Answer:
0.432 drinks are toxic
Explanation:
The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):
1.11g/mL * (0.1mL / kg) = 0.111g/kg
If the victim weighs 85kg, its letal dose is:
85kg * (0.111g/kg) = 9.435g of ethylene glycol
Using the concentration of ethylene glycol in the liquid:
9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.
The drinks are:
43.2g of liquid * (1 drink / 100 g) =
0.432 drinks are toxicMeasurements show that the energy of a mixture of gaseous reactants increases by 190 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined easurements show that the energy of a mixture of gaseous reactants increases by during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 143kJ of work is done on the mixture during the reaction.that of work is done on the mixture during the reaction.
The enthalpy or heat content of a system can be defined as the sum of the internal energy and the pressure volume energy of the system. It is denoted by H. The energy change of mixture is 47 kJ.
The transference of energy may take place in the form of work if the system and surroundings have different pressures. According to international conventions, work done on the system is positive and work done by the system is negative.
The enthalpy change is:
ΔH = ΔU + PΔV
190 = ΔU + 143
ΔU = 47 kJ
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Draw the Lewis electron dot
structure for COCI2.
What is the VSEPR shape of this
particle? PLS HELP
Answer:
Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry
Question 2 (1 point) 6. Rebecca has written a story. Which sentence from the story shows that it is fiction? I got Max when he was a kitten. He is black with a white spot on his chest. Max told me that he got his white spot by jumping through the snow. His spot makes him the cutest cat in the world! He is black with a white spot on his chest I got Max when he was a kitten Max told me that he got his white spot by jumping through the snow. His spot makes him the cutest cat in the world!
What are the major species present in 0.250 M solutions of each of the following acids? Calculate the pH of each of these solutions.a.HOC6H5b. HCN
The pH of a 0.250 M solution of HOC6H5 is 2.92 and HCN is 5.96
a. HOC6H5, or benzoic acid, is a weak acid that partially dissociates in water to form H+ and C6H5COO- ions. The dissociation reaction is
HOC6H5 ⇌ H+ + C6H5COO-
To determine the pH of a 0.250 M solution of benzoic acid, we need to calculate the concentration of H+ ions in solution. The equilibrium expression for the dissociation reaction is:
Ka = [H+][C6H5COO-]/[HOC6H5]
where Ka is the acid dissociation constant for benzoic acid. The value of Ka for benzoic acid is 6.5 × \(10^-5.\)
We can assume that the initial concentration of H+ ions in the solution is zero. At equilibrium, let x be the concentration of H+ ions in solution and 0.250 - x be the concentration of C6H5COO- ions in solution. Then:
Ka = x(0.250 - x)/0.250
Solving for x, we get:
x = 1.21 × \(10^-3\) M
the pH of a 0.250 M solution of benzoic acid is:
pH = -log[H+] = -log\((1.21 × 10^-3)\) = 2.92
b. HCN, or hydrocyanic acid, is also a weak acid that partially dissociates in water to form H+ and CN- ions. The dissociation reaction is:
HCN ⇌ H+ + CN-
To determine the pH of a 0.250 M solution of HCN, we need to calculate the concentration of H+ ions in solution. The equilibrium expression for the dissociation reaction is:
Ka = [H+][CN-]/[HCN]
where Ka is the acid dissociation constant for HCN. The value of Ka for HCN is 4.9 ×\(10^-10\).
We can assume that the initial concentration of H+ ions in the solution is zero. At equilibrium, let x be the concentration of H+ ions in solution and 0.250 - x be the concentration of CN- ions in solution. Then:
Ka = x(0.250 - x)/0.25
Solving for x, we get:
x = 1.1 × \(10^-6\) M
pH :- -log[H+] = -log\((1.1 × 10^-6)\)
= 5.96
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What mass of sucrose is needed to make 300.0 mL of a 0.5 M solution? (molar mass=
342.34 g/mol)
Use the following balanced equation to answer the questions below.
Answer:
A. 4.5 mol Mg(OH)₂
B. 6 mol NaOH
Explanation:
Let's consider the following balanced equation.
Mg(NO₃)₂ + 2 NaOH ⇒ Mg(OH)₂ + 2 NaNO₃
PART A
The molar ratio of NaOH to Mg(OH)₂ is 2:1. The moles of Mg(OH)₂ produced from 9 moles of NaOH are:
9 mol NaOH × 1 mol Mg(OH)₂/2 mol NaOH = 4.5 mol Mg(OH)₂
PART B
The molar ratio of NaOH to NaNO₃ is 2:2. The moles of NaOH needed to produce 6 moles of NaNO₃ are:
6 mol NaNO₃ × 2 mol NaOH/2 mol NaNO₃ = 6 mol NaOH
Chemistry Lab Determination of the Universal Gas Constant (R)
SHOW ALL WORK
Given:
Initial mass of butane lighter: 54.24g
Final Mass of Butane Lighter: 54.01g
Temperature of water: 23.0°C
Volume of gas collected: 100.0mL
FIND:
Barometric pressure of room: 766.86 mmHg CONVERTED TO atm
Vapor pressure of water at room temperature(PH2O) (IN atm)
FIND:
Mass difference if butane lighter in grams
Moles of Butane gas collected in moles of C4H10
Partial pressure if butane gas in atm
Converted temperature of water in Kelvin
Converted volume of gas collected in Liters
Experimental value of R in Latm/molk
Accepted value of R in Latm/molk
Percent error in experimental value of R in %
CONCLUSION QUESTIONS:
1. List at least 3 factors that either did it could contribute to the percent error
2. Should the value of R go up or down if the gas had not been corrected for the partial pressure of water. Why?
3. How could this experiment be repeated to increase the accuracy, or in other words, decrease the percent error?
NOTE: LET ME KNOW IF YOU WANT A PICTURE OF THE LAB INSTRUCTIONS TO HELP SOLVE
ALSO SHOW ALL WORK PLS
To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.
Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.
Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.
Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.
Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.
Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).
Accepted value of R:The accepted value of R is 0.0821 Latm/molK.
The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.
Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.
If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.
To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.
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please help!!
62.4 mL of an H2SO3 solution
were titrated with 65.25 mL of a
0.235 M KOH solution to reach the
equivalence point. What is the
molarity of the H2SO3 solution?
The concentration of H₂SO₃ solution is equal to 0.123 M.
What is a neutralization reaction?A neutralization reaction is described as a reaction in which an acid and base react to form salt and water. When a strong acid will react with a base then the salt which is formed can be neither acidic nor basic.
When H₂SO₃ (a strong acid) reacts with KOH, the resulting salt is K₂SO₃ and water.
H₂SO₃ + 2KOH → K₂SO₃ + 2H₂O
Given, the concentration of KOH = 0.235 M
The volume of the KOH = 65.25 ml = 0.06525 L
The number of moles of KOH, n = M × V = 0.235 × 0.06525 = 0.0153 M
The volume of the H₂SO₃ = 62.4 ml = 0.0624 L
The number of moles of H₂SO₃, n = 0.0153/2 = 0.00767 mol
The concentration of H₂SO₃ =0.00767/0.0624 = 0.123 M
Therefore, the molarity of H₂SO₃ is 0.123 M.
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To format the electron configuration correctly make sure to superscript where needed, do not add spaces to your answer and italics are not possible in this module. Write the ground-state electron configuration for calcium, Ca. You may write either the full or condensed electron configuration.
Answer:
\(1s^{2}2s^{2} 2p^{6}3sx^{2}3p^{6} 4s^{2}\) [full configuration]
Explanation:
Calcium has 20 electrons in its nucleus, and by virtue of its position on the periodic table (fourth row, second column), it is an s-block element with its entire lower orbital filled. it has two valence electrons.
Therefore, its configuration is:
\(1s^{2}2s^{2} 2p^{6}3sx^{2}3p^{6} 4s^{2}\)
To condense this, you can utilize Argon's stable configuration before \(4s^{2}\) to show that all orbitals before 4s are filled.
I hope this was helpful.
Question: Which is the last step in excavation of the skeletal remains?
Answer options:
A: defining the investigation area
B: identifying the layout of the remains
C: exposing the remains
D: screening of the soil
E: lifting the remains
Answer:
B
Explanation:
No explanation needed for it i got 100% on it
Lifting the remains is the last step in the excavation of the skeletal remains. Therefore, option E is correct.
What is the excavation of the skeletal remains?In archaeology, excavation can be described as the exposure, processing, and recording of archaeological remains. An excavation site or "dig" can be the area being studied. These locations are from one to various areas at a time while a project can be conducted over weeks to several years.
Excavation involves the recovery of various types of data from a site. This data includes ecofacts, artifacts, features, and archaeological context. Before excavating, the presence of remains can often be suggested by remote sensings, such as ground-penetrating radar.
During excavation, stratigraphic excavation removes phases of the site one layer at a time and keeps the timeline of the material remains consistent. This is done through mechanical means and the soil is processed via methods like mechanical sieving or water flotation.
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Please help me thanks so much
Answer:
the answer is in the next one I just answered
98.96g/mol of CH2O what will be the chemical formula
How does the number of atoms or molecules in a system affect its thermal energy?
A. A system with fewer atoms and molecules has more thermal energy.
B. A system with more atoms and molecules has more thermal energy.
C. The number of atoms or molecules does not affect the thermal energy of a system.
D. Thermal energy increases as the atoms and molecules in a system move more.
Answer:
D. Thermal energy increases as the atoms and molecules in a system move more.
Explanation:
Thermal energy is a form of kinetic energy possessed by molecules of a system. The measure of this kinetic energy in an atom is called heat.
The average kinetic energy of a system is the temperature.
According to the kinetic theory, the more the particles move, the more their thermal energy. Thermal energy is often predicated on the velocity of the particles of the medium.Perform the followingmathematical operation, andreport the answer rounded tothe correct number ofsignificant figures.43.6 /21.2 = [?]=
Answer:
\(2.06\)Explanation:
Here, we want to perform the given division operation and give the answer to the right significant figures
The right significant figures here would be the least significant figures present in the division
Mathematically, we have this as:
\(\frac{43.6}{21.2}\text{ = 2.06}\)Sample 2: Initial volume of buret (mL)
We have that the Initial volume of buret (mL) is give as
\(V_1=(ml)\)From the question we are told
Sample 2: Initial volume of buret (mL)
Initial volumeGenerally In ital volume is a relative terminology as you cant have a initial without having a final
the initial volume of the brute speaks to a gauge of the buret in comparison to another gauge of the buret
From the image the buret has its present gauge at 4.1(mL)
and this might be either the initial or the final
But we ascertain that as the final volume , and as the image looks to start at a gauge of 3(ml)
Therefore
The initial volume of buret is at
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What volume of CO2(g), measured at STP is produced if 15.2 grams of CaCO(s) is heated?
Answer:
Volume = 3.4 L
Explanation:
In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:
CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)
Now, let's calculate the number of moles in 15.2 g CaCO₃:
mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)
= \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)
= 0.1518 moles
From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.
Hence, from the formula for the number of moles of a gas, we can calculate the volume of CO₂:
mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)
⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)
⇒ Volume = 0.1518 × 22.4
= 3.4 L
Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.
Which of the following represents the velocity of a moving object?
Select one:
40 m north.
40.
40 m/s north.
40 m/s.
Answer:
The correct answer would be 40 m/s
Explanation:
The reason 40 m/s is the correct answer is because m/s stands for meters per second.
Hope this helps you with what you're working on! :D
Answer:
40 m/s north
Explanation:
Velocity is a vector quantity, so it have both direction and magnitude.
_ Na3PO4 + _ HCl NaCl + _ H3PO4
Answer:
Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄
The coefficients are: 1, 3, 3, 1
Explanation:
_Na₃PO₄ + __HCl —> __NaCl + _H₃PO₄
The above equation can be balance as follow:
Na₃PO₄ + HCl —> NaCl + H₃PO₄
There are 3 atoms of Na on the left side and 1 atom on the right side. It can be balance by writing 3 before NaCl as shown below:
Na₃PO₄ + HCl —> 3NaCl + H₃PO₄
There are 3 atoms of Cl on the right side and 1 atom on the left side. It can be balance by writing 3 before HCl as shown below:
Na₃PO₄ + 3HCl —> 3NaCl + H₃PO₄
Now, the equation is balanced.
The coefficients are: 1, 3, 3, 1
4. What are two ways that you experience gases or gaspressures in real life?
ANSWER
EXPLANATION
Gas pressures are experienced in the following;
Motor tyres
Lungs
In tyre, flat tire takes up less space than an inflated tyre
Lungs expand as they fill with air. Exhaling decreases the volume of the lungs
1.Which of the following is the nature of sound wave?
Answer:
the answer is longgitudinal
Select the correct terms to complete this statement about charged particles.
Like charges attract | repel, and opposite charges attract repel. According to Coulomb's law, as the distance between two charged particles decreases, the force between the particles decreases I increases. As the magnitude of the charges decreases, the force decreases | increases.
Like charges repel each other, while opposite charges attract each other. This principle is one of the fundamental aspects of electrostatics. According to Coulomb's law, the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
As the distance between two charged particles decreases, the force between them increases. This is because the closer the particles are, the stronger the electric field they create, leading to a stronger force of interaction.
On the other hand, as the magnitude of the charges decreases, the force between the particles also decreases. This is because the force is directly proportional to the product of the charges. If one or both of the charges are smaller, the force they exert on each other will be weaker.
In summary, according to Coulomb's law, decreasing the distance between charged particles increases the force between them, while decreasing the magnitude of the charges decreases the force. This understanding of the relationship between charge, distance, and force is crucial in explaining the behavior of charged particles and the interactions between them.
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If you had clothes made of graphene, would it be soft or scratchy? Thanks
Graphene is the perfect material to improve a piece of clothing due to its high thermal and electrical conductivity. Maternity, utility, and intelligent clothing products can benefit from the good heat retention property and electrical conductivity.
Can a fabric composed of graphene be produced?Graphene may be incorporated directly into the fibre or applied as a coating on the textile's surface. The coating approach is less complicated, more economical, and perfect for a variety of textiles and related high-value materials. Textiles with graphene coatings have the potential to be perfect for wearable technology.
Hypoallergenic, non-cytotoxic, and non-toxic describe graphene. One layer of carbon atoms makes up graphene, which is 200 times stronger than steel.
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Do Some vertebrates' offspring develop inside the mothers body.
Answer: Some reptiles, amphibians , fish and invertebrates carry their developing young inside them.
Explanation: Some of them :)
At constant temperature, the behavior of a real gas more closely approximates that of an ideal gas as its volume increases due to which of the following?
At Constant temperature, the behavior of a Ideal gas more closely approximates that of an ideal gas as its volume increases due to the average distance between the molecule becomes greater.
According to the Molecular Theory of gases, at constant temperature the behavior of a sample of a real gas more closely approximates that of an ideal gas as its volume is increased because the average distance between molecules becomes greater. The temperature did not change, so the average kinetic energy and average molecular speed did not change. The molecule size does not change either, so the molecule could not have expanded. The distance between the molecules increases causing a decrease in intermolecular forces, thus reducing the interaction between the molecules.
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When excess hydrogen is passed over 4.5g of heated oxide of metal X, 3.6 g of X are finally left. Calculate the RAM of X and the minimum volume of hydrogen (at stp) used in this reaction XO + H₂(g) → X + H₂O(g)
Answer:
We can use the information given in the problem to calculate the RAM (relative atomic mass) of X and the minimum volume of hydrogen used in the reaction.
First, we need to calculate the mass of oxygen in the oxide XO:
mass of oxygen = mass of oxide - mass of metal
mass of oxygen = 4.5 g - 3.6 g
mass of oxygen = 0.9 g
Next, we can use the mass of oxygen to calculate the number of moles of oxygen:
moles of oxygen = mass of oxygen / molar mass of oxygen
moles of oxygen = 0.9 g / 16.00 g/mol
moles of oxygen = 0.05625 mol
Since the oxide XO is formed by the combination of X and oxygen, we can assume that the mass of X in the oxide is equal to the mass of the oxide minus the mass of oxygen:
mass of X = mass of oxide - mass of oxygen
mass of X = 4.5 g - 0.9 g
mass of X = 3.6 g
We can use the mass of X and the number of moles of oxygen to calculate the number of moles of X:
moles of X = mass of X / atomic mass of X
moles of X = 3.6 g / atomic mass of X
Combining this with the stoichiometry of the reaction, which tells us that 1 mole of XO reacts with 1 mole of H2 to produce 1 mole of X and 1 mole of H2O, we can write:
moles of H2 = moles of X / 1 = (3.6 g / atomic mass of X) / 1
To determine the minimum volume of hydrogen at STP (Standard Temperature and Pressure), we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature. At STP, the pressure and temperature are 1 atm and 273 K, respectively, and the universal gas constant is 0.08206 L atm/(mol K).
Substituting the given values and solving for V, we get:
V = nRT/P = [(3.6 g / atomic mass of X) / 1] * (0.08206 L atm/(mol K)) * 273 K / 1 atm
Simplifying and solving for the atomic mass of X, we get:
atomic mass of X = (3.6 g / V) * (1 mol/2 mol of H2) * (1 mol of XO/1 mol of X) * (16.00 g/mol of oxygen + atomic mass of X)
Substituting the given values, we get:
atomic mass of X = (3.6 g / V) * (0.5) * (1 / 1) * (16.00 g/mol + atomic mass of X)
Multiplying out, we get:
atomic mass of X = (1.8 g / V) * (16.00 g/mol + atomic mass of X)
Solving for atomic mass of X, we get:
atomic mass of X = (1.8 g / V) * 16.00 g/mol / (1 - 1.8 g / V)
Substituting V = 22.4 L (the volume of 1 mole of gas at STP), we get:
atomic mass of X = (1.8 g / 22.4 L) * 16.00 g/mol / (1 - 1.8 g / 22.4 L)
atomic mass of X ≈ 56.1 g/mol
Therefore, the RAM of X is approximately 56.1 g/mol, and the minimum volume of hydrogen used in the reaction is approximately 22.4 L at STP.
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A backpacker wants to carry enough fuel to heat 2.7 kg of water from 21 ∘C to 100.0 ∘C.
If the fuel he carries produces 36 kJ of heat per gram when it burns, how much fuel should he carry? (For the sake of simplicity, assume that the transfer of heat is 100 % efficient.)
Answer:
24.8g of fuel
Explanation:
while
\(C_{water}=4180j/kg*k\)
\(m=\frac{2.7*4180*(100-21)}{36*1000}=24.8g\)
A patient provides you a prescription for Percocet, a medication he has never taken before and his insurance company is requiring prior authorization. What steps should be taken?
To ensure insurance coverage for Percocet, it is essential to verify the patient's insurance coverage and check if prior authorization is required. If prior authorization is necessary, gather the required information, complete the authorization form, and submit it to the insurance company.
When a patient presents a prescription for a medication like Percocet, which requires prior authorization from the insurance company, several steps should be taken:
Verify Insurance Coverage: Check the patient's insurance coverage and confirm if prior authorization is required for Percocet. This can be done by contacting the insurance company or using an online portal provided by the insurer.
Review Prior Authorization Criteria: Understand the specific requirements set by the insurance company for obtaining prior authorization for Percocet. This may include documentation, medical history, and supporting evidence to justify the need for the medication.
Gather Patient Information: Collect relevant patient information, including medical records, diagnosis, and any previous treatments. This information will be used to support the prior authorization request.
Complete Prior Authorization Form: Fill out the necessary prior authorization form provided by the insurance company. Ensure that all required information is accurately entered, including the patient's details, prescriber information, and supporting documentation.
Submit the Request: Send the completed prior authorization form along with any supporting documents to the insurance company. This can be done electronically through their designated channels or by fax/mail, following their specified process.
Follow Up: Monitor the progress of the prior authorization request. Follow up with the insurance company to confirm receipt, inquire about any additional information needed, and track the status of the request.
Inform the Patient: Keep the patient informed about the prior authorization process, estimated timelines, and any potential out-of-pocket costs they may incur.
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The volume of a sample of helium is 4.5ml at 20 degrees Celsius and 203 kPa. What will it’s volume be
The new volume of the helium sample at 50°C and 203 kPa would be 6.16 mL.
How to determine the new volume of the helium sample.First we need to use the ideal gas law equation:
PV = nRT
Where
P is the pressureV is the volumen is the number of moles of gas R is the gas constant T is the temperature in KelvinTo solve for the new volume, we can use the following steps:
Convert the initial temperature to Kelvin:
T = 20°C + 273.15 = 293.15 K
Use the initial conditions to calculate the number of moles of helium:
n = PV/RT = (203 kPa x 4.5 mL) / (8.314 J/(mol·K) x 293.15 K) = 0.00073 mol
Use the new conditions to solve for the new volume:
V = nRT/P = (0.00073 mol x 8.314 J/(mol·K) x (273.15°C + 50°C)) / 203 kPa = 6.16 mL
Therefore, the new volume of the helium sample at 50°C and 203 kPa would be 6.16 mL.
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chemistry question please help
Answer:
It was deflected by a magnet charged particles
Differences between voltage, current and resistance?
Answer:
Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.
Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.
Hope this helps!