A class has one student named Alice. There are 20 students in the class. There are 12 girls in the class. A student in the class is selected at random. What is the probability that the student will be Alice? (pls need this quick)
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Answer:

19 bags of chips

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

10.45 ÷ 0.55 = 19

$0.55 x 19 = $10.45

Answer:

x is = 25° by complimentary angles

Sequences can start at either 0 or 1, depending on the specific sequence and the conventions used.

In mathematics, there are two main ways to number the elements of a sequence: zero-indexing and one-indexing. In zero-indexing, the first element of a sequence is assigned the index 0, the second element is assigned the index 1, and so on. This is the standard convention used in computer science and programming.

On the other hand, in one-indexing, the first element of a sequence is assigned the index 1, the second element is assigned the index 2, and so on. This is the standard convention used in mathematics and many other fields.

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Answer:

Step-by-step explanation:

h(x)= 2x-3

h(5)=2*5-3

=10-3

=7

Answer:

it's 7

Step-by-step explanation:

From the given curve we found that

T(1) = 2i + 2j

N(1) = (1/sqrt(2))i + (1/sqrt(2))j

An(1) = i + j

To find the tangent vector T(t), normal vector N(t), acceleration vector At, and normal acceleration vector An at the given time t for the curve r(t) = t^2i + 2tj, we need to compute the derivatives of the position vector r(t) with respect to time.

The tangent vector is the derivative of the position vector with respect to time:

T(t) = r'(t) = d(r(t))/dt

Differentiating each component of r(t):

T(t) = (d(t^2)/dt)i + (d(2t)/dt)j

= 2ti + 2j

At t = 1:

T(1) = 2(1)i + 2j

= 2i + 2j

The normal vector is obtained by normalizing the tangent vector:

N(t) = T(t) / ||T(t)||

Finding the magnitude of T(t):

||T(t)|| = sqrt((2t)^2 + 2^2)

= sqrt(4t^2 + 4)

= 2sqrt(t^2 + 1)

Normalizing the tangent vector:

N(t) = (2i + 2j) / (2sqrt(t^2 + 1))

= (i + j) / sqrt(t^2 + 1)

At t = 1:

N(1) = (i + j) / sqrt(1^2 + 1)

= (i + j) / sqrt(2)

= (1/sqrt(2))i + (1/sqrt(2))j

The acceleration vector is the derivative of the velocity vector with respect to time:

At(t) = d(T(t))/dt

Differentiating each component of T(t):

At(t) = (d(2t)/dt)i + 0j

= 2i

At t = 1:

At(1) = 2i

Normal acceleration vector An:

The normal acceleration vector is obtained by projecting the acceleration vector onto the normal vector:

An(t) = (At(t) · N(t)) * N(t)

Calculating the dot product of At(t) and N(t):

At(t) · N(t) = (2i) · ((1/sqrt(2))i + (1/sqrt(2))j)

= (2/sqrt(2)) + (0/sqrt(2))

= sqrt(2)

Projecting the acceleration vector onto the normal vector:

An(t) = (sqrt(2)) * ((1/sqrt(2))i + (1/sqrt(2))j)

= i + j

At t = 1:

An(1) = i + j

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Answer:

it's c

Step-by-step explanation:

c is the answer becuse its showing u that ob is perpenlicular to Ac

Answer:

The area is 8

Step-by-step explanation:

If the perimeter is 12, we can just start guessing and checking. in this case, if 4 is the length, that means 2 is its width, since 4-2=2. then you find the area(basexhight) 4x2=8!

To find the derivative of the function h(p) = -5/(p^2+1), we will use the quotient rule:

h'(p) = [(-5)'(p^2+1) - (-5)(p^2+1)'] / (p^2+1)^2

Simplifying this expression, we get:

h'(p) = (10p) / (p^2+1)^2

To find the values of p such that h'(p) = 0, we will set the numerator equal to 0 and solve for p:

10p = 0

p = 0

Therefore, h'(p) = 0 when p = 0.

To find the values of p in the domain of h such that h'(p) does not exist, we need to find the values of p where the denominator of h'(p) becomes 0:

p^2+1 = 0

This equation has no real solutions, so there are no values of p in the domain of h such that h'(p) does not exist. Therefore, we enter DE (does not exist).

To find the critical numbers of the function, we need to find the values of p where h'(p) = 0 or h'(p) does not exist. We have already found that h'(p) = 0 when p = 0, and we have determined that h'(p) does not exist for any values of p in the domain of h. Therefore, the only critical number of the function is p = 0.
Let's first find the derivative of the given function, h(p) = (p - 5)/(p^2 + 1).

Using the quotient rule, h'(p) = [(p^2 + 1)(1) - (p - 5)(2p)]/((p^2 + 1)^2).

Simplifying, h'(p) = (p^2 + 1 - 2p^2 + 10p)/((p^2 + 1)^2) = (-p^2 + 10p + 1)/((p^2 + 1)^2).

To find the values of p such that h'(p) = 0, set the numerator of h'(p) equal to zero:

-p^2 + 10p + 1 = 0.

This is a quadratic equation, but it does not have any real solutions. Therefore, there are no values of p for which h'(p) = 0, so the answer is DNE.

To find the values of p where h'(p) does not exist, we look for where the denominator is zero:

(p^2 + 1)^2 = 0.

However, this equation has no real solutions, as (p^2 + 1) is always positive. Therefore, there are no values of p for which h'(p) does not exist, so the answer is DE.

Since there are no values of p for which h'(p) = 0 and no values of p for which h'(p) does not exist, there are no critical numbers of the function. The answer is DNE.

Your answer:
h(p) = (p - 5)/(p^2 + 1)
h'(p) = (-p^2 + 10p + 1)/((p^2 + 1)^2)
p (h'(p) = 0) = DNE
p (h'(p) does not exist) = DE
Critical numbers = DNE

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Answer:

  D

Step-by-step explanation:

We expect the height of a helium balloon to be increasing, up to the point where it bursts.

The only graph that shows consistently increasing altitude with a final drop is graph D.

_____

Additional comment

The graph of D shows the altitude increases at an increasing rate. The buoyancy force decreases with altitude, so we expect the balloon would actually have a decreasing rate of altitude increase. The actual curve would likely be concave downward.

Answer:

Okay...................

Answer:

24

Step-by-step explanation:

dont exaclty have an explanations - its just the calculations

The range of sales Dr. Spencer Lewis must exceed to profit the most from the second deal is 15,000 sales.

To find the range that will benefit Dr. Spencer Lewis the most with the second deal, we must perform the following operation:

We must replace the X with several numbers and buy the result, when the result of operation B exceeds the result of operation A, it means that it will be more profitable.

According to the above, if we replace the X with 15,000, the values will be the same, however, each number that we increase will mean a greater profit in agreement B.

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Step-by-step explanation:

To rent a jet ski it cost a flat fee of $80 for the entire day. How much does it cost for 2 hours of use?

there are 24 hours in a day

80/24 = 3.333333 per hour

for two hours it costs:

3.33333 * 2 = $6.67 (rounded)

Using the standard deviation value of these interarrival times, the coefficient of variation is 0.012.

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.

The standard deviation to mean ratio, or coefficient of variation (CV), illustrates the degree of variability in proportion to the population mean. The dispersion increases with increasing CV.

Formula is given by:

\(CV = \frac {\sigma}{\mu}\)

\(\sigma = 0.02\)

Mean for the time of 0.02 sec is = 79 * 0.02

=1.58

CV= 0.02/1.58

=0.012

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Answer:

A B and C

Step-by-step explanation:

it's a simple question

Answer:

n = - 4

Step-by-step explanation:

8 = - 2n ( isolate n by dividing both sides by - 2 )

- 4 = n

Answer:

n = -4

Step-by-step explanation:

8= -2n   (divide both sides by -2)

8 / (-2) = n  

n = -4

hope this helps

(x,y) = (3,2)

y = x - 1

2 = 3 - 1

2 = 2

y = -x + 5

2 = -3 + 5

2 = 2

If (3, 2) is a solution of the system y = x - 1 and y = - x + 5 then the ordered pair (3, 2) satisfies both equations simultaneously.

Graphical solutions of a system of equations are way of finding the intersection points of all the equations given.

A system with two or more than two equations has a solution only when they have a common intersection point.

Given, The system of equation y = x - 1 and y = - x + 5 has a

solution (3, 2).

If the ordered pair (3, 2) is a solution of both equations this implies that this ordered pair satisfies both equations simultaneously.

For,

y = x - 1.

At, x = 3,

y = 3 - 1

y = 2   (satisfied).

For,

y = - x + 5.

At, x = 3,

y  - 3 + 2.

= 2     (satisfied).

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Answer: q=2

Step-by-step explanation: do you want me to explain

Answer:

here

Step-by-step explanation:

The counting numbers {1, 2, 3, ...} are commonly called natural numbers; however, other definitions include 0, so that the non-negative integers {0, 1, 2, 3, ...} are also called natural numbers.

Answer:

B. >

Step-by-step explanation:

Yes, you got it correct! Anything with a "-" is always less than a "+". Look at it this way:

I have 11 dollars (+11) and you owe me one dollar (-1). Now which is better?

Hope this helps

~R3VO

A = π r² is the formula

r is the radius

Hope it helps ✨

Answer:

Step-by-step explanation:

\(A=\pi \times r^2\)          where r is the circle's radius

Answer:

It is x2 -4  because it correct

The general solution to the system of differential equations is:

A = 64t - 2t^2 + C1

To solve the system of differential equations dz/dt = A and dA/dt = 64 - 4t, we can proceed as follows:

First, let's solve the second equation for A. We have dA/dt = 64 - 4t, which is a separable equation. We can rewrite it as dA = (64 - 4t) dt and integrate both sides:

∫dA = ∫(64 - 4t) dt

A = 64t - 2t^2 + C1

where C1 is the constant of integration.

Now, let's substitute this expression for A into the first equation dz/dt = A:

dz/dt = 64t - 2t^2 + C1

This is a separable equation as well. Rearranging the terms, we have dz = (64t - 2t^2 + C1) dt. Integrating both sides:

∫dz = ∫(64t - 2t^2 + C1) dt

z = 32t^2 - (2/3)t^3 + C1t + C2

where C2 is another constant of integration.

Therefore, the general solution to the system of differential equations is:

z = 32t^2 - (2/3)t^3 + C1t + C2

A = 64t - 2t^2 + C1

The constants C1 and C2 can be determined by applying the initial conditions given for t = t0. These initial conditions will provide specific values for z and A, allowing you to solve for the constants and obtain the particular solution for the system.

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We are 90% confident that the true difference between the mean strengths of the two types lies between 0.015 and 0.105. The data does not show at the 0.05 level that the mean strengths are different, with a p-value of approximately 0.055. Therefore, we fail to reject the null hypothesis that the means are equal.

To find a 90% confidence interval for the difference in the mean strengths of the two types, we can use the two-sample t-test with pooled variance. The formula for the confidence interval is:

\($(\bar{x}_1 - \bar{x}2) \pm t{\alpha/2,\nu} \cdot s_p \cdot \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}$\)

Plugging in the given values, we get:

\(\bar{x}1 = 3.18, \bar{x}2 = 3.24, n_1 = 5, n_2 = 7, s_p = \sqrt{\frac{ (n_1 - 1)s_1^2 + (n_2 - 1)s_2^2 }{ df }} = \sqrt{\frac{ (40.042^2 + 60.048^2) }{ 10 }} = 0.046, t{\alpha/2,\nu} = t{0.05/2,10} = 2.306$\)

Therefore, the 90% confidence interval for the difference between the mean strengths of the two types is:

\($(3.24 - 3.18) \pm 2.306 \cdot 0.046 \cdot \sqrt{\frac{1}{5}+\frac{1}{7}} = 0.06 \pm 0.045$\)

So the interval is (0.015, 0.105).

Thus, we are 90% confident that the true difference between the mean strengths of the two types lies between 0.015 and 0.105.

To test whether the mean strengths are different, we can use a two-tailed hypothesis test with a significance level of 0.05. The null hypothesis is that the means are equal, while the alternative hypothesis is that they are different. We can calculate the t-value as:

\($t = \frac{\bar{x}_1 - \bar{x}_2}{s_p \cdot \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} = \frac{3.18-3.24}{0.046 \cdot \sqrt{\frac{1}{5}+\frac{1}{7}}} = -2.13$\)

The degrees of freedom are the same as before, \($df = n_1 + n_2 - 2 = 10$\)

The p-value is the probability of getting a t-value at least as extreme as the observed one, assuming the null hypothesis is true. From a t-distribution table, we can find that the p-value for t = -2.13 with df = 10 is approximately 0.055. Since this is greater than the significance level of 0.05, we fail to reject the null hypothesis.

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Answer:

(-3,0)

Step-by-step explanation:

The vertex is the maximum  of a downward facing parabola

The maximum is (-3,0)