A container has .25 moles of CO, 1.25 moles of NH 3 , and .75 moles Kr. If the pressure of Carbon
Monoxide is 440 torr, what is the total pressure and the pressure of the other two gasses?

Answer:

Second one

Explanation:

In the given structure of the resonance hybrid, there are three contributing resonance structures. Resonance Structure 1, Resonance Structure 2 and Resonance Structure 3.

Resonance Structure 1: Carbon 1 has a double bond with Carbon 2, and Carbon 2 has a double bond with Carbon 3. Carbon 3 has a double bond with Carbon 4, and Carbon 4 has a double bond with Oxygen. Carbon 1 and Carbon 3 both have a partial negative charge.

Resonance Structure 2: Carbon 1 has a double bond with Carbon 2, and Carbon 2 has a double bond with Carbon 3. Carbon 3 has a double bond with Carbon 4, and Carbon 4 has a double bond with Oxygen. Carbon 1 and Carbon 3 both have a partial negative charge.

Resonance Structure 3: Carbon 1 has a double bond with Carbon 2, and Carbon 2 has a double bond with Carbon 3. Carbon 3 has a double bond with Carbon 4, and Carbon 4 has a double bond with Oxygen. Carbon 1 and Carbon 3 both have a partial negative charge.

These three resonance structures contribute to the overall resonance hybrid.

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The resonance hybrid consists of three contributing resonance structures, including a dotted double bond and partial charges on certain carbon atoms.

The three contributing resonance structures for the given resonance hybrid with a 5-carbon chain are:

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The pH of a 0.01 M \(HNO_2\)(aq) solution is in which of the following ranges is option (A) Between 1 and 2.

To determine the pH range of a 0.01 M \(HNO_2\)(aq) solution, we need to consider the ionization of \(HNO_2\)and the equilibrium expression for its acid dissociation.

The given Ka (acid dissociation constant) for\(HNO_2\) is\(4.0 * 10^(-4),\) which indicates that \(HNO_2\) is a weak acid.

The acid dissociation reaction is as follows:

\(HNO_2\)(aq) ⇌ H+(aq) + NO2^-(aq)

Since the concentration of\(HNO_2\)is 0.01 M, and assuming x represents the concentration of H+ and \(NO2^-,\) we can set up the equilibrium expression:

Ka = [H+][NO2^-] / [\(HNO_2\)]

Since the concentration of \(HNO_2\) is much larger than the concentration of H+ and \(NO2^-,\), we can assume that the concentration of \(HNO_2\) remains approximately 0.01 M throughout the reaction.

Therefore, we can simplify the equilibrium expression as follows:

Ka ≈ [H+][\(NO2^-,\)] / 0.01 M

Since the concentration of \(HNO_2\) is constant and the concentration of H+ and \(NO2^-,\)are equal, we have:

\([H+]^2\) ≈ Ka * 0.01 M

Taking the square root of both sides, we get:

[H+] ≈ √(Ka * 0.01 M)

Now, we can calculate the approximate value of [H+]. Using the given Ka value (\(4.0 * 10^{(-4)\)), we have:

[H+] ≈ √(\(4.0 * 10^{(-4)\) * 0.01 M)

[H+] ≈ 0.02 M

To determine the pH, we take the negative logarithm (base 10) of [H+]:

pH ≈ -log10(0.02)

pH ≈ 1.7

Therefore, the pH of the 0.01 M \(HNO_2\)(aq) solution is between 1 and 2.

The correct answer is (A) Between 1 and 2.

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The pH of a solution depends on the concentration of hydrogen ions (H+) present.

In the case of HNO2, it is a weak acid and dissociates partially in water to give H+ and NO2-. The Ka value for HNO2 is 4.0 × 10^(-4). To find the pH of a 0.01 M HNO2 solution, we can use the formula for weak acids, pH = pKa + log([A-]/[HA]), where [A-] is the concentration of the conjugate base and [HA] is the concentration of the acid. Plugging in the values, we get pH = 3.77, which falls in the range of (B) Between 2 and 3. Therefore, the pH of a 0.01 M HNO2(aq) solution is between 2 and 3.
To determine the pH range of a 0.01 M HNO2(aq) solution, we can use the Ka expression. For HNO2(aq), Ka = 4.0 × 10^(-4). The Ka expression is Ka = [H+][NO2-]/[HNO2]. Since the initial concentration of HNO2 is 0.01 M, we can set up the equation as 4.0 × 10^(-4) = [x][x]/(0.01-x), where x is the concentration of H+ ions. Solving for x, we get x ≈ 6.3 × 10^(-3) M. Converting to pH, we have pH = -log(6.3 × 10^(-3)), which is approximately 2.2. Therefore, the pH of the 0.01 M HNO2(aq) solution falls in the range of (B) Between 2 and 3.

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From the balanced equation below the mole ratio of PCl3 to PCl5 is 1:1

\(PCl_{5} + PCl_{5}\) -------------------> \(PCl_{5}\)

Number of moles of \(PCl_{3}\) can be expressed as  1 mole

Number of moles of  \(Cl_{2}\) can be expressed as 1 mole

Number of moles of  \(PCl_{5}\) can be expressed as 1 mole

Mole ratio of \(PCl_{5}\) can be expressed as 1:1

The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.

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Answer:

All elements have protons and neutrons.

Explanation:

Sure, some standard norms of elements don't have neutrons present (like hydrogen), but different forms of hydrogen have neutrons. Neutrons can and are present in every element in the Periodic Table of Elements.

These factors contribute to the formation of a fine-grained microstructure, which can affect the material's mechanical properties.

The melt pool geometry and microstructure of Ti6Al4V with B additions processed by selective laser melting additive manufacturing can be explained as follows:

1. Melt pool geometry: When the Ti6Al4V alloy with B additions is processed using selective laser melting (SLM) additive manufacturing, a laser beam is used to selectively melt the metal powder layer by layer, resulting in the formation of a melt pool. The melt pool geometry refers to the shape and dimensions of this molten region.

2. Microstructure: The microstructure of a material refers to its internal arrangement of grains, phases, and other microstructural features. In the case of Ti6Al4V with B additions processed by SLM, the microstructure is influenced by the rapid solidification that occurs after the melting process. The cooling rate during SLM can lead to the formation of a fine-grained microstructure, which can have an impact on the material's mechanical properties.

3. Manufacturing: Selective laser melting (SLM) is an additive manufacturing process that involves building objects layer by layer using a laser to selectively melt metal powders. In the case of Ti6Al4V with B additions, SLM offers the advantage of producing complex shapes and structures with good mechanical properties.

4. 150: The number "150" mentioned in the question might refer to a specific parameter or condition related to the melt pool geometry and microstructure of Ti6Al4V with B additions processed by SLM. However, without further context, it is not possible to provide a specific explanation for this number.

In summary, the melt pool geometry and microstructure of Ti6Al4V with B additions processed by selective laser melting additive manufacturing can be influenced by factors such as the shape and dimensions of the melt pool, the rapid solidification process, and the cooling rate during SLM. These factors contribute to the formation of a fine-grained microstructure, which can affect the material's mechanical properties.

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Answer:

For this angular momentum, no quantum number exist

Explanation:

From the question we are told that

   The magnitude of the angular momentum is  \(L = 6\sqrt{\frac{h}{2 \pi} }\)

The generally formula for Orbital angular momentum is mathematically represented as

           \(L = \sqrt{(l * (l + 1)) } * \frac{h}{2 \pi}\)

Where \(l\) is the quantum number

now  

We can look at the given angular momentum in this form as

      \(L = 6\sqrt{\frac{h}{2 \pi} } = \sqrt{36} * \sqrt{\frac{h}{2 \pi}} }\)

comparing this equation to the generally equation for Orbital angular momentum

     We see that there is no quantum number that would satisfy this equation

Answer:

the products are more stable than the reactants

Explanation:

Stainless steel is the most common type of metal used for knives and is not susceptible to corrosion. Washing stainless steel knives with soap and water should be perfectly safe.

Metal is a material composed of atoms that are held together by metallic bonds. It is a solid material that is malleable and ductile, meaning it can be shaped and stretched without breaking. Metals are naturally occurring elements on the periodic table and can be found in nature. They have a shiny luster and are good conductors of heat and electricity. Metals are used in a variety of applications, from jewelry to construction. Depending on the type of metal, it may also be resistant to corrosion and weathering. Metals are also used in electronics, vehicles, and medical instruments. Examples of common metals include aluminum, iron, copper, and steel. Each type of metal has its own unique properties and can be used in various ways, from creating tools to making art. Metal is an essential material in today's society, and its importance and versatility will likely continue to grow in the future.

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Answer:

Select all that apply:

B

The number of reactant molecules and product molecules is even.

C and D

The reaction 2N2 + 3H2 → 2NH3 occurs.

The molarity of a solution of 12.9 g fructose and 31.0 g water is 1.26 M.

Molarity is the number of moles of solute dissolved in one liter of a solution. The formula to calculate molarity is:

Molarity (M) = moles of solute / liters of solution

To find the molarity of the given solution, we first need to determine the number of moles of fructose present. We can do this using the molar mass of fructose.

Molar mass of fructose = (6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol)= 180.18 g/mol

The number of moles of fructose present in 12.9 g can be calculated as:

Number of moles of fructose = mass of fructose / molar mass of fructose= 12.9 g / 180.18 g/mol= 0.0716 mol

Number of moles of water = mass of water / molar mass of water= 31.0 g / 18.02 g/mol= 1.722 mol

Now, we can calculate the total volume of the solution.

Total mass of the solution = mass of fructose + mass of water= 12.9 g + 31.0 g= 43.9 g

We can convert this to liters using the density of water.

Density of water = 1 g/mL= 1000 g/L43.9 g = 0.0439 L (volume of solution)

Now that we know the number of moles of fructose and water and the volume of the solution, we can calculate the molarity:

Molarity (M) = moles of solute / liters of solution= 0.0716 mol / 0.0439 L= 1.26 M

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The molecular formula of the compound is C6H12O6.

1) We know that;

1 mole of CO2 contains 6.02 X 10^23 atoms

x moles of CO2 contains 1.5 X 10^23 atoms

x = 1 mole X  1.5 X 10^23 atoms /6.02 X 10^23 atoms

x = 0.25  moles of CO2

2) 1 mole of pure Al has 27 g

x moles of Al has 5 g

x = 1 mole ×  5 g/ 27 g

x = 0.19 moles

If 1 mole of Al contains 6.02 X 10^23 atoms

0.19 moles of Al contains 0.19 moles  ×  6.02 X 10^23 atoms /1 mole

= 1.14 X 10^23 atoms

3) From 2Na + Cl2 ---> 2NaCl;

2 moles of Na produces 2 moles of NaCl hence 3 moles of Na will also produce 3 moles of NaCl.

4) The molar mass of K2SO4 is obtained from;

2(39) + 32 + 4(16) = 78 + 32 + 64 = 174 g/mol

Now;

Percentage by mass of K = 2(39)/ 174  ×  100/1 = 44.8%

Percentage by mass of S = 32/174 ×  100/1 = 18.4%

Percentage by mass of O = 4(16)/174 ×  100/1 = 36.8%

5) The reaction equation is;

4Al(s) + 3O2(g) ----> 2Al2O3

Total mass present =  162g + 144g = 306 g

Mass percent of Al =  162g/ 306 g ×  100/1 =52.9%

6)

C - 40/12     H -  6.71/1        O - 53.29/16

C - 3.33      H - 6.71            O - 3.33

Dividing through by the lowest ratio

C- 3.33/3.33     H - 6.71/3.33    O - 3.33/3.33

C - 1                  H - 2                 O - 1

The empirical formula is CH2O

Now;

[12 + 2(1) + 16] n = 180.16

30n = 180.16

n = 180.16/30

n = 6

The molecular formula is C6H12O6.

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For  question B, 2. the reaction is delayed until just before the balloon pops

For question  C, 1.the reaction can start right away

Based on the fact that the hydrogen-only swell contains immaculate hydrogen gas, whereas the blended swell contains both hydrogen and oxygen gasses.

When the fire is added, the hydrogen in both inflatables will burn, but within the hydrogen-only balloon, the response will take longer to reach unstable levels since there's no oxygen display to respond with the hydrogen.

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The net ionic equation for the reaction between silver(I) nitrate and potassium phosphate is Ag+ + PO43- → Ag3PO4.

The net ionic equation focuses on the species directly involved in the chemical reaction, excluding spectator ions that do not participate in the formation of the products. In this case, the reaction involves the combination of silver(I) nitrate (AgNO3) and potassium phosphate (K3PO4) to form silver(I) phosphate (Ag3PO4) and potassium nitrate (KNO3).

The balanced molecular equation for the reaction is:

3AgNO3(aq) + K3PO4(aq) → Ag3PO4(s) + 3KNO3(aq)

To write the net ionic equation, we need to consider the dissociation of the ionic compounds. Silver(I) nitrate dissociates into silver(I) ions (Ag+) and nitrate ions (NO3-), while potassium phosphate dissociates into potassium ions (K+) and phosphate ions (PO43-). However, since both silver(I) phosphate and potassium nitrate are soluble, they remain in their ionized forms in the solution.

The net ionic equation can be written by representing the species that undergo a change:

Ag+(aq) + PO43-(aq) → Ag3PO4(s)

This equation shows the formation of solid silver(I) phosphate from the combination of silver(I) ions and phosphate ions. It represents the essential chemical change occurring in the reaction while excluding spectator ions.

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Answer:Gas is the answer

Answer:

\(\huge\boxed{\sf t = 50 \ seconds}\)

Explanation:

Acceleration = a = 0.4 m/s²

Initial Speed = \(V_i\) = 20 m/s

Final Speed = \(V_f\) = 40 m/s

Time = t = ?

\(\displaystyle a =\frac{V_f-V_i}{t}\)

Rearranging formula for t

\(\displaystyle t =\frac{V_f-V_i}{a} \\\\t = \frac{40-20}{0.4} \\\\t = \frac{20}{0.4} \\\\\boxed{t = 50 \ seconds}\\\\\rule[225]{225}{2}\)

Answer:

50 seconds

Explanation:

Equation used :

v = u + at

Given :

⇒ a = 0.4 m/s²

⇒ u = 20 m/s

⇒ v = 40 m/s

Solving :

⇒ 40 = 20 + 0.4t

⇒ 0.4t = 20

⇒ t = 20/0.4

⇒ t = 50 seconds

Answer:

The way I just figured it out myself and made another acc to put the answer on :/

Explanation:

Compound A is likely an organic halide, Compound B is a derivative of benzene, Compound C is benzene itself, and Compound C can be converted into toluene through a Friedel-Crafts alkylation reaction.

i) Compound A is an alkene.

When heated with silver powder, it undergoes oxidative cleavage to produce Compound B which is an aldehyde.

So the IUPAC names of Compound A and Compound B are ethene and ethanal, respectively.

ii) The acidic nature of Compound B can be proved by treating it with sodium hydrogen carbonate. If effervescence occurs, it is due to the evolution of carbon dioxide gas.

This indicates that Compound B is acidic in nature and reacts with a base to form salt and water.

iii) When Compound C (Benzene) reacts with bromine in the presence of catalyst FeCl3, Bromine water is decolorized to form a colorless solution.

This is an addition reaction that occurs due to the presence of an electron-rich benzene ring.

iv) Compound C (Benzene) can be converted into Toluene (Methylbenzene) through a process known as Friedel-Crafts Alkylation, where Benzene is allowed to react with Chloromethane (Methyl chloride) in the presence of Lewis acid catalyst, Aluminum chloride (AlCl3).

The resulting product is then heated to obtain Toluene (Methylbenzene).

The chemical reaction for the conversion of Benzene to Toluene is given below:C6H6 + CH3Cl → C6H5CH3 + HCl

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The concentration of molecule and temperature has a positive correlation with the chemical reaction. The higher the concentration and temperature, the faster the reaction rate will be. The average kinetic can be calculated by using this formula KE = \(\frac{1}{2}mv^{2}\).

There are some factors that affect the motion of the molecules:

If the concentration is increased, more particles move together. There will be more collisions and the chemical reaction rate is increased.

The rate of a chemical reaction can be changed caused by the temperature. If the temperature is increased, it will raise the average kinetic energy of the molecule and cause it moves more quickly.

The amount of kinetic energy can be calculated with the equation:

KE = \(\frac{1}{2}mv^{2}\) . The kinetic energy of a moving object depends on its mass and velocity. The faster a molecule moves, the more kinetic energy it has.

Thus, increasing the concentration and temperature will increase the rate of reaction. The average kinetic energy can be calculated by using this formula KE = \(\frac{1}{2}mv^{2}\)

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Answer:

Water is a remarkable substance, and its unique properties are largely due to the presence of polar covalent bonds and hydrogen bonds in its structure. These characteristics play a crucial role in the physical and chemical properties of water, making it essential for life as we know it.

Explanation:

The polar covalent bonds in water arise from the unequal sharing of electrons between oxygen and hydrogen atoms. This results in the oxygen atom having a partial negative charge (δ-) and the hydrogen atoms having partial positive charges (δ+). These charges create polarity within the water molecule, leading to the formation of hydrogen bonds.

Hydrogen bonds occur when the partially positive hydrogen atom of one water molecule is attracted to the partially negative oxygen atom of another water molecule. These hydrogen bonds are relatively weak individually, but when present in large numbers, they contribute to the cohesion, surface tension, and high boiling point of water.

The importance of these bonds is manifold. The cohesion between water molecules due to hydrogen bonding enables water to form droplets, have a high surface tension, and flow freely, facilitating transport within organisms and in the environment. Additionally, hydrogen bonding leads to the high specific heat capacity and heat of vaporization of water, making it an effective regulator of temperature in living organisms and ensuring stable environmental conditions.

Furthermore, hydrogen bonds play a crucial role in the unique properties of water as a solvent. The polar nature of water allows it to dissolve a wide range of substances, including ionic compounds and polar molecules, facilitating various biological processes such as nutrient transport and chemical reactions in cells.

The correct word equation for the reaction described is: calcium hydride + water → calcium hydroxide + hydrogen gas. Therefore, the correct chemical equation for this reaction is: CaH2 + 2H2O → Ca(OH)2 + 2H2

Calcium hydride is an inorganic compound with the chemical formula CaH2. It is a white to gray solid, often sold in a powder form, and is highly reactive with water. When calcium hydride reacts with water, it produces hydrogen gas and calcium hydroxide. Calcium hydride is commonly used as a drying agent in organic solvents and gases because it reacts with water to form hydrogen gas and calcium hydroxide, which can be easily removed. It is also used in the production of hydrogen gas for fuel cells and as a reducing agent in metallurgy.

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Answer:

grow

Explanation:

it needs light

Answer:

It would wilt and die

Explanation:

The plant  needs sunlight and the lamp doesn't produce as much light and nutrients for the plant.

Answer:

0.1

Explanation:

300/(30*10*10)=0.1

Answer: hola

Explanation:Añada cinco gotas al 2 por ciento de tintura de yodo de farmacopea EE. UU. (U.S.P., por sus siglas en inglés) por cada litro de agua limpia. Para el agua turbia añada diez gotas y deje la solución reposar durante 30 minutos por lo menos.

Answer:

9.45

⋅

10

24

molecules CH

3

OH

⋅

Avogadro's constant



1 mole CH

3

OH

6.022

⋅

10

23

molecules CH

3

OH

=

15.69 moles CH

3

OH

Isotope of phosphorus containing 19 neutrons can represented as ²⁴₁₅P.

Isotopes are those atoms of the same elements that have same number of protons or same atomic number but different mass  number.

Atomic number = number of protons in the atom = number of electrons in the neutral atom

Mass number = number of protons + number of neutrons

Mass number is represented as Z

Atomic number is represented as A.

While writing the symbol of an atom the mass number is written on the left and side and as a superscript to the symbol of the atom and atomic number is written to the left and as a subscript to the symbol.

The question requires us to explain the differences in radii of neutral atoms, cations and anions.

To answer this question, we need to keep in mind that a neutral atom presents the same number of protons (positive particles) and electrons (negative particles). Another important information is that the protons are located in the nucleus of the atom, while the electrons are around the nucleus. Also, there is an electrostatic force between protons and electrons, which means that they the protons tend to attract the electrons to the nucleus.

While a neutral atom presents the same number of protons and electrons, a cation is an ion with positive charge, which means it has lost one or more electrons. In a cation, the balance between protons and electrons doesn't exist anymore: now, there is more positive than negative charge (more protons than electrons), and the overall attractive force that the protons have for the electrons is increased. As a result, the electrons stay closer to the nucleus and the radius of a cation is smaller than the neutral atom from which it was derived.

On the other side, anions present negative charge, which means they have received electrons. Similarly to cations, the balance between protons and electrons doesn't exist anymore, but in this case, there are more electrons than protons. In an anion, the overall attractive force that the protons have for the electrons is decreased. As a result, the electrons are "more free" to move and, as they are not so attracted to the nucleus, they tend to stay farther from the positive nucleus compared to the neutral atom - because of this, the radius of an anion is larger than the neutral atom from which it was derived.