceleration:

a = (mg sinθ - μk mg cosθ) / m

Simplifying this expression, we get:

a = g(sinθ - μk cosθ)

(b) Substituting θ = 31° and μk = 0.25 into the expression we derived in part (a), we get:

a = 9.81 m/s^2 (sin31° - 0.25 cos31°)

a = 4.53 m/s^2

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Answer:

The answer would be the last option (the one with the arrow pointing sideways)

Explanation:

The arrow lost it's acceleration and is starting to go downwards but it isn't a straight slope down

According to Boyle's Law, there is an inverse relationship between pressure and gas volume.

Therefore, option b. There is an inverse relationship between pressure and gas volume is the correct answer.

Boyle's Law is defined as the principle that explains the relationship between the volume and pressure of a gas at a constant temperature. It is formulated by Robert Boyle, an Irish physicist and chemist, in the 17th century. Boyle's Law states that the pressure of a given amount of gas is inversely proportional to its volume, provided the temperature remains constant.

Mathematically, it can be expressed as

P₁V₁ = P₂V₂,

where P₁ and V₁ are the initial pressure and volume of the gas, respectively, and P₂ and V₂ are the final pressure and volume of the gas. Therefore, option b. There is an inverse relationship between pressure and gas volume is the correct answer.

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Answer:carbon

Explanation:

Answer:

a)  E_{z} = 0, b) E_{z} = 0, c)    z = 1.73 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)], d)   \(E_{max}\)Emax = 9.7  10¹⁰ N / C

Explanation:

For this exercise we use the expression

          E = k ∫ dq / r²

By applying this expression to our problem of a ring of radius R, with a perpendicular axis in the z direction, we can calculate the electric field for a small charge element

          dE = k dq / r²

In the attachment we can see a diagram of the electric field, it is observed that the fields perpendicular to the z axis cancel and the field remains in the direction of the axis

           d\(E_{z}\)= dE cos φ

we substitute

         E_{z} = k∫  \(\frac{dq}{r^2}\)  cos φ

let's write the expressions

          r² = R² + z²

          cos φ = z / r

we substitute in the integral, where we see that the load differential does not depend on the distance and the value of the total load is + Q

          E_{z} = k  \(\frac{1}{ (R^2 +z^2) } \ \frac{z}{ (R^2 + z^2)^{1/2} }\) ∫  dq

          E_{z} = k Q  \(\frac{z}{ (R2+z^2)^{3/2} }\)  

This is the expression for the electric field in the axis perpendicular to the ring, we analyze this expression to answer the questions

a) the magnitude of the field at z = 0

         E_{z} = 0

b) the magnitude of the field for z = inf

        when z »R the expression remains

          E_{z} = k \(\frac{z}{z^{3} }\) Q

          E_{z} = k Q \(\frac{1}{z^2}\)

therefore when the value of z = int the field goes to E_{z} = 0

c) In value of z for which the field is maximum.

    We have an extreme point when the first derivative is equal to zero

     \(\frac{dE_z}{dz } = k Q [ (R^2 +z^2)^{3/2} - z \ 3 \frac{z}{ (R^2 +z^2)^{1/2} } = 0\)

we solve

    (R² + z²)^{ 3/2} = 3 z² /(R² +z²) ^{1/2}

    (R² + z²)² = 3z²

    r² + z² = √3    z

    z² –1.732 z + R² = 0

we solve the quadratic equation

       z = [1.732 ± \(\sqrt{3 - 4R^2}\)]/ 2 = [1.73 ± 1.73 \(\sqrt{ 1 - \frac{4 R^2}{3} }\)   ] / 2

       z = 0.865 [1 ± \(\sqrt{1 - \frac{4R^2}{3} }\)]

Therefore there are two points where the field has an extreme point one, one is a maximum and the other a minimum, as we have already determined a minimum at z = 0 the maximum point must be

  z = 0.865 [1 + \(\sqrt{1 - \frac{4R^2}{3} }\)]

d) the value of Emax

         z₁ = 0.865 [1+\(\sqrt{1 - \frac{4 \ 0.04^2}{3} }\)) = 1.73 [1 + √0.99786]

          z₁ = 1.729 m

         z₂ = 0.865 [1 - √0.99786 ]

         z₂ = 0.0011 m≈ 0

for which the field has a maximum value substituting in equation 1

            \(E_{max} = 9 10^9 \ 9 \ \frac{1.729}{(0.04^2 + 1.729^{3/2})}\)

            \(E_{max}\) = 81 10⁹   \(\frac{1.729}{1.4408}\)

            \(E_{max}\)Emax = 9.7  10¹⁰ N / C

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

According to Newton's Third Law of Motion, the forces exerted by the car and the truck on each other when the car hits the large truck are equal. Despite the forces being equal, the truck, due to its larger mass, will experience less acceleration and appear to move less.

The subject you're asking about is a fundamental concept in Physics, specifically Newton's Third Law of Motion. According to Newton's Third Law of Motion, when a car hits a large truck, the forces they exert on each other are equal. This law states that 'For every action, there is an equal and opposite reaction.' Therefore, the correct statement is, 'The car and the truck exert equal forces on each other.' However, because the truck has a much greater mass than the car, it will feel less acceleration and appear to move less, even though the force exerted on it is equal to that exerted by it on the car.

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Answer: False.Machine efficiency is a measure of how much work is produced by a machine compared to how much energy is required to operate the machine.

The ratio of useful output work divided by the total input work is known as machine efficiency. This number is frequently expressed as a percentage (100 x work output / work input).Example:

For example, if you lift a 50-pound weight 10 feet in the air using a pulley, the work done is 500 foot-pounds. However, if it took 600 foot-pounds of energy to lift the weight, the pulley system's efficiency would be calculated as follows: 500/600 = 0.83 or 83 percent.

The efficiency of a machine is always less than one, in general. It is defined as the ratio of output energy to input energy. Because of losses due to friction and other variables, the output energy is always less than the input energy. As a result, the efficiency of a machine is always less than one.Answer: False.

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Answer:

The foil makes the microwave spark it can smoke up and catch fie.

Explanation:

-The aluminum foil's sharp edges are what causes the fire, smoke, and sarks.

- Hope This Helps!

-Justin:)

Answer:

itll spark and catch fire

Explanation:

Non-crystalline ceramics deform by viscous flow instead of dislocation motion, True

Ceramics are inorganic compounds. They can be non-metallic or solid materials that can be comprised of metals, non-metal or atoms. Ceramics are known are hard and strong in compression but weak in tension and shearing, these materials are also known for their brittle properties.

Ceramics exits in two major types, these are: crystalline ceramics and non-crystalline ceramics. Crystalline ceramics are those that can easily be shaped to situ, formed with powders and sintered to form a solid body.

On the other hand non-crystalline ceramics are more of glass and formed through melting. They have no regular crystalline structure, and also have no slip or dislocations in them

Non-crystalline ceramics when deforming, they allow ions to slide past each other, hence deforms by breaking and reforming bonds. A condition known as viscous flow.

Thus, the statement given is True, option a is correct.

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Answer:

Light energy

Explanation:

This happens by means of chlorophyll combining with the carbon, from carbon dioxide, and the hydrogen and oxygen, from water, to form carbohydrates

Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

The net force on particle  \(\(q_3\)\)  due to particles \(\(q_1\)\) and  \(\(q_2\)\)  can be determined using Coulomb's Law.

The force between two charged particles is given by \(\(F = \frac{{k \cdot |q_1 \cdot q_2|}}{{r^2}}\)\), where k is the electrostatic constant \((\(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2\))\), \(\(|q_1|\)\) and \(\(|q_2|\)\) are the magnitudes of the charges, and r is the separation distance between the charges. First, let's calculate the force between \(\(q_1\)\) and  \(\(q_2\)\)  using their magnitudes and the given separation distance of \(\(0.300 \, \text{m}\)\):

\(\[F_{12} = \frac{{k \cdot |q_1 \cdot q_2|}}{{r_{12}^2}} = \frac{{(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2) \cdot (28.1 \times 10^{-6} \, \text{C}) \cdot (25.5 \times 10^{-6} \, \text{C})}}{{(0.300 \, \text{m})^2}} = -3.58 \, \text{N}\]\)

Next, let's calculate the force between \(\(q_2\)\) and \(\(q_3\)\) using their magnitudes and the given separation distance of \(\(0.300 \, \text{m}\)\):

\(\[F_{23} = \frac{{k \cdot |q_2 \cdot q_3|}}{{r_{23}^2}} = \frac{{(8.99 \times 10^9 \, \text{N m}^2/\text{C}^2) \cdot (25.5 \times 10^{-6} \, \text{C}) \cdot (47.9 \times 10^{-6} \, \text{C})}}{{(0.300 \, \text{m})^2}} = 9.06 \, \text{N}\]\)

The net force on  \(\(q_3\)\)  is the vector sum of the forces \(\(F_{12}\)\) and \\(F_{23}\)\). Since both forces are directed towards \(\(q_3\)\), we can add their magnitudes:

\(\[F_{\text{net}} = |F_{12}| + |F_{23}| = 3.58 \, \text{N} + 9.06 \, \text{N} = 12.64 \, \text{N}\]\)

Therefore, the net force acting on particle \(\(q_3\)\) is \(\(12.64 \, \text{N}\)\) in the direction towards particle  \(\(q_3\)\) .

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Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

\( x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2} \)   (1)

Where:

\( x_{f}\): is the final position in the horizontal direction = 80 m

\( x_{0}\): is the initial position in the horizontal direction = 0

\(v_{0_{x}}\): is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

\( t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s \)

b) The height of the hill is given by:

\( y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} \)

Where:

\( y_{f}\): is the final position in the vertical direction = 0

\( y_{0}\): is the initial position in the vertical direction =?

\(v_{0_{y}}\): is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

\( y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m \)  

I hope it helps you!

Answer:

Neil Armstrong

Explanation:

Answer:

Neil Armstrong.

Explanation:

. PLEASE GIVE BRAINLIEST.

Answer:

79%.

Explanation:

Step 1:

Data obtained from the question. This include:

Input temperature = 100 °C.

Output temperature = 22 °C.

Step 2:

Conversion of celsius temperature to Kelvin temperature.

Temperature (Kelvin) = temperature (celsius) + 273

T (K) = T (°C) + 273

Input temperature = 100 °C.

Input temperature = 100 °C + 273 = 373 K.

Output temperature = 22 °C.

Output temperature = 22 °C + 273 = 295 K.

Step 3:

Determination of the efficiency of the locomotive.

Input temperature = 373 K.

Outpu temperature = 295 K.

Efficiency =...?

Efficiency = output /input x 100

Efficiency = 295/373 x 100

Efficiency = 79.1 ≈ 79%

Therefore, the efficiency of the locomotive is approximately 79%.

the mix of the answer is tin